you are on a spaceship traveling at 95% the speed of light with respect to the earth. a strobe lamp fires at the

The amount of heat produced by a welding arc is primarily determined by the amperage, which refers to the strength of the electric current flowing through the welding circuit.

Amperage is directly proportional to the amount of heat generated, meaning that a higher amperage will result in a hotter arc. Voltage, electrode material, and type of gas used can also affect the welding arc, but their impact on the heat produced is relatively minor compared to amperage. Voltage controls the arc length and penetration, while electrode material and gas type affect the stability and quality of the weld. However, if the amperage is too high, it can lead to excessive heat buildup, which can cause the electrode to melt or the base material to warp, resulting in a defective weld. Therefore, it is essential to maintain the correct amperage setting based on the type and thickness of the materials being welded, as well as the welding process used. Overall, understanding the relationship between amperage and heat is crucial for producing high-quality and durable welds.

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The parachute  would be made to be heavier and more efficient. Option A

We know that the way that the parachute functions would be related to the way that it is designed. We have to know that if the parachute is heavy, it is going to take a shorter time for the parachute to reach the ground because the air resistance would be overcome by the weight of the parachute.

For the redesign of the parachute. The best option is to ensure that the parachute us made in such a way that it is much heavy and able to travel through air easily.

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Answer: The company can design a parachute with more surface area.

Explanation: I just did the quick check and it was right!

A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.

Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.

In Science, the motion of an object or physical body is described in terms of the following parameters:

Furthermore, there are three (3) forms of motion based on dimension and these include:

1. Motion in one dimension

2. Motion in two dimension

3. Motion in three dimension

A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.

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Answer: Cross-cutting features are always younger than the surrounding rock.

When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

The options include:

1. An unconformity is created when lava pours out on Earth’s surface.

2. Faults are the result of volcanic activity.

3. Intrusions and extrusions are sedimentary formations.

4. Cross-cutting features are always younger than the surrounding rock.

5. When material erodes before sediment is deposited on it, a geologic gap results.

The law of superposition simply states that when there is a layers of rocks, we would see that the younger layers will lie and be on top of the layers that are older.

Other tools that can help scientist with relative dating are:

• Cross-cutting features are always younger than the surrounding rock.

• When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

It's on Edge

The correct definition of precession, and the correct explanation of how does it affect what we see in our sky is the direction in which the earth's rotation axis points in space changes slowly over centuries, and we call this change, precession because of this movement, the celestial poles and therefore the pole star change slowly in time.

Option D is correct.

The north and south celestial poles are described as the two points in the sky where Earth's axis of rotation, indefinitely extended, intersects the celestial sphere.

In conclusion, the celestial poles appear permanently directly overhead to the observers at Earth's North Pole and South Pole, respectively.

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Answer:

The weeping willow is a gentle, graceful tree, but willow tree roots are very shallow and invasive. This means it's not the best backyard tree option for many

Explanation:

Answer:

Electrons are retained by the electromagnetic force in the orbit around the nucleus since the nucleus is positively charged in the middle of the atom and absorbs the electrons charged negatively.

Hope this helps!

We have that for the Question "Why do you think the electron of the hydrogen atom stays close to the proton in the atom’s nucleus" it can be said that

From the question we are told

Why do you think the electron of the hydrogen atom stays close to the proton in the atom’s nucleus?

Generally

This is because of the law of attraction where unlike charges reply

Therefore

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The terms with their correct definition is matched as follows:

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Answer:

Explanation:

All matter is made up of atoms, which are turned up of protons, neutrons and electrons.

They bond together to make up matter

Answer:

Atoms

Explanation:

All matter is made up of atoms, which are in turn made up of protons, neutrons and electrons. Atomess come togetheer to forms molecules, which are the building blocks for all types of matter

Answer:

closed

Explanation:

sorry if I'm wrong

To solve this problem, we will use the principle of conservation of mass applied to fluid flow, which states that the mass flow rate of the fluid is constant throughout the hose.

Explanation:

Mathematically, this is represented by the equation:

mass_flow_rate_in = mass_flow_rate_out

The mass flow rate can be calculated using the formula:

mass_flow_rate = area × velocity

where area = π(diameter/2)^2.

First, we need to calculate the area of the hose and nozzle:

Area_hose = π(0.016/2)^2
Area_hose ≈ 0.000201 m^2

Area_nozzle = π(0.0050/2)^2
Area_nozzle ≈ 0.0000196 m^2

Now, let's apply the conservation of mass principle:

Area_hose × velocity_hose = Area_nozzle × velocity_nozzle

We know the diameter and velocity of the hose (0.016 m and 3 m/s). We need to find the exit velocity of water from the nozzle (velocity_nozzle).

0.000201 × 3 = 0.0000196 × velocity_nozzle

Rearrange the equation to find the velocity_nozzle:

velocity_nozzle = (0.000201 × 3) / 0.0000196
velocity_nozzle ≈ 30.66 m/s

The exit velocity of water from the garden hose when a nozzle of diameter 0.0050 m is attached to the end of the hose is approximately 30.66 m/s.

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The magnitude of the average force of air resistance exerted on the baseball is 0.313 N.

To find the magnitude of the average force of air resistance exerted on the baseball, we can use the principles of kinematics and dynamics. When the baseball is dropped from a height of 15.0 m, it undergoes free fall under the influence of gravity. The acceleration due to gravity is approximately 9.8 \(m/s^2.\)

Using the equation of motion for free fall, we can find the time it takes for the baseball to reach the ground. The equation is:

\(h = (1/2)gt^2,\)

where h is the height, g is the acceleration due to gravity, and t is the time. Rearranging the equation, we have:

\(t^2 = (2h)/g.\)

Plugging in the values, we find:

\(t^2 = (2 * 15.0 m) / (9.8 m/s^2).\)

Calculating this expression, we get t = 1.75 s. This is the time it takes for the baseball to fall and reach the ground.

Next, we can use the equation of motion to find the average force of air resistance. The equation is:

v = gt,

where v is the final velocity of the baseball (7.50 m/s) and g is the acceleration due to gravity. Rearranging the equation, we have:

t = v/g.

Plugging in the values, we find:

\(t = (7.50 m/s) / (9.8 m/s^2)\)

Calculating this expression, we get t = 0.765 s. This is the time it takes for the baseball to decelerate from its initial velocity to 0 m/s due to air resistance.

Finally, we can use Newton's second law of motion to find the magnitude of the average force of air resistance. The equation is:

F = mΔv/Δt,

where F is the force, m is the mass of the baseball (148 g), Δv is the change in velocity, and Δt is the change in time. Since the baseball starts from rest, Δv is equal to the final velocity (7.50 m/s). Plugging in the values, we find:

F = (148 g)(7.50 m/s) / (0.765 s).

Calculating this expression, we get F = 0.313 N. Therefore, the magnitude of the average force of air resistance exerted on the baseball is 0.313 N.

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The kinematic relations we can find the results for the different short questions are:

6.  Range is    R = 141.4 m

7. Range is    R = 251.2 m

8.  a) Time  t = 4.42 s  b) Range  x = 55.25 m

9. a) Initial speed es v₀ = 16.16 m / s   b) range is  x = 11.55 m

10. Range  R = 6 1.9 m

Kinematics studies the movement of bodies, looking for relationships between the position, speed and acceleration of bodies.

6. They ask the range of the home run.  

Indicates initial velocity of 40.0 m / s and departure angle 30º

        R =\(\frac{v_o^2 sin 2 \theta }{g}\)  

        R = \(\frac{40.0^2 sin\ 2 \ 30 }{9.8 }\)  

        R = 141.4 m

7) Ask where the golf ball arrives to the ground.

They indicate the initial velocity of 40.0 m / s and the angle of 50º

        R = \(\frac{50.0^2 sin\ 2 \ 50 }{9.8}\)

        R = 251.2 m

8) They indicate the initial velocity of 25.0 m / s and an angle of 60.0º

a) Time in the air.

When the ball reaches the ground its height is zero.

       y = \(v_{oy}\)  t - ½ g t²

       0 = (\(v_{oy}\)  - ½ g t) t

the solution is

      t=0               exit point

      t = \(\frac{2 v_{oy}}{ g}\)  

vertical speed is

      \(v_{oy}\) =  v₀ sin  60

Let's substitute

      t = \(\frac{2 \ 36 \ sin 60}{9.8}\)  

      t = 4.42 s

b) How far does the ball go

      x = v₀ₓ t

      x = v₀ cos 60  t

      x = 25 4.42 cos 60

      x = 55.25 m

9) They indicate the height of the window y = 10.0 m and the launch angle is  60º

a) What is the initial speed of the throw

As it barely reaches the window, its vertical speed is zero

      \(v_y^2 = v_{oy}^2 - 2 g y \\0 = v_{o}^2 sin ^2 \theta - 2 g y\\ \\v_o^2 = \frac{2gy}{sin^2 \theta }\)

      v₀² = \(\frac{2 \ 9.8 \ 10.0}{9.8}\)

      v₀ = \(\sqrt{261.33}\)  

      v₀ = 16.16 m / s

b) What is the horizontal distance

Let's find the time until we reach the window

       \(v_y = v_{oy} - gt\\0 = v_{oy} - gt\)  

       t = \(\frac{v_o sin \theta}{g}\)

       t = \(\frac{16.16 sin 60}{9.8}\)

       t = 1.43 s

The horizontal distance is

     x = v₀ₓ t

     x = 1(6.16 cos 60) 1.43

10) The range of the balloons

      \(R = \frac{v_o^2 sin 2 \theta }{g}\\R = \frac{25.0^2 sin \ 2 \ 38 }{9.8}\)  

      R = 6 1.9 m

In conclusion using the kinematics relations we can find the results for the different short questions are:

       6.  Range is    R = 141.4 m

       7. Range is    R = 251.2 m

       8.  a) Time  t = 4.42 s  b) Range  x = 55.25 m

       9. a) Initial speed es v₀ = 16.16 m / s   b) range is  x = 11.55 m

      10. Range  R = 6 1.9 m

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The graph that corresponds to 0.1 s in one complete cycle is graph D.

option D is the correct answer.

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.

Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.

From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;

Period = 1 s / 10

Period = 0.1 s

From the graphs, the only option that has one complete cycle in one second is option D.

Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.

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Answer:

89.53    North

Explanation:

Total N-S displacement

   23.72  -  39.25 + 105.06   =  + 89.53

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

f is the force

m is the mass

From the question we have

\(a = \frac{750}{349} \\ = 2.14899713...\)

We have the final answer as

Hope this helps you

The angle that D makes with the z-axis is 68.7 degrees.

We have D = 2.13i - 4.5j + 1.95k.

(a) To find the angle that D makes with the x-axis, we need to find the angle that D makes with the vector i = 1i + 0j + 0k. The dot product of D and i is:

D · i = |D| |i| cos(θ)

where |D| is the magnitude of D, |i| is the magnitude of i, and θ is the angle between D and i. Since |i| = 1, we have:

D · i = |D| cos(θ)

The magnitude of D is:

|D| = sqrt(2.13^2 + (-4.5)^2 + 1.95^2) = 4.96 m

So, we have:

D · i = 2.13 cos(θ)

Solving for θ, we get:

θ = arccos(D · i / |D|) = arccos(2.13 / 4.96) = 63.8 degrees

Therefore, the angle that D makes with the x-axis is 63.8 degrees.

(b) To find the angle that D makes with the y-axis, we need to find the angle that D makes with the vector j = 0i + 1j + 0k. The dot product of D and j is:

D · j = |D| |j| cos(θ)

where |j| is the magnitude of j. Since |j| = 1, we have:

D · j = |D| cos(θ)

Solving for θ, we get:

θ = arccos(D · j / |D|) = arccos(-4.5 / 4.96) = 130.8 degrees

Therefore, the angle that D makes with the y-axis is 130.8 degrees.

(c) To find the angle that D makes with the z-axis, we need to find the angle that D makes with the vector k = 0i + 0j + 1k. The dot product of D and k is:

D · k = |D| |k| cos(θ)

where |k| is the magnitude of k. Since |k| = 1, we have:

D · k = |D| cos(θ)

Solving for θ, we get:

θ = arccos(D · k / |D|) = arccos(1.95 / 4.96) = 68.7 degrees.

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According to Law of Conservation of energy ,

One form of energy is transformed into another form of energy and there is no loss of energy in the transformation process.

The law of conservation of energy states that the energy can neither be created nor be destroyed only converted from one form of energy to the other form of energy means that the system always has the same amount of energy , unless its's added from the outside.

The only way to use energy is to transform energy from one form to another form.

example - Heat energy is transformed into Kinetic and Potential energy.

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The molar mass of a compound can be found by adding the molar masses of all of the atoms in the compound.

The molar mass of an atom can be found on the periodic table by looking at the atomic mass listed for that element.

For example, to find the molar mass of water (H2O), we would add the molar masses of two hydrogen atoms (2 x 1.01 g/mol) and one oxygen atom (16.00 g/mol) to get a total molar mass of 18.02 g/mol.

Another way is by finding the molecular formula of the compound, it can be done by analyzing the compound's chemical and physical properties and then using the mass spectrometer to determine the molecular weight.

In conclusion, the molar mass of a compound can be found by adding the molar masses of the atoms in the compound using the atomic masses listed on the periodic table, or by determining the molecular formula of the compound and using a mass spectrometer to find the molecular weight.

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Answer:

A) 1.79ohms

Explanation:

Total resistance of resistors in parallel is given by ;

1/R = 1/R1 + 1/R2 +1/R3

Put in the values and make R the subject

There is evidence that a supermassive black hole is at the center of the Milky Way based on several observations and studies.

Some of the key pieces of evidence include:

1. Stellar Orbits: Astronomers have observed the orbits of stars near the center of the Milky Way. These stars exhibit high speeds and tight orbital patterns, indicating the presence of a massive object with strong gravitational influence. By analyzing these stellar orbits, scientists have deduced the presence of a supermassive black hole.

2. Radio Source Sagittarius A*: In the constellation Sagittarius, there is a strong radio source known as Sagittarius A*. Detailed observations of this source have revealed it to be an extremely compact and highly energetic region. Based on its characteristics, scientists believe that Sagittarius A* is a supermassive black hole at the center of our galaxy.

3. X-ray and Infrared Emissions: Observations in X-ray and infrared wavelengths have detected intense emissions coming from the center of the Milky Way. These emissions are consistent with the behavior of matter being heated and accelerated as it falls into a supermassive black hole.

4. Gas and Dust Dynamics: Studies of gas and dust clouds near the galactic center have shown significant disturbances and high velocities. These observations suggest the presence of a massive object exerting gravitational forces on the surrounding material, indicating a supermassive black hole. Collectively, these lines of evidence provide strong support for the existence of a supermassive black hole at the center of the Milky Way.

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The hydrogen atom will have 5 values for the azimuthal quantum number, l.

i) A group of quantum states of the hydrogen atom has the principal quantum number as,

n = 5.

Therefore, the possible values of the azimuthal quantum number of the hydrogen atom, l will be,

l = 0, 1 ,2, ..., (n - 1) = 0, 1, 2, ..., (5 - 1) values

l = 0, 1, 2, 3, 4

So, the hydrogen atom will have 5 values for the azimuthal quantum number.

ii) Given that,

The principal quantum number of hydrogen atom, n = 5

Azimuthal quantum number of the hydrogen atom, l = 3

Therefore, the possible values of magnetic quantum number, m will be,

m = -l, ..., 0, ...+l

m = -3, -2, -1, 0, 1, 2, 3

So, the hydrogen atom will have 7 values for the magnetic quantum number.

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Time taken to slow down the speed will be 5 seconds.

Average acceleration of the bus, a = 1.8 m/s²

Initial velocity of the bus, u = 9.0 m/s

Final velocity of the bus, v = 0 m/s

According to the First Equation of the motion which relates the acceleration, velocity and time we can say that

v = u + at

v - u = at

0 - 9 = (-1.8) * t

9 = 1.8 * t

t = \(\frac{9}{1.8}\)

t = 5 s

Therefore 5 seconds will be required by the bus to slow down its speed from 9.0 m/s to 0.0 m/s

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The volume of marble with a mass of 3g and a density of 2.7g/mL is  1.11mL.

It can be calculated using the formula: Volume = Mass / Density. In this case, the mass of the marble is 3g and the density is 2.7g/mL. By substituting these values into the formula, we get: Volume = 3g / 2.7g/mL.

Upon dividing 3g by 2.7g/mL, we obtain the volume in milliliters (mL). The result is approximately 1.11mL. Therefore, the volume of the marble with a mass of 3g and a density of 2.7g/mL is approximately 1.11mL.

This calculation is essential in various fields such as engineering, physics, and chemistry for determining the amount of space an object occupies, as well as understanding its physical properties.

It's important to note that the density value provided in the question is critical for accurate results since it represents the mass-to-volume ratio of the material, in this case, the marble.

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(1) The moment of 20N about the wheel is 30 Nm. (2) The distance of the wheel to the center of mass of the wheelbarrow is 1.2m.

1. The moment of 20N about the wheel can be calculated using the formula:

Moment = Force x Distance

Moment = 20N x 1.5m

Moment = 30 Nm

2. To find the distance of the wheel to the center of mass of the wheelbarrow, we can use the principle of moments, which states that the sum of the clockwise moments about a point is equal to the sum of the anticlockwise moments about the same point. Let the distance from the wheel to the center of mass be x.

Clockwise moment = Weight x Distance

Clockwise moment = 80N x (1.5m - x)

Anticlockwise moment = Upforce x Distance

Anticlockwise moment = 20N x x

Using the principle of moments:

80N x (1.5m - x) = 20N x x

Simplifying and solving for x:

120m = 100x

x = 1.2m

Therefore, the distance of the wheel to the center of mass of the wheelbarrow is 1.2m.

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Answer:

Explanation:

1.-Energía eléctrica ( electricidad ) proveniente de una fuente AC ( es decir de corriente alterna)

2.-Hay un proveedor de servicios que lleva la energía a las comunidades en general y en particular la lleva hasta mi casa y escuela. Se define como acometida eléctrica, la infraestructura que lleva la energía desde la red de distribución al tablero principal en el abonado. La acometida puede ser aérea o subterránea, y normalmente consta de tres conductores ( de los cuales dos son calibre AWG # 8 ( dos fases ) y uno AWG # 10 ( neutro ). Esta configuración permite tener: 120 y 240 (V) en servicio en la casa y suficiente capacidad para la carga eléctrica de una casa normal

3.-Si, el tipo de corriente. En el caso de una linterna se usan "pilas" o baterías de corriente directa ( que no varia en el tiempo), en la casa la corriente es alterna de 60 ciclos por segundo de frecuencia.

4.-Si el voltaje es menor en una medida importante la ampolleta no alumbra por cuanto si por ejemplo el voltaje nominal ( o de funcionamiento es 120 V y el voltaje suministrado es 50 V ese voltaje será insuficiente para hacer funcionar el circuito). Si el voltaje es mayor dígamos 240 V la ampolleta se quema.

5.-El interruptor nos asegura la maniobra a nuestra voluntad del circuito del cual forma parte. Es decir si tengo un circuito de alumbrado ( 1 bombillo y un interruptor ) ese interruptor me permitirá apagar y encender la luz cuando yo quiera.

Los breaker son "interruptores" son dispositivos de protección para caso de sobrecargas y/o cortocircuitos