Answer:
It will be positive.
Step-by-step explanation:
When you multiply the two negative numbers or two positive numbers the answer will always be positive. one positive and one negative, the answer will be negative.
What is always true about the interquartile range of a data set? Select all that apply.
A.
The interquartile range is greater than the range.
B.
The interquartile range contains the median of the data set.
C.
The interquartile range is less than the range.
D.
The interquartile range contains about 50% of the data set.
The interquartile range is.....
Answer:
Our goal is to understand how range and interquartile range describe data. To do this, we have to define the range and interquartile range of a given set of data, we have to be able to calculate the range and interquartile a range of a given set of data, and then we want to be able to determine how range and interquartile range are impacted by outliers.
So how can you describe data with range and interquartile range? Range tells us if data is grouped closely together or spread far apart. Interquartile range tells us if data is grouped closely around the median. The key concepts. Range is the difference of the maximum and minimum values.
So if we wanted to calculate the range of this particular data set here, we would say 20 minus 1 and get a range of 19. Interquartile range is the difference of the upper and lower quartiles. In order to do this, we first have to find the median to find those upper and lower quartiles. The median of this data set, the value in the middle, is 6. The lower quartile is the median of the lower half, the middle value then of these three data points being 3.
The upper quartile would be the middle of this data set, and that would be 8. So if we wanted to find the interquartile range, we'd subtract those values. 8 minus 3 gives us an interquartile range of 5. Interquartile range describes the spread of data around the median.
A small interquartile range means that most of the data, the middle half, is clustered tightly around the median, whereas a large interquartile range would mean that that data that's in the middle is more spread out. And finally, outliers impact the range, but have little impact on the interquartile range. If we consider our data set here, we see that we have an outlier of 20, but it really only impacts the range.
It does not play a significant role on the interquartile range.
Step-by-step explanation: also brainleist
Hence your answer will be D
bernardo and silvia play following game. an integer between 0 and 999, inclusive, is selected and given to bernardo. whenever bernardo receives a number, she doubles it and pass the result to silvia. whenever silvia recieves a number, she adds 50 and passes teh result to bernardo. the winner is the last person who produces a number less than 100. what is the smallest initial number that results in a win for bernardo
The smallest initial number that results in a win for Bernardo is 31.
Winning number in GameHere's the breakdown of how the game would play out:
Bernardo starts with 31 and doubles it to get 62.Silvia receives 62 and adds 50 to get 112.Bernardo receives 112 and doubles it to get 224.Silvia receives 224 and adds 50 to get 274.Bernardo receives 274 and doubles it to get 548, which is greater than 100, so Bernardo loses.If Bernardo starts with any number less than 31, the final number will be less than 100 and Bernardo will win. Any number greater than 31 will result in Bernardo losing.
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Evaluate the integral: S1 0 (-x³ - 2x² - x + 3)dx
The integral: S1 0 (-x³ - 2x² - x + 3)dx is -1/12
An integral is a mathematical operation that calculates the area under a curve or the value of a function at a specific point. It is denoted by the symbol ∫ and is used in calculus to find the total amount of change over an interval.
To evaluate the integral:
\($ \int_0^1 (-x^3 - 2x^2 - x + 3)dx $\)
We can integrate each term of the polynomial separately using the power rule of integration, which states that:
\($ \int x^n dx = \frac{x^{n+1}}{n+1} + C $\)
where C is the constant of integration.
So, we have:
\($ \int_0^1 (-x^3 - 2x^2 - x + 3)dx = \left[-\frac{x^4}{4} - \frac{2x^3}{3} - \frac{x^2}{2} + 3x\right]_0^1 $\)
Now we can substitute the upper limit of integration (1) into the expression, and then subtract the result of substituting the lower limit of integration (0):
\($ \left[-\frac{1^4}{4} - \frac{2(1^3)}{3} - \frac{1^2}{2} + 3(1)\right] - \left[-\frac{0^4}{4} - \frac{2(0^3)}{3} - \frac{0^2}{2} + 3(0)\right] $\)
Simplifying:
\($ = \left[-\frac{1}{4} - \frac{2}{3} - \frac{1}{2} + 3\right] - \left[0\right] $\)
\($ = -\frac{1}{12} $\)
Therefore,
\($ \int_0^1 (-x^3 - 2x^2 - x + 3)dx = -\frac{1}{12} $\)
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In order to look at specific differences between groups in a one-way ANOVA, you need to conduct: An omnibus test Post hoc comparisons A follow-up correlation O A follow-up regression Previous NE No new data to save. If you perform multiple t-tests, which of the following is true? Type I error increases Type I error decreases Type I error is not impacted 10% chance of committing Type I error Previous
If you perform multiple t-tests, the Type I error increases.
When conducting multiple t-tests, each individual test has a certain probability of committing a Type I error, which is the probability of incorrectly rejecting the null hypothesis when it is actually true. The standard threshold for Type I error is typically set at 5% (or 0.05).
However, when multiple tests are performed, the probability of committing at least one Type I error across all the tests increases. This is known as the problem of multiple comparisons or multiple testing.
The more tests you perform, the higher the likelihood of observing a significant result by chance alone, leading to an increased Type I error rate.
To address this issue, it is common to adjust the significance level (e.g., using Bonferroni correction) or conduct post hoc comparisons using methods such as Tukey's test or Bonferroni adjustment.
These methods help control the overall Type I error rate when multiple comparisons are made.
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What is the absolute value of -5
Answer:
5
Step-by-step explanation:
helpppppppppp meeeeeeeeeee 50points
Answer:
1) 48
2)44
Step-by-step explanation:
Answer: 48 44 Are The Correct Answers
Step-by-step explanation:Hope This Helps
Find the 15th term of the arithmetic sequence whose common difference is d= 7 and whose first term is a1 = 5
Answer:
The 15th term is 103
Step-by-step explanation:
Arithmetic Sequence
An arithmetic sequence is a list of numbers with a definite pattern by which each term is found by adding or subtracting a fixed quantity to the previous term. If n is the number of the term, then:
\(a_n=a_{n-1}+d\)
Where d is called the common difference. If we know the first term, the nth term is calculated by:
\(a_n=a_1+(n-1)*d\)
The question asks us to find the term n=15 of an arithmetic sequence with a common difference d=7 and first term a1=5.
Applying the formula above:
\(a_{15}=5+(15-1)*7\)
\(a_{15}=5+14*7\)
\(a_{15}=5+98=103\)
The 15th term is 103
Find the length of the hypotenuse of a right angle triangle if remaining side are 3 cm and 4 cm.
Answer:
5 cm
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
let h be the hypotenuse , then
h² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )
h = \(\sqrt{25}\) = 5
Nonnegativity conditions are examples of a. Lower bounds on the decision variables. b. Upper bounds on the decision variables. c. Nonlinear constraints. d. Infeasible models.
Nonnegativity conditions impose b. upper bounds on the decision variables in an optimization problem. The correct answer is b. Upper bounds on the decision variables.
They ensure that the variables cannot take negative values and are typically used when the variables represent quantities that cannot be negative, such as quantities of goods or resources.
By setting an upper bound of zero or a positive value, the nonnegativity condition restricts the feasible region of the optimization problem to only include nonnegative values for the decision variables.
This is a common constraint in many optimization models to reflect real-world limitations or practical considerations.
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Help! f(x)=2x+3 g(x)=3x+2
Answer:
5x + 5
Step-by-step explanation:
(f + g)(x) = f(x) + g(x)
f(x) + g(x)
= 2x + 3 + 3x + 2 ← collect like terms
= 5x + 5
Answer:
Step-by-step explanation:
(f+g)(x)=f(x)+g(x)
(f+g)(x)=2x+3+3x+2
(f+g)(x)=5x+5
It looks like they want you to type just
5x+5
write an expression to represent the measure of an angle supplementary to the given angle
Answer:
80+100=supplementary, right? A sup. angle is 2 angles making 180 digres.
Nora's savings account has a balance of $3979. After 4 years, what will the amount of interest be at 12% compounded semiannually?
Answer:
$7798.84
Step-by-step explanation:
please mark brainliest if correct
Use the diagram below to find the measure of each angle (4 questions)
Angle EAB *
Angle CAF *
Angle BAD *
Write a rule about the distance from the center of dilation to the vertices of the pre-image and image.
(Hint: Your rule should include the phrase "scale factor")
Answer:
If A is the distance from the center of the dilation to a vertex of the pre-image, and B is the distance from the center of the dilation to the corresponding vertex on the image, then B/A is the scale factor of the dilation.
Step-by-step explanation:
The rule about the distance from the center of dilation to the vertices of the pre-image and image is \((x,y) \to (kx,ky)\)
DilationDilation involves changing the size of a shape.
The ruleAssume the image is shape B, and the pre-image is shape A
Scale factorThe scale factor would be to divide the side length of the image, by the corresponding side length of the pre-image
So, the scale factor (k) is:
\(k = \frac BA\)
Hence, the rule of dilation is:
\((x,y) \to (kx,ky)\)
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(properties of the moment generating function). We defined the moment generating function (m.g.f.) of a random variable X as ψχ(t)-E(eXt) which is a function of t (note: I sometimes use vx (t) instead of Mx(t) as the name of a moment generating function). More explicitly, it has one of the two forms or allr if X is a discrete or continuous random variable, respectively. (a) Show that, for any r.v. X, it is the case that bx(0)-1. (So the m.g.f. is always defined at t-0.) (b) Show that if Y-aX +b, where a and b are constants, then py (t-ebtPX (at) (c) Show that if the random variables X and Y are independent and Z = X + Y, then ψ2(t)-PX(t)Vy(t). Hint: you have to use the fact that if two random variables X and Y are independent and f and g are two functions, then the two new random variables U = f(X) and V = g(Y) are also independent.
In this problem, we consider the moment generating function (m.g.f.) of a random variable X, denoted as ψχ(t). We are asked to prove three properties of the moment generating function.
(a) To show that ψχ(0) = 1 for any random variable X, we substitute t = 0 into the definition of the moment generating function: ψχ(t) = E(e^(Xt)). When t = 0, we have e^(Xt) = e^(0) = 1. Therefore, ψχ(0) = E(1) = 1.
(b) To prove that ψy(t) = e^(bt) * ψχ(at) when Y = aX + b, we substitute the expression for Y into the definition of the moment generating function: ψy(t) = E(e^(Yt)). Using the linearity of the expectation, we have ψy(t) = E(e^((aX + b)t)). By rearranging terms and using the fact that e^(bx) = (e^x)^b, we can write ψy(t) = e^(bt) * E(e^(aXt)), which is equal to e^(bt) * ψχ(at).
(c) To show that ψz(t) = ψχ(t) * ψy(t) when X and Y are independent and Z = X + Y, we start with the definition of the moment generating function for Z: ψz(t) = E(e^(Zt)). By using the property of independent random variables and the definition of Z, we can express ψz(t) as the product of the moment generating functions of X and Y: ψz(t) = E(e^(Xt) * e^(Yt)) = E(e^(Xt)) * E(e^(Yt)) = ψχ(t) * ψy(t).
Thus, we have demonstrated the three properties of the moment generating function as required.
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Answer choices are
-
X=7
X=5
X=9
X=13
Answer:
Step-by-step explanation:
9
_______________ is the value of the best alternative given up when a choice is made.
At the instant when the radius of a cone is 3 inches, the volume of
the cone is increasing at the rate of 9 pi cubic inches per minute. If
the height is always 3 times the radius, find the rate of change of the
radius at that instant.
Answer:
The rate of change of the radius of the cone when the radius is 3 inches is 0.\(\overline 3\) inch/minute
Step-by-step explanation:
The given parameters are;
The radius of the cone = 3 inches
dV/dt = 9·π in.³/min
The height, h = 3 × Radius, r
The formula for the volume of a cone, V is V = 1/3×π×r²×h = 1/3×π×r²×3×r = π·r³
Therefore, we have;
dV/dt = dV/dr × dr/dt
dV/dr =3·π·r²
∴ dr/dt = dV/dt/(dV/dr) = 9·π/(3·π·r²) = 3/r²
When r = 3 inches, we have;
dr/dt = 3/r² = 3/(3²) = 1/3 inch/minute
The rate of change of the radius of the cone when the radius is 3 inches = 0.\(\overline 3\) inch/minute
Merry Christmas! this is my biggest point ever but it's a holiday can you: Please Answer All Of The Questions no link you can save and write on the screenshot to save a lot of your time lol 30! pts and CROWN PLEASE! THIS IS A MATH ASSIGNMENT DUE TODAY!
Answer: there aren’t any questions attached lol maybe try again?
Express in the form n : 1.
Give n as a fully simplified fraction.
20 : 15
Answer:
this is the answer
Step-by-step explanation:
20:15=20/15=4/3=n
Hence, 1:n=3:4
i got the first part but cant figure out the second, help would be appreciated
Answer:
see explanation
Step-by-step explanation:
look at the explanation& answer photo
If a business had sales of $4,000,000, and a margin of safety of 25%, the break-even point was:
a. $3,000,000
b. $12,000,000
c. $1,000,000
d. $5,000,000
If a business had sales of $4,000,000, and a margin of safety of 25%, the break-even point was is c. $1,000,000.
The margin of safety is the difference between the actual or expected sales and the break-even point. In this case, if the margin of safety is 25%, it means that the business is generating sales that are 25% higher than the break-even point.
To calculate the break-even point, we can use the following formula:
Break-even point = Fixed costs / Contribution margin ratio
The contribution margin ratio is the difference between the sales price and variable costs, divided by the sales price. We don't have enough information to calculate it directly, but we can use the margin of safety to estimate it.
If the margin of safety is 25%, it means that the contribution margin ratio is 25% of the sales price. So, the variable costs must be 75% of the sales price, and the contribution margin ratio is 25%/100% = 0.25.
We know that the sales are $4,000,000, but we don't know the fixed costs. However, we can use the break-even formula to solve for it:
$1,000,000 = Fixed costs / 0.25
Fixed costs = $250,000
Therefore, the break-even point is $250,000 / 0.25 = $1,000,000.
Based on the given information, the break-even point for the business with sales of $4,000,000 and a margin of safety of 25% is $1,000,000.
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Rocky Mountain Tire Center sells 10,000 go-cart tires per year. The ordering cost for each order is $35, and the holding cost is 40% of the purchase price of the tires per year. The purchase price is $25 per tire if fewer than 200 tires are ordered,$17 per tire if 200 or more, but fewer than 8,000, tires are ordered, and $13 per tire if 8,000 or more tires are ordered.
a) How many tires should Rocky Mountain order each time it places an order?
b) What is the total cost of this policy?
a) Rocky Mountain should order 200 tires each time it places an order.
b) The total cost of this policy is $17,160.
a) To determine how many tires Rocky Mountain should order each time, we need to consider the different price levels and find the point where it is most cost-effective to order. Let's analyze the three price levels:
If fewer than 200 tires are ordered: The purchase price is $25 per tire.
If 200 or more, but fewer than 8,000 tires are ordered: The purchase price is $17 per tire.
If 8,000 or more tires are ordered: The purchase price is $13 per tire.
Since the ordering cost is $35 per order, it is most cost-effective to order the maximum quantity that falls within the second price level, which is 200 tires.
b) To calculate the total cost of this policy, we need to consider the ordering cost and the holding cost. The holding cost is 40% of the purchase price per tire per year. Let's calculate the total cost:
Total holding cost = (Purchase price per tire * Quantity ordered * Holding cost rate) / 2 = (($17 * 10,000 * 0.4) / 2) + (($13 * 2,000 * 0.4) / 2) = $34,000 + $5,200 = $39,200
Total cost = Total ordering cost + Total holding cost = (Ordering cost per order * Number of orders) + Total holding cost = ($35 * (10,000 / 200)) + $39,200 = $1,750 + $39,200 = $40,950
Therefore, the total cost of this policy is $40,950.
Rocky Mountain Tire Center should order 200 tires each time it places an order, resulting in a total cost of $40,950 for this policy. This ordering quantity and cost analysis allows Rocky Mountain to make efficient and cost-effective decisions in managing their inventory.
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One factor of f (x ) = 5 x cubed 5 x squared minus 170 x 280 is (x 7). What are all the roots of the function? Use the Remainder Theorem. X = –4, x = –2, or x = 7 x = –7, x = 2, or x = 4 x = –7, x = 5, or x = 280 x = –280, x = –5, or x = 7.
To solve the problem we must know about the Remainder Theorem.
What is the Remainder theorem?According to the remainder theorem, when a polynomial P(x) is divided by (x-t) then the remainder of the division is equal to P(t). If P(t)=0, then the (x-t) is the factor of the polynomial.
The roots of the function are -7, 2, and 4.
Given to us
One factor of f (x) = \(5x^3+5x^2-170x+280\) is (x +7).What is the quotient of the function?We know (x+7) is the factor of the function, f(x) = \(5x^3+5x^2-170x+280\),
therefore,
\(f(x) =5x^3+5x^2-170x+280 = [(x+7) \times quotient] + Remainder\)
As (x-2) is the factor of the function, therefore, the remainder will be zero for the equation,
\(\rm quotient=\dfrac{5x^3+5x^2-170x+280}{(x+7)}\)
\(\rm quotient=5x^2-30x+40\)
What are the factors of the function?Solving the quadratic equation,
\(5x^2-30x+40\\\text{Dividing the equation by 5}\\\\=x^2-6x+8\\=(x-2)(x-4)\)
Hence, the roots of the function are -7, 2, and 4.
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Answer:
its b
Step-by-step explanation:
Please help me I need to finish this :)
Find the missing values in the ratio table. Then write the equivalent ratios.
Fish 6 3
Snails 2
4
15
The equivalent ratios are 6 : 2, 3 : ___ __ : 4, 15 : .
The missing values in the ratio table are presented by completing the ratio table as follows;
Fish: \({}\) 6, 3, 12, 15
Snails: \({}\) 2, 1, 4. 5
What is a ratio table?A ratio table is a table used to present or describe the relationship between two quantity values.
The given ratio table of Fish to Snails is presented as follows;
Fish: \({}\) 6, 3, _, 15
Snails: \({}\) 2, _, 4. _
Whereby the ratio of fish to snails is a constant, c, we have, from the first data point;
\(c = \dfrac{6}{2} = 3\)
Which gives;
\(c = \dfrac{The \ number \ fishes}{The \ number \ of \ snails}\)
The number of fishes = 3 × The number of snails
When the number of fishes = 3, we have;
\(3 = \dfrac{3}{The \ number \ of \ snails}\)
\(\therefore \ The \ number \ of \ snails = \dfrac{3}{3} = 1\)
When the number of fishes = 3, the number of snails = 1
Similarly, when the number of snails = 4, we have;
The number of fishes = 3 × 4 = 12
When the number of fishes = 15, then; \(3 = \dfrac{15}{The \ number \ of \ snails}\)
\(\therefore The \ number \ of \ snails = \dfrac{15}{3} = 5\)
The completed table is therefore;
Fish: \({}\) 6, 3, 12, 15
Snails: \({}\) 2, 1, 4. 5
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Please help me with 24For the following exercises, write the equation for the hyperbola in standard form if it is not already, and identify the vertices and foci, and write equations of asymptotes.
Given the equation,
\(-9x^2+72x+16y^2+16y+4=0\)Complete squares as shown below,
\(\begin{gathered} -9x^2+72x-a^2=-(9x^2-72x+a^2)=-9(x^2-8x+b^2) \\ \end{gathered}\)Thus,
\(\begin{gathered} \Rightarrow-9x^2+72x-a^2=-9(x^{}-4)^2 \\ \Rightarrow a^2=16\cdot9=144\Rightarrow a=12 \\ \Rightarrow-9x^2+72x-144=-9(x^{}-4)^2 \end{gathered}\)Similarly,
\(\begin{gathered} 16y^2+16y=16(y^2+y) \\ \Rightarrow16(y+\frac{1}{2})^2=16(y^2+y+\frac{1}{4}) \end{gathered}\)Therefore,
\(\begin{gathered} -9x^2+72x+16y^2+16y+4=0 \\ \Rightarrow-9(x-4)^2+16(y+\frac{1}{2})^2+4=-144+4 \\ \Rightarrow-9(x-4)^2+16(y+\frac{1}{2})^2=-144 \end{gathered}\)Finally, the standard form is.
\(\begin{gathered} \Rightarrow-\frac{(x-4)^2}{16}+\frac{(y+\frac{1}{2})^2}{9}=-1 \\ \Rightarrow\frac{(x-4)^2}{16}-\frac{(y+\frac{1}{2})^2}{9}=1 \end{gathered}\)As for the vertices, foci, and asymptotes,
\(\begin{gathered} c=\pm\sqrt[]{16+9}=\pm5 \\ \text{center:}(4,-\frac{1}{2}) \\ \Rightarrow\text{foci:}(4-5,-\frac{1}{2})_{},(4+5,-\frac{1}{2})_{} \\ \Rightarrow\text{foci:}(-1,-\frac{1}{2}),(9,-\frac{1}{2}) \end{gathered}\)Foci: (-1,-1/2), (9,-1/2)
Vertices
\(\begin{gathered} \text{center:}(4,-\frac{1}{2}),\text{vertices:}(4\pm a,-\frac{1}{2}) \\ \text{vertices:}(4+4,-\frac{1}{2}),(4-4,-\frac{1}{2}) \\ \text{vertices:}(8,-\frac{1}{2}),(0,-\frac{1}{2}) \end{gathered}\)Vertices: (8,-1/2), (0,-1/2)
Asymptotes:
\(\begin{gathered} y=\pm\frac{3}{4}(x-4)-\frac{1}{2} \\ \Rightarrow y=\frac{3}{4}x-\frac{7}{2} \\ \text{and} \\ y=-\frac{3}{4}x+\frac{5}{2} \end{gathered}\)Asymptotes: y=3x/4-7/2 and y=-3x/4+5/2
A runner is running a 10 km race. It takes her 17.5 minutes to reach the 2.5 km mark. at that rate, how long would it take her to run the whole race?
Answer:
time = 70 minutes
2 Divided by 1 / 5. Rlly need help on this
Answer:
The answer will be 10
Step-by-step explanation:
2/1/5=10
A card is selected to from a standard deck of 52 card what are the odds of selecting a red 9
The odds of selecting a red 9 is 1/26.
Probability of an event E is represented by P(E) can be defined as (the number of favorable outcomes) / (Total number of outcomes).
Given the total number of cards in a standard deck = 52
there can be only two red9 as one 9 from heart and one red from diamond.
So the number of outcome for red 9 =2
the probability of odds of selecting red 9 is \(\frac{2}{52}\) which can be further simplified into \(\frac{1}{26}\).
Therefore , The odds of selecting a red 9 is 1/26.
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