Write the formula of the coordination compound ammonium hexafluororhodate(V).
Enclose the coordination complex in square brackets, even if there are no counter ions. Do not enclose a ligand in parentheses if it appears only once. Enter water as H2O.
Answers
The formula for the coordination compound ammonium hexafluororhodate(V) is [\(NH_{4}\)][\(RhF_{6}\)].
In this compound, the rhodium ion (Rh) is coordinated with six fluoride ions (F) in an octahedral arrangement.
The ammonium ion (\(NH_{4+}\)) acts as the counter ion to balance the charge of the complex ion [\(RhF_{6}\)]−.
The formula is written in this way to emphasize the difference between the complex ion and the counter ion.
The coordination complex is enclosed in square brackets to indicate that it is a single entity with its own properties and reactivity.
The compound does not contain any water molecules, so water is not included in the formula.
To know more about octahedral arrangement, refer here:
https://brainly.com/question/14241452#
#SPJ11
Related Questions
How many L of 1.2 M solution of HCl are needed to react completely with 150 mL of 1.6 M HIO3 solution? Assume excess ICI.ICI + HIO3 + 5 HCI → 2 IC13+ 3 H2O0 3.6L02.1L2.5 LO 1.0L
Answers
They give us the balanced equation of the reaction. Now, we need to know the moles of HIO3 present in the solution that they describe to us. We are given the molarity and volume of the solution, so the moles will be:
\(\begin{gathered} molHIO_3=1.6M\times150mL\times\frac{1L}{1000mL} \\ molHIO_3=\frac{1.6molHIO_3}{1L}\times150mL\times\frac{1L}{1,000mL}=0.24molHIO_3 \end{gathered}\)Now, we will find the moles of HCl that will be needed to react 0.24mol of HIO3. We see the stoichiometry of the reaction. The ratio HCl to HIO3 is 5/1. So, the moles of HCl that we need is:
\(\begin{gathered} molHCl=GivenmolHIO_3\times\frac{5molHCl}{1molHIO_3} \\ molHCl=0.24molHIO_3\times\frac{5molHCl}{1molHIO_{3}}=1.2molHCl \end{gathered}\)They ask us about the volume of the solution, we have the molarity and the moles. So, the volume will be:
\(\begin{gathered} Molarity=\frac{MolesSolute}{Lof\text{solution}} \\ LofSolution=\frac{MolesSolute}{Molarity} \\ LofSolution=\frac{1.2molHCl}{1.2molHCl/1L}=1.0L \end{gathered}\)To react completely with 150 mL of 1.6 M HIO3 solution are needed 1.0 of 1.2M solution of HCl .
So, the answer will be the last option: 1.0L
50 POINTS.
1,What trends exist in the periodic table?
2.What information can be gathered from reading the periodic table?
What are the answers to these questions, for I am struggling a lot.
Answers
Answer:
1. Trends that exist in the periodic table include:
- Atomic size: atomic radius generally decreases from left to right across a period and increases from top to bottom down a group.
- Ionization energy: the energy required to remove an electron from an atom generally increases from left to right across a period and decreases from top to bottom down a group.
- Electronegativity: the ability of an atom to attract electrons in a chemical bond generally increases from left to right across a period and decreases from top to bottom down a group.
- Metallic character: metals are generally located on the left side of the periodic table and become less metallic going to the right and up the table.
- Nonmetallic character: nonmetals are generally located on the right side of the periodic table and become more nonmetallic going to the right and up the table.
- Reactivity: the reactivity of elements varies depending on the type of reaction and the group or period an element is in.
2. The periodic table provides a wealth of information about each element, including:
- Atomic number: the number of protons and electrons in an atom's nucleus
- Element symbol: an abbreviation used to represent each element
- Element name: the full name of the element
- Atomic mass: the mass of an atom, expressed in atomic mass units (amu)
- Group: the vertical columns in the periodic table, which share similar chemical and physical properties
- Period: the horizontal rows in the periodic table, which show trends in atomic properties
- Electron configuration: the arrangement of electrons in an atom's orbitals
- Oxidation state: the number of electrons an atom gains, loses, or shares when forming a chemical compound
- Physical properties: such as melting point, boiling point, density, color, and state (solid, liquid, gas)
- Chemical properties: such as reactivity, bond formation, and acid-base behavior.
Help me please!!!!!!!
Answers
Answer:
1. 264.369
2. 1772.65
3. 3.25
4.488
5. 0.164525
Explanation: I just added 0's to the ones that didnt have as many decimals which made it easy.
Give one example each for Ionic and Covalent Bonding by writing the following:
a. LEDS
b. Bonding type/method (show the sharing or giving)
c. Chemical Formula
d. Chemical Name
Answers
Answer:C. Chemical Formula
Explanation:
PLEASE HELP!!!!!How do different types of salt affect the boiling point of water? I really don’t understand this
Answers
I need help with my chemistry homework
Answers
Speed in excess of 100 km/h, which is 208.8 km / h
Further explanationLinear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
• An equation of uniformly accelerated motion
\(\large {\boxed {\bold {x=xo+vo.t+\frac {1} {2} at ^ 2}}}\)
vt = vo + at
vt² = vo² + 2a (x-xo)
x = distance on t
vo / vi = initial speed
vt / vf = speed on t / final speed
a = acceleration
I think it's not chemistry but physics
KnownΔx = 290 m
vf = 0⇒stop
Δt = 10 s
We use the formula in the question
\(\tt \Delta x=\dfrac{1}{2}(vf+vi)\Delta t\\\\290=\dfrac{1}{2}(0+vi).10\\\\vi=58~m/s=\boxed{\bold{208.8~km/h}}\)
a sample of blood is found to contain 64.5 micrograms of valproic acid. how many milligrams of valproic acid does this blood sample contain?
Answers
The valproic acid contains 0.0645 milligrams
Conversion scale1000 microgram = 1 milligram
Data obatined from the questionFrom the question given, the following data were obtained:
Mass (in micrograms) = 64.5 microgramsMass (in milligrams) =?How to convert 64.5 micrograms to milligramsWe can convert 64.5 micrograms to milligrams as illustrated below:
1000 microgram = 1 milligram
Therefore,
64.5 micrograms = (64.5 micrograms × 1 milligram) / 1000 microgram
64.5 micrograms = 0.0645 milligrams
Thus, the valproic acid contains 0.0645 milligrams
Learn more about conversion:
https://brainly.com/question/1444594
#SPJ1
Where do CFCs come from?
A:spray cans
B :fire extinguishers
C:Air conditioner
D: manufacturing foams
Or all above
Answers
Answer:
all of the above
Explanation:
Answer:
All of the above
Explanation:
Prior to the montreal CFC production ban, all of these products released CFCs into the atmosphere. Some old air conditioner still release CFC so please be sure to dispose of them as CFC kills the ozone layer.
Nitrogen dioxide, a major air pollutant, can be produced by the combustion of nitrogen oxide as shown. 2NO + O2 Right arrow. 2NO2 In a plant, 1,500 kg of nitrogen oxide is consumed per day to produce 1,500 kg of nitrogen dioxide per day. What is the percent yield? Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100.. 21.7% 32.6% 43.5% 65.2% Mark this and return Save and Exit Next Submit
Answers
Answer:
65.2%
Explanation:
It is given that :
\($2NO + O_2 \rightarrow 2NO_2$\)
Therefore, 60 g of nitrogen oxide will produce 92 g of nitrogen dioxide
or 60 kg of nitrogen oxide will produce 92 kg of nitrogen dioxide
or 1500 kg of nitrogen oxide will produce \(2300\ kg\) of nitrogen dioxide
Therefore the percentage yield = (Actual yield / Expected yield) x 100
percentage yield = \($\frac{1500}{2300} \times 100$\)
Percentage yield = 65.217 %
Answer:
the person above me is correct, the answer for this is 65.2% or option D!
Explanation:
thank you person above me! i got a 100% on the test! :D
One event in a high school track meet is the 400 meter run. If the runners of the 400
meter event start and end at the same location, what is their DISTANCE?
0 meters
© 200 meters
0 400 meters
800 meters
Answers
Answer:
400 meters
Explanation:
Distance is the amount traveled. It doesn't matter if the runners start and end in the same place for distance, they still travel 400 meters.
calculate the ph of 1.0 l of the solution upon addition of 0.010 mol of solid naoh to the original buffer solution. express your answer to two decimal places.
Answers
The pH of the solution after adding 0.010 mol of solid NaOH is 4.47.
The pH of the solution will increase upon addition of the solid NaOH because it is a strong base that will react with the weak acid in the buffer solution. To calculate the new pH, we need to use the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
First, we need to determine the initial concentrations of the acid (HA) and its conjugate base (A-) in the buffer solution. Let's assume the buffer contains acetic acid (CH3COOH) and its conjugate base acetate (CH3COO-), and that the pKa of this buffer is 4.76. We can use the equation:
pKa = pH + log([CH3COO-]/[CH3COOH])
Rearranging this equation, we get:
[CH3COO-]/[CH3COOH] = 10^(pKa - pH)
At the initial pH of the buffer solution, let's say it's 4.0, we can calculate the ratio of [CH3COO-]/[CH3COOH]:
[CH3COO-]/[CH3COOH] = 10^(4.76 - 4.0) = 0.251
This means that the initial concentrations of CH3COOH and CH3COO- are in the ratio of 1:0.251.
Now, let's add 0.010 mol of NaOH to the solution. This will react with the acetate ion to form more CH3COOH and water:
CH3COO- + NaOH → CH3COOH + Na+ + OH-
The amount of CH3COOH formed will be equal to the amount of NaOH added, which is 0.010 mol. This will increase the concentration of CH3COOH while decreasing the concentration of CH3COO-. We can calculate the new concentrations of the acid and base using the following equations:
[HA] = [HA]initial + [OH-]added
[A-] = [A-]initial - [OH-]added
Plugging in the values, we get:
[HA] = 1.0 mol/L + (0.010 mol / 1.0 L) = 1.01 mol/L
[A-] = 0.251 mol/L - (0.010 mol / 1.0 L) = 0.241 mol/L
Now, we can calculate the new pH using the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA]) = 4.76 + log(0.241/1.01) = 4.47
Therefore, the pH of the solution after adding 0.010 mol of solid NaOH is 4.47.
Know more about Buffer Solution here:
https://brainly.com/question/24262133
#SPJ11
choose any bases that will selectively deprotonate the above acid, that is, any bases that will favor the formation of products.
Answers
In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.
Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.
For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.
To learn more visit:
https://brainly.com/question/5613072?referrer=searchResults
Calculate the pH at the following points in a titration of 40 mL (0. 040 L) of 0. 100 M
barbituric acid (Ka = 9. 8 10–5) with 0. 100 M KOH.
(a) no KOH added
(b) 20 mL of KOH solution added
(c) 39 mL of KOH solution added
(d) 40 mL of KOH solution added
(e) 41 mL of KOH solution added
Answers
Molarity of
C
4
H
4
N
2
O
3
=
0.100
M
Volume of
C
4
H
4
N
2
O
3
=
40
m
L
Molarity of
K
O
H
=
0.100
M
K
a
=
9.8
×
10
−
5
Chemical reaction:
C
4
H
4
N
2
O
3
+
K
O
H
→
C
4
H
3
N
2
O
3
K
+
H
2
O
Part a:
no KOH is added.
The concentration of hydrogen ion can be calculated as:
C
4
H
4
N
2
O
3
⇌
C
4
H
3
N
2
O
−
3
+
H
+
K
a
=
[
C
4
H
3
N
2
O
−
3
]
[
H
+
]
[
C
4
H
4
N
2
O
3
]
[
C
4
H
3
N
2
O
−
3
]
=
[
H
+
]
9.8
×
10
−
5
=
[
H
+
]
2
[
C
4
H
4
N
2
O
3
]
9.8
×
10
−
5
=
[
H
+
]
2
0.100
[
H
+
]
2
=
9.8
×
10
−
6
[
H
+
]
=
3.13
×
10
−
3
M
The pH value of the solution is:
p
H
=
−
log
[
H
+
]
p
H
=
−
log
(
3.13
×
10
−
3
)
p
H
=
2.50
Part b:
20 mL of KOH is added.
We will find the initial moles of the reactants:
M
o
l
e
s
(
n
)
=
M
o
l
a
r
i
t
y
(
M
)
×
V
o
l
u
m
e
(
V
)
n
C
4
H
4
N
2
O
3
=
0.100
M
×
0.040
L
=
0.0040
m
o
l
n
K
O
H
=
0.100
M
×
0.020
L
=
0.0020
m
o
l
Moles of the acid and salt after the addition of KOH:
n
C
4
H
4
N
2
O
3
=
0.00400
−
0.0020
=
0.0020
m
o
l
n
C
4
H
3
N
2
O
3
K
=
0.00200
m
o
l
The concentration of acid and salt:
M
=
n
V
V
=
40
+
20
=
60
m
L
[
C
4
H
4
N
2
O
3
]
=
0.0020
m
o
l
0.060
L
=
0.033
M
[
C
4
H
3
N
2
O
3
K
]
=
0.0020
m
o
l
0.060
L
=
0.033
M
The pH value is calculated as:
p
H
=
−
log
(
K
a
)
+
log
(
[
C
4
H
3
N
2
O
3
K
]
[
C
4
H
4
N
2
O
3
]
)
p
H
=
−
log
(
9.8
×
10
−
5
)
+
log
(
0.033
0.033
)
p
H
=
4.01
Part c:
39 mL of KOH is added.
We will find the initial moles of the reactants:
M
o
l
e
s
(
n
)
=
M
o
l
a
r
i
t
y
(
M
)
×
V
o
l
u
m
e
(
V
)
n
C
4
H
4
N
2
O
3
=
0.100
M
×
0.040
L
=
0.0040
m
o
l
n
K
O
H
=
0.100
M
×
0.039
L
=
0.0039
m
o
l
Moles of the acid and salt after the addition of KOH:
n
C
4
H
4
N
2
O
3
=
0.00400
−
0.0039
=
0.0001
m
o
l
n
C
4
H
3
N
2
O
3
K
=
0.0039
m
o
l
The concentration of acid and salt:
M
=
n
V
V
=
40
+
39
=
79
m
L
[
C
4
H
4
N
2
O
3
]
=
0.0001
m
o
l
0.079
L
=
0.00126
M
[
C
4
H
3
N
2
O
3
K
]
=
0.0039
m
o
l
0.079
L
=
0.0494
M
The pH value is calculated as:
p
H
=
−
log
(
K
a
)
+
log
(
[
C
4
H
3
N
2
O
3
K
]
[
C
4
H
4
N
2
O
3
]
)
p
H
=
−
log
(
9.8
×
10
−
5
)
+
log
(
0.0494
0.00126
)
p
H
=
4.01
+
1.59
p
H
=
5.60
Part d:
40 mL of KOH is added.
We will find the initial moles of the reactants:
M
o
l
e
s
(
n
)
=
M
o
l
a
r
i
t
y
(
M
)
×
V
o
l
u
m
e
(
V
)
n
C
4
H
4
N
2
O
3
=
0.100
M
×
0.040
L
=
0.0040
m
o
l
n
K
O
H
=
0.100
M
×
0.040
L
=
0.0040
m
o
l
Moles of the acid and salt after the addition of KOH:
n
C
4
H
4
N
2
O
3
=
0.00400
−
0.0040
=
0.0
m
o
l
n
C
4
H
3
N
2
O
3
K
=
0.0040
m
o
l
The concentration of acid and salt:
M
=
n
V
V
=
40
+
40
=
80
m
L
[
C
4
H
4
N
2
O
3
]
=
0.0
m
o
l
0.080
L
=
0.0
M
[
C
4
H
3
N
2
O
3
K
]
=
0.0040
m
o
l
0.080
L
=
0.050
M
The pH value is calculated as:
p
H
=
7
+
1
2
(
p
K
a
+
log
[
C
4
H
3
N
2
O
3
K
]
)
p
H
=
7
+
1
2
(
4.01
+
log
(
0.05
)
)
p
H
=
7
+
1
2
(
4.01
−
1.30
)
p
H
=
7
+
1.35
p
H
=
8.35
Part e:
41 mL of KOH is added.
We will find the initial moles of the reactants:
M
o
l
e
s
(
n
)
=
M
o
l
a
r
i
t
y
(
M
)
×
V
o
l
u
m
e
(
V
)
n
C
4
H
4
N
2
O
3
=
0.100
M
×
0.040
L
=
0.0040
m
o
l
n
K
O
H
=
0.100
M
×
0.041
L
=
0.0041
m
o
l
Moles of the base remains left over after the addition of KOH:
n
K
O
H
=
0.0041
−
0.0040
=
0.0001
m
o
l
The concentration of base:
M
=
n
V
V
=
40
+
41
=
81
m
L
[
K
O
H
]
=
0.0001
m
o
l
0.081
L
=
0.00123
M
The concentration of hydroxide ion is equal to 0.00123 M because it dissolves as:
K
O
H
→
K
+
+
O
H
−
The pOH value of the solution:
p
O
H
=
−
log
[
O
H
−
]
p
O
H
=
−
log
(
0.00123
)
p
O
H
=
2.91
The pH value is calculated as:
p
H
+
p
O
H
=
14
p
H
+
2.91
=
14
p
H
=
11.1
One way of purifying gaseous H2 is to pass it under high pressure through the holes of a metal's crystal structure. Palladium, which adopts a cubic closest packed structure, absorbs more H2 than any other element and is one of the metals currently used for this purpose. Although the metal-hydrogen interaction is unclear, it is estimated that the density of absorbed H2 approaches that of liquid hydrogen (70.8 g/L). What volume (in L) of gaseous H2, measured at STP, can be packed into the spaces of 1 dm3 of palladium metal
Answers
Answer:
\(V=795.26L\)
Explanation:
From the question we are told that:
Volume \(V=1dm^3=>1L\)
Density \(\rho=70.8g/L\)
Generally the equation for Density is mathematically given by
\(\rho =\frac{Mass}{Volume}\)
Therefore
\(M=\rho*V\)
\(M=70.8*1\)
\(M=70.8g\)
Since at STP
\(T=273K\)
\(P=1atm\)
\(Mass =70.8g\)
Therefore
\(Moles\ of\ Hydrogen=\frac{Mass}{2g}\)
\(Moles\ of\ Hydrogen=\frac{70.8}{2g}\)
\(Moles\ of\ Hydrogen=35.4moles\)
Generally the equation for Ideal gas is mathematically given by
\(PV=nRT\)
Therefore
\(V=\frac{nRT}{P}\)
\(V=\frac{35.4*0.0826*273}{1}\)
\(V=795.3L\)
K3PO4+AgNO3--> ???
Ba(HCO3)2+Ba(OH2)-->
Answers
Explanation:
A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.
For 1:When potassium phosphate reacts with silver nitrate, it leads to the formation of silver phosphate and potassium nitrate.
The balanced chemical equation follows:
\(3AgNO_3+K_3PO_4\rightarrow Ag_3PO_4+3KNO_3\)
For 2:When barium bicarbonate reacts with calcium hydroxide, it leads to the formation of barium carbonate, calcium carbonate and water
The balanced chemical equation follows:
\(Ba(HCO_3)_2+Ca(OH)_2\rightarrow BaCO_3+CaCO_3+2H_2O\)
geostrophic winds blow question 7 options: parallel to isobars from low pressure to high pressure from high pressure to low pressure perpendicular to isobars
Answers
Geostrophic winds blow parallel to isobars from low pressure to high pressure from high pressure to low pressure perpendicular to isobars.
This means that they move along lines of equal pressure, rather than moving from areas of high pressure to areas of low pressure or vice versa. Isobars are lines or contours on a weather map that connect areas of equal atmospheric pressure. Geostrophic winds are typically found in the upper atmosphere, where the Coriolis effect is strong enough to balance out the pressure gradient force and cause the winds to move in a straight line. In the lower atmosphere, friction and other factors can cause the winds to deviate from this pattern.
To learn more about Isobars :
https://brainly.com/question/29971663
#SPJ11
What are the 3 chemical properties of / for Neon ?
Answers
3 chemical properties of for Neon is colorless, odorless and tasteless
Neon is a rare atmospheric gas and as such is non toxic and chemically inert and neon poses no threat to the environment and can have no impact at all because its chemically unreactive and form no compound and no known ecological damage caused by this element and the properties of neon include the colorless and tasteless and odorless inert gas and it changes to reddish orange color in vacuums tube and it is chemically inactive
Know more about chemical properties
https://brainly.com/question/489869
#SPJ1
can someone Fing answer this PLEASE! NOW
Chemical Reactions Performance Task
Description: A student conducted two different demonstrations in their science class that started with copper chloride (CuCl₂). They have provided you with the following data tables to help you determine if a physical change or chemical reaction occurred during the demonstrations.
Demonstration 1:
Reactants
substances at beginning of reaction
Products
substances at the end of the reaction
Substance
(Chemical Formula)
Copper Chloride
(CuCl₂)
Water
(H₂O)
Copper Chloride
(CuCl₂)
Water
(H₂O)
Properties
Density: 2.51 g/cm³
Melting Point: 100ºC
Boiling Point: 993ºC
Density: 1 g/cm³
Melting Point: 0ºC
Boiling Point: 100ºC
Density: 2.51 g/cm³
Melting Point: 100ºC
Boiling Point: 993ºC
Density: 1 g/cm³
Melting Point: 0ºC
Boiling Point: 100ºC
Based on the patterns (similarities and differences) in the properties of the reactants and products in the table above, is this a physical or chemical reaction? Cite specific evidence from multiple properties in the data table to support your answer. (5pts)
Claim
Evidence
Reasoning
Demonstration 2:
Reactants
substances at beginning of reaction
Products
substances at the end of the reaction
Substance
(Chemical Formula)
Copper Chloride
(CuCl₂)
Iron
(Fe)
Iron Chloride
(FeCl₂)
Copper
(Cu)
Properties
Density: 2.51 g/cm³
Melting Point: 100ºC
Boiling Point: 993ºC
Density: 7.86 g/cm³
Melting Point: 1538ºC
Boiling Point: 2682ºC
Density: 3.16 g/cm³
Melting Point: 677ºC
Boiling Point: 1023ºC
Density: 8.96 g/cm³
Melting Point: 1085ºC
Boiling Point: 2562ºC
Based on the patterns (similarities and differences) in the properties of the reactants and products in the table above, is this a physical or chemical reaction? Cite specific evidence from multiple properties in the table to support your answer. (5pts)
Claim
Evidence
Reasoning
Using the data from Demonstrations 1 and 2, fill out the table below to describe the difference between a physical and chemical reaction in terms of the rearrangement and/or conservation of atoms and molecules. Choose conserved or not conserved for atoms. Choose rearranged or not rearranged for molecules. (4pts)
Physical Changes
Chemical Reactions
Atoms:
(conserved/not conserved)
Molecules
(Rearranged/Not rearranged)
Answers
Answer:
Need to broken down more.
Explanation:
Answer:
its FIND NOT fing
Explanation:
28
Aisha was preparing two cupcakes with the same
mass and volume in the same oven. In order to
determine the specific heat of the cupcakes, Aisha
measured the temperature of each one at four
different times. The graph below shows the changes
in temperature with time.
Answers
Answer:
Explanation:
I am sorry but the graph is not given
Use the following equation to answer questions : 2 C6H10 + 17 O2 12 CO2 + 10 H2O a) If I do this reaction with 35 grams of C6H10 and 45 grams of oxygen, how many grams of carbon dioxide will be formed? b) What is the limiting reagent? ___________ c) How much of the excess reagent is left over after the reaction is finished? d) If 35 grams of carbon dioxide are actually formed from the reaction, what is the percent yield of this reaction?
Answers
The answers of every subquestion is given below:
What is percentage yield ?
Percent yield of the reaction is the percent ratio of actual yield to the theoretical yield.It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%.
The theoretical yield is the amount predicted by a stiochiometric calculation based on the number of moles of all reactants present.
This calculation assumes that only one reaction occurs and that the limiting reactant reacts completely.
The actual yield is the quantity of a product that is obtained from a chemical reaction.
2 C₆H₁₀ + 17 O₂ ⇒ 12 CO₂ + 10 H₂O
1. When you do this calculation for 35 grams of C₆H₁₀, you find that 113 grams of CO2 will be formed.
When you do the calculation for 45 grams of oxygen,You find that 43.7 grams of CO2 will be formed.Because 43.7 grams is the smaller number forming 43.7 grams of product.
2. Oxygen is the limiting reagent
3. 21.4 grams of C₆H₁₀ will be left over.
4. 80.1%
To know more about percent yield:
brainly.com/question/17042787
#SPJ1
I NEED HELP PLEASE, THANKS!
Electrochemistry is important in many aspects of daily life.
i. Define voltaic cell.
ii. Fill in the blanks for the drawing of a voltaic cell that’s made with copper/copper (II) nitrate (E° = 0.34 V) and zinc/zinc (II) nitrate (E° = –0.76 V). Briefly explain the role of the salt bridge.
iii. Using the equation E°cell = E°cathode – E°anode, calculate the overall cell potential for the cell.
iiii.
a. _____________
b. _____________
c. _____________
d. _____________
e. _____________
f. _____________
g. _____________
h. _____________
Answers
Answer:
Here's what I get
Explanation:
(i) Voltaic cell
A voltaic cell is a device that uses a chemical reaction to produce electrical energy.
(ii) Overall Cell Potential
The standard reduction potentials for the half-reactions are
ℰ°/V
Cu²⁺ + 2e⁻ ⇌ Cu 0.34
Zn²⁺ + 2e⁻ ⇌ Zn -0.76
The half-reaction with the more positive potential is the reduction half-reaction. It is the reaction that occurs at the cathode.
The half-reaction with the more negative potential is the oxidation half-reaction. It is the reaction that occurs at the anode.
We reverse that half-reaction and subtract the voltages to get the cell reaction.
ℰ°/V
Cathode: Cu²⁺ + 2e⁻ ⇌ Cu 0.34
Anode: Zn ⇌ Zn²⁺ + 2e⁻ -0.76
Cell: Zn + Cu²⁺ ⇌ Zn²⁺ + Cu 1.10
\(\mathcal{E}_{\text{cell}}^{\circ} = \mathcal{E}_{\text{cat}}^{\circ} - \mathcal{E}_{\text{an}}^{\circ} = \text{0.34 V} - \text{(-0.76 V)} = \text{0.34 V} + \text{0.76 V} = \textbf{1.10 V}\)
(iii) Diagram
The specific labels will depend on your textbook.
They are often as follows.
a. Electron flow
b. Voltmeter or lightbulb
c. Electron flow
d. Cathode or Cu
e. Cu²⁺(aq) and NO₃⁻(aq)
f. Salt bridge
g. Zn²⁺(aq) and NO₃⁻(aq)
h. Anode or Zn
The salt bridge enables ions to flow in the internal circuit and to maintain electrical neutrality in the two compartments.
It often consists of a saturated solution of KCl.
As Zn²⁺ ions form in the anode compartment, Cl⁻ ions move in to provide partners for them.
As Cu²⁺ ions are removed from the cathode compartment, K⁺ ions move in to replace them.
Answer:a. Electron flow
b. Voltmeter or lightbulb
c. Electron flow
d. Cathode or Cu
e. Cu²⁺(aq) and NO₃⁻(aq)
f. Salt bridge
g. Zn²⁺(aq) and NO₃⁻(aq)
h. Anode or Zn
Explanation:
What is an atom of Gold's mass number if it has 111 neutrons?
Answers
Answer:
190
Explanation:
Gold has atomic number of 79, which is the number of protons.
Mass number = #protons + #neutrons = 79 + 111 = 190
what is the standard molar heat of solution for solid calcium bromide given in the standard enthalpy of formation
Answers
The standard molar heat of solution for solid calcium bromide can be calculated using the standard enthalpy of formation. The heat of solution is approximately -675 kJ/mol.
The standard molar heat of solution refers to the amount of heat released or absorbed when one mole of a substance dissolves in a specified amount of solvent. In this case, we are considering solid calcium bromide (CaBr₂) dissolving in a solvent.
To calculate the heat of solution, we can utilize the standard enthalpy of formation, which is the change in enthalpy when one mole of a compound is formed from its constituent elements in their standard states. The standard enthalpy of formation for solid calcium bromide (CaBr₂) is -675 kJ/mol. The standard molar heat of solution for calcium bromide can be determined by considering the following reaction,
CaBr₂(s) → Ca²⁺(aq) + 2Br⁻(aq)
Since the heat of formation is typically given in terms of the formation of one mole of a compound, we need to consider the formation of one mole of calcium ions and two moles of bromide ions.
The enthalpy change for the dissolution of one mole of calcium bromide can be calculated as follows,
ΔH_solution = [1 × ΔH₂(Ca²⁺(aq))] + [2 × ΔH₂(Br⁻(aq))]
Substituting the given standard enthalpy of formation values,
ΔH_solution = [1 × (-675 kJ/mol)] + [2 × 0 kJ/mol]
= -675 kJ/mol
Therefore, the standard molar heat of solution for solid calcium bromide is approximately -675 kJ/mol.
To know more about standard enthalpy of formation, visit,
https://brainly.com/question/30431725
#SPJ4
draw the lewis structure for the peroxynitrite ion, onoo−. label each atom with its state of hybridization and specify the composition of each of the different types of bond.
Answers
Lewis Structure for the peroxynitrite ion:
O O
\ \ / /
O-N-O
The hybridization of each atom is as follows:
Nitrogen (N): sp2 hybridized.
Oxygen (O): sp3 hybridized.
The composition of each bond is as follows:
Nitrogen-oxygen (N-O) bonds: These are sigma bonds.
Oxygen-oxygen (O-O) bond: This is a sigma bond.
To draw the Lewis structure of the peroxynitrite ion (ONOO-), we need to determine the arrangement of atoms and the distribution of valence electrons.
Start by identifying the central atom. In this case, the central atom is nitrogen (N) since it is less electronegative than oxygen (O).
Determine the total number of valence electrons. Nitrogen contributes 5 valence electrons, each oxygen contributes 6 valence electrons, and the negative charge adds an additional electron. So we have a total of 5 + 6 + 6 + 6 + 1 = 24 valence electrons.
Connect the atoms with single bonds. Nitrogen will form single bonds with both oxygen atoms:
O O
\ /
N
Distribute the remaining electrons around the atoms to satisfy the octet rule (except for hydrogen, which can have a duet).
a. Place two electrons on each oxygen atom to complete their octets:
O O
\ \ / /
O-N-O
b. We have used 6 electrons so far (2 on each oxygen atom). We have 24 - 6 = 18 electrons remaining.
c. Place the remaining electrons around the central nitrogen atom. Since nitrogen has 5 valence electrons, it will have 8 electrons around it (octet rule).
O O
\ \ / /
O-N-O
Check if all atoms have an octet. In this case, nitrogen has an octet, and each oxygen atom has an octet.
Finally, add the negative charge (-1) to the structure by placing the additional electron on one of the oxygen atoms:
O O
\ \ / /
O-N-O
The hybridization of each atom is as follows:
Nitrogen (N): sp2 hybridized. It forms three sigma bonds with three atoms (two oxygen and one nitrogen) and has one unhybridized p orbital containing a lone pair of electrons.
Oxygen (O): sp3 hybridized. Each oxygen atom forms one sigma bond with nitrogen and two sigma bonds with electrons in the lone pairs.
The composition of each bond is as follows:
Nitrogen-oxygen (N-O) bonds: These are sigma bonds formed by the overlap of sp2 hybrid orbitals of nitrogen and sp3 hybrid orbitals of oxygen.
Oxygen-oxygen (O-O) bond: This is a sigma bond formed by the overlap of sp3 hybrid orbitals of oxygen atoms.
It's important to note that Lewis structures provide a simplified representation of bonding and electron distribution, and the actual electronic structure may involve resonance or delocalization of electrons.
To know more about Lewis structures, refer to the link below:
https://brainly.com/question/29756546#
#SPJ11
the experimentally determined atomic mass of o-16 is 15.99491 amu. calculate the mass defect, the binding energy in j/mol the binding energy in mev/atom. mass defect
Answers
The mass defect of O-16 is approximately 0.00509 amu. The mass defect is the difference between the experimental mass of an atomic nucleus and the sum of the masses of its individual protons and neutrons. In this case, we are calculating the mass defect of O-16.
The atomic mass of O-16 is given as 15.99491 amu (atomic mass units).
The sum of the masses of 8 protons (each with a mass of 1.007276 amu) and 8 neutrons (each with a mass of 1.008665 amu) is:
8 protons × 1.007276 amu/proton = 8.058208 amu
8 neutrons × 1.008665 amu/neutron = 8.06932 amu
The sum of these masses is:
8.058208 amu + 8.06932 amu = 16.127528 amu
To calculate the mass defect, we subtract the experimental mass from the sum of the masses of the individual particles:
16.127528 amu - 15.99491 amu = 0.132618 amu
The binding energy can be calculated using Einstein's mass-energy equivalence equation, E = mc^2, where E is the energy, m is the mass defect, and c is the speed of light (approximately 2.998 × 10^8 m/s).
To convert the mass defect to energy, we multiply it by c^2:
0.132618 amu × (2.998 × 10^8 m/s)^2 = 1.187 × 10^14 J/mol
To convert the binding energy to MeV/atom, we can use the conversion factor:
1 J/mol = 6.242 × 10^18 MeV/atom
Therefore, the binding energy in MeV/atom is:
1.187 × 10^14 J/mol × 6.242 × 10^18 MeV/atom = 7.41 × 10^32 MeV/atom
The mass defect of O-16 is approximately 0.00509 amu. The binding energy is calculated to be 1.187 × 10^14 J/mol and 7.41 × 10^32 MeV/atom.
To know more about neutrons , visit;
https://brainly.com/question/3197731
#SPJ11
provide a stepwise mechanism for the formation of the monoacetylated produt in the reaction onvolving ferrocene, acetyl chloride, an anhydrous alcl3
Answers
Stepwise mechanism for the formation of the monoacetylated product in the reaction involving ferrocene, acetyl chloride, and anhydrous AlCl3.
1. Protonation: The anhydrous AlCl3 protonates the acetyl chloride, generating a more electrophilic acylium ion (R-C≡O+).
2. Coordination: The acylium ion coordinates with the π-electron-rich aromatic ring of ferrocene through the cyclopentadienyl rings.
3. Electrophilic attack: One of the π-electrons from the cyclopentadienyl ring attacks the acylium carbon, forming a cyclopentadienyl cation intermediate.
4. Rearrangement: The positive charge on the cyclopentadienyl cation is delocalized onto the adjacent carbon atom, resulting in the migration of the acetyl group to a neighboring carbon.
5. Deprotonation: The resulting intermediate is deprotonated by AlCl3, forming the monoacetylated ferrocene product.
The reaction involves the initial protonation of acetyl chloride by AlCl3, followed by coordination with ferrocene. The electrophilic acylium ion then undergoes attack by a π-electron from the aromatic ring, forming a cyclopentadienyl cation intermediate. The positive charge is subsequently delocalized, leading to a rearrangement and migration of the acetyl group. The final product is obtained after deprotonation of the intermediate. This mechanism highlights the role of AlCl3 as a Lewis acid catalyst in facilitating the formation of the monoacetylated product.
Learn more about anhydrous AlCl3 here:
https://brainly.com/question/28573812
#SPJ11
A 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH. Determine the pH of the solution before the addition of any KOH. The Ka of HF is 3.5 x 10-4. A) 4.15 B) 0.70 C) 2.08 D) 3.46 E) 1.00
Answers
1.58 is not among the given options, so we must choose the closest option. the pH of the solution before the addition of any KOH. The correct answer is E) 1.00.
To determine the pH of the solution before the addition of any KOH, we need to find the concentration of H+ ions in the solution using the Ka expression.
Step 1: Write the dissociation equation for HF.
HF ⇌ H+ + F-
Step 2: Write the Ka expression for the reaction.
Ka = [H+][F-] / [HF]
Step 3: Set up an equilibrium table (ICE table) to solve for [H+].
Initial: [HF] = 0.20 M, [H+] = 0, [F-] = 0
Change: [HF] = -x, [H+] = +x, [F-] = +x
Equilibrium: [HF] = 0.20 - x, [H+] = x, [F-] = x
Step 4: Substitute the equilibrium concentrations into the Ka expression.
Ka = (x)(x) / (0.20 - x)
Step 5: Solve for x, which is equal to [H+].
Ka = 3.5 x 10^-4
3.5 x 10^-4 = (x)(x) / (0.20 - x)
Since Ka is small, we can assume x is much smaller than 0.20, so we can simplify the equation to:
3.5 x 10^-4 = (x)(x) / (0.20)
Solve for x:
x ≈ 2.64 x 10^-2 M
Step 6: Calculate the pH using the [H+] concentration.
pH = -log10[H+]
pH = -log10(2.64 x 10^-2)
pH ≈ 1.58
For more question on pH click on
https://brainly.com/question/172153
#SPJ11
Which of the following pure substances will have hydrogen bonds? (Lone electron pairs have been omitted from these structures.)
a. acetone
b. dimethyl ether
c. methanol
d. acetone and methanol
e. dimethyl ether and methanol
Answers
The correct option is c) methanol
The pure substance which will have hydrogen bonds among the given options is option c, methanol.
A pure substance is a substance that has a fixed chemical composition and characteristic properties. A pure substance can be a single element or a single compound, whereas a mixture is a combination of two or more pure substances.
Hydrogen bonding occurs in molecules where hydrogen is attached to the highly electronegative elements oxygen, fluorine, or nitrogen. When an electronegative atom has a hydrogen atom attached to it, a dipole-dipole interaction is formed. This is because the oxygen-hydrogen, nitrogen-hydrogen, or fluorine-hydrogen bond is polar, meaning that the electrons in the bond are not shared equally. The given pure substance is methanol, which is a type of alcohol. Methanol contains a hydroxyl (-OH) group, which is bonded to a carbon atom. The oxygen atom has two lone pairs of electrons and is highly electronegative, while the hydrogen atom is electropositive. Because of the hydrogen atom's polar nature and oxygen's electronegativity, the hydrogen atom in methanol forms a hydrogen bond with the oxygen atom.
Learn more about methanol
https://brainly.com/question/3909690
#SPJ11
what are some of the alternative, unconventional resources for oil and natural gas?
Answers
There are several unconventional resources for oil and natural gas, including shale gas, tight gas, coalbed methane, and oil sands.
These resources are unconventional because they require specialized extraction techniques, such as hydraulic fracturing and horizontal drilling. Shale gas, for example, is extracted from shale rock formations by injecting a mixture of water, sand, and chemicals at high pressure to release the gas trapped within the rock. Coalbed methane is extracted from coal seams by pumping out water and lowering the pressure, allowing the gas to be released.
Oil sands, on the other hand, are a mixture of sand, water, and bitumen (a heavy crude oil) that require surface mining or in-situ methods to extract. While unconventional resources can provide a significant source of oil and gas, their extraction can be controversial due to environmental concerns and potential impacts on local communities.
To know more about unconventional resources. Visit :-
https://brainly.com/question/32127222
#SPJ11
You want to push a table 5 feet across the floor. How would a decrease in the resistance caused by friction change the amount of force needed to move an object? Write 1-2 sentences.(2 points) BoldItalicUnderline
Answers
Friction and force applied on an object is inversely related to each other.
How friction effect the amount of force?Friction refers to the force that resists the motion of an object that collide or slide against each other. If the friction is increased, more energy is needed for the movement of the object.
While on the other hand, if friction is decreased less force is needed so we can conclude that friction and force is inversely related to each other.
Learn more about friction here: https://brainly.com/question/24338873