You are able to see non-luminous objects because light has undergone. A. diffuse reflection. B. refraction. C. constructive interference.

The ways to  make a skit are:

In skit making, one can start by coming up with humorous concepts for your skit. Write out your scenario, practice it, and then perform it in front of an audience or record it. Then Continue to create fresh drafts.

Note that one can ask someone you trust's opinion should see your sketch. Then make a note of what people found amusing and not amusing.

Therefore, skit  is seen as short comedy show that can be performed by second graders.

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When carbon fuses, it will produce all of the following except aluminium. Hence option c is correct.

The process of burning carbon results in the production of oxygen, neon, sodium, and magnesium through fusion reactions.

At this phase, the star's core consistently undergoes nuclear fusion, a process that converts hydrogen into helium. In specifics, a helium nucleus is created by joining (fusing) four hydrogen nuclei (four protons) (two protons and two neutrons).

However, once a carbon-12 nucleus fuses with a proton to generate nitrogen-13, one of the protons decays with the emission of a positron and a neutrino to form carbon-13, negating the fundamental motif of the carbon cycle, which is the addition of protons.

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Approximately 1.52 g of (s)-1-chloro-4-ethyl-2-methylhexane and 2.12 g of triphenylphosphine would be required to get the required product.

Molar mass of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium = (4 x molar mass of C) + (1 x molar mass of Cl) + (1 x molar mass of P) + (4 x molar mass of H) + (3 x molar mass of C6H5)

= (4 x 12.01 g/mol) + (1 x 35.45 g/mol) + (1 x 30.97 g/mol) + (4 x 1.01 g/mol) + (3 x 78.11 g/mol)

= 628.02 g/mol

Next, we can use stoichiometry to determine how much (s)-1-chloro-4-ethyl-2-methylhexane and triphenylphosphine are required to produce 4.15 g of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium. The balanced chemical equation for the reaction is:

(s)-1-chloro-4-ethyl-2-methylhexane + triphenylphosphine → (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium chloride

From the balanced equation, we can see that one mole of (s)-1-chloro-4-ethyl-2-methylhexane reacts with one mole of triphenylphosphine to produce one mole of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium chloride. Therefore, we need to calculate the number of moles of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium chloride produced from 4.15 g, and then use stoichiometry to determine the amount of (s)-1-chloro-4-ethyl-2-methylhexane and triphenylphosphine required.

Number of moles of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium chloride = mass / molar mass

= 4.15 g / 628.02 g/mol

= 0.0066 mol

Since the yield is given as 81%, we need to adjust the amount of (s)-1-chloro-4-ethyl-2-methylhexane and triphenylphosphine accordingly:

Amount of (s)-1-chloro-4-ethyl-2-methylhexane = 0.0066 mol / 0.81

= 0.0081 mol

Amount of triphenylphosphine = 0.0066 mol / 0.81

= 0.0081 mol

Finally, we can convert the moles of each compound to grams using their respective molar masses:

Mass of (s)-1-chloro-4-ethyl-2-methylhexane = 0.0081 mol x 186.71 g/mol

= 1.52 g

Mass of triphenylphosphine = 0.0081 mol x 262.29 g/mol

= 2.12 g

Therefore, approximately 1.52 g of (s)-1-chloro-4-ethyl-2-methylhexane and 2.12 g of triphenylphosphine would be required to produce 4.15 g of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium assuming an  81% yield of reaction.

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Answer:

Option C is correct

Explanation:

Covalent substances have weaker intermolecular attractions.

Scored 100% on my quiz on Edge :)

The characteristic that best explains the difference in melting behaviors is

The melting point of covalent substances ( i.e. substances bounded by covalent bonding ) is lower than the melting point of ionic substances, this is because of the weak intermolecular attractions which exists in covalent compounds and this makes atoms in covalent substance to dissociate easily .

Hence we can conclude that the characteristic that best explains the difference in melting behaviors is Covalent substances have weaker intermolecular attractions.

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The value of van't Hoff factor for the electrolyte is i =  0.28

Molarity of solution = 5.61 m

The temperature which depresses the freezing point of water = 2.93 °C

The freezing point depression constant, kfp, for water  = 1.86 °C kg\(mol^{-1}\)

To find the van't Hoff factor, let's use the following formula.

ΔTf = kf × molality × i

Here ΔTf  = depression fo freezing point

kf = freezing point depression constant

i = Van't Hoff's factor

Now substitute the values in the above formula.

2.93  =  1.86 x 5.61 x i

i = 2.93 / 1.86 x 5.61

i = 2.93 / 1.043  = 0.28

Hence, the value of van't Hoff factor is 0.28

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The complete question is:

A 05.61 m solution of unknown electrolyte depresses the freezing point of water by 2.93 °C. What is van't Hoff factor for this electrolyte? The freezing point depression constant (Kf) for water is 1.86 °C kg\(mol^{-1}\).

Nonelectrolytes are compounds that do not tend to get ionize in all solution. As a result, solutions which contains nonelectrolytes will not conduct electricity.

Ionic compounds dissolve in water and break into the constituent ions through the process called ionization. Now These electrolyte solutions can either be acids, or bases, or salts.

If  the process of ionization produces a large no. of ions in the solution, it is a strong electrolyte. On the other hand, if it produces only a few ions, the solution is a weak electrolyte,

Potassium chloride (KCL) is a strong electrolyte,

Lactic acid (HC3H503) is a weak electrolyte,

Whereas, Ethanol (C3H7OH) is a non electrolyte,

Dimethylamine (CH3)2NH is a weak electrolyte,

Sodium hydroxide(NaOH) is a strong electrolyte.

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The group of amino acids that has a net positive charge at pH 7 is the basic amino acids. Basic amino acids have an amino group (-NH2) in their side chain that can gain a proton (H+) at pH 7, resulting in a positively charged amino acid. The basic amino acids include arginine (Arg), lysine (Lys), and histidine (His).

At pH 7, which is considered neutral, the amino group of basic amino acids tends to be protonated and carries a positive charge. This positive charge is balanced by the negative charge of the carboxyl group (-COO-) present in all amino acids. The net positive charge of basic amino acids allows them to participate in specific interactions, such as forming salt bridges with negatively charged molecules or binding to negatively charged regions of proteins or nucleic acids.

It's important to note that the net charge of an amino acid at a specific pH depends on the pKa values of its functional groups and the pH of the environment. At pH values below their pKa values, basic amino acids tend to be fully protonated and carry a positive charge.

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Answer:

its 210

Explanation:

Just add all atomic mass used in the formula together: 2*(14+16*3)+88= 2*62+88=124+88=210

Hope this was helpful

The relative formula mass of strontium nitrate Sr(NO₃)₂ is 210

The relative atomic masses of N, O and Sr are 14,16 and 88 respectively.

In calculating the relative atomic mass of an element with isotopes, the relative mass and proportion of each is taken into account. Adding the atomic masses together gives the relative formula mass of a compound

So, relative atomic mass of Sr(NO₃)₂ is calculated as

88+ 2(14+16×3) = 210

The atomic mass constant (symbol: mu) is defined as being 1/12 th of the mass of a carbon-12 atom. Since both quantities in the ratio are masses, the resulting value is dimensionless; hence the value is said to be relative atomic mass.

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The inorganic substance with the chemical formula BaSO4 is barium sulfate (or sulphate). It is a tasteless, crystalline white substance that is insoluble in water.

A barium cation and a sulfate anion are the two elements that make up barium sulfate. There are four oxygen atoms joined to the sulfur. A sulfate salt of barium, known as BaSO4, is present in the mineral barite. It is a white crystalline substance that is soluble in strong acids but insoluble in water and alcohol.

Elements include both barium and bromine. Barium is a metal belonging to Group 2 of the modern periodic table, and bromine is a non-metal belonging to Group 17 (halogen).

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The answer response are:

Lead is a metal that is commonly used in various applications, including protecting against radiation in dental x-rays and as a component in car batteries. The carbon family, located in Group 14 of the periodic table, includes elements such as carbon, silicon, and germanium. These elements have similar chemical properties and physical characteristics such as having four valence electrons, being non-metallic, etc.

Therefore, Some common uses of the carbon family include the production of semiconductors, alloys, and ceramics. Silicon, for example, is used in the production of computer chips and solar panels, while carbon is used in the production of graphite and diamond. Understanding the properties and applications of these elements can have important implications for various fields such as engineering, materials science, and environmental health.

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Answer:

Formal

Explanation:

Answer:

I think its formal because the question looks a bit fancy by using all the present perfect tense..

hope this helped you

please mark as the brainliest ( if its correct)(ㆁωㆁ)

Answer:

1.67*10^9

Explanation:

Answer:1.67*10^9

Explanation:

The expected inflation premium is 7.2 percent, using the exact (multiplicative) formulation given the real rate is 2.8 percent and the nominal rate is 10.3 percent.

Here is how to calculate the expected inflation premium using the exact (multiplicative) formulation;The exact (multiplicative) formulation is given by; $$(1 + r_n) = (1 + r_r)(1 + i)$$ where $r_n$ is the nominal rate, $r_r$ is the real rate, and $i$ is the inflation rate.

Substituting the values of $r_n$ and $r_r$ in the above equation we have; $$(1 + 0.103) = (1 + 0.028)(1 + i)$$Solving for $i$, we have; $$(1.103) = (1.028)(1 + i)$$$$\frac{1.103}{1.028} = 1 + i$$$$i = \frac{1.103}{1.028} - 1$$$$i \approx 0.072$$Therefore, the expected inflation premium is 7.2 percent, using the exact (multiplicative) formulation.

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Answer:

Only 2moles are produced from it

The mass of 2.00 moles of Ca(OH)₂ is 148.2 g.

A mole is a unit of measurement used in chemistry to represent particles, such as atoms, molecules, or ions. A mole is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are in 12 grams of pure carbon-12.

Moles and mass are directly proportional to each other since they both represent the quantity of substance.

Moles = Mass/Molar mass

Mass = Moles x Molar mass

The molar mass of Ca(OH)₂ is calculated as follows:

Molar mass of Ca = 40.1 g/mol

Molar mass of O = 16.0 g/mol

Molar mass of H = 1.0 g/mol2 atoms of oxygen, 2 atoms of hydrogen, and 1 atom of calcium are present in Ca(OH)₂.

Therefore, the molar mass of Ca(OH)₂ = 40.1 g/mol + 2(16.0 g/mol) + 2(1.0 g/mol) = 74.1 g/mol

The mass of 2.00 moles of Ca(OH)₂ = Moles × Molar mass= 2.00 × 74.1= 148.2 g

Hence, 148.2 g is the mass of 2.00 moles of Ca(OH)₂.

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Answer: There are three main types of MS, relapsing primary progressive and secondary progressive

The IV flow rate of Apo-isoproterenol in mililitres per hour is to be set at 37.5.

The conversion will be done by using the formula -

Dosage rate × IV concentration × Conversion factors

Keeping the values in formula to find the IV flow rate in ml/hr.

The desired flow rate = 5 mcg / minute × (250 mililitres / 2 miligram ) × (1 mg / 1000 mcg) × (60 minutes / 1 hour)

Performing multiplication and division on Right Hand Side of the equation

The desired flow rate = 37.5 mililitres per hour

Hence, the IV flow rate in mililitres per hour is 37.5.

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The partial pressure of the hydrogen gas collected in this way is 710 mmHg. When collecting a gas over water, the total pressure of the system includes the vapor pressure of water at that temperature

When collecting a gas over water, the total pressure of the system is the sum of the partial pressure of the gas and the vapor pressure of water at that temperature. In this case, the total pressure is given as 742 mmHg, and the vapor pressure of water at 30°C is 31.8 mmHg.

To find the partial pressure of the hydrogen gas, we need to subtract the vapor pressure of water from the total pressure. Therefore, the partial pressure of the hydrogen gas can be calculated as:

Partial pressure of hydrogen gas = Total pressure - Vapor pressure of water

Partial pressure of hydrogen gas = 742 mmHg - 31.8 mmHg

Partial pressure of hydrogen gas = 710 mmHg

In this chemical reaction, the collected hydrogen gas exerts a partial pressure of 710 mmHg.

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The coefficient in front of Cl₂ is 1, wen the equation is balanced

The balanced chemical equation for the reaction between Zinc and Chlorine gas is:

Zn + Cl₂ → ZnCl₂

To balance this equation, we need to make sure that the number of atoms of each element is equal on both the reactant and product side of the equation.

In this case, there is one Zinc atom and two Chlorine atoms on the reactant side, and one Zinc atom and two Chlorine atoms on the product side. So, the equation is already balanced.

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According to the mixed melting point concept, this result may indicate that: b.)trimyristin was not hydrolyzed to myristic acid.

A hydrolysis reaction is that reaction in which one molecule breaks apart to form multiple smaller molecules. Acidic hydrolysis of an ester produces carboxylic acid and an alcohol. Basic hydrolysis that is saponification of an ester gives carboxylate salt and alcohol.

Any chemical reaction in which a molecule of water breaks one or more chemical bonds is called hydrolysis. The term is used mainly for substitution, elimination, and solvation reactions in which water is the nucleophile.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Suppose a student hydrolyzes trimyristin to myristic acid and wants to confirm if the reaction works. During the melting point measurement, a 50:50 mixture of the starting trimyristin and the product myristic acid is found to have the same melting point as that of trimyristin. According to the mixed melting point concept, the result indicated that:

a. trimyristin was hydrolyzed to myristic acid

b. trimyristin was not hydrolyzed to myristic acid

c. trimyristin is the same as myristic acid

d. trimyristin was decomposed during the hydrolysis reaction

e. none of the above

Answer:

A chemical reaction

Explanation:

4.33 grams of nitrogen are produced when 7.80 grams of dinitrogen tetrahydride reacts with hydrogen peroxide.

To determine the mass of nitrogen (N2) produced when 7.80 grams of dinitrogen tetrahydride (NaH) reacts with hydrogen peroxide (H2O2), we need to calculate the stoichiometry of the balanced chemical equation and use the molar masses of the compounds involved.

The balanced chemical equation is:

2NaH + 2H2O2 → N2 + 4H2O

From the equation, we can see that 2 moles of NaH react with 2 moles of H2O2 to produce 1 mole of N2. To find the molar mass of N2, we add the atomic masses of two nitrogen atoms:

Molar mass of N2 = 2 × Atomic mass of nitrogen = 2 × 14.01 g/mol = 28.02 g/mol

Now, let's calculate the number of moles of NaH:

Moles of NaH = Mass of NaH / Molar mass of NaH

Moles of NaH = 7.80 g / (22.99 g/mol + 1.01 g/mol) ≈ 0.3088 mol

According to the balanced equation, the molar ratio of NaH to N2 is 2:1. Therefore, the moles of N2 produced will be half the moles of NaH used:

Moles of N2 = 0.3088 mol / 2 ≈ 0.1544 mol

Finally, to find the mass of nitrogen produced, we multiply the moles of N2 by the molar mass of N2:

Mass of N2 = Moles of N2 × Molar mass of N2

Mass of N2 = 0.1544 mol × 28.02 g/mol ≈ 4.33 g

Therefore, approximately 4.33 grams of nitrogen are produced when 7.80 grams of dinitrogen tetrahydride reacts with hydrogen peroxide.

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The volume occupy at 415K and 12.3atm is 37.25ml.

Ideal gas:

An ideal gas is a theoretical gas composed of many randomly moving point particles that are not subject to interparticle interactions. It is one for which both the volume of molecules and forces between the molecules are so small that they have no effect on the behavior of the gas.

Here we have to find the volume occupied.

The formula for an ideal gas:

P1 V1 / T1 = P2 V2 / T2

V2 = P1 V1 T2 / T1 P2

P1 = 14.8atm

P2 = 12.3atm

V1 = 23.5 ml

T1 = 315K

T2 = 415K

Now putting these values in the equation we get:

V2 = (14.8× 23.5 × 415)/ ( 12.3 × 315)

     = 144,337 / 3874.5

    = 37.25 ml

Therefore the 37.25ml is the volume.

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Answer:

~441.8mmHg

Explanation:

Use Gay-Lussac's law;

(P1/T1)=(P2/T2)

P1=418mmHg

T1=298K

P2=?

T2=315K

From the equation above, we can derive the equation for P2.

So, P2=(P1 x T2)/(T1)

          =(418 x 315)/(298)

          ~441.8mmHg

Hope it helps:)

Answer:

441.8mmHg

Explanation:

Lone pairs in a trigonal bipyramidal arrangement will occupy the equatorial positions to minimize repulsions between electron groups. The presence of lone pairs in a molecule creates additional electron-electron repulsions, and placing them in the equatorial positions allows for greater separation and minimizes these repulsions.

In a trigonal bipyramidal arrangement, there are five electron groups around the central atom. These electron groups can consist of both bonding pairs and lone pairs. Lone pairs exert larger repulsions compared to bonding pairs due to their higher electron density.

To minimize the repulsions between electron groups, the lone pairs are placed in the equatorial positions. This arrangement maximizes the distance between the lone pairs, reducing the repulsive forces between them. Placing the lone pairs in the axial positions would result in closer proximity and stronger repulsions between the lone pairs, leading to higher energy and less favorable geometry.

By occupying the equatorial positions, the lone pairs are positioned away from each other as much as possible, reducing electron-electron repulsions and achieving a more stable arrangement.

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Answer: 1) \(2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O\)

2) \(2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O\)

3) \(2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O\)

4)\(2C_{10}H_{22}+31O_2\rightarrow 20CO_2+22H_2O\)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.

The balanced chemical reactions will be:

1) Ethane + Oxygen = Carbon Dioxide + Water : \(2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O\)

2) Butane + Oxygen = Carbon Dioxide + Water : \(2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O\)

3) Octane + Oxygen = Carbon Dioxide + water: \(2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O\)

4) Decane + Oxygen = Carbon Dioxide + Water :  \(2C_{10}H_{22}+31O_2\rightarrow 20CO_2+22H_2O\)

Explanation:

The molar mass of a substance is the mass in grams of one mole of the substance. In a compound, add the atomic masses of the components.

 HCl

 Atomic mass of H  = 1g/mol,  Cl = 35.5g/mol

   HCl  = (1 + 35.5) = 36.5g/mol

 ZnF₂

Atomic mass of Zn  = 65.4g/mol, F = 19g/mol

      ZnF₂  = 65.4 + 2(19) = 103.4g/mol

 K₂CO₃

   Atomic mass of K = 39, C  = 12, O = 16

    K₂CO₃  = 2(39) + 12 + 3(16)  = 138g/mol

 FePO₄

Atomic mass of Fe = 55.8, P = 31, 0 = 16

 FePO₄ = 55.8 + 31 + 4(16) = 150.8g/mol

Cu₂S

  Atomic mass of Cu = 63.5g/mol, S = 32

    Cu₂S = 2(63.5) + 32 = 159g/mol

Each term in the series represents a sinusoidal component with a frequency of (kπ/4) and an amplitude of 4.

To express the given periodic signal x(t) in the form x(t) = ∑[k=0 to infinity] A_k cos(w_kt + ϕ_k),\

we can use the formula for the Fourier series representation of a periodic signal.

1. First, let's find the values of A_k, w_k, and ϕ_k using the given Fourier series coefficients.

The given coefficients are:

a_1 = a_-1* = j

a_5 = a_-5 = 2

Since x(t) is real-valued, the coefficients for negative frequencies (a_-k) are the complex conjugates of the coefficients for positive frequencies (a_k).

From the given coefficients, we can determine the values of A_k:

A_1 = a_1 + a_-1 = j + conj(j) = j - j = 0

A_5 = a_5 + a_-5 = 2 + conj(2) = 2 + 2 = 4

Since the fundamental period T is 8, the fundamental frequency is ω_0 = 2π/T = 2π/8 = π/4.

The values of w_k can be determined as:

w_0 = 0

w_k = k * w_0 = k * (π/4) for k ≠ 0

The values of ϕ_k can be determined as:

ϕ_0 = 0

ϕ_k = arg(a_k) for k ≠ 0

2. Now, let's express x(t) in the desired form using the determined values.

x(t) = A_0 cos(w_0t + ϕ_0) + ∑[k=1 to infinity] A_k cos(w_kt + ϕ_k)

Substituting the values we found:

x(t) = 0 cos(0t + 0) + ∑[k=1 to infinity] 4 cos((kπ/4)t + arg(a_k))

Simplifying:

x(t) = ∑[k=1 to infinity] 4 cos((kπ/4)t + arg(a_k))

This is the expression of x(t) in the desired form.

Remember that the series is infinite, so it includes all integer values of k.

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Significant figures are important because they indicate the precision of a measurement.

Precision:

The precision of a substance is defined as the degree to which two or more measurements agree with one another. It is incredibly precise but not always accurate to measure something if you weigh it five times and get 3.2 kg each time. Accuracy is not necessary for precision. You can learn how to be accurate but not precise by looking at the examples below. There are various categories of precision:

Repeatability:

The fluctuation that results from taking multiple measurements under the same circumstances in a short amount of time.

Reproducibility:

The variation occurs when several instruments, operators, and longer time periods are used in the same measurement process.

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