why do we use methyl benzoate

In order for X to maintain a larger concentration in the cell in an equilibrium state, it must be a positive-charged ion, or a cation.

equilibrium's definition.

A state of equilibrium among opposing factions or activities that can be rigid (like a body acted on by the energy which result is negative) or fluidity (like a chemical process cyclical where the speeds of both sides are equal).

What does the equilibrium of a body mean?

The body's internal energy and motion are unaffected by the time that passes while it is in balance. If anything is in equilibrium, the forces are equalised.

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Answer:

A physical property because there haven't been a change yet.

Explanation:

Answer:

A solution of NaOH has concentration 1.2M. Calculate the mass of NaOH in g/dm3 in this solution. = 1.2x 40x 1 = 48 g 3.

The mass of NaOH in the solution having concentration of 1.2 M is 48.00 grams per decimeter cubed (g/dm³).

Concentration refers to the amount of a solute dissolved in a given amount of solvent or solution. It is a measure of how much solute is present in a specific volume or mass of the solution.

Concentration can be expressed in various units, such as molarity (moles of solute per liter of solution), mass percent (mass of solute per 100 grams of solution), parts per million (ppm), and others.

Given:

Concentration of NaOH solution = 1.2 M

The molar mass of NaOH (sodium hydroxide) is:

Na: 22.99 g/mol

O: 16.00 g/mol

H: 1.01 g/mol

Total molar mass of NaOH = 22.99 + 16.00 + 1.01

= 40.00 g/mol

1 mole of NaOH = 40.00 g

1.2 moles of NaOH = 1.2 moles × 40.00 g/mole

= 48.00 g/L

1 L = 1 dm³

So, 48.00 g/L = 48.00 g/dm³

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Answer:

Explanation:

Entropy is measure of disorder so as we lower the temperature of gas , its entropy decreases .

Hence at - 200°C entropy of nitrogen will be less than that at - 190°C .

At freezing point ,

entropy of fusion  = latent heat / freezing temperature

= .71 kJ / ( 273 - 210 )

= 710 / 63 J mol⁻¹ K⁻¹ .

= 11.27 J mol⁻¹ K⁻¹ .

entropy of fusion = 11.27 J mol⁻¹ K⁻¹ .

Answer:

wait so dose it acid burn your body I would say hydrogen but I'm probably wrong tell me if I am

Answer:

Hydrogen Bonding (H-Bonding)

To determine the limiting reactant, we need to compare the moles of each reactant and their stoichiometric coefficients in the balanced equation. The balanced equation for the reaction is:

C + SiO2 -> SiC + CO2

First, we convert the masses of carbon (C) and silicon dioxide (SiO2) to moles using their respective molar masses. The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of silicon dioxide (SiO2) is 60.08 g/mol.

Moles of C = mass of C / molar mass of C = 2.50 g / 12.01 g/mol = 0.208 mol C

Moles of SiO2 = mass of SiO2 / molar mass of SiO2 = 2.50 g / 60.08 g/mol = 0.0416 mol SiO2

Next, we compare the moles of each reactant to their stoichiometric coefficients in the balanced equation:

From the balanced equation: 1 mol C reacts with 1 mol SiO2

Since the ratio of moles of C to moles of SiO2 is 0.208 mol C : 0.0416 mol SiO2, we can see that the mole ratio is 5:1. Therefore, for every 5 moles of carbon, 1 mole of SiO2 is required.

Since we have equal moles of carbon and silicon dioxide (0.208 mol C and 0.0416 mol SiO2), we can see that the limiting reactant is SiO2. It is the limiting reactant because there is not enough SiO2 to react completely with the available carbon.

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To find the concentration of sulfide ion when hydroxide ion begins to precipitate, we need to determine the point at which the reaction between sodium sulfide and iron(III) nitrate produces a precipitate.

This reaction can be represented by the following balanced equation: Na2S(aq) + Fe(NO3)3(aq) → FeS(s) + 2NaNO3(aq) First, let's write the balanced equation for the reaction between potassium hydroxide and iron(III) nitrate:

3KOH(aq) + Fe(NO3)3(aq) → Fe(OH)3(s) + 3KNO3(aq)

From the balanced equation, we can see that for every 3 moles of potassium hydroxide (KOH), we get 1 mole of Fe(OH)3(s) precipitate.

Therefore, when hydroxide ion begins to precipitate, the concentration of sulfide ion will be equal to the concentration of potassium hydroxide. Given that the concentration of sodium sulfide is 1.27×10^(-2) M and the concentration of potassium hydroxide is 1.35×10^(-2) M, the concentration of sulfide ion [S^2-] at the point of precipitation is also 1.35×10^(-2) M. Therefore, the concentration of sulfide ion when hydroxide ion begins to precipitate is 1.35×10^(-2) M.

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We are going to assume that the gas mentioned behaves like an ideal gas. The equation that describes the behavior of an ideal gas is as follows:

Where,

P is the pressure of the gas, 358kPa

V is the volume of the gas, 14.0L

R is the gas constant, 8.31 L kPa/mol K

T is the temperature of the gas, 269K

Now, we will clear the number of moles, n.

We replace the known data:

Answer: In the sample of gas there are 2.24 moles

Answer:

17.46× 10²³ molecules

Explanation:

Given data:

Mass of acetic acid = 172.90 g

Number of molecules = ?

Solution:

First of all we will calculate the number of moles of acetic acid :

Number of moles = mass / molar mass

Number of moles = 172.90 g/ 60.1 g/ol

Number of moles = 2.9 mol

Now the given problem will solve by using Avogadro number.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

2.9 mol × 6.022 × 10²³ molecules  / 1 mol

17.46× 10²³ molecules

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The volume will be 2400 ml.

The equation used here will be

M1 × V1 = M2 × V2

M1 = initial concentration

M2 = final concentration

V1 = initial volume

V2 = final volume

So according to the data;

M1 = 12m

M2 = 0.15m

V1 = 30ml

V2 = ?

By putting the values in the equation as follows;

M1 × V1 = M2 × V2

V2 = M1 × V1  / M2

By putting the values given in the question we will solve this question as follows

V2 =  12 × 30 / 0.15

V2 = 360 / 0.15

So the volume used will be;

V2 = 2400 ml

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Depending on the temperature of the solvent, KBr can dissolve in water up to the corresponding solubility limit, which ranges from approximately 53 g/100 mL to 100 g/100 mL.

The solubility of potassium bromide (KBr) depends on the temperature of the solvent in which it is dissolved. In general, the solubility of most salts, including KBr, tends to increase with an increase in temperature.

However, to provide a specific answer, we need to refer to a solubility chart or data for KBr. Here is an approximate solubility of KBr in water at different temperatures:

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Br2 is a strong oxidizing agent that can oxidize Ag to Ag+ but it cannot oxidize Cl- to Cl2. This is because the reduction potential of Br2 is higher than that of Ag.

That Br2 has a greater tendency to gain electrons and be reduced. On the other hand, Cl- has a lower reduction potential than Br2, so Br2 cannot oxidize Cl- to Cl2.

Reduction potentials indicate how likely a species is to gain electrons. A higher reduction potential means a species is more likely to gain electrons (be reduced). For a reaction to occur spontaneously, the oxidizing agent (the one being reduced) should have a higher reduction potential than the reducing agent (the one being oxidized). Comparing the standard reduction potentials.

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The least likely element combination would be hydrogen (H) and sodium (Na) since their ionization energies differ significantly.

To determine the least likely element combination, we need to consider the ionization energies and their relative values. The element combination that is least likely would involve elements with similar or close ionization energies.

Comparing the ionization energies:

1,312 kJ/mol (H) < 1,402 kJ/mol (N) < 1,314 kJ/mol (O) < 496 kJ/mol (Na)

Based on these values, the least likely element combination would be hydrogen (H) and sodium (Na) since their ionization energies differ significantly.

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To calculate the contribution to the molar internal energy from vibrations of the bond of surface-adsorbed CO, we can use the equation:

Uvib = (1/2)RT^2 * (dlnq/dT)

where Uvib is the contribution to the molar internal energy from vibrations, R is the gas constant, T is the temperature (in Kelvin), and q is the vibrational partition function.

Given that the vibrational partition function for surface-adsorbed CO is 0.0204 and the temperature is 300K, we can plug in these values to get:

Uvib = (1/2)(8.314 J/mol*K)(300K)^2 * (dln(0.0204)/dT)

To find dlnq/dT, we can use the relation:

dlnq/dT = θvib/2T^2

where θvib is the vibrational temperature.

Given that the vibrational temperature θvib for surface-adsorbed 12C16O molecule is 2340 K, we can plug in this value to get:

dlnq/dT = (2340 K)/(2*300K^2) = 0.013

Plugging this value back into the original equation, we get:

Uvib = (1/2)(8.314 J/mol*K)(300K)^2 * (0.013) = 68.9 J/mol

Therefore, the contribution to the molar internal energy from vibrations of the bond of surface-adsorbed CO is 68.9 J/mol.

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Answer:

54.44C and 327.59K

Explanation:

The delta notation, indicating the polarity of for the presented covalent bonds are:

δ+   C-O   δ-

δ-   O-Cl   δ+

δ+   O-F   δ-

δ+   C-N   δ-

δ+   C-Cl   δ-

δ-   S-H   δ+

δ+   S-Cl   δ-

How delta notation indicate the polar bonds?

Atoms with varying electronegativities form polar bonds.

The polarity direction is denoted using the delta notation.

A partial negative charge (represented by the symbol -) is acquired by the atom with the higher electronegativity, whereas a partial positive charge (represented by the symbolδ +) is acquired by the atom with the lower electronegativity.

Let's consider the following elements with their electronegativities.

C (2.5)

O (3.5)

Cl (3.0)

F (4.0)

N (3.0)

S (2.5)

H (2.1)

The delta notation for the presented bonds are:

δ+   C-O   δ-

δ-   O-Cl   δ+

δ+   O-F   δ-

δ+   C-N   δ-

δ+   C-Cl   δ-

δ-   S-H   δ+

δ+   S-Cl   δ-

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The  pressure of the gas in the sample container connected to the manometer is 25.6 mmHg. First, we need to convert the height difference of the mercury levels from centimeters to millimeters. There are 10 mm in 1 cm, so the height difference is 3.41 cm x 10 mm/cm = 34.1 mm.

We need to find the pressure difference between the gas in the sample container and the atmospheric pressure. This can be found by subtracting the height difference of the mercury levels from the atmospheric pressure. 99.54 kPa - (34.1 mm / 760 mmHg/kPa) = 99.54 kPa - 0.045 = 99.495 kPa ,Now we can use the conversion factor of 1 mmHg = 0.133 kPa to convert the pressure difference from kilopascals to millimeters of mercury. 99.495 kPa x (1 mmHg/0.133 kPa) = 748.5 mmHg .

First, convert the atmospheric pressure from kPa to mmHg. 1 kPa is approximately equal to 7.50062 mmHg. So, 99.54 kPa × 7.50062 (mmHg/kPa) ≈ 746.99 mmHg. Convert the difference in mercury levels from cm to mm. 1 cm is equal to 10 mm. So, 3.41 cm × 10 (mm/cm) = 34.1 mm. The level of mercury in the arm connected to the atmosphere is 3.41 cm higher than the arm connected to the sample container, meaning the gas pressure is lower than the atmospheric pressure. Subtract the difference in mercury levels from the atmospheric pressure to find the gas pressure: 746.99 mmHg - 34.1 mm = 726.4 mmHg.
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The correct option is A) 2.46 x 10^-4. To find the energy in joules of a mole of photons associated with visible light of wavelength 486 nm, we can use the formula E=hc/λ, where E is energy, h is Planck's constant, c is the speed of light, λ is the wavelength.

First, we need to convert the wavelength from nanometers to meters, so we have λ = 486 nm * (1 m / 10^9 nm) = 4.86 x 10^-7 m. Then, we can plug in the values for h, c, and λ:

E = (6.63 x 10^-34 J·s) * (3.00 x 10^8 m/s) / (4.86 x 10^-7 m)
E = 4.08 x 10^-19 J

This is the energy of one photon with a wavelength of 486 nm. To find the energy in joules of a mole of photons, we need to multiply by Avogadro's number (NA = 6.022 x 10^23 mol^-1):

E = (4.08 x 10^-19 J/photon) * (6.022 x 10^23 photons/mol)
E = 2.46 x 10^5 J/mol

This is a relatively large amount of energy, which is why visible light can have effects on chemical reactions and biological processes.

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The particles of liquid have enough kinetic energy to easily slide by each other. The correct option is D.

The kinetic-molecular hypothesis stated matter states and is based on the assumption that matter is made up of tiny particulate that are constantly in motion.

This theory adds to the knowledge of observable properties and behaviors of solids, liquids, and gases.

Because they are densely packed and vibrate in place, solids have the lowest kinetic energy.

Since liquids have higher kinetic energy, the particles slide past each other. Because gases have the most kinetic energy, they float around in the air.

Particles in liquids are very close together and move randomly throughout the container.

Due to the shorter distances between particles, particles move rapidly in all orientations but strike with each other more frequently than in gases.

Thus, the correct option is D.

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Answer:

3.52 moles are equal to 21.2 ×10²³ molecules

Explanation:

Given data:

Number of moles of oxygen fluoride = 3.52 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

1 mole contain 6.022×10²³ molecules

3.52 mol ×6.022×10²³ molecules / 1 mol

21.2 ×10²³ molecules

Thus, 3.52 moles are equal to 21.2 ×10²³ molecules .

I’m sorry that I couldn’t write it, brainly kept saying that I have inappropriate words for some reason.

Answer:

If I remember correctly, 0.0149991895187944

Explanation:

hope this helps:)

Two approaches to calculate the number of carbon monoxide molecules in 45 pg are using Avogadro's number or molar mass.

1) Approach using Avogadro's number:

Determine the molar mass of carbon monoxide (CO). The molar mass of carbon is approximately 12.01 g/mol, and the molar mass of oxygen is approximately 16.00 g/mol. Therefore, the molar mass of carbon monoxide (CO) is: 12.01 g/mol (carbon) + 16.00 g/mol (oxygen) = 28.01 g/mol

Convert the given mass of carbon monoxide to moles. 45 pg = 45 x 10⁻¹² g (since 1 pg = 10⁻¹²  g) moles = mass / molar mass moles = 45 x 10⁻¹²  g / 28.01 g/mol

Calculate the number of molecules using Avogadro's number. Avogadro's number states that there are 6.022 x 10²³ molecules in one mole of a substance. Number of molecules = moles x Avogadro's number of molecules = (45 x 10⁻¹²  g / 28.01 g/mol) x (6.022 x 10²³ molecules/mol)

Approach using molar mass

Determine the molar mass of carbon monoxide (CO). The molar mass of carbon monoxide (CO) is calculated as 28.01 g/mol (as explained in Approach 1).

Convert the given mass of carbon monoxide to moles. 45 pg = 45 x 10⁻¹² g (since 1 pg = 10⁻¹²  g) moles = mass / molar mass moles = 45 x 10⁻¹²  g / 28.01 g/mol

Use stoichiometry to calculate the number of molecules. The balanced chemical equation for carbon monoxide (CO) is: 1 mole of CO = 6.022 x 10²³molecules of CO

Since the stoichiometry is 1:1, the number of molecules is equal to the number of moles. Number of molecules = 45 x 10⁻¹²  g / 28.01 g/mol

Both approaches involve using the molar mass of carbon monoxide and Avogadro's number to convert mass to moles and then to molecules.

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Answer:

molecular recognition based on structural complementarity

Explanation:

Enzymes work on the basis of a lock and key model. The substrates on which enzymes act are specifically tailored to suit the shape of the enzyme.

As such, the enzyme just fits into the substrate in the same way as the right key fits into a lock.

Hence, molecular recognition based on structural complementarity is the basis for the specificity of enzyme activity.

The following are the factors that influence the body's ability to absorb minerals:

The type of minerals the body contains.

supplements that are consumed without food.

Mineral excretion loss.

Nutritional factors and nutrient intake.

the person's state of health.

The bioavailability of oxide forms of trace minerals is typically the lowest, while the sulphate salts of these minerals have a bioavailability of 100%. Complete bioavailability of trace minerals is provided by sulphate salts, which improves flock performance.

The body needs zinc (Zn), copper (Cu), selenium (Se), chromium (Cr), cobalt (Co), iodine (I), manganese (Mn), and molybdenum as essential trace elements.

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Neon

The noble gas that is used by researchers to cool down samples for analysis is neon.

What is a noble gas?

A noble gas is a group of elements that make up group 18 of the periodic table. Noble gases are nonreactive, nonmetallic chemical elements that have full outer electron shells (thus making them highly stable) and low reactivity. The six noble gases are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn).

What are the uses of neon?

Neon has a number of applications in a variety of fields, some of which are listed below:

Electronics: neon is used in high-voltage indicators, lightning arresters, and electronic equipment as a low-pressure gas.

Neon lamps are used in night glow signs and decorative lighting for homes and businesses. Lasers: Neon gas is used in gas lasers, which are frequently used in medical equipment and research laboratories.

Radiometric dating: Radon-222, a decay product of radium-226, can be used to date rocks and fossils.

Neon is used by researchers to cool down samples for analysis.

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Answer:

N2+ 3H2－> 2NH3

2Fe + 6HCl －> 3H2 + 2FeCl3