You add 5.7 g of iron to 25.20ml of water and observe that the volume of the iron and water together is 25.92ml calculate thw density of the iron

Answer:

true

Explanation:

google

Answer:

1.44 g

Explanation:

1. get number of nitrogen atoms in 9.79 grams of nitrogen

1 mole of Nitrogen is 6.022 x 10^23 atoms N which is = 14.01g N

2.

if 6.022 x 10^23 atoms of Nitrogen is 14

then x atoms  of Nitrogen is 9.79

3.

6.022 x 10^23/ x = 14/9.79 ->

x = 8.431 x 10^24 / 9.79 =

8.61799714478 x 10^23

4.

8.61799714478 x 10^23 atoms of N

6.022 x 1023 atoms of H have a mass of 1.008g, so

8.61799714478 x 10^23 atoms of H have a mass of (1.008/6.022 x 1023) x 8.61799714478 x 10^23) = 1.44250051072175g

1.44 g

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Answer:

The four elements most commonly found in living things are carbon, nitrogen, hydrogen, and oxygen.

Explanation:

The four elements most commonly found in living things are carbon, nitrogen, hydrogen, and oxygen.

These are the formal charges for compounds 1 and 2:

The formal charge of an atom is the charge that an atom would have if all of the electrons in a bond were shared equally. To calculate the formal charge of an atom, use the following formula:

formal charge = valence electrons - (bond electrons / 2) - non-bonding electrons

In compound 1, the nitrogen atom has 5 valence electrons, 3 bond electrons (one from each of the two C-N bonds), and 0 non-bonding electrons. Therefore, the formal charge on the nitrogen atom is 0.

The oxygen atom in compound 1 has 6 valence electrons, 2 bond electrons (one from each of the two C-O bonds), and 4 non-bonding electrons. Therefore, the formal charge on the oxygen atom is -1.

The chlorine atom in compound 1 has 7 valence electrons, 1 bond electron (from the C-Cl bond), and 6 non-bonding electrons. Therefore, the formal charge on the chlorine atom is -1.

In compound 2, the nitrogen atom has 5 valence electrons, 1 bond electron (from the N-O bond), and 4 non-bonding electrons. Therefore, the formal charge on the nitrogen atom is +1.

The oxygen atom in compound 2 has 6 valence electrons, 2 bond electrons (one from the N-O bond and one from the C=O bond), and 0 non-bonding electrons. Therefore, the formal charge on the oxygen atom is -1.

The carbon atoms in both compounds have 4 valence electrons, 4 bond electrons, and 0 non-bonding electrons. Therefore, the formal charge on the carbon atoms is 0.

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

INFORMATION:

We have the next balanced equation

And we must find how many grams of NO are produced if 17 moles of O2 are reacted

STEP BY STEP EXPLANATION:

To find how many grams of NO are produced if 17 moles of 02 are reacted, we must analyze the equation.

We can see in the equation that:

- 1 mole of NH3 (on complete reaction) gives 1 mole NO.

- 5 moles of O2 produce 4 moles of NO, so 1 mol of O2 gives 4/5 = 0.8 mole of NO.

Thus, O2 will be the limiting reactant.

Now, if 17 moles of O2 are reacted, we must calculate the number of moles of NO that will be produce multiplying 0.8 by 17

Then, using the molecular mass of NO (30.01 g/mol), we can calculate the number of grams that are produced

ANSWER:

408.136 grams of NO are produced if 17 moles of O2 are reacted.

The density of ammonia is 00117 gm|M|.

We know D = MP/RT

Now, P = 1600 mm = 1600/760=2.10atm

∴D=\(\frac{17\times2.10}{821\times 373}\)

D= 0.00117 gm|M|

Density of a material shows the density of that material in a  given area. The density of a material is defined as its mass per unit volume. Density is basically a measure of how tightly  packed a substance is. It is a unique physical property of a particular object. The principle of density was discovered by the Greek scientist Archimedes. Calculating density is easy  if you know the formula and understand the  units involved. The symbol ρ means density, or it can also be indicated by the letter D.

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d = 0.00117gm|M|

The density of ammonia gas is 0.00117gm|M|

Here we want to find density of ammonia gas,

The equation is,

                       d = MP/RT,

where d is the gas's density in g/L,

M is the gas's molar mass in g/mol,

P is the gas's pressure in ATM, and R is the gas law constant.

The equation shows that as the density of a gas increases, so does its molar mass.

given ,

M = 17.1 g/mol

P = 1600mmHg => (to convert to ATM) = 1600/760  = 2.10 atm

R= 8.31J/K⋅mol

T= 373°c

substituting values,

        d = (17.1 x 2.10) / 8.31 x 373

         d  = 0.00117gm|M|

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We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Answer:

A: True

Explanation:

Statement is true because chrysanthemic acid is formed naturally as a result of production of two molecules of dimethylallyl diphosphate which forms pyrophosphate ester.

Thus, it belongs to the pyrethrum family

Answer: Positive environmental changes.

Explanation: Without many humans around, the environment has been getting better as more sea life have been spotted in places they haven't been for decades, as well as clearer waters and less rubbish about. Pollution levels have dropped as there are barley any planes in the sky and not many cars about.

Answer:

honestly,i can say that socially being away from people reduces stress

Explanation:

Answer:Expert-Verified Answer

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From Practical perform shown below, It conclude that  If you increase the temperature of a reaction, then the reaction rate will increase because particles experience more collisions at higher temperatures.

The effects of temperature and a reactant’s particle size on reaction rate.

Step 1: Gather Materials250 mL graduated cylinder

   Thermometer

   Water

   Timer

   Four 250 mL beakers

   Seven 1,000 mg effervescent tablets

Step 2: Measure the Reaction Rate at ≈ 20°C (Room Temperature)

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Measure the temperature of the water and record it in the correct row of Table A.

c) Reset the timer. Start the timer as you place a full tablet into the beaker.

d) Record the reaction time on the Data Sheet in the correct row of Table A.

e) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table A.

Step 3: Measure the Reaction Rate at ≈ 40°C Repeat Step 2, heating the water to approximately 40°C using a hot plate during sub-step a.

Step 4: Measure the Reaction Rate at ≈ 65°CRepeat Step 2, heating the water to approximately 65°C using a hot plate during sub-step a.

Step 5: Measure the Reaction Rate at ≈ 5°CRepeat Step 2, chilling the water to approximately 5°C inside an ice bath during sub-step a. (To create an ice bath, place 100 mL of ice and 100 mL of water in a 600 mL beaker of ice water and wait until the temperature reaches approximately 5°C. To save time, you may wish to set up the ice bath, using an additional 250 mL beaker, while working on Step 4.)Variation of Particle Size

Step 6: Measure the Reaction Rate for a Full Tablet

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Reset the timer. Start the timer as you place the tablet in the beaker.

c) Record the reaction time on the Data Sheet in the appropriate row of Table B.

d) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table B.

Step 7: Measure the Reaction Rate for a Partially Broken Tablet Repeat Step 6, but this time break the tablet into eight small pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 8: Measure the Reaction Rate for a Crushed Tablet Repeat Step 6, but this time crush the tablet into tiny pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Explanation:

According to chemical equilibrium,if you increase the temperature of a reaction, then the reaction rate will increase because particles experience more collisions at higher temperatures.

Chemical equilibrium is defined as the condition which arises during the course of a reversible chemical reaction with no net change in amount of reactants and products.A reversible chemical reaction is the one wherein the products as soon as they are formed react together to produce back the reactants.

At equilibrium, the two opposing reactions which take place take place at equal rates and there is no net change in amount of the substances which are involved in the chemical reaction.At equilibrium, the reaction is considered to be complete . Conditions which are required for equilibrium are given by quantitative formulation.

Factors which affect chemical equilibrium are change in concentration , change in pressure and temperature and presence of catalyst.

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This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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Answer:

Ni(NO3)2 is the limiting reactant.

Explanation:

- First, we balance the equation...

Ni(NO3)2 + 2 KOH --->  2 KNO3 + Ni(OH)2

- Second, we find the moles of each substance...

65g Ni(NO3)2 / 182.703g Ni(NO3)2 = 0.356 mol Ni(NO3)2

58g KOH / 56.1056g KOH = 1.034 mol KOH

- Third, to make the molar ratio equal to each other for comparison, we either multiply KOH by 1/2 or multiply Ni(NO3)2 by 2 to compare the number of moles; because the Ni(NO3)2 to KOH molar ratio is 1 to 2. Note that the multiplication of moles is only for comparison. We do not use these multiplied values. We use the values from step 2...

0.356 mol Ni(NO3)2 * 2 = 0.712 mol Ni(NO3)2

0.712 mol Ni(NO3)2 < 1.034 mol KOH ... Ni(NO3)2 is the limiting reactant.

How much of the original sample will still be there at the end of the second year if the half-life of a radioactive isotope sample is one year? by the third year's end?

when the fourth year comes to an end? Answer The balance at the conclusion of the second year equals 1 4 times the initial amount. The balance at the conclusion of the third year is equal to 1/8 of the initial amount. Radioactive isotopes that are unstable usually undergo radioactive decay in order to become stable. The nucleus of the isotope undergoes a spontaneous nuclear transition during this event, and particles and energy are released. The decay process causes half of the isotope's initial mass to disintegrate at a specific point in time known as the half-life.

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Answer:

SUBSTANCE

Explanation:

hope that help you thanx

The scientist needs to create 45 soil mixtures in order to test all possible combinations of the 10 soil types. Option B.

To calculate the number of unique soil mixtures, we can use the formula for the number of combinations of n objects taken k at a time, which is given by:

C(n,k) = n! / (k! * (n-k)!)

In this case, we have 10 soil types and we want to take 2 at a time to create unique mixtures. Thus, we substitute n=10 and k=2:

C(10,2) = 10! / (2! * (10-2)!)

= 10! / (2! * 8!)

= (10 x 9) / 2

= 45

In other words, the scientist needs to create 45 soil mixtures in order to test all possible combinations of the 10 soil types.

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Answer:

question not clear can u rewrite

Answer:

Invasive species are living things not naturally found in that ecosystem. They upset the natural balance.

Explanation:

Scientists uses scientific methods and well designed experiments to solve a scientific question. They can use some laws and previous scientific records as an aid.

A scientific question arises from selected topic under study. A scientific question addresses a natural phenomenon, a socially relevant problem or a any personal curiosity.

The scientific question must be testable. The first prediction for the question based on observation and scientific records is called the hypothesis.

The hypothesis must be tested using a well designed scientific experiment based on a scientific method. The methodology should be clearly specify what to collect and how to use them. Hence, option B is correct.

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Answer:

Explanation:

Na react with H2O to form NAOH

2 Na+2H2O....................2NAOH + H2

Ca react with water and form calcium hydroxide

Ca + 2H2O........................Ca(OH)2

Mg react with water and form Magnesium hydroxide

Mg +2H2O .........................Mg(OH)2 however this coating of mg(oh)2 prevent it from further reaction

 Fe react with water and form ferric hydride

3Fe +H2O.......................2 FeH +FeO

copper do not react with water

Answer:

its sodium hydroxide

Explanation:

Answer:change in number of atoms

Explanation:AP3X

Answer:

The rms speed of its molecules becomes. (T) has become four times. Therefore, v_(rms) will become two times,...

It is the 4th scenario is the dependent event. There are 7 gold tokens and 4 silver tokens in a cup. The first student randomly draws a gold token and keeps it. A second student randomly draws a gold token from the cup.

The fouth scenario is a dependent event because the probability of the second student drawing a gold token is affected by the outcome of the first student's draw.

If the first student draws a gold token, then there are only 6 gold tokens left in the cup, the probability changes. but  if the first student does not draw a gold token, then there are 7 gold tokens left in the cup, the probability will remain the same

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The percent yield of ammonia in the reaction  is 79.045%

The reaction of the formation of ammonia when hydrogen and nitrogen reacts is as follows:

                  N₂ + 3H₂ -------------> 2NH₃

It is given that 5.18g of Hydrogen gas and nitrogen gas reacted to produce 23.2g of Ammonia. To find the percent yield, the following formula is to be used:

Percent yield = Actual yield/ Theoretical yield x(100)

To calculate the actual yield of Ammonia, we get

Actual yield = (5.18g of H₂/1) x (1 mole of H₂ / 2g of H₂) x (2 moles of NH₃/ 3 moles of H₂) x (17g of NH₃/1 mole of NH₃)

= 5.18 x 0.5 x (34/3)

= 88.06/3

Actual yield = 29.35g

Therefore, the actual yield of ammonia is 29.35g

From this we can calculate the percent yield as follows:

Percent yield = 23.2/29.35 x(100)

Percent yield = 79.045%

Therefore the percent yield if 5.18 g of hydrogen gas and excess nitrogen gas were reacted to produce 23.2 g of ammonia is 79.045%

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The theoretical yield of water formed from the reaction of 46.8g of octane and 287g of oxygen gas is 58.58 g.

A balanced chemical equation is a representation of a chemical reaction using chemical formulas and symbols. It shows the reactants and products of the reaction, and the coefficients in front of the formulas ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced chemical equation for the reaction between octane and oxygen gas is:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

According to the stoichiometry of the balanced equation, 2 moles of octane react with 25 moles of oxygen gas to produce 18 moles of water. Therefore, the molar ratio of octane to water is 2:18 or 1:9.

First, we need to determine which reactant is limiting, i.e., which reactant will be completely consumed in the reaction. To do this, we can calculate the amount of water that would be produced if each reactant were to react completely and then compare the results.

The molar mass of octane (C8H18) is 114.23 g/mol, so 46.8 g of octane is equal to:

46.8 g / 114.23 g/mol = 0.41 mol

The molar mass of oxygen gas (O2) is 32.00 g/mol, so 287 g of oxygen gas is equal to:

287 g / 32.00 g/mol = 8.97 mol

Now, we can calculate the theoretical yield of water based on the amount of each reactant:

Octane: 0.41 mol octane × 9 mol H2O/1 mol octane = 3.69 mol H2O

Oxygen gas: 8.97 mol oxygen gas × 9 mol H2O/25 mol O2 = 3.25 mol H2O

Since the stoichiometry of the reaction indicates that the amount of water produced should be proportional to the amount of octane used, and the calculation shows that less water would be produced if we used all of the oxygen gas, we conclude that oxygen is the limiting reactant.

Therefore, the theoretical yield of water formed is 3.25 mol H2O × 18.02 g/mol = 58.58 g H2O.

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The surface area of the Lake Louise in square miles is 0.31 sq. miles

Unit conversion is the process of converting the measurement of a given amount between various units, often by multiplicative conversion factors that alter the value of the measured quantity without altering its effects.

To create a unit conversion issue where one (or more) units cancel out until just the desired unit is left, follow these steps:

The fundamental rule is to multiply when converting from a bigger unit to a smaller unit. Divide if you need to go from a smaller to a larger unit. You will reduce the number, and you are already aware that division is all about reducing numbers.

Given ,

2.59 sq kilometers is equivalent to 1 sq. mile

1 sq. kilometer = (1/2.59) sq. miles

0.8 sq kilometers is equivalent to (1/2.59)*0.8 = 0.31 sq miles

The surface area of the Lake Louise in square miles is 0.31 sq. miles

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The surface area of the Lake Louise in square miles is 0.31 sq. miles

Unit conversion is the process of converting the measurement of a given amount between various units, often by multiplicative conversion factors that alter the value of the measured quantity without altering its effects.

To create a unit conversion issue where one (or more) units cancel out until just the desired unit is left, follow these steps:

Find out what kind of unit you have.

Determine the desired unit.

Choose the proper unit conversion factor(s).

unit cancellation and math computations (e.g., multiply, divide).

The fundamental rule is to multiply when converting from a bigger unit to a smaller unit. Divide if you need to go from a smaller to a larger unit. You will reduce the number, and you are already aware that division is all about reducing numbers.

Given ,

2.59 sq kilometers is equivalent to 1 sq. mile

1 sq. kilometer = (1/2.59) sq. miles

0.8 sq kilometers is equivalent to (1/2.59)*0.8 = 0.31 sq miles

The surface area of the Lake Louise in square miles is 0.31 sq. miles

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