Why does the ball rolling westward appear to move east when observed from the outside of the truck

Answer:

I think it's c but don't know for sure

Answer:

1/6 m/s^2      ( about 1/6th gravity of Earth ( 9.81 m/s^2)

Explanation:

Displacement =  yo  +  vo t  - 1/2 a t^2

      -  3.2          = 0     +  0     - 1/2 a(2.0)^2

      -     3.2       =                -2a

             a = 3.2 / 2 = 1.6 m/s^2

An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape. Then the acceleration due to gravity of the moon is 1.6 m/s².

Gravity, which derives from the Latin word gravitas, which means "weight", is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between objects and governs the motion of planets, stars, galaxies, and even light.

Sublunar tides in the oceans are created by the Moon's gravity, much as gravity on Earth imparts weight to physical things (the analogous antipodal tide is generated by inertia).

according to kinematics,

S = ut + 1/2 at²

initial velocity is zero

S = 1/2 at²

putting all the values,

3.2 = 1/2a2²

6.4/4 = a

a = 1.6 m/s²

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The fringe separation of the double-slit interference is 0.884 mm.

When two coherent light waves from separate sources collide, the energy distribution caused by the first wave is altered by the second. The term "interference of light" refers to this alteration in the distribution of light energy brought on by the superposition of two light waves.

Wavelength of light: λ = 680 nm = 680 × 10⁻⁹ m.

Separation between the two slits: d = 0.1 mm = 0.1 × 10⁻³ m.

Screen distance: D = 1.3 m.

Hence, the fringe separation: x = λD/d

= ( 680 × 10⁻⁹)×(1.3 )/(0.1 × 10⁻³ ) m

= 0.000884 m

= 0.884 mm.

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The required speed with which the pebble strikes the ground when the pebble is fired from the slingshot with specified initial velocity is calculated to be 29.53 m/s.

The initial speed of the pebble with which it is fired is 15 m/s.

The height of the building is given as 33 m.

Acceleration due to gravity g = 9.8 m/s²

Now, let us calculate the velocity of the pebble with which it strikes the ground.

The suitable equation of motion is, v² - u² = 2 a s

where,

v is final velocity

u is initial velocity

a is acceleration

s is distance

Entering the values into the above equation by making v as subject, we have,

v² - u² = 2 a s

v² = u² + 2 a s

v = √(u² + 2 a s) = √[15² + 2(9.8)(33)] = √(225 + 646.8) = √871.8 = 29.53 m/s

Thus, the final velocity is calculated to be 29.53 m/s.

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The engine in a small airplane is specified to have a torque of 500 N⋅m. This engine drives a 2.3-m-long, 40 kg single-blade propeller.The engine in a small airplane is specified to have a torque of 500 N⋅m. it takes approximately 18.6 seconds for the propeller to reach 2000 rpm.

To determine how long it takes the propeller to reach 2000 rpm, we need to use the torque equation:

T = Iα

where T is the torque, I is the moment of inertia, and α is the angular acceleration.

We can rearrange this equation to solve for α:

α = T/I

where T is the torque and I is the moment of inertia.

The moment of inertia of a thin rod about its center of mass is given by:

I = (1/12)M\(L^2\)

where M is the mass of the rod (propeller) and L is its length.

In this case, M = 40 kg and L = 2.3 m. Therefore:

I = (1/12)(40 kg)(\(2.3 m)^2\)= 44.33 kg⋅\(m^2\)

The torque T is given as 500 N⋅m.

Substituting the values in the equation for α, we get:

α = T/I = (500 N⋅m) / (44.33 kg⋅\(m^2\)) = 11.27 rad/\(s^2\)

We need to find the time it takes for the propeller to reach 2000 rpm, which is equivalent to 209.44 rad/s. We can use the following kinematic equation to find the time t:

ω = ω0 + αt

where ω0 is the initial angular velocity, which is zero in this case.

Substituting the values, we get:

209.44 rad/s = 0 + (11.27 rad/\(s^2\)) t

Solving for t, we get:

t = 18.6 seconds (rounded to one decimal place)

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Answer:

Microscope

Explanation:

Answer:

1411.8 N/m

Explanation:

From Hooke's law;

F= Ke

Where

F= force on the spring

K= force constant

e = extension

But e= 8.50 × 10^-2m

F= weight = 12.0 kg × 10 = 120 N

K = F/e = 120/8.50 × 10^-2

K= 1411.8 N/m

Answer:

the ohms law says

Explanation:

ohm found that current, voltage, and resistance in a circuit are always related in the same day.

ohms obersivations

ohms found that if the factors that affect resistance are held constant, the resistance of most conductors does not depend on the voltage across them charging the voltage in a circuit changes the current but does not change the resistance regardless of the applied voltage. the ohms law resistance in a circuit is equal to voltage divided by current

resistance =current or voltage =current × resistance

Answer:

I think it would be V=g/t

B. The equivalent resistance of the two resistors is 20.0 ohms.

C. The voltmeter will measure the voltage across the 30.0 ohm resistor.

D. The 30.0 ohm resistor will stop working.

B. The total resistance of the circuit is 60.0 ohms. This is because the 30.0 ohm resistor and the 60.0 ohm resistor are in parallel, and the equivalent resistance of two resistors in parallel is equal to the product of the resistors divided by the sum of the resistors.

R_T = 1/(1/R_1 + 1/R_2 + ...)

In this case, the product of the resistors is:

30.0 ohms × 60.0 ohms = 1800 ohms,

and the sum of the resistors is:

30.0 ohms + 60.0 ohms = 90.0 ohms.

Therefore, the equivalent resistance of the two resistors is 1800 ohms / 90.0 ohms = 20.0 ohms.

C. Meter 1 is an ammeter, and it is connected in series with the 30.0 ohm resistor. This means that the ammeter will measure the current flowing through the 30.0 ohm resistor.

Meter 2 is a voltmeter, and it is connected in parallel with the 30.0 ohm resistor. This means that the voltmeter will measure the voltage across the 30.0 ohm resistor.

D. When the switch is opened, the 30.0 ohm resistor will stop working. This is because the switch is in series with the 30.0 ohm resistor, and when the switch is opened, the circuit is broken.

The 60.0 ohm resistor will continue to work, because it is in parallel with the switch, and the current will continue to flow through the 60.0 ohm resistor even when the switch is opened.

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Speed of the rocket under uniform circular motion is 4.97 × \(10^7\) m/s.

A fictitious force that moves in a circle and is directed away from the center of the circle is called centrifugal force. When measurements are taken in an inertial frame of reference, the force does not exist. It only becomes relevant when we switch from a ground/inertial reference frame to a rotating reference frame.

As the rocket is in uniform circular motion, the gravitational force due to earth and centrifugal force must be equal in magnitude.

The magnitude of gravitational force due to earth, \(F_G = \frac{G M m}{R^2}\)

And, the magnitude of centrifugal force, \(F_C = \frac{mv^2}{R}\)

Where,

G = universal gravitational constant =   6.67 * 10-11 N (m/kg)².

M = the mass of the earth = 5.97 x \(10^{24\) Kg.

m =  the mass of the rocket = 0.5 x \(10^6\)kg.

R = the orbit of the rocket = \({8*10^6}\)m.

For uniform circular motion,

\(\frac{G M m}{R^2}\) = \(\frac{mv^2}{R}\)

⇒ v² = \(\frac{GM}{R}\)

⇒v² =\(\frac{6.67 * 10^{-11 } *5.97 x 10^{24 } }{8*10^6}\)

⇒ v = 4.97 × \(10^7\) m/s.

Hence, the speed of the rocket is 4.97 × \(10^7\) m/s.

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Answer:

I got this question on Ap3x. The answer is Car C...I got it correct

Explanation:

This is because Car C is at the lowest point with the lowest amount of potential energy. Potential energy is stored at it's highest when it has the "potential" to fall, move, or etc. Car C seems to have gone farther down from the high point of the slope, meaning that most of the potential energy transformed into kinetic energy. All in all, Car C has the least potential energy. (Please give Brainliest, or not...your choice but this is the first question that I answered)

The vector potential inside the sphere is μ₀cπ, and the magnetic field inside the sphere is zero. Outside the sphere, the magnetic field intensity is given by B = (μ₀cR²/r²), where R is the radius of the sphere and r is the radial distance from the center of the sphere.

To find the vector potential and intensity of the magnetic field inside and outside a rotating sphere with a constant surface charge density, we can use the Biot-Savart law and Ampere's law.

Inside the sphere:

Inside the sphere, the radial distance r is less than the radius R of the sphere. We consider a circular current loop of radius r within the sphere.

Using the Biot-Savart law, the vector potential (A) at a point inside the sphere due to the circular current loop can be expressed as:

A = (μ₀/4π) ∫(Idl × r)/r²

Since the charge density is constant, the current (I) flowing through the circular loop is proportional to the area of the loop, which can be expressed as I = c × πr².

Substituting this expression for I into the equation for A, we get:

A = (μ₀c/4) ∫(dl × r)/r²

By integrating around the loop, we find that the integral term is equal to 2π, and simplifying further, we obtain:

A = (μ₀c/2r) ∫dl

The integral term on the right-hand side is simply the circumference of the loop, which is 2πr. Substituting this back into the equation, we get:

A = (μ₀c/2r) × 2πr = μ₀cπ

The magnetic field (B) can be obtained from the vector potential using the equation B = ∇ × A. Since the vector potential A is independent of position, the curl of A is zero. Therefore, the magnetic field inside the sphere is zero.

Outside the sphere:

Outside the sphere, the radial distance r is greater than the radius R of the sphere. Using Ampere's law, we can find the magnetic field.

Around a circular loop outside the sphere, the magnetic field is given by:

B = (μ₀I/2πr)

Since the current I is proportional to the area of the loop, which is πR², we have I = cπR². Substituting this expression for I into the equation for B, we get:

B = (μ₀cR²/2πr³) × 2πr = (μ₀cR²/r²)

Therefore, the intensity of the magnetic field outside the sphere is given by B = (μ₀cR²/r²).

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Answer: See the explanation.

Explanation:

When we say a substance is magnetic it means the atoms are lined in a way that created a magnetic field that goes from one side to the other

These are essentially two aspects of the same thing, because a changing electric field creates a magnetic field, and a changing magnetic field creates an electric field. This is the relationship.

Answer: Copper isn't ferromagnetic,

Aluminum isn't ferromagnetic,

String does have a ferromagnetic property

Answer:

2560m or 2.56km (rounded to 3 significant figures)

Explanation:

First, list all known and desired values/variables (initial vertical velocity is 0 as the plane is kept level and vertical acceleration is just gravity):

\(Vertical \ velocity \ (\frac{m}{s} ) = u_{v} = 0 \\\\ Horizontal \ velocity \ (\frac{m}{s} ) = u_{h} = 200\\\\ Vertical \ acceleration \ (\frac{m}{s^{2} } ) = a_{v} = 9.8 \\\\ Horizontal \ acceleration \ (\frac{m}{s^{2} } ) = a_{h} = 0 \\\\ Vertical \ displacement \ (m) = s_{v} = 800 \\\\ Horizontal \ displacement \ (m) = s_{h}\)

The horizontal displacement is going to be the distance travelled, horizontally of course, once the package is released;

First thing to understand is that the vertical and horizontal components are to be dealt with separately because they don't affect each other;

Since there is no horizontal acceleration (ignoring air resistance), we simply require a velocity and time to find the horizontal displacement, using the formula v = d/t (or speed = distance/time);

What we have is the horizontal velocity but we don't have the time taken;

One thing we know is that the time elapsed for the vertical fall of 800m and for the horizontal displacement must be the same;

What we do, therefore, is find the time taken for the vertical displacement using the formula, s = ut + ¹/₂·at², since we know the vertical velocity, height and acceleration:

800 = (0)t + ¹/₂·(9.8)t²

800 = 4.9t²

t² = 163.26...

t = 12.77...

We now have the time taken for the vertical fall and the horizontal displacement, we can use this with the horizontal velocity we know already and get the horizontal displacement:

\(u_{h} = \frac{s_{h} }{t} \\\\ 200 = \frac{s_{h} }{12.77...} \\\\ s_{h} = 200(12.77...) \\\\ s_{h} = 2555.5...\)

mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.

An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.

De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.

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Answer:

b. time-dependent magnetic field.

An electric field is associated with every time-dependent magnetic field.

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Additionally, it refers to a system of charged particles' physical field. The magnetic impact on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field.

An electric field is produced by a time-varying magnetic field. The first law of Faraday states that an electromotive force is always produced when a conductor is exposed to a changing magnetic field. Induced current is the term for the current that results when the conductor circuit is closed.

An electric field is associated with every time-dependent magnetic field.

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Answer:−4.05

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 30 × 2.4

We have the final answer as

Hope this helps you

Explanation:

Power = change in work/change in time

P = 600 joules/ 4 seconds

P= 150 watts

hope this helps :)

A cart at the end of a spring undergoes simple harmonic motion of amplitude A = 10 cm and frequency 5.0 Hz. Assume that the cart is at x = −A when t = 0.

(a) T = 0.2 sec

(b) x(t) = − (10 cm)cos(10π) s⁻¹ t

(c) x(0.050) = 0

(d) x(0.100) = 10 cm

Simple harmonic motion is described as the periodic movement of a point down a straight line with an acceleration that is always toward a fixed point on that line and is proportional to that point's distance from the moving point.

Given that,

frequency (f) = 5.0 Hz

Amplitude (A) = 10 cm

(a) As we know,

T = 1/f

or, T = 1/5 Hz

or, T = 0.2 sec

(b) Because the expression for the cart position is at  x= −A when t=0 , this means that the function which describes the position of the cart is a cosine function because, cos(0)=1.

Notice that the form of the equation that describes the position of a vibrating object is as follows :

x(t) = A cos (2Π/T) × t

Substitute for the values of T=0.2s ; A=10 cm and because x = −A when t = 0,then the function will have a negative sign

x(t) = −(10 cm)cos(10π) s⁻¹ t

(c) the position of the cart at 0.050 s:

x(0.050) = −(10 cm)cos(10π) s⁻¹ × (0.050)

x(0.050) = −(10 cm) (cos π/2)

x(0.050) = 0

(d) the position of the cart at 0.100 s:

x(0.100) = −(10 cm)cos(10π) s⁻¹ × (0.100)

x(0.100) = −(10 cm) (cos π)

x(0.100) = 10 cm

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A. P=IV

Explanation

Electric power is the rate, per unit time, at which electrical energy is transferred by an electric circuit.

the electric powe can be written as follows:

therefore, according to the given choices, the answer is

A. P=IV

I hope this helps you

Answer: An 8 kg book at a height of 3 m has the most gravitational potential energy.

Explanation:

Gravitational potential energy is the product of mass of object, height of object and gravitational field.

So, formula to calculate gravitational potential energy is as follows.

U = mgh

where,

m = mass of object

g = gravitational field = \(9.81 m/s^{2}\)

h = height of object

(A) m = 5 kg and h = 2m

Therefore, its gravitational potential energy is calculated as follows.

\(U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 2 m\\= 98.1 J (1 J = kg m^{2}/s^{2})\)

(B) m = 8 kg and h = 2 m

Therefore, its gravitational potential energy is calculated as follows.

\(U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 2 m\\= 156.96 J (1 J = kg m^{2}/s^{2})\)

(C) m = 8 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

\(U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 3 m\\= 235.44 J (1 J = kg m^{2}/s^{2})\)

(D) m = 5 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

\(U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 3 m\\= 147.15 J (1 J = kg m^{2}/s^{2})\)

Thus, we can conclude that an 8 kg book at a height of 3 m has the most gravitational potential energy.

Answer:

Theres no given?

Explanation:

Well, whatever.

I observed the shift of their sunset time.

Examples like:

January to June = their sunset time increased while

July to December = their sunset time decreased

Answer a

Explanation: a

Answer:

42.5m

Explanation:

How far does sound travel in 0.25 s at a speed of 340 m/s?

d = v*t = 85 m

Sound travels from her hands to the wall, bounces off and comes back.

So the distance traveled is twice the length from the wall.

d = 2L

L = d/2

L = 42.5 m.