you are testing a jet back pack on a dummy. you start it rising with an upward acceleration of 3 m/sec/sec. after 9 seconds the jetpack fails (upward acceleration stops, gravity takes over). how fast is the dummy moving when it hits the ground?
Answers
The dummy was moving at a velocity of approximately 93 m/s (or 335 km/h) just before hitting the ground.
Find the velocity of the dummy when the jetpack fails,
v = u + at
where v is final velocity, u is initial velocity (which is 0 m/s in this case), a is acceleration (which is 3 m/s^2 in the upward direction), and t is time (which is 9 seconds).
v = 0 + (3 m/s^2)(9 s) = 27 m/s
Distance traveled,
s = (1/2)at^2
s = (1/2)(-9.8 m/s^2)(9 s)^2
s = -441 m (taking upward direction as positive)
Here, we have taken the upward direction as positive and the negative value of s indicates that the dummy fell a total distance of 441 meters after the jetpack failed.
v^2 = 0 + 2(-9.8 m/s^2)(-441 m)
v^2 = 8623.6 m^2/s^2
v = 93 m/s (approx)
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Related Questions
calculate the reactance of, and rms current in, a 260-mh radio coil connected to a 240-v (rms) 10.0-khz ac line. ignore resistance.
Answers
The reactance of the 260 mH radio coil connected to the 240 V (rms) 10.0 kHz AC line is approximately 1633.6 Ω, and the RMS current flowing through the circuit is approximately 0.147 A.
To calculate the reactance (X) of the 260 mH radio coil and the RMS current (I) in the circuit, we can use the following formulas:
Reactance (X) = 2πfL,
RMS current (I) = V / X,
where f is the frequency, L is the inductance, V is the voltage, and X is the reactance.
Given:
Inductance (L) = 260 mH = 0.260 H,
Voltage (V) = 240 V,
Frequency (f) = 10.0 kHz = 10,000 Hz.
Calculating the reactance:
X = 2πfL = 2π(10,000 Hz)(0.260 H) ≈ 1633.6 Ω.
To calculate the RMS current, we can use Ohm's law:
I = V / X = 240 V / 1633.6 Ω ≈ 0.147 A (rounded to three significant digits).
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Two objects are experiencing a force of gravitational attraction. If you triple the mass of one of the objects and double the distance between their centres, the new force of gravity compared to the old (Fg) will be: A) 3 Fg B) 1.5 Fg C) 0.75 Fg D) the same
Satellite A and B are both in stable orbit of the Earth, but Satellite B is twice as far from the Earth's centre. Compared to Satellite A, the orbital period of Satellite B is a) 2.83 times larger b) 1.41x larger c) The same d) 0.70 times as large e) 0.35 times as large
Answers
To determine the new force of gravity in the first scenario, we can use the formula for gravitational force:
\(Fg = (G * m1 * m2) / r^2,\)
where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers.
If we triple the mass of one object and double the distance between their centers, the new force of gravity can be calculated as follows:
New \(Fg = (G * (3m) * m) / (2r)^2.\)
Simplifying this expression, we get:
New Fg = (G * 3m * m) / (4r^2).
Since (3m * m) / (4r^2) is equivalent to (3/4) * (m * m) / (r^2), we can rewrite the equation as:
New \(Fg = (3/4) * (G * m * m) / r^2.\)
Comparing this to the original force of gravity, Fg, we see that the new force is (3/4) times the original force. Therefore, the answer is C) 0.75 Fg.
Regarding the second scenario, for objects in stable orbit, the orbital period is determined by the formula:
\(T = 2π * sqrt(r^3 / (G * M)),\)
where T is the orbital period, r is the distance between the center of the object and the center of the Earth, G is the gravitational constant, and M is the mass of the Earth.
If Satellite B is twice as far from the Earth's center compared to Satellite A, we can say that r_B = 2 * r_A.
Let's compare the orbital periods of the two satellites:
T_B = 2π * sqrt((2r_A)^3 / (G * M)) = 2π * sqrt(8r_A^3 / (G * M)).
T_A = 2π * sqrt(r_A^3 / (G * M)).
Dividing T_B by T_A, we get:
T_B / T_A = (2π * sqrt(8r_A^3 / (G * M))) / (2π * sqrt(r_A^3 / (G * M))).
Simplifying this expression, we find:
T_B / T_A = sqrt(8r_A^3 / (r_A^3)) = sqrt(8) = 2.83.
Therefore, the answer is a) 2.83 times larger.
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When two objects are experiencing gravitational attraction, if you triple the mass of one of the objects and double the distance between their centers, the new force of gravity compared to the old will be 0.75 times the original force (0.75 Fg).The orbital period of Satellite B compared to Satellite A is 2.83 times larger.
This is because the force of gravitational attraction between two objects is inversely proportional to the square of the distance between their centers of mass. If you double the distance between two objects, the force of gravitational attraction decreases by a factor of 4 (2^2). On the other hand, if you triple the mass of one of the objects, the force of gravitational attraction increases by a factor of 3.
Therefore, combining these effects, the new force of gravity will be 3/4 or 0.75 times the original force.
Satellite A and Satellite B are both in stable orbit around the Earth, but Satellite B is twice as far from the Earth's center as Satellite A. The orbital period of Satellite B compared to Satellite A is 2.83 times larger.
This is because the orbital period of an object in circular motion is dependent on the radius of the orbit. The further an object is from the center of the orbit, the longer it takes to complete one full orbit. Since Satellite B is twice as far from the Earth's center as Satellite A, its radius is also twice as large. The orbital period is directly proportional to the radius, so Satellite B's orbital period will be 2.83 times larger than Satellite A's orbital period.
Therefore, the correct statement is:
The new force of gravity compared to the old will be 0.75 Fg.
The orbital period of Satellite B compared to Satellite A is 2.83 times larger.
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What is the speed of a wave that has a frequency of 110 Hz and a wavelength
of 0.21 m?
OA. 23.1 m/s
OB. 0.04 m/s
O C. 523 m/s
OD. 0.002 m/s
Answers
The speed of the wave of wavelength 0.21 m is 23.1 m/s. And the correct answer is 0A. 23.1 m/s.
How to calculate the speed of a wave?The speed of a wave is calculated by multiplying the wavelength and the frequency of the wave.
To calculate the speed of the wave, we use the formula below.
Formula:
s = λf......................................Equation 1Where:
s = Speed of the waveλ = Wavelength of the wavef = Frequency of the waveFrom the question,
Given:
f = 110 Hzλ = 0.21 mSubstitute these values into equation 1
s = 110×0.21s = 23.1 m/sHence, the speed of the wave is 23.1 m/s.
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What is the Doppler Effect in Physics?
Answers
The Doppler Effect in Physics is a phenomenon that occurs when there is a change in the frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source.
The Doppler effect occurs when there is relative motion between a source or receiver of sound or electromagnetic waves, resulting in a change in the observed frequency of the waves.
This effect is commonly observed in the change in pitch of a siren as it moves towards or away from an observer. As the siren moves towards the observer, the sound waves are compressed, causing the frequency to increase and the pitch to become higher. Conversely, as the siren moves away from the observer, the sound waves are stretched, causing the frequency to decrease and the pitch to become lower.
The Doppler Effect also applies to light waves, causing the color of an object to shift towards the blue end of the spectrum as it moves towards an observer, and towards the red end of the spectrum as it moves away.
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during the light reactions what structure is responsible for absorbing the solar energy?
Answers
Chloroplasts are responsible for absorbing the solar energy during the light reactions.
Chloroplasts are the cellular organelles of plants and green algae that are responsible for carrying out photosynthesis.
Photosynthesis is the process of metabolism that allows certain organisms to synthesize organic substances using sunlight as an energy source.
Chloroplasts have vesicles called thylakoids that house molecules capable of transforming light energy from the sun's rays into chemical energy.
One of these storage molecules is chlorophyll, a green photosynthetic pigment that absorbs light energy.
Each chlorophyll molecule has:
A phytol chain (which allows chlorophyll to remain integrated in the photosynthetic membrane).A ring of porphyrin (which develops the absorption of light).Therefore, Chloroplasts are responsible for absorbing the solar energy during the light reactions, chlorophyll being, specifically, an essential biomolecule for the development of photosynthesis.
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An___ is a pure substance that cannot be separated into any other substance
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A force of 16 lb is required to hold a spring stretched 4 inches beyond its natural length. How much work is done in stretching it from its natural length to 10 inches beyond its natural length?
Answers
The work done in stretching the spring from its natural length to 10 inches beyond its natural length is 112 lb·in.
The work done in stretching a spring is given by the formula:
\(\[ W = \frac{1}{2} k (x_f^2 - x_i^2) \]\)
In this case, the spring is stretched 4 inches beyond its natural length, so the initial displacement is 4 inches. The force required to hold the spring at this displacement is 16 lb. We can use Hooke's Law to find the spring constant:
\(\[ k = \frac{F}{x_i} = \frac{16 \, \text{lb}}{4 \, \text{in}} = 4 \, \text{lb/in} \]\)
Now, we can calculate the work done in stretching the spring to 10 inches beyond its natural length:
\(\[ W = \frac{1}{2} (4 \, \text{lb/in}) \left( (10 \, \text{in})^2 - (4 \, \text{in})^2 \right) = 112 \, \text{lb·in} \]\)
Therefore, the work done in stretching the spring is 112 lb·in.
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Can someone help me
Answers
Answer:
C?
Explanation:
Physics assignment <3 [100 points]
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Answers
Case B: All of the forces that have been applied on this object are in balance because they all cancel each other out. In conclusion it means that the object is not moving.
Case C: The forces that have been applied to this object are unbalanced. Therefore the object will move to the right because it has a force of 2N
Porque deja de funcionar una estufa electrica cuando la electricidad es excesiva??
Answers
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Could you sky-dive on the Moon? Why or why not?
Answers
Answer:
no
Explanation:
the moon's force of gravity is not strong enough to pull you down compared to earth, so you will just float
A 0. 0850-kg arrow is fired horizontally. If the bowstring exerts an average force of 89. 0 n on the arrow over a distance of 0. 782 m, with what speed does the arrow leave the bow?.
Answers
The arrow leaves the bow at a speed of 40.47 m/s.
When the arrow is released from its bow, the arrow will move and accelerate. Newton's second law of motion applies to the arrow. The formula F = ma
m = mass of the arrow (kg) = 0.0850 kga = acceleration of the arrow (m/s²)F = force (N) = 89.0 N\(a \:=\: \frac{F}{m}\)
\(a \:=\: \frac{89.0}{0.0850}\)
a = 1,047.059 m/s²
When the object has acceleration, the object will move in a non-uniform motion. The formula
v = u+atv² = u² + 2ad\(d \:=\: v_0 \times t \:+\: \frac{1}{2} \times a \times t^2\)u = initial speed (m/s) = 0 m/s (arrow stationary in bowstring)v = final speed (m/s) a = acceleration (m/s²) = 1,047.059 m/s²t = interval (s)d = distance (m) = 0.782 mv² = u² + 2ad
v² = 0² + (2×1,047.059×0.782)
v² = 1,637.6
\(v_t \:=\: \sqrt{1,637.6}\)
\(v_t\) = 40.47 m/s
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At what time of day do we use more energy? Why?
Answers
Answer:
The bottom line
That's because our internal clocks tend to use up the most calories from 4 p.m. to 6 p.m. and the least from 4 a.m. to 6 a.m., researchers concluded. If we're up late and eating when our bodies are using up fewer calories, those calories get stored instead, which can result in weight
Explanation:
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The acceleration due to gravity on Mimas a moon on Saturn, is 0.066m/s^2 . Starting from rest how much time does it take for an object to fall 10m on Mimas?
Answers
The equation to obtain the vertical distance cobered by the object is,
\(h=ut+\frac{1}{2}gt^2\)The acceleration due to gravity on saturn is 0.066 m/s2.
Plug in the known values,
\(\begin{gathered} 10\text{ m=(0 m/s)t+}\frac{1}{2}(0.066m/s^2)t^2 \\ t^2=\frac{2(10\text{ m)}}{0.066m/s^2} \\ t=\sqrt[]{303.03s^2} \\ \approx17.4\text{ s} \end{gathered}\)Thus, the time taken by object to fall is 17.4 s.
A golf ball is initially travelling at 25m/sec hits a sand traps and slow down with an acceleration of -25m/sec. find its displacement after 2.0 sec.
Answers
The displacement of the ball is zero.
What is displacement?
The smallest distance between the initial and final position of an object.
What are the equations of motion?
There are three equations of motion that completely describes the motion of an object.
The first equation of motion gives the relationship between the initial velocity, final velocity, acceleration, and time.
The second equation of motion gives the relationship between the initial velocity, displacement, acceleration, and time.
The third equation of motion gives the relationship between the initial velocity, final velocity, acceleration, and displacement.
Given time, initial velocity, and acceleration, the displacement can be calculated using the second equation of motion. The second equation of motion is,
s=u*t+(1/2)*a*t^2
Here, u=25 m/sec, a=-25 m/sec and t=2.0 sec.
Put the values in the formula and calculate the displacement.
s= (25)*(2.0)+(1/2)*(-25)*(2.0)^2
s=50-50
s=0 m.
Hence the displacement of the ball is zero.
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find net force and acceleration
Answers
Rightward acceleration is 16.5 m/s² and the net force is 165 N. The acceleration of an object is determined by its mass divided by the net force acting on it, in accordance with Newton's second law of motion.
The net force formula is what?The total of all forces exerted on an object is known as the net force. A mass can accelerate due to net force. A body is subject to another force whether it is at rest or in motion.
How does an item accelerate as a result of net force?A moving item accelerates due to resultant force. Always moving in the same manner as the net force is acceleration. When something is being pushed to the right with more force than resists and its resultant torque is to the right, it will accelerate to the right.
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Hello, I am currently stuck on this question and I am very confused as to how to solve it, may I have some help?
Answers
Recall, Newton's gravitational law states that any particle of matter in the universe attracts any other particle with a force varying directly as the product of their masses and inversely as the square of the distance between them. It is expressed as
F = Gm1m2/r^2
where
F is the force in Newton
G is gravitational constant = 6.673 x 10^-11 Nm^2/kg^2
m1 and m2 are the masses in kg
r is the distance in meters
From the information given,
r = 1.5
acceleration = 2cm^2/s
Recall, 100 cm = 1m
2 cm = 2/100 = 0.02m
Thus,
acceleration = 0.02m/s^2
Since the masses are identical, then m1 = m2
Each of them is accelerating at 0.02m/s^2
Recall,
Force = mass x acceleration
Force = m1 x 0.02 = 0.02m1 N
By substituting the given values into the formula, we have
0.02m1 = (6.673 x 10^-11 x m1 x m1)/1.5^2
m1 on the left cancels out one m1 on the right. It becomes
0.02 = (6.673 x 10^-11 x m1)/1.5^2
By crossmultiplying,
0.02 x 1.5^2 = 6.673 x 10^-11 x m1
0.045 = 6.673 x 10^-11 x m1
m1 = 0.045/6.673 x 10^-11
m1 = 6.74 x 10^8 kg
The mass of each ball is 6.74 x 10^8 kg
1. A stone is dropped from the top of the tower and reaches the ground in 6 seconds. Find the height of the tower.
Answers
Answer:
176.4 m
Explanation:
To calculate the distance, the equation would be:
distance = acceleration X time² / 2
Assuming the stone is held at a complete stop before dropping, the acceleration would be equal to gravity which is 9.8m/s². So:
d = (9.8m/s²)( 6s)² / 2
= (9.8m/s²)(36s²) / 2
= 176.4 m
at rest, hydrogen has a spectral line at 163 nm. if this line is observed at 157 nm for the star proxima, how fast is proxima moving in km/s?
Answers
At rest, hydrogen has a spectral line at 163 nm. If this line is observed at 157 nm for the star proxima, how fast is proxima moving in km/s is as follow:
The change in wavelength of a spectral line due to the Doppler effect is given by
Δλ/λ=ν/c
where Δλ is the change in wavelength, λ is the wavelength of the spectral line, ν is the velocity of the object towards or away from the observer, and c is the speed of light.
Using this equation, the velocity of Proxima can be found.
Δλ/λ = ν/c
where λ = 163 nm(spectral line for hydrogen), and Δλ = 163 nm - 157 nm = 6 nm (since the spectral line is observed at 157 nm instead of 163 nm)
ν = Δλ * c / λ
= 6 nm * 3.00 x 10^8 m/s / 163 nm
= 1.1 x 10^7 m/s
Now, to convert this velocity into km/s, divide by
1000:1.1 x 10^7 m/s ÷ 1000 m/km
= 11,000 km/s
Therefore, Proxima is moving away from us at a velocity of 11,000 km/s.
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If one soccer ball is rolling to the right at 3 m/s and another soccer ball is rolling left with a speed of 5 m/s, how much momentum is there in this system before they collide with each other? Both have a mass of 1 KG
Answers
Answer:
Final momentum after a head on collision is -2kgm/
Explanation:
One ball moves to the right and the other moves opposite and momentum is a vector quantity so that considering the direction
Initial momenta are P₁=2x3=6kgm/s P₂=4x(-2)=-8kgm/s
Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s
What is the name of the following atoms?
a) An atom with 3 protons and 4 neutrons:
b) An atom with 2 protons and 4 neutrons:
c) An atom with 4 protons and 4 neutrons:
Answers
Answer:
an atom with 3 protons and 4 neutrons
Explanation:
The coefficient of static friction between a block and the floor is 0.60 and the coefficient of kinetic friction
If a 20-kg block is pushed across the floor by a horizontal force with a constant speed. What is the force applied t
A)
50 N
B)
100 N
C)
120 N
D)
200 N
Answers
Answer: B) 100N
Explanation:usatestprep
gaya adalah...?? [tolong yaaa..]
Answers
I can try to help if you speak English
After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg bowling pin initially at rest. Find the final velocity of the second pin in the following situations: a) The first pin moves to the right after the collision at 0.8 m/s. Answer in units of m/s. 010 (part 2 of 2) 10.0 points b) The first pin stops moving when it hits the second pin. Answer in units of m/s
Answers
Answer:
a) v₂ = 4.2 m/s
b) v₂ = 5 m/s
Explanation:
a)
We will use the law of conservation of momentum here:
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0.8 m/s
v₂ = speed of second after before collsion = ?
Therefore,
\((1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s\)
v₂ = 4.2 m/s
b)
We will use the law of conservation of momentum here:
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0 m/s
v₂ = speed of second after before collsion = ?
Therefore,
\((1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)\)
v₂ = 5 m/s
what is the work done on the ball by the 10 n tension force in the string during one revolution of the ball?
Answers
The work done on the ball by the 10 N tension force is zero ( 0 Joules).
Given that:
The circumference(displacement d) of the ball = 3 m
the tension force of the ball = 10 N
the angle θ between the tension force and the displacement =90°
∴Using the work equation;
W = F × d cos θ
W = 10×3× cos (90)
W = 10 × 3 × 0
W = 0 Joules
The definition of work done includes both the forces applied to the body and the total displacement of the body. A constant force F is present before to this block. The goal of this force is to move the body d meters in a straight line in the force's direction.
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Read the scenario. A car starts 10 m north of a reference point. It moves at a constant velocity over the next 5 s, reaching a position of 10 m south of the reference point. What is the car’s average velocity? 2 m/s south 4 m/s north 0 m/s 4 m/s south
Answers
Answer:
4 m/s south
Explanation:
This is a pretty easy one.
Assume that the car has a reference point ragged x
We also know that the car starts moving at a point 10 m North of X. It moves steadily at a uniform velocity and ended at a position 10 m south of X.
If x is the reference point, we can infer that the car moves a total distance of, 10 m + 10 m.
Thus, the total distance moved by the car is 20 m.
It is also stated that it achieves that distance in 5 seconds.
Velocity is defined as the ratio of distance with respect to the tome taken, i.e V = d/t
Then, the velocity is
V = 20 / 5 = 4 m/s
Considering the fact that the car left and moved towards the south. We can say that it moved 4 m/s South.
The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column? Column 1 0 2 4. 6 8 10 Column 2 5 10 15 20 25 30 Column 1 should be titled "Time," and Column 2 should be titled "Velocity." Column 1 should be titled "Velocity," and Column 2 should be titled "Time." Column 1 should be titled "Time," and Column 2 should be titled "Acceleration." O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."
Answers
Answer:
Explanation:
Since we are looking at speed over a time unit, we have an acceleration graph. The definition of acceleration mathematically is:
\(a=\frac{v_f-v_0}{t}\) (that's the change in velocity over the change in time). The slope of any line in this graph wil represent the acceleration. Slope is rise over run, or y over x. Therefore, if acceleration is velocity over time, then the y axis is the velocity axis and the x axis is the time axis. It makes perfect, beautiful sense!!
What is the angular displacement (in radians) of a person standing at the Earth's equator for 6 hours assuming the Earth has a diameter of 13750 km
Answers
Answer:
π/2 radians.
Explanation:
Angular Displacement
It's the angle expressed in radians, degrees, revolutions, etc. through which a point revolves around a point called the center.
To find the angular displacement, we must recall a full revolution, or turn around the center measures 360 degrees, or 2π radians.
The Earth completes a turn every 24 hours. This means that in 6 hours, it has given 6/24 = 1/4 of a turn.
This means that, measured in radians, the angular displacement of a person during 6 hours is:
1/4*2π radians
Simplifying:
π/2 radians.
Find the maximum energy stored in the spring bumpers
Answers
The maximum energy stored in the spring bumpers is given as ¹/₂kx².
Maximum energy stored in a springThe maximum energy stored in a spring is given by the following equations;
E = ¹/₂kx²
where;
E is the energy stored in the springk is spring constantx is extension of the springThus, the maximum energy stored in the spring bumpers is given as ¹/₂kx².
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What is the conversion of how many kilograms are in 48 ounces
Answers
Answer:1.36078
Explanation: