who wants a brainly :D if u get this right what is 1567÷7

Answer:

x= -2

Step-by-step explanation:

The maximum combined loads for a residential building using the recommended AISC 7 expressions for LRFD is 434 kips.

The maximum combined loads for a residential building using the recommended AISC 7 expressions for LRFD,

where

D = 100k,

L = 140k, L < 100psf,

Lr = 40k,

W = +160k or −100k, and

E = +180k or −125k is given below:

Design load = 1.2D + 1.6(Lr or S or R) + 0.5(L + Lr or R) + (W or E)

Here, D is the weight of dead load, L is the weight of live load, Lr is the weight of the roof live load, W is the weight of wind load and E is the weight of earthquake load.

Therefore, for the given loads,

D = 100k

L = 140k

Lr = 40k

W = +160k or −100k

E = +180k or −125k

Max load = 1.2D + 1.6(Lr) + 0.5(L + Lr) + W

= 1.2 (100) + 1.6 (40) + 0.5 (140 + 40) + 160

= 120 + 64 + 90 + 160

= 434 kips

Therefore, the maximum combined loads for a residential building using the recommended AISC 7 expressions for LRFD is 434 kips.

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The growth constant k is approximately 0.2310.

To find the growth constant k, we can use the information that the population has a doubling time of 3 hours.

In the exponential growth model, the doubling time is the time it takes for the population to double in size.

Let's set up an equation to solve for k:

2Po = Po * e^(k * 3)

Here, 2Po represents double the initial population, and Po * e^(k * 3) represents the population after 3 hours of exponential growth.

Dividing both sides of the equation by Po:

2 = e^(k * 3)

To solve for k, we take the natural logarithm (ln) of both sides:

ln(2) = ln(e^(k * 3))

Using the property of logarithms (ln(a^b) = b * ln(a)):

ln(2) = k * 3 * ln(e)

Since ln(e) is equal to 1:

ln(2) = k * 3

Now we can solve for k:

k = ln(2) / 3

Using a calculator, we find that k ≈ 0.2310.

Therefore, the growth constant k is approximately 0.2310.

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Answer:

F type connector

Step-by-step explanation:

Use an F-type connector for broadband cable connections that use coaxial cable.

The F connector is a coaxial RF connector commonly used for "over the air" terrestrial television, cable television and universally for satellite television and cable modems,

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\(m\angle E=\sin \dfrac{\sqrt{10}}{2\sqrt5}=\sin \dfrac{\sqrt2}{2}=45^{\circ}\)

The distance traveled over 9 hours at a speed of 840 km/h is 7,560 km.

Speed can be thought of as the rate at which an object covers distance.

A fast-moving object has a high speed and covers a relatively large distance in a given amount of time, while a slow

moving object covers a relatively small amount of distance in the same amount of time.

To calculate the distance traveled over 9 hours at a speed of 840 km/h, follow these steps:

1. Identify the time and speed given in the student question: 9 hours and 840 km/h.

2. Use the formula for distance:

distance = speed × time.

3. Plug in the values:

distance = 840 km/h × 9 hours.

4. Calculate the distance:

distance = 7,560 km.

So, the distance traveled over 9 hours at a speed of 840 km/h is 7,560 km.

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The domain of the function k(z) can be written as: Domain of k(z) = (-3, 2].

The graph of the given function k(z) is as shown below: Graph of k(z)

The following questions will be answered using the above graph:

(a) Identify any vertical intercepts of k. Write your answer(s) in the form (z, k(z)).

It can be seen from the graph of k(z) that it passes through the y-axis at the point (0, 1).

(b) Identify any horizontal intercepts of k. Write your answer(s) in the form (z, k(z)).

It can be seen from the graph of k(z) that it passes through the x-axis at the point (-2, 0) and (1, 0).

(c) Identify any vertical asymptotes of k. Write your answer(s) in the form z=0.

There is a vertical asymptote at z = -1.5.

(d) Identify any horizontal asymptotes of k.

Write your answer(s) in the form y = = 0.

There is a horizontal asymptote at y = 0.(e)

What is the domain of k?

Write your answer as a union of intervals.

From the graph of k(z), it can be seen that the graph is defined on the interval (-3, 2].

Therefore, the domain of the function k(z) can be written as: Domain of k(z) = (-3, 2].

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Step-by-step explanation:

-9x+15=3(2-x)

6-6x

2. collect like terms

-9x+15= 6-6x

15-6 = 6x+9x

11= 15x

3. divide both sides by the coefficient of X which is 15

x= 11/15

Answer:

They are supplementary.

Step-by-step explanation:

A linear pair consists of two opposite angles whose non-common sides create a straight line. If a linear pair consists of two angles, then they are supplementary

the solution of equation problem is estimated distance of the gold medal winning discus throw in 1980 is approximately 65.03 meters. The answer is option C.

An equation is a statement that says two things are equal. It can contain variables, which can take on different values. Equations are used to solve problems and model real-world situations by expressing relationships between variables.

A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("="). For illustration, 2x - 5 = 13.

Here,

5 and 13 are expressions for 2x.

These two expressions are joined together by the sign "="

To estimate the distance of the gold medal winning discus throw in 1980 using the line of best fit, we need to first calculate the value of x for the year 1980

x = 1980 - 1920 = 60

Now, we can substitute x=60 into the equation of the line of best fit to find the estimated distance:

y = 0.34x + 44.63

y = 0.34(60) + 44.63

y = 20.4 + 44.63

y ≈ 65.03

Therefore, the estimated distance of the gold medal winning discus throw in 1980 is approximately 65.03 meters. The answer is option C.

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The given inequality is: x+5-2x > 23 (both sides multiplied by -1, inequality reversed) ⇒ x > 23/2.

Now, let's put this in one of the given answer options to see which one is equivalent to this:

x+5/18−2x​ > 0

To check if this inequality is equivalent to x > 23/2, we can plug in a number greater than 23/2 in both inequalities. Let's say we plug in 13:

x > 23/2 = 13 > 23/2 (true)

x+5/18−2x​ > 0 = 13+5/18−2×13​ > 0 = -4/3 (false)

Since the answer option (C) gives us a false statement, it is not equivalent to the given inequality.

Let's try the other answer options:

x+5/2x−18​ < 0

Let's plug in 13 again:

x+5/2x−18​ = 13+5/2×13−18​ = 8/3 (false)

We can discard this option as well.

x+5/x−9​ > 0

Let's plug in 13 again:

x+5/x−9​ = 13+5/13−9​ > 0 = 9/4 (true)

This option gives us a true statement, so it is equivalent to the given inequality. Therefore, the correct answer is option (B): x+5/x−9​ > 0.

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Answer:

SOLUTION: " The largest US standard postage stamp ever issued has a width of about 1 inch, which was 3/4 of the height of the stamp. Write and solve an equation to find the height of the st

Answer:

The last option, 10 is correct

Step-by-step explanation:

f(x) = 3x^2 - 4

f(2) = 3(2)^2 - 4

f(2) = 12 - 4

f(2) = 8

g(x) = 2x - 6

g(8) = 2(8) - 6

g(8) = 16 - 6

g(8) = 10

This means that g(f(2)) is equal to 10

Answer:

Its 10 or D

Step-by-step explanation:

The function T(n) in terms of the number of operations is:

T(n) = 2n^3 + 3n^2 + 2n + 1 and the asymptotic complexity of the matrix multiplication algorithm is O(n^3).

To analyze the provided pseudo code for matrix multiplication and determine the function T(n) in terms of the number of operations, we need to examine the code and count the number of operations performed.

The pseudo code for matrix multiplication may look something like this:

```

MatrixMultiplication(A, B):

   n = size of matrix A

   C = empty matrix of size n x n

   for i = 1 to n do:

       for j = 1 to n do:

           sum = 0

           for k = 1 to n do:

               sum = sum + A[i][k] * B[k][j]

           C[i][j] = sum

   return C

```

Let's break down the number of operations step by step:

1. Assigning the size of matrix A to variable n: 1 operation

2. Initializing an empty matrix C of size n x n: n^2 operations (for creating n x n elements)

3. Outer loop: for i = 1 to n

- Incrementing i: n operations  

- Inner loop: for j = 1 to n

- Incrementing j: n^2 operations (since it is nested inside the outer loop)

- Initializing sum to 0: n^2 operations

- Innermost loop: for k = 1 to n

- Incrementing k: n^3 operations (since it is nested inside both the outer and inner loops)

- Performing the multiplication and addition: n^3 operations

- Assigning the result to C[i][j]: n^2 operations

- Assigning the value of sum to C[i][j]: n^2 operations

Total operations:

1 + n^2 + n + n^2 + n^3 + n^3 + n^2 + n^2 = 2n^3 + 3n^2 + 2n + 1

Therefore, the function T(n) in terms of the number of operations is:

T(n) = 2n^3 + 3n^2 + 2n + 1

To determine the asymptotic (big O) complexity of the algorithm, we focus on the dominant term as n approaches infinity.

In this case, the dominant term is 2n^3. Hence, the asymptotic complexity of the matrix multiplication algorithm is O(n^3).

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Daniel and Maria must babysit for 6 hours for their total fees to be the same.

To find the number of hours at which Daniel and Maria have the same total fee, we need to compare their fee structures and determine when their fees are equal.

Daniel charges a flat fee of $10 plus $6 per hour. So his total fee can be represented by the equation:

Total fee (Daniel) = $10 + $6 * Number of hours

Maria's total fee is given in the table. We can see that the total fee increases by $4 for every additional hour. So we can represent Maria's total fee by the equation:

Total fee (Maria) = $22 + $4 * Number of hours

To find the number of hours at which their fees are equal, we set the two equations equal to each other and solve for the number of hours:

$10 + $6 * Number of hours = $22 + $4 * Number of hours

Simplifying the equation, we get:

$6 * Number of hours - $4 * Number of hours = $22 - $10

$2 * Number of hours = $12

Dividing both sides by $2, we find:

Number of hours = $12 / $2

Number of hours = 6

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the criteria used when deciding upon the inclusion of a variable are A - Theory, B - t-statistic, C - Bias, and D - Adjusted R^2.

When deciding upon the inclusion of a variable, the following criteria are commonly used:

A - Theory: Theoretical justification is often considered to include a variable in a model. It involves assessing whether the variable is relevant and aligns with the underlying theory or conceptual framework.

B - t-statistic: The t-statistic is used to determine the statistical significance of a variable. A variable with a significant t-statistic suggests that it has a meaningful relationship with the dependent variable and may be included in the model.

C - Bias: Bias refers to the presence of systematic errors in the estimation of model parameters. It is important to consider the potential bias introduced by including or excluding a variable and assess whether it aligns with the research objectives.

D - Adjusted R^2: Adjusted R^2 is a measure of the goodness of fit of a regression model. It considers the trade-off between the number of variables included and the overall fit of the model. Adjusted R^2 helps in assessing whether the inclusion of a variable improves the model's explanatory power.

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Answer:

Let x be the smallest integer (the first integer)

1st: x, 2nd: x + 1, 3rd: x + 2, 4th: x + 3, 5th: x + 4

Hence,

x +  x + 1 + x + 2 + x + 3 + x + 4 = 10

5x + 10 = 10

5x = 0

x = 0

Therefore, the answers are

0, 1, 2, 3, 4

Step-by-step explanation:

Integers include all positive integers, negative integers and 0.

0 is an integer but it is neither positive nor negative.

The shaded area is 0.0808, the area between z = -0.34 and z = 1.3 is approximately 0.9032 - 0.3665 = 0.5367.

Draw a standard normal curve and shade the area indicated. Then find the area of the shaded region. For this problem, we need to shade the area to the left of z = -1.4 on a standard normal curve.

Using a standard normal table, we can find that the area to the left of z = -1.4 is approximately 0.0808. Therefore, the shaded area is 0.0808. Draw a standard normal curve and shade the area indicated. Then find the area of the shaded region.

To solve this problem, we need to shade the area between z = -0.34 and z = 1.3 on a standard normal curve. Using a standard normal table, we can find that the area to the left of z = -0.34 is approximately 0.3665, and the area to the left of z = 1.3 is approximately 0.9032. Therefore, the area between z = -0.34 and z = 1.3 is approximately 0.9032 - 0.3665 = 0.5367.

Find the z-Score such that the area to the right of the z-score is 0.483. To find the z-score that corresponds to an area of 0.483 to the right of it on a standard normal curve, we need to look up the value in a standard normal table.

The area to the left of the z-score will be 1 - 0.483 = 0.517. Looking up this value in the standard normal table, we find that the corresponding z-score is approximately 0.05.

Find the Z-scores that separate the middle 92% of the data from the area in the tails of the standard normal distribution. We need to find the z-scores that correspond to the 4% area in the tails of the standard normal distribution.

Since the standard normal distribution is symmetric, each tail will have an area of 2%. Using a standard normal table, we can find that the z-score that corresponds to an area of 0.02 to the right of it is approximately 2.05. Therefore, the z-scores that separate the middle 92% of the data from the area in the tails are -2.05 and 2.05.

Find the value of Z0.20. It is not clear what is meant by "Z0.20". If this is meant to represent the z-score that corresponds to an area of 0.20 to the right of it on a standard normal curve, we can proceed as follows.

The area to the left of the z-score will be 1 - 0.20 = 0.80. Looking up this value in a standard normal table, we find that the corresponding z-score is approximately 0.84.

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Answer:

  f'(x) = -2/√(x³)

Step-by-step explanation:

You want the derivative of f(x) = 4/√x.

The power rule for derivatives is ...

  \(\dfrac{d}{dx}(x^n)=nx^{(n-1)}\)

Applied to the given function, we have ...

  \(f(x)=\dfrac{4}{\sqrt{x}}=4x^{-\frac{1}{2}}\\\\f'(x)=4(-\frac{1}{2}x^{-\frac{3}{2}})\\\\\boxed{f'(x)=-\dfrac{2}{\sqrt{x^3}}}\)

__

Additional comment

The first attachment shows a calculator gives the same result.

The second attachment shows the derivative curve matches the one described by the function we found.

Answer:

13

Step-by-step explanation:

Use the distance formula to solve for the distance between two points.

\(d=\sqrt{(x2-x1)^2 + (y2-y1)^2\)

Plug in your coordinate points.

\(d=\sqrt{(7-(-5))^2 + (2-7)^2\)

\(d=\sqrt{(12)^2 + (-5)^2\)

\(d=\sqrt{144 + 25\)

\(d=\sqrt{169\)

d= 13

The RTS of the isoquant is 1000K, indicating the rate at which labor can be substituted for capital while maintaining constant production. The labor to capital cost ratio is 0.5. To minimize the cost of producing q units per hour, the specific value of q is needed to find the optimal combination of K and L along the expansion path, represented by the cost function C(K, L) = 40K + 20L.

The RTS (Rate of Technical Substitution) measures the rate at which one input can be substituted for another while keeping the production level constant. To determine the RTS, we need to calculate the derivative of the production function with respect to L, holding q constant.

Given the production function q = 1000KL, we can differentiate it with respect to L:

d(q)/d(L) = 1000K

Therefore, the RTS of the isoquant for production level q is 1000K.

The ratio of labor to capital cost can be calculated by dividing the labor cost by the capital cost.

Labor cost = $20/hour

Capital cost = $40/machine/hour

Ratio of labor to capital cost = Labor cost / Capital cost

                              = $20/hour / $40/machine/hour

                              = 0.5

The ratio of labor to capital cost is 0.5.

To find the combination of K and L that minimizes the cost of producing q units per hour, we need to set up the cost function and take its derivative with respect to both K and L.

Let C(K, L) be the total cost function.

The cost of capital is $40 per machine per hour, and the cost of labor is $20 per hour. Therefore, the total cost function can be expressed as:

C(K, L) = 40K + 20L

To produce q units per hour at minimal cost, we need to find the values of K and L that minimize the total cost function while satisfying the production constraint q = 1000KL.

The expansion path of the firm represents the combinations of K and L that minimize the cost at different production levels q.

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According to the given information, the noise level in a restaurant is normally distributed with an average of 30 decibels. To find the value below which 99% of the time the noise level is, we need to use the Z-table.

We know that 99% of the area under the normal curve is below a Z-score of 2.33 (found from the Z-table).

To find the corresponding noise level value, we use the formula:

Z-score = (X - μ) / σ

where X is the noise level value we want to find, μ is the average (30 decibels), and σ is the standard deviation (which is not given in this question).

However, we can use the empirical rule (68-95-99.7 rule) to estimate the standard deviation. According to the rule, 99.7% of the data falls within 3 standard deviations of the mean. So, if 99% of the time the noise level is below a Z-score of 2.33, then we can estimate that the standard deviation is approximately:

(2.33 x σ) = 3

Solving for σ, we get:

σ = 3 / 2.33 = 1.29 (approx.)

Now we can use the formula above to find the noise level value below which 99% of the time the noise level is:

2.33 = (X - 30) / 1.29

X - 30 = 2.33 x 1.29

X = 33.01

So, 99% of the time, the noise level in the restaurant is below 33.01 decibels (rounded to two decimal places).

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Answer:

Constant of porportionality is 4

Step-by-step explanation:

Directly proportional

y = kx

For x = 2, y = 8

8 = 2(k)

Divide both sides by 2

4 = k

Step-by-step explanation:

I hope this helps whomever needs it!

An ogive is used to plot cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class when displaying quantitative data. Option B.

An ogive is a graph that represents a cumulative distribution function (CDF) of a frequency distribution. It shows the cumulative relative frequency or cumulative frequency of each class plotted against the upper limit of the corresponding class. In other words, an ogive can be used to represent data through graphs by plotting the upper limit of each class interval on the x-axis and the cumulative frequency or cumulative relative frequency on the y-axis.

An ogive is used to display the distribution of quantitative data, such as weight, height, or time. It is also useful when analyzing data that is not easily represented by a histogram or a frequency polygon, and when we want to determine the percentile or median of a given set of data. Based on the information given above, option B: "Cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class" is the correct answer.

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The area of the parcel of land is 226934.799 square feet.

Given:

a triangular parcel of land has sides of lengths 590 feet, 980 feet and 1423 feet.

a).

Let a = 590 , b = 980, c = 1423  lengths

s = semi-perimeter

= 1/2(a+b+c)

= 1/2(590+980+1423)

= 1496.5

s-a = 1496.5-590

= 906.5

s-b = 1496.5-980

=516.5

s-c = 1496.5-1423

= 73.5

Heron's formula for area:

A = \(\sqrt{(s(s-a)(s-b)(s-c))}\)

= √1496.5(906.5)(516.5)(73.5)

= √51499402997.4

≈ 226934.799

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P: x + 2 = 9

   x = 7 # Subtract 2 from both sides

E: q - 5 = 12

    q = 17 # Add 5 to both sides

H: 6 + m = 27

    m = 21 # Subtract 6 from both sides

Y: t - 14 = -3

   t = 11 # Add 14 to both sides

J: u - 7.5 = 2.4

   u = 9.9 # Add 7.5 to both sides

I: n + 7 = -20

  n = -27 # Subtract 7 to both sides

G: d - 1 = -16

   d = -15 # Add 1 to both sides

A: b - 40 = -25

   b = 15 # Add 40 to both sides

M: 18 + w = 7

    w = -11 # Subtract 18 from both sides

L: k + 8.3

   k = 11.5 # Subtract 8.3 from both sides.

Answer:

P.x+2=9

x=9-2

x=7

L.n+7= -20

n=-20-7

n=-27

E.q- 5 = 12

q=12+5

q=17

G.d-1=-16

d=-16+1

d=-15

H. 6 + m = 27

m=27-6

m=21

A. b - 40 = -25

b=-25+40

b=15

Y. t - 14 = -3

t=-3+14

t=11

M. 18 + w = 7

w=7-18

w=-11

J.u - 7.5 = 2.4

u=2.4+7.5

u=9.9

L.K+ 8.3 = 19.8

k=19.8-8.3

k=11.5