will give brainliest need quickly though

Answer:

19219.48

Step-by-step explanation:

16540x0.162+16540

The original price would be 100%

It was marked down 16.2%

100 % - 16.2% = 83.8%

The price you paid was 83.8% of the original price.

To find the original price divide the amount you paid by the percentage of the original price:

16,540 / 0.838 = 19.737.47

Original price: $19,737.47

Answer:

Option 1

Step-by-step explanation:

3x - 7y = -7y + 3x

They have simply been moved to opposite ends of the equation.

Answer:

7 1/2

Step-by-step explanation:

3 / x = 2 / 5

Cross multiply

15 = 2x

x = 7 1/2

Answer:

He will use 7 1/2 tbs

Step-by-step explanation:

I hope this help you!

The Vertex is : (-6, -30)

The X-intercepts are : Approximately (-10.89, 0) and (-1.11, 0)

The Y-intercept is : (0, 6)

The Axis of symmetry is : x = -6

The functions Domain: is All real numbers

The Range is : All real numbers greater than or equal to -30.

To sketch the graph of the quadratic function \(f(x) = x^2 + 12x + 6,\) we can start by identifying the vertex, x-intercepts, y-intercept, axis of symmetry, domain, and range.

To find the vertex, we can use the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic equation in standard form\((ax^2 + bx + c).\)

In this case, a = 1, b = 12, and c = 6.

Applying the formula, we get x = -12/(2 \(\times\) 1) = -6.

To find the y-coordinate of the vertex, we substitute this x-value into the equation:\(f(-6) = (-6)^2 + 12(-6) + 6 = 36 - 72 + 6 = -30.\)

So, the vertex is (-6, -30).

To determine the x-intercepts, we set f(x) = 0 and solve for x. In this case, we need to solve the quadratic equation \(x^2 + 12x + 6 = 0.\)

Using factoring, completing the square, or the quadratic formula, we find that the solutions are not rational.

Let's approximate them using decimal values: x ≈ -10.89 and x ≈ -1.11. Therefore, the x-intercepts are approximately (-10.89, 0) and (-1.11, 0).

The y-intercept is obtained by substituting x = 0 into the equation: \(f(0) = 0^2 + 12(0) + 6 = 6.\)

Thus, the y-intercept is (0, 6).

The axis of symmetry is the vertical line that passes through the vertex. In this case, it is the line x = -6.

The domain of the function is all real numbers since there are no restrictions on the possible input values of x.

To determine the range, we can observe that the coefficient of the \(x^2\) term is positive (1), indicating that the parabola opens upward.

Therefore, the minimum point of the parabola occurs at the vertex, (-6, -30).

As a result, the range of the function is all real numbers greater than or equal to -30.

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Answer:

Step-by-step explanation:

A. x + 5=12

7x = 21

B. b - 2/3 = 5/6

1/5m = 20

C. 45 = 3(x + 1)

D. 22.5 = 1.5x

E. Mark has $20 in his bank account. He saves $5 each week. How much money does Mark have in his account after 9 weeks? Use w to represent the number of weeks and t to represent the total amount Mark has after any number of weeks.

Given- Square root of 14 multiplied by square root of 10

To find - which is equivalent to the product below

Explanation - We can write the square root of 14 as

\(\sqrt{14} =\sqrt{2} \sqrt{7}\)

and square root of 10 as

\(\sqrt{10} =\sqrt{2} \sqrt{5}\)

Now

\(\sqrt{14} \sqrt{10} =\sqrt{2} \sqrt{5} \sqrt{2} \sqrt{7} =2\sqrt{35}\)

Hence the choice is equivalent is D

Final answer - The final answer is D

Answer:

\(\displaystyle \frac{\pi(5e^4+8e^2-1)}{2e^4}\approx9.526\)

Step-by-step explanation:

This can be solved with either the washer (easier) or the shell method (harder). For the disk/washer method, the slice is perpendicular to the axis of revolution, whereas, for the shell method, the slice is parallel to the axis of revolution.  I'll show how to do it with both:

Shell Method (Horizontal Axis)

\(\displaystyle V=2\pi\int^d_cr(y)h(y)\,dy\)

Radius: \(r(y)=2-y\) (distance from y=2 to x-axis)

Height: \(h(y)=2-(-\ln y)=2+\ln y\) (\(y=e^{-x}\) is the same as \(x=-\ln y\))

Bounds: \([c,d]=[e^{-2},1]\) (plugging x-bounds in gets you this)

Plugging in our integral, we get:

\(\displaystyle V=2\pi\int^1_{e^{-2}}(2-y)(2+\ln y)\,dy=\frac{\pi(5e^4+8e^2-1)}{2e^4}\approx9.526\)

Washer Method (Parallel to x-axis)

\(\displaystyle V=\pi\int^b_a\biggr(R(x)^2-r(x)^2\biggr)\,dx\)

Outer Radius: \(R(x)=2-e^{-x}\) (distance between \(y=2\) and \(y=e^{-x}\))

Inner Radius: \(r(x)=2-1=1\) (distance between \(y=2\) and \(y=1\))

Bounds: \([a,b]=[0,2]\)

Plugging in our integral, we get:

\(\displaystyle V=\pi\int^2_0\biggr((2-e^{-x})^2-1^2\biggr)\,dx\\\\V=\pi\int^2_0\biggr((4-4e^{-x}+e^{-2x})-1\biggr)\,dx\\\\V=\pi\int^2_0(3-4e^{-x}+e^{-2x})\,dx\\\\V=\pi\biggr(3x+4e^{-x}-\frac{1}{2}e^{-2x}\biggr)\biggr|^2_0\\\\V=\pi\biggr[\biggr(3(2)+4e^{-2}-\frac{1}{2}e^{-2(2)}\biggr)-\biggr(3(0)+4e^{-0}-\frac{1}{2}e^{-2(0)}\biggr)\biggr]\\\\V=\pi\biggr[\biggr(6+4e^{-2}-\frac{1}{2}e^{-4}\biggr)-\biggr(4-\frac{1}{2}\biggr)\biggr]\)

\(\displaystyle V=\pi\biggr[\biggr(6+4e^{-2}-\frac{1}{2}e^{-4}\biggr)-\frac{7}{2}\biggr]\\\\V=\pi\biggr(\frac{5}{2}+4e^{-2}-\frac{1}{2}e^{-4}\biggr)\\\\V=\pi\biggr(\frac{5}{2}+\frac{4}{e^2}-\frac{1}{2e^4}\biggr)\\\\V=\pi\biggr(\frac{5e^4}{2e^4}+\frac{8e^2}{2e^4}-\frac{1}{2e^4}\biggr)\\\\V=\pi\biggr(\frac{5e^4+8e^2-1}{2e^4}\biggr)\\\\V=\frac{\pi(5e^4+8e^2-1)}{2e^4}\approx9.526\)

Use your best judgment when deciding on what method you use when visualizing the solid, but I hope this helped!

Answer:

9-6r

Step-by-step explanation:

9(1−r)+3r

Use the distributive property to multiply 9 by 1−r.

9−9r+3r

Combine −9r and 3r to get −6r.

Answer: 9−6r

Answer:

-6r + 9

Step-by-step explanation:

9( 1 - r ) + 3r

9 - 9r + 3r

9 - 6r

So, the answer is -6r + 9

Answer:

y=12, x=6

Step-by-step explanation:

y+3=15

3x-6=12

Answer:

1:3

Step-by-step explanation:

because you would get 1 of 3 flavours

The sacks in factory A = 3386

and the sacks in factory B = 17414

What is a system of equation?

A finite set of equations for which common solutions are sought is referred to as a set of simultaneous equations, often known as a system of equations or an equation system.

Here, we have

Given: There was a total of 20800 sacks of rice in Factory A and Factory B.

Let us assume

The sacks in factory A = x

and the sacks in factory B = y

∴ x + y = 20800

y = 20800 - x

After of 3/4, the sacks of rice in Factory A and 3/5 of the sacks of rice in Factory B were sold.

∴ 3x/4 + 3y/5 were sold

x -3x/4 + y - 3y/5 = x + 1040 + x

x -3x/4 + 20800 - x -3/5(20800 - x) = 2x + 1040

-3x/4 + 20800 - 12480 + 3x/5 = 2x + 1040

-43x/20 = -7280

x = 3386.046

y = 17413.95

Hence, The sacks in factory A = 3386

and the sacks in factory B = 17414

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Answer:

2+ m-1+m..............

Answer:

13

Step-by-step explanation:

w = -8 -5 =-13=13

The number of meetings they attended in the last five years (x) and the number of papers they submitted to peer reviewed journals (y) during the same period is \(-8.6+3.15\).

What is formula for slope and intercept is?

\($$\begin{aligned}& b=\frac{n \sum x y-\left(\sum x\right)\left(\sum y\right)}{n \sum x^2-\left(\sum x\right)^2} \\& a=\bar{y}-b \bar{x} \\& \hat{y}=a+b x\end{aligned}$$\)

The slope is

\($$\begin{aligned}b & =\frac{n \sum x y-\left(\sum x\right)\left(\sum y\right)}{n \sum x^2-\left(\sum x\right)^2} \\& =\frac{12 \times 318-(12 \times 4)(12 \times 4)}{12 \times 232-(12 \times 4)^2} \\& =3.15\end{aligned}$$\)

The intercept is

\($$\begin{aligned}a & =\bar{y}-b \bar{x} \\& =4-3.13 \times 4 \\& =-8.6\end{aligned}$$\)

The regression equation is

\($$\begin{aligned}\hat{y} & =a+b x \\& =-8.6+3.15 x\end{aligned}$$\)

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\((\stackrel{x_1}{-5}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-5)}}} \implies \cfrac{3 +5}{1 +5} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{ 4 }{ 3 }\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{ \cfrac{ 4 }{ 3 }}(x-\stackrel{x_1}{(-5)}) \implies y +5 = \cfrac{ 4 }{ 3 } ( x +5) \\\\\\ y+5=\cfrac{ 4 }{ 3 }x+\cfrac{ 20 }{ 3 }\implies y=\cfrac{ 4 }{ 3 }x+\cfrac{ 20 }{ 3 }-5\implies {\Large \begin{array}{llll} y=\cfrac{ 4 }{ 3 }x+\cfrac{5}{3} \end{array}}\)

Given:

Score in first game = 28 points

Score in second game = 35 points

To find his percentage increase, use the formula below:

Input values into the formula above to find the percentage increase.

Thus, we have:

Therefore the percent of increase from the first game to the second game is 25%.

ANSWER:

25%

The difference between the selling price and the cost price is the profit he earned.

Profit = Selling Price - Cost Price

Profit = $216 - $180

Profit = $36

To find the percentage profit, we need to calculate what proportion of the cost price the profit represents, and express that as a percentage :

Percentage Profit = (Profit : Cost Price) * 100%

Percentage Profit = ($36 : $180) * 100%

Percentage Profit = 0.2 * 100%

Percentage Profit = 20%

Therefore, his percentage profit is 20%.

The difference between the depths in February and July is 31 feet.

The method of measuring depth depends on what we are trying to measure the depth of. Here are some general methods for measuring different types of depth:

Depth of water: The depth of water can be measured using a sounding device such as a sonar or a simple depth gauge. A sonar uses sound waves to determine the distance from the water's surface to the bottom. A depth gauge is a simple device that measures the distance from the surface of the water to the bottom using a weight and a line.

Depth of a hole: The depth of a hole can be measured using a tape measure or a ruler. Simply insert the measuring device into the hole and measure the distance from the top of the hole to the bottom.

Depth of a trench: The depth of a trench can be measured using a measuring tape or a surveyor's level. Place the measuring device at the edge of the trench and measure the distance from the top of the trench to the bottom.

Depth of a pool: The depth of a pool can be measured using a pool depth marker or by using a measuring tape. A depth marker is usually located on the side of the pool and indicates the depth at various points. Alternatively, you can use a measuring tape to measure the distance from the surface of the water to the bottom of the pool.

Depth of a well: The depth of a well can be measured using a well sounder or a tape measure. A well sounder is a device that sends a signal down the well and measures the time it takes for the signal to bounce back. The time it takes is then used to calculate the depth of the well. Alternatively, a tape measure can be used to measure the distance from the surface of the water to the bottom.

Given, In February, it measured 6 ft deep, or |−6| and in July, it was 25 ft deep, or |−25|.

The difference between the depths in February and July is:

|−6| − |−25| = 6 − (−25) = 6 + 25 = 31

Therefore, the correct choice is B) 31 feet.

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Answer:

e would be 130 because its vertical angles and it has to add up to 180 so f would be 50 im not sure about d yet

Answer:

e = 130º it's a vertical angle

f = 50º it's supplementary to 130º

d = 90º it's a right angle

Answer: The number of essay questions is 9

From the system of linear equation given

m + s = 26 --------------- equation 1

3m + 8s = 123 ----------- equation 2

where m represents the number of multiple question and s represents the number of essay question

To find the value of s, we need to isolate m in equation 1

Equation 1 becomes

m = 26 - s

Substitute the value of m in equation 2

3(26 - s ) + 8s = 123

Open the parenthesis

3 x 26 - 3 x s + 8s = 123

78 - 3s + 8s = 123

collect the like terms

-3s + 8s = 123 - 78

5s = 45

Divide both sides by 5

5s/5 = 45/5

s = 9

Therefore , the number of essay questions is 9

Hi Chloe!

Answer:

The outdoor temperature is -4 degrees.

The indoor temperature is 72 degrees.

Explanation:

We use negative integer to represent loss, below , or withdrawal etc. On the other hand we use positive integers to show gain , above , deposit etc.

Answer:

  160/13 ≈ 12.3 units per second

Step-by-step explanation:

The product of pressure and volume is proportional to temperature, and temperature is 100 when pressure and volume are 10 and 13, respectively. You want to know the rate of change of temperature when volume decreases at 1 per second and pressure increases at 2 per second.

The given proportion can be written with constant of proportionality k as ...

  PV = kT

The value of k is ...

  k = PV/T = (10)(13)/100 = 1.3

Solving the relation for T, we have ...

   T = PV/k = PV/1.3

The rate of change is found by differentiating this product:

  T' = (P'V +PV')/k

  T' = ((+2)(13) +(10)(-1))/1.3 = (26-10)/1.3 = 16/1.3

  T' = 160/13 ≈ 12.3

Temperature is increasing at about 12.3 units per second.

Answer: 6 4/5 pounds

Step-by-step explanation:

Answer:

Step-by-step explanation:

The circumference of a circle is given by the formula:

C = πd

where d is the diameter of the circle. In this case, the diameter is given as 14 cm, so we can substitute that into the formula:

C = π(14 cm)

Multiplying, we get:

C = 14π cm

So the circumference of the circle is 14π cm. The units are centimeters, since circumference is a length measurement.

Answer:

32 degrees

Step-by-step explanation:

Answer:

32 degrees

Step-by-step explanation:

Answer:

Option B

Step-by-step explanation:

Given:

To determine the percentage of the production was out of spec, we need to use the percentage formula (x/y × 100).

\(\implies \dfrac{x}{y} \times 100\)

The value of "x" is the the number of pieces that were out of spec and the value of "y" is the total pieces in the production results.

\(\implies \dfrac{130}{3500} \times 100\)

Simplify the expression to determine the percentage of the pieces that were out of spec.

\(\implies \dfrac{13000}{3500}\)

\(\implies \dfrac{130}{35} = \dfrac{130 \div 5}{35 \div 5} = \dfrac{26}{7} = 3.714... \%\)

When the percentage is estimated to nearest hundredth, we get 3.71%

(Option B)

Answer:

B)  3.71%

Step-by-step explanation:

\(\textsf{130 out of 3500}\sf =\dfrac{130}{3500}\)

To convert to a percentage, multiply by 100:

\(\implies \sf \dfrac{130}{3500} \times 100\%=0.03714.. \times 100\%=3.71\%\)

Answer: 3 ≤ 47

Step-by-step explanation:

The inequality given is 3 ≤ 47.

To determine the solutions to this inequality, we need to find the values of x that satisfy the inequality.

Looking at the options provided:

x = 24: This is not a solution because 24 is less than 47.

x = 51: This is a solution because 51 is greater than or equal to 47.

x = 6: This is not a solution because 6 is less than 47.

x = 99: This is a solution because 99 is greater than or equal to 47.

Therefore, the solutions to the inequality 3 ≤ 47 are x = 51 and x = 99.

Solution :

The function :    \($f: Z_{10} \rightarrow Z_{10}$\)   be a random permutation.

f is a permutation on \($Z_{10}$\) ,  i.e. f is permutation 10.

Now we know that the total number of distinct permutation on to symbolize 10!.

Each of these 10! permutation to a permutation function  \($f: Z_{10} \rightarrow Z_{10}$\)  

Therefore, total number of permutation functions  \($f: Z_{10} \rightarrow Z_{10}$\)   are 10!.

Now we want the total number of permutation functioning :

\($f: Z_{10} \rightarrow Z_{10}$\)   such that  f(0) = 0 and f(1)= 1

Now we notice that when f(0)=0 and f(1)=1, then two symbol '0' and '1 are fixed under permutation f.

So essentially when f(0) = 0 and f(1) = 1, f becomes permutation on 8 symbol.

Total number of permutation functioning  \($f: Z_{10} \rightarrow Z_{10}$\)  , f(0)=0 and f(1)=1 are 8!

Now we want the probability that a random permutation  \($f: Z_{10} \rightarrow Z_{10}$\)   satisfies f(0) = 0 and f(1) = 1.

The number of permutation function  \($f: Z_{10} \rightarrow Z_{10}$\)  , i.e.

The probability that a random permutation  \($f: Z_{10} \rightarrow Z_{10}$\)   satisfies f(0) = 0 and f(1) = 1 is

\($\frac{8!}{10!} = \frac{8!}{10 \times 9\times 8!} =\frac{1}{10 \times 9}=\frac{1}{90}$\)

Therefore, the probability that a random permutation  \($f: Z_{10} \rightarrow Z_{10}$\)   satisfies f(0)= 0 and f(1)=1 is  \($\frac{1}{90}$\)