Xavier determined 36% of students bring their lunch to school.
If there are 325 students, how many brought their lunch?

Answer:

\( f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } }\)

Step-by-step explanation:

\(f(x) = ( {x}^{3} - 8)^{ \frac{2}{3} } \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2} - 0) \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2 - 3}{3} } \times 3 {x}^{2} \\ \\ f'(x) = 2{x}^{2}( {x}^{3} - 8)^{ \frac{ - 1}{3} } \\ \\ f'(x) = \frac{2{x}^{2}}{( {x}^{3} - 8)^{ \frac{ 1}{3} } } \\ \\ \huge \red{ \boxed{ f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } } }}\)

Answer: x = 2/23

Step-by-step explanation:

\(46x-23x=2\)

\(\mathrm{Add\:like\:terms:}\:46x-23x=23x\)

\(23x=2\)

\(\mathrm{Divide\:both\:sides\:by\:}23\)

\(\frac{23x}{23}=\frac{2}{23}\)

\($$Simplify\)

\(\bold{x=\frac{2}{23}}\)

Answer:

Step-by-step explanation:

Inthis question we are given with one equation that is 46x - 23x = 2 and we have asked to find the value of x or solve for x .

So , from here we are solving :

\( \longmapsto \: 46x - 23x = 2\)

Step 1 : Taking 23x common at left hand side :

\( \longmapsto \: 23x(2 - 1) = 2\)

Step 2 : Subtracting 1 with 2 :

\( \longmapsto \:23x = 2\)

Step 3 : Transposing 23 to right hand side :

\( \longmapsto \: \red{ \boxed{x = \frac{2}{23} }}\)

Verifying the answer :

We are verifying our answer by substituting the value of x in the given equation .

\( \longmapsto \: 46(\frac{2}{23}) - 23( \frac{2}{23} ) = 2\)

Now , calculating :

\( \longmapsto \: \cancel{46}(\frac{2}{ \cancel{23}}) - \cancel{23}( \frac{2}{ \cancel{23}} ) = 2\)

\( \longmapsto \: 4 - 2 = 2\)

\( \longmapsto \: 2 = 2\)

\( \longmapsto \: L.H.S = R.H.S\)

\( \longmapsto \: Hence, \: Verified . \: \)

please don't know what to do 3about I am going through the silence of my own thoughts on this you will be able and my brother to make the world but you will not come to Nepa with you and say you will come in your house is like the one of your daughters of God in your heart to 8be to make the Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.Nepal is a beautiful country in the world full of natural diversity.

a) The probability that the homeowner will get less than $260,000 if he leaves the house on the market for another month is equal to the area under the probability density function (PDF) of the uniform distribution from $245,000$ to $260,000$. Since the distribution is uniform, the PDF is constant over the interval of interest, and its value is $\frac{1}{270000-245000}=\frac{1}{25000}$. Therefore, the probability is:

�

(

selling price

<

260

,

000

)

=

260

,

000

−

245

,

000

25

,

000

=

0.6

P(selling price<260,000)=

25,000

260,000−245,000

​

=0.6

b) Similarly, the probability that the homeowner will get more than $260,000$ if he leaves the house on the market for another month is equal to the area under the PDF of the uniform distribution from $260,000$ to $270,000$. Therefore, the probability is:

�

(

selling price

>

260

,

000

)

=

270

,

000

−

260

,

000

25

,

000

=

0.4

P(selling price>260,000)=

25,000

270,000−260,000

​

=0.4

c) The probabilities calculated in parts a) and b) provide a way to assess the risk and potential benefit of leaving the house on the market for another month. If the homeowner is risk-averse and prefers a certain outcome, then he should take the $260,000 offer, since the probability of getting less than $260,000 is higher than the probability of getting more. On the other hand, if the homeowner is willing to take a risk for the potential benefit of a higher selling price, then he should leave the house on the market for another month. Ultimately, the decision will depend on the homeowner's risk preferences and other personal circumstances.

The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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Answer: 31.25%

Step-by-step explanation:

Draw a Ven diagram in a rectangle with 2 circles one for F and the other for C. The intersection overlap will have the 10 who play both outside the circles but within the rectangle the 7 who do neither so then fill the rest of F with 4 to give a total of 14 and 11 for the C to total 21. When you add all the numbers you’ll get a class total of 32. Then the % who play both F and C is = (10/32)*100 = 31.25%

Using the normal distribution, the area underneath the shaded region between the two z-scores is given by:

C. 0.6766.

The z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:

\(Z = \frac{X - \mu}{\sigma}\)

Hence, for this problem, the area is the p-value of z = 0.75 subtracted by the p-value of z = -1.3.

Looking at the z-table, the p-values are given as follows:

Then:

0.7734 - 0.0968 = 0.6766.

Which means that option C is correct.

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Answer:

  a) payment: $1082.84

  b) interest: $194,822.40

Step-by-step explanation:

The monthly payment on the mortgage can be found using the given formula with the given values of principal (P=195000), interest rate (r=0.053), and time period (t=30). The value of n is 12, corresponding to the number of months in a year.

The monthly payment is ...

  \(k=\left(1+\dfrac{r}{n}\right)^{nt}=\left(1+\dfrac{0.053}{12}\right)^{12\cdot30}\approx 4.88661119\\\\\text{monthly payment}=\dfrac{P\cdot\dfrac{r}{n}\cdot k}{k-1}=\dfrac{195000\cdot0.0044166667\cdot4.88661119}{4.88661119-1}\\\\\boxed{\text{monthly payment}=\$1082.84}\)

__

The interest owed is the difference between the total of monthly payments and the principal of the loan:

  interest owed = (360)(1082.84) -195000 = 194,822.40

The interest owed over 30 years is $194,822.40.

Answer:

Step-by-step explanation:

This means the point travled to -5 on the x axis, then went down to -5 on the y axis, and then went +5 along the z axis

The variance of Billy's grades obtained from his test scores is 15.76

The variance is a measure of variability or spread a dataset. The variance can be calculated from the sum of the square of the differences of the data points from the mean divided by the number or count of the data points.

The variance of Billy's test scores can be calculated by finding the mean or the average of the scores, then finding the sum of the squares of the differences of each score from the mean as follows;

The mean score = (89 + 88 + 93 + 90 + 81)/5 = 88.2

The square of the differences of the values from the mean can be calculated as follows;

(89 - 88.2)² = 0.64, (88 - 88.2)² = 0.04, (93 - 88.2)² = 23.04, (90 - 88.2)² = 3.24, and (81 - 88.2)² = 51.84

The sum of the square of the differences is therefore;

0.64 + 0.04 + 23.04 + 3.24 + 51.84 = 78.8

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Answer:

6 units

Step-by-step explanation:

There is only a translation being shown, meaning that the shape is only moving. It is not getting larger or smaller.

Answer:

your answer will be option C.6

because the length does not change on translation

Step-by-step explanation:

have a nice day

Answer:

5/6

Step-by-step explanation:

I hope this helps you you gotta convert the 2/3 into 4/6 and then you add 4/6 + 1/6= 5/6

Answer:

75 po ang sagot

Step-by-step explanation:

pa brailess 1x po pls

Answer:

x < -4

-64/16 = -4

Answer:

19 trains

Step-by-step explanation:

Firstly, we need to calculate the difference in the number of hours

From the question, we have 7 am to 11 pm

7 am to 7 pm is 12 hours

7 pm to 11 pm is 4 hours

So total is 16 hours

16 hours to minutes is multiplied by 60 minutes

We have this as;

16 * 60 = 960 minutes

so to get the number of trains, we simply have to divide the number of minutes by 50

Mathematically, we have this as 960/50

= 19.2

Since we cannot have a fractional train stop, it means the number of trains that has stopped is 19

I messed up sorry I gave you the wrong answer just ignore this

Answer:

\((x + 12)^2 + (y + 7)^2 = 277\)

Step-by-step explanation:

Equation of a circle:

The equation of a circle with center \((x_0,y_0)\) is given by:

\((x - x_0)^2 + (y - y_0)^2 = r^2\)

In which r is the radius.

Center (-12, – 7)

This means that \(x_0 = -12, y_0 = -7\). So

\((x - x_0)^2 + (y - y_0)^2 = r^2\)

\((x - (-12))^2 + (y - (-7))^2 = r^2\)

\((x + 12)^2 + (y + 7)^2 = r^2\)

Passes through the point (-3,7).

This means that we use \(x = -3, y = 7\) to find the radius squared. So

\((x + 12)^2 + (y + 7)^2 = r^2\)

\((-3 + 12)^2 + (7 + 7)^2 = r^2\)

\(81 + 196 = r^2\)

\(r^2 = 277\)

The equation of the circle is:

\((x + 12)^2 + (y + 7)^2 = r^2\)

\((x + 12)^2 + (y + 7)^2 = 277\)

Answer:

The equation of the line that passes through the point (-6,8) and has a slope of -5/3 is y = (-5/3)x - 2.

Step-by-step explanation:

The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

We have the point (-6,8) and a slope of -5/3.

Step 1: Use the point-slope formula to find the equation of the line in point-slope form.

y - y1 = m(x - x1)

where x1 and y1 are the coordinates of the given point.

y - 8 = (-5/3)(x - (-6))

Simplify this equation:

y - 8 = (-5/3)(x + 6)

Step 2: Convert the equation to slope-intercept form.

Distribute (-5/3) to get:

y - 8 = (-5/3)x - 10

Add 8 to both sides:

y = (-5/3)x - 2

This is the equation of the line in slope-intercept form. Therefore, the equation of the line that passes through the point (-6,8) and has a slope of -5/3 is y = (-5/3)x - 2.

\(\bold{\huge{\underline{ Solution }}}\)

- I have used different colours for indicating different process

- I used brown colour to indicate steps

- I used green colour for explaining solution

- Pink colour for known properties of integration

- Purple colour for the middle steps that are optional.

[Note :- For solving such questions it is mandatory that you should know all the functions and it's derivatives ]

\(\sf{=}{\sf{\dfrac{ x^{2}}{2}}}{\sf{ + 7x + 67x .In| x - 4 | - 30.In| x - 3 | + c }}\)

Answer:

\(\displaystyle \large{\frac{x^2}{2}+7x+67\ln |x-4|-30\ln |x-3| + C}\)

Step-by-step explanation:

To find an integration of this function, first, you must know these integration methods and differences of them.

These methods above are common when it comes to integrating fractional functions, except there are differences when to use these methods.

Examples (of these integrands that require partial fraction technique)

\(\displaystyle \large{\int \frac{3}{x^2-5x+6} \ dx}\\\displaystyle \large{\int \frac{x+2}{x^2-4} \ dx}\)

Examples (of these integrands that require long division)

\(\displaystyle \large{\int \frac{x^2+5x+6}{x+2} \ dx}\\\displaystyle \large{\int \frac{x^4+3}{x} \ dx }\)

Therefore, from the given integral, the integrand requires long division method. (See attachment for long division.)

After long division, we should get:

\(\displaystyle \large{\int x+7+\frac{37x-81}{x^2-7x+12} \ dx}\)

Recall important properties of integral such as:

\(\displaystyle \large{\int [f(x) \pm g(x)] \ dx = \int f(x) \ dx \pm \int g(x) \ dx}\)

Hence:

\(\displaystyle \large{\int x \ dx + \int 7 \ dx + \int \frac{37x-81}{x^2-7x+12} \ dx}\)

Recall important integration formula for polynomial and constant:

\(\displaystyle \large{\int x^n \ dx = \frac{x^{n+1}}{n+1} + C}\\\displaystyle \large{\int x \ dx = \frac{x^2}{2} + C}\\\displaystyle \large{\int k \ dx = kx + C \ \ \tt{(k \ \ is \ \ a \ \ constant.)}\)

Therefore:

\(\displaystyle \large{\frac{x^2}{2}+7x+\boxed{\int \frac{37x-81}{x^2-7x+12} \ dx}}\)

From the boxed integral above, we cannot evaluate it by default. From what I said, if the degree of numerator is less than the degree of denominator, we’ll use partial fraction technique.

Therefore, factor the denominator:

\(\displaystyle \large{\frac{37x-81}{(x-4)(x-3)}}\)

Set to A/x-4 and B/x-3

\(\displaystyle \large{\frac{37x-81}{(x-4)(x-3)} = \frac{A}{x-4} + \frac{B}{x-3}}\)

Multiply both sides by (x-4)(x-3).

\(\displaystyle \large{\frac{37x-81}{(x-4)(x-3)} \cdot (x-4)(x-3)= \frac{A}{x-4} \cdot (x-4)(x-3) + \frac{B}{x-3} \cdot (x-4)(x-3)}\\\displaystyle \large{37x-81= A(x-3) + B(x-4)}\\\displaystyle \large{37x-81= Ax-3A+Bx-4B}\\\displaystyle \large{37x-81= (A+B)x-(3A+4B)}\)

Then compare the coefficients:

\(\displaystyle \large{\left \{ {{A+B=37} \atop {3A+4B=81}} \right}\)

Solve the simultaneous equation for A and B.

\(\displaystyle \large{\left \{ {{A=37-B} \atop {3A+4B=81}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {3(37-B)+4B=81}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {111-3B+4B=81}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {111+B=81}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {B=81-111}} \right}\\\displaystyle \large{\left \{ {{A=37-B} \atop {B=-30}} \right}\\\displaystyle \large{\left \{ {{A=67} \atop {B=-30}} \right}\\\)

Therefore, A = 67 and B = -30. Substitute the values in:

\(\displaystyle \large{\int \frac{67}{x-4}-\frac{30}{x-3} \ dx}\\\displaystyle \large{\int \frac{67}{x-4} \ dx -\int \frac{30}{x-3} \ dx}\)

Recall the integration formula for above:

\(\displaystyle \large{\int \frac{k}{x-a} \ dx = \int k \cdot \frac{1}{x-a} \ dx = k\ln |x-a| + C}\)

Therefore:

\(\displaystyle \large{\int \frac{37x-81}{x^2-7x+12} \ dx = \int \frac{67}{x-4}-\frac{30}{x-3} \ dx = 67\ln |x-4| - 30\ln |x-3|}\)

Back from this:

\(\displaystyle \large{\frac{x^2}{2}+7x+\boxed{\int \frac{37x-81}{x^2-7x+12} \ dx}}\)

Substitute in:

\(\displaystyle \large{\frac{x^2}{2}+7x+67\ln |x-4|-30\ln |x-3| + C}\)

Therefore the solution is:

\(\displaystyle \large \boxed{\frac{x^2}{2}+7x+67\ln |x-4|-30\ln |x-3| + C}\)

Answer:

5

Step-by-step explanation:

5555

Answer:

x = 65

Step-by-step explanation:

the sum of the interior angles of a quadrilateral = 360°

sum the angles and equate to 360

x + 95 + 118 + 82 = 360

x + 295 = 360 ( subtract 295 from both sides )

x = 65

The number of runs per inning that Kim's team could have scored to win the game would be greater than 11/8.

Let's suppose that in the final four innings, Kim's squad scored "p" runs on average. In that case, Kim's side would have scored a total of:

(Number of innings) x (Total runs scored by Kim's side) (Number of runs per inning)

Kim's squad scored 6 runs in the first 4 innings, so there were a total of the following runs scored by her team:

Six runs were scored by Kim's squad in the first four innings.

The total number of innings in the game would be 8, as there were still 4 innings to play. As a result, Kim's squad scored a total of runs during the entire game, which is:

Eight innings times the number of runs per inning is eight runs for Kim's team overall.

Kim's team ended up winning the game with the most runs. The total runs scored by her team must therefore be higher than the total runs scored by the opposing team. The opposing team scored 17 runs in the first four innings and none more in the following four. The total runs scored by the opposition would therefore be as follows:

The other team scored a total of 17 runs.

Combining everything, we may represent the inequality as follows:

Total runs scored by Kim's team surpasses all other teams' total runs.

8p + 6 > 17

When we reduce the inequality, we obtain:

8p > 11

When we multiply both sides by 8, we get:

p > 11/8

In order to win the game, Kim's squad would have needed to score more runs per inning than 11/8.

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Answer:

6+4p>17

Kim's team scored a minimum of

3 runs per inning.

Step-by-step explanation: Khan Academy

Given:

a function f(x) = (x-2)^2 is given.

Find:

we have to find the function whose graph is a result of horizonal shift of 2 units of the original graph.

Explanation:

Since the given graph of the function is shifted 2 units horizontally,

and we know y is vertical axis, x is horizontal axis.

So put x = x+2 in the given function, we get

Therefore the graph of f(x)=(x-2)^2 is a result of horizontal shift of 2 units of f(x) = x^2.

The graphs are given for the reference

\(solution \\ x = 10 \\ now \\ (7x - 5) \\ = (7 \times 10 - 5) \\ = (70 - 5) \\ = 65\)

Hope it helps....

Good luck on your assignment

Answer:

65

Step-by-step explanation:

= 7x-5

Putting x = 10

= 7(10)-5

= 70-5

= 65

Answer:

Step-by-step explanation:

If he is 43 ft underground and climbs a ladder up 14 ft then he is now 29 ft underground. You subtract 14 from 43 to get 29 ft.

Hope that helped! :)

The value of the missing segment n using the product of intersecting chord theorem is 14cm

The product of the segments of two intersecting chords are equal.

The segments of the chords ;

Chord 1 = 4 and n

Chord 2 = 7 and 8

The principle can be related Mathematically thus ;

4 × n = 7 × 8

4n = 56

Divide both sides by 4

4n/4 = 56/4

n = 14

Therefore, the value of n in the question is 14cm

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Answer:

No

Step-by-step explanation:

For this problem let the ratio stand for pages: minutes. Emeline can type at a ratio of 10:4. Simplify by dividing by the greatest common factor. In this case, that is 2. So, the final ratio is 5:2. Merle's ratio is 15:5. Simplify this ratio the same way, using 5 as the GCF, to make a final ratio of 5:3. Since 5:2 is not the same as 5:3, they are clearly not equal ratios.

The correct answer is 3/2. In this case, x = 3/2, and its square, (3/2)^2 = 9/4, is rational. x satisfies the given condition.option (c)

To explain further, we need to understand the properties of rational and irrational numbers.

A rational number can be expressed as a fraction of two integers, while an irrational number cannot be expressed as a fraction and has non-repeating, non-terminating decimal representations.

In the given options, (a) √5102.0 (£) and (b) √2 are both irrational numbers.

Their squares, (√5102.0)^2 and (√2)^2, would also be irrational, violating the given condition. On the other hand, (d) 4/5 is rational, and its square, (4/5)^2 = 16/25, is also rational.

Option (c) 3/2 is rational since it can be expressed as a fraction. Its square, (3/2)^2 = 9/4, is rational as well.

Therefore, (c) 3/2 is the only option where x is rational, but its square is irrational, satisfying the condition mentioned in the question.

In summary, the number x that satisfies the given condition, where x^2 is irrational but x is rational, is (c) 3/2.option (c)

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Answer:

\(-\frac{1}{2} (x - 1)^2 + 1\)

Explanation:

Since it is flipped and now extending to negative infinity, we make \(x^2\) negative, so it is \(-x^2\).

Lastly, there are a few shifts, it is shifted right once and up once.

To shift it right once, you would subtract a 1 from x directly: \(-(x - 1)^2\)

To shift it up once, you would add 1 to the entire equation: \(-(x - 1)^2 + 1\)

To account for the stretching, it would be: \(-\frac{1}{2} (x - 1)^2 + 1\)

Answer:

Top-left system: (3,5)

Bottom-right

system: (-1,0)

Step-by-step explanation:

One way to solve a system of equations is to graph them. The solution is the point of intersection (where the lines cross). If you need to give the x-value and y-values separately, the first number in the pair is the x and the second number is the y.