would you say the rate if cell growth is increasing or decreasing explain.​

CO2 contains one carbon atom and two oxygen atoms.

C stands for carbon

O for oxygen

Answer:

true

Explanation:

Answer: True

Explanation:

Answer:

=(220^2 +150^2)

/

put this on a square root

for you to get 266.2705391

round it to a whole number =266km/h

Explanation:

p

Answer:

(1) The relationship between the altitude height, 'h', and the orbital speed, \(v_{orbit}\), of the satellite is an inverse relationship

\(v_{orbit}\) = 1/(h + R)

(2) The height of the satellite, is approximately 24,442 meters

(3) Please find attached the drawing showing the two lines that indicate the direction of the gravitational force on the satellites created with Microsoft Visio

Explanation:

(1) From the given data table, as the altitude increases, the orbital velocity decreases, therefore, the relationship between altitude, 'h', and orbital velocity, '\(v_{orbit}\)', is an inverse relationship which can be expressed as follows;

\(v_{orbit} = \sqrt{\dfrac{G \cdot M}{r} }\)

Where;

G = The universal gravitational constant

M = The mass of the Earth, or planet about which the satellite orbits

r = The distance between the center of the planet and the satellite = h + R

R = The radius of the planet

When \(v_{orbit}\) = 27,500, h = r - R = 1000

We have;

\(v_{orbit}\)² ∝ 1/r

\(v_{orbit}\)² = k/r = k/(R+ h)

When, \(v_{orbit}\)² = 27,500² = 756,250,000

r = h + R = 1000 + R

∴ 756,250,000 = k/(1000 + R)

(1,000 + R) × 756,250,000  = k

When, \(v_{orbit}\)² = 18,000² = 324,000,000

r = h + R = 10,000 + R

∴ 324,000,000 = k/(10,000 + R)

324,000,000 = ((1,000 + R) × 756,250,000)/(10,000 + R)

∴ 324,000,000×(10,000 + R) = (1,000 + R) × 756,250,000

R × (756,250,000 - 324,000,000) = 324,000,000×10,000 - 1,000 × 756,250,000

R = (324,000,000×10,000 - 1,000 × 756,250,000)/(756,250,000 - 324,000,000) = 5746.09600925

R = 5,746.09600925

k = (1,000 + R) × 756,250,000  = (1,000 + 5,746.09600925) × 756,250,000 = 5.1017351 × 10¹²

k = 5.1017351 × 10¹²

(2) When, \(v_{orbit}\) = 13,000 m/s, we have;

13,000² = 5.1017351 × 10¹²/(5,746.09600925 + h)

∴ 5,746.09600925 + h = 5.1017351 × 10^(12)/(13,000²) = 30187.7816568

h = 30187.7816568 - 5,746.09600925 = 24,441.6856476

The height of the satellite, h ≈ 24,442 meters

(3) Please find attached the drawing showing the two lines indicating the direction of the force of gravity exerts on the satellites created with Microsoft Visio.

The resultant of the two given vectors is 346.4 units.

The resultant of the three vectors is the sum of all the three vectors acting together. The resultant vector is the single vector that will represent all the three vectors in terms of magnitude and direction.

The sum of the vectors in x-direction;

Vx = V cosθ

where;

for 200 units, θ = 0⁰ (above the horizontal)

for 400 units, θ = 60⁰ (above the horizontal)

Vx = 200 cos(0) - 400 cos(60)

Vx = 0

The sum of the vectors in y-direction;

Vy = 200 sin(0) + 400 sin(60)

Vy = 346.4 units

The resultant vector is calculated as;

V = √(Vx² + Vy²)

V = √(0² + 346.4²)

V = 346.4 units

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Answer:

V= 125volts

Explanation:

R =25ohms

I = 5 amp

V = ?

t = 36seconds

V = IR

V = 5× 25

V= 125volts

Q = It

Q = 5×36

Q = 180 coulombs

Q is the amount of charge.

Answer:

its most definitely c. trust me

Explanation:

The angular magnification of this lens if the image is viewed by a relaxed eye with a near point of 25 cm is 0.056.

The given values are: The focal length of a converging lens is 10 cm and the near point of the relaxed eye is 25 cm. To determine the angular magnification of this lens if the image is viewed by a relaxed eye with a near point of 25 cm, we need to use the formula given below:Angular magnification, m = (-) v / uwhere v = the distance of the image from the eyeand u = the distance of the object from the eye

The near point of the relaxed eye is 25 cm, so the distance of the object from the eye, u = 25 cm.Using the formula of the lens equation, we can find the value of v:1/f = 1/v - 1/u1/10 = 1/v - 1/25v = 1/10 + 1/25v = (5 + 2) / 50v = 7/50 cmNow we can substitute the values of u and v to calculate the angular magnification:m = (-) v / um = (-) (7/50) / 25m = (-) 7 / 125m = -0.056 or 0.056 (taking magnitudes)

Therefore, the angular magnification of this lens if the image is viewed by a relaxed eye with a near point of 25 cm is 0.056.

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Answer:

Josie's ball faster than T

Explanation:

\(speed : \)

\(speed : U = \frac{(90 \times 1000) \: m}{(1 \times 3600) \: s} \\ = 25 \: m {s}^{ - 1} \\ from \: third \: equation \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {25}^{2} \times (2 \times - 0.5 \times S) \\ 625 = S \\ S = 625 \: m\)

Answer:

8.45m/s = recoil speed

Explanation:

Momentum = mass • velocity

9.8kg • 88.03m/s = 102.1kg • recoil speed

862.694kg•m/s = 102.1kg • recoil speed

divide both sides by 102.1kg

8.45m/s = recoil speed

The arrow leaves the bow at a speed of 40.47 m/s.

When the arrow is released from its bow, the arrow will move and accelerate. Newton's second law of motion applies to the arrow. The formula F = ma

\(a \:=\: \frac{F}{m}\)

\(a \:=\: \frac{89.0}{0.0850}\)

a = 1,047.059 m/s²

When the object has acceleration, the object will move in a non-uniform motion. The formula

v² = u² + 2ad

v² = 0² + (2×1,047.059×0.782)

v² = 1,637.6

\(v_t \:=\: \sqrt{1,637.6}\)

\(v_t\) = 40.47 m/s

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Explanation:

mass=50g

velocity=42cm/s

Kinetic energy

As we know that

\({\boxed{\sf kinetic\:energy={\dfrac {1}{2}}mv^2}}\)

\({:}\longrightarrow\)\(\sf k.v={\dfrac {1}{{\cancel{2}}}}\times 50\times {\cancel{42}}^2 \)

\({:}\longrightarrow\)\(\sf k.v=50\times 21^2 \)

\({:}\longrightarrow\)\(\sf k.v=50×441 \)

\({:}\longrightarrow\)\(\sf k.v=22050MJ \)

\(\therefore\)\({\underline{\boxed{\bf Kinetic\:energy=22Joule}}}\)

The feature that is true of both solar and wind power is (b) Both power sources produce no greenhouse gas emissions during normal operation.

This makes them a more environmentally friendly alternative to traditional fossil fuels, which emit carbon dioxide (CO2) and other harmful gases during combustion.

However, the other options are not completely accurate. Solar and wind power can be intermittent, but this does not necessarily mean that they require a backup energy source. Energy storage technologies, such as batteries or pumped hydro storage, can be used to store excess energy generated during times of high production and release it during times of low production.

Furthermore, while solar and wind power currently supply a small fraction of global energy demand, it is important to note that their usage is increasing rapidly. In fact, renewable energy sources, including solar and wind power, are projected to be the fastest-growing energy source over the next few decades.

In conclusion, solar and wind power's most significant shared feature is their ability to operate without producing greenhouse gas emissions. While they do have other characteristics that are sometimes associated with them, these features are not always completely accurate and may not apply in every circumstance.

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Answer:Joe's velocity leaving the ground is 1.00 m/s.

Explanation: The velocity of Joe immediately after leaving the ground can be calculated using the formula v = at, where a is the acceleration and t is the time. Joe's acceleration can be found using the equation F = ma, where F is the net force and m is the mass.So, Joe's acceleration can be calculated as a = F/m = 100N / 90kg = 1.11 m/s^2.Then, using v = at, we can calculate Joe's velocity as v = 1.11 m/s^2 x 0.9 s = 1.00 m/s. Therefore, Joe's velocity immediately after leaving the ground is 1.00 m/s.

Answer:

My arms are doing a negative work

Explanation:

When you set something on the ground, the displacement of the object set towards the ground is in the downward direction. which means that, in this case, there is a downward displacement.

As the object is set on the ground, the force exerted by the arms on the object acts in the upward direction.

Summarily, direction of force is upwards while the direction of displacement is downwards.

Since the force and displacement act in opposite direction, a negative work is said to be done.

Answer:

The answer is D because when the faults move that is the tectonic plates moving. So earth quakes will be forming when the fault moves.

Explanation:

Answer:

See the answers below

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f}=v_{o}+a*t\)

where:

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

First case

Vf = 6 [m/s]

Vo = 2 [m/s]

t = 2 [s]

\(6=2+a*2\\4=2*a\\a=2[m/s^{2} ]\)

Second case

Vf = 25 [m/s]

Vo = 5 [m/s]

a = 2 [m/s²]

\(25=5+2*t\\t = 10 [s]\)

Third case

Vo =4 [m/s]

a = 10 [m/s²]

t = 2 [s]

\(v_{f}=4+10*2\\v_{f}=24 [m/s]\)

Fourth Case

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

\(v_{f}=5+8*10\\v_{f}=85 [m/s]\)

Fifth case

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

\(8=v_{o}+4*2\\v_{0}=8-8\\v_{o}=0\)

Force of gravity = mg = 8.35 * 9.8 = 81.83 N

normal force (N) = 81.83 N

force of friction =   30.69 N

Applied force = 119.2 N

net force = 88.51 N

given

mass = 8.35 kg

acceleration = 10.6 \(m/s^{2}\)

coefficient of friction (mu) = 0.375

force of gravity = mg = 8.35 * 9.8 = 81.83 N

normal force (N) = 81.83 N ( as mg = N )

force of friction = mu * normal = 0.375 * 81.83 = 30.69 N

F net = 0

applied force - force of friction = mass * acceleration

F - fr = ma

F = ma + fr

  = 8.35 * 10.6 + 30.69

  = 119.2 N

net force = F - fr = ma = 8.35 *  10.6

               = 88.51 N

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Option A: Among the elements listed, the one that, when doping a matrix of germanium, does not result in an n-type semiconductor is Bi (Bismuth).

Bismuth is not commonly used as a dopant for creating an n-type semiconductor in germanium. However, it can be used as a dopant for creating a p-type semiconductor. The other elements listed, At (Astatine), Ga (Gallium), Sb (Antimony), and P (Phosphorus), can be used as dopants to create an n-type semiconductor when added to a germanium matrix.

In both N-type and P-type semiconductors, the doping process intentionally introduces impurities into the semiconductor material to modify its electrical properties and allow for the controlled flow of electric current. The combination and interaction of N-type and P-type semiconductors form the basis for various semiconductor devices, such as diodes, transistors, and integrated circuits.

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Correct question:

Among the elements below, mark the one that, when doping a matrix of germanium, does not result in an n-type semiconductor.

A. Bi

B. At

C. Ga

D. Sb

E. P

Answer:

b.positive and decreasing in magnitude.

Explanation:

The kinematics of a body can be calculated by means of the following expression.

\(v_{f}=v_{o}-g*t\)

where:

vf = final velocity [m/s]

vo = initial velocity = 40 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

As we can see from the above equation, the final velocity of a body decreases its initial velocity as time increases. That is, as the body rises, the velocity decreases.

Answer:

A

Explanation:

A conductor works by allowing electrons to move through it with relative ease. In metals, this movement is facilitated by the structure of the material. Metals consist of a lattice of atoms in which the outermost electrons are not tightly bound to any particular atom. Instead, they are shared by all the atoms in the lattice and are free to move through the material. This allows electricity to flow freely through the metal, making it a good conductor.

Answer:

don't know it is very complicated question

Spiral galaxies are classified based on spiral arm tightness, bulge size, and amount of gas and dust present. This allows astronomers to categorize them into subtypes such as Sa, Sb, and Sc.

The classification of spiral galaxies is based on three properties:

1. Spiral arm tightness: This refers to how tightly wound the spiral arms are around the galaxy's center. Galaxies with more tightly wound arms are classified as "Sa," while those with more loosely wound arms are classified as "Sc."

2. Bulge size: The central bulge of a spiral galaxy can vary in size. Larger bulges are typically found in early-type spiral galaxies (such as Sa), while smaller bulges are found in late-type spiral galaxies (like Sc).

3. Amount of gas and dust: The presence and distribution of gas and dust within a spiral galaxy also play a role in its classification. Early-type spiral galaxies generally have less gas and dust compared to late-type spiral galaxies.

By considering these three properties, astronomers can classify spiral galaxies into various subtypes (such as Sa, Sb, and Sc) within the broader spiral galaxy category.

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The lighter block will also accelerate to the right with an acceleration of -0.82 m/s².

(a) μ = 0

The heavier block will accelerate to the right with an acceleration of:

a = F / m = k x / m = (3.70 N/m) (0.0864 m) / 0.261 kg = 1.22 m/s²

The lighter block will also accelerate to the right with an acceleration of 1.22 m/s².

(b) μ = 0.110

The heavier block will accelerate to the right with an acceleration of:

a = F - μk / m = k x / m - μk / m = (3.70 N/m) (0.0864 m) / 0.261 kg - (0.110)(0.261 kg)(9.80 m/s²) = 0.68 m/s²

The lighter block will not accelerate because the force of friction is greater than the force of the spring.

(c) μ = 0.480

The heavier block will accelerate to the right with an acceleration of:

a = F - μk / m = k x / m - μk / m = (3.70 N/m)(0.0864 m) / 0.261 kg - (0.480)(0.261 kg) (9.80 m/s²) = -0.82 m/s²

Therefore, the lighter block will also accelerate to the right with an acceleration of -0.82 m/s².

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Answer:

Magnitude is 2691.33m 5.32° North of East

Explanation:

The plane is flying directly east so the only component is the x component ie + 135 m/s

The wind acceleration is directly northeast. That means 45° N relative to the x-axis(which is the same as saying 45° E relative to the y-axis)

Therefore there are two components to the acceleration due to the wind

The y or North component of acceleration  is 2.18 x sin45°

The x or East component of acceleration is 2.18 x cos 45°

The displacement is given by the formula

s = ut + (1/2)at² where a is the acceleration, t is the time, u = initial velocity and v the final velocity

Substituting values for t= 18s, u = 0, v = 135 m/s and a = 2.18 cos 45° we get

Horizontal displacement
Sx = 135 x 18 + (1/2) x (2.18cos(45°) x (18²)
= 2,679.72 m

Vertical displacement in the +ve y-axis is
Sy = (1/2) x 2.18sin(45°) x (18²) = 249.72 m/s

Both components are equal since sin45 = cos 45

The magnitude of the resulting vector displacement
\(= $\sqrt{2679.72^2 +249.72^2}\\\\\\= 2691.33$ m\\\\Angle is given bytan\theta = $\dfrac{y-component}{x-component}$\\or $\theta = tan^{-1}(\dfrac{249.72}{2679.72})$\\\\\\= 5.32^\circ$ north of east\)

The resultant displacement direction is at an angle of 5.32 ° North of East or directly NE

Answer:

12 m

Explanation:

Given data:

M.A. =  8 (No units),

Ramp height (h)= 1.5 m, lifted,

Determine how long is the ramp=?

General formula

Mechanical Advantage = (Ramp length) ÷ (Ramp height),

                            M.A = l  ÷ h

                                 8 × 1.5 = l = 12 m long

length of the ramp l ramp = 12 m

Answer:

64 ohms =R

Explanation:

R is directly proportional to V

R is inversely proportional to I(Current

Answer:

B

Explanation:

Answer:

B. is the correct option! The person above was correct :)

Explanation:

Have a great day!