Write the equation of the line in fully simplified slope intercept form

The trapezoidal rule is a numerical integration method that uses trapezoids to estimate the area under a curve. The trapezoidal rule can be used for both definite and indefinite integrals. The trapezoidal rule approximation, Tn, to the integral sin r dz is given by:

Tn = (b-a)/2n[f(a) + 2f(a+h) + 2f(a+2h) + ... + 2f(b-h) + f(b)]where h = (b-a)/n. To determine how large n should be so that Tn is accurate to within 0.00001, we can use the error bound given in Section 5.9 of the course text. According to the error bound, the error, E, in the trapezoidal rule approximation is given by:E ≤ ((b-a)³/12n²)max|f''(x)|where f''(x) is the second derivative of f(x). For the integral sin r dz, the second derivative is f''(r) = -sin r. Since the absolute value of sin r is less than or equal to 1, we have:max|f''(r)| = 1.

Substituting this value into the error bound equation gives:E ≤ ((b-a)³/12n²)So we want to choose n so that E ≤ 0.00001. Substituting E and the given values into the inequality gives:((b-a)³/12n²) ≤ 0.00001Simplifying this expression gives:n² ≥ ((b-a)³/(0.00001)(12))n² ≥ (b-a)³/0.00012n ≥ √(b-a)³/0.00012Now we just need to substitute the values of a and b into this expression. Since we don't know the upper limit of integration, we can use the fact that sin r is bounded by -1 and 1 to get an upper bound for the integral.

For example, we could use the interval [0, pi/2], which contains one full period of sin r. Then we have:a = 0b = pi/2Plugging in these values gives:n ≥ √(pi/2)³/0.00012n ≥ 5073.31Since n must be an integer, we round up to the nearest integer to get:n = 5074Therefore, we should choose n to be 5074 so that the trapezoidal rule approximation, Tn, to the integral sin r dz is accurate to within 0.00001.

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Answer:

Step-by-step explanation:

ABCD is a cyclic quadrilateral

It has the property that opposite angles are supplementary: A with C and B with D.

Solve following for x:

The angles are:

Answer:

t = 20

Step-by-step explanation:

First off we have t as the variable. So you don't really have much but to use PEMDAS and go through the equation step by step.  Like so,

30 = 2t - 10

+ 10        +10

40 = 2t

Now to isolate the variable you must divide, since it's the opposite of multiplication.

40 ÷ 2 = 20

2t ÷ 2 = t

So what we are left with is t = 20

Hope that helps and have a great day!

The  trains are side by side after approximately 15 seconds.Option (b) is correct.

The position of the first train is given by the function:

\($$y_1 = 14t^2$$\)

The position of the second train is given by the function:

\($$y_2 = 130t + 1200$$\)

To find the time when the trains are side by side, we need to solve for the value of t that makes y1 = y2. Thus, we can set the two equations equal to each other:

\($$14t^2 = 130t + 1200$$\)

Rearranging the terms, we get:

\($$14t^2 - 130t - 1200 = 0$$\)

Dividing both sides by 2 to simplify the coefficients, we get:

\($7t^2 - 65t - 600 = 0$$\)

We can use the quadratic formula to solve for t:

\($t = \frac{-(-65) \pm \sqrt{(-65)^2 - 4(7)(-600)}}{2(7)} = \frac{65 \pm \sqrt{4225 + 16800}}{14}$$\)

Simplifying the expression under the square root, we get:

\($$\sqrt{21025} = 145$$\)

So the solutions are:

\($t_1 = \frac{65 + 145}{14}=15$$\)

\($t_2 = \frac{65 - 145}{14} \approx -5.71$$\)

Since time cannot be negative, we discard t2 as an extraneous solution. Thus, the viable time when the trains are side by side is:

\($t = t_1 =15$$\)

Therefore, the trains are side by side after approximately 15 seconds.

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Answer:

(-1.5, 2.5)

Step-by-step explanation:

look at x-value and y-value

find difference between -1 and -2 which is 0.5 same goes with y-axia

Answer:

if he can work 15 hours and must make at least 160 dollars, he'll need to work 8 hours lifeguarding and 7 hours washing cars

Step-by-step explanation:

13 x 8 = 104

8 x 7 =56

when added we get 160, and the hours are exactly 15

x + y ≤ 15

13x + 8y = 160

We can construct a chart, a table for the values of the given function as follows:

1. We need to have the function g(x) = -4x^2.

2. We can obtain the values for the function for the values:

x = -4, x = -2, x = 0, x = 2, x = 4.

3. We need to evaluate the function for each of these values.

4. Finally, we can have a table of the values of x and y.

Having this information into account, we can proceed as follows:

1. x = -4

2. x = -2

3. x = 0

4. x = 2

5. x = 4

Then, having these values, we can construct the values for the function using these values:

We can draw part of this function using these values. We have to remember that, in functions, we can say that y = f(x).

We can also say that the domain of the function is, in interval notation:

And the range, as we can see from the values, is as follows (using interval notation):

This is because the values for y (or f(x)) are less or equal to zero.

In summary, we can have a table to construct a graph using the values for the independent variable and plug these values in the function to obtain the values for y.

We need to remember that y = f(x). Additionally, this function has a domain from -infinity to infinity (all the values in the Real set), and a range for values from -infinity to 0 (including zero).

A graph for this function is as follows:

Main Answer:The linear combination of v = (13/14)u1 + (2/7)u2 + (47/14)u3  

Supporting Question and Answer:

How can we express a vector as a linear combination of  vectors using a system of equations?

To express a vector as a linear combination of  vectors using a system of equations, we need to find the coefficients that multiply each given vector to obtain the desired vector. This can be done by setting up a system of equations, where each equation corresponds to the components of the vectors involved.

Body of the Solution:

(a) To show that the vectors u1 = (2, 0, 3), u2 = (-3, 0, 2), and u3 = (0, 7, 0) form an orthogonal basis for R^3, we need to demonstrate two conditions: orthogonality and linear independence.

u1 · u2 = (2)(-3) + (0)(0) + (3)(2) = -6 + 0 + 6 = 0

u1 · u3 = (2)(0) + (0)(7) + (3)(0) = 0 + 0 + 0 = 0

u2 · u3 = (-3)(0) + (0)(7) + (2)(0) = 0 + 0 + 0 = 0

Since the dot product of every pair of vectors is zero, they are orthogonal.

   2.Linear Independence: We need to show that the vectors u1, u2, and u3 are linearly independent, meaning that no vector can be written as a linear combination of the other vectors.

We can determine linear independence by forming a matrix with the vectors as its columns and performing row operations to check if the matrix can be reduced to the identity matrix.

[A | I] = [u1 | u2 | u3 | I] =

[2 -3 0 | 1 0 0]

[0 0 7 | 0 1 0]

[3 2 0 | 0 0 1]

Performing row operations:

R3 - (3/2)R1 -> R3

R1 <-> R2

[1 0 0 | -3/2 1 0]

[0 1 0 | 0 1 0]

[0 0 7 | 0 0 1]

Since we can obtain the identity matrix on the left side, the vectors u1, u2, and u3 are linearly independent.

Therefore, the vectors u1 = (2, 0, 3), u2 = (-3, 0, 2), and u3 = (0, 7, 0) form an orthogonal basis for R^3.

(b) To write v = (1, 2, 3) as a linear combination of u1, u2, and u3, we need to find the coefficients x, y, and z such that:

v = xu1 + yu2 + z*u3

Substituting the given vectors and coefficients:

(1, 2, 3) = x(2, 0, 3) + y(-3, 0, 2) + z(0, 7, 0)

Simplifying the equation component-wise:

1 = 2x - 3y

2 = 7y

3 = 3x + 2y

From the second equation, we can solve for y:

y = 2/7

Substituting y into the first equation:

1 = 2x - 3(2/7)

1 = 2x - 6/7

7 = 14x - 6

14x = 13

x = 13/14

Substituting the found values of x and y into the third equation

3 = 3(13/14) + 2(2/7)

3 = 39/14 + 4/7

3 = 39/14 + 8/14

3 = 47/14

Therefore, we have determined the values of x, y, and z as follows:

x = 13/14

y = 2/7

z = 47/14

Thus, we can write the vector v = (1, 2, 3) as a linear combination of u1 = (2, 0, 3), u2 = (-3, 0, 2), and u3 = (0, 7, 0) as:

v = (13/14)u1 + (2/7)u2 + (47/14)u3

Therefore, v can be expressed as a linear combination of the given vectors.

Final Answer:Therefore,the linear combination of v = (13/14)u1 + (2/7)u2 + (47/14)u3  

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The linear combination of v = (13/14)u1 + (2/7)u2 + (47/14)u3  

To express a vector as a linear combination of  vectors using a system of equations, we need to find the coefficients that multiply each given vector to obtain the desired vector. This can be done by setting up a system of equations, where each equation corresponds to the components of the vectors involved.

Body of the Solution:

(a) To show that the vectors u1 = (2, 0, 3), u2 = (-3, 0, 2), and u3 = (0, 7, 0) form an orthogonal basis for R^3, we need to demonstrate two conditions: orthogonality and linear independence.

Orthogonality: We need to show that each pair of vectors is orthogonal, meaning their dot product is zero.

u1 · u2 = (2)(-3) + (0)(0) + (3)(2) = -6 + 0 + 6 = 0

u1 · u3 = (2)(0) + (0)(7) + (3)(0) = 0 + 0 + 0 = 0

u2 · u3 = (-3)(0) + (0)(7) + (2)(0) = 0 + 0 + 0 = 0

Since the dot product of every pair of vectors is zero, they are orthogonal.

  2.Linear Independence: We need to show that the vectors u1, u2, and u3 are linearly independent, meaning that no vector can be written as a linear combination of the other vectors.

We can determine linear independence by forming a matrix with the vectors as its columns and performing row operations to check if the matrix can be reduced to the identity matrix.

[A | I] = [u1 | u2 | u3 | I] =

[2 -3 0 | 1 0 0]

[0 0 7 | 0 1 0]

[3 2 0 | 0 0 1]

Performing row operations:

R3 - (3/2)R1 -> R3

R1 <-> R2

[1 0 0 | -3/2 1 0]

[0 1 0 | 0 1 0]

[0 0 7 | 0 0 1]

Since we can obtain the identity matrix on the left side, the vectors u1, u2, and u3 are linearly independent.

Therefore, the vectors u1 = (2, 0, 3), u2 = (-3, 0, 2), and u3 = (0, 7, 0) form an orthogonal basis for R^3.

(b) To write v = (1, 2, 3) as a linear combination of u1, u2, and u3, we need to find the coefficients x, y, and z such that:

v = xu1 + yu2 + z*u3

Substituting the given vectors and coefficients:

(1, 2, 3) = x(2, 0, 3) + y(-3, 0, 2) + z(0, 7, 0)

Simplifying the equation component-wise:

1 = 2x - 3y

2 = 7y

3 = 3x + 2y

From the second equation, we can solve for y:

y = 2/7

Substituting y into the first equation:

1 = 2x - 3(2/7)

1 = 2x - 6/7

7 = 14x - 6

14x = 13

x = 13/14

Substituting the found values of x and y into the third equation

3 = 3(13/14) + 2(2/7)

3 = 39/14 + 4/7

3 = 39/14 + 8/14

3 = 47/14

Therefore, we have determined the values of x, y, and z as follows:

x = 13/14

y = 2/7

z = 47/14

Thus, we can write the vector v = (1, 2, 3) as a linear combination of u1 = (2, 0, 3), u2 = (-3, 0, 2), and u3 = (0, 7, 0) as:

v = (13/14)u1 + (2/7)u2 + (47/14)u3

Therefore, v can be expressed as a linear combination of the given vectors.

Therefore, the linear combination of v = (13/14)u1 + (2/7)u2 + (47/14)u3  

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If the data of the research subjects are presented in a frequency distribution graph, a histogram-type graph should be used.

If the data are presented in a frequency distribution graph, then the type of graph that should be used is a histogram. A histogram is a type of bar graph that displays the distribution of a continuous variable by dividing the range of values into intervals, and bins, and counting the number of observations that fall within each bin.

If the academic majors were nominal a bar graph could also be used to display the frequency of each major. In a bar graph, each category would be plotted on the horizontal axis, and the frequency of students in each category would be plotted on the vertical axis.

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Answer:

28 : 14

Step-by-step explanation:

4 : 2

4 + 2 = 6

42 ÷ 6 = 7

7 × 4 = 28

7 × 2 = 14

Answer:

6. 12cm

7. 11.2 cm

8. 92 degrees

9. 53 degrees

10. 37.5 cm

11. $ 693.12

Step-by-step explanation:

For questions 6-9 the triangle is congurent which means both their angles will be equal.

For the sides you can see that the second triangle is 1.5 times smaller than the first one as taking one of the sides 21/14= 1.5

So for Q. 6 we can multiply side PQ by 1.5.

For Q.7 divide CA by 1.5.

For Q. 10 we can do cross multiplication:

5/4 = x/30

= 150= 4x

= 37.5=x

For Q 11 we can see the size of the paper is 1.9 times bigger than the original one (38/20)

So the shorter side is 30.4 cm.

Then we have to find the area of the paper to multiply the two dimensions and we get 1155.2 square inches.

Then to figure out the money we multiply again and we get $693.12.

Each payment into the sinking fund should be $4,566.71, made at the end of each period.

To find the amount of each payment to be made into a sinking fund, we can use the formula:

P = A * (r / ((1 + r)^n - 1))

Where:
P = payment amount
A = amount to be accumulated ($50,000 in this case)
r = interest rate per period (4% per period in this case)
n = number of periods (since interest is compounded semiannually, there will be 2 periods per year, so if we want to accumulate the $50,000 in, say, 5 years, then n = 5 * 2 = 10)

Substituting the values into the formula, we get:

P = 50000 * (0.04 / ((1 + 0.04)^10 - 1))
P = $4,566.71 (rounded to the nearest cent)

Therefore, each payment into the sinking fund should be $4,566.71, made at the end of each period.

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The required answer is  sec θ = -√2.

Explanation:-

Part 1: Given cosine of theta is equal to radical 3 over 2 on the domain [0,[infinity]).

To determine three possible angles θ,  the cosine inverse function which is a cos and since cosine function is positive in the first and second quadrant. Therefore  conclude that, cosine function of θ = radical 3 over 2 implies that θ could be 30 degrees or 330 degrees or 390 degrees. So, θ = {30, 330, 390}.Part 2:To convert 495° to radians, multiply by π/180°.495° * π/180° = 11π/4To find sec θ, we use the reciprocal of the cosine function which is sec.

Therefore, sec θ = 1/cos θ.To find cos 11π/4,  the reference angle, which is 3π/4. Cosine is negative in the third quadrant so the final result is sec θ = -√2.

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On evaluating the value of the expression  [4.2−3(2.1)] + 1 (-0.2)² is -2.06 .

In the question ,

the expression is given as

[4.2−3(2.1)] + 1 (-0.2)²

the value of (-0.2)²= (-0.2)*(-0.2)

                              = 0.04

Substituting the value of (-0.2)² in expression , we get

=[4.2−3(2.1)] + 1*0.04

=[4.2−3(2.1)] + 0.04

Solving the terms inside [ ] , we have

multiplying 3 with 2.1 we get

3*2.1= 6.3

Substituting it in the expression above we get

= [4.2−6.3] + 0.04

Simplifying further , we get

= -2.1 + 0.04

= -2.06

Therefore , on evaluating the value of the expression  [4.2−3(2.1)] + 1 (-0.2)² is -2.06 .

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Answer:

Step-by-step explanation:

The answer is -2.06.

hope you get a good grade!!!

the vector fields F with the plots labeled I-IV, Then give a one sentence description of the vector field would look like if you plotted it. F(x, y) = (x, xy): rot(F) = 0; The vector field would look like a series of straight lines that move away from the origin

I: F(x, y) = (y, x) - This vector field corresponds with plot I, as it forms a series of counter-clockwise circular paths.

II: F(x, y) = (1, sin y) - This vector field corresponds with plot II, as it forms a series of parallel lines.

III: F(x, y) = (x - 2, x + 1) - This vector field corresponds with plot III, as it forms a series of diagonal lines that move outward from the origin.

IV: F(x, y) = (y, 1/x) - This vector field corresponds with plot IV, as it forms a series of concentric circles with the origin as their center.

F(x, y) = (x, y): rot(F) = 0; The vector field would look like a grid of straight lines.

F(x, y) = y i = x j: rot(F) = 1; The vector field would look like a series of counter-clockwise circular paths.

F(x, y) = (y, -x): rot(F) = -1; The vector field would look like a series of clockwise circular paths.

F(x, y) = (1 + xy)i + x^2 sin y j: rot(F) = x^2; The vector field would look like a series of curves that rotate counter-clockwise around the origin.

F(x, y) = (x, xy): rot(F) = 0; The vector field would look like a series of straight lines that move away from the origin

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Answer:

Step-by-step explanation:

This is a parabola. If we plot the vertex and the focus, we see that the focus is below the vertex. What this tells us is that the parabola opens "upside down" since the parabola wraps itself around the focus. If it opens upside down, then the format for the equation is

\(4p(y-k)=-(x-h)^2\)

where p is the distance between the vertex and the focus (4), h is the first coordinate of the vertex (0), and k is the second coordinate of the vertex (0). Filling in the formula then:

\(4(4)(y-0)=-(x-0)^2\) which simplifies down to

\(16y=-x^2\) and then finally,

\(y=-\frac{1}{16}x^2\)

The probability that a winner wins a gold medal and from the US is 0.06349

From the question, we have the following parameters that can be used in our computation:

The table of values

Gold medal from the US are 48

And the total number of winners of Gold is 48 + 90 + 107 + 114 + 397

So, we have

Total = 756

So, we have

P = 48/756

Evaluate

P = 0.06349

Hence, the probability is 0.06349

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Given that f(x) is the square of x, there are no negative values in its range, which ranges from 0 to.

The answer to a polynomial equation with polynomial coefficients is a function, and that function is an algebraic function.

Linear, quadratic, cubic, polynomial, rational, and radical algebraic functions are some examples of the several types of algebraic functions.

The range of the function f(x) = x2 is higher than or equal to zero, and the domain of the function is the set of all real numbers (x can be anything).

A function that represents an upward-facing parabola is f(x) = x2.

Its range from - to - is its domain.

Given that f(x) is the square of x, there are no negative values in its range, which ranges from 0 to.

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Answer:

\(y - 3 = - 4(x + 2)\)

Answer:

  (a)  11

Step-by-step explanation:

You want the degree of the monomial 7m^6n^5.

The degree of a monomial is the sum of the exponents of its variables.

  m has an exponent of 6

  n has an exponent of 5

The degree is 6+5 = 11.

The least common multiple (LCM) of the factored polynomials x(x-2) and x(x+1) is x(x-2)(x+1).

The Least Common Multiple (LCM) of two or more polynomials is the smallest polynomial that is a multiple of all the given polynomials. To find the LCM of the factored polynomials x(x-2) and x(x+1), we need to follow these steps:

1. Identify the common factors of the polynomials. In this case, the common factor is x.
2. Multiply the common factor by the remaining factors of each polynomial. In this case, we have (x-2) and (x+1).
3. Multiply the remaining factors together to get the LCM. In this case, we have (x-2)(x+1).
4. Finally, multiply the common factor by the product of the remaining factors to get the LCM. In this case, we have x(x-2)(x+1).

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=======================================================

Explanation:

n = diagram number

m = number of matches for diagram n

The given figures show that we have this info so far

\(\begin{array}{|c|c|} \cline{1-2}n & m\\\cline{1-2}1 & 3\\\cline{1-2}2 & 5\\\cline{1-2}3 & 7\\\cline{1-2}\end{array}\)

In other words, we have this sequence of values to represent the number of matches: 3, 5, 7

Each time we generate a new figure, we add 2 matches to the far right side. One match being horizontal and the other vertical.

This shows the common difference of this arithmetic sequence is d = 2.

The starting term is \(a_1 = 3\).

Let's find the nth term.

\(a_n = a_1 + d(n-1)\\\\a_n = 3 + 2(n-1)\\\\a_n = 3 + 2n-2\\\\a_n = 2n+1\\\\\)

Then we can determine the 50th term.

\(a_n = 2n+1\\\\a_{50} = 2(50)+1\\\\a_{50} = 100+1\\\\a_{50} = 101\\\\\)

There are 101 matches in the 50th diagram of the pattern.

Answer: n=1/27=0.037

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 3*n-(1/9)=0

Simplify 1/9

3n -  1/9  = 0

Rewrite the whole as a fraction using  9  as the denominator :

          3n     3n • 9

    3n =  ——  =  ——————

          1        9  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3n • 9 - (1)     27n - 1

————————————  =  ———————

     9              9  

End of step 2  

27n - 1

 ———————  = 0

    9  

Start of step 3

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 27n-1

 ————— • 9 = 0 • 9

   9  

Now, on the left hand side, the  9  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  27n-1  = 0

Solving a Single Variable Equation:

3.2      Solve:    27n-1 = 0

Add  1  to both sides of the equation :

                     27n = 1

Divide both sides of the equation by 27:

                    n = 1/27 = 0.037

Answer:

slope is 3

Step-by-step explanation:

10,17

7,8

8-17=-9

7-10=-3

-9/-3=3

The length x of the right triangle is 8.66 units.

A right triangle is a triangle that has one of its angles as 90 degrees. The sum of angles in a triangle is 180 degrees.

Therefore, the side of the right triangle can be found using trigonometric ratios as follows:

Hence,

tan 60° = opposite / adjacent

where

opposite side = x

adjacent side = 5

Therefore,

tan 60° =  x  / 5

cross multiply

x = 5 tan 60°

x = 5 × 1.73205080757

x = 8.66025403784

x = 8.66 units

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Answer:

1) s > 6

2) d < 84

3) w >= 9

4) z <= 64

5) b < -18

Answer:

PEMDAS

Step-by-step explanation:

parenthesis

Exponents

Multiply

Divide

Add

Subtract

The answer is, (1)  the probability of switching from Brand 3 to Brand 1 after 3 months of advertising is 0.1 * 0.1 * 0.1 = 0.001 (or 0.1%)., (2) x = 0.1667 (or 16.67%) ,y = 0.3571 (or 35.71%) ,z = 0.4762 (or 47.62%) , (3) μ33 = 1 / P[3,3] = 1 / 0.8 = 1.25 months. , (4) μ12 = 1 / P[1,2] = 1 / 0.2 = 5 months.

1. To determine the probability of switching from Brand 3 to Brand 1 after 3 months of advertising, we can use the transition matrix.

The probability can be calculated by multiplying the probabilities of transitioning from Brand 3 to Brand 1 over the course of 3 months.

The transition probability from Brand 3 to Brand 1 is 0.1 (P[3,1] = 0.1), and we need to multiply it by itself three times since we want to find the probability after 3 months.

Therefore, the probability of switching from Brand 3 to Brand 1 after 3 months of advertising is 0.1 * 0.1 * 0.1 = 0.001 (or 0.1%).

2. To determine the steady state probabilities, we need to solve the equation P = P * P, where P is the transition matrix and * represents matrix multiplication.

The steady state probabilities are the eigenvector corresponding to the eigenvalue 1.

Let x, y, and z represent the steady state probabilities for Brand 1, Brand 2, and Brand 3, respectively.

We have the following equations:
0.8x + 0.3y + 0.1z = x
0.2x + 0.5y + 0.1z = y
0.2y + 0.8z = z

Simplifying the equations, we get:
0.8x + 0.3y + 0.1z - x = 0
0.2x + 0.5y + 0.1z - y = 0
-0.2y + 0.8z - z = 0

Solving these equations, we find that the steady state probabilities are:
x = 0.1667 (or 16.67%)
y = 0.3571 (or 35.71%)
z = 0.4762 (or 47.62%)

3. The average number of months it takes a customer to return to Brand 3 can be found by calculating the expected number of transitions from Brand 3 to Brand 3.

This is represented by the element μ33 in the transition matrix.

In the given transition matrix, P[3,3] represents the probability of staying with Brand 3 after one month.

Therefore, μ33 = 1 / P[3,3] = 1 / 0.8 = 1.25 months.

4. To determine the average number of months it takes to switch from Brand 1 to Brand 2, we need to calculate the expected number of transitions from Brand 1 to Brand 2.

This is represented by the element μ12 in the transition matrix.

In the given transition matrix, P[1,2] represents the probability of switching from Brand 1 to Brand 2 after one month. Therefore, μ12 = 1 / P[1,2] = 1 / 0.2 = 5 months.

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