\(x = ( - 16, - 6) \gamma ( - 2,8)\)
hope it helps
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Can someone please help me I will mark u brilliant
Answer: 6.50 + 5.75n
Step-by-step explanation:
Answer:
6.50 + 5.75n
Step-by-step explanation:
because since it said let n equal the number of hours AFTER the FIRST hour.
(just have to read the question carefully)
Graph Set A: {(c,y):y>2x^2+5x-3
Hurry!
The following is a function, true or false?
Answer:
Step-by-step explanation: true
Which of the scenarios below would a t-test of the difference between means for dependent samples be appropriate?
a) Comparing the mean mathe 2G pfa sample of Grade 8 students in a peer instruction program and a sample of Grade 8 students receiving traditional instruction.
b) Comparing the mean perception of company morale of a sample of managers and a sample of subordinates of each manager.
c) Comparing the mean bullying awareness scores of a sample of Grade 6 boys and a sample of Grade 6 girls at a particular school.
d) Comparing the mean amount of time spent studying of a sample of adult learners and a sample of traditional students in an online course.
Answer:
4g
Step-by-step explanation:
scatter
A nine-month old baby drank an average of 7 1/4 oz during each of four feedings. If the baby drank 7 1/2oz, 7 3/8oz, & 6 3/8oz in the first three feedings, how many ounces were taken during the fourth feeding?
A) 7 3/8
B) 6 3/8
C) 6 3/4
D) 7 3/4
Show work please
Answer: D) 7 3/4
Step-by-step explanation:
With averages, we add all the values and divide by the number of values. Here, we know three out of the four days, let's label the day we don't know x. There are four days, so we can divide by four. 7 1/4 is the average, so we can set the equation equal to 7 1/4.
7 1/4 = (7 1/2 + 7 3/8 + 6 3/8 + x) / 4
Let's multiply both sides by 4 to get rid of the fraction. Let's also add what is in the parentheses
29 = 21 1/4 + x
Now we can isolate x by subtracting 29-21 1/4
so
x = 7 3/4 thus the answer is D
Answer:
D) 7 3/4
Step-by-step explanation:
Let x = amount of last feeding.
7 1/4 = (7 1/2 + 7 3/8 + 6 3/8 + x)/4
4 × 7 1/4 = 7 1/2 + 7 3/8 + 6 3/8 + x
28 + 1 = 7 4/8 + 7 3/8 + 6 3/8 + x
29 = 20 10/8 + x
(20 10/8 is the same as 20 + 10/8 = 20 + 8/8 + 2/8 = 20 + 1 + 1/4 = 21 + 1/4 = 21 1/4)
29 = 21 2/8 + x
29 = 21 1/4 + x
x = 29 - 21 1/4
x = 28 4/4 - 21 1/4
x = 7 3/4
Answer: 7 3/4
4x(10-3+2) simplify expression
Answer:
20
Step-by-step explanation:
Find to value of a if you knew the perimeter was 250 inches long
Answer:
To find the value of "a" when you know the perimeter of a shape, you need to know the specific shape you're referring to. Please provide more information about the shape in question, such as whether it's a rectangle, triangle, or another geometric figure. Additionally, if you have any specific measurements or relationships between the sides of the shape, please provide them as well.
Solve for x when x^2+x-2=0
We can solve the equation as:
\(x^2+x-2=0\)\(\begin{gathered} x=\frac{-1\pm\sqrt[]{1^2-4\cdot1\cdot(-2)}}{2\cdot1} \\ x=\frac{-1\pm\sqrt[]{1+8}}{2} \\ x=\frac{-1\pm\sqrt[]{9}}{2} \\ x=\frac{-1\pm3}{2} \\ x_1=\frac{-1-3}{2}=-\frac{4}{2}=-2 \\ x_2=\frac{-1+3}{2}=\frac{2}{2}=1 \end{gathered}\)Answer: The solution for this equation is x=-2 and x=1.
find the value of
tan 45º . tan- 30° tan 60°
Answer:
Find the exact value of tan 45º = 1/1 = 1.
Find the exact value of cos 30º = √3/2.
Find the exact value of csc 60º = 2√(3)/3
Step-by-step explanation:
math
The diagram shows EFG. Which term describes point H?
A. Circumcenter
B. Incenter
C. Orthocenter
D. Centroid
Point H is the ortho-center of our given triangle and option c is the correct choice.
We have been given an image of a triangle. We are asked to find the term that describes point H.
We can see that point H is the point, where, all the altitudes of our given triangle EFF are intersecting.
We know that ortho-center of a triangle is the point, where all altitudes of triangle intersect. Therefore, point H is the ortho-center of our given triangle and option c is the correct choice.
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In this Exploration we will use a situation modeled by an exponential function to investigate the rate of change of that function. There will be two different types of rate of change examined, the average rate of change of the function and the instantaneous rate of change of the function. The average rate of change of a function gives information about how the dependent variable of the function changes with respect to the independent variable between two independent values of the function. This can be expressed as the average rate of change off, which is the quantity
f(x)-f(c)/x-c
where x is an independent value of choice and c is a particular value of interest in the domain of f . In what context have you encountered expression (1) in past mathematics classes? 1. What do the average rates of change found in Exercise 3 represent with respect to the rim of the tire and its proximity to the street? 2. We want to find out how fast the rim of the tire is approaching the street at the instant t=3sec. Discuss how using the average rate of change is an approximation but not exact at the instant t=3sec
1. The average rates of change found in Exercise 3 represent the average speed at which the rim of the tire is moving
towards or away from the street between two specific time intervals.
2. The instantaneous rate of change, which is typically found by taking the derivative of the function and evaluating it at the desired point (t=3 sec in this case).
In past mathematics classes, you may have encountered expression (1) in the context of finding the slope of a secant
line between two points on a curve, which represents the average rate of change of a function.
1. The average rates of change found in Exercise 3 represent the average speed at which the rim of the tire is moving
towards or away from the street between two specific time intervals.
2. Using the average rate of change is an approximation but not exact at the instant t=3sec because it considers the
change over an interval of time rather than at a specific instant.
To find the exact rate at which the rim of the tire is
approaching the street at t=3 sec, we need to calculate the instantaneous rate of change, which is typically found by
taking the derivative of the function and evaluating it at the desired point (t=3 sec in this case).
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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than examine the records for all students, the dean randomly selects 200 students and finds that 118 of them are receiving financial aid. The 95% confidence interval for is 0.590.07. Interpret this interval. A. It can be said that 95% of the students get between 52% and 66% of their tuition paid for by financial aid. B. One can be 95% confident that between 52% and 66% of the sampled students receive some sort of financial aid. C. One can be 95% confident that the true proportion of all students receiving financial aid is between 0.52 and 0.66. D. One can be 95% confident that 59% of the students are on some sort of financial aid.
Answer:
C. One can be 95% confident that the true proportion of all students receiving financial aid is between 0.52 and 0.66
Step-by-step explanation:
Given that the confidence interval is a term that defines a range of values with the probability to contain a population value that has an actual degree of confidence.
This is represented in a situation where population means falls in between upper and lower intervals.
Hence, in this case, the correct interpretation is option C: One can be 95% confident that the true proportion of all students receiving financial aid is between 0.52 and 0.66
Each week in math class, Haley takes a quiz with 5 questions. She earns 2 points for each correct answer and loses 1 point for each incorrect answer. If she answers 4 questions correctly and 1 question incorrectly on each quiz, how many points will she earn after 6 weeks?
Answer:
42
Step-by-step explanation:
4x2x6=48
48-6=42
Answer:
42
Step-by-step explanation
8 - 1 * 6 = 42
PQ is perpendicular bisector if ST. Find the values of m and n.
The given parallelogram is a Rhombus, with characteristics
1- The diagonals bisect each other at the midpoint.
2- Each diagonal divides it into two congruent triangles
3- All the sides of the Rhombus are of equal lenght.
PQ divides the figure into two congruent triangles, then the corresponding sides are equal.
If PS=TP, then
\(\begin{gathered} 3m+9=5m-13 \\ 3m-5m=-13-9 \\ -2m=-22 \\ -\frac{2m}{-2}=-\frac{22}{-2} \\ m=11 \end{gathered}\)If SQ=QT, then
\(\begin{gathered} 6n-3=4n+14 \\ 6n-4n=14+3 \\ 2n=17 \\ \frac{2n}{2}=\frac{17}{2} \\ n=8.5 \end{gathered}\)Becky invested 19,800 in a CD that pays an annual interest rate of 5.3%. The CD is set to compound
daily. How much is in Becky’s account after 9 years?
use the formula for exponential decay:
f(t)=a(l-r)^t
After 9 years, the amount in Becky's account will be approximately \($29,530.95\).
To calculate the amount in Becky's account after 9 years, we need to use the formula for compound interest, not exponential decay.
The formula for compound interest is:
\(A = P(1 + r/n)^{(n \times t)\)
Where:
A is the final amount (the amount in Becky's account after 9 years)
P is the principal amount (the initial investment) which is\($19,800\)
r is the annual interest rate in decimal form, which is 5.3% or 0.053
n is the number of times the interest is compounded per year, in this case, it compounds daily, so n = 365 (assuming a non-leap year)
t is the number of years, which is 9
Now we can substitute the given values into the formula and calculate the final amount:
A = 19,800 × (1 + 0.053/365)⁽³⁶⁵ ˣ ⁹⁾
Calculating this expression will give us the amount in Becky's account after 9 years.
A ≈ 19,800 × (1.0001452055)³²⁸⁵
A ≈ 19,800 × 1.4918336585
A ≈ 29,530.95
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Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this lesson to solve the following exercise.
Find the following sums without using a calculator or a formula. Hint: Apply the procedure used by Gauss. (See the Math Matters on page 31.)
+393 +394 + 395
(a) 1+2+3+4+...+392
(b) 1+2+3+4
x
546 + 547 +548 + 549
(c) 2+4+6+8+...+76 + 78 + 80 +82
(a) The sum of the series 1+2+3+4+...+392 is 77,028.
(b) The sum of the series 1+2+3+4...x is (x/2)(1 + x).
(c) The sum of the series 546 + 547 + 548 + 549 is 2,190.
To solve the exercise using Polya's four-step problem-solving strategy, we will apply the procedures presented in the lesson.
(a) For the series 1+2+3+4+...+392:
Using the arithmetic series formula Sn = (n/2)(a + l), where n is the number of terms, a is the first term, and l is the last term, we can substitute the values: Sn = (392/2)(1 + 392) = 196(393) = 77,028.
(b) For the series 1+2+3+4...x:
To find the sum of this series, we need to know the number of terms (n) based on the value of x. Since the series follows a consecutive pattern, the number of terms will be equal to x itself. Thus, the sum of the series would be Sn = (x/2)(1 + x).
(c) For the series 546 + 547 + 548 + 549:
Using the arithmetic series formula Sn = (n/2)(a + l), we can determine the number of terms (n) by subtracting 546 from 549 and then adding 1: n = 549 - 546 + 1 = 4. Substituting the values into the formula: Sn = (4/2)(546 + 549) = 2(1095) = 2,190.
The final answer for each part is:
(a) The sum of the series 1+2+3+4+...+392 is 77,028.
(b) The sum of the series 1+2+3+4...x is (x/2)(1 + x).
(c) The sum of the series 546 + 547 + 548 + 549 is 2,190.
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If Malik has 4 times as many nickels as quarters and they have a combined value of 315 cents, how many of each coin does he have?
Set up your equation
4q + q = 315 Add (q = amount of quarters)
5q = 315 Divide
q = 63
Therefore he has 63 quarters.
To find the amount of nickels, multiply 4 and 63
4 x 63 = 252
Therefore he has 63 quarters and 252 nickels.
I hope this helps! :)
100 POINTS
Don and Celine have been approved for a $400,000, 20-year mortgage with an APR of 3.35%. Using the mortgage and interest formulas, set up a two-month amortization table with the headings shown and complete the table for the first two months.
To set up the amortization table, we can use the mortgage and interest formulas as follows:
Mortgage formula:
M = P [ i(1 + i)^n / (1 + i)^n - 1]
where M is the monthly payment, P is the principal (the amount borrowed), i is the monthly interest rate (APR divided by 12), and n is the total number of payments (20 years multiplied by 12 months per year).
Interest formula:
I = P * i
where I is the monthly interest payment, P is the remaining principal balance, and i is the monthly interest rate.
Using these formulas, we can set up the following amortization table for the first two months:
Month Payment Principal Interest Balance
1 $400,000
2
To fill in the table, we need to calculate the monthly payment (M) and the monthly interest payment (I) for the first month, and then use these values to calculate the principal payment for the first month. We can then subtract the principal payment from the initial balance to get the balance for the second month, and repeat the process to fill in the remaining columns.
To calculate the monthly payment (M), we can use the mortgage formula:
M = P [ i(1 + i)^n / (1 + i)^n - 1]
where P is the principal amount, i is the monthly interest rate, and n is the total number of payments.
Plugging in the given values, we get:
M = 400,000 [ 0.00279 (1 + 0.00279)^240 / (1 + 0.00279)^240 - 1]
M = $2,304.14
Therefore, the monthly payment is $2,304.14.
To calculate the interest payment for the first month, we can use the interest formula:
I = P * i
where P is the remaining principal balance and i is the monthly interest rate.
Plugging in the values for the first month, we get:
I = 400,000 * 0.00279
I = $1,116.00
Therefore, the interest payment for the first month is $1,116.00.
To calculate the principal payment for the first month, we can subtract the interest payment from the monthly payment:
Principal payment = Monthly payment - Interest payment
Principal payment = $2,304.14 - $1,116.00
Principal payment = $1,188.14
Therefore, the principal payment for the first month is $1,188.14.
To calculate the balance for the second month, we can subtract the principal payment from the initial balance:
Balance = Initial balance - Principal payment
Balance = $400,000 -$1,188.14
Balance = $398,811.86
Therefore, the balance for the second month is $398,811.86.
Using these values, we can complete the first two rows of the amortization table as follows:
Month Payment Principal Interest Balance
1 $2,304.14 $1,188.14 $1,116.00 $398,811.86
2
To fill in the remaining columns for the second month, we can repeat the process using the new balance of $398,811.86 as the principal amount for the second month. We can calculate the interest payment using the same method as before, and then subtract the interest payment from the monthly payment to get the principal payment. We can then subtract the principal payment from the balance to get the new balance for the third month, and repeat the process for the remaining months of the amortization period.
This graph represents the flight path of a model rocket launched in a park.
What do the key features of the curve represent in terms of the flight path of the rocket?
Chose from the drop-down to match each situation.
ill give brainlyest to the first to correctly answer this
The drop down menu is used to match each situation as below.
1. The rocket reached its maximum the x-value of the vertex
height in 5 s.
2. ground level the y-intercept
3. The rocket launcher was the y-value of the point containing
on the ground. the x-intercept on the right
4. The rocket was in the air 10 the x-intercept on the right
5. The maximum height of the the y-value of the vertex
rocket is 50 ft.
6. the time the rocket was the x-value of the point containing the
launched y-intercept
What is the key feature of the curveThe key features of the curve such as the x intercept is the point the launcher and the rocket were on ground.
The vertex is the point the rocket had the maximum and height.
Generally, the curve traces a parabolic path
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Part A: Factor 3x2c2 + 5xc2 − 2c2. Show your work. (4 points) Part B: Factor x2 + 6x + 9. Show your work. (3 points) Part C: Factor x2 − 9. Show your work. (3 points) (10 points)
Answer:
\(\boxed{\mathrm{view \: explanation}}\)
Step-by-step explanation:
A) 3x²c² + 5xc² - 2c²
Factor c² from all terms in the expression.
c²(3x² + 5x - 2)
Factor 3x² + 5x - 2
c²(3x-1)(x+2)
B) x² + 6x + 9
x² + 3x + 3x + 9
Factor common terms.
x(x+3)+3(x+3)
Take x+3 common.
(x+3)(x+3)
C) x² - 9
x² -3²
Apply formula : a² - b² = (a+b)(a-b)
(x+3)(x-3)
Answer:
A) \(c^2(3x-1)(x+2)\)
B) \((x+3)(x+3)\)
C) \((x+3)(x-3)\)
Step-by-step explanation:
Part A:
\(3x^2c^2+5xc^2-2c^2\)
Taking \(c^2\) common
\(c^2(3x^2+5x-2)\)
Using mid term break formula
\(c^2 (3x^2+6x-x-2)\)
\(c^2[3x(x+2)-1(x+2)]\)
\(c^2(3x-1)(x+2)\)
Part B:
\(x^2 + 6x + 9.\)
\((x)^2+2(x)(3)+(3)^2\)
\((x+3)^2\)
\((x+3)(x+3)\)
Part C:
\(x^2-9\)
\((x)^2-(3)^2\)
\((x+3)(x-3)\)
Segment JL has endpoints J(-3, -4) and L(7, 6). What are the coordinate of point K, so that point K is on line segment JL and JK = 3/5 JL. Explain.
Answer:
K(3,2).
Step-by-step explanation:
We want to find a point K(x,y).
JK = 3/5 JL.
This means that:
\(K - J = \frac{3(L - J)}{5}\)
We use this to find both the x-coordinate and the y-coordinate of K.
x-coordinate:
x-coordinate of J: -3
x-coordinate of L: 7
\(K - J = \frac{3(L - J)}{5}\)
\(x - (-3) = \frac{3(7 - (-3))}{5}\)
\(x + 3 = 6\)
\(x = 3\)
y-coordinate:
y-coordinate of J: -4
y-coordinate of L: 6
\(K - J = \frac{3(L - J)}{5}\)
\(y - (-4) = \frac{3(6 - (-4))}{5}\)
\(y + 4 = 6\)
\(y = 2\)
The point is K(3,2).
whats the distance between points p1=(-3,5) P2=(4,2)
Step-by-step explanation:
First, find the vector.
= (4,2) - (-3,5)
= (4-(-3),2-5)
= (7,-3)
And then, find the distance.
= √(7² + (-3)²)
= √(49 + 9)
= √58 ✓
PLEASE HELP!!! Solve 5sin(π/3x)=3 for the four smallest positive solutions
This one's a special case of a right angled triangle with sides (3, 4, and 5 units)
Back to the problem :\(\qquad\displaystyle \tt \dashrightarrow \: 5 \sin \bigg( \frac{ \pi}{3} x \bigg) = 3\)
\(\qquad\displaystyle \tt \dashrightarrow \: \sin \bigg( \frac{ \pi}{3} x \bigg) = \frac{3}{5} \)
Now, check the triangle, sin 37° = 3/5
therefore,
\(\qquad\displaystyle \tt \dashrightarrow \: \sin \bigg( \frac{ \pi}{3} x \bigg) = \sin(37 \degree) \)
[ convert degrees on right side to radians ]
\(\qquad\displaystyle \tt \dashrightarrow \: \sin \bigg( \frac{ \pi}{3} x \bigg) = \sin \bigg(37 \degree \times \frac{ \pi}{180 \degree} \bigg ) \)
There are three more possible values as :
\(\qquad\displaystyle \tt \dashrightarrow \: \sin( \theta) = \sin(\pi - \theta) \)
\(\qquad\displaystyle \tt \dashrightarrow \: sin( \theta) = \sin \bigg( { 2\pi}{} + \theta \bigg) \)
\(\qquad\displaystyle \tt \dashrightarrow \: sin( \theta) = \sin \bigg( \frac{ 3\pi}{} - \theta\bigg) \)
Equating both, we get : First value :\(\qquad\displaystyle \tt \dashrightarrow \: \frac{ \pi}{3} x = 37 \times \frac{ \pi}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: x = 37 \times \frac{ \cancel \pi}{180} \times \frac{3}{ \cancel \pi} \)
\(\qquad\displaystyle \tt \dashrightarrow \: x = \frac{37}{60} \)
or in decimals :
\(\qquad\displaystyle \tt \dashrightarrow \: x = 0.616666... = 0.6167\)
[ 6 repeats at third place after decimal, till four decimal places it would be 0.6167 after rounding off ]
similarly,
Second value :\(\qquad\displaystyle \tt \dashrightarrow \: \pi - \frac{ \pi}{3} x = 37 \times \frac{ \pi}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: \pi \bigg(1 - \frac{x}{3} \bigg ) = 37 \times \frac{ \pi}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: 1 - \frac{x}{3} = \frac{37}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: - \frac{x}{3} = 0.205 - 1\)
\(\qquad\displaystyle \tt \dashrightarrow \: \frac{x}{3} = 0.795\)
\(\qquad\displaystyle \tt \dashrightarrow \: x = 3 \times 0.795\)
\(\qquad\displaystyle \tt \dashrightarrow \: x = 2.385\)
Third value :\(\qquad\displaystyle \tt \dashrightarrow \: 2\pi + \frac{ \pi}{3} x = 37 \times \frac{ \pi}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: \pi \bigg(2 + \frac{x}{3} \bigg ) = 37 \times \frac{ \pi}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: 2 + \frac{x}{3} = \frac{37}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: \frac{x}{3} = 0.205 - 2\)
\(\qquad\displaystyle \tt \dashrightarrow \: \frac{x}{3} = - 1.795\)
\(\qquad\displaystyle \tt \dashrightarrow \: x = 3 \times -1 .795\)
\(\qquad\displaystyle \tt \dashrightarrow \: x = -5.385\)
Fourth value :\(\qquad\displaystyle \tt \dashrightarrow \: 3 \pi - \frac{ \pi}{3} x = 37 \times \frac{ \pi}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: \pi \bigg(3 - \frac{x}{3} \bigg ) = 37 \times \frac{ \pi}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: 3 - \frac{x}{3} = \frac{37}{180} \)
\(\qquad\displaystyle \tt \dashrightarrow \: - \frac{x}{3} = 0.205 - 3\)
\(\qquad\displaystyle \tt \dashrightarrow \: \frac{x}{3} = 2.795\)
\(\qquad\displaystyle \tt \dashrightarrow \: x = 3 \times 2.795\)
\(\qquad\displaystyle \tt \dashrightarrow \: x = 8.385\)
" x can have infinite number of values here with the same result, here are the four values as you requested "
I hope it was helpful ~
Use the two given functions to write y as a function of x.
y = -3a + 3, a = -5x + 1
Answer:
Step-by-step explanation:
To write y as a function of x using the given functions, we can substitute the value of "a" in the first equation with the expression "-5x + 1" from the second equation.
Given:
y = -3a + 3
a = -5x + 1
Substituting the value of "a" in the first equation:
y = -3(-5x + 1) + 3
Now, let's simplify this expression:
y = 15x - 3 + 3
y = 15x
Therefore, y can be expressed as a function of x as:
y = 15x
I’ll give brainlest please help!
D) If one gallon of paint covers 0.6 square meters, how many gallons of black paint they
need to paint the house?
Show your work
The width of the house is 3.5m and the height is 2.5m
Answer:
14.5833333333
Step-by-step explanation:
3.5x2.5=8.75, divided by 0.6 is 14.5833333333
area of sector................................
Answer:
A ≈ 25.1 cm²
Step-by-step explanation:
the area (A) of the sector is calculated as
A = area of circle × fraction of circle
= πr² × \(\frac{\frac{4\pi }{9} }{2\pi }\)
= π × 6² × \(\frac{\frac{4\pi }{9} }{2\pi }\)
= 36π × \(\frac{\frac{4\pi }{9} }{2\pi }\)
= 18 × \(\frac{4\pi }{9}\)
= 2 × 4π
= 8π
≈ 25.1 cm² ( to the nearest tenth )
Use the box-and-whisker plot to find the given measure.
3. least value
4. first quartile
5. median
6. range
7. greatest value
8. third quartile
Please help asap!!
What is the equation of the line in slope intercept form?
Answer:
y = x + 60
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (20, 80) and (x₂, y₂ ) = (40, 100) ← 2 points on the line
m = \(\frac{100-80}{40-20}\) = \(\frac{20}{20}\) = 1
the line crosses the y- axis at (0, 60 ) ⇒ c = 60
y = x + 60 ← equation of line
Hi! This is a urgent question and I'm looking for someone to do it!
Please help!
:)
Step-by-step explanation:
JOIN MY MEETING
ID-9384026088
PASSWORD 1234
Answer:
35
Step-by-step explanation:
35 because according to the pic 25-49 shirts is 15 dollars and 20$ in shipping fee so 15+20=35. Hope this helps!