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Which of the following is a type of intellectual property?


software

benchmarks

tariffs

quotas

Answer:

x = 10; y = 10

Step-by-step explanation:

\( \sin(theta) = \frac{opposite}{hypotenuse} \)

\( \cos( {theta} ) = \frac{adjacent}{hypotenuse} \)

\( \tan( {theta} ) = \frac{opposite}{adjacent} \)

theta = 45°

opposite = x

hypotenuse = 10√2

adjacent = y

\( \sin(theta) = \frac{opposite}{hypotenuse} \)

\( \sin(45) = \frac{x}{10 \sqrt{2} } \)

\( \sin(45) \times 10 \sqrt{2} = x\)

\(10 = x\)

\(x = 10\)

\( \cos( {theta} ) = \frac{adjacent}{hypotenuse} \)

\( \cos(45) = \frac{y}{10 \sqrt{2} } \)

\( \cos(45) \times 10 \sqrt{2} = y\)

\(10 = y\)

\(y = 10\)

Step-by-step explanation:

Given

Slope (m) = - 2/3

Y-intercept (c) = - 9

Writing in slope intercept form

y = mx + c

y = - 2/3 x - 9

Hope it helps. :)

Answer:

Step-by-step explanation:

m = -2/3 ; (0 , -9)

y - y1 = m(x -x1)

\(y -[-9]= \frac{-2}{3}(x - 0)\\\\y + 9 = \frac{-2}{3}x\\\\ y = \frac{-2}{3}x -9\)

The standard deviation is relatively small when the data are all concentrated close to the mean, exhibiting little variation or spread.

The standard deviation could be a degree of the changeability or spread of a set of information. It is calculated by finding the square root of the normal of the squared contrasts between each information point and the cruel(mean).

In other words, it tells us how much the information values are scattered around the mean.

When the information is all concentrated near the cruel(mean), it implies that the contrasts between each information point and the cruel are moderately little.

This comes about in a little while of squared contrasts, which in turn leads to a little standard deviation. On the other hand, when the information is more spread out, it implies that the contrasts between each information point and the cruel are bigger.

This comes about in a bigger entirety of squared contrasts, which in turn leads to a bigger standard deviation.

For case, let's consider two sets of information:

Set A and Set B.

Set A:

2, 3, 4, 5, 6

Set B:

1, 3, 5, 7, 9

Both sets have the same cruel(mean) (4.0), but Set A encompasses a littler standard deviation (1.4) than Set B (2.8).

This is because the information values in Set A are all moderately near to the cruel(mean), while the information values in Set B are more spread out.

Subsequently, we will say that the standard deviation is generally small when the information is all concentrated near the mean, showing a small variety or spread.

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The Laplace transform Y(s) of the solution y(t) to the given initial value problem is Y(s) = (3s + 9) / (s^2 + 6s + 18).

To solve the given initial value problem \(y'' + 6y' + 18y = 38(t - \pi)\) with \(y(0) = 3\) and \(y'(0) = 9\), we can use the Laplace transform method. The Laplace transform of a function \(y(t)\) is denoted as \(Y(s)\) and is obtained by applying the Laplace transform operator to both sides of the differential equation.

Applying the Laplace transform to the given differential equation, we obtain the algebraic equation \[s^2Y(s) - sy(0) - y'(0) + 6sY(s) - 6y(0) + 18Y(s) = 38\left(\frac{1}{s} - \frac{e^{-\pi s}}{s}\right).\] Substituting the initial conditions \(y(0) = 3\) and \(y'(0) = 9\), we can simplify the equation to \[(s^2 + 6s + 18)Y(s) - (3s + 9) = 38\left(\frac{1}{s} - \frac{e^{-\pi s}}{s}\right).\]

To find \(Y(s)\), we rearrange the equation and solve for \(Y(s)\): \[Y(s) = \frac{3s + 9 + 38\left(\frac{1}{s} - \frac{e^{-\pi s}}{s}\right)}{s^2 + 6s + 18}.\]

In the second paragraph, we can further simplify the expression for \(Y(s)\) by performing algebraic manipulations. By multiplying out the numerator and denominator and combining like terms, we can obtain a more concise form of \(Y(s)\). However, without the specific values for \(s\) and \(\pi\), it is not possible to determine the exact numerical expression for \(Y(s)\).

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Answer:

b

Step-by-step explanation:

X would be the number of lawns he mows. We dont know that answer.

Y would be the amount he is paid. So i think it would be

Y=35 + X

Trying my best here im not good with algebra. I know that Y goes with the 35$

Answer:

36 miles

Step-by-step explanation:

Given - Dylan just started a running plan where he runs 14 miles the first

            week and then increases the number of miles he runs by 10% each

            week.

To find - If he keeps up this plan for 11 weeks, how many total miles would  

              Dylan have run ?

Proof -

1st week = 14 miles

2nd week = 14 + 10% of 14 = 14 + 1.4 = 15.4

3rd week = 15.4 + 10% of 15.4 = 15.4 + 1.54 = 16.94

4th week = 16.94 + 10% of 16.94 = 16.94 + 1.694 = 18.634

5th week = 18.634 + 10% of 18.634 = 18.634 + 1.8634 = 20.4974

6th week = 20.4974 + 10% of 20.4974 = 20.4974 + 2.04974 = 22.54714

7th week = 22.54714 + 10% of 22.54714 = 22.54714 + 2.254714 = 24.801857

8th week = 24.801857  + 10% of 24.801857  = 24.801857  + 2.4801857  = 27.2820427

9th week = 27.2820427  + 10% of 27.2820427  = 27.2820427+ 2.72820427  = 30.01024697

10th week = 30.01024697  + 10% of 30.01024697  = 30.01024697 + 3.001024697  = 33.01127167

11th week = 33.01127167  + 10% of 33.01127167  = 33.01127167 + 3.301127167  = 36.31239884 ≈ 36

∴ we get

Total miles Dylan would run = 36 miles.  

Mean of country A is $29600 and median $29000. Mean of country B is $49800 and median is $29000. Country B has greater income inequality. So option B is the correct answer.

Mean of incomes in country A = (9000+ 21000+ 29000 + 39000+ 50000)/5   =  $29600

Median income of country A = (5+1)/2 th term = 3rd term = $29000

Mean to median ratio = 29600/ 26000= 1.02

Mean income of country B = ( 9000+ 21000+ 29000+ 39000+ 151000)/5 = $ 49800

Median income = (n+1)/2 th term = (5+1)/2 = 3rd term = 29000

Mean to median ratio of country B = 49800/29000 = 1.71

Since mean and median are closer to each other, standard deviation is less. The mean to median ratio is greater for country B. So country B has greater income inequality.

If the income inequality has been increasing, then the mean-median ratio will increase, due to the extreme values, mean will increase. So option B is the correct answer.

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Answer:

I can't answer the question without further information.

Step-by-step explanation:

Answer:

(1)xy=-5-3

-8ans

Step-by-step explanation:

(2) -3x =-18

-15ans

Answer:

last answer

Step-by-step explanation:

Answer:

If he spent 141 dollars then he would have 59 dollars left over.

Step-by-step explanation:

That's the answer.

Answer:

Step-by-step explanation:

a. -120 - 400

b. -(120+400)

c. -120 - 400 = -(120+400) = -520

The volume of the triangular prism is 216 cubic meters.

To find the volume of a triangular prism, we need to multiply the area of the triangular base by the length of the prism.

Calculate the area of the triangular base.

The base of the triangular face is given as 8 meters, and the height is 9 meters. We can use the formula for the area of a triangle: area = (1/2) * base * height.

Plugging in the values, we get:

Area = (1/2) * 8 meters * 9 meters = 36 square meters.

Multiply the area of the base by the length of the prism.

The length of the prism is given as 12 meters.

Volume = area of base * length of prism = 36 square meters * 12 meters = 432 cubic meters.

Adjust for the shape of the prism.

Since the prism is a triangular prism, we need to divide the volume by 2.

Adjusted Volume = (1/2) * 432 cubic meters = 216 cubic meters.

Therefore, the volume of the triangular prism is 216 cubic meters.

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The number of hours Bruce spent doing homework last week if he spent 1/5 of Darell's time is 1 hour.

Time Darell spent doing homework last week = 5 hours

Time Bruce spent doing homework last week = 1/5 of Darell's time

= 1/5 of 5

= 1/5 × 5

= (1 × 5) / (5 × 1)

= 5/5

= 1 hour

In conclusion, given the fraction of time Bruce spent doing homework last week, that means, he spent 1 hour doing homework.

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In question 27, the price elasticity of supply for shampoo is given as 20, and the price of shampoo increases by 0.7%. The expected change in the quantity of shampoo supplied can be determined using the concept of price elasticity of supply. However, the specific percentage change in quantity supplied is not provided, so a precise answer cannot be given based on the given information.

In question 20, an inferior good in which the income effect dominates the substitution effect is referred to as a Giffen good. It is not classified as a normal good, luxury good, mass-produced good, or favored good.

In question 30, the cross elasticity of demand measures the responsiveness of the quantity demanded of a particular good to changes in the prices of its substitutes and complements. The correct answer is that the cross elasticity of demand measures the responsiveness to changes in both substitutes and complements.

In question 27, without the specific percentage change in quantity supplied, we cannot determine the exact outcome based on the given information. The price elasticity of supply of 20 suggests that the quantity supplied is highly responsive to changes in price, but the specific percentage change in quantity supplied cannot be calculated without additional data.

In question 28, the relationship between pasta being a Giffen good and other characteristics is not specified. While pasta being a Giffen good indicates that the quantity demanded increases as the price increases, it does not imply whether pasta is a normal good, luxury good, or how price changes affect quantity demanded.

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Answer:

Multiply them

Step-by-step explanation:

use the strategy

Answer:

110

Step-by-step explanation:

180-70=110

the full line is 180 so subtract the angle, 70.

The highest score is 32

The following receive the highest individual score:

Total Players' Points: 8 - Seven players' combined points

= 14.5*8 - 12*7

= 116 - 84

= 32.

The overall Average was decreased as a result of 1 player being excluded. As a result, by answering the question as stated above, you can determine the score of the highest individual score.

Alternative strategy:

The top individual rating

= 14.5 + 2.5*7

= 14.5 + 17.5

= 32

clean air.

Sharma, Divya

reply from a year ago

8 players total score = mean score * players

= 14.5*8 = 116

7 players total score = 7 players' mean score * number of players

= 12*7 = 84

The highest score is equal to 8 players' total score minus 7 players' total score.

= 116 — 84

= 32.

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The size sample would be needed to estimate the proportion of black with an error of no more than 0.05 and a confidence level of 95% is 289.

The size sample can be calculated with the equation as follows:

\(n=(\frac{Z_{1-\frac{a}{2} }^ }{a})^{2} P (1-P)\)

where,

n = size sample

\(Z_{1-\frac{a}{2} }^{2}\) = 1.96 for \(a\)=0.05

\(P\) = population

\(a\) = margin of error

Therefore,

\(n=(\frac{1.96^{}}{0.05})^{2} 0.25(1-0.25)\)

\(n=(\frac{1.96^{}}{0.05})^{2} 0.25(0.75)\)

\(n=288.12\) ≈ 289

The number of size sample is 289

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Answer:

The answer is $1.70

Step-by-step explanation:

What I did is $31.80-21.60=$10.20. $10.20 is the amount of money for all 6 pendants, so to find how much 1 pendant is I just divided $10.20 by 6 which got me $1.70. Hope that helped you. :)

This is a pond in the shape of a prism. It is completely full of water. Colin has to wait for the pond to completely empty is 2hrs and 30minutes.

We have a pond which is completely filled with the water.

Area of the side face ( trapezium shaped)

= 1/2 x (1.4 + 0.6) x 2

= 2 m²

Volume = area x height (here width)

V = 2x1 = 2 m³

The level goes down by 20cm in the first 30 mins

Volume of water that will be taken down =

=0.2 x 1 x 2

=0.4 m³ ( upper water will form cuboid face)

Now,

⇒0.4 m³ water is taken out in 30 minutes

⇒1 m³ water is taken out in 30/0.4 minutes

⇒2 m³ water is taken out in 30/0.4 x 2 minutes

⇒30x2/0.4

⇒150 minutes.

So the pond will be completely empty in 150 min that is 2hrs30mins.

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Brett and his family need to start hiking no later than 4:20 PM to reach their camping spot and set up camp before it gets dark.

To calculate the latest time Brett and his family can start hiking, we need to subtract the total time required for hiking and setting up the camp from the sunset time.

Total time required:

Hiking time: 2 hours 55 minutes = 2.92 hours

Setting up camp time: 1 hour 10 minutes = 1.17 hours

Total time required = Hiking time + Setting up camp time = 2.92 hours + 1.17 hours = 4.09 hours

Now, subtract the total time required from the sunset time:

Sunset time: 8:25 PM

Latest start time = Sunset time - Total time required

Latest start time = 8:25 PM - 4.09 hours

To subtract the hours and minutes, we need to convert 4.09 hours into minutes:

0.09 hours * 60 minutes/hour = 5.4 minutes

So, the latest start time is 8:25 PM - 4 hours 5.4 minutes:

Latest start time = 8:25 PM - 4 hours 5.4 minutes = 4:20 PM

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The value of the standard normal random variable z call it. z 0z0​,such that the following probabilities are satisfied:

The standard normal distribution is a special type of normal distribution where the mean is 0, and the standard deviation is 1.

a) P(: 0.0973)

Lookup the Z-value corresponding to the region 0.0973 to the left of the normal curve in the Z-table or use the excel formula " =NORM.S.INV(0.0975) " to get the probability.

\(\mathbf{\therefore z_o={\color} \mathbf{-1.30}}}\)

(b) P( Z 0.95)

Lookup the Z-value corresponding to the region 0.0973 to the left of the normal curve in the Z-table or use the excel formula " =NORM.S.INV(0.0975) " to get the probability.

P(Z1.96) = 0.95

\(\mathbf{\therefore z_o={\color{} 1.96}}\)

\({\color{} \mathbf{(c)}}\;P(-z_o\leq Z\leq z_o)=0.90\)

Lookup the Z-value corresponding to the region 0.0973 to the left of the normal curve in the Z-table or use the excel formula " =NORM.S.INV(0.0975) " to get the probability.

\(\Rightarrow P(Z\leq 1.64)=0.95\)

\(\mathbf{\therefore z_o={\color{} 1.64}}\)

\({\color{} \mathbf{(d)}}\;P(-z_o\leq Z\leq z_o)=0.8214\)

Lookup the Z-value corresponding to the region 0.0973 to the left of the normal curve in the Z-table or use the excel formula " =NORM.S.INV(0.0975) " to get the probability.

\(\Rightarrow P(Z\leq 1.35)=0.9107\)

\(\mathbf{\therefore z_o={\color{} 1.35}}\)

(e) \(\Rightarrow P(Z\leq z_o)=0.7579\)

Lookup the Z-value corresponding to the region 0.0973 to the left of the normal curve in the Z-table or use the excel formula " =NORM.S.INV(0.0975) " to get the probability.

\(\mathbf{\therefore z_o={\color{} 0.70}}\)

(f) P(Z =0.9588)

Lookup the Z-value corresponding to the region 0.0973 to the left of the normal curve in the Z-table or use the excel formula " =NORM.S.INV(0.0975) " to get the probability.

Zo = 1.74

\({\color{} \mathbf{g)}}\;P(z > z_o)=0.5\)

Lookup the Z-value corresponding to the region 0.0973 to the left of the normal curve in the Z-table or use the excel formula " =NORM.S.INV(0.0975) " to get the probability.

\(\mathbf{\therefore z_o={\color{} \mathbf{0.00}}}\)

\({\color{} \mathbf{h)}}\;P(z\leq z_o)=0.0031\)

Lookup the Z-value corresponding to the region 0.0973 to the left of the normal curve in the Z-table or use the excel formula " =NORM.S.INV(0.0975) " to get the probability.

\(\mathbf{\therefore z_o={\color{} \mathbf{-2.74}}}\)

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Y = 8000/1000= 8

Y= 8*20

Y= 160

Answer: 4

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

its easy

its easy