Answer:
y=2x-2
Step-by-step explanation:
y intercept is (0,-2) so that is b value. slope is 2 so that is your m value
A hypothesis test is to be performed for a population mean. Which of the following does the probability of a type II error not depend on?
options:
The significance level
The sample mean
The sample size
The true (population) mean
When a thesis test is being performed for a population mean, the probability of a type II error isn't dependent on the sample mean. Option B is the right answer.
A type II error occurs when a null thesis isn't rejected despite it being incorrect. It's worth noting that the threat of making a type II error is affected by several factors, including the sample size, the true population mean, the position of significance, and the variability of the data.
As a result, the larger the sample size, the lower the threat of making a type IIerror.The true population mean also has an impact on the liability of a type II error. As the difference between the true mean and the hypothecated mean grows, the threat of a type II error decreases.
The position of significance is also pivotal in determining the threat of a type II error. As the significance position increases, the threat of a type II error decreases.
So, the correct answer is B
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Which values are solutions to the inequality below? Check all that apply.
x^2<8
A. -2
B. 3
C. 4
D. 2.
Solve |2x - 5| = 4.
Answer:
x = - 0.5
\(x=-\frac{1}{2}\)
Step-by-step explanation:
2x + 5 = 4
2x + 5 - 5 = 4 - 5
2x = - 1
2x ÷ 2 = - 1 ÷ 2
x = - 0.5
A rectangle is 2 0 meter long and 2 3 meters wide. What is the area of the rectangle? Enter your answer in the box below.
Answer:
The answer is 460m²
Step-by-step explanation:
Area of rectangle =Length × Width
A=20×23
A=460m²
Answer:460
Step-by-step explanation: 20
x 23
_____
60
+400
Halona walks 1.93 kilometers to a neighbor’s house in 23 minutes. Assuming she walks at a constant speed, write a proportion that represents how many kilometers,y, Halona can walk in x minutes. Then solve your proportion for y.
Answer:
proportion: 1.93/23 = y/x
solve for y: y = x(0.083913)
Step-by-step explanation:
The required relationship of the proportionality is y = 0.08 x.
Given that,
In 23 minutes, Halona travels 1.93 kilometers to a neighbor's home. assuming she moves at a steady pace.
How many kilometers, y, Halona can walk in x minutes, expressed as a proportion. After that, find y using your percentage.
The relationship between two or more sets of values—whether they are directly proportional or inversely proportional to one another—is referred to as proportionality.
Here,
according to the question,
y ∝ x
y = kx
Where k is the constant of the proportionality,
at x = 23, y = 1.93
1.93 = 23 k
k = 1.93/23
k = 0.08
Put k in the proportionality equation,
y = 0.08k
Thus, the required relationship of the proportionality is y = 0.08 x.
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If z = 2x2 - 3y with u = x2 siny and v= 2y cosx, determine expressions for dz/du and dz/dv
The expressions for dz/du and dz/dv are as follows:
dz/du = 4x siny
dz/dv = -6y cosx
To find the expressions for dz/du and dz/dv, we need to differentiate the given function z = 2x^2 - 3y with respect to u and v, respectively.
1. dz/du:
Since u = x^2 siny, we can express z in terms of u by substituting x^2 siny for u in the original function:
z = 2u - 3y
Now, we differentiate z with respect to u while treating y as a constant:
dz/du = d/dx (2u - 3y)
= 2(d/dx (x^2 siny)) - 0 (since y is constant)
= 2(2x siny)
= 4x siny
Therefore, dz/du = 4x siny.
2. dz/dv:
Similarly, we express z in terms of v by substituting 2y cosx for v in the original function:
z = 2x^2 - 3v
Now, we differentiate z with respect to v while treating x as a constant:
dz/dv = d/dy (2x^2 - 3v)
= 0 (since x^2 is constant) - 3(d/dy (2y cosx))
= -6y cosx
Therefore, dz/dv = -6y cosx.
In summary, the expressions for dz/du and dz/dv are dz/du = 4x siny and dz/dv = -6y cosx, respectively.
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A and B are
independent events. P(A) = .6 and P(B) = .2. What is
P(B|A)?
Answer:
P(B|A) = 0.2 or 20%
Step-by-step explanation:
Here, we want to find the conditional probability.
Mathematically, the term P(B|A) = (P(B) * P(A))/P(B)
where P(A) =0.6 and P(B) = 0.2
Plugging these values, we have
P(B|A) = (0.6 * 0.2)/0.6 = 0.2 or simply 20%
-8-x= x - 4x
Can u help me know the answer please and I need to show my work
Answer:
x= -4
Step-by-step explanation:
-8 -x= x -4x
Simplify:
\( - 8 - x = - 3x\)
Bring all x terms to 1 side by adding x on both sides:
\( - 8 = - 3x + x\)
Simplify:
\( - 8 = - 2x \\ - 2x = 8\)
Divide both sides by -2:
\(x = \frac{8}{ - 2} \\ x = - 4\)
25 startlongdivisionsymbol 1,658 endlongdivisionsymbol to find the quotient, start by dividing into.
The required quotient would be \(66\frac{8}{25}\) or 66.32 which is determined by dividing 1,658 by any divisor 25.
Define Quotient?The result of dividing an integer by any so-called quotient divisor is referred to as the quotient. The divisor appears in the dividend a certain number of times.
Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.
Multiplication operation: Multiplies values on either side of the operator
For example \(12*2=24\)
Division operation: Divides left-hand operand by right-hand operand
For example \(\frac{4}{2} =2\)
Dividend is equal to 1,658
Divisor is equal to 25
Unit place value of 1658 is equal to 8.
25 is not a factor of 1658
Smallest number to 1658 divisible by 25 is 1650
Divide 1658 by 25 we get remainder
Dividend = ( Divisor × quotient) + remainder
1658 = 1650 + 8
1658 = ( 25 × 66 ) + 8
Remainder is equal to 8
Quotient is equal to 66
In decimal form
⇒ 1658 ÷ 25
Apply the Division operation, and we get
⇒ \(\frac{1658}{25}\)
⇒ 66.32
⇒ \(66\frac{8}{25}\)
Therefore,
The required quotient would be \(66\frac{8}{25}\) or 66.32 which is determined by dividing 1,658 by any divisor 25.
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Splitting investments. Joan had $3,000 to invest. She invested part of it in an investment paying 8% and the remainder in an investment paying 10%. If the total income on three investments was $290, than how much did she invest at each rate?
Answer:
Step-by-step explanation:
From the given information:
Let assume that the invested amount in the investment paying 8% interest is a
Now, since the total amount invested = $3000.
Then, the amount invested in the investment that will be paying 10% interest can be represented as:
= $(3000-a)
Income earned on $a that is being invested in 8% interest = $a × 8/100 = $0.08a
Income earned from $(3000-a) in the 10% investment is:
= $(3000-a)× 10/100
= $(300 - 0.1a)
Since total income of the two investment = $290;
Then;
0.08a + (300 - 0.1a) = 290
0.08a + 300 - 0.1a = 20-
300 - 0.02a = 290
-0.02a = -10
a = -10/-0.02
x = 500
Thus;
the amount invested in an investment paying 8% interest = $500
the amount invested in an investment paying 10% interest = $(3000 - 500) = $2500
Find the greatest
7/16٫ 3/8٫ 11/24٫ 10/21٫ 21/46
Write an equation in slope-intercept form of the line that passes through the given points. PLEASE HELLLPPPPPPPPP.....
The equation of the table in slope intercept form is y = - 5 / 2x - 1
How to write equation in slope intercept form?Linear equation can be represented in various form, such as standard form, point slope form and slope intercept form.
But the equation of the table below will be represented in slope intercept form.
The equation in slope intercept form can be represented as follows:
y = mx + b
where
m = slopeb = y-interceptTherefore, using (-4, 9)(-2, 4)
m = 4 - 9 / -2 + 4
m = - 5 / 2
Hence, let's find the y-intercept using (0, -1)
y = - 5 / 2x + b
-1 = - 5 / 2(0) + b
b = -1
Therefore, the equation is y = - 5 / 2x - 1
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A 6-lb bag of candy costs $9.48, and a 9-lb bag of the same type of candy costs $12.69. jada found the unit price, which is the constant of proportionality between cost and weight, for each bag of candy. what is the difference in the unit prices
The constant of proportionality between cost and weight for bag weight 6-lb is 1.58 and for other is 1.41. The difference in the unit prices of candies in bag is equals to the $0.17.
We have two bags of candies,
Weight of one bag of candy, w1 = 6 lb
Weight of second bag of candy, w2 = 9 lb
Cost of first bag of candies = $9.48
Cost of second bag of candies = $12.69
Division method : This method is used to distribute the things in equal parts. It is inverse of multiplication. So, as we know,
Cost of 6 lb candies in bag = $9.48
so, unit prices of first bag's candies = 9.48/6
= $1.58
So, the constant of proportionality between cost and weight of first bag = 1.58
Similarly, unit prices of second bag's candies
= 12.69/9 = $1.41
The constant of proportionality between cost and weight of first bag = 1.41
The difference between the unit prices of candies in both bags = $1.58 - $1.41 = $0.17..
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in a study, of adults questioned reported that their health was excellent. a researcher wishes to study the health of people living close to a nuclear power plant. among adults randomly selected from this area, only reported that their health was excellent. find the probability that when adults are randomly selected, or fewer are in excellent health.
The probability of randomly selecting or fewer adults having excellent health is:P(X≤) = P(X=0) + P(X=1) + P(X=2) + … + P(X=) + P(X=)= (nC0) p0(1−p) n−0+ (nC1) p1(1−p) n−1+ (nC2) p2(1−p) n−2+ …+ (nC) p(1−p) n−= ∑ P(X≤) , where x=≤nCalculate the value of P(X≤)
The given data says that of adults questioned reported that their health was excellent and a researcher wishes to study the health of people living close to a nuclear power plant. Among adults randomly selected from this area, only reported that their health was excellent.The total adults who participated in the study are not given, so we cannot calculate the probability of randomly selecting adults from the given area. But, we can find the probability of adults who have excellent health from this area that is less than or equal to .To find the probability, we can use binomial distribution theory.
A binomial distribution is a discrete probability distribution of the number of successes in a sequence of independent trials with a given probability of success in each trial.Mathematically, a binomial distribution is represented by:P(x) = (nCx) px(1−p) n−xHere, n is the number of trials, p is the probability of success, and x is the number of successes.Using the above formula, we can find the probability of randomly selecting x adults having excellent health from n adults who participated in the study.
The probability of randomly selecting or fewer adults having excellent health is given by the sum of probabilities of randomly selecting 0, 1, 2, … , , , adult(s) having excellent health.P(X≤x)= P(X=0) + P(X=1) + P(X=2) + … + P(X=) + P(X=)Therefore, the probability of randomly selecting or fewer adults having excellent health is:P(X≤) = P(X=0) + P(X=1) + P(X=2) + … + P(X=) + P(X=)= (nC0) p0(1−p) n−0+ (nC1) p1(1−p) n−1+ (nC2) p2(1−p) n−2+ …+ (nC) p(1−p) n−= ∑ P(X≤) , where x=≤nCalculate the value of P(X≤) using the given information.
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Find the limit. 1 lim x-5+ (x-5)² O A) -[infinity]0 OB) -1 O C) O OD) [infinity]o 8
The limit as x approaches 5 from the right (x → 5+) of the expression (x - 5)² is 0.
To find the limit of the expression as x approaches 5 from the right (x → 5+), we can directly substitute the value into the expression.
The given expression is (x - 5)².
So, let's substitute x = 5 into the expression:
lim(x → 5+) (x - 5)² = (5 - 5)² = 0² = 0
This means that as x approaches 5 from the right, the expression (x - 5)² represents the square of the distance between x and 5. As x gets closer to 5, the distance between them decreases, and the square of that distance approaches 0.
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This is for
sa afaa42
Answer:
1-J
2-A
3-E
4-B
5-H
6-C
7-I
8-F
9-D
10-G
DUE FRIDAY WELL WRITTEN ANSWERS ONLY !!!!!!!HELP
The value of tan(3π/4) is -1. How does the value of tan(3π/4 – π) compare? Explain your reasoning.
Answer:
The value of tan(3π/4) is indeed -1.
Now, to evaluate tan(3π/4 - π), we can use the following trigonometric identity:
tan(a - b) = (tan(a) - tan(b)) / (1 + tan(a)*tan(b))
Applying this identity to the expression tan(3π/4 - π), we get:
tan(3π/4 - π) = (tan(3π/4) - tan(π)) / (1 + tan(3π/4)*tan(π))
Substituting the values of tan(3π/4) = -1 and tan(π) = 0, we get:
tan(3π/4 - π) = (-1 - 0) / (1 + (-1)*0) = -1
So the value of tan(3π/4 - π) is also -1, which is the same as the value of tan(3π/4).
In other words, the value of tan(3π/4 - π) is equal to the value of tan(3π/4) because π is equal to 180 degrees, which is a full rotation. Subtracting a full rotation from an angle simply results in an equivalent angle in the opposite direction. Thus, the values of tangent for both angles remain the same.
City A has a travel demand function q=3.0×106−4000t, and road performance function t1=30+6×10−6q, where t is in minutes. There is a proposal to expand the road such that the road performance function will become t2=20+3×10−6q, with a construction cost of $9.6×107 Q9.1: Given that the value of time is $1.5 per minute, justify the proposal. Q9.2: To what value of the construction cost would the proposal become justified?
Q9.1: To justify the proposal, we need to compare the benefits of the road expansion (in terms of reduced travel time) with its costs. The value of time represents the monetary value individuals place on their time spent traveling. In this case, the value of time is $1.5 per minute.
First, let's calculate the reduction in travel time resulting from the road expansion. We compare the two road performance functions: t1 = 30 + 6×10−6q and t2 = 20 + 3×10−6q. By subtracting t2 from t1, we can determine the time savings: Δt = t1 - t2 = (30 + 6×10−6q) - (20 + 3×10−6q) = 10 + 3×10−6q Next, we multiply the time savings by the number of trips (q) to obtain the total time savings: Total Time Savings = Δt × q = (10 + 3×10−6q) × q Now, we can determine the monetary value of the time savings by multiplying the total time savings by the value of time ($1.5 per minute): Monetary Value of Time Savings = Total Time Savings × Value of Time
= (10 + 3×10−6q) × q × $1.5 If the monetary value of the time savings exceeds the construction cost of $9.6×107, then the proposal is justified. Q9.2: To determine the construction cost at which the proposal becomes justified, we set the monetary value of the time savings equal to the construction cost and solve for q: (10 + 3×10−6q) × q × $1.5 = $9.6×107 By solving this equation for q, we can find the corresponding construction cost at which the proposal becomes justified.
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One serving of a cereal is 3/4 cup. Each box of cereal has about 9 cups of cereal and costs $3.80. Is the price per serving greater than $0.50? Complete the explanation.
Answer:
The price per serving is $0.315, therefore, it's less than $0.5
Step-by-step explanation:
In order to calculate the price per serving, we can first calculate the price per cup, this is done by dividing the total value of the box by the number of cups it can serve:
\(price_{cup} = \frac{3.8}{9} = 0.42\)
Since each serving is \(\frac{3}{4}\) of a cup, then it's price has the same proportion and is given by:
\(price_{serving} = \frac{3}{4}*0.42 = 0.315\)
The price per serving is $0.315, therefore, it's less than $0.5
WILL GIVE BRIANLIST OT BEST ANSWER
Determine if the sequence is geometric. If it is, find the common ratio, the term named in the problem, the explicit-formula, and the three terms in the sequence after the last one given.
Show work
Find f(10)
7) -4, -12, -36, -108, ...
The common ratio is equal to 3.
The tenth term of this geometric sequence is -78,732.
The explicit-formula of this geometric sequence is aₙ = -4(3)ⁿ⁻¹.
The three terms in the sequence after the last one given are -324, -972, and -2916.
How to calculate the nth term of a geometric sequence?In Mathematics, the nth term of a geometric sequence can be calculated by using this mathematical expression:
aₙ = a₁rⁿ⁻¹
Where:
aₙ represents the nth term of a geometric sequence.r represents the common ratio.a₁ represents the first term of a geometric sequence.Next, we would determine the common ratio as follows;
Common ratio, r = a₂/a₁
Common ratio, r = -12/-4
Common ratio, r = 3.
For the explicit formula, we have:
aₙ = a₁rⁿ⁻¹ = -4(3)ⁿ⁻¹
Now, we can determine three terms in the sequence after the last one given;
a₅ = a₁r⁵⁻¹ = -4(3)⁴ = -324.
a₆ = a₁r⁶⁻¹ = -4(3)⁵ = -972.
a₇ = a₁r⁷⁻¹ = -4(3)⁶ = -2916.
f(10) = a₁₀ = a₁r¹⁰⁻¹ = -4(3)⁹ = -78,732.
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Bob bought 40 gumboils from a quarter machine. The number of each flavor he got is shown in the table. If there are 140 gumboils remaining in the machine, what is a reasonable prediction for the number of cola flavored gumboils left?
Flavors: Amount:
Grape 4
Cherry 12
Cola 16
Orange 8
Answer:
56 cola flavored gumboils
Step-by-step explanation:
Bob's 40 count of gumballs has 16 cola gumballs
Therefore the probability of a gumball being cola based on the sample size of Bob's purchase = 16/40 = 2/5
There are 140 gumballs left in the machine so we can expect that, on an average, 2/5 of them should be cola gumballs
So number of cola gumballs left is expected to be 2/5 x 140 = 56
This is only a prediction based on Bob's sample of 40 cola gumballs
A circle with a radius of 6 feet has a central angle of 120° in terms of π what is the area of the sector?
-7- 2x² - 6 = −2x² + 1
First Step:
13- 2x² = 2x² + 1
What property is this
Answer:
Combine like terms, although the provided answer is missing a "-" sign in front of the "13."
Step-by-step explanation:
Combine like terms. The -7 and -6 can be added to produce -13.
The correct result is -13 - 2x^2 = -2x^2 + 1 [Not _13- 2x² = _2x² + 1
Perhpas the initial equation is written incorrectly(?)
In the past, the output of a process had a mean of 2.050 and a standard deviation of 0.020 liters. If a current sample of output had these values {2.038 2.054 2.053 2.055 2.059 2.059 2.009 2.042 2.053 2.047}, would that indicate that the process is still "in order" (as opposed to being "out of order")? What if the sample was {2.022 1.997 2.044 2.044 2.032 2.045 2.045 2.047 2.030 2.044}?
For the first sample {2.038 2.054 2.053 2.055 2.059 2.059 2.009 2.042 2.053 2.047}, the process is still "in order," while for the second sample {2.022 1.997 2.044 2.044 2.032 2.045 2.045 2.047 2.030 2.044}, the process might be "out of order."
To determine whether the process is still "in order" or "out of order," we can compare the current sample of output to the known mean and standard deviation of the process.
For the first sample {2.038 2.054 2.053 2.055 2.059 2.059 2.009 2.042 2.053 2.047}:
Calculate the sample mean by summing up all the values in the sample and dividing by the number of values (n = 10):
Sample mean = (2.038 + 2.054 + 2.053 + 2.055 + 2.059 + 2.059 + 2.009 + 2.042 + 2.053 + 2.047) / 10 = 2.048.
Compare the sample mean to the known process mean (2.050):
The sample mean (2.048) is very close to the process mean (2.050), indicating that the process is still "in order."
Calculate the sample standard deviation using the formula:
Sample standard deviation = sqrt(sum((x - mean)^2) / (n - 1))
Using the formula with the sample values, we find the sample standard deviation to be approximately 0.019 liters.
Compare the sample standard deviation to the known process standard deviation (0.020):
The sample standard deviation (0.019) is very close to the process standard deviation (0.020), further supporting that the process is still "in order."
For the second sample {2.022 1.997 2.044 2.044 2.032 2.045 2.045 2.047 2.030 2.044}:
Calculate the sample mean:
Sample mean = (2.022 + 1.997 + 2.044 + 2.044 + 2.032 + 2.045 + 2.045 + 2.047 + 2.030 + 2.044) / 10 ≈ 2.034
Compare the sample mean to the process mean (2.050):
The sample mean (2.034) is noticeably different from the process mean (2.050), indicating that the process might be "out of order."
Calculate the sample standard deviation:
The sample standard deviation is approximately 0.019 liters.
Compare the sample standard deviation to the process standard deviation (0.020):
The sample standard deviation (0.019) is similar to the process standard deviation (0.020), suggesting that the process is still "in order" in terms of variation.
In summary, for the first sample, the process is still "in order" as both the sample mean and sample standard deviation are close to the known process values.
However, for the second sample, the difference in the sample mean suggests that the process might be "out of order," even though the sample standard deviation remains within an acceptable range.
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Please help me with this anyone 15 pts
Answer:
y = 3/8x
Step-by-step explanation:
You want a line through point (0, 0) parallel to y = 3/8x +3.
Slope-intercept formThe given equation is in slope-intercept form:
y = mx + b
It has m=3/8 and b = 3.
The line you want will have the same slope. The given point is the origin, corresponding to a y-intercept of 0.
y = 3/8x + 0
y = 3/8x
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One customer is chosen at random for a prize giveaway. What is the probability that the customer is at least 20 but no older than 50
Suppose that a special type of bean only grows on a 20 square mile plot of land outside of Springfield, OR. This plot of land is currently split evenly between you and another farmer (the market is a duopoly). There is no opportunity to collude with this other farmer and you will compete on price. Additionally, we will assume that the beans that are grown on your plot of land are identical to those grown on the other farmer's plot of land.
Part A) Based on the description above and what you have learned from lecture, what will your profit be in this market for beans? Explain your answer.
Part B) Under price competition, what is required for a firm to be able to earn positive profits? Apply this answer to the situation above to come up with a way that you could earn positive profits by growing these beans on your land.
Part A) Your profit in this market for beans will depend on the market equilibrium price and your production costs. The specific profit amount cannot be determined without knowing the market price and your production costs.
Part B) To earn positive profits under price competition, you need to have production costs lower than the market price. By reducing your production costs through various strategies, you can increase your chances of earning positive profits in the duopoly market for beans.
Let us discuss in a detailed way:
Part A) Your profit in this market for beans will depend on the market equilibrium price and your production costs. As a duopoly, you and the other farmer will compete on price, aiming to maximize your individual profits.
In a competitive market, price tends to be driven down to the marginal cost of production. If both you and the other farmer have identical production costs, and the market is perfectly competitive, the price of the beans will likely settle at the marginal cost of production. In this case, since you share the land equally, your 50% share of the 20 square mile plot would be 10 square miles.
To determine your profit, you need to consider your production costs and the price at which you can sell your beans. If the market price equals your production cost, your profit would be zero. If the market price is higher than your production cost, you will earn positive profits, and if it is lower, you will incur losses.
Part B) In order to earn positive profits under price competition, a firm must have a production cost that is lower than the market price. Applying this to the situation above, you can earn positive profits by growing these beans on your land if your production cost is lower than the market price.
To achieve this, you could focus on reducing your production costs through various means such as improving farming techniques, using more efficient equipment, or negotiating better deals for inputs like fertilizers and pesticides. By lowering your production costs, you can maintain a competitive advantage and potentially earn positive profits even if the market price is relatively low.
In summary, your profit in this market for beans will depend on the market equilibrium price and your production costs. To earn positive profits, you need to ensure that your production costs are lower than the market price. By focusing on cost reduction strategies, you can increase your chances of earning positive profits in the duopoly market for beans.
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What is the value of x?
Triangle B C D. Angle B is 91 degrees, angle C is 33 degrees, and angle D is x degrees.
56°
66°
124°
236°
Answer:
56°
Step-by-step explanation:
The interior angles of a triangle add up to 180.
You would first set up the following problem:
91 + 33 + x = 180
You would now subtract 91 from both sides.
33 + x = 89
You would now subtract 33 from both sides.
x = 56
The value of x is 56 degrees.
Angle of triangle D is 56 degrees.
What is a triangle?"A triangle is a simple closed curved made of three segments. A triangle has three sides and three angles, and all three sides and angles are called six elements of the triangle."
We have
Angle sum property of a triangle = \(180^{0}\)
<B + <C + <D = \(180^{0}\)
⇒ \(91^{0}+33^{0} +x^{0}=180^{0}\)
⇒ \(x^{0}=180^{0}-91^{0}-33^{0}\)
⇒ \(x^{0}=56^{0}\)
The value of x is 56 degrees.
Hence, angle of triangle D is 56 degrees.
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n vancouver, british columbia, the probability of rain during a winter day is 0.58, for a spring day is 0.38, for a summer day is 0.25, and for a fall day is 447 0.53. each of these seasons lasts one quarter of the year. a. what is the probability of rain on a randomly chosen day in vancouver? b. if you were told that on a particular day it was raining in vancouver, what would be the probability that this day would be a winter day?
If it is raining in Vancouver, the probability that it is a winter day is approximately 0.133 or 13.3%.
a. To find the probability of rain on a randomly chosen day in Vancouver, we need to consider the probabilities of rain in each season and their respective durations.
Given:
Probability of rain in winter = 0.58
Probability of rain in spring = 0.38
Probability of rain in summer = 0.25
Probability of rain in fall = 0.53
Since each season lasts one quarter of the year, we can calculate the overall probability of rain by taking the weighted average of the probabilities:
P(rain) = (P(rain in winter) * P(winter) + P(rain in spring) * P(spring) + P(rain in summer) * P(summer) + P(rain in fall) * P(fall))
P(rain) = (0.58 * 0.25 + 0.38 * 0.25 + 0.25 * 0.25 + 0.53 * 0.25)
P(rain) = 0.145 + 0.095 + 0.0625 + 0.1325
P(rain) = 0.435
Therefore, the probability of rain on a randomly chosen day in Vancouver is 0.435 or 43.5%.
b. To find the probability that a rainy day in Vancouver is a winter day, we can use Bayes' theorem.
Let:
A = Event of it being a winter day
B = Event of it being a rainy day
We need to find P(A|B), the probability of it being a winter day given that it is raining. According to Bayes' theorem:
\(P(A|B) =\frac{ (P(B|A) * P(A))}{P(B)}\)
We are given:
P(B|A) = Probability of rain on a winter day = 0.58 (from the given data)
P(A) = Probability of a winter day = 1/4 (since each season lasts one quarter of the year)
P(B) = Probability of rain = 0.435 (from part a)
Substituting the values into the equation, we have:
\(P(A|B) = \frac{(0.58 * 1/4)}{ 0.435}\)
\(P(A|B) =0.133333\)
Therefore, if it is raining in Vancouver, the probability that it is a winter day is approximately 0.133 or 13.3%.
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Which verbal expression best represents the algebraic expression 3n -4
Answer:
Four less than three times a number
Step-by-step explanation: