Why do gas molecules move at different speeds at a given temperature?

Answers

Answer 1

Answer:

Gas molecules move at different speed at a given temputure bc as temp increases they move faster

Explanation:

they move faster bc they gain kinetetic energy


Related Questions

what is the name of the organic compound with structural formula of nine carborns and sisteen hydrogens ?

Answers

The  name of the organic compound with structural formula of nine carbons and sixteen hydrogens  depends on different factors

What is the organic compound?

The nomenclature of the organic molecule comprising nine carbons and sixteen hydrogens is determined by the arrangement of its atoms as well as the nature of the chemical bonds linking them together. Cyclononane is a circular formation of nine carbon atoms.

An organic substance belongs to a group of chemicals that have carbon atoms linked to each other and other atoms through covalent bonds, and are present in the biological cells. Organic compounds contain usual elements such as carbon, as well as hydrogen, oxygen, and nitrogen.

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A 0.43g samle of KHP required 24.11cm of NaOH for neutralization. Calculate the molarity of NaOH

Answers

Answer:

0.083 M

Explanation:

We'll begin by calculating the number of mole in 0.43 g of KHP (potassium hydrogen phthalate, C₈H₅O₄K). This is can be obtained as follow:

Mass of C₈H₅O₄K = 0.43 g

Molar mass of C₈H₅O₄K = (8×12) + (5×1) + (16× 4) + 39

= 96 + 5 + 64 + 39 = 204 g/mol

Mole of C₈H₅O₄K =?

Mole = mass / molar mass

Mole of C₈H₅O₄K = 0.43 / 204

Mole of C₈H₅O₄K = 0.002 mole

Next, we shall determine the number of mole of NaOH required to react with 0.43 g (i.e 0.002 mole) of KHP. This can be obtained as follow:

C₈H₅O₄K + NaOH → C₈H₄O₄KNa + H₂O

From the balanced equation above,

1 mole of KHP reacted with 1 mole of NaOH.

Therefore, 0.002 mole of KHP will also react with 0.002 mole of NaOH.

Next, we shall convert 24.11 cm³ to L. This can be obtained as follow:

1000 cm³ = 1 L

Therefore,

24.11 cm³ = 24.11 cm³ × 1 L / 1000 cm³

24.11 cm³ = 0.02411 L

Finally, we shall determine the molarity of NaOH. This can be obtained as follow:

Mole of NaOH = 0.00 2 mole

Volume = 0.02411 L

Molarity of NaOH =?

Molarity = mole /Volume

Molarity of NaOH = 0.002 / 0.02411

Molarity of NaOH = 0.083 M

Which statement describes how the binary ionic compound KBr is named?

Answers

Which statement describes how the binary ionic compound KBr is named? The metal is named first, and the name is unchanged. Which of these is a property of a substance that is composed of atoms that are held together by ionic bonds?

B. The metal is named first and the name is unchanged.

A 95,000g refrigerator is located on the 70th floor of a skyscraper (300 meters above the ground) What is the
potential energy of the refrigerator?

Answers

Answer:

285 kJ

Explanation:

potential energy

= m g h

= 95,000 g × 10 m/s² × 300 meters

= 95 kg × 10 m/s² × 300 meters

= 950 kgm/s² × 300 meters

= 285,000 J

= 285 kJ

Calculate the volume that a 0.75 mol sample of gas will occupy at 295k and a pressure of 1.5 atm

Answers

The volume occupied by the 0.75 mole of the gas at 295 K and a pressure of 1.5 atm is 12.11 L

How do i determine the volume occupied by the gas?

From the question given above, the following data were obtained:

Number of mole of gas (n) = 0.75 moleTemperature of gas (T) = 295 KPressure of gas (P) = 1.5 atmGas constant (R) = 0.0821 atm.L/molKVolume of occupied by gas (V) =?

Ideal gas equation is written as shown below:

PV = nRT

When we input the given parameters, the volume occupied is obatined as:

1.5 × V = 0.75 × 0.0821 × 295

Divide both sides by 4.31

V = (0.75 × 0.0821 × 295) / 1.5

V = 12.11 L

Thus, from the above calculation, we can say that the volume occupied by the gas is 12.11 L

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What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic
weight of Ca is 40.1 and the atomic weight of Br is 79.9.
A) 452.3 g
B) 53.04 g
C) 44.2 g
D) 88.4 g

Answers

Answer:

Below

Explanation:

Let n be the quantity of matter in the Calcium Bromide

● n = m/ M

M is the atomic weight and m is the mass

M of CaBr2 is the sum of the atomic wieght of its components (2 Bromes atoms and 1 calcium atom)

M = 40.1 + 2×79.9

● 0.422 = m/ (40.1+2×79.9)

●0.422 = m/ 199.9

● m = 0.422 × 199.9

● m = 84.35 g wich is 88.4 g approximatively

88.4 g approximatively is  the mass in grams of 0.442 moles of calcium bromide, CaBr2 ,therefore option (d) is correct.

What do you mean by mass ?

Mass is the amount of matter that a body possesses. Mass is usually measured in grams (g) or kilograms (kg) .

To calculate mass in grams of 0.442 moles of calcium bromide, CaBr2,

Let n be the quantity of matter in the Calcium Bromide

M is the atomic weight and m is the mass

n = m/ M

M of CaBr2 is the sum of the atomic weight of its components

Mass of  Ca = 40.1 , Mass of Br = 79.9

M = 40.1 + 2×79.9

  0.422 = m/ (40.1+2×79.9)

  0.422 = m/ 199.9

  m = 0.422 × 199.9

  m = 84.35 g which is 88.4 g approximatively .

Thus ,88.4 g approximatively is  the mass in grams of 0.442 moles of calcium bromide, CaBr2 , hence option (d) is correct .

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When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely

Answers

When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.

What is super saturation?

Super saturation occurs with a chemical solution when the concentration of a solute exceeds the concentration specified by the value equilibrium solubility.

Additional water into the soil will cause the soil to be super saturated and eventually runs off due to the steepness of the area.

Thus, when the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.

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What nucleus emits an alpha particle and forms Th-234?

Answers

Answer:

Uranium-238

Explanations:

The process by which an atomic nucleus looses energy by radiation is known as radioactivity.

An alpha particle, have an atomic number of 2 and a mass number of 4 as shown;

\(_2^4He\)

When this is combined with Th-234, it forms Uranium-238. This shows that the uranium nucleus emits alpha particle to form Th-234 according to the chemical equation below;

\(_{92}^{238}U\rightarrow_2^4He+_{90}^{234}Th\)

Imagine that you mixed flour, sugar, salt, baking powder, eggs, and milk in a bowl while making cake batter. Would the order in which you mixed the ingredients affect the total mass of the mixture?

ANSWER THIS EMEDEITLY PLEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEAAAASE


thank you ✍(◔◡◔)


(ps. this is the closest subject to science (that deals with volume, mass, and matter you know that kind of stuff )that I could find

Answers

Answer:

Explanation:

no becuase everything goes in the mass shouldn't change unless you put extra

Milk of magnesia, which is an aqueous suspension of magnesium hydroxide, is used as an antacid in the reaction below. How many molecules of HCl would have to be present to form 34.52 g of MgCl₂?
Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

Answers

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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Mothballs are composed primarily of the hydrocarbon naphthalene (C10H8 ). When 1.312 g of naphthalene burns in a bomb calorimeter, the temperature rises from 24.710 ∘C to 30.188 ∘C .Find ΔrH for the combustion of naphthalene at 298 K . When considering phase, assume all reactants and products are at 298 K.

Answers

Explanation:

To find ΔrH for the combustion of naphthalene, we can use the equation: ΔrH = qp / n

where qp is the heat absorbed by the bomb calorimeter and n is the number of moles of naphthalene.

First, we need to find qp. We can use the formula: qp = mcΔT

where m is the mass of naphthalene, c is the specific heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that m = 1.312 g, c = 4.184 J/g°C, and ΔT = 30.188 - 24.710 = 5.478 °C

qp = (1.312 g)(4.184 J/g°C)(5.478 °C) = 27.948 J

Next, we need to convert the mass of naphthalene to moles. We can use the molar mass of naphthalene, which is 128.17 g/mol

n = m / M = 1.312 g / 128.17 g/mol = 0.0103 mol

Finally, we can use the equation ΔrH = qp / n to find ΔrH:

ΔrH = qp / n = 27.948 J / 0.0103 mol = 2713.8 J/mol

Therefore, the ΔrH for the combustion of naphthalene at 298 K is 2713.8 J/mol.

In addition to the 4Ps of marketing, it is also important to consider the sustainability, ethics and social responsibility in the twenty-first century marketplace when launching a campaign. It is important to consider the impact the product, service or campaign has on the environment and the society, how it is produced and how it is marketed to the public. Additionally, understanding the target audience, their demographics and what they value is important to create an effective marketing campaign.

Which describes any compound that has at least one element from group 17
A.halide
B.noble gas
C.meltalloid
D.Transition metal

HELP

Answers

The answer is A. (Halide)

show the formation of oxygen molecule​

Answers

Answer: H2o

Explanation:

because oxygen is in the air

H2O is the correct answer because I went to school and I know this

during a baseball game the sound of the bat hitting the ball

Answers

During a baseball game, the sound of the bat hitting the ball can be heard in most parts of the stadium. That sound is weaker at greater distances. The cause of this phenomenon is inverse-square law.

What is sound?

Sound is a physical disturbance from an equilibrium condition that travels via an elastoplastic medium. A completely subjective definition of sound, as perceived by the ear, is also viable, but it is not especially informative and is overly limited, because it is important to speak of noises which can be heard by the auditory system, such as those produced by dog whistles or sonar technology.

The inverse-square law, that states that the strength of a sound wave is inversely related to the square of the distance to the source, is the cause of this phenomena. The strength of such sound wave reduces as the distance to the source rises.

Therefore,  the cause of this phenomenon is inverse-square law.

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4. Which type of molecule forms a bilayer within a cell membrane?

Answers

Answer:

The answer is Phospholipids.

Explanation:

A phospholipid bilayer. Phospholipids spontaneously form stable bilayers, with their polar head groups exposed to water and their hydrophobic tails buried in the interior of the membrane.

I really hope this helps!! Have an amazing day!! :)

Which of the following is the best description of the music Mussorgsky wrote to accompany the Gnome?
A. Bright, upbeat, lively
B. Major key, legato, fermatas
C. Dark, choppy, dynamic contrasts
D. Long flowing phrases

Answers

Dark, choppy, dynamic contrasts the following is the best description of the music Mussorgsky wrote to accompany the Gnome.

The composer Modest Mussorgsky is known for creating unique Russian music such as Night on Bald Mountain Pictures at an Exhibition, and the opera Boris Godunov. Mussorgsky is famous for his operas and songs. He discovered a new spelling of the voice that is highly melodic and yet also corresponds to the Russian language. His most famous opera is Boris Godunov.

He wrote the overture Night on the Mountain. Modest Petrovich Mussorgsky 1839-1881 was one of five Russian composers known as the Mighty Fists for their nationalist tendencies. Mussorgsky was one of music's greatest originals. Everything he composed was conceived in relation to the natural rhythms, melodies, and harmonies of Slavic folk music. Art songs by contrast are intended for performance by professional singers or at least carefully trained singers usually accompanied by a piano or instrumental ensemble.

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PLEASE HELP WILL MARK BRAINLEST!!!!

PLEASE HELP WILL MARK BRAINLEST!!!!

Answers

Answer: c????????

Explanation:

If you titrate 35 drops of vinegar to the equivalence point with 43 drops of 0.600M sodium hydroxide what is the concentration of the vinegar?

Answers

To determine the concentration of vinegar (acetic acid) based on the titration with sodium hydroxide, we need to use the concept of stoichiometry and the volume and concentration of the sodium hydroxide solution.

Let's assume that each drop of the sodium hydroxide solution is approximately 0.03 mL. Based on this assumption, the volume of sodium hydroxide solution used would be:

Volume of NaOH = 43 drops × 0.03 mL/drop = 1.29 mL

Now, we need to determine the moles of sodium hydroxide used in the titration. Using the volume and concentration of the sodium hydroxide solution:

Moles of NaOH = Volume of NaOH (L) × Concentration of NaOH (mol/L)

             = 1.29 mL × (1 L / 1000 mL) × 0.600 mol/L

             = 0.000774 mol

Since acetic acid (CH3COOH) and sodium hydroxide (NaOH) react in a 1:1 molar ratio, the moles of acetic acid present in the vinegar can be determined as well:

Moles of CH3COOH = Moles of NaOH = 0.000774 mol

Finally, we need to calculate the concentration of acetic acid (vinegar) in the solution. Assuming the volume of vinegar is 1 L:

Concentration of CH3COOH = Moles of CH3COOH / Volume of CH3COOH

                      = 0.000774 mol / 1 L

                      = 0.000774 M

Therefore, the concentration of the vinegar (acetic acid) is approximately 0.000774 M.

Two structures found in a plant cell but not in an animal cells are​

Answers

Answer:

The plant cell has a cell wall, chloroplasts, plastids, and a central vacuole—structures not found in animal cells.

Explanation:

that is my answer

An isomer of C3H7O undergoes one step oxidation reaction. Answer the following questions due to this reaction.
a) Write a full symbol equation for this reaction.b) Name the proper reagent and catalyst for this reaction.c) Why do you think there is no need to remove the product from the reaction vessel?

Answers

Answer:

C3H7O + O2 → CO2 + H2O

Explanation:

a) The full symbol equation for the oxidation reaction of an isomer of C3H7O can be represented as:

C3H7O + O2 → CO2 + H2O

b) The proper reagent for this oxidation reaction is O2 (oxygen gas). The catalyst required for this reaction depends on the specific conditions. Common catalysts used for oxidation reactions include transition metals such as platinum (Pt), palladium (Pd), or copper (Cu).

c) There is no need to remove the product (CO2 and H2O) from the reaction vessel because they are typically in the gas or liquid phase and do not significantly interfere with the reaction. The product gases can be easily vented out of the vessel, while the liquid water can be left in the reaction mixture. Additionally, the product CO2 is a stable and inert gas, which does not pose any hazards in most cases. Therefore, it is often not necessary to remove the products after the reaction is complete.

"The following name is incorrect. Select the correct IUPAC name.
3−ethyl−3−octen−5−ol
a) 6-ethyl-5-octen-4-ol
b) 6,6-diethyl-5-hexen-4-ol
c) 1,1-diethyl-1-hexen-1-ol"

Answers

The actual iupac name for the chemical compounds is 6,6-diethyl-5-hexen-4-ol. The International Union of Pure and Applied Chemistry is a worldwide association of National Adhering Organizations.

Striving to establish vocabulary and nomenclature in order to enhance the chemical sciences. The organisation belongs to the International Science Council (ISC). Chemical compounds are made up of numerous similar molecules (or molecular entities) that contain atoms from multiple chemical elements and are joined by chemical bonds. Therefore, a molecule made up of atoms from only one element is not a compound. Multiple types of atoms are joined together by chemical bonds to form compounds. Compounds can become simpler substances as a result of chemical processes. Water (H2O) and table salt are examples of compounds (NaCl).

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The mass of evaporating dish

Answers

\(\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}\)

The mas.s of evaporating dish is 21.345g B.

ThanksHope it helps

A water treatment tablet contains 20.0 mg of tetraglycine hydroperiodide, 40.0% of which is available as soluble iodine. If two tablets are used to treat 1.00 liter of drinking water, what is the concentration in ppm of iodine in the treated water

Answers

Answer:

\(16\ \text{ppm}\)

Explanation:

Mass of one tablet = 20 mg

Mass of two tablets = \(2\times 20=40\ \text{mg}\)

Percent that is soluble in water = 40%

Mass of tablet that is soluble in water = \(0.4\times 40=16\ \text{mg}\)

So, mass of solute is \(16\ \text{mg}\)

Density of water = 1 kg/L

Volume of water = 1 L

So, mass of 1 L of water is \(1\times 1=1\ \text{kg}=1000\ \text{g}\)

PPM is given by

\(\dfrac{\text{Mass of solute}}{\text{Mass of solvent}}\times 10^6=\dfrac{16\times 10^{-3}}{1000}\times 10^6\\ =16\ \text{ppm}\)

Hence, the concentration of iodine in the treated water \(16\ \text{ppm}\).

The store paid 4.50 for a book and sold it for $7.65.what is the profit as a percent of the cost to the store? A. 3. 15% b. 58.8% c. 70% d. 315%

Answers

Answer: This would be C.) 70%

Explanation:

Iron-59 which is used to diagnose anaemia has a half life of 45days, what fraction of it is left in 90 days

Answers

Answer:

0.25 of the original

Explanation:

(0.5)^(90/45)

The fraction of iron-59 after 90 days is 0.25.

Iron-59 decays following first-order kinetics. Given the half-life (\(t_{1/2}\)) of 45 days, we can calculate the rate constant (k) using the following expression.

\(k = \frac{ln2}{t_{1/2}} =\frac{ln2}{45day} = 0.015 d^{-1}\)

For first-order kinetics, we can find the fraction of Fe ([Fe]/[Fe]₀) after and an elapsed time (t) of 90 days, using the following equation.

\(\frac{[Fe]}{[Fe]_0} =e^{-k \times t } = e^{-0.015 d^{-1} \times 90 d } \approx 0,25\)

The fraction of iron-59 after 90 days is 0.25.

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Identify the reducing agent in the following reaction: 2Ca + 2H₂O => Ca(OH)2 + H₂
H₂
H₂O
Ca(OH)2
Ca

Answers

In terms of oxidation number, oxidation can be defined as the chemical change in which there occurs an increase in the oxidation number of an atom. Reduction may be defined as a chemical change in which there occurs a decrease in the oxidation number of an atom. The correct option is D.

An oxidizing agent is a substance which suffers a decrease in the oxidation number of one or more of its elements and a reducing agent is a substance which suffers an increase in the oxidation number of one or more of its elements.

In the reaction, oxidation state of 'Ca' increases from 0 to +2, so calcium is oxidized and acts as a reducing agent.

Thus the correct option is D.

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Which bone is located between the incus and the inner ear?

cochlea

stapes

incus

malleus

Answers

Answer: The answer is incus

You add 5.7 g of iron to 25.20ml of water and observe that the volume of the iron and water together is 25.92ml calculate thw density of the iron

Answers

Answer:

7.92gml-1

Explanation:

water=25.20ml

water+iron=25.92ml

iron=5.7g

P=mass/volume (formula of density)

mass=5.7g

volume=25.92-25.20

=0.72ml

p=5.7/0.72

=7.92gml-1

Given:

Initial volume of water = 25.20mL

Volume of water after iron is added = 25.92mL

Mass of iron = 5.7g

So, the volume of iron = 25.92mL - 25.20mL = 0.72mL

∴ Density of iron will be

Density = Mass/Volume

Density = 5.7g / 0.72mL

Density = 7.91 g/mL

What is density in short answer?

The density of a substance is the relationship between its mass and how much space it takes up. Density equals the mass of the substance divided by its volume, D = m/v.

What is the SI unit of density?

Though SI unit of density is kg/m³ solids, g/ml for liquids and g/L for gases.

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Balanced or Unbalanced

K+2MgBr=KBr+Mg

Answers

Unbalanced because NaBr + CaF2 → NaF + CaBr2

How do I go about solving a Nuclear Equation?

How do I go about solving a Nuclear Equation?

Answers

Answer:

How do amoeba respire.

How do plants respire.

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twenty marbles are in bag. ten red, five blue, three green, two white. if four marbles are drawn out of bag without replacement. what is the probability that all four colors will be represented in the sample Read the passage from Animal FarmWhich statement about the passage best reflects theinfluence of a totalitarian dictator?the inability of the animals to sleep nightx the increased discomfort the animals feelthe continued belief that the key was stolenthe refusal to capture SnowballSuddenly, early in the spring, an alarming thing wasdiscovered Snowball was secretly frequenting the farmby night! The animals were so disturbed that they couldhardly sleep in their stalls. Every night, it was said, hecame creeping in under cover of darkness andperformed all kinds of mischief. He stole the corn, heupset the milk pails, he broke the eggs, he trampledthe seedbeds, he gnawed the bark off the fruit trees.Whenever anything went wrong it became usual toattribute it to Snowball. If a window was broken or adrain was blocked up, someone was certain to say thatSnowball had come in the night and done it, and whenthe key of the store-shed was lost, the whole farm wasconvinced that Snowball had thrown it down the well.Curiously enough, they went on believing this evenafter the mislaid key was found under a sack of meal.The cows declared unanimously that Snowball creptTHE ANSWER IS C Suppose the particle is placed at the 40V equipotential surface along the line connecting the two central positive and negative charges.(Hint: The electric field can be obtained using the 40V and 30V potential difference lines.)1. What is the force on the charged particle if q=80C? (mN) (m-milli 10-3)2. What is the force on the charged particle if it is now located at the 0V potential difference line? (mN) Australia is called the _____ Continent20 points A. 35B. 130C. 70D. 65 What would happen if citizens did not meet their duties and responsibilities? 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Both companies are preparing their financial statements under IFRS.On 31st December 2014 the individual balance sheets of the two entities are the following:Hredit (k$)31/Dec/2014Soll (k$)31/Dec/2014Investment in Soll700-Land and building3001 000Plant and equipment1 000400Inventory400300Receivables600200Cash and equivalent1 000100TOTAL ASSETS:4 0002 000Issued capital10050Share premium-100Retained earnings1 900450Equity:2 000600Long term loans900400Account payables and other short term liabilities1 1001 000Liabilities2 0001 400OWNERS EQUITY + LIABILITY:4 0002 000The following information is relevant (acquisition):1. The issued capital and share premium of both companies are the same since incorporation.2. The movement in the retained earnings of the companies were the following during 2014:HreditSoll1st January 2014 (opening)1000150Net profit (2014)1500300Dividend declared(600)31st December 2014 (closing)1900450The profit of Soll is NOT generated equally during the year. The following table illustrates how the profit was generated during 2014 (in percentage):Period% of RevenueQ1 jan-march20%Q2 april-june10%Q3 july -sep30%Q4 oct-dec40%Total100%The following items that belong to Soll were identified at acquisition of the subsidiary:One of the reasons of the acquisition was to acquire the customer relations of Soll, so Hredit can enter into new markets. These customer relations are recorded in a customer list. A firm that has expertise in this area professionally evaluated the customer list. The fair value of the customer list is said to be 80 k$. The list was extended by Hredit (Hredit wrote up his own information on the list). The list with this addition had a value of 120 k$. The useful life of the list regardless of the fact if it is the extended or the original list is 4 years.Soll had an ongoing litigation for years. The legal advisers of Soll said that there is a very little chance that the company will loose the case so this issue was classified being a contingent liability and was not recognized correctly as a liability in the separate financial statement of Soll. The fair value of this obligation was evaluated to be 15 k$ at the date of the acquisition. By the end of the year the case was closed and unexpectedly the court decided against Soll. Therefore Soll was obliged to pay 60 k$ to the other party. (Noting was recorded yet in the financial statements of Soll due to this matter.)The fair value of net assets of Soll was the same with their book value except the land and buildings. Soll only has a land (under the heading land and building). The fair value of this land at the date of the acquisition was 1 200 k$.Intercompany transactions:5. The members of the group had the following intercompany transactions:a. Hredit sold one of his plants to Soll on 1st July 2014. The cost of this asset was 100 k$ and the book value of the asset was 50 k$ at the date of the sale. The selling price was 90 k$. The remaining useful life of the sold asset was four years at the date of the sale. Soll paid only one-third of the invoice until the end of the reporting period.b. Soll sold inventory to Hredit for 200 k$. The cost of the goods sold was 120 $k. Until the end of the year 25% of these goods were sold to customers outside the entity. On 30th December 2014 Hredit paid 50 k$ to Soll. The payment was only received and credited to the bank account of Soll on 3rd January 2015.6. Hredit calculated that the goodwill on the acquisition is impaired by 44 k$.Prepare the consolidated balance sheet of Hredit Group for 31st December 2014 Two spheres have volumes of 87pi cm and 64pi cm. If the surface area of the smaller sphere is 16pi cm, what is thesurface area of the larger sphere?O 64pi cmO 96pi cmO 128pi cmO 256pi cm Which statement best sums up the most important purpose of the text features in Into the Unknown? They make the text more interesting to read. They tell readers what the main ideas of the text are. They help readers visualize some of the central ideas of the text. The artistic style helps readers understand the time period. what is the value of the expression 8 1/2 minus 2 plus 4 3/4 what happens if diaphragm is not there in the body? can someone help meRachel borrows $2,000 from her bank. At a simple interest rate of 3%, how much does she have to pay back in 5 years? 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