With increasing angle of attack, the stagnation point will move (I) and the point of lowest pressure will move (II).A) (I) up, (II) forward.B) (I) down, (II) aft.C) (I) up, (II) aft.D) (I) down, (II) forward.
Answers
When an object moves through a fluid, such as air, the fluid flows around the object creating areas of high and low pressure. These pressure differences are critical to understanding how an object moves and behaves in the fluid. As the angle of attack increases, which is the angle between the object and the fluid flow direction, the flow around the object changes, and the pressure distribution changes with it.
the correct answer is (C) (I) up, (II) aft.
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Related Questions
the greatest hazards posed by hand tools result from:
Answers
Workers should always be educated about hand tool safety and taught to use the appropriate tool for the job, maintain their tools, and work in a safe manner.
Hand tools are the most common tools used in workplaces across the globe. Hand tools are used in a variety of industries, including construction, manufacturing, and maintenance. Hand tools may cause a variety of injuries, including cuts, punctures, bruises, broken bones, and amputations. The greatest hazards posed by hand tools result from misuse, poor maintenance, and failure to select the correct tool for the job.
The incorrect usage of hand tools can cause a variety of injuries, ranging from minor cuts and punctures to serious injuries such as fractures, amputations, and even fatalities. The hazards are amplified when the hand tools are of inferior quality or have not been adequately maintained or repaired.
Hand tools are subject to many types of wear and tear over time, including bending, blunt edges, and worn grips. Using a hand tool in such a condition can be extremely hazardous, resulting in injuries that could have been avoided by repairing or replacing the tool at the right time.Another significant hazard is using the wrong tool for the job. For example, using a chisel instead of a screwdriver or pliers to tighten a screw can damage the screw head or damage the chisel, which can lead to injuries or accidents.
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the contents of programmable read-only memory (prom) can be erased and reprogrammed.
TRUE OR FALSE
Answers
The statement is partially true. Programmable Read-Only Memory (PROM) can be programmed only once, and after that, the contents cannot be erased or reprogrammed.
However, a similar type of memory known as Erasable Programmable Read-Only Memory (EPROM) can be erased and reprogrammed. EPROMs are designed to be erased using ultraviolet light and reprogrammed by exposing the memory to an electrical charge.
In contrast, Electrically Erasable Programmable Read-Only Memory (EEPROM) can be erased and reprogrammed electronically without the need for ultraviolet light. EEPROMs are commonly used in modern electronics to store small amounts of data that need to be retained even when power is removed. In summary, while PROM cannot be erased and reprogrammed, both EPROM and EEPROM can be reprogrammed.
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Which of the following is NOT a line used on blueprints?
Answers
Answer: Photo lines
Explanation: made more sense
You will be using the fictional manufacturing facility Acme Automotive Parts (AAP) throughout the course. AAP manufactures several support parts for new automobiles as a small supplier to Nissan, Honda, and Volkswagen facilities in the United States. Their processes include shipping/receiving, hydraulic presses, metal working lines, robotic welding stations, hand-welding stations in rework areas, two small paint booths, a quality assurance/quality control (QA/QC) laboratory, and a final inspection area.
For this unit please answer the following question:
Determine what information you would use to anticipate health hazards that might be present in each of the eight areas of the AAP plant. State where you might find the information you need.
Answers
To anticipate health hazards in each of the eight areas of the AAP plant, the following information could be used:
1. Shipping/Receiving:
Type of materials being received and shippedPossible exposure to hazardous chemicals, dust, and fumesPossible exposure to heavy machinery and equipmentInformation could be found in Material Safety Data Sheets (MSDS) for the materials, as well as through workplace observations and assessments.2. Hydraulic Presses:
Possible exposure to hydraulic fluids and associated fumesPossible exposure to high pressure and loud noise levelsInformation could be found in MSDS for hydraulic fluids and through workplace assessments and monitoring.3. Metal Working Lines:
Possible exposure to metal dust, fumes, and particlesPossible exposure to high noise levelsPossible exposure to sharp edges and hot surfacesInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the metal working process.4. Robotic Welding Stations:
Possible exposure to welding fumes, dust, and particlesPossible exposure to high noise levelsPossible exposure to high heat and bright lightInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the welding process.5. Hand-Welding Stations in Rework Areas:
Same hazards as in robotic welding stationsPossible exposure to sparks and hot surfacesInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the welding process.6. Small Paint Booths:
Possible exposure to paint fumes and particulate matterPossible exposure to high noise levelsInformation could be found through workplace assessments and monitoring, as well as through MSDS for the paint materials.7. QA/QC Laboratory:
Possible exposure to chemicals and hazardous materials used in testing and analysisPossible exposure to high noise levels from laboratory equipmentInformation could be found through workplace assessments and monitoring, as well as through MSDS for the chemicals and hazardous materials used in the laboratory.8. Final Inspection Area:
Possible exposure to dust and fumes from various manufacturing processesPossible exposure to high noise levelsInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the final inspection process.To anticipate health hazards in each area of Acme Automotive Parts (AAP) manufacturing facility, the following information would be relevant.
What are the information that are relevant in this case?1. Shipping/Receiving: Material Safety Data Sheets (MSDS) for chemicals received, potential for heavy lifting injuries, and risks associated with forklift operations.
2. Hydraulic Presses and Metal Working Lines: MSDS for lubricants and coolants, risks of crush injuries, and exposure to metal fumes.
3. Robotic and Hand-Welding Stations: MSDS for welding materials, welding fume exposure, and risk of burns.
4. Paint Booths: MSDS for paints and coatings, potential for volatile organic compounds (VOCs) exposure, and respiratory hazards.
5. QA/QC Laboratory: MSDS for chemicals used in testing, potential for chemical exposure, and ergonomic risks.
6. Final Inspection Area: Ergonomic risks associated with repetitive tasks, MSDS for any chemicals used, and general safety precautions.
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Of the shielding gases used for gtaw, ___ allows the deepest penetration.group of answer choices
Answers
Among the shielding gases used for GTAW, argon is known for providing the deepest penetration during the welding process.
Of the shielding gases used for GTAW (Gas Tungsten Arc Welding), the gas argon allows the deepest penetration.
Argon is commonly used as a shielding gas in GTAW due to its inert properties and high density. It provides a stable arc and excellent protection for the weld pool.
The deep penetration capability of argon is advantageous when welding materials with thick sections or when deeper penetration is desired.
During the GTAW process, the argon gas is supplied through the welding torch to create a protective atmosphere around the welding area. This shielding gas displaces the surrounding air and prevents atmospheric contamination, such as oxidation, which can negatively impact the quality and strength of the weld.
The deep penetration achieved with argon as the shielding gas is beneficial for welding applications where strong and durable welds are required. It allows for better fusion between the base metals, resulting in a weld with good penetration depth and structural integrity.
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If you find fluid dripping from a vehicle where is the likeliest direction to look for the actual leak
Answers
If I find fluid dripping from a vehicle, the likeliest direction to look for the actual leak is upwards” from ground based.
How will you identify the origins of any fluid leaks?A person has to look for leaks in the heater hoses, water pump, engine core plugs, radiator hoses, and radiator hoses. When the engine is cold, the coolant level should be checked.
Note that The coolant level need to or should be visible in the coolant overflow reservoir. There can be a leak if the fluid level does not or was unable to reach the full line.
Therefore, If I find fluid dripping from a vehicle, the likeliest direction to look for the actual leak is upwards” from ground based.
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Answer:
If you notice a leak near the rear of the vehicle, you must consider a defective fuel tank is a cause. Fuel leaks can occur in two ways - near the rear of the vehicle and near the front if the fuel line is broken or an injector is going bad. Both fuels are clear, but diesel might have a slight blue tint to it when compared to regular fuel.
Explanation:
An electrical engineer at GRIDCO is given two separate toolboxes to keep his working tools. The first toolbox has 4 white fuses and 3 black fuses and the second toolbox has 3 white fuses and 5 black fuses. Suppose the engineer select a fuse from the first toolbox and placed unseen in the second toolbox. What is the probability that: (a) the fuse drawn from the second toolbox is black? (B) the fuse drawn from the second toolbox is white? (8) ane is white?
Answers
(a) The probability of drawing a black fuse from the second toolbox is 4/7.
(b) The probability of drawing a white fuse from the second toolbox is 3/7.
(c) The probability that one fuse is white is 27/49.
To calculate the probabilities, we need to consider the number of white and black fuses in each toolbox.
First, let's determine the total number of fuses in each toolbox:
First Toolbox:
Total fuses = 4 white fuses + 3 black fuses = 7 fuses
Second Toolbox:
Total fuses = 3 white fuses + 5 black fuses = 8 fuses
(a) The probability that the fuse drawn from the second toolbox is black:
The probability of drawing a black fuse from the second toolbox depends on the fuse selected from the first toolbox. There are two scenarios to consider:
Scenario 1: The fuse selected from the first toolbox is black.
In this case, the second toolbox will have 3 black fuses remaining out of the total 7 fuses.
Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)
Probability = 3/7
Scenario 2: The fuse selected from the first toolbox is white.
In this case, the second toolbox will have 5 black fuses out of the total 7 fuses.
Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)
Probability = 5/7
To calculate the overall probability, we need to consider the probability of each scenario and weigh it by the probability of selecting a fuse of that color from the first toolbox. Since the fuse from the first toolbox has an equal chance of being white or black, we need to take an average of the probabilities in both scenarios.
Probability of drawing a black fuse from the second toolbox = (Probability of scenario 1 + Probability of scenario 2)/2
Probability of drawing a black fuse from the second toolbox = (3/7 + 5/7)/2
Probability of drawing a black fuse from the second toolbox = 8/14
Probability of drawing a black fuse from the second toolbox = 4/7
Therefore, the probability of drawing a black fuse from the second toolbox is 4/7.
(b) The probability that the fuse drawn from the second toolbox is white:
Similarly, we can calculate the probability of drawing a white fuse from the second toolbox. It will be the complement of the probability of drawing a black fuse.
Probability of drawing a white fuse from the second toolbox = 1 - Probability of drawing a black fuse from the second toolbox
Probability of drawing a white fuse from the second toolbox = 1 - 4/7
Probability of drawing a white fuse from the second toolbox = 3/7
Therefore, the probability of drawing a white fuse from the second toolbox is 3/7.
(c) The probability that one is white:
To calculate the probability that one fuse is white, we need to consider both scenarios: either the fuse drawn from the first toolbox is white and the fuse drawn from the second toolbox is black, or the fuse drawn from the first toolbox is black and the fuse drawn from the second toolbox is white.
Scenario 1: Fuse drawn from the first toolbox is white, and the second toolbox has a black fuse:
Probability = (Probability of drawing a white fuse from the first toolbox) * (Probability of drawing a black fuse from the second toolbox)
Probability = (3/7) * (5/7)
Scenario 2: Fuse drawn from the first toolbox is black, and the second toolbox has a white fuse:
Probability = (Probability of drawing a black fuse from the first toolbox) * (Probability of drawing a white fuse from the second toolbox)
Probability = (4/7) * (3/7)
To calculate the overall probability, we need to sum up the probabilities of both scenarios:
Probability that one fuse is white = Probability
of scenario 1 + Probability of scenario 2
Probability that one fuse is white = (3/7) * (5/7) + (4/7) * (3/7)
Probability that one fuse is white = 15/49 + 12/49
Probability that one fuse is white = 27/49
Therefore, the probability that one fuse is white is 27/49.
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2.2.2 Make a list of the electronic components that could be used in making this product (energy saving switch).
Answers
The electronic components that could be used in making of energy saving switch are:
Transistors semiconductor devices CapacitorsCoils (inductors) Which electronic component is used as a switch?Transistors as well as other kinds of semiconductor devices are known to be tools or element that can be used in the making of switches. In its use or applications.
Note that the base or gate of a transistor, based on the kind of transistor that is known to be in use, and it is one that is often employed as a form of control element to be able to switch on as well as switch off the current that often exist between the emitter as well as the collector or the source and that of the drain.
Note also that the electronic components that are able to store energy in regards to electronic devices, are known to be capacitors and coils (inductors) and they often play a key function of temporarily saving energy. One key role of a capacitor is to save an electric charge.
Therefore, The electronic components that could be used in making of energy saving switch are:
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Consider the same piping system. this time, the same pipe is buried underground. assuming that there is a constant heat flux of 100w/m^2 from the outer surfance of the pipe to the soil determine the exit temperature of the water.
a. 129.1
b. 111.1
c. 82.1
d. 68.1
Answers
Complete Question
Complete Question is attached below
Answer:
Option A
Explanation:
From the question we are told that:
inner Diameter of pipe \(d_i=100^c\)
Thickness \(t=50mm\)
Outer diameter of pipe \(d_o=1.1m\)
Length \(l=5m\)
Temperature \(T_i=130^oC\)
Generally the equation for Heat Balance is mathematically given by
\(q*\pi d_oL=mC_p(T_i-T_o)\)
Therefore
\(T_o=T_i+\frac{q*\pi d_oL}{mC_p}\)
\(T_o=130+\frac{100*3.142 *1.1*5}{0.5*4000}\)
\(T_o=129.136^oC\)
Therefore the exit temperature of the water.is \(T_o=129.136^oC\)
Option A
7-5.*A four-bit ripple counter is driven by a 20-MHz clock signal. Draw the waveforms at the output of each FF if each FF has tpd =20 ns. Determine which counter states, if any, will not occur because of the propagation delays.
Answers
Answer:
look below
Explanation:
A ripple counter is a type of counter that advances to the next state on each clock pulse, with the output of each flip-flop (FF) being connected to the input of the next FF in the chain. The output of the first FF is connected to the input of the second FF, the output of the second FF is connected to the input of the third FF, and so on.
In a four-bit ripple counter, there are four FFs, each of which has a propagation delay (tpd) of 20 ns. This means that it takes 20 ns for the output of each FF to change in response to a change in its input.
The waveform at the output of each FF will depend on the state of the counter at each clock pulse. If the counter is in state 0001 at the beginning of a clock pulse, for example, the output of the first FF will change to 1 and the outputs of the other FFs will remain at 0. The outputs of the other FFs will change on the next clock pulse, depending on the state of the counter at that time.
It is possible that certain states may not occur because of the propagation delays. For example, if the counter is in state 0001 at the beginning of a clock pulse and the input to the first FF changes to 0 before the output of the first FF has a chance to change, the output of the first FF will not change and the counter will remain in state 0001. This can happen if the clock frequency is too high for the propagation delays of the FFs.
To determine which states will not occur, you would need to analyze the waveforms at the input and output of each FF and determine whether the input changes before the output has a chance to change. This can be done using a timing diagram or by solving the equations for the output of each FF.
A ripple counter is a type of counter that advances to the next state on each clock pulse, with the output of each flip-flop (FF) being connected to the input of the next FF in the chain.
What is propagative delay?In a four-bit ripple counter, there are four FFs, each of which has a propagation delay (tpd) of 20 ns. This means that it takes 20 ns for the output of each FF to change in response to a change in its input.
The waveform at the output of each FF will depend on the state of the counter at each clock pulse. If the counter is in state 0001 at the beginning of a clock pulse, for example, the output of the first FF will change to 1 and the outputs of the other FFs will remain at 0. The outputs of the other FFs will change on the next clock pulse, depending on the state of the counter at that time.
Therefore, A ripple counter is a type of counter that advances to the next state on each clock pulse, with the output of each flip-flop (FF) being connected to the input of the next FF in the chain.
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Which of the following situations illustrate the problem of the introduction of new goods in the construction of the CPI? The introduction of air bags in carsGreater use of fuel-efficient cars after gasoline prices increaseThe invention of cell phonesMore scoops of raisins in each package of Raisin BranIncreased personal computer purchases in response to a decline in their price
Answers
Greater use of fuel-efficient cars after gasoline prices increase.
The invention of cell phones illustrates the problem of the introduction of new goods in the construction of the CPI because there was nothing like it in the past.
What is meant by the CPI?A consumer price index is a price index that measures the cost of a weighted average market basket of consumer goods and services bought by households. Changes in the measured CPI reflect price changes over time.The consumer price index, or CPI, is a metric used to calculate inflation. CPI specifically measures retail inflation by collecting data on the prices of goods and services consumed by the country's retail population.A CPI is a statistical estimate based on the prices of a representative sample of items whose prices are collected on a regular basis. Sub-indices and sub-sub-indices for various categories and sub-categories of goods and services can be computed and combined to produce the overall index, with weights reflecting their share of the total consumer expenditures covered by the index. Most national statistical agencies calculate it as one of several price indices.To learn more about CPI refer :
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A brick column with cross section 10 cm by 10 cm [Thermal conductivity, k = 0.69 W/moC and thermal diffusivity, α = 0.5 x 10-6 m2/s] is initially at a uniform temperature Ti = 225oC. Suddenly the surfaces are subjected to convective cooling with a heat transfer coefficient h = 60 W/m2 oC into an ambient at T∞ = 25oC. Calculate the center temperature To at t = 1 hour after the start of the cooling.
Answers
The center temperature To at t = 1 hour after the start of the cooling is 185.6 °C
How can you calculate the center temperature of the brick?To calculate the center temperature of the brick column at t = 1 hour after the start of the cooling, we need to use the heat equation, which is a partial differential equation describing how heat flows through a material over time. The heat equation for a two-dimensional steady state problem is given by:
∇²T = α ∂T/∂t
Where T is the temperature, α is the thermal diffusivity, and t is time.
The solution to this equation can be found using the semi-infinite solid solution which is given by
To = Ti + (T∞-Ti) erfc(x/2*√(αt))
where,
To is the center temperature,
Ti is the initial temperature of the column,
T∞ is the ambient temperature,
x is the distance from the surface of the column, α is the thermal diffusivity, and
t is time.
In this case,
To = 225 + (25-225) erfc(5/2√(0.510^-6 * 3600))
Plugging in the given values, the center temperature is around Tₒ = 225 + (25-225) erfc(0.0156) ≈ 185.6 °C
Therefore, the correct answer is as given above
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. The four concentric forces act on the post. Determine the resultant force and its direction, measured counterclockwise from the positive x axis. F2 = 600 N F1 = 300 N 30° x 60° 1213 F4 = 250 N S F3 = 450 N
Answers
A simple addition of the forces' magnitudes; rather, it is the addition of the forces as vectors, which is more complex because vectors contain both a magnitude and a direction that must be taken into account.
What is Resultant force?The resultant force is 0 if an object is not subject to any forces, and it is equal to one force if there is only one force acting on the object, according to the equation above.
These two situations are quite straightforward, but what if an object is being affected by two or more forces.
The combined magnitude of the two forces produces a force that is in the same direction as the original two forces.
Therefore, A simple addition of the forces' magnitudes; rather, it is the addition of the forces as vectors, which is more complex because vectors contain both a magnitude and a direction that must be taken into account.
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(a) What is the distinction between hypoeutectoid and hypereutectoid steels? (b) In a hypoeutectoid steel, both eutectoid and proeutectoid ferrite exist. Explain the difference between them. What will be the carbon concentration in each? (c) In bullet format compare and contrast the expected mechanical behavior of hypoeutectoid and hypereutectoid steels in terms of: (i) Yield strength (ii) Ductility (iii) Hardness (iv) Tensile strength (d) If you want to choose an alloy to make a knife or ax blade would you recommend a hypoeutectoid steel alloy or a hypereutectoid steel alloy? Explain your recommendation in 1-3 bullet points. (e) If you wanted a steel that was easy to machine to make a die to press powders or stamp a softer metal, would you choose a hypoeutectoid steel alloy or a hypereutectoid steel alloy? Explain your choice in 1-3 bullets.
Answers
Answer:
See explanation below
Explanation:
Hypo-eutectoid steel has less than 0,8% of C in its composition.
It is composed by pearlite and α-ferrite, whereas Hyper-eutectoid steel has between 0.8% and 2% of C, composed by pearlite and cementite.
Ferrite has a higher tensile strength than cementite but cementite is harder.
Considering that hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains whereas hypereutectoid steel contains a higher amount of cementite, the following properties are obtainable:
Hypo-eutectoid steel has higher yield strength than Hyper-eutectoid steel
Hypo-eutectoid steel is more ductile than Hyper-eutectoid steel
Hyper-eutectoid steel is harder than Hyper-eutectoid steel
Hypo-eutectoid steel has more tensile strength than Hyper-eutectoid steel.
When making a knife or axe blade, I would choose Hyper-eutectoid steel alloy because
1. It is harder
2. It has low cost
3. It is lighter
When making a die to press powders or stamp a softer metals, I will choose hypo-eutectoid steel alloy because
1. It is ductile
2. It has high tensile strength
3. It is durable
Answer:
(a)
Steels having carbon within 0.02% – 0.8% which consist of ferrite and pearlite are known as hypoeutectoid steel.
Steels having greater than 0.8% carbon but less than 2.0% are known as hypereutectoid steel.
(b)
The proeutectoid ferrite formed at a range of temperatures from austenite in the austenite+ferrite region above 726°C. The eutectoid ferrite formed during the eutectoid transformation as it cools below 726°C. It is a part of the pearlite microconstiutents . Note that both hypereutectoid and hypoeutectoid steels have proeutectoid phases, while in eutectoid steel, no proeutectoid phase is present.
Proeutectoid signifies is a phase that forms (on cooling) before the eutectoid austenite decomposes. It has a parallel with primary solids in that it is the first phase to crystallize out of the austenite phase. If the steel is hypoeutectoid it will produce proeutectoid ferrite and if it is hypereutectoid it will produce proeutectoid cementite. The carbon concentration for both ferrites is 0.022 wt% C.
(c)
(i) Yield strength: The hypoeutectoid steel have good yield strength and hypereutectoid steels have little higher yield strengh.
(ii) Ductility: The hypoeutectoid steel is more ductile and the ductility has decreased by a factor of three for the eutectoid alloy. In hypereutectoid alloys the additional, brittle cementite on the pearlite grain boundaries further decreases the ductility of the alloy. The proeutectoid cementite restricts plastic deformation to the ferrite lamellae in the pearlite.
(iii) Hardness: hypoeutectoid steels are softer and hypereutectoid steel contains low strength cementite at grain boundary region which makes it harder than hypoeutectoids.
(iv) Tensile strength: Grain boundary regions of hypereutectoid steel are high energy regions prone to cracking because of cementite in the grain boundaries, its tensile strength decreases drastically even though pearlite is present. Hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains, so grain boundaries being the high energy state region, it has a higher tensile strength.
(d)
I would recommend hypereutectoid steel alloy to make a knife or ax blade
1- Hardness is required at the surface of the blades.
2- Ductility is not needed for such application.
3- Due to constant impact, the material will not easily yield to stress.
(e)
I would choose a hypoeutectoid steel alloy to make a steel that was easy to machine.
1- hypoeutectoid steel alloys have high machinability, hence better productivity
2- It will be used on softer metals, hence its fitness for the application
3- Certain amount of ductility is required which hypoeutectoid steel alloys possess.
Explanation:
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at location in Europe , it is necessary to supply 200kW of 60Hz power . THe only power sources available operate at 50hx. it is decided to generate the power by means of a motor generator set consisting of a sysnchronous motor driving a synchronous generator. how many pols of a synchronous generator should be coupled with a 10-pole synchronous motor in order to convert 50ha power to 60-hz power?
Answers
A synchronous motor driving a synchronous generator is used to produce 60 Hz power at a location in Europe, where 200 kW of 60 Hz power is needed, but only 50 Hz power sources are available
The question is asking for the number of poles of the synchronous generator that should be connected with a 10-pole synchronous motor to convert the power from 50 Hz to 60 Hz.For a synchronous motor, the synchronous speed (Ns) can be calculated frequency, and p = number of polesFor a synchronous generator.
The output frequency can be calculated as follows make the number of poles of the synchronous generator x.Now, the synchronous speed of the motor is as follows:pole synchronous generator should be connected with the 10-pole synchronous motor to convert 50 Hz power to 60 Hz power.
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Write 3 important things learned about oxyfuel cutting and welding system.
Answers
Answer:
see and make me brainlist
Explanation:
What is oxy fuel cutting used for?
Oxy-fuel cutting is used for the cutting of mild steel. Only metals whose oxides have a lower melting point than the base metal itself can be cut with this process. Otherwise as soon as the metal oxidises it terminates the oxidation by forming a protective crust.
An isometric drawing of a metal block is shown below. All the holes pass completely through the block.
A. Draw and label the front top, and right side views of the block. Include all hidden lines. Make your drawing in proper pre-portion.
B. Which of these two types of drawings, the isometric drawing shown or your drawing from part (a), would an engineer give to a machinist to make a prototype of the block? Explain your answer.
Answers
A. The drawing is made and attached
B. The drawing shown in part A is what the engineer give to machinist
What is isometric drawing?Isometric drawing is a technique used in technical and engineering drawings to represent three-dimensional objects on a two-dimensional plane.
The Engineer will give the machinist the drawing in part A because it shows more detail than the isometric drawing will show. An instance is the cylindrical hole that appears as just circle in the isometric view.
The engineer's drawing will enable the machinist know the extent of the hole
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Consider steady flow of blood in a tube whose thin walls are made of a linearly elastic Hookean material, so that changes in hoop stress are directly proportional to changes in hoop strain.You may treat the blood as Newtonian, with viscosity ?.
(a) When blood is flowing, it is observed that tube diameter decreases with axial position along the tube, x (Fig. 4.32). Why is this?
(b) Show that a change in internal pressure dp causes a change in radius dR given by: dR = (R2/Eh)*dp where h is the tube wall thickness.
(c) If the tapering of the tube is not too severe, then the flow is "nearly" Poiseuille and can be described by:
Q = ?(?R4/8?)*(dp/dx)
Using this expression, as well as the results of part (b) above, derive an expression for R in terms of the inlet radius (Ro),?, the flow rate (Q), E, h, and the axial position within the tube, x.
(d) Blood (effective Newtonian viscosity 3.5 cP) flows in such a tube with E = 100 dynes/cm2 and h = 1 mm. If Q is 100 ml/min and the radius at the inlet is 1 cm, determine the tube radius at 20 cm from the inlet.
Answers
It should be noted that when blood is flowing, it is observed that tube diameter decreases with axial position along the tube, x because pressure decreases with x due to frictional losses.
How to calculate the pressureb. For a thin wall, B = D / Eh
D / Eh = 2dR / Rdp = 2R / Eh = 2dR / Rdp
dR = R²/Ehdp
c. Q = πR⁴ / 8u dp/dx and dR = R²/Ehdp
dp = Q8u/πR⁴ dx
dR = R²/Eh;(-Q8u/πR⁴ dx)
= Q . 8u/Eh . 1/πR² dx
1/3(R³ - Ro³) = -8uW/Ehπx
R = (Ro³ - 24uQ/Ehπ x)^1/3
d. R(x = 20cm) = [(1cm)³ - {24(3.5 × 10^-2)/1.67} / 100 × 0.1 π × 10]^1/3
= 0.47cm
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Divide. Give the exact answer, written as a decimal. 5) 3.6
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Answer:
I believe the answer is 0.138
8. Describe and correct the error in stating the domain. Xf * (x) = 4x ^ (1/2) + 2 and g(x) = - 4x ^ (1/2) The domain of (f + g)(x) is all real numbers
Answers
The correct statement of the domain of (f+g)(x) is that it is restricted to all non-negative real numbers, or [0,∞).
What is the error in stating the domain of (f + g)(x) as all real numbers?The error in stating the domain of (f + g)(x) as all real numbers is that the domain of the function (f+g)(x) is determined by the intersection of the domains of the functions f(x) and g(x).
In the given equations, the domain of f(x) is restricted to non-negative real numbers as the square root of a negative number is undefined in the real number system. However, the domain of g(x) is all non-negative real numbers.
To find the domain of (f+g)(x), we need to find the intersection of the domains of f(x) and g(x). Since the domain of g(x) is already included in the domain of f(x), the domain of (f+g)(x) is also restricted to all non-negative real numbers.
The correct statement of the domain of (f+g)(x) is that it is restricted to all non-negative real numbers, or [0,∞).
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Pressure bleeding is being discussed. Technician A says to pump the brake pedal several times during the bleed procedure. Technician B says to hold the metering valve open during the bleed procedure. Who is correct
Answers
When performing a pressure bleeding procedure on a brake system, it is not necessary to pump the brake pedal several times. In fact, doing so can introduce air bubbles into the brake system and make the bleeding process less effective. Instead, a pressure bleeder is used to force brake fluid through the system while the bleeder valves are opened to allow the fluid and any air bubbles to escape.
As for Technician B, there is no need to hold the metering valve open during the bleed procedure. The metering valve, also known as a proportioning valve, is designed to regulate the pressure between the front and rear brakes, and does not typically need to be adjusted or manipulated during a brake bleeding procedure.
Therefore, neither Technician A nor Technician B is completely correct. The proper procedure for pressure bleeding a brake system involves using a pressure bleeder to force brake fluid through the system, while opening the bleeder valves to allow any air bubbles to escape. The metering valve does not need to be manipulated or adjusted during this process.
When your workplace obtains new materials, you should add them to the chemical list
Answers
High-mount stop lamps are typically attached to the exterior of the vehicle using:
A. nylon retainers.
B. visible screws.
C. rivets
D. self-locking nuts.
Answers
Answer:
Option A
Explanation:
Nylon retainers are knocking screws that have nylon coating on their thread which prevents them from loosening. It generally has two heads Hex Key an star screw. For high mount fixing, star screw is used as it is less prone to stripping. The nylon insert of a Nylock nuts enters into the screw and prevent it from loosening. It is useful in areas where there is high vibration.
Hence, option A is correct
Suppose that instead of a frame, a point P[3, 9, 5]T in space was translated a distance of d = 4,7,8 T. Find
the new location of the point relative to the reference frame
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The new location of the point P[3, 9, 5]T after being translated a distance of d = 4,7,8 T relative to the reference frame is (7, 16, 13).
The new location of the point P[3, 9, 5]T after being translated a distance of d = 4,7,8 T relative to the reference frame can be found by adding the translation vector to the original coordinates of point P.
To find the new location, we can add the corresponding components of the translation vector to the coordinates of point P.
The translation vector d = 4,7,8 T represents the distances to be added to the x, y, and z coordinates, respectively.
So, the new x-coordinate of the point is 3 + 4 = 7.
The new y-coordinate of the point is 9 + 7 = 16.
The new z-coordinate of the point is 5 + 8 = 13.
Therefore, the new location of the point P relative to the reference frame is (7, 16, 13).
By adding the corresponding components of the translation vector to the original coordinates of point P, we found that the new location of the point P relative to the reference frame is (7, 16, 13).
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Which user management tool is required to assign a logon script to a user?
-. Advanced Users and Groups MMC snap-in
-. Local Users and Groups MMC snap-in
-. Advanced User Accounts applet
-. User Accounts in Control Panel
Answers
The tool required to assign a logon script to a user is the Local Users and Groups MMC snap-in. The Local Users and Groups snap-in allows administrators to manage user accounts and groups on a local computer.
To assign a logon script to a user, an administrator can follow these steps:
Open the Local Users and Groups snap-in by typing "lusrmgr.msc" in the Run dialog box or the Start menu search bar.
Expand the "Users" folder and select the user account that needs to have the logon script assigned.
Right-click the user account and select "Properties".
In the user account properties window, select the "Profile" tab.
In the "Logon script" field, enter the path to the logon script file.
Click "OK" to save the changes.
Once the logon script is assigned to the user, it will be executed every time the user logs on to the computer.
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What is a sculpture that can be viewed from all sides?
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A sculpture that can be viewed from all sides is called a "freestanding sculpture."
A freestanding sculpture is a three-dimensional artwork that is not attached to any wall or surface and can be viewed from all angles. It is also known as a sculpture in the round or an in-the-round sculpture. Freestanding sculptures have been around for thousands of years and are one of the oldest forms of artistic expression. They can be made from a variety of materials such as stone, metal, wood, clay, and even ice. They can vary in size from small handheld pieces to large outdoor installations.
One of the most famous freestanding sculptures is Michelangelo's David. The statue is over 17 feet tall and is made of marble. It depicts the biblical hero David before his battle with Goliath. It is considered one of the greatest works of art ever created and is admired for its intricate details and a lifelike appearance. Another famous example of a freestanding sculpture is Rodin's The Thinker. It is a bronze sculpture that depicts a man in deep thought. It is over 6 feet tall and has been replicated numerous times around the world. It is often used as a symbol of intellectualism and philosophy.
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A rigid triangular frame is pivoted at C and held by two identical horizontal wires at points A and B (see figure). Each wire has axial rigidity EA = 120 k and coefficient of thermal expansion (a) If a vertical load P = 500 lb acts at point D, what are the tensile forces TA and TB in the wires at A and B, respectively?
(b) If, while the load P is acting, both wires have their temperatures raised by 180°F, what are the forces TA and TB?
(c) What further increase in temperature will cause the wire at B to become slack?
Answers
We must first ascertain the responses at point C as a result of the applied load P. As a result of the frame being in equilibrium, all forces operating on it must be zero in total. Hence, we have
What is the initial prerequisite for equilibrium issues with answers?Equilibrium, which is characterised as motion without linear or rotational acceleration, requires the fulfilment of two requirements. The net external force acting on the system must be zero in order for equilibrium to occur, or net F to equal 0.
TAcos(30°) + TBcos(30°) = 0 when Fx = 0. (1)
TAsin(30°) + TBsin(30°) - 500 = 0 when Fy = 0. (2)
ΔL = αLΔT (3) (3)
Assuming that the temperature change is T = 50°C and that the wires are originally at room temperature (20°C), we have:
ΔL = αLΔT = 1210⁻⁶ ×L ×50 = 610⁻⁴ ×L (4)
Δθ = ΔL / r (5) (5)
We may calculate r using the geometry of the frame as follows: r = 2/3 ×L ×sin(30°) = 0.577×L (6)
Equation (5) is obtained by substituting equations (4) and (6).
Δθ = (6/10000) ×L² (7) (7)
TA = -TB(8), -TBsin(30°), + TBsin(30°), -500 = 0.
We can calculate TB as follows: TB = 500 / sin(30°) = 1000 lb (9)
Δθ = (6/10000) ×L² = (6/10000) ×(2/3 ×r / sin(30°)) 2 TA = EA ×/ L = EA ×(6/10000 ×r / sin(30°) × 2/3 × EA × ² / L
We derive the following by substituting the values of EA,, L, r, and T:
TA = 120 x 10 x 6 x 10 000 x 2 / 3 x 0.577 x L / sin(30°)
² / L ΔTA = 5.247 lb
Hence, TA = TB + TA = 1000 + is the tensile force in wire A.
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The following is a series of questions pertaining to the NSPE Code of Ethics. Please indicate whether the statement are true or false. These questions are provided by the NSPE.
Engineers in public service as members, advisors or employees of a governmental or quasi-governmental body or department may participate in decisions with respect to services solicited or provided by them or their organizations in private or public engineering practice as long as such decisions do not involve technical engineering matters for which they do not posses professional competence
Answers
Geomorphic
Explanation:
Because it's pretty easy if you think of the right ways of geomorphic ways to process the equation
If a circuit produces a phase shift of 45 degrees between the voltage and current curves and the apparent power is 100 VA, what is the TRUE power in the circuit?
50 W
70.7 VA
70.7 W
100 A
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The true power is obtained as 70.7 VA.
What is the true power?We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.
Thus;
True power = PcosΦ
P = 100 VA
Φ = 45 degrees
True power = 100 VA * cos 45 degrees
True power = 70.7 VA
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HELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HEL
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Answer:
oh this happened with me to ,this will be alright just wait a bit