write the equation of the line fully simplified slope-intercept form

Write The Equation Of The Line Fully Simplified Slope-intercept Form

Answers

Answer 1

Answer:

y=6x-5

Step-by-step explanation:

The slope is 6 and the y-intercept is -5.

Answer 2

Answer:

y=6x+-5

Step-by-step explanation:

y=mx+b

the slope is 6/1 so simplified it would be 6

the y-intercept is -5

y=6x+-5 or y=6x-5


Related Questions

PLEASE HELP!! i’ll give brainliest

A. ||
B.
C. neither they are skew lines

PLEASE HELP!! ill give brainliest A. ||B. C. neither they are skew lines

Answers

Answer:

I think it's A (parallel)

Answer:

A. its parallel

Step-by-step explanation:

all angles are equal... two sides are perpendicular and two are parallel

Un auto recorre 50 km desde el punto o al punto P con dirección al Este y
¿Como se expresa la posicion del punto P? es urgente es de números
positivos y negativos​

Answers

Assuming that "in an easterly direction" means that the displacement from O to P is in the positive direction, the position of point P can be expressed as +50 km.

What are the expressions of positive and negative numbers?

Positive numbers are typically expressed with no sign or with a plus sign (+) in front of them. For example, +5 or 7. Negative numbers are expressed with a minus sign (-) in front of them. For example, -3 or -10.

These expressions are used to differentiate between values that are greater than zero (positive) and those that are less than zero (negative).

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2. Suppose A is a n x n matrix. Write a matlab code to find: (a) sum of diagonal elements (b) product of diagonal elements (c) Execute the sum and product when A= ones (5)

Answers

it displays the computed sum and product of the diagonal elements.

Here's a MATLAB code to find the sum and product of the diagonal elements of a given matrix `A`, as well as an example execution for `A = ones(5)`:

```matlab

% Define the matrix A

A = ones(5);

% Get the size of the matrix

[n, ~] = size(A);

% Initialize variables for sum and product

diagonal_sum = 0;

diagonal_product = 1;

% Calculate the sum and product of diagonal elements

for i = 1:n

   diagonal_sum = diagonal_sum + A(i, i);

   diagonal_product = diagonal_product * A(i, i);

end

% Display the results

disp("Sum of diagonal elements: " + diagonal_sum);

disp("Product of diagonal elements: " + diagonal_product);

```

Example execution for `A = ones(5)`:

```

Sum of diagonal elements: 5

Product of diagonal elements: 1

```

In this example, `A = ones(5)` creates a 5x5 matrix filled with ones. The code then iterates over the diagonal elements (i.e., elements where the row index equals the column index) and accumulates the sum and product. Finally, it displays the computed sum and product of the diagonal elements.

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Simplify the expression:

7(–3 + r) =

Answers

-21+7r
You would just distribute the 7

If f(-1) for the polynomial….

If f(-1) for the polynomial.

Answers

Answer:

Yes ,because (x+1) is the factor of all degree 4 polynomial

A supermarket gives a special
offer to cus-
tomers who purchase at least a pack of
vests and a pack of T-shirts. The offer is
restricted to a total of 7 of these items.
a) Write down three inequalities which
must be satisfied.
(b) Draw the graphs of the above condi-
tions and shade the region that satis-
fies them.
(c) If the supermarket makes a gain of N5
on each vest and N8 on each T-shirt,
find the maximum gain made by the
supermarket.

Answers

A) the three inequalities that must be satisfied are:

The number of vests, represented by x, must be a non-negative integer: x ≥ 0.The number of T-shirts, represented by y, must also be a non-negative integer: y ≥ 0.The total number of vests and T-shirts must not exceed 7: x + y ≤ 7.

B) Graph shaded and satisfying all conditions is attached.

What is an inequality?

An inequality in mathematics is a relationship that makes a non-equal comparison between two integers or other mathematical expressions.

It is most commonly used to compare the sizes of two numbers on a number line.

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A supermarket gives a specialoffer to cus-tomers who purchase at least a pack ofvests and a pack of T-shirts.

Can someone help me with this

Can someone help me with this

Answers

Answer:

1) B) 123 years

2) B) 51 years

Step-by-step explanation:

1)given information

2) 2011-1960=51

Answer:

1. B: 123 years

2. B: 51 years

Step-by-step explanation:

1)

1927 - 1804 = 123

2)

2011 - 1960 = 51

Can someone help me with this

If a figure is a square, its diagonals divide it into isosceles triangles.

p: A figure is a square.

q: A figure's diagonals divide into isosceles triangles.

Which represents the converse of this statement? Is the converse true?

Answers

The converse of the statement "If a figure is a square, its diagonals divide it into isosceles triangles" would be:

"If a figure's diagonals divide it into isosceles triangles, then the figure is a square."

The converse statement is not necessarily true. While it is true that in a square, the diagonals divide it into isosceles triangles, the converse does not hold. There are other shapes, such as rectangles and rhombuses, whose diagonals also divide them into isosceles triangles, but they are not squares. Therefore, the converse of the statement is not always true.

Therefore, the converse of the given statement is not true. The existence of diagonals dividing a figure into isosceles triangles does not guarantee that the figure is a square. It is possible for other shapes to exhibit this property as well.

In conclusion, the converse statement does not hold for all figures. It is important to note that the converse of a true statement is not always true, and separate analysis is required to determine the validity of the converse in specific cases.

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please explain how to do this one as well ...

please explain how to do this one as well ...

Answers

Answer:

x = 13

Step-by-step explanation:

Step 1: Define

f(x) = (x - 1)/2

f(x) = 6

Step 2: Substitute and solve for x

6 = (x - 1)/2

12 = x - 1

x = 13

what is the long method of 23 ÷ 650​

Answers

Answer:  The long division method is a way to solve division problems by hand. Here are the steps to do long division:

Write the dividend (the number being divided) inside a long division bracket, and write the divisor (the number doing the dividing) outside of the bracket.

Divide the first digit of the dividend by the divisor. Write the answer (the quotient) above the dividend, and write any remainder (what’s left over) below the first digit of the dividend.

Bring down the next digit of the dividend next to the remainder.

Repeat step 2 until you’ve brought down all of the digits of the dividend.

The final answer is your quotient with any remainder written as a fraction.

a pair of fair dice is tossed. find the probability of getting (a) a total of 10; (b) at most a total of 11.

Answers

(a) The probability of getting a total of 10 is 1/18; (b) The probability of getting at most a total of 11 is 1.

The probability of getting a total of 10 when a pair of fair dice is tossed can be found by dividing the number of favorable outcomes by the total number of possible outcomes. The total number of possible outcomes when two dice are tossed is 6 x 6 = 36. The favorable outcomes for getting a total of 10 are (4, 6) and (6, 4), so there are 2 favorable outcomes. Therefore, the probability of getting a total of 10 is 2/36 = 1/18.

The probability of getting at most a total of 11 can be found by adding the probabilities of getting a total of 2, 3, 4, 5, 6, 7, 8, 9, 10, and 11. The favorable outcomes for each of these totals are:

2: (1, 1)
3: (1, 2), (2, 1)
4: (1, 3), (2, 2), (3, 1)
5: (1, 4), (2, 3), (3, 2), (4, 1)
6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)
7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)
8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2)
9: (3, 6), (4, 5), (5, 4), (6, 3)
10: (4, 6), (5, 5), (6, 4)
11: (5, 6), (6, 5)

The total number of favorable outcomes is 2 + 2 + 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 = 36. Therefore, the probability of getting at most a total of 11 is 36/36 = 1.

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Three sons inherited 2,179 ducats from their father. The father bequeathed the older brother 2 times more money than the younger one. At the same time, the middle brother should receive more than the younger one, but less than the older one. How many ways are there to fulfill the will of the father, if each son must receive a whole number of ducats?

Answers

Three sons inherited 2,179 ducats from their father. The number of ways the father can bequeath the resources is

108 ways

How to find the number of ways of fulfilling the fathers wish

Information from the problem helped in generating the following equations

The father bequeathed the older brother 2 times more money than the younger one

let the youngest receive an amount equivalent to y

then the eldest will receive 2y

let the middle receive x

Using the sharing formula described we have

y + 2y + x = 2179

3y + x = 2179

the middle brother should receive more than the younger one, but less than the older one

x > y

x < 2y

plotting the equations on a graphing calculator and getting the solutions we have

(544.75, 544.75) and (871.6, 435.8)

y ranges from 435.8 to 544.75 using whole numbers

436 to 544

The number of ways

= 544 - 436

= 108 ways

the number of ways of sharing according to fathers will is 108

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Three sons inherited 2,179 ducats from their father. The father bequeathed the older brother 2 times

Find the required annual interest rate, to the nearest tenth of a percent, for $955 to grow to $1514 if interest is compounded monthly for 3 years.
A. 30.9%
B. 10.3%
C. 1.3%
D. 15.5%

Answers

Answer:

D

Step-by-step explanation:

\(A=P(1+\dfrac{r}{n})^{nt}\)

where A is the final amount of money, P is the initial amount of money input, r is the interest rate, n is the amount of times compounded per year, and t is the time in years.

\(1514=955(1+\dfrac{r}{12})^{(12)(3)}\)

\(1.585=(1+\dfrac{r}{12})^{36}\)

\(1.0128762=1+\dfrac{r}{12} \\\\\\0.0128762=\dfrac{r}{12} \\\\\\r\approx 0.155=15.5\%\)

Hope this helps!

the answer would be D because of the way it is set up in the problem on the screen it helped a lot of other people

what is volume of a trapezoid prism?

what is volume of a trapezoid prism?

Answers

Answer:

If the prism length is L, trapezoid base width B, trapezoid top width A, and trapezoid height H, then the volume of the prism is given by the four-variable formula: V(L, B, A, H) = LH(A + B)/2. In other words, multiply together the length, height, and average of A and B.

Step-by-step explanation:

a student has some $1 and $5 bills in his wallet he has a total of 12 bills that are worth $32 how many of each bill does he have​

Answers

Five $5 bills, and seven $1 bills :)

Solve the equation: log5 9 + log5 (x + 8) = log5 31

Answers

Step-by-step explanation:

Using the rules of logs

log5 (9) + log5(x+8) =  log (9 *(x+8)) = log (9x+72) and this equals  log5 (31)

   so  9x+72 = 31

           9x = -41

              x = -41/9 = -4.555

Matthew has $0.72. He wants to buy stickers that cost $0.08 each. How many stickers can he buy?​

Answers

9......
he can buy 9

Answer:

Matthew can buy 9 stickers.

Step-by-step explanation:

0.72 / 0.08 =

72 / 8 = 9

so he can buy 9 stickers

Plz mark as brainliest if correct! Have a nice day!!!

-Lil G

What inequality is graphed below?

What inequality is graphed below?

Answers

The Answer is a. X < 14
The correct answer is,

X<14 or A. :)

Frame zero, F0. is the fixed global frame. For each of
the cases below find T 1: 0
(a) F1 is rotated by an angle θ about zo.
(b) F1 is rotated by θ about xo.
(c) F1 is rotated by θ about yo.

Answers

(a) `T1:0 = [cos150 sin150 0 0; -sin150 cos150 0 0; 0 0 1 0; 0 0 0 1]`

(b) `T1:0 = [1 0 0 0; 0 cos150 sin150 0; 0 -sin150 cos150 0; 0 0 0 1]`

(c) `T1:0 = [cos150 0 -sin150 0; 0 1 0 0; sin150 0 cos150 0; 0 0 0 1]`

Given that Frame zero, F0 is the fixed global frame.

For each of the cases below find T1

Case (a)

F1 is rotated by an angle θ about zo.

Let O be the origin of the fixed frame F0, A be the origin of the frame F1 and α be the angle between the x-axis of the frame F0 and the projection of the x-axis of the frame F1 on the xy plane of the frame F0.

Let l, m, n be the direction cosines of the vector from O to A, expressed in F0.

The content-loaded frame zero F0 is the fixed global frame, which means that the vectors i, j, k representing the x, y, and z-axis of F0 are fixed and cannot be transformed.

Therefore, the transformation matrix T1:0

in this case is:

`T1:0 = [l1 m1 n1 0; l2 m2 n2 0; l3 m3 n3 0; 0 0 0 1]`

Case (b)

F1 is rotated by θ about xo.

Let β be the angle between the y-axis of F0 and the projection of the y-axis of F1 on the yz plane of F0.

Let γ be the angle between the z-axis of F0 and the projection of the z-axis of F1 on the zx plane of F0.

The transformation matrix T1:0

in this case is given by:

`T1:0 = [1 0 0 0; 0 cosθ sinθ 0; 0 -sinθ cosθ 0; 0 0 0 1]`

Case (c)

F1 is rotated by θ about yo.

Let β be the angle between the y-axis of F0 and the projection of the y-axis of F1 on the yz plane of F0.

Let γ be the angle between the z-axis of F0 and the projection of the z-axis of F1 on the zx plane of F0.

The transformation matrix T1:0

in this case is given by:

`T1:0 = [cosθ 0 -sinθ 0; 0 1 0 0; sinθ 0 cosθ 0; 0 0 0 1]`

Thus, the transformation matrix T1:0

for the three cases (a), (b), and (c) are given as follows:

(a) `T1:0 = [cosθ sinθ 0 0; -sinθ cosθ 0 0; 0 0 1 0; 0 0 0 1]`

(b) `T1:0 = [1 0 0 0; 0 cosθ sinθ 0; 0 -sinθ cosθ 0; 0 0 0 1]`

(c) `T1:0 = [cosθ 0 -sinθ 0; 0 1 0 0; sinθ 0 cosθ 0; 0 0 0 1]`

Given θ = 150,

T1:0 for the three cases are:

(a) `T1:0 = [cos150 sin150 0 0; -sin150 cos150 0 0; 0 0 1 0; 0 0 0 1]`

(b) `T1:0 = [1 0 0 0; 0 cos150 sin150 0; 0 -sin150 cos150 0; 0 0 0 1]`

(c) `T1:0 = [cos150 0 -sin150 0; 0 1 0 0; sin150 0 cos150 0; 0 0 0 1]`

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Lily earns $29.75 an hour. If she works 6 hours each day during the week and 4 hours a day
during the weekend, find her weekly wage.

Answers

Answer:

the answer is $1062.10

Step-by-step explanation:

explanation above

Lily earns $29.75 an hour. If she works 6 hours each day during the week and 4 hours a dayduring the

calculate the average height above the x-axis of a point in the region 0≤y≤x2, for 0≤x≤25.

Answers

The average height above the x-axis of a point in the region \(0\leq y\leq x^2\), for 0≤x≤25 using definite integral is 208.33 units.

To calculate the average height above the x-axis of a point in the region \(0\leq y\leq x^2\), for 0 ≤ x ≤ 25, we need to find the average value of y over this range.

The equation y = x² represents a parabola that opens upwards. To find the average height, we need to integrate the function y = x² over the given range and then divide by the length of the range.

Let's calculate it step by step:

Calculate the definite integral of y = x² with respect to x over the range 0 to 25:

∫[0,25] \(x^{2}\) dx = \([x^3/3]\) evaluated from 0 to 25

\(= (25^3/3) - (0^3/3)\\= (25^3/3)\\= 16666.67\)

Calculate the length of the range:

Length = 25 - 0 = 25

Divide the definite integral by the length of the range to find the average height:

\(Average height = (25^3/3) / 25\\= (25^2/3)\\= 208.33\)

Therefore, the average height above the x-axis of a point in the region \(0\leq y\leq x^2\), for 0 ≤ x ≤ 25, is approximately 208.33 units.

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Which of the following functions (there may be more than one) are solutions of the differential equation y' 4y' + 4y = et ? y = e%t + et Iy = et y = e2t + tet y = te2t +et y = e2t

Answers

Thus, the answer is y = e2t which is the solution of the given differential equation.

The given differential equation is, y' + 4y' + 4y = et .....(1)

To solve this differential equation, we will write the equation in the standard form of differential equation which is y' + p(t)y = f(t)Where p(t) and f(t) are functions of t.

We can see that p(t) = 4 and f(t) = etLet's find the integrating factor which is given by I.

F. = e∫p(t)dtI.

F. = e∫4dtI.

F. = e4t

So, we multiply both sides of the equation (1) by the I.F.

I.F. × y' + I.F. × 4y' + I.F. × 4y = I.F. × et(e4t)y' + 4(e4t)y = e4t × et(e4t)y' + 4(e4t)y

= e5t

So, the differential equation is reduced to this form which is y' + 4y = e(t+4t)

Using the integrating factor, e4t, we get(e4t)y' + 4(e4t)y = e4te5tNow, we integrate both sides with respect to t to get the general solutiony = (1/4) e(-4t) ∫ e(4t+5t) dty

= (1/4) e(-4t) ∫ e9t dty

= (1/4) e(-4t) (1/9) e9ty

= (1/36) ey

As we have obtained the general solution of the differential equation, now we can substitute the given functions into the general solution to check which of the given functions are solutions of the differential equation.

Functions y = e%t + et,

y = e2t + tet, and

y = te2t +et are not solutions of the given differential equation but the function y = e2t is the solution of the given differential equation because it satisfies the differential equation (1).

Therefore, the only function which is a solution of the differential equation y' + 4y' + 4y = et is y = e2t which is verified after substituting it into the general solution of the differential equation.

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(1 point) you have a spinner with red and blue regions. when you spin, it comes up blue 80 percent of the time. you do an experiment where you spin the spinner 120 times, and it comes up blue 101 times. (a) what proportion of spins came up blue in your sample?

Answers

84 percent of spins came up blue in your sample.

What are ratio and proportion?

A ratio is a comparison between two similar quantities in simplest form.

Proportions are of two types one is the direct proportion in which if one quantity is increased by a constant k the other quantity will also be increased by the same constant k and vice versa.

In the case of inverse proportion if one quantity is increased by a constant k the quantity will decrease by the same constant k and vice versa.

Given, You spin the spinner 120 times, and it comes up blue 101 times.

∴ The proportion of spins that came up blue in your sample is,

= (101/120).

= 0.84 Or 84% of the spins came up blue.

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2. 3x = 18 then the value of x is

Answers

Answer:

x=6

Step-by-step explanation:

(I don't know if you mean question 2 3x= 18 or 2 times 3x = 18)

2.3x = 18
3x = 18 / 2 = 9
x = 9/3 = 3

Or : x = 18/3 = 6

It costs $2.37 to paint one square foot of wall. You need to paint a wall that measures 864.5 square feet. It will cost to paint that wall. (Round your answer to the nearest hundredth)
a $204.88
b $2,048.87
c $2,048.86
d. $2,848.87 ​

Answers

Answer:

B- hope this helps:)

Step-by-step explanation:

The total cost to paint 864.5 square feet of wall is $2,048.87.

It is given that the cost to paint one square foot of wall is $2.37.

We are asked to find the total cost to paint 864.5 square feet of wall.

What are the different place values in a given number with a decimal point?

If we have a number that has a decimal point then we have two parts.

The whole number part and the fractional part.

After the decimal point, we will count the place value as tenths, hundredths, thousandths, and so on.

You can also see the given figure below.

We know that,

One square foot = $2.37.

Remember that Feet is the plural form of the foot.

We can write,

864.5 square feet = 864.5 x  one square foot

Because in 864.5 square feet we have 864.5 one square foot.

And since one square foot cost $2.37.

864.5 square feet will cost 864.5 x 2.37 dollars.

Now,

864.5 x 2.37 = $2048.865.

Rounding to the nearest hundredth.

6 is in the hundredth place so we will round 86 to 87 since the number in the thousandth place is greater than 4.

Thus the total cost to paint a wall of 864.5 square feet is $2,048.87.

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It costs $2.37 to paint one square foot of wall. You need to paint a wall that measures 864.5 square

Help please it’s emergency: I don’t understand how to do number 7

Help please its emergency: I dont understand how to do number 7

Answers

With a greater mean value , we can conclude that the sixth period class test was better than the second period .

Calculating the mean of each class

Second period class:

Mean = (55+70+6*75+6*80+2*85+3*90+95)/20

Mean = 1590/20 = 79.5

Sixth period class:

Mean = (65+3*75+5*80+6*85+3*90+2*95)/20

Mean = 1660/20 = 83

Therefore, From the mean values , we can infer that students performed better in test for the sixth period class than the second .

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A muzzle-loading rifle fires 22U bullets such that as they travel down the barel of the riffe their apeed is given by. v=(−5.00×10
2
)e
2
+(2.30×10
2
)t where v is in meters per second and t is in seconds. The acceleration of the bullet just an it leaves the barrel is zero, (a) Determine the acceleration (in m/t
2
) and posicon (in m) of the bullet as a function of time when the bullet is in the barrel. (Use the following as necestaryt t. Round all numencal coetficients to at lesth three signicant figures. Do not include units in your answers. Assume that the position of the bullet at t a 0 is zero.) a(t)=
3
m

? x(t)=
2
m

(c) Find the speed atwhich the builet leaves the barrel (in m/s) mese (d) What is the length of the baitel (in m)?

Answers

(a) The acceleration of the bullet in the barrel is given by \(a(t) = (10.00*10^2)e^{-2} + 2.30*10^2\).

(b) The position of the bullet in the barrel is given by \(x(t) = (-5.00*10^2)(-1/2)e^{-2} + (2.30*10^2)(1/2)t^2\).

(c) The speed at which the bullet leaves the barrel is \((-5.00*10^2)e^{-2} m/s.\)

(d) The length of the barrel is t meters, where \(t = e^{-2}\).

(a) To determine the acceleration of the bullet as a function of time when it is in the barrel, we differentiate the given velocity equation with respect to time:

\(v = (-5.00*10^2)e^{-2} + (2.30*10^2)t\)

Differentiating with respect to time:

\(a(t) = d(v)/dt = [(-5.00*10^2)e^{-2} + (2.30*10^2)t]' = 0 - 2(-5.00*10^2)e^{-2} + 2.30*10^2 = (10.00*10^2)e^{-2} + 2.30*10^2\)

Simplifying the expression:

\(a(t) = (10.00*10^2)e^{-2} + 2.30*10^2\)

Therefore, the acceleration of the bullet in the barrel is given by \(a(t) = (10.00*10^2)e^{-2} + 2.30*10^2.\)

(b) To determine the position of the bullet as a function of time when it is in the barrel, we integrate the given velocity equation with respect to time:

\(v = (-5.00*10^2)e^{-2} + (2.30*10^2)t\)

Integrating with respect to time:

\(x(t) = \int[(-5.00*10^2)e^{-2} + (2.30*10^2)t] dt = (-5.00*10^2)\int e^{-2} dt + (2.30*10^2)\int t dt\)

\(x(t) = (-5.00*10^2)(-1/2)e^{-2} + (2.30*10^2)(1/2)t^2 + C\)

Since the initial position of the bullet at t = 0 is zero, we have C = 0.

Therefore, the position of the bullet in the barrel is given by \(x(t) = (-5.00*10^2)(-1/2)e^{-2} + (2.30*10^2)(1/2)t^2.\)

(c) To find the speed at which the bullet leaves the barrel, we substitute the final time value of the barrel into the velocity equation:

\(v = (-5.00*10^2)e^{-2} + (2.30*10^2)t\)

Substituting t = 0:

\(v = (-5.00*10^2)e^{-2} + (2.30*10^2)(0) = (-5.00*10^2)e^{-2}\)

Therefore, the speed at which the bullet leaves the barrel is \((-5.00*10^2)e^{-2} m/s.\)

(d) The length of the barrel can be determined by finding the time it takes for the bullet to leave the barrel. Since the acceleration of the bullet just as it leaves the barrel is zero, we can set the acceleration equation to zero and solve for t:

\(a(t) = (10.00*10^2)e^{-2} + 2.30*10^2 = 0\)

\((10.00*10^2)e^{-2} = -2.30*10^2\)

\(e^{-2} = -2.30*10^2 / (10.00*10^2)\)

Using the natural logarithm to solve for e:

\(-2 = ln(-2.30*10^2 / (10.00*10^2))\)

Taking the inverse of the natural logarithm to solve for t:

\(t = e^{-2}\)

Therefore, the length of the barrel is t meters.

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IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.
Out of a randomly selected 2200 people from the population, how many of them
would have an IQ less than 115, to the nearest whole number?

Answers

Using the normal distribution, it is found that 1851 people would have an IQ less than 115.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\(\mu = 100, \sigma = 15\)

The proportion of IQ scores less than 115 is the p-value of Z when X = 115, hence:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{115 - 100}{15}\)

Z = 1

Z = 1 has a p-value of 0.8413.

Out of 2200 people:

0.8413 x 2200 = 1851.

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Answer:

1851

Step-by-step explanation:

if its a whole number than its 1851

pls help the last one was wrong

pls help the last one was wrong

Answers

Answer:

its 0

Step-by-step explanation:

6 squared plus 2 squared = 40 40/4=10 10-10=0

Answer: D

Step-by-step explanation:

classify each hypothetical setting as a binomial, poisson, or exponential distribution. binomial poisson answer bank exponential approximately 11 cars are sold every week at a car dealership. find the probability that the dealer will wait two days for the next car to sell. the mean number of fuses that blow in a particular building each year is five. find the probability that no fuses will be blown next year. the probability of a defective computer part is 0.05 at a particular factory. find the probability that there are 10 defective parts in 100 boxes. two percent of cats in the united states have feline leukemia. find the probability that nine out of 45 cats at an animal shelter have feline leukemia. on average, two babies are born with a health defect every hour at a local hospital. find the probability that two hours will go by without a baby being born with a health defect.

Answers

Binomial distributions are,

1) Find the probability that two 20- year-old homes out of 50 are without cracks in the foundation

4) Two percent of cats in the United States have feline leukemia. Find the probability that nine out of 45 cats at an animal shelter have feline leukemia.

5) In a standard deck of 52 cards, the probability of drawing a king is 0.08. Find the probability that four out of 10 people draw a king with replacement.

The Poisson distribution is

3) On average, airplanes take off every 20 minutes at a particular airport. Find the probability that the next airplane will take off less than or equal to 10 minutes after the previous airplane

The exponential distribution is

2) Approximately 11 cars are sold every week at a car dealership. Find the probability that the dealer will wait two days for the next car to sell.

The binomial distribution is used when there are a fixed number of independent trials, each with a binary outcome (success or failure). It is commonly used in situations where we want to count the number of successes out of a fixed number of trials.

1) Find the probability that two 20- year-old homes out of 50 are without cracks in the foundation

4) Two percent of cats in the United States have feline leukemia. Find the probability that nine out of 45 cats at an animal shelter have feline leukemia.

5) In a standard deck of 52 cards, the probability of drawing a king is 0.08. Find the probability that four out of 10 people draw a king with replacement.

The Poisson distribution is used to model the number of events occurring in a fixed interval of time or space. It is commonly used in situations where the number of events is rare, but the probability of each event is small.

3) On average, airplanes take off every 20 minutes at a particular airport. Find the probability that the next airplane will take off less than or equal to 10 minutes after the previous airplane

The exponential distribution is used to model the time between consecutive events in a Poisson process. It is commonly used in situations where we want to model the time between occurrences of rare events.

2) Approximately 11 cars are sold every week at a car dealership. Find the probability that the dealer will wait two days for the next car to sell.

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The given question is incomplete, the complete question is:

Classify each hypothetical setting as a binomial, Poisson, or exponential distribution. Binomial Poisson Exponential Answer Bank The mean number of cracks in the foundation of a 20-year-old home is six. 1) Find the probability that two 20- year-old homes out of 50 are without cracks in the foundation. 2) Approximately 11 cars are sold every week at a car dealership. Find the probability that the dealer will wait two days for the next car to sell. 3) On average, airplanes take off every 20 minutes at a particular airport. Find the probability that the next airplane will take off less than or equal to 10 minutes after the previous airplane. 4) Two percent of cats in the United States have feline leukemia. Find the probability that nine out of 45 cats at an animal shelter have feline leukemia. 5) In a standard deck of 52 cards, the probability of drawing a king is 0.08. Find the probability that four out of 10 people draw a king with replacement.

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