Non-Malleable and Ductile: Non-metals are very brittle, and cannot be rolled into wires or pounded into sheets. Conduction: They are poor conductors of heat and electricity. Luster: These have no metallic luster and do not reflect light.
Group 15, the nitrogen family, contains two nonmetals: nitrogen and phosphorus. These non-metals usually gain or share three electrons when reacting with atoms of other elements. Group 16, the oxygen family, contains three nonmetals: oxygen, sulfur, and selenium.
Elements: Nitrogen; Oxygen; Phosphorus; Selenium...
What is the y component of a vector defined as 12.2m at 245^o
Given:
v = 12.2 m
Angle = 245 degrees
Let's find the y-component of the vector.
Let's first sketch a free body diagram representing the vector.
We have:
To find the y-component of the vector, apply the formula:
\(d_y=dcos\theta\)Where:
θ = 25 degrees
d = -12.2 m
Thus, we have:
\(\begin{gathered} d_y=-12.2cos25 \\ \\ d_y=-11.1\text{ m} \end{gathered}\)Therefore, the y-component of the vector is -11.1 m.
Which interaction has the highest electrostatic potential energy?
O A +2 and -2 particle separated by a distance of 5 nm.
O A +1 and -2 particle separated by a distance of 5 nm.
O A +2 and +2 particle separated by a distance of 10 nm.
O A +2 and -2 particle separated by a distance of 10 nm.
O A +2 and +2 particle separated by a distance of 100 nm.
O A +1 and -2 particle separated by a distance of 10 nm.
O A +2 and +2 particle separated by a distance of 5 nm.
Answer:
The interaction with the highest electrostatic potential energy is:
A +1 and -2 particle separated by a distance of 5 nm.
Explanation:
The electrostatic potential energy between two charged particles depends on the magnitude of their charges and the distance between them. The formula for calculating electrostatic potential energy is:
U = k * (q1 * q2) / d
where U is the electrostatic potential energy, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and d is the distance between them.
In the given options, the interaction between +1 and -2 particles separated by a distance of 5 nm has the highest electrostatic potential energy because the charges have a higher magnitude (compared to other options) and they are close to each other, resulting in a stronger electrostatic force of attraction. The other options either have smaller charges, larger distances, or both, leading to lower electrostatic potential energy.
The diagram shows two forces acting on the dog. What are these two forces
Answer:
kenietic and potential i guess
Explanation:
After using an air mattress, Lucy opens the valve to deflate it and air begins rushing out of the mattress. When will the air most likely stop rushing out of the mattress?
Answer:
When the air pressure in the mattress is EQUAL to atmospheric pressure.
Explanation:
I looked it up, and it is kind of obvious so I don't know why no one has answered this yet
a six sided number cube numbered 1 through 6 is rolled 300 times. the number 3 comes up 66 times. What is the experiment probability of rolling a 3.
The probability is obtained by calculating the quotient in between the number of time you get a 3 over the total number of rollings.
Then, based on the information of the question, you have:
p = 66/300 = 0.22
the probability of getting a 3 is 0.22, which is the same that the probability is 22%.
Sam is driving along the highway towards Savannah. He travels 150 m in 3 seconds. What is his speed
Answer:
50m/s
Explanation:
Speed = distance/ time
Distance = 150m
Time = 3 secs
Therefore Speed =150/3
Speed = 50 m/s
Object A has a mass of 8.0 kg and is accelerating at 4.0 m/s2. Object B has a mass of 10.0 kg and is accelerating at 3.0 m/s2. Object C has a mass of 7.0 kg and is accelerating at 5.0 m/s2. Place the objects in increasing order according to the net force they are experiencing.
a. A, B, C
b. B, A, C
c. C, B, A
d. C, A, B
Answer:
b. B, A, C
Explanation:
To solve this problem, let us find the net forces they are experiencing.
Net force = mass x acceleration
Object A; mass = 8kg and acceleration = 4m/s²
Net force = 8 x 4 = 32N
Object B; mass = 10kg and acceleration = 3m/s²
Net force = 10 x 3 = 30N
Object C: mass = 7kg and acceleration = 5m/s²
Net force = 7 x 5 = 35N
So, increasing order of their net force;
B < A < C
А bus has started to move from
the rest with an acceleration of
0.25 m/s². find its final velocity
What force acts on a projectile in the horizontal direction?
The force that acts on a projectile in the horizontal direction is Gravitational force.
A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.
Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.
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1. Wind
A. Definition
B. What Heat Transfer Causes
c. Types
Answer:
B . a heat transfer caused
Are these bones axial, appendicular
or both?
Answer:
Axial and Appendicular Skeletons The axial skeleton forms the central axis of the body and consists of the skull, vertebral column, and thoracic cage. The appendicular skeleton consists of the pectoral and pelvic girdles, the limb bones, and the bones of the hands and feet. Figure 6.41.
Explanation:
Identify the correct statement regarding the strength of chemical bonds. Strong bonds form with large atoms and weak bonds with small atoms. Weak bonds require less energy to form than strong bonds. Strong bonds occur with high temperature and weak bonds with low temperature. Weak bonds require more energy to form than strong bonds.
Option B is the right answer. The correct statement regarding the strength of chemical bonds is that weak bonds require less energy to form than strong bonds.
Bonds form when two atoms share, give, or take electrons.
The electrons in the valence shell or outermost energy level of an atom are used to create bonds.
When atoms interact and share electrons, they lower their potential energy.
The more tightly an atom's electrons are bound, the greater the energy required to break those bonds.
There are two types of bonds: strong and weak.
Strong bonds have a lower potential energy than weak bonds, and they require more energy to break.
As a result, strong bonds tend to be more difficult to break than weak bonds.
The type of bond between two atoms is determined by the difference in their electronegativities.
The strength of a bond is determined by the energy required to break it.
Bonds are considered strong when they have a higher bond energy than weak bonds, which have a lower bond energy.
This implies that more energy is required to break a strong bond than to break a weak bond.
Therefore, weak bonds require less energy to form than strong bonds.
To conclude, the correct statement regarding the strength of chemical bonds is that weak bonds require less energy to form than strong bonds.
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If the change in entropy dS = dQ / T and that S=f(Q,T) prove that entropy is a state function .
Answer:
It is because the entropy of a system depends only on its state, just like its internal energy. Or, putting it the other way round, a given state of a system has a particular entropy.
The formula dS = dQ/T only applies to a reversible change, and such a change has only one path, or a few equivalent paths.
I chose A. is it right?
If a particular cell is known to be round and incapable of producing its own food, which one of these organelles would you assume the cell must have?(1 point)
CENTRAL VACUOL
plasma membrane
cell wall
chloroplast
Answer:
nice try but it's plasma membrane
The cell that is known to produce their own food should have a central vacuole. The correct option is A.
What is a vacuole?A vacuole is a cell organelle that is membrane-bound. Vacuoles are generally small in animal cells and help to sequester waste products.
Vacuoles in plant cells help to retain water balance. A solo vacuole can sometimes take up the maximum of the interior space of a plant cell.
Plant cells have much larger vacuoles than animal cells. When a plant cell stops growing, it usually has one very large vacuole.
That vacuole can sometimes take up more than half of the cell's volume. The vacuole can hold a lot of water or food.
The given cell is known to be round and incapable of producing its own food, so it must be having a central vacuole.
The correct option is A.
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3. Which is a general chemical equation for an endothermic, double-replacement reaction?
✓
O AB+ CD + energy-> AD+ CB
O AB+ CD AD + CB + energy
O AB+ C + energy - A+ CB
O AB+C- A+ CB + energy
The correct answer is A. AB+ CD + energy-> AD+ CB
Explanation:
In chemistry, a reaction is endothermic if the reaction involves absorption of heat or energy and this is necessary for the reaction to start. In terms of the chemical equation, this implies energy is part of the reactants or initial substances. Besides this, if the reaction is a double-replacement reaction this means two ions of the original substances are swapped or replaced, which means new substances in the products.
According to this, option A is the correct chemical equation because energy is part of the reactants, which shows the reaction is endothermic and the reactants AB + CD lead to the products AD + CB which shows two ions of the compounds were replaced (double replacement).
Answer:
The proper Answer is A) AB+CD + Energy --> AD + CB
Explanation:
what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees
Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:
You have the initial velocity (v): 35 m/s
You have the launch angle (θ): 45 degrees
We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.
To calculate vx (horizontal component):
vx = v * cosθ
vx = 35 * cos(45) = 24.7 m/s
To calculate vy (vertical component):
vy = v * sinθ
vy = 35 * sin(45) = 24.7 m/s
We can calculate the horizontal distance (d) traveled using:
d = vx * t (where t is time)
Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:
t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)
t = 24.7 / 9.8 = 2.52 seconds
Now we can calculate the full horizontal distance traveled:
d = vx * t
d = 24.7 * 2.52
= 62.3 meters
So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.
Let me know if you have any other questions!
Answer:
To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.
The horizontal component of the motion remains constant throughout the trajectory and is given by:
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.
The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:
Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)
Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.
The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.
Using these calculations, we can find the horizontal distance traveled by the object.
Let's calculate step by step:
Step 1: Calculate the time of flight
Vertical displacement = 0 (at the highest point)
0 = (35 * sin(45))^2 / (2 * 9.8)
0 = (24.75^2) / 19.6
0 = 616.0125 / 19.6
0 = 31.43
Step 2: Calculate the time of flight
Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2
0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2
0 = 24.75 * time - 4.9 * time^2
4.9 * time^2 - 24.75 * time = 0
time * (4.9 * time - 24.75) = 0
time = 0 (initial point) or 24.75 / 4.9
time = 5.05 seconds
Step 3: Calculate the horizontal distance
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
Horizontal distance = 35 * 5.05 * cos(45)
Horizontal distance = 35 * 5.05 * (sqrt(2)/2)
Horizontal distance = 88.96 meters
Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.What is a force that acts upon a projectile launched into the air?
1. Centripetal
2. Gravity
3. Trajectory
The force that acts upon a projectile launched into the air is gravity.
What is gravity?Gravity is a fundamental force of nature that causes all physical objects to attract each other. It is the force that pulls objects towards each other, and it is the reason why objects with mass are attracted towards the center of the Earth.
When an object is launched into the air, it is subject to the force of gravity, which pulls the object down towards the Earth. As the object moves through the air, the force of gravity causes it to follow a curved path, known as a trajectory, until it eventually hits the ground. While other forces such as air resistance may also act upon the projectile, gravity is the primary force that determines the path of the projectile.
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a 5kg-jumps on a table with a mass 30kg.as the dog walk around on top of the table what is the average force that the table applies to the dog?
Answer:
Problem:
a 5 kg dog jumps on table with a mass of 30 kg what is the average force that the table applies to the dog.
Note:
What ever is the force applied by the dog to the table, it will be the same force exerted by the table to the dog but in opposite direction. Study on the Newton's Third law of motion
Given Data:
m ( mass ) = 5 kg
a ( acceleration ) = 9.8 m/s²
F ( Force ) = ? unknown
Solution:
We will use the formula of Force ( F = m × a ) in order to solve the problem.
F = m × a
= 5 kg × 9.8 m/s²
= 49 kg·m/s²
= 49 N
Answer:
The table will exert 49 N of Force to the dog
In the setup of a cart pulled by a hanging mass, without friction, we have the following information: the mass of the cart is 0.53 Kg., and the hanging mass is 0.077 Kg.
Determine the acceleration of the cart (in m/s2).
The acceleration of the cart
a=1.2431m/s^2
What is acceleration?Generally, The equation for Newton's second law of motion is
2nd law of motion,
Fnet=m a
on hanging mass,
m_1 g-T=m_1 a
m_1 g-m_2 a=m_1 a
Acceleration, \($a=\frac{m_1 g}{m_1+m_2}$\)
\(&a=\frac{0.077 \mathrm{~kg} \times 9.8 \mathrm{~m} / \mathrm{s}^2}{0.077 \mathrm{~kg}+0.53 \mathrm{~kg}} \\\)
a=1.2431m/s^2
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After meeting the end the wave willa- reflect with larger amplitude.b- disappear.c- reflect with the same displacement. (not inverted)d- reflect with opposite displacement. (inverted)
Answer:
c- reflect with the same displacement. (not inverted)
Explanation:
When a wave goes to an end that is free to move, the reflected wave will be equal to the initial wave but will go to the opposite direction. Since the end of the wave is free to move, the answer is
c- reflect with the same displacement. (not inverted)
A ball rows off a table with a horizontal velocity of four (ms/s). If it is 0.5 seconds for the ball to reach the floor, how high above the floor is the table top? Using g=10(m/s2)
Since the velocity roll off the table with a horizontal velocity this means that the vertical initial velocity is zero. Now, while the ball is falling, the vertical motion is a free fall motion, which means that we can use the following equation:
\(y=y_0+v_0t-\frac{1}{2}gt^2\)In this case we know that:
• The final height, y, is zero (the ground).
,• The initial velocity is zero.
,• The time it takes to hit the ground is 0.5 s.
,• The acceleration of gravity is 10.
Plugging these and solving for the initial height, y0, we have:
\(\begin{gathered} 0=y_0+(0)(0.5)-\frac{1}{2}(10)(0.5^2) \\ y_0=(5)(0.25) \\ y_0=1.25 \end{gathered}\)Therefore, the initial height is 1.25 m
During which sequence of phases does the moon's visibility increase
During the "waxing" phases, the two weeks immediately following the New Moon.
New Moon ==> waxing crescent ==> First Quarter ==> waxing gibbous ==> Full Moon
The phase of the moon decides the moon's visibility. The sequence of phases does the moon's visibility increases is; the waxing crescent, first quarter, waxing gibbous, full Moon.
What is the moon phase?The moon changes shape every day. This is due to the fact that the celestial body has no light of its own and can only reflect sunlight.
Only the side of the moon facing the sun can reflect this light and seem bright. The opposite side appears black. this is a full moon.
We can only see the black section when it lies between the sun and the earth when a new moon occurs. We witness intermediate phases like a half-moon and crescent in between these two extremes.
Following are the sequence of phases does the moon's visibility increase is;
1. Waxing crescent
2. First Quarter
3. Waxing gibbous
4. Full Moon
The phase of the moon decides the moon's visibility. Hence the visibility changes with the change in the phase of the moon.
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determine the value of the resultant and its location from O.
see attach image.
Answer:
Explanation:
In the x direction the force will be
½(-w₀)L/2 = -¼w₀L
acting ⅔(L/2) = L/3 below the x axis.
In the y direction the force will be
½(-w₀)L + ½w₀L/2 = -¼w₀L
the magnitude of the resultant will be
F = w₀L √((-¼)² + (-¼)²) = w₀L√⅛
in the direction
θ = arctan(-¼w₀L / -¼w₀L) = 225°
to find the distance, we balance moments
(w₀L√⅛)[d] = ½(w₀)L[⅔L] + ¼w₀L[⅔L/2] - ¼w₀L[L - ⅓L/2]
(√⅛)[d] = ½ [⅔L] + ¼ [⅔L/2] - ¼ [L - ⅓L/2]
(√⅛)[d] = ½[⅔L] + ¼[⅔L/2] - ¼[L - ⅓L/2]
(√⅛)[d] = ⅓L + ⅟₁₂L - ¼L + ⅟₂₄L
(√⅛)[d] = 5L/24
d = 5L/24 / (√⅛)
d = 5√⅛L/3
Whoever can answer this is smart
What is an electrostatic force in a simple definition
What is a magnetic force in simple definition
Answer:
Hope it helps you
Explanation:
An electrostatic force is an attractive as well as replusive force caused by the electric charge particles.
Magnetic force is a consequence of electromagnetic force and is caused due to the motion of charges.
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The arm of a crane at a construction site is
20.0 m long, and it makes an angle of 10.0°
with the horizontal. Assume that the max-
imum load the crane can handle is limited
by the amount of torque the load produces
around the base of the arm.
What maximum torque can the crane with-
stand if the maximum load the crane can
handle is 520 N?
Answer in units of N. m.
The maximum torque that the crane can withstand is 512.1 N.
What is the maximum torque the crane can withstand?
To calculate the maximum torque that the crane can withstand, we need to find the force produced by the load and the distance from the axis of rotation to the line of action of this force.
And also the distance from the axis of rotation to the line of action of the force = horizontal component of the arm length
The horizontal component of the arm length is given by:
r = Lcos(θ)
Finally, the maximum torque that the crane can withstand is given by:
τ = F r
τ = 520 N x cos ( 10 )
τ = 512.1 N
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What type of circuit is in the diagram?
b
O series circuit
O parallel circuit
PLEASE HELPPP
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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A scale used to weigh fish consists of a spring hung from a support. The spring's equilibrium length is 10.0 cm. When a 4.0 kg fish is suspended from the end of the spring, it stretches to a length of 12.0 cm.
What is the spring constant k for this spring?
If an 8.0 kg fish is suspended from the spring, what will be the length of the spring?
.
Answer:
We can use Hooke's Law to find the spring constant k:
F = kx
where F is the force applied to the spring, x is the displacement of the spring from its equilibrium length, and k is the spring constant.
We can find the force applied to the spring by using the weight of the 4.0 kg fish:
F = mg = (4.0 kg)(9.81 m/s^2) = 39.24 N
The displacement of the spring is the difference between its length with the fish and its equilibrium length:
x = 12.0 cm - 10.0 cm = 2.0 cm = 0.02 m
Now we can solve for k:
k = F/x = 39.24 N / 0.02 m = 1962 N/m
To find the length of the spring with an 8.0 kg fish suspended from it, we can use the same formula with the new weight:
F = mg = (8.0 kg)(9.81 m/s^2) = 78.48 N
We can solve for x, which is the new displacement of the spring:
x = F/k = 78.48 N / 1962 N/m = 0.04 m
Therefore, the length of the spring will be:
10.0 cm + 4.0 cm = 14.0 cm
Explanation:
Car À moves at a speed of 8m/s for 43 seconds. Car B moves at a speed of 7 m/s for 50 seconds. Which car traveled a longer distance
Please show working
Distance = (speed) x (time)
Car A: Distance = (8 m/s) x (43 s) = 344 meters
Car B: Distance = (7 m/s) x (50 s) = 350 meters
350 meters is a longer distance than 344 meters.
Car-B traveled a longer distance than Car-A did.
Answer:
\(\boxed {\boxed {\sf Car \ B : 350 \ meters }}\)
Explanation:
Distance is equal to the product of speed and time.
\(d=s*t\)
1. Car A
Car A has a speed of 8 meters per second and travels for 43 seconds.
\(s= 8 \ m/s \\t= 43 \ s\)
Substitute the values into the formula.
\(d= 8 \ m/s *43 \ s\)
Multiply and note that the seconds will cancel out.
\(d= 8 \ m*43= 344 \ m\)
2. Car B
Car B has a speed of 7 meters per second and travels for 50 seconds.
\(s= 7 \ m/s \\t= 50 \ s\)
Substitute the values in and multiply.
\(d= 7 \ m/s * 50 \ s\)
\(d= 7 \ m * 50 = 350 \ m\)
350 meters is a longer distance than 344 meters, so Car B traveled the longer distance.
hi i think it 573 udaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
ummm I didn't understand the question