You are trying to pry a boulder out of your back yard. You have a 2 m iron bar propped under the rock to use as a lever and have placed a piece of wood about 0. 3 m from the end of the bar under the rock. You weigh 157 pounds or 700 N. The rock weighs 1300 N. Do you move it? Draw a sketch of the situation to help solve
Answers
Using the 2 m iron bar as a lever with a fulcrum 0.3 m from the end under the rock, you can move the 1300 N rock with your weight of 700 N.
To determine whether you can move the rock, we need to analyze the forces and lever arm lengths involved. In this situation, we have:
1. The 2 m iron bar acting as a lever
2. The fulcrum point, which is the piece of wood at 0.3 m from the end of the bar under the rock
3. Your weight (700 N) acting as the effort force
4. The rock's weight (1300 N) acting as the resistance force
Now let's use the principle of levers to solve the problem:
Step 1: Calculate the lever arm lengths on both sides of the fulcrum.
Effort arm length (EAL) = 2 m - 0.3 m = 1.7 m
Resistance arm length (RAL) = 0.3 m
Step 2: Calculate the mechanical advantage (MA) of the lever system.
MA = EAL / RAL = 1.7 m / 0.3 m = 5.67
Step 3: Determine if your weight can move the rock.
Effort force * MA = Resistance force
700 N * 5.67 = 3970 N
Since the effort force (3970 N) is greater than the resistance force (1300 N), you can move the rock.
Here's a sketch of the situation:
```
Rock (1300 N)
|
+-----|------||----+
| 0.3m || 1.7m|
Piece of wood You (700 N)
(Fulcrum)
```
In conclusion, using the 2 m iron bar as a lever with a fulcrum 0.3 m from the end under the rock, you can move the 1300 N rock with your weight of 700 N.
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Related Questions
2. The timing mechanism in a grandfather's clock is based on the principles of a simple
pendulum. If your clock is gaining time (running fast) what should you do to get it running
more accurately?
Answers
To get a grandfather clock running more accurately, if it is gaining time, you should adjust the length of the pendulum.
How to adjust the length of the pendulum?
This can typically be done by moving the pendulum bob up or down the pendulum rod. A shorter pendulum will cause the clock to run faster, while a longer pendulum will cause it to run slower.
It is important to make small adjustments and wait for the clock to stabilize before making further adjustments. It's also recommended to consult the clock's manual for instructions on how to adjust the pendulum length.
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There are four forces in nature. Which one allows you to close a door by pushing on it?
Answers
Weak nuclear force, electric force, nuclear force, and gravitational force are the four fundamental forces of nature. The weak and strong forces are dominant only at the level of subatomic particles and are only effective across extremely small distances. amongst Electric force allows you to close a door by pushing on it.
Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion define how it affects the target body and how it does so. One of the many forces that affect things is the electric force.
For instance, moving a box results in a force being applied to it because the negatively charged electrons in the hand pushing it repel the similarly negatively charged electrons in the box's atoms.
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helppppppppppppppppppppppppp
Answers
Answer:
value of x=35°
y=72.5°
hope it helps you
make me brainliest plz
A car has a kinetic energy of 4.32 x 10^5 J when traveling at a speed of 23 m/s.
What is its mass?
A. 1333.27 kg
B. 1433.27 kg
C. 1533.27 kg
D. 1633.27 kg
Answers
Answer:
I think the most interesting 3rd century 3g durga was 5f5
Explanation:
I 50degree and I have not done a good morning mam sushant since I am not pregnant and have no
A 3. 000 kg ball is pitched with a kinetic energy of 20. 00 joules. Then the momentum of the ball is.
Answers
Answer:
5.48 kg m/s
Explanation:
a 2.0 kg ball is dropped from a height of 20 m onto a soft surface and rebounds to a height of 5.0 m . what is the magnitude of the impulse exerted on the ball by the floor?
Answers
Based on the data provided, the impulse of the floor on the ball is 59.4 Ns.
What is the impulse of the floor on the ball?Using the equation of motion to determine the velocity at the end of the fall
v^2 = u^2 + 2ghWhere v is velocity at the end of fall
u is initial velocity = 0
g is acceleration due to gravity = 9.81 m/s^2
h is height = 20
Taking downward velocity as negative and up as positivev^2 = 0 + 2 (9.81)(20)
v^2 = 392.4
v = - 19.8 m/s
The velocity, v after bouncing is calculated also:
u = 0
g = 9.81 m/s^2
h = 5.0 m
v^2 = 0 + 2(9.81)(5)
v^2 = 98.1
v = 9.904 m/s
Impulse = change in momentum Impulse = m(v- u)Impulse = 2.0 × (9.9 -(-19.8)
Impulse = 59.4 Ns
Therefore, the impulse of the floor on the ball is 59.4 Ns.
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Find the range for the following set of data: 22, 36, 7, 19,56.
Answers
56-7
49
The range is 49
Hope that helps :)
Answer:
49 is the answer
Explanation:
Take the highest number and the lowest and subtract! :)
which type of sediment is most common in the ocean by area?
Answers
The most common type of sediment in the ocean by area is biogenous sediment. Biogenous sediment is made up of the hard remains of once-living organisms.
The majority of biogenous sediment is found in regions of the ocean where there is a high concentration of biological activity, such as close to continental shelves, upwelling zones, and polar regions. Biogenous sediment is composed of the hard remains of once-living organisms, such as shells and skeletons of marine animals.
The kind and amount of marine animals present in a certain area, as well as the pace of sedimentation, the degree of ocean currents and mixing, and the depth and topography of the seabed, are all elements that affect the buildup of biogenous silt on the seafloor over time.
Terrigenous sediment, which is composed of transported rock and mineral fragments that have weathered, is one of the several forms of sediment found in the ocean.
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The peak wavelength for the blackbody curve a star is in the UV range assuming the radiation from the star can reach earth would you be able to see it yes or no
Answers
Answer:
No
Explanation:
We would not be able to see the star because its radiation is in the UV range. For the star to be visible, it has to be in the visible spectrum of light for me to be able to see it with my eyes.
Brody and Ethel are arguing about waves. Brody says that waving his hand back and forth is a scientific wave. Ethel
says that it is not.
Which statement best describes who is correct?
A) Brody is correct because the wave involves an input of energy.
B) Ethel is correct because energy is not carried from one place to another.
C) Brody is correct because the pattern repeats.
D) Ethel is correct because the motion has no pattern.
Answers
Answer:
b
Explanation:
Answer:
B.)Ethel is correct because energy is not carried from one place to another.
Explanation:
stay safe 2021
A pole-vaulter clears a crossbar and takes 1.0 s to fall from the apex of his flight to the landing pit. What was his downward vertical velocity at the end of this second? a. 4.9 m/s b. 9.81 m/s c. 1.0 m/s d. 19.62 m/s
Answers
The pole vaulters downward vertical velocity at the end of this second is. 9.81 m/s. The correct option is b.
When an object falls freely under gravity, its velocity increases at a constant rate of 9.81 m/s^2. This acceleration due to gravity is denoted by 'g' and has a magnitude of 9.81 m/s^2 on the surface of the Earth.
In the given problem, the pole-vaulter is falling freely under gravity after clearing the crossbar. The time taken for him to fall is 1.0 s. Therefore, his final downward velocity can be calculated using the formula:
v = g * t
where v is the final velocity, g is the acceleration due to gravity, and t is the time taken for the fall.
Substituting the values, we get:
v = 9.81 m/s^2 * 1.0 s = 9.81 m/s
Therefore, the downward vertical velocity of the pole-vaulter at the end of the second is 9.81 m/s, which is the answer (option b).
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if elecomegtic force is stonger than gravity, why is it overpowered by gravity on large scales
Answers
The electromagnetic force and gravitational force are two of the four fundamental forces of nature. While the electromagnetic force is much stronger than the gravitational force on a small scale, it appears that gravity dominates on larger scales.
The electromagnetic force is strongest between electrically charged particles, while the gravitational force is proportional to the mass of objects. The electromagnetic force is approximately 10^36 times stronger than the gravitational force on the scale of single atoms and molecules. However, on larger scales, the gravitational force begins to dominate.
This is because the electromagnetic force is a long-range force that decreases rapidly with distance, while the gravitational force is a long-range force that decreases more slowly with distance. As a result, the total amount of gravitational force between two large objects like stars or planets is much greater than the total amount of electromagnetic force.
In summary, the electromagnetic force is much stronger than the gravitational force on a small scale, but it is overpowered by gravity on large scales due to the long-range nature of the gravitational force and its relatively slower decrease with distance.
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a 23.9 a current flows in a long, straight wire. find the strength of the resulting magnetic field at a distance of 58.3 cm from the wire.
Answers
The magnetic field at a distance of 58.3 cm from a long, straight wire carrying a 23.9 A current, the strength of the resulting magnetic field can be found using the equation B = μ0*I/2π*r, where B is the magnetic field strength, μ0 is the permeability of free space, I is current, and r is the distance.
Therefore, the strength of the magnetic field at 58.3 cm from the wire is B = 4π * 10-7 * 23.9/2π * 58.3 = 0.0067 N/Amp.
The magnetic field strength due to the current in the wire is caused by the current producing a magnetic field, which is a result of moving electric charges (electrons) in the wire. The strength of the magnetic field depends on the magnitude of the current and the distance from the wire.
As the current increases, the magnetic field strength increases; likewise, as the distance from the wire increases, the magnetic field strength decreases. The direction of the magnetic field can be determined using the right-hand rule.
The strength of the magnetic field can be used to calculate the force on a moving charged particle, F = q * v * B, where q is the charge of the particle, v is its velocity, and B is the magnetic field strength. By using this equation, the force acting on a charged particle due to the magnetic field at 58.3 cm from the wire can be found.
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A 500kg car is driven forward with a thrust force of 1500N. Air resistance and friction acts against the motion of the car with magnitude 200N and 300N respectively. What is the acceleration of the car?
Answers
The acceleration of the car is 2m/s^2.
What are acceleration and its SI unit?
Speed, in physics, is the rate of change of object speed in relation to time. The acceleration of an object is the sum total of any force and all that is active in an object, as defined by Newton's Second Law. The SI acceleration unit is a meter per second (m s ^ −2).
What are acceleration and velocity?
Acceleration of the vector value is defined as the rate at which an object changes speed. An object is faster when it changes its speed. Since speed is a vector model, it has direction and magnitude.
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Aircraft carriers use catapults to launch jets from their deck. One such catapult accelerates a 18,900 kg aircraft from rest to 61 m/s in 3.3 s. What is the magnitude of the force (in N) required to do this?
Answers
Given that the mass of catapult, m = 18900 kg
The initial velocity is
\(v_o=\text{ 0 m/s}\)As the body is at rest initially.
The final speed is
\(v_f=\text{ 61 m/s}\)The time taken is t = 3.3 s
We have to find the force.
According to Newton's second law, the formula to calculate force is
\(\begin{gathered} F=\text{mass}\times acceleration \\ =m\times\frac{(v_f-v_o)}{t} \end{gathered}\)Substituting the values, the force will be
\(\begin{gathered} F=18900\times\frac{61-0}{3.3} \\ =349363.63\text{ N} \end{gathered}\)Thus, the force is 349363.63 N
one end of a light inextensible string is attached to a tool box of mass 2.5 kg which is lying on a horizontal table. The string passing over a smooth pulley and is tied at the other end to a bag of mass 1.4kg as shown in the diagram
a. If the toolbox on the point of sliding, find the value for μ, the coefficient of friction.
b. Supposing the coefficient of friction between the tool boxe and the table is 0.20, calculate the acceleration of the system and the tension in the string gravity as 10 m per second square
Answers
Answer:
the answer is A
Explanation:
hydrogen bombs and stars both produce energy with nuclear ?
Answers
Answer:
If we are talking fusion. Yes they both use nuclear fusion.
if its fission or anything else no.
a metal sphere of radius 15 cm has a net charge of 7.0 10-8 c. (a) what is the electric field at the sphere's surface?
Answers
Answer:
Electric field on the surface of the ball 28 kV/m
Explanation:
Given:
R = 15 cm = 0.15 m
q = 7.0·10⁻⁸ C
________________
E - ?
Electric field on the surface of the ball:
E = k·q / R²
E = 9·10⁹·7.0·10⁻⁸ / (0.15)² ≈ 28 000 V/m or E = 28 kV/m
A string attached to a kite was maintained at an angle of 65.0° with the ground. If 120 m of string was reeled in to return the kite back to the ground, what was the vertical height of the kite? (Assume the string was straight and did not sag)
Answers
Answer:
The hypotenuse is measured at 120 meters of string, and you need to solve for the leg of the triangle that is horizontal. The degree is 40, so use trigonometry to figure it out.
Cosin (40) is equal to around .766
Adjacent/Hypotenuse
x/120 = cos40
Answer: 91.92533.
If you use 3 significant figures it should be 91.9 meters.
Explanation:
A bullet of mass 0.05kg has a speed 400.what is it's kinetic energy.
if the bullet hits a wall of which the average resistive force is 10000 newton.calculate the distance penetrated by the bullet.
Answers
Answer:
K.E =1÷2M×V^2
= 1÷2×0.05×(400)^2
= 4000
Explanation:
what is the formula for calculating the magnitude of kinetic frictional force
Answers
This means that measuring the pulling froce F is like measuring the force of static friction fs . Uk = FK . here
f= FK. FK = force of kinetic friction uk = coefficient of kinetic friction and N= normal to the contacting surfaces.
Which of the below is an action-oriented objective in a SMART goal setting system?
A) Increase my running speed to an 8 1/2-minute mile pace.
B) Run on the trail 4 times a week.
C) Complete the Rock 'n Roll marathon next year.
D) Increase my distance by one-half mile every other week
Answers
The action-oriented objective in a SMART goal setting system is option D) Increase my distance by one-half mile every other week.
This objective is specific, measurable, achievable, relevant, and time-bound. It is specific because it defines a clear action to be taken (increasing distance), measurable because it includes a specific metric (one-half mile), achievable because it is realistic to increase distance gradually, relevant because it aligns with the goal of completing a marathon, and time-bound because it specifies a regular interval (every other week) for progress tracking. Options A, B, and C are also specific and measurable but lack the regular interval and gradual progression aspects of a SMART goal.
In a SMART goal setting system, an action-oriented objective is one that focuses on specific actions to achieve the desired outcome. Among the given options, B) Run on the trail 4 times a week is the most action-oriented objective. This objective clearly outlines the action (running on the trail) and the frequency (4 times a week), making it easier to track progress and achieve the goal. The other options focus more on outcomes or results, which are important aspects of a goal, but they do not explicitly state the specific actions needed to reach those outcomes.
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What is the frequency of a wave moving at 1782 m/s if its wavelength is 30.2 m?
Answers
Answer:
Explanation:
Wavelength = Velocity / Frequency
= 1782/30.2
= 59 metre.
12. A 4,000 kg truck and a 2,000 kg car are both traveling at 10 m/s when they hit a wall.
Which vehicle has more momentum just before striking the wall? What is the ratio of their
momenta?
Answers
The object with greater mass will have greater momentum. Hence, the 4000 kg truck with 10 m/s speed has greater momentum than 2000 kg car moving with the same speed.
What is momentum ?Momentum of an object is the product of its mass and velocity.
P = m v
Momentum increases with both mass and velocity.
If two objects of same mass having different speed, the one with greater speed will have greater momentum. Similarly, if they move with same speed but having different masses, then the greater mass have greater momentum.
Given
mass of truck = 4000 kg
v = 10 m/s
P = 40000 kg m/s
Mass of car = 2000 kg
v = 10 m/s
P = 20000 kg m/s.
Hence, the truck have greater momentum. The ratio of the momentum of truck to the car is 2:1.
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Which statement describe newtons first law?
Answers
Newton's first law, also known as the law of inertia, states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.
It implies that any object, either stationary or in motion, would remain as it is, unless an external force acts on it. When an external force is applied, it results in a change in motion in terms of direction, speed, or both. This is a statement that describes Newton's first law of motion.Basically, Newton's First Law of Motion states that a body at rest remains at rest and a body in motion maintains uniform motion in a straight line, unless acted upon by an external force.
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What value of resistor R gives the circuit in the figure a time constant of 22 μs ?
Answers
The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.
The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:
RC = τ, where R is the resistance and C is the capacitance of the circuit.
Rearranging the above formula, we get:R = τ / C
Where τ is the time constant and C is the capacitance of the circuit.
From the figure, the capacitance is given as 0.1 μF
.Substituting the values of τ and C in the above formula, we get:
R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)
R = 220 Ω
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The state in which the inside of each heart cell is negatively charged and the outside is positively charged is:
Answers
Answer:
Resting state
Explanation:
activity 1 more or less, pls answer this ASAP
Answers
Answer:
ididate is a good one and
The position of a particle along a straight-line path is defined by s=(t³−6t²−15t+7)ft, where t is in seconds. Determine the total distance traveled when t=9.00 s. What is the particle's average velocity at time t=9.00 s ? What is the particle's average speed at time t=9.00 s ?
Answers
To determine the total distance traveled when t = 9.00 s, we need to find the displacement between the initial and final positions of the particle.
Given:
s = t³ - 6t² - 15t + 7
To find the initial position, substitute t = 0:
s(0) = (0³) - 6(0²) - 15(0) + 7
s(0) = 7 ft
To find the final position, substitute t = 9.00 s:
s(9) = (9³) - 6(9²) - 15(9) + 7
s(9) = 729 - 486 - 135 + 7
s(9) = 115 ft
The displacement between the initial and final positions is:
Δs = s(9) - s(0)
Δs = 115 - 7
Δs = 108 ft
Therefore, the total distance traveled when t = 9.00 s is 108 ft.
To calculate the average velocity at time t = 9.00 s, we need to find the instantaneous velocity at that time.
The velocity function is the derivative of the position function:
v = ds/dt
Given:
s = t³ - 6t² - 15t + 7
Differentiating s with respect to t:
v = ds/dt = 3t² - 12t - 15
Substitute t = 9.00 s:
v(9) = 3(9²) - 12(9) - 15
v(9) = 243 - 108 - 15
v(9) = 120 ft/s
Therefore, the particle's average velocity at time t = 9.00 s is 120 ft/s.
To calculate the average speed at time t = 9.00 s, we need to find the total distance traveled divided by the time taken.
Average speed = total distance / time
Given:
Total distance = 108 ft
Time = 9.00 s
Average speed = 108 ft / 9.00 s
Average speed = 12 ft/s
Therefore, the particle's average speed at time t = 9.00 s is 12 ft/s.
Total distance traveled when t = 9.00 s: 108 ft
Particle's average velocity at time t = 9.00 s: 120 ft/s
Particle's average speed at time t = 9.00 s: 12 ft/s
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PLS HELP DUE IN 30 MINS!!! True or false: A large-amplitude pulse travels at a faster speed than a small-amplitude pulse. Explain your answer.
Answers
Answer:
False
Explanation:
Larger pulse with more energy means that the wave has large amplitude. As in the given question, both the waves are travelling in the same medium, hence their speeds will remain same and therefore the larger pulse will not overtake the smaller pulse. Remember the amplitude of a wave does not affect the speed at which the wave travels
Answer:
False
Explanation:
The amplitude of a wave does not affect the speed at which the wave travels. The speed of a wave is only altered by alterations in the properties of the medium through which it travels.