why are fillers added to polymers? • to improve tensile strength. • to improve compressive strength. • to improve flexibility.
• to improve thermal stability. • to improve toughness.

if you work it put you will get the 3rd one I think

Answer:

P₂ = 1.5 atm

Explanation:

Given data:

Initial volume = 270 cm³

Initial pressure = 1atm

Final volume = 180 cm³

Final pressure = ?

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1 atm × 270 cm³= P₂ × 180cm³

P₂ = 270 atm.  cm³/ 180cm³

P₂ = 1.5 atm

The volume of oxygen at STP that will be obtained when 24.5 g of potassiumtrioxochlorate(V) crystals are heated is approximately 6.17 L.

Potassiumtrioxochlorate(V) is a chemical compound with the chemical formula KClO3. It is also known as potassium chlorate or chloric acid, potassium salt.

The chemical formula for potassiumtrioxochlorate(V) is KClO3.

We can start by writing a balanced chemical equation for the reaction :

2KClO3(s) → 2KCl(s) + 3O2(g)

From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2. Therefore, we need to first calculate the number of moles of KClO3 in 24.5g of the compound:

Since 2 moles of KClO3 produce 3 moles of O2, we can use this ratio to calculate the number of moles of O2 produced:

moles of O2 = (3/2) x moles of KClO3 = (3/2) x 0.2 mol = 0.3 mol

Finally, we can use the ideal gas law to calculate the volume of O2 at STP:

PV = nRT

Where

Rearranging the equation, we get:

V = nRT/P = (0.3 mol)(0.08206 L atm/mol K)(273 K)/(1 atm) = 6.17 L

Therefore, the volume of oxygen at STP that will be obtained when 24.5 g of potassiumtrioxochlorate(V) crystals are heated is approximately 6.17 L.

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Approximately 2.89 grams of dry NH₄Cl need to be added to 2.00 L of a 0.500 M solution of NH₃ to prepare a buffer solution with a pH of 8.88.

Use the Henderson-Hasselbalch equation to calculate the required amount of NH₄Cl,

pH = pKa + log([NH₄⁺]/[NH₃])

[NH₄⁺] = [NH₃] x 10^(pH - pKa)

Substituting the given values,

[NH₃] = 0.500 M

pH = 8.88

pKa = 9.24

[NH₄⁺] = 0.500 M x 10^(8.88 - 9.24) = 0.027 M

To calculate the amount of NH₄Cl needed to make 2.00 L of a 0.027 M solution,

moles of solute = molarity x volume (in liters)

moles of NH₄Cl = 0.027 M x 2.00 L = 0.054 mol

The molar mass of NH₄Cl is 53.49 g/mol, so the mass of NH₄Cl needed is,

mass = moles x molar mass = 0.054 mol x 53.49 g/mol ≈ 2.89 g

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Answer:

192mmHg

Explanation:

The partial pressure of O2 in the gas mixture is 192 mmHg. The correct option is a.

What is Partial Pressure?

Partial pressure refers to the pressure exerted by a single gas in a mixture of gases. In a mixture, each gas exerts a partial pressure proportional to its concentration or mole fraction and is independent of the presence of other gases.

Dalton's law of partial pressures states that the total pressure of a gas mixture is equal to the sum of the partial pressures of its individual components.

The total pressure of a gas mixture is the sum of the partial pressures of the individual gases. In this case, the total pressure is given as 755 mmHg, and the partial pressures of Ar and He are given as 174 mmHg and 389 mmHg, respectively.

To find the partial pressure of O2, we subtract the sum of the partial pressures of Ar and He from the total pressure:

Partial pressure of O2 = Total pressure - Partial pressure of Ar - Partial pressure of He

= 755 mmHg - 174 mmHg - 389 mmHg

= 192 mmHg

Therefore, the partial pressure of O2 in the gas mixture is 192 mmHg, which corresponds to option (a).

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Complete question:

The total pressure of an O2-Ar-He gas mixture is 755 mmHg. If the partial

pressure of Ar is 174 mmHg and the partial pressure of He is 389 mmHg,

then the partial pressure of O2 is —

a 192 mmHg

b 282 mmHg

c 366 mmHg

d 563 mmHg

Explanation:

LiCl2 3 M =

in sol. 1 L there is LiCl2 3 mol

if sol. 0.5 L there is LiCl2 0.5×3 = 1.5 mol

LiCl2 = 6.9 + 35.5(2)

= 6.9 + 71

= 77.9 g

Answer:

63.52g of LiCl are in a 3.0 molarity solution of 0.5L

Explanation:

Moles = Molarity x Volume

Molarity = 3.0 mol/L

Volume = 0.5L

Moles = (3.0) x (0.5)

Moles = 1.5

In order to find the grams dissolved in the solution, we must first find the molar mass of Lithium Chloride (LiCl).

Molar mass of LiCl = (6.9) + (35.45) = 42.35g/mol

Now we multiply the moles by the molar mass of LiCl to get the grams of LiCL dissolved in the solution.  

1.5 * 42.35 = 63.52g of LiCl

The stoichiometry of the reaction is 1:2:2 for Q:R:S.

Hence, the correct option is c.

The reaction is Q-2R 2S, which means that for every mole of Q that reacts, 2 moles of R react and 2 moles of S are produced. Thus, the stoichiometry of the reaction is 1:2:2 for Q:R:S.

At the beginning of the reaction, [S] = 0.0 M, [Q] = [R] = 2.0 M.

At time t = t", [S]* = 1.0 M, which means that 1.0 M of S has been produced, and 1.0/2 = 0.5 M of R has been consumed. Since the initial concentration of R was 2.0 M, the concentration of R at time t" is

[R]* = 2.0 M - 0.5 M = 1.5 M

Since the stoichiometry of the reaction is 1:2:2, for every mole of R that reacts, 0.5 moles of Q react. Thus, the concentration of Q at time t" is

[Q]* = 2.0 M - 0.5/2 = 1.75 M

This answer is not one of the options provided, so the correct answer is (c) none of these.

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(a) First, we need to write the combustion reaction for ethanol (CH3CH2OH)

CH3CH2OH + O2 → CO2 + H2O

Then, we need to balance this equation. To do that, remember to start with C, then move on to H and finally balanced the amount of O:

CH3CH2OH + 3 O2 → 2 CO2 + 3 H2O

(b) Since this is a reaction that realeases heat (726.7 kJ /mol of ethanol), we know that is an exothermic reaction and the general scope of an enthalpy diagram would be like this:

Where, for the combustion of ethanol, the reactants would be CH3CH2OH + O2, the products would be CO2 + H2O, and ΔH would be -726.7 kJ/mol

Answer:

which parts electrical charges you are asking ??

The class of mineral that forms when the elements Cl or F are bonded with a metal, as in the mineral halite, is known as a halide.

The mineral halite, which has the chemical formula NaCl, is a prime example of a halide mineral.

It belongs to the halide class, which consists of minerals that are composed of halogen elements (chlorine, fluorine, bromine, iodine, or astatine) bonded with a metal element.

In the case of halite, chlorine (Cl) forms an ionic bond with the metal sodium (Na).

The sodium atom loses an electron to achieve a stable electron configuration, becoming a positively charged ion (Na+), while the chlorine atom gains that electron to form a negatively charged ion (Cl-).

These oppositely charged ions attract each other and form an ionic compound, resulting in the formation of halite.

Halite is a common mineral that is widely distributed and often occurs as evaporite deposits in areas where seawater or saltwater lakes have evaporated.

It is commonly known as rock salt and is used extensively in various industries, including food seasoning, chemical production, and water treatment.

The mineral halite, which forms when the elements Cl or F are bonded with a metal, belongs to the halide class. Halides are a group of minerals composed of halogen elements combined with metal elements through ionic bonding.

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Answer:

Initially,  endoplasmic reticulum plays a key role in the production of protein, while BiP found in the endoplasmic reticulum contains Lysine , Aspartic acid , Glutamic acid  and Leucine sequence.  All these, cause BiP concentration to remain high in the ER (endoplasmic reticulum) hence retained. Making the lumen always concentrated on BiP.

Explanation:

BiP is known as binding protein, that binds two or more molecules together and is found in the endoplasmic reticulum at the lumen due to the absence of glucose.

The endoplasmic reticulum found in fungi cells, plant cells, animal cells, and protists cells, makes and processes proteins.

Lysine , Aspartic acid , Glutamic acid  and Leucine sequence ensures the protein concentration is protected in the endoplasmic reticulum (ER).

The expression to be rearranged K = [CO][Cl₂] [COCI₂]  are x = 0.327 or x = 339.

The expression to be rearranged K = [CO][Cl₂] [COCI₂] is:

(0.156 - x) (0.156 - x) (0.263 + x) = 5.00 × 10⁻²

We will expand and simplify the expression:

(0.156 - x) (0.156 - x) (0.263 + x) = 5.00 × 10⁻²(0.156)² + (0.156)(x) - (x)(0.156) - (x)² (0.263 + x)

= 5.00 × 10⁻²(0.156)² - (0.263)(0.156)(x) - (0.156)(x) + (0.263)(0.156)(x) + x²(0.263 + x) - 5.00 × 10⁻² = 0

After simplifying:

-0.0132302 x² - 0.001002 x + 0.0014256 = 0

This is in the form ax² + bx + c = 0 where a = -0.0132302, b = -0.001002 and c = 0.0014256

Using the quadratic formula, we have:

\(\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]\)

Substituting values, we get:

\(\[x = \frac{-(-0.001002) \pm \sqrt{(-0.001002)^2-4(-0.0132302)(0.0014256)}}{2(-0.0132302)}\]\)

Solving, we get:x = 0.327 or 3.39 × 10²

Therefore, the solutions are x = 0.327 or x = 339.

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Answer:

Robot 1 : 150 J

Robot 2: 40 J

Explanation:

30 N x 5m = 150 J

20 N x 2m = 40 J

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The percent by mass of acetic acid in the vinegar is 2.33%.

Below are the steps to solve the given problem using the data table given below:

Step 1: Calculate the mass of the vinegar. Given,Mass of flask and vinegar solution- 25.17gMass of flask- 15.12gMass of vinegar solution = Mass of flask and vinegar solution - Mass of flask= 25.17 g - 15.12 g= 10.05 g

Step 2: Calculate the moles of NaOH used in the titration.Molarity of NaOH solution is 0.1 M.Moles of NaOH = Molarity × Volume of NaOH usedMoles of NaOH = 0.1 M × 39.00 mL (since the initial volume of NaOH is 0.00 mL)Moles of NaOH = 0.0039 moles

Step 3: Determine the moles of acetic acid used in the reaction.The balanced chemical equation for the reaction between NaOH and acetic acid (the main component of vinegar) is given below:CH3COOH + NaOH → CH3COONa + H2OMoles of NaOH = Moles of CH3COOH (since they react in a 1:1 ratio)Moles of CH3COOH = 0.0039 moles

Step 4: Calculate the mass of acetic acid used in the reaction.Molar mass of acetic acid is 60.05 g/mol.Mass of CH3COOH = Moles of CH3COOH × Molar mass of CH3COOH= 0.0039 moles × 60.05 g/mol= 0.234 gStep 5: Calculate the percent by mass of acetic acid in the vinegar.Percent by mass of acetic acid = (Mass of CH3COOH / Mass of vinegar solution) × 100%= (0.234 g / 10.05 g) × 100%= 2.33%.

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Answer: Electron

Explanation:An electron is most likely to be found in an energy level within an atom.

In addition to respiration, a process known as guttation involves the loss of liquid water from a plant's healthy leaf or stem, mostly through water stomata.

The physiological loss of water . water of water vapor, mostly from the stomata of leaves, but also by evaporation first from surfaces of leaf tissue, flowers, and stems, is known as transpiration.

Additionally, by providing evaporative cooling, vegetation transpiration makes a major contribution to the energy balance of the leaf. Additionally, transpiration speeds up the movement of nutrients and water from roots to the shoots. Transpiration occurs when water vapor leaves a plant through the stomata.

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Answer:

The correct statement is;

(B) Only II

Explanation:

I) The atomic mass unit or amu which is also known as daltons which is defined as 1/12 × the mass of a carbon-12 atom, which is therefore, 1.660538921 × ⁻²⁴ grams

Therefore, the mass of 1 atom of carbon-12 = 12 amu

II) The mass of one mole of oxygen-16 is 16 grams while the mass of one mole of carbon-12 is 12 grams

The mass of 4 atoms of carbon 12 = 4 × 12 amu = 48 amu

The mass of 1 atom of oxygen-16 = 15.99491461956 amu

Therefore, the mass of 3 atoms of oxygen-16 = 3 × 15.99491461956 = 47.9847438587 amu ≈ 48 amu

Therefore only II is correct.

Answer:

Substance B

Explanation:

Heat capacity is a measure of how much energy is needed to raise the temperature of an object.

A high heat capacity means that an object requires large amounts of heat energy to change/increase its temperature. It can take in a lot of heat energy before it starts changing temperature.

A low heat capacity means that an object requires a minimal amount of heat energy to change/increase its temperature. It can start changing more rapidly as compared to objects with higher heat capacities.

So, if the same amount of heat is added to both substances (Substance A and Substance B), the substance that will increase in temperature more rapidly is Substance B.

The assumption built into the TWA (time-weighted average) value with regard to years of exposure is that the exposure to the content loaded in a particular environment is spread out over a working career, which typically spans around 30 years.

Therefore, the TWA value is based on an average exposure over a period of time, assuming that an individual will work in that environment for a full career length. However, it should be noted that TWA values may vary depending on the specific type of content being measured and the associated health risks.

The assumption built into the Time Weighted Average (TWA) value with regard to years of exposure is "A working career." This typically means that the TWA value is calculated based on a worker's exposure to a substance or hazard over a 40-hour work week for a duration of approximately 30 years, which is considered a standard working career.

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The molar mass of the compound is 88 g/mol and the formula of the compound is  \(P_{2} F_{2}\).

We know that the ideal gas equation is the equation that we can be able to obtain any of the parameters that has to do with a gas. In this case, we have the gas that we are told that it is a certain gaseous fluoride of phosphorus and that the density of the gas is about  3.93 g/l

Given that;

MM = dRT/P

MM = molar mass

d = density of the gas

R = gas constant

T = temperature

P = pressure

Then we have to be able to substitute the values as shown;

MM =  3.93  * 0.082 * 273/1

MM = 88 g/mol

The formula of the gas is obtained from;

[PF]n = 88

[31 + 19]n = 88

50n = 88

n = 88/50

n = 2

The molecular formula of the compound is \(P_{2} F_{2}\).

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Answer: 324 g (to 3 sf)

Explanation:

Based on the coefficients of the equation, we know that when 3.00 mol of water is consumed, 3.00 mol of carbon dioxide is also consumed.

Thus, the formula mass of carbon dioxide is:

\(6(15.9994)+12.011=108.0074\) g/mol.

Thus, 3.00 mol has a mass of (108.0074)(3.00)=324 g (to 3 sf)

The dead battery with a percentage composition of 70.0% Mn and 30.0% O has the empirical formula Mn₂O₃.

An empirical formula is the minimal relationship between the atoms in a chemical formula.

A dead alkaline battery is 70.0 % Mn and 30.0 % O. To find the empirical formula, we will divide each percentage by the molar mass of the element.

Then, we divide both numbers by the smallest one.

Finally, we multiply both numbers by 2 so that they are whole numbers.

The empirical formula of the compound is Mn₂O₃.

The dead battery with a percentage composition of 70.0% Mn and 30.0% O has the empirical formula Mn₂O₃.

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Answer:

This:

Explanation:

Black holes occur when a massive star or larger reaches the final stage of it's lifespan. The star implodes and a black hole is the dying star's remains

You would need to add 250 mL of water.

The difference in kinetic energy if a 6 kg bowling ball rolling at 16 mph and when it is rolling at 14 mph is 180J.

Kinetic energy of an object can be calculated using the following formula;

K.E = ½mv²

Where;

According to this question, a 6 kg bowling ball is rolling at 16 mph and 14 mph respectively.

K.E = (½ × 6 × 16²) - (½ × 6 × 14²)

K.E = 768 - 588

∆K.E = 180J

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Explanation:

Polyatomic ions are ions which consist of more than one atom. For example, nitrate ion, NO3-, contains one nitrogen atom and three oxygen atoms. The atoms in a polyatomic ion are usually covalently bonded to one another, and therefore stay together as a single, charged unit.

Answer:

d

Explanation:

Answer:

D

Explanation:

help me on my work please