Wind energy is increasingly relied upon to help meet global energy needs. Wind energy can be used to generate electricity using wind turbines. Which of the following are often used for energy storage of wind power? A). Converters B). Generators C). Batteries D). Rotor blades

Lenses, which are pieces of curved, clear glass, were employed in early telescopes to focus light.

Curved mirrors are used by the majority of telescopes nowadays to collect light from the night sky. Light is focused by a telescope's mirror or lens' shape.

Astronomers use a telescope to observe distant things. Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from the night sky.

The original telescopes employed lenses, which are simply curved pieces of clear glass, to focus light. The "optics" of a telescope are the mirrors or lenses. Strong telescopes may view objects that are extremely faint and incredibly far away.

Therefore, Lenses, which are pieces of curved, clear glass, were employed in early telescopes to focus light.

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The amount of charge that will pass through the cross-sectional area of the conductor in 1 min is 192 C.

We can use the formula Q = I * t,

where;

Given that a charge of 6.4 C passes through a cross-sectional area of the conductor in 2 s, we can find the current using the formula:

I = Q / t = 6.4 C / 2 s = 3.2 A

So, the current through the conductor is 3.2 A.

To find the amount of charge that will pass through the cross-sectional area of the conductor in 1 min (60 s), we can use the same formula:

Q = I * t = 3.2 A * 60 s = 192 C

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The answer is A. Photosynthesis is caused when plants trap light energy in their leaves and use that energy to change water and carbon dioxide into glucose. Hope this helps :)

Answer:

(1) 1000 N (2) 1 m/s²

Explanation:

(1) Given that,

The mass of a car, m = 1000 kg

Radius of a circular track, r = 100 m

Speed of the car, v = 10 m/s

We need to find the magnitude of the centripetal force acting on the car. The magnitude of the centripetal force is given by :

\(F=\dfrac{mv^2}{r}\\\\F=\dfrac{1000\times (10)^2}{100}\\\\F=1000\ N\)

So, the correct option is (c) i.e. 1000 N

(2).The mass of a car, m = 1000 kg

Radius of a circular track, r = 100 m

Speed of the car, v = 10 m/s

We need to find the magnitude of the centripetal acceleration of the car. The magnitude of the centripetal acceleration is given by :

\(a=\dfrac{v^2}{r}\\\\a=\dfrac{(10)^2}{100}\\\\a=1\ m/s^2\)

So, the correct option is (b) i.e. \(1\ m/s^2\)

Answer:6

Explanation:

Answer:

6

Explanation:

Answer:

Factors Affecting the Strength of the Magnetic Field of an Electromagnet: Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core

Explanation:

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The following factors affect the strength of an electromagnet; number of turns, wire size, current and the presence of iron core.

This is a type of magnet  in which the magnetic field is produced by an electric current.

The following factors affect the strength of an electromagnet;

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Answer:

Using Ohm's Law, we can calculate the voltage of the battery as V = IR = (4 A)(7 Ω) = 28 V.

The total resistance of the circuit is R = R₁ + R₂ + r, where r is the internal resistance of each element.

We know that R₁ = 14 Ω and R = 7 Ω, so we can solve for R₂:

R₂ = R - R₁ = 7 Ω - 14 Ω = -7 Ω

This is a negative resistance, which doesn't make sense physically. However, it indicates that there is an error in the problem or the calculations.

To find the internal EDS of the elements, we can use the equation:

V = ε - Ir

where V is the voltage of the battery, ε is the internal EDS of each element, I is the current flowing in the circuit, and r is the internal resistance of each element.

We know that V = 28 V, I = 4 A, and r = 6 Ω, so we can solve for ε:

ε = V + Ir = 28 V + (4 A)(6 Ω) = 52 V

Therefore, the internal EDS of each element is 52 V.

Answer:

7.46×10⁻⁶ m

Explanation:

Applying,

F = kqq'/r²............ Equation 1

make r the subject of the equation

r = √(F/kqq').......... Equation 2

From the question,

Given: F = 8 N, q' = q= 4 C

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 2

r = √[8/(4×4×8.98×10⁹)]

r = √(55.7×10⁻¹²)

r = 7.46×10⁻⁶ m

Answer:

Blood is moved away from the brain

Explanation:

Took the test

The net electric force on particle 2 is -21.7 N.

The net force on particle q₂ is determined by applying Coulomb's law of electrostatic force.

F = kq₁q₂ / r²

where;

The force  between particle 2 and particle 1 is calculated as;

F = -( 9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.1)²

F = - 25.2 N

The force  between particle 2 and particle 3 is calculated as;

F = ( 9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.15)²

F = 3.5 N

The net force on particle 2 = 3.5 N - 25.2 N = -21.7 N

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1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.

We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.

The heat lost by the metal is given by

Q1 = m1c1ΔT1

Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.

The heat gained by the ice is given by

Q2 = m2c2ΔT2

Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.

Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2

m1c1ΔT1 = m2c2ΔT2

Solving for c1, we get

c1 = m2c2ΔT2 / (m1ΔT1)

By putting these values we get

c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]

c1 = 0.902 kJ/kg·K

Hence, the specific heat of the metal is 0.902 kJ/kg·K.

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Answer:

1.25 sec, 2 m/s

Explanation:

Period = 2 * 0.625 sec = 1.25 sec

speed = 2.5/1.25 = 2 m/s

Answer:

Below

Explanation:

x = total power

.69 x = 2245  w

x = .2245 / .69 = 3254 Watts

The net-work required to accelerate the car of mass 1200 kg is 840000 J.

Work can be deifned as the product of force and distance.

To calculate the amount of net-work required to accelerate 1200 kg car from 25 m/s to 45 m/s, we use the formula

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the net-work required is 840000 J.

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A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s, Speed it will have when it slides back down to its starting point is 2.36 m/s

The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab). The electromagnetic attraction between charged particles in two contacting surfaces, according to scientists, is what causes it.

using work energy theorem ,

change in kinetic energy = work done by frictional force

\(\frac{1}{2}\) m(\(x^{2}\)-\(y^{2}\)) =  μmghcos30°

where mass is m=200g

x is speed with which it slides back

y is speed at top of metal ramp=3.8 m/s

μ is coefficient of kinetic friction=0.3

g is gravity = 9.8m/\(s^{2}\)

h is height to which hockey puck is reached on metal ramp=1.18m

Substituting the values and solving for speed x,

x=2.36m/s

speed  it will have when it slides back down to its starting point is 2.36m/s

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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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Answer:

Gravity pulls down on the ball at g=-9.81 m/s^2. Up is positive, down is negative. The ball started at a certain initial velocity of Vi m/s. Time it took is t=4s. Final velocity is Vf=0 m/s, because at the highest point the ball stops moving.

Answer:

i got u

Explanation:

The iron will have the higher final temperature. This is because the specific heat capacity of iron is much lower than the specific heat capacity of ice. Specific heat capacity is the amount of heat energy required to raise the temperature of a substance by a certain amount, and it varies from substance to substance. Since the specific heat capacity of iron is lower, it means that it takes less heat energy to raise the temperature of iron than it does to raise the temperature of ice by the same amount. Therefore, when equal amounts of heat are added to equal masses of ice and iron at the same initial temperature, the iron will have a higher final temperature than the ice.

Answer:

a)40 meters

b)2 m/s

c)2 m/s

d)0 m/s

e)45 degrees northeast

Explanation:

a) The displacement from C to A is the distance directly across the river, which is 40 meters.

b) The speed of the boat as seen by people standing at A is the magnitude of the boat's velocity vector, which is equal to the displacement divided by the time taken:

Speed = displacement / time = 40 m / 20 s = 2 m/s.

c) Let v be the speed of the water in the river. The boat is moving at right angles to the flow of the river, so the water exerts a perpendicular force on the boat. The time taken for the boat to travel from A to C is 20 seconds, during which time the boat will have been carried downstream by the river by a distance equal to v times the time taken.

Distance carried downstream = v × time = v × 20 m.

Since the boat landed at C, which is directly across the river from A, the distance it traveled horizontally is 40 meters. Therefore:

40 m = (boat speed) × (time taken) = (boat speed) × 20 s.

Hence, the speed of the boat is:

Boat speed = 40 m / 20 s = 2 m/s.

So, we have two equations:

Distance carried downstream = v × 20 m

Boat speed = 2 m/s

From the first equation, we get:

v × 20 m = 40 m

Therefore, the speed of the water in the river is:

v = 40 m / 20 m = 2 m/s.

d) The speed of the boat as seen by a fish drifting with the river is the difference between the speed of the boat and the speed of the water in the river:

Boat speed - Water speed = 2 m/s - 2 m/s = 0 m/s.

So, the speed of the boat as seen by a fish drifting with the river is zero.

e) The boat should head in a direction that makes its velocity vector point directly from A to B. Since A and B are directly opposite each other, this means the velocity vector should be perpendicular to the line connecting A and B.

We know the boat's velocity vector has a magnitude of 2 m/s and is at right angles to the velocity vector of the water in the river, which has a magnitude of 2 m/s. So, we can draw a vector diagram with the velocity vector of the boat pointing straight up and the velocity vector of the water pointing straight to the right. The vector connecting the tail of the water velocity vector to the head of the boat velocity vector will then point directly from A to B.

The angle between the boat's velocity vector and the line connecting A and B can be found using trigonometry. Let θ be this angle. Then:

tan(θ) = (boat speed) / (water speed) = 2 m/s / 2 m/s = 1.

Taking the inverse tangent of both sides gives:

θ = tan^(-1)(1) = 45°.

So, the boat should head in a direction 45 degrees to the right of straight up, or northeast.

Answer:

Useable energy, electricity

Answer:

In the taller, skinnier cylinder, each tick mark represents 2, while in the larger one, each tick mark represents 50.

Explanation:

If you count the tick marks between each big number, then you can divide, and figure out what amount each tick mark represents.

Answer:

Explanation:

40 km/h

a) The average density of the block can be calculated using the formula for density.Since the mass of the block is 1.80 N and the volume is 2.0 × 10∧5 \(m^{3}\), the average density is 0.9 kg/\(m^{3}\).

Mass is a measure of the amount of matter contained in an object. It is a fundamental physical property that is commonly used to measure the size of objects. Mass is usually measured in grams (g) or kilograms (kg) but can also be measured in other units such as ounces, pounds and tons. Mass is different from weight, which is a measure of the force of gravity on an object.

b) The normal force the floor of the vessel exerts on the submerged body can be calculated using the formula for buoyancy. In this case, the normal force is equal to 1000 kg/\(m^{3}\) × 2.0 × 10∧5 \(m^{3}\)× 9.81 m/\(s^{3}\), which is equal to 1.962× 10∧8 N.

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The statement regarding work and retirement that is true is that most older Americans say they would prefer to enter retirement gradually.

Retirement is defined as the time in an individuals life that such leaves the Labour market or the workforce.

In some countries such as the United States of America, most elderly citizen prefer taking retirement process slowly.

Therefore, the statement regarding work and retirement is that retirement is a gradual process which one starts to process while actively in service

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Answer:

\(-180.38\ \text{N}\)

Explanation:

\(q_1=-53\ \mu\text{C}\)

\(q_2=105\ \mu\text{C}\)

\(q_3=-88\ \mu\text{C}\)

r = Distance between the charges

\(r_{12}=0.5\ \text{m}\)

\(r_{23}=0.95\ \text{m}\)

\(r_{13}=1.45\ \text{m}\)

k = Coulomb constant = \(9\times 10^9\ \text{Nm}^2/\text{C}^2\)

Net force is given by

\(F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}\)

The force on the particle \(q_1\) is \(-180.38\ \text{N}\).

Answer:

The answer sir would be 180.38

Explanation:

Put in 180.38 trust

The change in friction force experienced by the car is

The friction is caused between two uneven contacting surfaces.

When car is on ice, the friction force is

f = μ N

f₁ = 0.2 x 14500 = 2900N

When the car is on dry road, the friction force is

f₂ = 0.8 x 14500 =11,600 N

The change in friction force =11600 - 2900 = 8700N

Thus, the change in friction force experienced by the car is  8700N.

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Answer:

Polishing the rough surface.

Oiling or lubricating with graphite or grease the moving parts of a machine.

Providing all bearings or wheels between the moving parts of a machine or vehicles reduce friction and allow smooth movement as rolling friction is less than sliding friction.

Explanation:

Answer:

Below   ( A )

Explanation:

161.3 km/hr  *  1 hr/ 3600 sec  * 1000m / km  = 44.8 m/s

mv = momentum       and     160 g = .160 kg

.160 kg * 44.8 m/s  = 7.17 kg m/s