wo 25.0-cm-focal-length converging lenses are placed 16.5 cm apart. an object is placed 35.0 cm in front of one lens. where will the final image formed by the second lens be located? what is the total magnification?

The speed of the connected cars is 1.67 m/s (3 sig figs). The kinetic energy of the system decreases by 1.87 × 10⁵ J (3 sig figs) during the collision.

To find the speed of the connected cars, we can apply the law of conservation of momentum. According to this law, the total momentum before the collision is equal to the total momentum after the collision.

The initial momentum of the first car is given by the product of its mass and velocity, which is (25,000 kg) × (2.50 m/s) = 62,500 kg·m/s. The initial momentum of the second car is (25,000 kg) × (1.00 m/s) = 25,000 kg·m/s.

When the two cars connect, they form a system with a total mass of 2 × 25,000 kg = 50,000 kg. The final momentum of the connected cars is the sum of the initial momenta, which is 62,500 kg·m/s + 25,000 kg·m/s = 87,500 kg·m/s.

To find the final speed of the connected cars, we divide the total momentum by the total mass: (87,500 kg·m/s) / (50,000 kg) = 1.75 m/s. Rounding to three significant figures gives a speed of 1.67 m/s.

To determine the change in kinetic energy during the collision, we need to calculate the initial and final kinetic energies and find their difference. The initial kinetic energy is given by: (1/2) × mass × velocity².

For both cars, the initial kinetic energy is (1/2) × (25,000 kg) × (2.50 m/s)² = 156,250 J.

The final kinetic energy of the connected cars can be calculated using the mass and final speed: (1/2) × (50,000 kg) × (1.67 m/s)² = 69,446 J.

The change in kinetic energy is the difference between the initial and final kinetic energies: 156,250 J - 69,446 J = 86,804 J. Rounding to three significant figures gives a decrease in kinetic energy of 1.87 × 10² J.

To know more about collision, refer here:

https://brainly.com/question/29308013#

#SPJ11

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, The Resistance is given as 20 Ohm's . Current is given as 1.5 Amperes . And, we have been asked to calculate the Voltage .

For calculating the Voltage , we will use the Formula :-

\( \bigstar \: \: \: \boxed {\sf { \: Voltage \: = \: Current \: \times \: Resistance \: }} \)

Therefore , by Substituting the given values in the above Formula :-

\( \Longrightarrow \: \: \: \sf { Voltage \: = \: Current \: \times \: Resistance } \)

\( \Longrightarrow \: \: \: \sf { Voltage \: = \: 1.5 \: \times \: 20 } \)

\( \Longrightarrow \: \: \: \bf { Voltage \: = \: 30 } \)

Hence :-

\( \underline {\rule {180pt}{4pt}} \)

Additional Information :-

\(\Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} \)

\( \Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance}} \)

\( \Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } \)

Answer:

Explanation:

Given:

To Find:

Solution:

Using formula:

By Substituting the required values,

⇢ Voltage = 1.5 × 20

⇢ Voltage = 30 Volts.

Hence,

Answer:

Change in velocity, change in direction, change in both velocity and direction

Explanation:

Troposphere, stratosphere, mesosphere, thermosphere and exosphere.

Earth's atmosphere has five major layers.

From lowest to highest, layers are the troposphere, stratosphere, mesosphere, thermosphere and exosphere.

a) What are the conditions in the troposphere?

The atmospheric temperature descends upward with a slope of ~10 K km−1 for dry air and ~7 K km−1 for wet air in troposphere.

The temperature of troposphere decreases with an increase in height.

B) What sort of temperatures would she experience in the stratosphere? What other layer is found within the stratosphere?

The temperature in the stratosphere ranges from- 60° F at the troposphere boundary to -5°F at the top.

The temperature increase is due to the ozone layer that absorbs ultraviolet light from solar radiation.

C)What sort of temperatures would she experience in the mesosphere?

The temperature in the mesosphere ranges from -2.5°C to -90°C

The temperature decreases because of a decrease in the absorption of penetrating solar radiation.

The atmosphere gets cooler with an increase in altitude because an increase in distance from the Earth's surface.

D)What sort of temperatures would she experience in the thermosphere? What other layer is found within the thermosphere?

4,500°F is the temperature of thermosphere.

Temperatures climb sharply in the lower thermosphere , then level off and hold fairly steady with increasing altitude above that height.

Temperatures in the upper thermosphere can range from about 500° C (932° F) to 2,000° C (3,632° F) or higher.

Learn more about layers of atmosphere here:

https://brainly.com/question/25881294

#SPJ1

Answer: B) force must be in the same direction as movement

Explanation:

Both the assertion and the reason given are true.If the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

The given assertion: When astronauts throw something in space, that object would continue moving in the same direction and with the same speed; and the given reason: The acceleration of an object produced by a net applied force is directly related to the magnitude of the force, and inversely related to the mass of the object are both correct.Astronauts are capable of throwing objects in space because they are beyond Earth's gravity and do not have to deal with any significant air resistance. In the absence of other forces like friction or air resistance, the initial velocity will be conserved, and the object will continue to move with the same speed and direction. The object would continue to move in a straight line with the same speed because no external force acts on it to change the object's state of motion.Newton's second law states that the force of an object is directly proportional to its acceleration, but inversely proportional to its mass. F=ma, where F is force, m is mass, and a is acceleration. Therefore, if the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

for such more questions on  force

https://brainly.com/question/12970081

#SPJ8

Answer:

392.4J

Explanation:

Ep= mgh

m = 20kg

h= 2m

and g= 9.81 m/s^2

Ep= 20 × 9.81 × 2

Ep= 392.4 J

Answer:

28.9 seconds

Explanation:

Convert km/hr to m/s.

83.4 km/hr × (1000 m/km) × (1 hr / 3600 s) = 23.2 m/s

16.4 km/hr × (1000 m/km) × (1 hr / 3600 s) = 4.56 m/s

Given:

Δx = 400 m

v₀ = 23.2 m/s

v = 4.56 m/s

Find: t

Δx = ½ (v + v₀) t

400 m = ½ (4.56 m/s + 23.2 m/s) t

t = 28.9 s

Answer: The train took 28.9 seconds to pass the crossing.

We first convert km/hr to m/s.

83.4 km/hr × (1000 m/km) × (1 hr / 3600 s) = 23.2 m/s

16.4 km/hr × (1000 m/km) × (1 hr / 3600 s) = 4.56 m/s

Given:

Δx = 400 m

v₀ = 23.2 m/s

v = 4.56 m/s

Then we find t:

Δx = ½ (v + v₀) t

400 m = ½ (4.56 m/s + 23.2 m/s) t

t = 28.9 s

Learn more: https://brainly.com/question/13262646

The range at which an object can be seen clearly is referred to as the far range of the eye. The closest object can be seen clearly and without strain at the eye's near point, which is also the shortest distant object.

A myopic eye's far point is immediately anterior to a corneal plane. As they reach the eye, the rays coming from this point are still highly divergent. Rays coming from the far spot end up highly concentrated at the retina because this divergence balances out the excessive converge that is integrated into the myopic eye.

The myopic person's (u) far point is 40 cm away. Final thought The place to start for the this question is 40 cm from the viewer and is a case of myopia. Therefore, the lens's focal length will be -40cm, or -0.4m.

To know more about focal length visit :

https://brainly.com/question/29870264

#SPJ4

About 4.5 mol of water will be created when the platinum-based engine is run continuously at 300 K for an hour with 0.5 atm of H2 and 0.5 atm of O2 injected for each reaction.

For fuel cell engines' electrodes, platinum is a requirement. It acts as an electrocatalyst to speed up the electrochemical reactions needed to induce H2 to release electrons and form H2 ions when it is placed on porous electrodes.

Platinum is particularly well suited as a fuel cell catalyst because it makes it possible for the hydrogen and oxygen reactions to occur at an ideal rate and because it is stable enough to withstand both the intense electrical current density and the complex chemical environment found inside a fuel cell. This allows platinum to function effectively over an extended period of time.

To learn more about platinum please visit -
https://brainly.com/question/15614668
#SPJ4

Developing good work habits is essential for professional success and personal growth. Here are five commendable work habits:

1. Trustworthiness: Being trustworthy builds strong relationships with colleagues and clients. It involves fulfilling commitments, maintaining confidentiality, and being honest and transparent.

2. Initiating Collaboration: Allowing others to start and actively participating in collaborative efforts fosters teamwork and encourages diverse perspectives. It shows respect for colleagues' expertise and encourages collective problem-solving.

3. Dependability: Demonstrating reliability and consistency in meeting deadlines and delivering quality work builds trust and credibility. Being dependable ensures that others can rely on you and reduces stress within the workplace.

4. Efficiency: Striving for efficiency maximizes productivity and minimizes wasted time and resources. Effective time management, prioritization, and streamlining processes contribute to a productive work environment.

5. Punctuality and Courtesy: Being punctual demonstrates respect for others' time and sets a positive example. Additionally, practicing courtesy, such as using polite language, active listening, and showing appreciation, promotes a harmonious and respectful workplace.

For more such questions on habits,click on

https://brainly.com/question/30068235

#SPJ8

Answer:

unforturnitly

Explanation:

step unstepable

The vector component forms for the given vectors are:

Vector A: (4.0 * cos(30°))i + (4.0 * sin(30°))j

Vector B: 0i - 6.0j

Vector C: 0i + 3.0j

To resolve the vectors given in the figure to their scalar components and express them in vector component form, we can break each vector into its horizontal (x-axis) and vertical (y-axis) components.

Let's consider each vector one by one:

1. Vector A: It has a magnitude of 4.0 units and is inclined at an angle of 30 degrees above the positive x-axis. To find its horizontal and vertical components, we can use trigonometric functions. The horizontal component (Ax) can be found as A * cos(θ), where θ is the angle with the x-axis. Similarly, the vertical component (Ay) can be found as A * sin(θ). So, for Vector A, the vector component form is (4.0 * cos(30°))i + (4.0 * sin(30°))j.

2. Vector B: It has a magnitude of 6.0 units and is directed vertically downward, opposite to the positive y-axis. Since it is directed purely vertically, its horizontal component is zero (Bx = 0), and the vertical component is simply its magnitude in the negative direction. So, for Vector B, the vector component form is 0i - 6.0j.

3. Vector C: It has a magnitude of 3.0 units and is directed along the positive y-axis. Similar to Vector B, its horizontal component is zero (Cx = 0), and the vertical component is its magnitude in the positive y-direction. So, for Vector C, the vector component form is 0i + 3.0j.

In summary, the vector component forms for the given vectors are:

Vector A: (4.0 * cos(30°))i + (4.0 * sin(30°))j

Vector B: 0i - 6.0j

Vector C: 0i + 3.0j

to learn more about vector click here:

brainly.com/question/30128095

#SPJ11

Answer:

a) Direction, direction

Answer: when water flows on the earths surface

Explanation:

Answer: 1.5 × 10^-17

Explanation:

Given the following :

Frequency(f) = 2.2 × 10^16 Hz

Planck's constant(h) = 6.63 × 10^-34

The energy of a photon 'E' is given as the product of frequency and the planck's constant

E = hf

E = (6.63 × 10^-34) × (2.2 × 10^16)

E = 6.63 × 2.2 × 10^(-34 +16)

E = 14.586 × 10^-18

E = 1.4586 × 10^-17

E = 1.5 × 10-17 (2 S. F)

Answer:

C. 1.5 × 10–16 J

Explanation:

Explanation:

4.08 seconds thank me later

Answer:

a. -40 kV b. -6.408 fJ c. 2.77 × 10⁶ m/s

Explanation:

a) Change of potential for this displacement (A =» B)?

The potential energy change ΔV = -EΔx where E = electric field strength = 8 × 10⁴ V/m and Δx = displacement of charge = 0.5 m

So, ΔV = -EΔx

ΔV = -8 × 10⁴ V/m × 0.5 m

ΔV = -4 × 10⁴ V

ΔV = -40 × 10³ V

ΔV = -40 kV

B) Change of P.E for this displacement (A =» B)?

The change in potential energy ΔU = qΔV where q = proton charge = +1.602 × 10⁻¹⁹ C and ΔV = change in potential = -4 × 10⁴ V

So, ΔU = qΔV

ΔU = +1.602 × 10⁻¹⁹ C × -4 × 10⁴ V

ΔU = -6.408 × 10⁻¹⁵ J

ΔU = -6.408 fJ

C) The speed of proton after the displacement?

From the conservation of energy,

The electric potential energy change of the charge equals its kinetic energy change

ΔK + ΔU = 0

ΔK = -ΔU

ΔK = -(-6.408 × 10⁻¹⁵ J)

K₂ - K₁ = 6.408 × 10⁻¹⁵ J

where K₁ = initial kinetic energy of proton = 0 J (since it starts from rest)

K₂ = final kinetic energy of proton = 1/2mv² where m = mass of proton = 1.673 × 10⁻²⁷ kg and v = speed of proton

K₂ - K₁ = 6.408 × 10⁻¹⁵ J

1/2mv² - 0 = 6.408 × 10⁻¹⁵ J

1/2mv² = 6.408 × 10⁻¹⁵ J

v² = 2(6.408 × 10⁻¹⁵ J)/m

v = √[12.816 × 10⁻¹⁵ J)/1.673 × 10⁻²⁷ kg]

v = √[7.66 × 10¹² J/kg]

v = 2.77 × 10⁶ m/s

If an individual who claims to see ghosts everywhere is put into an fmri and asked to observe ghosts in the room, the fMRI scan would show activation in specific brain regions that are associated with visual processing and perception.

The fMRI would detect increased activity in the visual cortex, which is responsible for processing visual information.The brain region called the temporal lobes is also involved in visual processing and perception, and activation in this area could be associated with the perception of ghosts. Furthermore, activity in the amygdala, which is involved in processing emotions and fear, may also be detected if the individual is experiencing fear or anxiety related to seeing ghosts.In conclusion, an fMRI scan of an individual who claims to see ghosts everywhere would show increased activation in brain regions associated with visual processing, perception, and emotional processing.

To learn more about ghosts everywhere

https://brainly.com/question/3446000

#SPJ11

According to this graph, an object that would cause a mass extinction would need to be at least 10 km is diameter.

Any word (or pronoun) that forms the subject of a verb or preposition is referred to as an object. There are three categories of items: Straight Thing (e.g., I know him.) Unrelated Item (e.g., Give her the prize.) Prepositional Object (e.g., Sit with them.)

An expression's subject. The subject's verb's action upon a person, place, or thing is typically called the object. As you might expect, looking for the pronoun or the noun that follows the verb is the quickest approach to identify the subject in a simple sentence.

To know more about object visit:

brainly.com/question/19682773

#SPJ4

(a) Flowchart: A condenser process flowchart is provided, illustrating the inputs and outputs of the humid air stream, O₂, N₂, and the condensed liquid water. (b) Total flow rate: The total flow rate of the feed stream entering the condenser is 5.296F mol/s, considering the flow rates of water vapor, O₂, and N₂. (c) Enthalpy and heat transfer: The enthalpy changes for water vapor and O₂ are calculated, resulting in a heat transfer of -0.072 kF kW, indicating heat removal by the condenser. the heat transferred by the condenser is -0.072 kF kW.

(a) Flowchart:

(b) Total flow rate of the feed stream:

The flow rate of N2 leaving the condenser is given as 5.18 mol/s.

The flow rate of water vapor entering the condenser is 58.0 mol% of F.

80% of the above water vapor is condensed and removed, leaving 20% remaining.

So, 20% of the above water vapor remaining in the humid air after condensation is 0.116F mol/s.

The flow rate of O2 is given as 8.8 mol% of F.

The total flow rate of the feed stream is the sum of the flow rates of water vapor, O2, and N2:

Total flow rate = Flow rate of water vapor + Flow rate of O2 + Flow rate of N2

              = 0.116F + 0.088F + 5.18

              = 5.296F mol/s

(c) Inlet-Outlet Enthalpy Table:

To calculate the heat transferred by the condenser, we need to determine the enthalpy changes for water vapor (H3 to H4) and O2 (H5).

The enthalpy change for water vapor can be calculated as:

ΔH_vap = Enthalpy of water vapor at 30°C - Enthalpy of water vapor at 150°C

      = [40.657 + 0.119 × (30 - 0)] - [40.657 + 0.119 × (150 - 0)]

      = -13.607 kJ/kmol

Enthalpy of water leaving the condenser (H4) can be calculated as:

H4 = Enthalpy of water vapor at 30°C = 40.657 kJ/kmol

Enthalpy of O2 leaving the condenser (H5) can be taken as:

H5 = Enthalpy of O2 at 30°C = 0.102 kJ/kmol

The heat transferred by the condenser (q) can be calculated as:

q = Total flow rate × ΔH

 = (5.296F mol/s) × (-13.607 kJ/kmol) × 10⁻³ kW/J

 = -0.072 kF kW (where kF is the constant conversion factor 10⁶)

Therefore, the heat transferred by the condenser is -0.072 kF kW.

To know more about condenser click here:

https://brainly.com/question/13853336

#SPJ11

When two capacitors 22 μF and 64 μF are connected to a 100-V source, the energy stored in each capacitor is different depending on whether the capacitors are connected in parallel or in series. When connected in parallel, the energy stored in each capacitor is 0.0022 mJ and 0.0064 mJ respectively. When connected in series, the energy stored in each capacitor is also 0.0022 mJ and 0.0064 mJ respectively.  

To answer the question of finding the energy stored in two capacitors 22 μF and 64 μF when connected to a 100-V source, first we need to determine if the capacitors are connected in parallel or series. When two capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances.

Therefore, for two capacitors 22 μF and 64 μF connected in parallel, the total capacitance is 86 μF. The energy stored in each capacitor can be found using the formula W = ½CV2, where C is the capacitance and V is the voltage. For the 22 μF capacitor, W22 = 0.5 * 22 * 10-6 * (100)2 = 0.0022 mJ. Similarly, for the 64 μF capacitor, W64 = 0.5 * 64 * 10-6 * (100)2 = 0.0064 mJ.

When two capacitors are connected in series, the total capacitance is the reciprocal of the sum of the reciprocals of the individual capacitances. Therefore, for two capacitors 22 μF and 64 μF connected in series, the total capacitance is 4.3 μF.

The energy stored in each capacitor can be found using the same formula W = ½CV2. For the 22 μF capacitor, W22 = 0.5 * 22 * 10-6 * (100)2 = 0.0022 mJ. Similarly, for the 64 μF capacitor, W64 = 0.5 * 64 * 10-6 * (100)2 = 0.0064 mJ.

Know more about capacitor here:

https://brainly.com/question/17176550

#SPJ11

Answer:

24° north of east

Explanation:

tan(x)=90/200 ie x=arctan(90/200)=24°

So the plane took off 24° east.

Answer:

24° north of east

Explanation:

Hope this will help

The 12-lead ECG test that shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv, could be a diagnostic for myocardial infarction.

A 12-lead electrocardiogram (ECG) is a medical test that is recorded using leads, or nodes, attached to the body.

Electrocardiograms, sometimes referred to as ECGs, capture the electrical activity of the heart and transfer it to graphed paper.

When a 12-lead ECG shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv, it could be a diagnostic for myocardial infarction.

Learn more about 12 - lead ECG test here: https://brainly.com/question/9328700

#SPJ11

The time it will take her to land on the other side is 0.5 seconds.

In a triangle with three angles of 30°, 60°, and 90°, the hypotenuse is twice as long as the shorter leg and three times as long as the latter. To understand why this is the case, consider that the triangle is a right triangle given these numbers according to the Converse of the Pythagorean Theorem. The lengths of the three sides in a triangle of this kind are referred to as a Pythagorean triple.

distance = velocity x time

In this case, the distance is 3 meters and the velocity is 6 m/s, so:

3 = 6 x time

Solving for time, we get:

time = 3/6 = 0.5 seconds

To know more about time visit:-

https://brainly.com/question/9834403

#SPJ1

The magnitude of the relative angle φ with which the ski jumper hits the slope

φ=14.08

This is further explained below.

Generally, the equation for time is mathematically given as

\(t = \frac{(2V tan \theta)}{g} \\\\t = \frac{2 * 24 * tan 59}{9.8}\)

t = 8.152 s

The formula will now provide the slope of the flight path at the time of impact;

tan = V y / V x

V_y = 9.8 * (8.152)

V_y= 78.89 m/s

In conclusion,

\(tan \alpha = \frac{78.89}{24}\)

\(tan \alpha = 3.2871\)

\(\alpha= 73.08°\)

Hence

φ=\(\alpha - \theta\)

=73.08-59

φ=14.08

Read more about the magnitude of the relative angle

https://brainly.com/question/19522133

#SPJ1

The complete question is;

A ski jumper travels down a slope and leaves the ski track moving in the horizontal direction with a speed of 24 m/s. The landing incline below her falls off with a slope of θ = 59◦ . The acceleration of gravity is 9.8 m/s².

What is the magnitude of the relative angle φ with which the ski jumper hits the slope? Answer in units of ◦

→ The magnitude of the wagons horizontal acceleration is 8.5755 m/s².

First, apply the Second Law of Newton in the 'y' direction. Note: The P force has a component in the axis, it is Psin(40)! Therefore:

\(\Large \text {$N + Psin(40) = W$}\\\\\Large \text {$N + 2N \times sin(40) = m \times g$}\\\\\Large \text {$N(1+ \times 2sin(40)) = m \times g$}\\\\\Large \text {$ \sf N = \dfrac {12 \times 9.8}{1+2sin(40)} = 51.453 $ N}\)

So, in the X direction:

\(\Large \text {$m \times a = 2N \times cos(40)$}\\\\\Large \text {$ \sf a = \dfrac {2 \times 51.453}{12} = 8.5755 m/s^2$}\)

→ See more on:

https://brainly.com/question/11697162

The projectile's initial velocity is 36.05 metres per second horizontally, 26.98 metres per second vertically, and 38.19 metres per second at an angle of 18.32 degrees below horizontal.

R equals u2 sin(90+2)g=u2 cos 2g for the angle (45+). Q. The ratio is used to represent the horizontal ranges covered by two projectiles launched from the same location with the same velocity at angles of (45°) and (45°+).

a) The horizontal component of the initial velocity: The formula for calculating the horizontal component of the initial velocity is

Vx = V cosθ

where V is the starting speed and is the projection angle with respect to the horizontal.

By substituting the provided values, we obtain:

Vx = 45 m/s sin 37 o

Vx = 36.05 m/s (rounded to two decimal places) (rounded to two decimal places)

As a result, the starting velocity's horizontal component is 36.05 m/s.

b) The initial velocity's vertical component

The equation Vy = V sin, where V is the starting velocity and is the angle of projection with the horizontal, can be used to calculate the vertical component of the initial velocity.

By substituting the provided values, we obtain:

Vy = 45 m/s sin 37°

Vy = 26.98 m/s (rounded to two decimal places)

Therefore, the vertical component of the initial velocity is 26.98 m/s.

To know more about projectile's visit:-

https://brainly.com/question/11049671

#SPJ1

Answer: 5 joules

Explanation:

mass=m=2.5kg

Velocity=v=2m/s

Kinetic energy=ke

ke=(m x v x v)/2

ke=(2.5 x 2 x 2)/2

Ke=10/2

Ke=5

Kinetic energy=5 joules

The kinetic energy of a 2.5 kg remote-controlled car that is moving at 2 m/s is 5 Joules.

The energy which an item has as a function of motion is determined by the initial energy. It is described as the effort required to propel a material body from rest to the given velocity.

It is given that:

Mass of the remote-controlled car = 2.5 kg

Velocity of the car = 2 m/s

As we know,

Kinetic energy = k

k = (mv²)/2

As we know,

The mass is a tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.

m = 2.5 kg

v = 2 m/s

k = (2.5×2²)/2

k = 10/2

k = 5 Joules

Thus, the kinetic energy of a 2.5 kg remote-controlled car that is moving at 2 m/s is 5 Joules.

Learn more about kinetic energy here:

https://brainly.com/question/12669551

#SPJ6