Why does the sequence of translating and reflections matter?

Answer:

its b

Step-by-step explanation:

got it right on edge

The volume of the metal in the cylinderical pipe given the dimensions of the larger and smaller cylinders is 271.30 mm³.

A cylinder is a three-dimensional object. It is a prism with a circular base.

Volume of a cylinder = nr^2h

Where:

The volume of the metal in the cylinderical pipe = 3.14 x 10 x [(8.4/2)² - 6/2)²] = 271.30 mm³

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This is the PDF of random variable x, which equals y with probability p and z with probability 1 - p.

To find the probability density function (PDF) of random variable x, which is equal to y with probability p and to z with probability 1 − p, we can use the law of total probability.

Let's denote the PDFs of y and z as fy(y) and fz(z), respectively. We want to find the PDF of x, which denote as fx(x).

By the law of total probability, the PDF of x is given by:

fx(x) = p × fy(x) + (1 - p) × fz(x)

This formula means that the PDF of x is a weighted average of the PDFs of y and z, where the weights are the probabilities p and 1 - p, respectively.

Here's the proof:

Case when x = y:

If x = y, it means that y occurs with probability p. So, the contribution to the PDF of x from y is p × fy(x).

Case when x = z:

If x = z, it means that z occurs with probability 1 - p. So, the contribution to the PDF of x from z is (1 - p) × fz(x).

Adding the contributions from both cases,  the overall PDF of x:

fx(x) = p × fy(x) + (1 - p) × fz(x)

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Variance of population is 15; option (B) 20.

To find the variance of a population, we need to use the formula:

Variance = (sum of the squared deviations from the mean) / (number of data values)

First, we need to calculate the squared deviation of each data value from the mean, u = 10. We can do this by subtracting the mean from each data value and then squaring the result:

(8 - 10)^2 = 4

(12 - 10)^2 = 4

(14 - 10)^2 = 16

(16 - 10)^2 = 36

Next, we add up the squared deviations:

4 + 4 + 16 + 36 = 60

Since there are 4 data values, we divide the sum by 4 to get the variance:

Variance = 60 / 4 = 15

Therefore, the variance of the population is 15. None of the choices given match this answer exactly, but (B) 20 is the closest approximation.

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Answer:

1/32 cubic yards

Step-by-step explanation:

Just do 1/4 x 1/4 x 1/2 which is 1/32

Answer:

1/32 yd^3

Step-by-step explanation:

V = lwh

Volume=1/4 x 1/2 x 1/4

Answer:

b, c

Step-by-step explanation:

a) 32=18 - not true

b) 32=18+14 - true

c) 18+32=50 - true

d) 32=-18/16 - not true

If  x and y vary directly, than the relationship between y and x will be →

y = (16/9)x

Direct proportion or direct variation is the relation between two quantities where the ratio of the two is equal to a constant value.

Given is x and y vary directly and y = 32 when x = 18.

Since x and y vary directly, this means that -

y/x = K [constant]

Now, we have -

x = 18

y = 32

Substituting values -

32/18 = K

K = 32/18 = 16/9

y/x = 16/9

y = (16/9)x

Therefore, if  x and y vary directly, than the relationship between y and x will be → y = (16/9)x

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Answer:

See Explanation

Step-by-step explanation:

See comment for correct presentation of the question

Given

\(Expression = 40\% * 75\)

\(Priya = \frac{2}{5} * 75\)

Required

Is Priya correct?

We start by simplifying the expression.

\(Expression = 40\% * 75\)

Express 40% as fraction

\(Expression = \frac{40}{100} * 75\)

Simplify fraction: Divide numerator and denominator by 20

\(Expression = \frac{40/20}{100/20} * 75\)

\(Expression = \frac{2}{5} * 75\)

By comparing:

\(Expression = \frac{2}{5} * 75\)

and

\(Priya = \frac{2}{5} * 75\)

We can conclude that Priya is correct because:

\(40\% = \frac{2}{5}\)

By performing a change of units, we will see that the amount of water left in the can is 3 cups.

We know that the can originally has 8 cups of water.

Then, you use 4 fluid ounces into each of 10 plants, then the amount used is:

40 fluid ounces.

Now we need to do a change of units.

8 fluid ounce = 1 cup.

1 = (1 cup/ 8 fluid ounces)

Then we can rewrite:

40 fluid ounces = 40 fluid ounces*(1 cup/ 8 fluid ounces) = 5 cups.

This means that lee used 5 cups out of the 8 in the can, so the amount of water left is:

8 cups - 5 cups = 3 cups.

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Answer:

Following are the equation to this question:

Step-by-step explanation:

\(\to \frac{\sqrt{(.24)(.76)}}{60} + \frac{(.24)(.76)}{60}\\\\\to \frac{\sqrt{0.1824}}{60} + \frac{0.1824}{60}\\\\\to \frac{0.42708313}{60} + \frac{0.1824}{60}\\\\\to \frac{0.42708313+0.1824}{60} \\\\\to \frac{0.60948313}{60} \\\\\to 0.0101580522\)

Answer:

43 is a prime number so no number except for 43 it's self

Answer: the slope=-60/2299

Step-by-step explanation:

\(\displaystyle\\(-42.49,5.3)\ \ \ \ (3.49,4.1)\\\\\boxed {The\ slope=\frac{y_2-y_1}{x_2-x_1} }\\\\x_1=-42.49\ \ \ \ x_2=3.49\ \ \ \ y_1=5.3\ \ \ \ y_2=4.1\\\\The\ slope=\frac{4.1-5.3}{3.49-(-42.49)} \\\\The\ slope=\frac{-1.2}{3.49+42.49} \\\\The\ slope=\frac{-1.2}{45.98} \\\\The \ slope=-\frac{0.6}{22.99} \\\\The\ slope=-\frac{0.6(100)}{22.99(100)}\\\\The\ slope=-\frac{60}{2299}\)

An IQ of 87 is more unusual than an IQ of 136. This is because the corresponding z-score for an IQ of 87 is further from 0 than the corresponding z-score for an IQ of 136 i.e.,the correct choice is Option B.

To determine which IQ is more unusual, we need to compare their corresponding z-scores.

The z-score measures the number of standard deviations a value is away from the mean.

Given that the IQ test has a mean of 107 and a standard deviation of 10, we can calculate the z-scores for the IQs of 87 and 136.

For an IQ of 87:

z-score = (87 - 107) / 10 = -2

For an IQ of 136:

z-score = (136 - 107) / 10 = 2.9

From the calculated z-scores, we can see that the z-score for an IQ of 87 is -2, indicating that it is 2 standard deviations below the mean.

On the other hand, the z-score for an IQ of 136 is 2.9, indicating that it is 2.9 standard deviations above the mean.

Since a z-score further from 0 indicates a more unusual value, we can conclude that an IQ of 87 is more unusual than an IQ of 136.

Therefore, the correct choice is OB: "An IQ of 87 is more unusual because its corresponding z-score is further from 0 than the corresponding z-score for an IQ of 136."

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Answer:

  36.5 square units

Step-by-step explanation:

There are a number of ways to compute the area of a polygon from the coordinates of its vertices. There are algebraic formulas, geometric methods involving decomposing the figure, and an interesting method described by Pick's theorem.

__

The figure can be enclosed by a rectangle that is 7 units high by 9 units wide. The actual figure is obtained by removing the triangular corners of this rectangle. The areas of those are given by the triangle area formula ...

  A = 1/2bh

Working clockwise from lower left, the triangle base (horizontal) and height (vertical) dimensions are 5×6, 7×1, 2×6, 4×1. That means the area of the triangles is ...

  A = 1/2(5×6 +7×1 +2×6 +4×1) = 1/2(30 +7 +12 +4) = 1/2(53) = 26.5

The area of the bounding rectangle is ...

  A = bh = 9×7 = 63

So, the area of the figure is the difference ...

  A = 63 -26.5 = 36.5 . . . square units

__

The other methods of finding the area have been added as attachments.

Considering the linear equation in slope-intercept form:

The y-intercept of the line is the constant of the equation, in this case, the y-intercept is -1.

The slope of the line corresponds to the coefficient of the x-term, i.e. the value that multiplies x. For this line, the slope is equal to 11.2

Answer:

  14 square units

Step-by-step explanation:

You want the area of the triangle whose vertices are the points A(-11, 4), B(-7, 8), C(-4, 4).

The area of a triangle is given by the formula ...

  A = 1/2bh

where b is the base of the triangle, and h is the height, the1 perpendicular distance to the opposite vertex.

The diagram shows one side is the horizontal line AC. The length of that is the difference of the x-coordinates of the end points:

  b = -4 -(-11) = 7

The opposite vertex, B, has a y-coordinate of 8, so the height of the triangle is ...

  h = 8 -4 = 4

We now have the information we need to use the area formula:

  A = 1/2(7)(4) = 14 . . . . square units

The area of ∆ABC is 14 square units.

__

Additional comment

You can use the diagram and count grid squares to find the dimensions of the triangle.

Option a) $213.34 is the correct answer.

Given that, Suppose that you are 34 years old now and that you would like to retire at the age of 75. Furthermore, you would like to have a retirement fund from which you can draw an income of $70,000 annually. You plan to reach this goal by making monthly deposits into an investment plan until you retire. The amount to be deposited each month needs to be calculated. It is assumed that the annual interest rate is 8% and compounded monthly.

The formula for the future value of the annuity is given by, \(FV = C * ((1+i)n -\frac{1}{i} )\)

Where, FV = Future value of annuity

            C = Regular deposit

            n = Number of time periods

            i = Interest rate per time period

In this case, n = (75 – 34) × 12 = 492 time periods and i = 8%/12 = 0.0067 per month.

As FV is unknown, we solve the equation for C.

C = FV * (i / ( (1 + i)n – 1) ) / (1 + i)

To get the value of FV, we use the formula,FV = A × ( (1 + i)n – 1 ) /i

where, A = Annual income after retirement

After substituting the values, we get the amount to be deposited as $213.34.

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Answer:

2160

Step-by-step explanation:

1872(volume of the cube)+288(volume of the square pyramid)=

2160

v of cube= lwh

v of square pyramid= a² times h/3

please mark brainliest!

Answer:

between 5 and 6

Step-by-step explanation:

You mean the square root of 35? You can get that by pressing the omega symbol at the bottom of the editor. Ω It's the √ the third one on the top row.

Anyway that does nothing to add to your question.

√35 is very nearly √36 which is 6

√35 is between 5 and 6. (Choice 4 down).

the area of the region between the graph of y = 64 − x^3 and the x-axis over the interval [2, 4] is 68 square units.

What is a Graph?

A graph is a visual representation of the relationship between two or more variables on the axes.

To find the area of the region between the graph of the function y = 64 − x^3 and the x-axis over the interval [2, 4], we can use the limit process by approximating the area using rectangles and taking the limit as the width of the rectangles approaches zero.

The first step is to divide the interval [2, 4] into smaller subintervals. Let's choose n subintervals, each with a width of Δx = (4 - 2)/n. This will give us n+1 points: x0 = 2, x1, x2, ..., xn-1, xn = 4.

Within each subinterval, we can choose a representative point, xi*, to evaluate the function y = 64 − x^3. The height of the rectangle corresponding to the ith subinterval will then be the function value at that representative point, which is y(xi*).

The area of the ith rectangle is given by A_i = y(xi*) * Δx.

To find the total area, we sum up the areas of all the rectangles:

A_total = A_1 + A_2 + ... + A_n.

Using the limit process, we can find the area by taking the limit as n approaches infinity:

A_total = lim(n→∞) [A_1 + A_2 + ... + A_n].

To evaluate this limit, we need to express it as a definite integral. Recall that the definite integral of a function f(x) over an interval [a, b] is given by:

∫[a,b] f(x) dx.

In our case, the definite integral that represents the area can be written as:

A_total = ∫[2,4] (64 - x^3) dx.

To compute this integral, we can use standard techniques for integration. Integrating the function 64 - x^3 gives us:

A_total = [64x - (x^4)/4] evaluated from x = 2 to x = 4.

Plugging in the limits, we have:

A_total = [64(4) - (4^4)/4] - [64(2) - (2^4)/4].

Simplifying the expression, we get:

A_total = [256 - 64] - [128 - 4].

Calculating further, we find:

A_total = 192 - 124.

Therefore, the area of the region between the graph of y = 64 − x^3 and the x-axis over the interval [2, 4] is 68 square units.

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The concentration of HCN that would produce a solution with a pH of 4.858 is approximately 1.17 x 10^(-5) mol/L.

To determine the concentration of HCN (hydrogen cyanide) that would produce a solution with a pH of 4.858, we can use the equation relating pH and the concentration of H+ ions in a solution:

pH = -log[H+]

First, we need to calculate the concentration of H+ ions corresponding to a pH of 4.858. Taking the antilog of both sides of the equation, we have:

[H+] = 10^(-pH)

[H+] = 10^(-4.858)

[H+] ≈ 1.17 x 10^(-5) mol/L

Since HCN is a weak acid, it partially dissociates in water, producing H+ ions. The concentration of HCN is equal to the concentration of H+ ions in the solution.

Therefore, the concentration of HCN that would produce a solution with a pH of 4.858 is approximately 1.17 x 10^(-5) mol/L.

Please note that the value provided is an approximation, and it is important to consider the temperature and other factors that might influence the dissociation of HCN in a solution.

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The midpoint of a line segment is known as the midpoint in geometry. It is the centroid of the segment and of the ends, and it is equally distant from both of them. It cuts the section in half.

The midpoint is the point on the middle of the line that is equally distant from the two points if a line is drawn connecting the two points. The midpoint is the point B that lies halfway between any two points, let's say A and C.

The middle value in a group of numbers that are arranged numerically is the median. It is also referred to as the midpoint because it represents the centre of the data collection. You can expect that half of the values on your list will be lower and half will be higher than the median.

To prove x =1.25

H is midpoint of FG

2x +7=12x-5.5

2x+12.5 =12x

12.5 = 10x

1.25 =x

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The given statement is true which is x = 1.25.

To prove x =1.25

H is midpoint of FG

2x +7=12x-5.5

2x+12.5 =12x

12.5 = 10x

1.25 =x

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Answer:

4 spaces to the right

Step-by-step explanation:

hope this helps!

We are given the function;

The input of this function as it is, is x. To evaluate the function at any given output we would simply replace/substitute the value of x with the value provided.

If for example, we are given the function and we have to evaluate its value at f(3), what we will simply do is replace x with two in the function. This is shown below;

Therefore, the value of the function at f(3) is -9.

This is basically the procedure we shall use when evaluating a function at any given output value.

The distance between the landing pads, which is the horizontal distance, is approximately 4.831 miles, and the distance between Pad A and Pad B is approximately 1.418 miles.

Let's denote the distance between the helicopter and Pad A as "x" and the distance between the helicopter and Pad B as "y".

Based on the given information, we can set up the following right triangles:

For Pad A:

In the right triangle formed by the helicopter, Pad A, and the line connecting them, the angle of depression to Pad A is 46 degrees. The opposite side is the distance between the helicopter and Pad A, which is "x". The adjacent side is the horizontal distance between Pad A and Pad B, which we need to find.

For Pad B:

In the right triangle formed by the helicopter, Pad B, and the line connecting them, the angle of depression to Pad B is 16 degrees. The opposite side is the distance between the helicopter and Pad B, which is "y". The adjacent side is the same horizontal distance between Pad A and Pad B.

We can set up the following trigonometric relationships:

For Pad A:

tan(46°) = x / adjacent side (horizontal distance between Pad A and Pad B)

For Pad B:

tan(16°) = y / adjacent side (horizontal distance between Pad A and Pad B)

From the information given, we know that x = 5 miles.

Solving the first equation for the adjacent side, we have:

adjacent side = x / tan(46°)

Substituting the values:

adjacent side = 5 miles / tan(46°)

Calculating the value of the adjacent side, we find:

adjacent side ≈ 5 miles / 1.03553031 ≈ 4.831 miles

Now, using the second equation, we can find the value of y:

tan(16°) = y / adjacent side

Substituting the values:

tan(16°) = y / 4.831 miles

Solving for y, we have:

y ≈ tan(16°) * 4.831 miles

Calculating the value of y, we find:

y ≈ 0.2938 * 4.831 miles ≈ 1.418 miles

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Answer:

18x=7y+1

18x-1=7y

x+33=7y

18x-1=x+33

17x=34

x=2

y=5

Step-by-step explanation:

Answer:

180-25 is the anwser

Step-by-step explanation:

The solution of the function is 3, 3, 7, 15, 15 and 31.

Let's look at the recurrence relation you mentioned: T(n) = { 3 : n< 2 , 2T(n-2) + 1 : n≥ 2. This formula defines the function T(n) recursively, in terms of its previous values. To solve it using the unrolling method, we need to start with the base case T(0) and T(1), which are given by the initial condition T(n) = 3 when n < 2.

T(0) = 3

T(1) = 3

Next, we can use the recurrence relation to calculate T(2) in terms of T(0) and T(1):

T(2) = 2T(0) + 1 = 2*3 + 1 = 7

We can continue this process to compute T(3), T(4), and so on, by using the recurrence relation to "unroll" the formula and express each term in terms of the previous ones:

T(3) = 2T(1) + 1 = 23 + 1 = 7

T(4) = 2T(2) + 1 = 27 + 1 = 15

T(5) = 2T(3) + 1 = 27 + 1 = 15

T(6) = 2T(4) + 1 = 215 + 1 = 31

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Complete Question:

Consider the following recurrences and solve them using the unrolling method

a) T(n) = { 3 : n< 2 , 2T(n-2) + 1 : n≥ 2

Answer:

One is 3x+2 while the other is 2x-1

Step-by-step explanation:

It is opposite to one another

the one with 3x+2 is opposite to the non given one and the one withb2x-1 is opposite

Answer:

Radian 50=0.872665

If the target behavior is recorded whenever it occurs at any point within the scoring interval, the measurement procedure used is called continuous recording or event recording. This method involves observing and recording each instance of the behavior without considering its duration or intensity.

Continuous recording is typically used when the target behavior is discrete and occurs relatively infrequently or has a short duration. With this measurement procedure, each occurrence of the behavior is recorded as a separate event, regardless of when it starts or ends within the scoring interval. Examples of behaviors that can be measured using continuous recording include vocalizations, hand clapping, or instances of aggression.

Continuous recording provides a comprehensive account of the frequency or rate at which the behavior occurs, allowing for a detailed analysis of its occurrence patterns. This method is particularly useful when a precise count of behavior instances is needed and when the duration or intensity of the behavior is not a focus of measurement.

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