X/-22=3 what is X Help

Answer:

Step-

In mathematics, a linear equation is an equation that may be put in the form a₁x₁+⋯+aₙxₙ+b=0, where x₁,…,xₙ are the variables (or unknowns), and b,a₁,…,aₙ are the coefficients, which are often real numbers. The coefficients may be considered as parameters of the equation, and may be arbitrary expressions, provided they do not contain any of the variables. To yield a meaningful equation, the coefficients a₁,…,aₙ are required to not all be zeroby-step explanation:

Check the equation for varying terms and constant terms. Usually, equations won't come with varying terms and constant terms lined up on separate sides.

In order to do this, you may have to subtract or add the numbers you want to move from both sides. ...

Move the varying terms to one side of the equation

Answer:

1 10/7

Step-by-step explanation:

Answer:

10/17

Step-by-step explanation:

Answer:

I think B because I think it right sorry if wrong

Step-by-step explanation:

sorry if wrong

Answer:

(23•32t5x)

Step-by-step explanation:

STEP1:

Equation at the end of step1:

(((2t)3) • x) • 32t2

STEP2:

Equation at the end of step2:

(23t3 • x) • 32t2

STEP3:

Multiplying exponential expressions :

 3.1    t3 multiplied by t2 = t(3 + 2) = t5

Final result :

(23•32t5x)

Answer:

add me as a friend and give me thanks

Step-by-step explanation:

the answer is A for sure

Answer:

49 pieces

Step-by-step explanation:

1. convert 12.25m into cm (1225 cm)

2. divide 1225cm by 25 = 49

Answer:

We can start by using the second equation to eliminate x:

2x + 5y - 2z = 3

2x = -5y + 2z + 3

x = (-5/2)y + z + 3/2

Now we can substitute this expression for x into the first and third equations:

x + y + z = 4

(-5/2)y + z + 3/2 + y + z = 4

(-5/2)y + 2z = 5/2

x + 7y - 7z = 5

(-5/2)y + z + 3/2 + 7y - 7z = 5

(9/2)y - 6z = 7/2

Now we have a system of two equations with two variables, (-5/2)y + 2z = 5/2 and (9/2)y - 6z = 7/2. We can use any method to solve for y and z, such as substitution or elimination. However, we will find that the system is inconsistent, meaning there is no solution that satisfies both equations.

Multiplying the first equation by 9 and the second equation by 5 and adding them, we get:

(-45/2)y + 18z = 45/2

(45/2)y - 30z = 35/2

Adding these two equations, we get:

-12z = 40/2

-12z = 20

z = -5/3

Substituting z = -5/3 into (-5/2)y + 2z = 5/2, we get:

(-5/2)y + 2(-5/3) = 5/2

(-5/2)y - 10/3 = 5/2

(-5/2)y = 25/6

y = -5/12

Substituting y = -5/12 and z = -5/3 into any of the original equations, we get:

x + y + z = 4

x - 5/12 - 5/3 = 4

x = 29/12

Therefore, the solution is (x, y, z) = (29/12, -5/12, -5/3). However, if we substitute these values into any of the original equations, we will find that it does not satisfy the equation. For example:

2x + 5y - 2z = 3

2(29/12) + 5(-5/12) - 2(-5/3) = 3

29/6 - 5/2 + 5/3 ≠ 3

Since there is no solution that satisfies all three equations, the system is inconsistent.

Step-by-step explanation:

Answer:

See below for proof.

Step-by-step explanation:

A system of equations is not consistent when there is no solution or no set of values that satisfies all the equations simultaneously. In other words, the equations are contradictory or incompatible with each other.

Given system of equations:

\(\begin{cases}x+y+z = 4\\2x+5y-2z =3\\x+7y-7z =5\end{cases}\)

Rearrange the first equation to isolate x:

\(x=4-y-z\)

Substitute this into the second equation to eliminate the term in x:

\(\begin{aligned}2x+5y-2z&=3\\2(4-y-z)+5y-2z&=3\\8-2y-2z+5y-2z&=3\\-2y-2z+5y-2z&=-5\\5y-2y-2z-2z&=-5\\3y-4z&=-5\end{aligned}\)

Subtract the first equation from the third equation to eliminate x:

\(\begin{array}{cccrcrcl}&x&+&7y&-&7z&=&5\\\vphantom{\dfrac12}-&(x&+&y&+&z&=&4)\\\cline{2-8}\vphantom{\dfrac12}&&&6y&-&8z&=&1\end{aligned}\)

Now we have two equations in terms of the variables y and z:

\(\begin{cases}3y-4z=-5\\6y-8z=1\end{cases}\)

Multiply the first equation by 2 so that the coefficients of the variables of both equations are the same:

\(\begin{cases}6y-8z=-10\\6y-8z=1\end{cases}\)

Comparing the two equations, we can see that the coefficients of the y and z variables are the same, but the numbers they equate to is different. This means that there is no way to add or subtract the equations to eliminate one of the variables.

For example, if we subtract the second equation from the first equation we get:

\(\begin{array}{crcrcl}&6y&-&8z&=&-10\\\vphantom{\dfrac12}-&(6y&-&8z&=&\:\:\;\;\:1)\\\cline{2-6}\vphantom{\dfrac12}&&&0&=&-11\end{aligned}\)

Zero does not equal negative 11.

Since we cannot eliminate the variable y or z, we cannot find a unique solution that satisfies all three equations simultaneously. Therefore, the system of equations is inconsistent.

The solution to the value of m in the inequality m + 1/5 < - 1 2/3 is "m is less than negative 1 and 13 over 15".

The correct answer option is option D

Inequality is a statement that is of two quantities I'm which one is specifically less than (or greater than) another. The symbols of inequality are;

m + 1/5 < - 1 2/3

substract 1/5 from both sides

m < -5/3 - 1/5

m < (-25-3) / 15

m < -28/15

Therefore, from the inequality m + 1/5 < - 1 2/3, m is less than negative 1 and 13 over 15.

Complete question:

m + 1/5 < -1 2/3

Responses

A. m > −1 13/15

m is greater than negative 1 and 13 over 15

B. m > −1 7/15

m is greater than negative 1 and 7 over 15

C. m < −1 7/15

m is less than negative 1 and 7 over 15

D. m < −1 13/15

m is less than negative 1 and 7 over 15

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Answer:

Explanation:

Given:

Equation 1:

When the first equation is shifted 2 units to the left and 7 units upward, the graph is:

Therefore, the equation for shifting 2 units to the left and 7 units upward is:

Answer:

Sorry

Step-by-step explanation:

I don't know the answer

Answer:

Step-by-step explanation:

$100x0.5x1=$5

The exponential function can be rewritten as:

f(x) = 48*e^(0.0198*x)

Here we start with the exponential function:

f(x) = 48*(1.02)^x

And we want to write this in the general form:

f(x) =a*e^(kx)

Notice that we can write the second form as:

f(x) = a*[e^k]^x

So, comparing this with the given exponential, we will get:

a = 48

e^k = 1.02

Apply the natural logarithm in both sides:

ln(e^k) = ln(1.02)

k*ln(e) = ln(1.02)

k = ln(1.02) = 0.0198

Then the exponential function is:

f(x) = 48*e^(0.0198*x)

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Answer:

The answer to your problem is, D. The range is the best measure of variability, and it equals 32.

Step-by-step explanation:

We know the scores earned in a flower-growing competition are represented in the stem-and-leaf plot.

The key will equal 2|1 means 21

Which we conclude to 17, 19, 21, 25, 29, 30, 31, 32, 46, 49.

Quartile:

Median, Minimum, Maximum, & Range:

Thus the answer to your problem is, D. The range is the best measure of variability, and it equals 32.

Answer:

Slope of line g = \(1\frac{1}{3}\)

Step-by-step explanation:

* Mathematics rule: If two lines are perpendicular to each other, then the product of their slopes is equal to -1 .

∴ \(-\frac{3}{4}\) × slope of line g = -1

Slope of line g = -1 ÷ \(-\frac{3}{4}\) = 4/3 = \(1\frac{1}{3}\)

Answer:

-11

3

5

-24

Step-by-step explanation:

Answer:

1.-11

2.3

3.5

4.-24

Step-by-step explanation:

Hope this helps! :)

The expressions that are equivalent to 3^8 are:

We have to solve these out

3^8. = 6561

From the options

A. 3^2x3^4

= 9 x 81

= 729

B  3²x3^6

= 9 x 729

= 6561

C.  3^16/3^2

= 43046721/9

= 4782969

d. 3^12/3^4

= 531441 / 81

= 6561

E.  (3^4)²

= 3⁴ x 3⁴

= 3⁴⁺⁴

= 3⁸

= 6561

F. (3¹)^7

= 3⁷

= 2187

The expressions that are equivalent to 3^8 are:

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Answer:

5/4 feet ^2

Step-by-step explanation:

1/2 x 2 1/2 = 1.25 or 5/4

Answer:

9 times 4

Step-by-step explanation:

Answer:

9 x 4.

Step-by-step explanation:

i got it right

The domain is [0,100].[0,100]. The range is [0,1500] [0,1500]

(a) To find the cost of making 25 items substitute

x=25 in the equation

=10+500(25)

=10(25)+500(25)=750

c(x)=10x+500

c(25)=10(25)+500

c(25)=750

the cost of making 25 items is

$750

(b)

Since the maximum cost allowed is

$1500  

10+500≤1500

10x+500≤1500

To solve this inequality

First, subtract 500 from both sides

10≤1000

10x≤1000

Divide both sides by 10

≤100x≤100

This means you can make at most 100 items.

The domain is

[0,100].[0,100].

The range is

[0,1500] [0,1500].

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Answer:

9

Step-by-step explanation:

Answer:

36 inches or 2160 i said 36 cause i did the whole problem

Step-by-step explanation:

Answer:

w<13

Step-by-step explanation:

Works identically to a normal single-variable equation.
Subtract 7 on both sides in order to isolate w--->w+7-7<20-7
The answer (which cannot be simplified any further) is w<13.

Answer:

w < 1`3

Step-by-step explanation:

Isolate the variable w on one side of the inequality sign.

w+7<20

w<20 - 7

w<13.

Answer:

  use "Help"

Step-by-step explanation:

You need to learn how your software expects to see "infinity." It may need to be spelled out "infinity" or abbreviated "inf" or "infty".

For starters, I suggest you use the "Help" link on the page you show. If that doesn't answer the question, then consult with your instructor.

Answer:

\(x_1 = 8+2\sqrt{5}=2(4+\sqrt{5} )\)

\(x_2 = 8-2\sqrt{5}=2(4-\sqrt{5} )\)

Step-by-step explanation:

\(x^2 - 16x + 64 = 20\)

I will solve it completing the square

\(x^2 - 16x + 64 = 20\)

\((x-8)^2 = 20\)

\(x-8= \pm\sqrt{20}\)

\(x=8 \pm\sqrt{20}\)

\(x=8 \pm2\sqrt{5}\)

\(x_1 = 8+2\sqrt{5}=2(4+\sqrt{5} )\)

\(x_2 = 8-2\sqrt{5}=2(4-\sqrt{5} )\)

Answer:  The answer is:  " x  =  8  ±  2√5  " .

____________________________

Step-by-step explanation:

____________________________

Given:

  x² - 16x + 64 = 20 ;  Solve for "x" ;

____________________________

Subtract "20" from each side of the equation:

  x² - 16x + 64 - 20 = 20 -20 ;

to get:

  x² - 16x + 44 = 0  ;

(i.e. to get an equation in "quadratic equation format" ;

that is; in the format of:    ax² + bx + c = 0 ;  (a ≠ 0) ;

____________________________

We cannot factor the "left-hand side" of the equation;

so, we can solve for "x" by using the quadratic equation formula;

Note that our equation:  " x² - 16x + 44 = 0 " ;

              is in "quadratic equation format" ;

    that is:  " ax² + bx + c = 0 " ;  (a ≠ 0) ;

                in which:

                   a  =  1 ;

(Note:  The implied coefficient of:  " ax² "  is:   "1" ;

     →  since "1" ; multiplied by any value, results in that exact value.

 This is known as the "identity property" of multiplication.}.

                   b  =  -16 ;

                   c  =  44  .

____________________________

To solve for "x" ; we use the quadratic equation formula:

____________________________

         →   x  =  [ - b  ± √(b² - 4ac) ]  /  [2a] ;

We solve for "x" by plugging in our values for "a" ; "b" ; and "c" ;

____________________________

         →   x  =  { - [-16) ± {√[(-16)² - 4(1)(44) ] }   /  [2 * 1]  ;

____________________________

        →    x  =  [ 16  ±  √ (16² - 4*44) ]  / [2] ;

____________________________

        →    x  =  [ 16  ±  √ (16² - 4*44) ]  / [2] ;

____________________________

        →    x  =  [ 16  ±  √ (256 - 176 )]  / [2] ;

____________________________

        →    x  =  [ 16  ±  √ (80 )]  / [2] ;

Now, let us rewrite:  " √80 " ;

____________________________

  " √80 " =  √16 * √5  =  4*√5 ;

                                     →  write as:  " 4√5 " .

____________________________

Now, take:

____________________________

        →    x  =  [ 16  ±  √ (80 )]  / [2] ;

____________________________

And replace:  " √80 " ;   with:   " 4√5 " ;  and rewrite:

____________________________

        →    x  =  [ 16  ±  4√5 )  / 2 ;

____________________________

Now, divide the numerator by "2" to simplify, and rewrite:

       →  Note:  16 ÷ 2 = 8 ; and:  4 ÷ 2 = 2 ;

So, we have:

____________________________

        →    x  =  8  ±  2√5

____________________________

Answer:

Sin(2x)+sin(x)+cos(2x)-1

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

1 , 3 and 4 have at least two pairs of parallel lines,

2 only have one pair of parallel line

(that's the only thing I can think of)

Answer:

x=2at/(1+t²)

dx/dt =[(1+t²)(2at)'-(2at)(1+t²)']/(1+t²)²

dx/dt=[(1+t²)(2a)-(2at)(2t)]/(1+t²)²

dx/dt=[2a+2at²-4at²]/(1+t²)²

dx/dt=[2a-2at²]/(1+t²)²

y=[b(1-t²)]/(1+t²)

dy/dt=[(1+t²)(b(1-t²))'-b(1-t²)(1+t²)']/(1+t²)²

dy/dt=[((1+t²)(-2bt)-b(1-t²)(2t)]/(1+t²)²

dy/dt=(-2bt-2bt³-2bt+2bt³)/(1+t²)²

dy/dt=(-4bt)/(1+t²)²

dy/dx=(dy/dt)/(dx/dt)

dy/dx=[(-4bt)/(1+t²)²]/[(2a-2at²)/(1+t²)²]

Cancelling common denominator

dy/dx=(-4bt)/(2a-2at²)

dy/dx=(-2bt)/(a-at²)

dy/dx=(2bt)/(at²-a)

Differentiating the above equation

y''=d²y/dx²=D[(2bt)/(at²-a)]

y''=[(at²-a)D(2bt)-(2bt)D(at²-a)]/(at²-a)²

y''=[(at²-a)(2b)(dt/dx)-(2bt)(2at)(dt/dx)]/(at²-a)²

dt/dx=(1+t²)²/(2a-2at²)

y''=[(at²-a)(2b)[(1+t²)²/(2a(1-t²))]-

(4abt²)[(1+t²)²/(2a-2at²)]/(at²-a)²

y''=[(-b)(1+t²)²-(2bt²)[(1+t²)²/(1-t²)]/(at²-a)²

y''=[(-b)(1+t²)²(1-t²)-(2bt²)(1+t²)²]/[(1-t²)(at²-a)²]

y''=[b(1+t²)²(t²-1)-2bt²(1+t²)²]/[(1-t²)(at²-a)²]

Step-by-step explanation: