You find a mysterious white powder in your kitchen. It could be cream of tartar (pH=5), sugar (pH=7), baking soda (pH=8), or drain cleaner (pH=14). Explain which pH indicator(s) you would use to determine the unknown substance.
1) Phenolphthalein (PHT) 2) Red cabbage 3) Bromthymol blue 4)Congo red (CR)

To determine which metal sample has the largest volume among the given options, we need to compare their densities. The sample with the lowest density will have the greatest volume for a given mass.

Let's calculate the volumes of the metal samples using the formula:

Volume = Mass / Density

1) For aluminum: Mass = 100 g, Density = 2.7 g/cm^3

Volume of aluminum = 100 g / 2.7 g/cm^3 = 37.04 cm^3

2) For gold: Mass = 100 g, Density = 19.3 g/cm^3

Volume of gold = 100 g / 19.3 g/cm^3 = 5.18 cm^3

3) For iron: Mass = 100 g, Density = 7.86 g/cm^3

Volume of iron = 100 g / 7.86 g/cm^3 = 12.72 cm^3

4) For magnesium: Mass = 100 g, Density = 1.74 g/cm^3

Volume of magnesium = 100 g / 1.74 g/cm^3 = 57.47 cm^3

5) For silver: Mass = 100 g, Density = 10.5 g/cm^3

Volume of silver = 100 g / 10.5 g/cm^3 = 9.52 cm^3

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Answer:

Explanation:

Hydrogen atoms have an electronic configuration of 1s¹. This indicates  that they require one more additional hydrogen in order to complete it octet structure and before they can form a reaction.

Helium have an electronic configuration of 1s², which is a noble gas. In noble gas, their octet structures are complete. As such they do not require additional electron before they can form a reaction.

Answer:

atoms and molecules

Explanation:

matter is made up of particles called atoms and molecules

Matter is made up of small molecules and attoms

Answer:

2C7H6O2 + 15O2 → 14CO2 + 6H2O  

Explanation:

C7H6O2 + O2 → CO2 + H2O

Carbon is not balanced (Reactant - 7, Product - 1)

Adding 7 to CO2;

C7H6O2 + O2 → 7 CO2 + H2O

Carbon is now balanced, however hydrogen is not balanced (Reactant - 6, Product - 3)

Adding 3 to H2O;

C7H6O2 + O2 → 7 CO2 + 3 H2O

Hydrogen is now balanced, however oxygen is not balanced (Reactant - 4, Product - 3)

Since 3H2O gives an odd value of O, multiply all through by 2;

2C7H6O2 + 2O2 → 14 CO2 + 6 H2O

Oxygen is still not balanced (Reactant - 8, Product - 34)

Change 2O2  to 15O2;

2C7H6O2 + 15O2 → 14CO2 + 6H2O  

Equation is now balanced.

Answer: a chemical bond; in which one atom donates an electron to another atom

Explanation:

Answer:

the answer to this is 74 :)

If the pressure is initially 1.15 atm before the addition of the gas and the position of the piston does not change,

If the pressure is initially 1.15 atm before the addition of the gas and the position of the piston does not change, then the pressure inside the cylinder will remain the same. This is because the position of the piston does not change, meaning that the volume of the cylinder remains constant.

According to Boyle's law, the pressure of a gas is inversely proportional to its volume when the temperature is kept constant. Therefore, if the volume does not change, the pressure cannot change either. Hence, the new pressure inside of the cylinder will be 1.15 atm, the same as the initial pressure

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The given chemical equation is,Na2SO4 + 2C → Na2S + 2CO2To determine the amount of Na2S produced from 24 grams of C, we need to use stoichiometry.

Using stoichiometry, we can calculate the number of moles of C that will react with Na2SO4 and produce Na2S.From the equation, we can see that 2 moles of C react with 1 mole of Na2SO4 to produce 1 mole of Na2S.So, the number of moles of C can be calculated as follows:Number of moles of C = Mass of C / Molar mass of CNumber of moles of C = 24 g / 12.01 g/mole Number of moles of C = 1.998 moles Now, using the stoichiometry, we can calculate the number of moles of Na2S that will be produced from 1.998 moles of C.

Number of moles of Na2S = Number of moles of C x (1 mole of Na2S / 2 moles of C)Number of moles of Na2S = 1.998 x (1 / 2)Number of moles of Na2S = 0.999 molesFinally, we can calculate the mass of Na2S produced from 24 grams of C.Mass of Na2S = Number of moles of Na2S x Molar mass of Na2SMass of Na2S = 0.999 moles x 78.04 g/molMass of Na2S = 77.96 gTherefore, 77.96 grams of Na2S will be produced from 24 grams of C.LONG ANSWER IN 100 WORDS:First, we need to balance the given chemical equation as follows:Na2SO4 + 2C → Na2S + 2CO2To determine the amount of Na2S produced from 24 grams of C, we need to use stoichiometry.

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The equation is 2N2 + H2 → 3NH3 ,2 upper case N subscript 2 end subscript plus upper case H subscript 2 end subscript rightward arrow 3 upper case N H subscript 3 end subscript.

A chemical equation that is balanced conserves mass and has an equal number of atoms of each element on both sides of the equation.

A chemical equation that is balanced has equal masses for the reactants and products, contains the same amount of atoms of each element on both sides of the equation.

Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Different elements' atom counts in the reactants and products of unbalanced chemical equations are different.

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The relationship between monosaccharides and polysaccharides are that monosaccharides are the building blocks of polysaccharides, which are formed by the linkage of multiple monosaccharides.

Monosaccharides and polysaccharides are both types of carbohydrates, but they have different chemical structures and functions. Monosaccharides, also known as simple sugars, are the simplest form of carbohydrates. They are composed of a single sugar unit and include glucose, fructose, and galactose. Monosaccharides can be further classified into aldoses (having an aldehyde group) and ketoses (having a ketone group). They can be used as energy source for cells, and are also the building blocks for other carbohydrates. Polysaccharides, on the other hand, are made up of many sugar units linked together. These carbohydrates are usually large and complex, and they serve a variety of functions in living organisms. They are used for energy storage, structural support, and as reserve food.

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Answer:

Soil permeability

Explanation:

Soil permeability is the ease with which gases, liquids or plant roots can penetrate or pas through the soil.

It is an important factor when considering soil property for agricultural purposes.

Answer:

Soil permeability

Explanation:

Answer:

here

Explanation:

1s22s22p63s23p1.

Answer:

Oxygen-O = 6

Carbon C = 4

Gallium G = 3

Astatine A = 7

Arsenic As = 5

Potassium K = 1

Hydrogen H = 1

Helium H = 2

Explanation:

The mass of Hg in the sample is 17.1g.

One of the fundamental quantities in physics and the most fundamental feature of matter is mass. The quantity of matter in a body is referred to as its mass. The kilogram, the standard international unit of mass (kg). You can write the mass formula as follows:

Mass = Density × Volume

The water weighs 1400 g. And one night later, we grew by one. Therefore, multiplying X 12.2 by 1400 multiplied by a million. We therefore possess 0.01708 grammes of mercury. When converted to milligrams, this amount equals 17.1 milligrams of mercury.

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I wrote, The platinum electrode is the cathode in this reaction. The tin electrode is the anode in this reaction. In the half reactions that occur the nitrate is reduced to nitric oxide(NO) while the tin electrode is oxidized to Sn2+.

Oxidation occurs at the tin half cell(anode) while reduction occurs at the nitrate half cell(cathode).

A galvanic cell refers to a cell that produces electrical energy spontaneously by redox reaction. Oxidation occurs at the anode while reduction occurs at the cathode in a galvanic cell.

The oxidation half equation at the anode occurs as follows;

3Sn(s) → 3Sn^2+(aq) + 6e

The reduction half equation that occurs at the cathode is;

2NO3–(aq) + 8H+(aq) + 6e→  2NO(g) + 4H2O(l)

We can see that electron loss occurs at the cathode while electron gain occurs at the anode as we can see in the equations above.

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Suppose 5.0 mol of antimony (III) fluoride is added to 10.0 mol of carbon tetrachloride, and from the 100% reaction there are the equivalents of 0 moles of SbF₃, 5.0 moles of SbCl₃, 0 moles of CCl₄, and 15.0 moles of CClF₂.

A balanced reaction is one where the reactants and products are present in equal amounts, and if the 100% reaction takes place, then the reactant sides have 1 mol of SbF₃ and 3 mol of CCl₄ that make the product of 1 mol of SbCl₃ and 3 mol of CClF₂. After the 100% reaction, all the reactants get converted into the product. The complete reaction is the below.

SbF₃ + 3CCl₄ → SbCl₃ + 3CClF₂

Hence, suppose  5.0 mol of antimony (III) fluoride is added to 10.0 mol of carbon tetrachloride, and from the 100% reaction there are the equivalents of 0 moles of SbF₃, 5.0 moles of SbCl₃, 0 moles of CCl₄, and 15.0 moles of CClF₂.

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The free energy for the dissociation reaction of HA(aq) at 25°C can be calculated by utilizing the given acid dissociation constant (Ka) of the weak acid HA. It is given that the Ka of weak acid HA at 25°C is 4.3 x 10^-8.

The dissociation reaction of the given weak acid HA can be represented as,HA(aq) + H2O(l) ↔ H3O+(aq) + A-(aq)The acid dissociation constant (Ka) is defined as the ratio of the concentrations of the products of dissociation (H3O+ and A-) to the concentration of the undissociated acid (HA).

K = [H3O+][A-]/[HA]...........(5)Comparing equation (5) with equation (1), we can write,[H3O+][A-]/[HA] = KaRearranging the above equation, we get,[H3O+][A-] = Ka [HA]...........(6)The free energy change (ΔG) of a reaction is related to the equilibrium constant (K) as follows:ΔG = -RT ln K...........(7)where, R is the universal gas constant (8.314 J mol^-1 K^-1), T is the temperature in Kelvin (25°C = 298 K)Therefore,ΔG = -RT ln K...........(8)Substituting the value of Ka from equation (3) in the above equation,ΔG = -RT ln KaΔG = - (8.314 J mol^-1 K^-1) (298 K) ln (4.3 x 10^-8) = + 37.9 kJ mol^-1.

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The condensation reaction between two molecules of glucose would result in the formation of maltose (C12H22O11) and the release of water.

Carbohydrates are organic compounds that are used to store energy. An example of a carbohydrate is glucose, which is a single sugar or a monosaccharide. The process of forming larger molecules from the combination of simple sugars is called the condensation process. A water molecule is released in the process of combining the molecules together through a glycosidic bond.

The condensation reaction for two molecules of glucose (C6H12O6) results in the formation of maltose, a disaccharide, and the release of water. The molecular formula of maltose is C12H22O11. It can be observed that the condensation reaction shown below is balanced.

Glucose (C6H12O6) + Glucose (C6H12O6)  → Maltose (C12H22O11) +H2O

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Answer:

stable, because there is always an equal amount of force surrounding the atom  

The dipole for PBr3 is shown in the attachment. PBr3 has non xero dipole moment because bromine atoms can not cancel out dipole moment of each other.

The three bromine atoms in this molecule do not cancel out the dipole moment of each other and molecule shows net dipole moment.it shows that PBr3 is a polar molecule.the partially positive charge surrounded by phosphorus atom and partially negative charged surrounded by bromine atom.

Dipole moment is used to define the symmetry of molecules. PBr3 has the trigonal pyramidal structure. bromine atom has more electronegative value than phosphorus.

Thus, the dipole moment in PBr3 is non zero due to unequal charge distribution.

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Answer:

c

Explanation:

In terms of Chalk , the  reflection and assumption  is that Chalk is a soft white rock used for writing, drawing, and various industries.

Assumptions: Chalk is seen as safe for schools, yet may have impurities/allergens causing health issues in large amounts. Also believed eco-friendly due to natural sources and biodegradability.

In terms of Vinegar, the  reflection and assumption  is that is an acidic liquid used in cooking, cleaning, and medicine. It's made by fermenting ethanol with acetic acid bacteria.

Vinegar's health benefits are assumed but not fully supported by science. Vinegar is a natural cleaning agent, but may not work as well as commercial products for some stains or germs.

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None of the given options is entirely correct.

With paper chromatography, mixtures of substances are separated according to how well they dissolve in a solvent and how well they stick to the paper's fibers.

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The aqueous solutions can be arranged in increasing boiling point order as follows: 0.050m Al(ClO4)3 < 0.110m K2CO3 < 0.300m C6H12O6.

The boiling point of a solution is influenced by the concentration of solute particles in the solution. The greater the concentration of solute particles, the higher the boiling point. In this case, we are comparing the boiling points of three different aqueous solutions.

The solution with the lowest boiling point is 0.050m Al(ClO4)3. This is because Al(ClO4)3 is an ionic compound that dissociates into multiple ions in water, thereby increasing the number of solute particles. Higher concentration of solute particles raises the boiling point.

The solution with the next higher boiling point is 0.110m K2CO3. K2CO3 is also an ionic compound and dissociates into two ions in water. Although the concentration is higher compared to Al(ClO4)3, it is lower than that of C6H12O6.

The solution with the highest boiling point is 0.300m C6H12O6. C6H12O6, which is glucose, is a molecular compound and does not dissociate into ions in water. Therefore, it has the lowest concentration of solute particles among the given solutions, resulting in the lowest boiling point.

Hence, the correct order of increasing boiling points is 0.050m Al(ClO4)3 < 0.110m K2CO3 < 0.300m C6H12O6.

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BeO or KCl will have a higher melting point than any other pair given above in the question.

The pair of molecules that would have the higher melting point would be e. BeO and KCl. BeO has a higher molecular weight and is more covalently bonded, which makes it more stable and more difficult to break the intermolecular forces. This makes it have a higher melting point than KCl, which is held together by ionic bonds, which are relatively weaker and easier to break.

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Answer:

What can be said about these common forms of sulphur is that;

(B) They will exhibit same chemical properties

Explanation:

Allotropy is the property of an element to exist in two or more forms in the same physical state

Allotropes have several similar chemical  properties but differ in their physical properties, such as the white, pale yellow to totally colorless diamond and the gray graphite

Sulphur can exist in several allotropic forms, and carbon is the only element that has more allotropes than sulphur

The sulphur allotropes includes S₂, S₆, and S₅ have similar chemical properties but different physical properties.

The correct option is;

What can be said about these common forms of sulphur is that they have the same chemical properties

The respective concentrations (m) of Mg^2+ and C2H3O2^- ions afforded by dissolving 0.600 mol of Mg(C2H3O2)2 in water and diluting to 135 ml are approximately 0.444 M and 0.889 M.

To determine the concentrations of Mg^2+ and C2H3O2^- ions, we need to consider the stoichiometry of the dissociation of Mg(C2H3O2)2 in water. Mg(C2H3O2)2 dissociates into one Mg^2+ ion and two C2H3O2^- ions:

Mg(C2H3O2)2 → Mg^2+ + 2 C2H3O2^-

The initial moles of Mg(C2H3O2)2 is given as 0.600 mol.

To calculate the concentrations, we need to determine the final volume of the solution after dilution. The given volume is 135 ml, which is equivalent to 0.135 L.

The concentration (molarity) of a solution is calculated by dividing the number of moles by the volume in liters:

Concentration (M) = Moles / Volume (L)

For Mg^2+:

Concentration of Mg^2+ = Moles of Mg^2+ / Volume of solution

Since one mole of Mg(C2H3O2)2 produces one mole of Mg^2+, the moles of Mg^2+ is also 0.600 mol.

Concentration of Mg^2+ = 0.600 mol / 0.135 L ≈ 4.44 M

For C2H3O2^-:

Since one mole of Mg(C2H3O2)2 produces two moles of C2H3O2^-, the moles of C2H3O2^- is 2 * 0.600 mol = 1.200 mol.

Concentration of C2H3O2^- = 1.200 mol / 0.135 L ≈ 8.89 M

Therefore, the respective concentrations (m) of Mg^2+ and C2H3O2^- ions are approximately 0.444 M and 0.889 M. None of the given answer choices match the calculated values exactly, but the closest option is 0.444 and 0.889.

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