The center of mass is usually near the middle of the suitcase and about halfway up its height and at a height that allows you to maintain good balance and control while running.
For a carry-on suitcase,. Keeping the center of mass low and close to your body can help reduce the amount of effort required to carry the suitcase, as well as improve stability and control while running.
When running with a suitcase, it's important to keep your upper body as upright and relaxed as possible, while allowing your legs and arms to move freely. This will help you maintain balance and reduce the strain on your muscles and joints. Additionally, it's helpful to grip the handle of the suitcase firmly, but not too tightly, so that you have control over its movement.
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how to sketch the following:Sketch a ray diagram for a spherical convex lens with an object at Do = 2f. (Submit a file with a maximum size of 1 MB.)
Do = 2f means that object distance is 2 x focal length.
2 x focal length = radius of curvature
When an object is placed at the radius of curvature, a real, inverted image is formed at the other radius of curvature. The sizes of the image and the object are the same. The sketch is shown below
When the car comes to a sudden stop, the passenger ________ in motion
Answer:
If the car comes to a sudden stop, your body tends to keep moving forward.
Explanation:
The water hyacinth lives in lakes and ponds it forms large floating mats of plants because it does not root in soil which adaptation lets it get nutrients directly from the water is it A.1 curly leaves B.Trailing C.Sturdy stems D. Upright flowers
Answer:
C. Sturdy stems
Explanation:
Sturdy stems is the adaptation that enables water hyacinth to get nutrients directly from the water because there is no roots are present for the absorption of nutrients from water. The hollow bulbous stem below each leaf of water hyacinth allows the plant to get nutrients from the water. This hollow bulbous stem allow the plants to float on the water surface, keeping the leaves and flowers above the water so they don't rot.
George walks to a friend's house. He walks 750 meters North, then realizes he walked
too far. He turns around and walks 250 meters South. The entire walk takes him 13
seconds.
Answer:
I think you are looking for the velocity, so the answer is 38.5 m/s
Explanation:
Velocity is giving by displacement/time. North will be positive and South will be negative, George travels 750 meters then travels -250 meters his displacement is then 750 - 250 or 500 meters. Divide that by 13 seconds to get 38.5 m/s.
A roller-coaster car has a potential energy of 250 000 J and a kinetic energy of 65 000 J at point A in its travel. At the low point of the ride, the potential energy is zero, and 35 000 J of work have been done against friction since it left point A. What is the kinetic energy of the roller coaster at this low point
The kinetic energy of the roller coaster at the low point of the ride is 280 000 J.
To find the kinetic energy of the roller coaster at the low point, we need to consider the conservation of mechanical energy, which states that the total mechanical energy remains constant if only conservative forces act on the object. The total mechanical energy is the sum of the potential energy and the kinetic energy.
At point A, the total mechanical energy is:
Total Energy = Potential Energy + Kinetic Energy
Total Energy = 250,000 J + 65,000 J = 315,000 J
Since 35,000 J of work have been done against friction, we need to subtract this value from the total mechanical energy:
Total Energy - Work Done = 315,000 J - 35,000 J = 280,000 J
At the low point, the potential energy is zero, so the remaining energy is kinetic energy:
Kinetic Energy = Total Energy - Potential Energy
Kinetic Energy = 280,000 J - 0 J = 280,000 J
So, the kinetic energy is 280,000 J.
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A 3.00 m long rod (I=1/3ML2) with a mass of 10.0 kg is set so that it pivots around its end. The rod is pulled back until it is horizontal and released. A small spherical ball with a mass of 4.00 kg is placed directly under the pivot point of the rod so that the end of the rod strikes the ball when it is vertical.
What is the angular velocity at the bottom before it hits the ball?
Hi there!
Assuming the rod is pulled back 90° (π/2 radians), we can use angular kinematics to solve.
Using the equation:
\(\omega_f^2= \omega_i^2 + 2\alpha \theta\)
\(\omega_f\) = final angular velocity (? rad/sec)
\(\omega_i\) = initial angular velocity (0 rad/sec)
\(\alpha\) = angular acceleration (rad/sec², must solve for)
\(\theta\) = angular displacement (π/2 rad)
Recall Newton Second Law's rotational equivalent:
\(\Sigma \tau = I\alpha\)
τ = Torque (Nm)
I = Moment of inertia (kgm²)
α = angular acceleration (rad/sec²)
Setting the pivot point at the end, and knowing that the force of gravity works at an object's center of mass (1.5m from the rod's end), we can solve for the angular acceleration.
\(\tau= F \times r\\\\\tau = W \times r = 10(9.8) * 1.5 = 147 Nm\)
Now, solve for the moment of inertia given I = 1/3ML² at one of its ends:
\(I = \frac{1}{3}(10)(3^2) = 30 kgm^2\)
Solve for the angular acceleration:
\(147 = 30\alpha\\\\\alpha = 4.9 \frac{rad}{sec^2}\)
Now, we can use the kinematic equation to solve.
\(\omega_f^2 = 0 + 2(4.9)(\frac{\pi}{2}})\\\\\omega_f = \sqrt{2(4.9)(\frac{\pi}{2})} = \boxed{3.923 \frac{rad}{sec}}\)
When the velocity of an object is tripled, by what factor is its momentum changed ?
Answer:
also tripled, factor of 3
Explanation:
equation of momentum is p = m * v , where p=momentum, m=mass, and v=velocity
if m is unchanged
p1 = m1 *v1
p2 = m2 *v2
m1 = m2 and v2 = 3*v1
p2 = m1 * 3v1 = 3*p1, tripled momentum
A 50.0 kg object is moving east at an unknown velocity when it collides with a 60.0 kg stationary object. After collision, the 50.0 kg object is traveling at a velocity of 6.0 m/s 50.0degree N of E and the 60.0 kg object is traveling at a velocity of 6.3 m/s 38degree S of E.
What was the velocity of the 50.0 kg object before collision?
p=m•v is the formula.
The principle of conservation of momentum states that:
momentum before collision = momentum after collisionMomentum = mass * velocityMomentum before collision:
Velocity of 50.0 kg object = v m/s
Momentum of 50.0 kg object = 50 * v
Momentum after collision:
Velocity of the 50.0 kg object = 6.0 m/s 50.0degree N of E
Velocity of the 60.0 kg object = 6.3 m/s 38degree S of E.
Momentum of 50.0 kg object = 50 * 6 = 300 kgm/s
Momentum of 50.0 kg object = 60 * 6.3 = 378 kgm/s
Total momentum after collision = 678 kgm/s
From the principle of conservation of momentum:
50 kg * v = 678 kgm/s
v = 678 kgm/s / 50 kg
velocity, v = 13.56 m/s
Therefore, the velocity of the 50.0 kg object before collision was 13.56 m/s.
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Chester is pushing a Ca1 with 2-50kg sacks on it. Neglecting the mass of the cart, how much force will he exate it to 1.2 m/s2 (neglect friction)?
Chester will need to exert a force of 120 Newtons to accelerate the cart at a rate of 1.2 m/s^2, neglecting the mass of the cart and assuming there is no friction.
To determine the force exerted by Chester to accelerate the cart, we can utilize Newton's second law of motion, which states that the force acting on an object is equal to the product of its mass and acceleration. In this scenario, the mass of the cart itself is neglected, so the total mass to consider includes the two 50 kg sacks, resulting in a total mass of 100 kg.
Newton's second law can be expressed as F = m * a, where F is the force, m is the mass, and a is the acceleration. Substituting the given values, we have:
F = (100 kg) * (1.2 m/s^2) = 120 N
Therefore, Chester will need to exert a force of 120 Newtons to accelerate the cart at a rate of 1.2 m/s^2, neglecting the mass of the cart and assuming there is no friction. This force will provide the necessary push to overcome the inertia of the combined mass and achieve the desired acceleration. However, it is important to note that in real-world scenarios, additional factors such as friction and air resistance would need to be considered, which may require greater force exertion by Chester to achieve the desired acceleration.
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For reasons known only to them, a group of extraterrestrials offers you your choice of three gold ingots. One weighs 10 lb on Earth, the second weighs 10 lb on Jupiter, and the third weighs 10lb on the Moon. To get the most gold, you should choose the ingot that weighs 10 lb on
A. Earth.
B. the Moon.
C. Jupiter.
D. No difference: 10 lbs is 10 lbs, wherever you go.
The answer is A. Earth. This is because the value of gold is determined by its weight and mass, which is the same on Earth and in the extraterrestrial market.
Therefore, the ingot that weighs 10 lb on Earth will have the most gold, regardless of its weight on other planets.To get the most gold, you should choose the ingot that weighs 10 lb on Jupiter because the gravity on Jupiter is much stronger than on Earth and the Moon. The ingot's mass will be greater if it weighs 10 lb under Jupiter's gravity, resulting in more gold for you.
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The activity of a radioactive material drops to 1/16 of its original value in 20 years. What is its half life?
Answer: 5 years
Explanation:
Expression for rate law for first order kinetics is given by:
\(t=\frac{2.303}{k}\log\frac{a}{a-x}\)
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant = x
a - x = amount left after decay process = \(\frac{x}{16}\)
a) for calculating k
\(20=\frac{2.303}{k}\log\frac{x}{\frac{x}{16}}\)
\(k=\frac{2.303}{20}\log{16}\)
\(k=0.138years^{-1}\)
b) for calculating half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
\(t_{\frac{1}{2}}=\frac{0.693}{0.138years^{-1}}\)
\(t_{\frac{1}{2}}=5years\)
Thus its half life is 5 years
A cube of a material with a density of 4230 kg/m^3 has a volume of 0.00100 m^3 and a weight of 41.5 N. When the cube is placed in water with a density of 1000. kg/m^3, what buoyant force acts on the material?
Answer:
The buoyant force is 9.8 N.
Explanation:
The buoyant force acting on the material is called upthrust, and can be determined as;
Upthrust = density of liquid x volume of object x gravitational force
So,
density = \(\frac{mass}{volume}\)
⇒ mass = density x volume
= 4230 x 0.001
= 4.23
mass of the material = 4.23 kg
But,
weight = mass x gravitational force
weight = 41.5 N, and mass = 4.23 kg, then;
41.5 = 4.23 x g
g = \(\frac{41.5}{4.23}\)
= 9.811
g = 9.8 m/\(s^{2}\)
Upthrust = 1000 x 0.001 x 9.81
= 9.81 N
The buoyant force is 9.8 N.
Given that R1 is 13 Ω, R2 is 10 Ω, and R3 is 4 Ω, what is the current coming out of the 9-V battery? What is the power dissipation of each resistor?
When observed from Earth, some stars appear red. What is the cause of redshift?
A.The star is at rest relative to Earth.
B. The star is in a very distant location and is moving away from Earth.
C. The star is moving toward Earth at decreasing speed.
D. The star is moving toward Earth at increasing speed.
Answer:
B
Explanation:
This is the discovery of redshift that led scientist to say the universeis still expanding
Calculate the momentum of a 1kg box moving at a velocity of 50 m/s.
the momentum = m * v
m : mass
v : velocity
momentum = 1 * 50 = 50 kg.m/s
I need help please!!
Answer:
A , C , E
they are all multiples of 3
1 2 3 4 5 6 7 8 9 10 Physical activity and exercise typically lead to __________. A. increased stress B. depression C. higher energy levels D. reduced quality of life Please select the best answer from the choices provided. A B C D
Physical activity and exercise typically lead to higher energy levels (C).
What is physical activity and exercise?Physical activity and exercise refer to any bodily movement that requires energy expenditure by the muscles. This can include activities such as walking, running, cycling, swimming, weightlifting, and team sports, among others.
Physical activity and exercise are important for maintaining good health and well-being, as they can help to improve cardiovascular fitness, muscular strength and endurance, flexibility, and overall body composition.
Physical activity and exercise are known to stimulate the production of endorphins, which are natural mood elevators. This can lead to increased energy levels and a general feeling of well-being.
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Which statement is FALSE regarding the Lewis structure for XeF4? O O O 0 The formal charge on the central atom is not zero. A total of 36 valence electrons are represented. The central atom has lone-pair electrons. It includes only single bonds.
The statement that is FALSE regarding the Lewis structure for XeF4 is that the central atom has lone-pair electrons.
In the Lewis structure for XeF4, xenon (Xe) is the central atom surrounded by four fluorine (F) atoms. Each fluorine atom is bonded to xenon through a single bond, making the total number of valence electrons represented in the structure 36.
The formal charge on the central atom is zero since xenon has eight valence electrons in its outermost shell and is fulfilling the octet rule. However, there are no lone-pair electrons on the central atom, as all of its valence electrons are either involved in the bonding or have paired up to fulfill the octet rule.
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pressure exerted on a surface depends on________
(a) force and pressure
(b) density and area
(c) height and density
(d)Area and density of liquid
Answer:
(a) Force and Pressure
Explanation:
Acc to the formula,
Force = Pressure/Area
Therefore it depends on force and pressure
Is this right?? Please help me. IT IS SOCIOLOGY!
if 20.0 kj of heat are given off when 2.0 g of condenses from vapor to liquid, what is for this substance?
a) ΔHvap for this substance is: -10000 J/mol or -10.00 kJ/mol
b) The molar heat of vaporization for this substance is: 5000 J/mol or 5.00 kJ/mol
c) The substance is: Water.
a) The amount of heat released is given as 20.0 kJ, and the mass of the substance is 2.0 g.
To find ΔHvap, we need to convert the mass of the substance to moles by dividing it by its molar mass, and then use the equation: ΔH = q/moles.
The molar mass of water is 18.02 g/mol, so the number of moles is 2.0 g / 18.02 g/mol = 0.111 mol.
Therefore, ΔHvap = -20.0 kJ / 0.111 mol = -10000 J/mol or -10.00 kJ/mol.
b) The molar heat of vaporization is defined as the amount of heat required to vaporize one mole of a substance.
Since we know ΔHvap for this substance is -10.00 kJ/mol, the molar heat of vaporization is +10.00 kJ/mol.
c) The values obtained for ΔHvap and the molar heat of vaporization are consistent with water, indicating that the substance in question is water.
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The given question is incomplete, so an complete question is written below,
As the question is missing an important part, all the important possibilities which can fill the gap is written below,
a) What is ΔHvap for this substance?
b) What is the molar heat of vaporization for this substance?
c) What is the substance?
an electron is trapped in an infinite well of width 1.31 nm. what are the three longest wavelengths permitted for the electron's de broglie waves?
If an electron is trapped in an infinite well of width 1.31 nm. The three longest wavelengths permitted for the electron's de broglie waves will be 14.39 * \(10^{2}\) m , 5.40 * \(10^{2}\) m and 2.88 * \(10^{2}\) m
1st longest wavelength will be
lambda = 8 * m * \(L^{2}\) * c / h ( \(n_f^{2}\) - \(n_i^{2}\))
m = mass of electron
L = width of infinite well
h = plank's constant
c = speed of light
lambda 1 = 8 * m * \(L^{2}\) * c / h ( \(n_f^{2}\) - \(n_i^{2}\))
= 8 * 9.1 * \(10^{-31}\) * 1.3 * \(10^{-9}\) * 3 * \(10^{8}\) / 6.626 * \(10^{-34}\) ( \(2 ^{2} - 1^{2}\) )
= 14.39 * \(10^{2}\) m
lambda 2 = 8 * 9.1 * \(10^{-31}\) * 1.3 * \(10^{-9}\) * 3 * \(10^{8}\) / 6.626 * \(10^{-34}\) ( \(3^{2} - 1^{2}\) )
= 5.40 * \(10^{2}\) m
lambda 3 = 8 * 9.1 * \(10^{-31}\) * 1.3 * \(10^{-9}\) * 3 * \(10^{8}\) / 6.626 * \(10^{-34}\) ( \(4^{2} - 1^{2}\) )
= 2.88 * \(10^{2}\) m
The three longest wavelengths permitted for the electron's de Broglie waves will be 14.39 * \(10^{2}\) m , 5.40 * \(10^{2}\) m and 2.88 * \(10^{2}\) m
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A grapefruit has a weight on Earth of 4.9 newtons. What is the grapefruit’s mass?
Answer:
0.5 kg
Explanation:
W = mg
4.9 = m(9.8)
4.9 = 9.8m
4.9/9.8 = m
m = 0.5 kg
4. Two students have volunteered to explore the galaxy in a spaceship. As they travel through space, they
measure the magnitude of the gravitational force between their spaceship and the Earth. They find that the
gravitational force on the spaceship is -
A. proportional to the distance from the Earth
B. inversely proportional to the distance from the Earth
C. proportional to the square of the distance from the Earth
D. inversely proportional to the square of the distance from the Earth
Answer:B
Explanation:
They find that the gravitational force on the spaceship is inversely proportional to the distance from the Earth. The correct option is B.
What is gravitational force?The gravitational pull would be stronger if the gap were cut in half. Coulomb's law, states that the gravitational force between two items in the universe is directly proportional to the product of the masses of the objects.
And inversely proportional to the distance between them is used to calculate the gravitational force between two objects in the universe. Whether there is a body there or not, gravity is the force between two bodies.
Everybody in the cosmos is drawn to every other body by a force that is directly inversely correlated to the square of the distance between them and directly inversely correlated to the product of their masses.
Therefore, the correct option is B. inversely proportional to the distance from the Earth.
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plzzzz urgent
solve this
Answer:
\( \large{ \tt{☄ \: EXPLANATION}} : \)
Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .\( \large{ \tt{♨ \:LET'S \: START}} : \)
Acceleration is defined as the rate of change of velocity. We know :\( \large{ \boxed{ \tt{❁ \: ACCELERATION \: (a) = \frac{FINAL \: VELOCITY(v) - INITIAL \: VELOCITY(u)}{TIME \: TAKEN \: ( \: t \: )}}}} \)
- Plug the values & then simplify !
\( \large{ \bf{↬a = \frac{60 - 0}{300} = \frac{60}{300} = \boxed{ \bold{ \bf{0.2 \: m {s}^{ - 2} }}} }}\)
The acceleration of the jeep is 0.2 m/s²\( \large{ \tt{۵ \: AGAIN, \: USING\: SECOND \: EQUATION \: OF \: MOTION}} : \)
\( \boxed{ \large{ \bf{✾ \: s = \frac{u + v}{2} \times t}}}\)
- Plug the values & then simplify !
\( \large{ \bf{↦s = \frac{0 + 60}{2} \times 300 = \boxed{ \bold{ \bf{9000 \: m}}}}}\)
The distance covered by the jeep is 9000 m .❃ The days that break you are the days that make you ! ♪
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Answer:
What she said is right I know it is
The velocity – time graph of an object moving along a straight line is shown in
fig. Find (a) the distance covered and (b) the displacement of the object in time
interval between t = 0 s and t = 10 s
(a) The distance travelled by the object is 100 m.
(b) The displacement of the object in time interval between t = 0 s and t = 10 s is 60 m.
What is the distance covered by the object?(a) The distance travelled by the object is calculated from the total area of the curve.
total distance = area of triangle 1 + area of triangle 2 + area of rectangle.
total distance = (¹/₂ x base x height)₁ + (¹/₂ x base x height)₂ + length x width
total distance = (¹/₂ x 6 s x 20 m/s) + (¹/₂ (8 - 6) 20) + (10 - 0)(10 - 8)
total distance = 60 m + 20 m + 20 m
total distance = 100 m
(b) The displacement of the object in time interval between t = 0 s and t = 10 s is calculated as follows;
displacement = final position - initial position
displacement = (¹/₂ x base x height)₁ + (¹/₂ x base x height)₂ + length x width
displacement = (¹/₂ x 6 s x 20 m/s) + (¹/₂ (8 - 6) (-20)) + (10 - 0)(10 - 8)
displacement = 60 m - 20 m + 20 m = 60 m
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You push really hard against a round rock, but you cannot make it roll. Which statement best explains why you cannot move the rock
(A)Gravity pulls the rock toward the center of Earth.
(B)The forces between you and the rock are balanced.
(C)The force of your push is greater than the opposing force.
(D)There is no friction to help you move the object.
Answer:
(A) Gravity pulls the rock toward the center of the Earth.
Explanation:
Which is a property of a neutron?
A)0charge
B)+1 charge
C)-1 Charge
D)Essentially no mass
Answer:
A. Neutrons have 0 Charge
Explanation
Neutrons have no charge for the same reason that plastics (and other insulators don't). They just don't.
"This isn't a great answer, but the thing with charge is that we don't really know what "charge" is. We know that certain "charged" objects will attract some objects, while repelling . We also know that other other "charged" objects will behave the same way, but when the two charged objects are brought together, they repell."
A storm is moving east towards your house at an average speed of 35 km / hr. If the storm is currently 80 km from your house, how much time do you expect it to arrive
Answer:
The expected time is 2.28 hours.
Explanation:
The speed of storm = 35 km/hr
The distance between the house and the storm = 80 km.
Now, we have to find the time taken by storm to arrive at the house. Here, we can determine the time by dividing the distance with speed.
The time, taken by storm = Distance/speed
The time, taken by storm = 80 / 35
The time, taken by storm = 2.28 hours.
If the definition of gravity is an attractive force between two masses, why do we not feel a gravitational force between two people?
Answer: Because your mass is so much less than the mass of the Earth,
Explanation:
You can't feel your gravitational force. Because the Earth's gravity has the same pull on every object, all objects fall at the same speed (in a vacuum). On Earth, we have air. Air resistance will cause some objects to fall more slowly than others will.
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