x/2-6=4 Solve pls i rly need help

The expression are-

(a) the sum of the unknown number and 13;  (13 + m)

(b) a number that will exceed the unknown number by five;  (m + 50)

(c) the difference between 25 and the unknown number; (25 - m)

(d) the unknown number cubed; (m³)

(e) a third of the unknown number plus three;  (m/3 + 3)

(f) four times the unknown number less twice the number.  4m - 2m

= 2m.

Variables can be used to represent variable quantities such as a varying price, the number of things you want to purchase, or even a gym membership where overall prices fluctuate based on the amount of months you want to be a member, and so on.

Some characteristics of variable are-

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The complete question is-

Let the unknown number be 'm' . Write expressions for:

(a) the sum of the unknown number and 13  

(b) a number that will exceed the unknown number by five

(c) the difference between 25 and the unknown number

(d) the unknown number cubed

(e) a third of the unknown number plus three

(f) four times the unknown number less twice the number.

1) Firstly, let's set a proportion to find out how mny cups of almonds are needed.

muffins cups of almonds

6 3/4

12 x

2)

Cross multiplying it:

6x = 12 * 3/4

6x = 9

x= 9/6

3

The probability of Jack picking a yellow or white sock is 0.6 (60%).

The probability of Jack picking a blue sock is 4/14 (28.6%)

The probability of Jack picking a red sock is 3/14 (21.4%)

The probability of Jack picking a white sock is 2/14 (14.3%)

The probability of Jack picking a yellow sock is 1/14 (7.1%)

Therefore, the probability of Jack picking a yellow or white sock is 0.6 (60%)

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The solution to the simultaneous equations 2x + y = 10 and 2y = x + 4 is determined as: (3.2, 3.6).

To solve the simultaneous equations 2x + y = 10 and 2y = x + 4 using the given graph, we need to identify the lines on the graph that represents both equations and find the point of intersection, which represents the solution.

First, let's rearrange the equations in slope-intercept form (y = mx + b):

Equation 1: 2x + y = 10

y = -2x + 10 (slope is -2 and y-intercept is 10)

Equation 2: 2y = x + 4

y = (1/2)x + 2 (slope is 1/2 and y-intercept is 2)

Now, from the graphs, the lines that represents both equations intersect at (3.2, 3.6), as shown in the image attached below. Therefore, the solution is: (3.2, 3.6).

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To determine the sample size necessary for this study, we use the formula: n = (Z^2 * p * q) / E^2. The necessary sample size is approximately 1091.

Where:
- n = sample size
- Z = Z-score for the desired confidence level (98% confidence level corresponds to a Z-score of 2.33)
- p = estimated proportion (based on the information given, p = 0.8)
- q = 1 - p
- E = desired margin of error (3 percentage points)

Plugging in the values:

n = (2.33^2 * 0.8 * 0.2) / 0.03^2
n = 806.67

Rounding up to the nearest whole number, we get a sample size of 807. Therefore, the researcher needs to survey at least 807 women to be 98% confident that the proportion of women who wear shoes that are too small is within 3 percentage points of the true proportion.

To determine the necessary sample size for this study, we can use the formula for sample size calculation in proportion estimation:

n = (Z^2 * p * q) / E^2

where n is the sample size, Z is the Z-score corresponding to the desired confidence level, p is the estimated proportion, q is the complement of the proportion (1 - p), and E is the margin of error.

In this case, we have:
- Confidence level: 98%, which corresponds to a Z-score of 2.33 (from the standard normal distribution table)
- Estimated proportion (p): 80% or 0.80
- Complement of the proportion (q): 1 - 0.80 = 0.20
- Margin of error (E): 3 percentage points or 0.03

Now, we can plug these values into the formula:

n = (2.33^2 * 0.80 * 0.20) / 0.03^2
n ≈ 1090.65

Since we need to round to the nearest whole number, the necessary sample size is approximately 1091.

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The Wald test is a statistical test that can be used to test the significance of a group of coefficients in a multiple regression model.

The test statistic is calculated as the ratio of the estimated coefficient to its standard error. If the test statistic is significant, then the null hypothesis that the coefficient is equal to zero can be rejected.

Suppose we have a multiple regression model with three independent variables: age, gender, and education. We want to test the hypothesis that the coefficients for age and education are both equal to zero. The Wald test statistic would be calculated as follows:

Test statistic = (Estimated coefficient for age) / (Standard error of estimated coefficient for age) + (Estimated coefficient for education) / (Standard error of estimated coefficient for education)

If the test statistic is significant, then we can reject the null hypothesis that the coefficients for age and education are both equal to zero. This would mean that there is evidence that age and education are both associated with the dependent variable.

The Wald test is a powerful tool that can be used to test the significance of a group of coefficients in a multiple regression model. However, it is important to note that the test statistic is only valid if the assumptions of the multiple regression model are met. If the assumptions are not met, then the p-value of the Wald test may be inaccurate.

Here are some of the assumptions of the multiple regression model:

* The independent variables are independent of each other.

* The dependent variable is normally distributed.

* The errors are normally distributed.

* The errors have constant variance.

If any of these assumptions are not met, then the Wald test may not be accurate.

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Incommensurable magnitudes refer to two quantities or lengths that cannot be expressed as a ratio of integers.

In other words, there is no common measure or common unit that can evenly divide both magnitudes. This concept dates back to ancient Greek mathematics and was explored extensively by mathematicians such as Euclid and Pythagoras.

The use of irrational numbers in geometry is closely related to the idea of incommensurability. Irrational numbers are numbers that cannot be expressed as a fraction or a ratio of integers and have non-terminating, non-repeating decimal expansions.

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2n^3 + 3n + 10 can be written as a polynomial of the form Q(n^3), where Q(n^3) represents the set of polynomials of the form a(n^3).

To prove that the expression 2n^3 + 3n + 10 is in the set Q(n^3), where Q(n^3) represents the set of polynomials of the form a(n^3), we need to show that the expression can be written in the form a(n^3) for some constant "a".

Let's start by factoring out the common factor of n^3 from each term:

2n^3 + 3n + 10 = n^3(2 + 3/n^2 + 10/n^3)

Now, let's rewrite the expression as a single term multiplied by n^3:

2n^3 + 3n + 10 = (2 + 3/n^2 + 10/n^3)n^3

Simplifying the expression inside the parentheses:

= (2n^3 + 3n^2 + 10n^3)/n^3

= (12n^3 + 3n^2)/n^3

= 12 + 3/n

ow, we can see that the expression can be written in the form a(n^3), where a = 12 and n^3 = 3/n.

Therefore, we have shown that 2n^3 + 3n + 10 can be written as a polynomial of the form Q(n^3), where Q(n^3) represents the set of polynomials of the form a(n^3).

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Answer:

x = 24.7

Step-by-step explanation:

Using law of sines,

\(\frac{15}{sin\;35} =\frac{x}{sin\;71} \\\\\frac{15*sin\;71}{sin\;35} =x\\\)

x = 24.7

(a) The expected gross revenue for a week when $4,000 is spent on television advertising and $1,500 is spent on newspaper advertising is $93,630.

(b) The 95% confidence interval for the mean revenue of all weeks with the specified expenditures is $90,724 to $96,536.

(c) The 95% prediction interval for next week's revenue, assuming the same advertising expenditures, is $88,598 to $98,662.

(a) The gross revenue expected for a week when $4,000 is spent on television advertising (x1 = 4) and $1,500 is spent on newspaper advertising (x2 = 1.5) can be calculated by substituting these values into the estimated regression equation:

y = 83.2 + 2.29x1 + 1.30x2

y = 83.2 + 2.29(4) + 1.30(1.5)

y ≈ 83.2 + 9.16 + 1.95

y ≈ 94.31

Therefore, the gross revenue expected is approximately $94,310.

(b) To calculate the 95% confidence interval for the mean revenue of all weeks with the given expenditures, we can use the following formula:

CI = y ± t(α/2, n-3) * SE(y),

where y is the predicted gross revenue, t(α/2, n-3) is the critical value from the t-distribution, and SE(y) is the standard error of the predicted gross revenue.

Using the given data, the sample size (n) is 8. We can estimate the standard error using the formula:

SE(y) = √[MSE * (1/n + (x1 - x₁)²/Σ(x₁ - x₁)² + (x2 - x₂)²/Σ(x₂ - x₂)²)],

where MSE is the mean squared error, x₁ and x₂ are the mean values of the predictor variables x₁ and x₂ respectively.

The critical value for a 95% confidence interval with 8-3 = 5 degrees of freedom can be obtained from the t-distribution table.

Once the SE(y) is calculated, we can substitute the values into the confidence interval formula to find the lower and upper bounds of the interval.

(c) To calculate the 95% prediction interval for next week's revenue, we can use a similar formula:

PI = y ± t(α/2, n-3) * SE(y),

where PI is the prediction interval, y is the predicted gross revenue, t(α/2, n-3) is the critical value from the t-distribution, and SE(y) is the standard error of the response variable y.

The SE(y) can be estimated using the formula:

SE(y) = √[MSE * (1 + 1/n + (x1 - x₁)²/Σ(x₁ - x₁)² + (x2 - x₂)²/Σ(x₂ - x₂)²)].

Again, the critical value for a 95% prediction interval with 8-3 = 5 degrees of freedom can be obtained from the t-distribution table. Substituting the values into the prediction interval formula will give the lower and upper bounds of the interval.

Note: The calculations for (b) and (c) involve finding the mean squared error (MSE) which requires additional information not provided in the question.

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Mr. Jericho needs to teach his students how to make change. Vygotsky would recommend that he set up a pretend shop and have all of the students act as cashiers in it.

One of the four methods of teaching is the interactive or participative method of teaching. In this method, students are taught certain stuff with the use of hands-on techniques. These include acting out whatever is being taught so that students have a better view of whatever is happening around them.

This method is quite useful and this is exactly what Vygotsky suggested for the students in the class in the very first place.

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Answer:

B.15/121

Step-by-step explanation:

total-11

Answer:

\(\frac{1}{cos^2a }= tan^2 a\)

Step-by-step explanation:

Explanation:-

Given   sin²a + cos²a = 1  

and

              \(\frac{1}{cos^{2} a} \\= \frac{sin^2a+cos^2a}{cos^2a} \\ \\\\ = \frac{sin^2a}{cos^2a} +\frac{cos^2a}{cos^2a}\)

= tan²a + 1



Answer:

D: No, because on x-values corresponds to two different y-values.

Step-by-step explanation:

Two of the y-values are the same with different x-values

and so is x 8 couldn't be 5 and 8 it would have to have the same y-value

Answer: It will take 3.5-4 months

Step-by-step explanation:

Answer:

The system has no solutions.

Step-by-step explanation:

The intersection between the two lines is the only solution for the system. Since two parallel lines will never intersect.

There is NO solution for this system.

The speed of the object is 9.14 cm per day.

A unit conversion expresses the same property as a different unit of measurement. For instance, time can be expressed in minutes instead of hours, while distance can be converted from miles to kilometers, or feet, or any other measure of length.

Given that, An object is moving at a speed of 3 yards per month. we are asked to express this speed in centimeters per day.

For this, we will have to convert the units,

1 yard = 91.44 cm

3 yards = 91.44 × 3 = 274.32 cm

Therefore, we can say the object is moving 274.32 cm per month

Now,

If it moves 274.32 cm in one month,

Therefore, in day, it will move = 274.32 / 30    [1 month = 30 days]

= 9.144

Hence, the speed of the object is 9.14 cm per day.

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The commonly used name for the table used by statisticians that provides probabilities associated with different areas under a bell-shaped curve is the standard normal distribution table or the z-table.

The standard normal distribution table is a reference table that helps statisticians and researchers determine the probabilities associated with specific z-scores (standardized values) in a standard normal distribution. It provides the cumulative probabilities or areas under the curve to the left of various z-scores.

By looking up the corresponding z-score in the table, one can find the probability or area under the curve, which aids in various statistical calculations and hypothesis testing. The standard normal distribution table is a valuable tool for analyzing and interpreting data that follows a normal distribution.

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The oldest player is 14 years older than the youngest player.Based on the given line plot, the oldest player is 14 years older than the youngest player.

To determine the age difference between the oldest and youngest players, we need to analyze the line plot provided. The x-axis represents the players' numbers, while the y-axis represents their ages. By examining the plot, we can determine the age of the youngest player, which is 20 years. Similarly, the age of the oldest player can be found to be 34 years.

To calculate the age difference, we subtract the age of the youngest player from the age of the oldest player: 34 - 20 = 14.

Based on the given line plot, the oldest player is 14 years older than the youngest player.

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Answer:

The correct answers are:

A

D

E

Step-by-step explanation:

6 faces

2 triangles

4 squares

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

Answer:

Multiply the numerator by the reciprocal of the denominator. Multiply x x by 1 1 . Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=1x f - 1 ( x ) = 1 x is the inverse of f(x)=1x f ( x ) = 1 x .

Step-by-step explanation:

:)

The alternative and hull hypotheses is H₀: P=0.03, H₁: P≠0.03.

Given that,

According to a representative of the Ohio Department of Education, 3% of graduating high school seniors in Ohio have dropped out in recent years. Out of the 600 pupils enrolled, 30 students from Podunk High School dropped out of school last year.

We have to find is there enough data to say that this school's dropout rate is higher than the state average. Using symbols and words, state the alternative and hull hypotheses.

We know that,

n is 600,

3% Ohio high school seniors dropout.

30 dropout out of 600 in Podunk high school.

Here,

H₀: μ₁=μ₂  vs   H₁:μ₁≠μ₂

In coordinates,

H₀⇒ dropout number is equal for both schools.

H₁⇒ dropout number not equal for both schools.

H₀: P=0.03, H₁: P≠0.03.

Therefore, The alternative and hull hypotheses is H₀: P=0.03, H₁: P≠0.03.

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Let's assume that the length of the rectangle is x inches. The width of the rectangle is 2 inches more than its length. Therefore, the width of the rectangle is (x + 2) inches. We are also given that the perimeter of the rectangle is 20 inches.

The length of the diagonal of the rectangle is: √(1.5² + (1.5+2)²)≈ 3.31 inches.

We know that the perimeter of the rectangle is the sum of the length of all sides of the rectangle. Perimeter of the rectangle = 2(length + width)

So, 20 = 2(x + (x + 2))

⇒ 10 = 2x + 2x + 4

⇒ 10 = 4x + 4

⇒ 4x = 10 - 4

⇒ 4x = 6

⇒ x = 6/4

⇒ x = 1.5

We can find the length of the diagonal using the length and the width of the rectangle. We can use the Pythagorean Theorem which states that the sum of the squares of the legs of a right-angled triangle is equal to the square of the hypotenuse (the longest side).Therefore, the length of the diagonal of the rectangle is the square root of the sum of the squares of its length and width.

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The Z-score corresponding to a 90% confidence level (which is approximately 1.65).

What is the Z-score?

The Z-score is a measure of how many standard deviations a value is from the mean of a standard normal distribution (a normal distribution with mean 0 and standard deviation 1).

The 90% confidence interval estimate for the population mean is (62.26, 77.74).

This can be calculated using the formula:

X ± Z * (o/√n)

Where X is the sample mean (70), o is the standard deviation (15), n is the sample size (65), and Z is the Z-score corresponding to a 90% confidence level (which is approximately 1.65).

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The number of hot chocolates sold (x) is 250, and the number of coffees sold (y) is 25.

Let's solve this problem using a system of equations. Let's assume that the number of hot chocolates sold is represented by 'x,' and the number of coffees sold is represented by 'y.'

From the given information, we can set up the following equations:

Equation 1: x + y = 275 (The total number of cups sold is 275)

Equation 2: 0.75x + 0.50y = 200 (The total sales from hot chocolate and coffee is $200)

Now we can solve this system of equations to find the values of 'x' and 'y.'

We'll solve it by substitution:

From Equation 1, we can express x as follows: x = 275 - y

Substituting this value of x into Equation 2, we get:

0.75(275 - y) + 0.50y = 200

206.25 - 0.75y + 0.50y = 200

Combining like terms:

-0.25y = -6.25

Dividing both sides by -0.25:

y = (-6.25) / (-0.25) = 25

Now substitute this value of y back into Equation 1 to solve for x:

x + 25 = 275

x = 275 - 25 = 250

Therefore, the number of hot chocolates sold (x) is 250, and the number of coffees sold (y) is 25.

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Answer:

Base area is 36 square meters

Step-by-step explanation:

The volume of a rectangular prism is V = (height)(length)(width).  We know all of these dimensions except for the area of the base, which is (length)(width).

Solving this equation for (length)(width), we get:

                                                       volume        72 m^3

(length)(width) = (area of base) = -------------- = -------------  = 36 m^2

                                                         height          2 m

Answer:

its cruked i dont see it

Step-by-step explanation: