Why are the magnetic fields of superconducting magnets often stronger than those of conventional magnets?

Answer:

rotational kinetic energy

angular momentum

the mechanical energy of frictionless systems

Explanation:

The quantities that are conserved in a movement are extremely useful for the simple resolution of different situations, in addition to the linear movement in the angular movement, some quantities are also conserved.

rotational kinetic energy

angular momentum

the mechanical energy of frictionless systems

Answer:

Decreases

Explanation:

Answer:

Decreases

ExplanatIon:

Answer:

- pendulum use to determine acceleration

Explanation:

by calculating need to understand first the problem

the length is measure to be 2s

the lenght is also 2

2 obtainer on invistigation the most nearly is 8.

Answer:

thermal

Explanation:

I think.Heat and thermal are the same

Answer: The biggest example of heat energy in our solar system is the sun itself. The sun radiates heat to warm us up on the planet earth. When the burner of a stove top is very hot, it is a source of heat energy. ... Automobile fuels such as gasoline are sources of heat energy, as is the hot engine of a race car or a school bus.

Explanation:  Here are some explainations

a) The first speed, 3.5 Hz, can be converted to rad/sec by multiplying it by 2π, the number of radians in one revolution:

3.5 Hz x 2π rad/rev = 22.0 rad/sec

Similarly, the final speed, 2 Hz, can be converted to rad/sec:

2 Hz x 2π rad/rev = 12.6 rad/sec

In order to convert from hertz (Hz) to radians per second (rad/sec), we need to know the number of radians in one revolution. This is equal to 2π, since a full circle is 2π radians. Therefore, we can simply multiply the frequency in Hz by 2π to get the angular velocity in rad/sec.

b) The angular deceleration can be calculated using the formula:

α = (ωf - ωi) / t

where α is the angular deceleration, ωf is the final angular velocity, ωi is the initial angular velocity, and t is the time it takes for the CD to slow down from the initial to the final speed. We know that the CD takes 80 minutes, or 4800 seconds, to slow down from 3.5 Hz to 2 Hz. Using the rad/sec values we found in part (a), we can plug in the numbers:

α = (12.6 rad/sec - 22.0 rad/sec) / 4800 sec ≈ -0.0017 rad/sec²

Note that the negative sign indicates that the CD is decelerating, or slowing down. The value of the angular deceleration is very small, since the CD is slowing down gradually over a long period of time.

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Answer:

at the bottoms of hills because all the potential energy has been converted to kinetic energy, which means more speed

Explanation:

The period of the orbit is 1.19 × 10⁸ seconds

Given the radius of an asteroid in circular orbit = r = 7.29 x 10¹¹ m.

Using Kepler’s third law of planetary motion, The square of the period of revolution of a planet (P) is proportional to the cube of its mean distance (r) from the sun. That is, we can express the relationship as: P² = k × r³, where k is a constant of proportionality.

To solve for P, we can rewrite the equation as: P = √(k × r³)

Since the asteroid is in a circular orbit, the mean distance is equal to the radius of the orbit.

Therefore, k = 4π²/GM, where G is the universal gravitational constant and M is the mass of the sun.

Substituting the values, G = 6.67 × 10⁻¹¹ Nm²/kg²M = 1.99 × 10³⁰ kg

k = 4π²/[(6.67 × 10⁻¹¹ Nm²/kg²) × (1.99 × 10³⁰ kg)] = 1.81 × 10⁻¹⁹ s²/m³

Substitute the value of k and r in the equation:

P = √(k × r³)P = √[(1.81 × 10⁻¹⁹ s²/m³) × (7.29 x 10¹¹ m)³]P = 1.19 × 10⁸ seconds

Therefore, the period of the asteroid’s orbit is 1.19 × 10⁸ seconds.

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The approximate value of tc for an ideal bose gas at a density of 125 kg/m3 is 8.3 * 10¹⁹ K

\(P_{c} = \frac{2mkt^{3/2} }{4 pi h^{2} } * (2.612)\frac{\sqrt{pi} }{2}\)

\(125 kg/m^{3} = \frac{2(6.65*10^{-24})(1.38*10^{-23})^{3/2} }{4pi^{2}(1.05*10^{-34}} *(2.612)\ \frac{sqrt{pi}}{2}\)

Tc = 8.3 * 10¹⁹ K

The substance's mass per unit of volume is its density (also known as specific mass or volumetric mass density). The Latin letter D can also be used to represent density, however the most common sign is (the lower case Greek letter rho). Mass divided by volume is the definition of density in mathematics, where  is the density, m is the mass, and V is the volume. Density is sometimes loosely described as weight per unit volume, although this definition is incorrect technically; the term "specific weight" is more appropriate. An example of this is in the US oil and gas business.

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Calculating the expression, we find that the hyperbolic orbit injection velocity is approximately 6.1293 km/sec. Therefore, the correct answer is 1. DV = 6.1293 km/sec.

To calculate the hyperbolic orbit injection velocity (hyperbolic periapsis speed), we can use the vis-viva equation: V² = Vp² + 2μ/r

Where: V = velocity of the spacecraft in the hyperbolic orbit

Vp = velocity of the planet (Earth) around the Sun

μ = gravitational parameter (1 for canonical units)

r = distance between the spacecraft and the planet (altitude + radius of the planet). Since the spacecraft is departing from Earth, we need to consider the velocity of the planet around the Sun. The velocity of the Earth around the Sun is given by: Vp = sqrt(μ / R)

Where R is the distance between the Earth and the Sun (1 AU).

Substituting the values and solving for V, we have:

V = sqrt(Vp² + 2μ/r)

V = sqrt((sqrt(μ / R))² + 2/r)

V = sqrt(μ / R + 2/r)

Converting the altitude from km to AU, we have:

r = (310 + 6378) km / (1 AU)

Now we can substitute the values into the equation:

V = sqrt(1 / 1 + 2 / r)

Calculating this expression, we find that the hyperbolic orbit injection velocity is approximately 6.1293 km/sec. Therefore, the correct answer is 1. DV = 6.1293 km/sec.

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Answer:

35cm

Explanation:

3500cm

3500 divided by 100

=35cm

that's the answer

Answer: You could tell if you made an error in your calculations by repeating the steps.

Speed of light is the fastest/maximum in vacuum which is equal to 3 × 10^8 m/s, therefore speed of light through any material equal to 4 × 10^8 m/s is physically and theoretically impossible and therefore incorrect.

Explanation:

a) Tina drives approximately 69.93 meters before passing David.

b) Her speed as she passes him is approximately 34.77 m/s.

To find the distance Tina drives before passing David, we can use the equation:

\(\[d = ut + \frac{1}{2}at^2\]\)

where:

d is the distance traveled,

u is the initial velocity (0 m/s for Tina),

a is the acceleration (2.90 m/s² for Tina), and

t is the time.

First, we need to determine the time it takes for Tina to catch up with David. Since David is driving at a constant speed of 31.0 m/s, the time Tina needs to catch up can be found using the equation:

\(\[t = \frac{d}{v}\]\)

where:

\(\(t\)\)  is the time,

\(\(d\) \\\) is the initial distance between Tina and David (0 m), and

v  is the relative velocity of Tina with respect to David (31.0 m/s).

Substituting the values, we find:

\(\[t = \frac{0\,m}{31.0\,m/s} = 0\,s\]\)

Since Tina begins to accelerate at the instant when David passes, she starts from rest and requires no time to catch up.

a) Using the equation for distance, we find:

\(\[d = ut + \frac{1}{2}at^2 = 0 + \frac{1}{2}(2.90\,m/s²)(0\,s)^2 = 0\,m\]\)

Therefore, Tina does not drive any distance before passing David.

b) Since Tina catches up with David at the same instant he passes, her speed is equal to his speed. Thus, her speed as she passes him is approximately 31.0 m/s.

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Tina drives approximately 158.2 meters before passing David. Tina's speed as she passes David is 31.0 m/s.

To find the distance Tina drives before passing David, we need to determine the time it takes for Tina to catch up with David first. We can use the equation:

d = v0t + 0.5at2

Where d is the distance, v0 is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation to solve for t:

t = (v - v0) / a

Substituting the given values:

t = (0 - 31.0 m/s) / (-2.90 m/s²)

t ≈ 10.69 seconds

To find the distance:

d = v0t + 0.5at2

d = 0 + 0.5(-2.90 m/s²)(10.69 s)2

d ≈ 158.2 meters

Therefore, Tina drives approximately 158.2 meters before passing David.

To find Tina's speed as she passes David, we can use the equation:

v = v0 + at

Substituting the given values:

v = 0 m/s + (2.90 m/s²)(10.69 s)

v ≈ 31.0 m/s

Therefore, Tina's speed as she passes David is 31.0 m/s.

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Answer:

WHAT'S YOUR LANGUAGE

I CAN'T UNDERSTAND

Answer:

please translate it.i can't understand it..

Voyager 2 passed closer to the southern magnetic pole of Uranus.

During its flyby of Uranus in 1986. This was determined by the measurements taken by the spacecraft's instruments, which detected the magnetic field of Uranus and allowed scientists to map its magnetic structure.

The spacecraft's trajectory and the data collected indicated that Voyager 2 passed nearer to the southern magnetic pole than the northern one. This encounter provided valuable insights into the magnetic field and overall magnetosphere of Uranus, contributing to our understanding of the planet's unique characteristics and the dynamics of its magnetic environment.

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The three wavelengths that will produce standing waves on this string are 4 m, 2 m, and 1.33 m.

To find the wavelengths that will produce standing waves on a stretched string fixed at both ends, we can use the formula:

λn = 2L/n

where λn is the wavelength of the nth harmonic, L is the length of the string, and n is the harmonic number.

For the fundamental frequency (n = 1), the wavelength would be:

λ1 = 2L/1 = 4 m

For the second harmonic (n = 2), the wavelength would be:

λ2 = 2L/2 = L = 2 m

For the third harmonic (n = 3), the wavelength would be:

λ3 = 2L/3 ≈ 1.33 m

So, the three wavelengths that will produce standing waves on this string are 4 m, 2 m, and 1.33 m.

Now, for a wavelength that would not produce a standing wave pattern, we can consider the case where the wavelength is equal to the length of the string, i.e., λ = L. In this case, the wave will not produce a standing wave pattern because the ends of the string are fixed nodes, and the only possible standing wave pattern is one that has a node at each end. If the wavelength is equal to the length of the string, the only possible pattern would be a single wave with an antinode at the center, which is not a standing wave.

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A wave that can be polarized is a transverse wave.

The reason for this is that in a transverse wave, the direction of the wave's oscillation is perpendicular to the direction of the wave's propagation. This means that the oscillation of the wave can be restricted to a single plane, which is the definition of a polarized wave.

In contrast, a longitudinal wave, in which the direction of oscillation is parallel to the direction of propagation, cannot be polarized because the oscillation cannot be restricted to a single plane. Therefore, only transverse waves, such as light waves and electromagnetic waves, can be polarized.

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Answer:

c is the correct answer

Explanation:

A Rube Goldberg Machine is “a comically involved, complicated invention, laboriously contrived to preform a simple operation.” 2. What are the 6 Simple Machines? A. The 6 Simple Machines are: wedge, screw, lever, wheel and axel, inclined plane and pulley

Answer: it’s actually A

Explanation:

Anything sharp like a knife, is a wedge so the hook thingy is a wedge

The angular magnification of the glass for that person when her eyes are focused at infinity is 2.5.

In the case where the image appears at infinity, let \($\mathrm{i}=-|\mathrm{i}| \rightarrow-\infty$\), so that \($1 / p+1 / 1=1 / p=1 / f$\), we have

\(\mathrm{m}=\frac{\theta^{\prime}}{\theta}=\frac{\mathrm{h} / \mathrm{p}}{\mathrm{h} / \mathrm{P}_{\mathrm{n}}}=\frac{1 / \mathrm{f}}{1 / \mathrm{P}_{\mathrm{n}}}=\frac{\mathrm{P}_{\mathrm{n}}}{\mathrm{f}}=\frac{25 \mathrm{~cm}}{\mathrm{f}}$$\)

With \($\mathrm{f}=10 \mathrm{~cm}$\),

\($$\mathrm{m}_\theta=\frac{25 \mathrm{~cm}}{10 \mathrm{~cm}}=2.5$$\)

At its focal point, the objective lens creates a true image of an extremely distant object. The eyepiece acts as a magnifying glass and creates a virtual picture that the spectator can see. The telescope's angular magnification is m = fo / fe.

The standard formula for focal length looks like this: Image distance and object distance are both provided in millimetres, therefore one focal length equals one image distance plus one object distance.

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About 96 percent of the universe is empty which can't be seen by the scientists.

All the stars, planets and galaxies that can be seen today make up about 4 percent of the universe while on the other hand, the 96 percent is made of materials that astronomers can't see or detect because they are dark in colour. Four percent of the universe can be seen by the scientist due to presence of universe whereas 96 percent of the universe is empty which can't be seen by the scientists.

So we can conclude that 96 percent of the universe is empty which can't be seen by the scientists.

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The car is at rest at \( t = 0 \) seconds, and it reaches a position of 80 feet at \( t = 4 \) seconds.

According to the given table, the position of the car at various times is measured. At \( t = 0 \) seconds, the car is at rest, as indicated by the position of 0 feet. This means that the car has not started moving yet.

As time progresses, we observe that the position of the car increases. For example, at \( t = 2 \) seconds, the car has moved to a position of 40 feet. This indicates that the car is covering a certain distance during each time interval.

At \( t = 4 \) seconds, we see that the car reaches a position of 80 feet. This means that in the time span of 4 seconds, the car has covered a distance of 80 feet.

The given information allows us to understand the relationship between time and position of the car. By analyzing the changes in position over time, we can determine the speed or velocity of the car at different instances.

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Answer: The first one

Explanation:

The average energy per unit volume (u) of the wave is approximately 1.0 x \(10^{-9\) J/m³.

u = I / c

u = 1.0 W/m² / (3.0 x \(10^8\) m/s)

Simplifying the expression, we get:

u = 1.0 x \(10^{-9\) J/m³

A wave is a disturbance that propagates through a medium, transferring energy without causing any net displacement of the medium itself. It can be characterized by its amplitude, wavelength, frequency, and speed. Waves can occur in various forms, including sound waves, light waves, water waves, and electromagnetic waves.

When a wave travels through a medium, the particles of the medium vibrate or oscillate in a periodic manner. This transfer of energy from one particle to another result in the wave's propagation. The amplitude of a wave represents its maximum displacement from its equilibrium position, while the wavelength is the distance between two consecutive points in phase.

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Using the formula 1/f = 1/di + 1/do, where f is the focal length of the lens, di is the distance of the image from the lens, and do is the distance of the object from the lens:
1/40 = 1/di + 1/100

Solving for di:
1/di = 1/40 - 1/100
1/di = (5 - 2)/200
1/di = 3/200
di = 200/3
di = 66.7 cm
Therefore, the image will be located 66.7 cm from the lens.
To find the image location, we can use the lens formula:
1/f = 1/do + 1/di
Here, f = focal length (40 cm), do = object distance (100 cm), and di = image distance (which we need to find).
1/40 = 1/100 + 1/di
Now, solve for di:
1/di = 1/40 - 1/100 = (5-2)/200 = 3/200
di = 200/3 ≈ 66.67 cm
So, the image will be located approximately 66.67 cm from the lens.

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The highest energy molecular process that occurs when a molecule absorbs a photon with specific energies. a) microwave is molecular rotation, b) infrared is molecular vibration, c) visible is electronic excitation, and d) ultraviolet is bond breakage

Microwave, when a molecule absorbs a microwave photon, the highest energy molecular process that occurs is molecular rotation. Microwave radiation causes rotational transitions in molecules, leading to energy changes. Infrared, the highest energy molecular process occurring when a molecule absorbs an infrared photon is molecular vibration. Infrared radiation induces vibrational transitions within the molecule, causing changes in vibrational energy levels.

Visible, when a molecule absorbs a visible photon, the highest energy molecular process is electronic excitation. Visible light promotes electrons to higher energy orbitals within the molecule, resulting in electronic transitions. Ultraviolet for ultraviolet photons, the highest energy molecular process that occurs upon absorption is bond breakage. Ultraviolet radiation has enough energy to break molecular bonds, causing chemical changes in the molecule. So therefore the highest energy  a) microwave is molecular rotation, b) infrared is molecular vibration, c) visible is electronic excitation, and d) ultraviolet is bond breakage.

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In the writing of ionic chemical formulas the value of each ion's charge is crossed over in the crossover rule.

Rules for naming Ionic compounds

The oxidation state of each ion is also important, thus in the crossover rule, the value of each ion's charge is crossed over.

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Answer:

Cause of Inertia of Motion

Explanation:

It can be explained as follows...when the moving bus suddenly stops, the lower part of the body of the passenger contact with the bus suddenly comes to rest while the upper part of the body tends to retain its state of motion due to inertia. As a result, the passenger is thrown forward.

A) The capacitance of the spherical capacitor is 1.45 pF (picofarads), B) The radius of the inner sphere is 3.60 cm. and C) The electric field just outside the surface of the inner sphere is \(2.36 * 10^6 V/m\) (volts per meter).

To calculate the capacitance, we can use the formula C = Q/V, where Q is the charge and V is the potential difference. Plugging in the values, we get \(C = (3.20 * 10^{-9} C)/(250 V) = 1.28 * 10^{-11} F\).

However, since the capacitor is a spherical one, we need to use the formula for the capacitance of a spherical capacitor, which is \(C = (4\pi \epsilon_0)(r_1 r_2)/(r_2-r₁)\), where r₁ and r₂ are the radii of the two shells and ε0 is the permittivity of free space.

Rearranging the formula and plugging in the values, we get \(r_1 = (C/4\pi \epsilon_0)(r_2-r_1)/r_2,\) which gives us r₁ = 3.60 cm.

To calculate the electric field just outside the surface of the inner sphere, we can use the formula

E = \(\frac{Q}{4\pi\epsilon_0 r^2}\), where r is the radius of the inner sphere.

Plugging in the values, we get \(E = (3.20 * 10^{-9} C)/(4\pi\epsilon_0(0.0460 m)^2) = 2.36 * 10^6 V/m.\)

This electric field arises due to the charge on the inner sphere and induces an opposite charge on the outer shell of the capacitor.

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Answer:

Over time

Explanation:

When the waves crash against the rocks (erosion) small bits of rock begin to wear off. Over a lot of years lots of rock would've worn off.

Answer:

when there is high wind e.g hurricane it can cause soil erosion, when there is flood it can cause soil erosion, when there are waves it can wear out the land and cause soil erosion

Explanation:

when there is high wind e.g hurricane it can cause soil erosion, when there is flood it can cause soil erosion, when there are waves it can wear out the land and cause soil erosion