Answer:
Alexander Fleming
Explanation:
the founder of pelincilin is Alexander Fleming
How do motion and Newton's laws apply to your everyday life? (all the laws)
For me personally, Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.
Solids in which the atoms have no particular order or pattern are called
Answer:
Amorphous solids are composed of atoms or molecules that are in no particular order. Each particle is in a particular spot, but the particles are in no organized pattern. Examples include rubber and wax. Crystalline solids have a very orderly, three-dimensional arrangement of atoms or molecules
Explanation:
how much work is done by a person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s? write your answer in joules.
The amount of work done by a person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s is 1517.25 Joules.
The work done is determined using the equation below;
W = FdW = mgd
Where,W = Work done by the person,m = mass of object = 6.7 kg,g = acceleration due to gravity = 9.8 md = distance lifted by the person = ?We know that F = m(g + a) where a is the acceleration of the object that was lifted. The object is lifted at a constant velocity and so the acceleration of the object is zero. Hence,
F = mgF = 6.7 × 9.8F = 65.66 N
We can now determine the distance d that was lifted using the equation below;
d = vt
Where,v = constant velocity = 2.5 m/s.t = time taken = 9 s
Substituting the values; d = 2.5 × 9d = 22.5 m
Now we can determine the work done;
W = FdW = 65.66 × 22.5W = 1472.85 Joules (3 decimal places)
The work done by the person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s is 1517.25 Joules (2 decimal places)Answer: 1517.25 Joules.
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The rate at which a body heats up by conduction is proportional to the difference between its temperature T and the temperature T s
of its surroundings. A fish at room temperature 20 ∘
C is cooked by putting it into boiling water at 100 ∘
C. After 5 minutes its temperature has risen to 30 ∘
C. How long will it take to be done 60 ∘
C ?
It will take 2.857 minutes (or about 2 minutes and 51 seconds) for the fish to reach a temperature of 60 °C.
To determine the time it will take for the fish to reach a temperature of 60 °C, we can use the principle of heat conduction and the concept of temperature difference.
We know that the rate of heating by conduction is proportional to the temperature difference between the body and its surroundings. Therefore, we can write the following equation:
(T - Ts) = k * t
where T is the temperature of the fish, Ts is the temperature of the surroundings (boiling water), k is the proportionality constant, and t is the time.
Given that the initial temperature of the fish is 20 °C and it takes 5 minutes to reach 30 °C, we can substitute these values into the equation:
(30 - 100) = k * 5
-70 = 5k
Solving for k, we find k = -14.
Now we can use this value of k to find the time it will take for the fish to reach 60 °C:
(60 - 100) = -14 * t
-40 = -14t
Dividing both sides by -14, we get t = 2.857 minutes.
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If a train is going 24 m/s and comes to a stop, what is the distance it covers if the acceleration
is -0.29 m/s??
Explanation:
u=24
v=0
a=-0.29
s=
v^2=u^2+2as
s=(v^2-u^2)/2a
s=(0-576)/0.58
s=-575.42
A rock is thrown upward with an initial velocity of 29m/s. What is the rock's maximum height?
43 m
35.8 m
14.5 m
O 58 m
PLSS HELLPPP MEEE WILL MARK BRAINLIEST
Answer:
a:s
b:s
c:r
d: r
e: s
f: s
g: s
Explanation:
When the right side pavement line or curb appears to run through the middle of the vehicle’s hood (VA inspection sticker), the vehicle is _____________________________.
a. 3-6 inches from the curb
b. 2 feet from the curb
c. 5 feet from the curb
d. 5 feet from the curb
When the right side pavement line or curb appears to run through the middle of the vehicle’s hood (VA inspection sticker), the vehicle is 3-6 inches from the curb. So, option a is correct choice.
What is Virginia Vehicle Inspection Sticker?Virginia's Vehicle Inspection Program is administered by the Virginia State Police. Before a vehicle can be registered or operated on Virginia highways, it must pass an annual safety inspection and display a valid inspection sticker on the windshield. There are more than 4,200 inspection stations in Virginia, and most are privately run service stations or garages.
Motorcycles, cars, and trucks with a gross vehicle weight of less than 10,000 pounds are included in the program. Buses, RVs, and other large vehicles are excluded.
The inspection takes approximately 30 minutes to complete, and the inspector examines all of the vehicle's safety equipment, such as brakes, lights, and tires, as well as any other equipment required by law, such as mirrors and horn. When the right side pavement line or curb appears to run through the middle of the vehicle’s hood (VA inspection sticker), the vehicle is 3-6 inches from the curb.
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The unit of pressure known as the pascal is equal to:________
The unit of pressure known as pascal is equal to 1 Newton / (metre)^2
It is the pressure exerted by a force of 1 newton , which is applied on an area of 1 metre square.
1 pascal pressure means that 1 newton force is equally distributed over an area of 1 metre square .
It is a small unit used for low pressures.
Pascal is denoted by the symbol Pa
It is derived from the formula pressure = force / area.
Sno2 + 2h2 sn + 2h2o identify the reactions as either synthesis, decomposition, single replacement, double replacement, or combustion.
The given equation, SnO2 + 2H2 → Sn + 2H2O, is a synthesis reaction. In a synthesis reaction, two or more substances combine to form a single compound. In this case, tin(IV) oxide (SnO2) and hydrogen gas (H2) react to form tin (Sn) and water (H2O).
A synthesis reaction involves the combination of two or more substances to form a single compound. In this equation, tin(IV) oxide (SnO2) reacts with hydrogen gas (H2) to produce tin (Sn) and water (H2O).
The given equation represents a synthesis reaction. In this type of reaction, two or more substances combine to form a single compound. In this case, tin(IV) oxide (SnO2) reacts with hydrogen gas (H2) to produce tin (Sn) and water (H2O).
The balanced equation shows that one mole of SnO2 combines with two moles of H2 to produce one mole of Sn and two moles of H2O. This reaction follows the law of conservation of mass, as the total number of atoms on both sides of the equation remains the same.
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Help!!! If you cannot type in the box, dont answer.
Answer: lollllllllllllllllllllll
Explanation:
Which substance has a melting point greater than room temperature?
A.
oxygen
B.
aluminum
C.
mercury
D.
water
Answer:
I think the answer is D.)
Explanation:
If it means something needs to melt into liquid i would have gone with B.) or C.) but since it doesn't specifiy. I thought D.) since all you have to do is heat it and it melts or boils.
1. A capacitor is made of 2 rectangular metal plates with side length of 3cmx6cm separated by a distance of 2. 36cm with water in between the plates. The capacitor has a voltage of 110v and is not connected to a battery. Calculate the capacitance. What is the new capacitance if we replace water with a new dielectric material with a constant of 3. 75 in between the plates? What is the new voltage? What is the charge on each plate?
2. A capacitor of 3. 23µF has an area of 6. 35mm^2. Determine the separation distance between the two plates. If the new capacitance is now 5. 63mF, what is the value of the dielectric inserted to the capacitor? What is the new voltage if the capacitor is connected to a 110 volts source? If the electric field created by two plates 8. 99x10^4 N/C and a working voltage of 63 volts. Will the capacitor experience a dielectric breakdown? Prove your answer.
USE GRESA
the electric field is more than the threshold value and the capacitor will experience dielectric breakdown.
1. Given values are,
side length of metal plates, a = 3 cm and b = 6 cm
distance between the plates, d = 2.36 cm
voltage, V = 110 V
dielectric constant of water, k = 80.4
dielectric constant of new material, k2 = 3.75
a) To calculate the capacitance of capacitor, the formula is, C=εA/d ……………… (1)
where A = area of plate, ε = permittivity, and d = separation distance between two plates.
We know that the permittivity of vacuum is given as, ε0 = 8.854 x 10^-12 F/m
The capacitance of capacitor can be expressed as,
C1 = ε0 (kA/d) …………….. (2)
where, ε0 = permittivity of vacuum, k = dielectric constant and A = area of plate.
Substituting the given values in equation (2),
C1 = 8.854 x 10^-12 x 80.4 x (0.03 x 0.06)/0.0236
C1 = 0.000132 F
Therefore, the capacitance of capacitor is 0.000132 F.
b) To calculate the new capacitance, the formula is given as,
C2 = k2ε0A/d ……………… (3)
where k2 is the dielectric constant of new material.
Substituting the given values in equation (3),
C2 = 3.75 x 8.854 x 10^-12 x (0.03 x 0.06)/0.0236
C2 = 0.000263 F
Therefore, the new capacitance is 0.000263 F.
c) The new voltage can be calculated as,
V2 = V1(C1/C2) …………… (4)
Substituting the given values in equation (4),
V2 = 110 (0.000132/0.000263)
V2 = 55 V
Therefore, the new voltage is 55 V.
d) The charge on each plate is given as,
Q = CV ………….. (5)
Substituting the given values in equation (5),
Q = 0.000132 x 110
Q = 0.0145 C
Therefore, the charge on each plate is 0.0145 C.
2. Given values are,
capacitance, C = 3.23 µF
area of plate, A = 6.35 mm^2
separation distance between two plates, d = ?
new capacitance, C2 = 5.63 mF
new dielectric constant, k2 = ?
voltage, V = 110 V
electric field between two plates, E = 8.99 x 10^4 N/C
working voltage, Vw = 63 V
a) The separation distance between two plates can be calculated as,
C1/C2 = d2/d1 …………….. (6)
where d1 and d2 are the initial and final separation distance, respectively.
Substituting the given values in equation (6),
3.23 x 10^-6/5.63 x 10^-3 = d2/d1
d2 = 5.63 x 10^-3 x (d1/3.23 x 10^-6)
Area of plate, A = 6.35 mm^2 = 6.35 x 10^-6 m^2
The capacitance can be expressed as,
C = εA/d
d = εA/C
where ε = permittivity of dielectric material.
Therefore, substituting the given values in above equation,
d1 = ε x 6.35 x 10^-6/3.23 x 10^-6
d1 = 12.50 ε
Substituting the value of d1 in equation (6),
5.63 x 10^-3 = d2/12.50 ε
d2 = 70.38 ε
The separation distance between two plates is 70.38 ε.
b) The new dielectric constant can be calculated as,
C2 = k2ε0A/d2
k2 = C2d2/ε0A
Substituting the given values in above equation,
k2 = 5.63 x 10^-3 x 70.38 ε/(8.854 x 10^-12 x 6.35 x 10^-6)
k2 = 3.95
Therefore, the new dielectric constant is 3.95.
c) The new voltage can be calculated as,
V2 = V1(C1/C2)
Substituting the given values in above equation,
V2 = 110(3.23 x 10^-6/5.63 x 10^-3)
V2 = 0.063 V
Therefore, the new voltage is 0.063 V.
d) The electric field can be expressed as,
E = V/d
d = V/E
Substituting the given values in above equation,
d = 63/8.99 x 10^4
d = 7.01 x 10^-4 m
The voltage, V = 110 V > working voltage, Vw = 63 V
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Help answer these questions please!
You only have to answer the first one unless it’s already been answered then answer the next one (if you could explain how you did it, it would be much appreciated :))
Answer:
1a: Lead atoms are heavier than aluminum atoms, which means that a given mass of lead contains fewer atoms than the same mass of aluminum. Since the heat required to raise the temperature depends on the number of atoms, it takes less heat to raise the temperature of the lead than the temperature of the aluminum.
A tennis ball is released at rest from the top of the school. It hits the ground after falling for 2.00 s. What was the height from which the ball was dropped?
a 15.4 m
b 9.8 m
c 19.6 m
d 20.7 m
Answer:
\(\huge\boxed{\sf h = 19.6\ m}\)
Explanation:
Given:
Time = t = 2.00 secs
Acceleration due to gravity = g = 9.8 m/s²
Initial Velocity = \(\sf V_{i}\) = 0 m/s
Required:
Height = h = ?
Formula:
\(\sf h = V_{i} t + \frac{1}{2} gt^2\)
Solution:
Putting the given in the above formula
h = (0)(2) + 1/2 (9.8)(2)²
h = 1/2 (9.8)(4)
h = (9.8)(2)
h = 19.6 m
Hope this helped!
~AnonymousHelper1807
A 1400-kg car is moving at a speed of 25 m/s. How much kinetic energy does the car have?
Answer:
Kinetic energy=1/2mvsquare
1/2 x 1400 x 25 x25
Therefore kinetic energy= 437500Joules
Explanation:
Answer:
437,500 Joules
Explanation:
KE= 1/2 × M
x V^2, where
M = Mass,
V = Velocity
KE = 1/2 × 1400 × 25^ 2
KE= 1/2 × 1400 × 625
KE = 437,500 Joules.
A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg•m2. if the arms are pulled in so the moment of inertia decreases to 1.80 kg•m2, what is the final angular speed?
A) 2.25 rad/s
B) 6.25 rad /s
C) 0.81 rad/s
D) 4.60 rad/s
Which is an example of kinetic energy?
a. an archer's bow with the string drawn back
b.river water at the top of a waterfall
c. a Ferris wheel before it starts turning
d.a crumb falling from a table.
Answer:
it's a
Explanation:
Answer:
I believe its D!
Explanation:
Kenetic energy is motion
Youre diving down the highway late one night at 20 m/s when a deer steps onto the road 41 m in How much distance is between you and the deer when you came to a stop? frort of you. Your reaction time before stepping on the brakes is 0.50 s, and the maximum Express your answer with the appropriato units. deceleration of your car is 10 m/s
2
. Part B What is the maximum speed you could have and still not hit the deen? Express your answer with the appropriate units.
Given that the initial speed of the car is 20 m/s.
The car comes to a stop and the maximum deceleration of the car is 10 m/s².
Part A
To find the distance between the deer and the car when it comes to a stop, we need to find the distance traveled by the car after the brakes are applied.Using the formula:
v² = u² + 2
as where v = 0 (final velocity), u = 20 m/s (initial velocity), a = -10 m/s² (deceleration) and s = distance traveled by the car after the brakes are applied.
0² = 20² + 2(-10)s=> 0 = 400 - 20s=> s = 400/20= 20 m
The distance between the car and deer is 41 m. Therefore, the distance between the car and deer when the car comes to a stop is:
Distance between car and deer = 41 m - 20 m = 21 m.
Part B
We can use the same formula to find the maximum speed at which the car should travel to avoid hitting the deer.
The maximum distance that the car travels after the brakes are applied should be equal to the distance between the car and deer.
v² = u² + 2aswhere v = 0 (final velocity), u = maximum speed, a = -10 m/s² (deceleration) and s = 41 m (distance between car and deer).
0² = u² + 2(-10)(41)=> 0 = u² - 820=> u² = 820=> u = √820 = 28.64 m/s
Therefore, the maximum speed at which the car should travel to avoid hitting the deer is 28.64 m/s.
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Please help ! Grades are due tmr and I just need a few questions !
A 12 kg ball is fired with a velocity of 88 meters per second from a 568 kg cannon. What is the
recoil velocity of the cannon?
The recoil velocity of the cannon would be 1.85 m/s to the left.
Recoil velocityLet's assume that the positive direction is to the right. The initial momentum of the system (cannon + ball) is:
p_initial = m_cannon * 0 m/s + m_ball * 88 m/s = 0 + 12 kg * 88 m/s = 1056 kg*m/s
After the ball is fired, the momentum of the cannon and the ball must be equal and opposite to conserve momentum. Let's assume that the recoil velocity of the cannon is v_cannon:
p_final = m_cannon * v_cannon + m_ball * 0 m/s = 0 + 12 kg * 0 m/s = 0
Using the conservation of momentum equation, we can set the initial momentum equal to the final momentum:
p_initial = p_final
m_cannon * 0 m/s + m_ball * 88 m/s = m_cannon * v_cannon + m_ball * 0 m/s
Solving for v_cannon, we get:
v_cannon = (m_ball/m_cannon) * 88 m/s
v_cannon = (12 kg / 568 kg) * 88 m/s
v_cannon = 1.85 m/s (to the left)
Therefore, the recoil velocity of the cannon is 1.85 m/s to the left.
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motion capture in movies, in which points of light on each joint of the body allow computers to regiter the motion of actors, is which kind of motion?
Motion capture in movies, in which points of light on each joint of the body allow computers to register the motion of actors, is a kind of biomechanical motion. This technology is also known as "performance capture" or "mo-cap" and is widely used in the entertainment industry to create realistic animations, video games, and movies
Motion capture is the technique of recording the motion of actors or objects in real-time and generating an animated sequence based on that data. It employs cameras and other equipment to capture and record the position, orientation, and movement of objects in a 3D space.In motion capture, markers or reflective dots are placed on various body parts of the actor to capture their movements. The computer system then analyzes the movements of these markers and generates a 3D model that mimics the actor's movements in real-time.In the entertainment industry, motion capture is used to create realistic animations, such as CGI or computer-generated imagery, for movies and video games. It is also used in sports to analyze athletes' movements to help them improve their performance.Motion capture works by tracking the movement of markers placed on a performer's body. The markers are small reflective dots that are positioned on the actor's joints, allowing the system to capture the position and movement of each joint accurately.The markers' movement is then captured by a series of high-speed cameras, which record the movement data and transmit it to a computer. The computer software then uses this data to create a 3D model of the actor's performance in real-time.Motion capture technology has revolutionized the entertainment industry by allowing filmmakers and game developers to create realistic animations that mimic the movement of real-life performers. It has also been used in the scientific field to analyze human movement patterns and improve physical therapy treatments.for more such question on biomechanical
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6. You apply 50 N of force to a lever over a distance of 2 meters. The other end of the lever raises up 1 meter
(a) How weight does the lever lift?
(b) What is the mechanical advantage?
Answer:
ok this is when we come to calculating the mechanical advantage of a lever. To do this, you divide the distance from the fulcrum, the point at which the lever pivots, to the applied force by the distance from the fulcrum to the resistance force. Using this picture, this means dividing distance b by distance a.
Explanation:
Which statement is true about Car A?
Car A has a velocity of 40 km/hr
west.
Car A has a velocity of 40 km/hr
east.
Car A has the same velocity Car E.
Car A has a velocity of 40 km/hr.
Answer:
Car A has a velocity of 40 km/hr west.
Explanation:
The velocity of an object is a vector quantity. It has both magnitudes as well as direction.
Arrows are used to show direction.
Car A is moving towards west. Car B is moving towards east-south direction. Car C is moving towards South direction. Car E is moving towards North direction.
So, the correct option is (a) i.e. Car A has a velocity of 40 km/hr west.
Ph11_UnitPacket2019
Page 30 of 38
3. A ray of light travels from air into a liquid. The ray is incident upon the liquid at an angle of 30.0 degrees
The angle of refraction is 19.9º.
a. What is the index of refraction for the liquid? 1901
1999
thin liquid could be.
Let's see
Use snells law
\(\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}\)
\(\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}\)
\(\\ \rm\Rrightarrow \mu=0.5/0.34\)
\(\\ \rm\Rrightarrow \mu=1.47\)
It may be glass
0 / 2 pts a ball is released from rest from the twentieth floor of a building. after 1 s, the ball has fallen one floor such that it is directly outside the nineteenth-floor window. the floors are evenly spaced. assume air resistance is negligible. what is the number of floors the ball would fall in 3s after it is released from the twentieth floor?
The number of floors from the 12th floor that the ball should descend in 3s is 9 when a ball is released from rest from the twentieth floor of a building.
From Newtons laws of motion we know that S = ut + 1/2at^2
where u denotes initial velocity, t denotes time taken, a denotes acceleration of the body and s denotes distance.
Given t = 1s, u = 0m/s since at rest and a = g = 9.8m/s^2
Then S = 0x1 + 1/2x9.8x1x1 = 4.9m
So the height of first floor == 4.9m
Then after 3s the distance covered by ball is S = ut +1/2at^2
S = 0x3 + 1/2x9.8x3x3 = 44.1m
Hence the distance covered by ball after 3s is 44.1m
Then the number of floor covered = 44.1/4.9 = 9
Therefore, we can conclude that the 9th floor is the floor from which the ball should descend in 3s starting on the 12th floor.
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complete question: A ball is released from rest from the twentieth floor of a building. After 1 s, the ball has fallen one floor such that it is directly outside the nineteenth-floor window. The floors are evenly spaced. Assume air resistance is negligible. What is the number of floors the ball would fall in 3s after it is released from the twentieth floor?
a. 3 floors or less
b. 4 to 6 floors
c. 7 to 10 floors
d. 11 floors or more
A tetherball on a 1.55-m rope is struck so that it goes into circular motion in a horizontal plane, with the rope making a 12.0° angle to the horizontal. Part A What is the ball's speed? Express your answer with the appropriate units. НА ?
Answer:
Approximately \(5.40\; {\rm m\cdot s^{-1}}\) (assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).)
Explanation:
Refer to the diagram attached. There are two forces on this tetherball: tension \(T\) in the string, and weight \(m\, g\)- where \(m\) is the mass of the tetherball.
Let \(T\) denote the tension in the string, and let \(\theta = 12^{\circ}\) denote the angle of elevation of this force. Decompose \(T\!\) into two components: horizontal and vertical:
Vertical: \(T\, \sin(\theta)\), andHorizontal: \(T\cos(\theta)\).The tetherball is moving in a horizontal plane, meaning that there is no motion in the vertical direction. Hence, the resultant force in the vertical direction should be \(0\). The vertical component of the tension \(T\, \sin(\theta)\) should exactly balance the weight of the tetherball \(m\, g\):
\(T\, \sin(\theta) = m\, g\).
Hence, the resultant (unbalanced) force on this tetherball would be equal to the horizontal component of tension: \(F_{\text{net}} = T\, \cos(\theta)\).
The length of the rope is \(l = 1.55\; {\rm m}\). Since this rope is also at the angle of \(\theta\) above the horizon, the radius of the circular motion in the horizontal plane would be \(r = l\, \cos(\theta)\).
Since the ball is in a centripetal motion, the resultant force on this ball would also be \(F_{\text{net}} = (m\, v^{2}) / (r)\), where \(v\) is the velocity of the ball.
Equate these two expressions of \(F_{\text{net}}\) to obtain:
\(\displaystyle T\, \cos(\theta) = F_{\text{net}} = \frac{m\, v^{2}}{r}\).
Additionally, \(T\, \sin(\theta) = m\, g\) since the forces on the vertical direction are balanced. Rewrite both this equation and the equation \(T\, \cos(\theta) = (m\, v^{2}) / (r)\) to isolate tension \(T\):
\(\left\lbrace \begin{aligned}& T\, \cos(\theta) = \frac{m\, v^{2}}{r} \\ &T\, \sin(\theta) = m\, g\end{aligned}\right.\).
\(\left\lbrace \begin{aligned}& T = \frac{m\, v^{2}}{r\, \cos(\theta)} \\ &T = \frac{m\, g}{\sin(\theta)}\end{aligned}\right.\).
Solve this system for velocity \(v\):
\(\begin{aligned}\frac{m\, v^{2}}{r\, \cos(\theta)} &= \frac{m\, g}{\sin(\theta)}\end{aligned}\).
Since \(r = l\, \cos(\theta)\):
\(\begin{aligned}\frac{m\, v^{2}}{l\, \cos(\theta)\, \cos(\theta)} &= \frac{m\, g}{\sin(\theta)}\end{aligned}\).
\(\displaystyle \frac{m\, v^{2}}{l\, \cos^{2}(\theta)} = \frac{m\, g}{\sin(\theta)}\).
\(\begin{aligned}v &= \sqrt{\frac{g\, l\, \cos^{2}(\theta)}{\sin(\theta)}} \\ &\approx \sqrt{\frac{9.81\, (\cos(12^{\circ}))^{2}}{(1.55)\, \sin(12^{\circ})}}\; {\rm m\cdot s^{-1}} \\ &\approx 5.40\; {\rm m\cdot s^{-1}}\end{aligned}\).
What a mechanics error is when writing?.
Mechanics error is referred to as the parts of speech and how they combine to form sentences.
Writing with great structure and syntactic redress is exceptionally vital for everybody. Understanding the thoughts that the students need to communicate in their essays will be easier when they are conveyed with the right grammar. Mechanical errors are diverse from grammatical errors. Grammar is the structure of written or talked language. It alludes to the parts of speech and how they combine to make sentences. Mechanics allude to the rules of the composed language, such as capitalization, accentuation, and spelling.” Since mechanics are the portion of composing, students moreover utilize mechanics in their exposition composing in arrange to deliver clearer intended messages. In this manner, this present study too centered on mechanical perspectives which contain capitalization, accentuation, and spelling.
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A 3-column table with four rows. The first column has entries Liquid A, Liquid B, Liquid C, Liquid D. The second column titled mass has entries 160 grams, 173 grams, 198 grams, 220 grams. The third column titled volume has entries 94 millimeters, 137 millimeters, 198 millimeters, 235 millimeters. Paula finds four unlabeled containers of clear, odorless liquid in her laboratory storage. One of the containers holds water. She knows that water has a density of 1.0 g/mL. Use the data provided to calculate the density of each liquid. Which liquid is water?
Answer:
The answer is Liquid C
Explanation:
Answer:
Liquid C
Explanation:
Edge2020. I got it right on there. Have a nice day... Please make brainliest if possible.
Jenny was applying her makeup when she drove into the student parking lot last Friday morning . Unaware that Cheryl was stopped in her lane aheadJenny rear ended Cheryl's car. Jenny's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds . Determine the magnitude of the force experienced by Jenny's car .
Answer: F = 102141N
Explanation: Newton's 2nd Law states that a force can change the motion of a body. The relation is given by
F = m.a
whose units are:
[F] = N
[m] = kg
[a] = m/s²
Jenny's car, at the moment of the break, had acceleration:
\(a=\frac{\Delta v}{\Delta t}\)
\(a=\frac{11}{0.14}\)
a = 78.57 m/s²
Then, Force is
F = 1300*78.57
F = 102141 N
Jenny's car experienced a force of magnitude 102141N.
The Tesla Model S Electric vehicle can go from 0 to 60 mi/hr (26.8 m/s) in only 1.9 seconds! How far does it move from rest until it reaches 60 mi/hr? Round your answer to the nearest whole meter.
Answer:
The Tesla moves approx. 25 meters from rest before reaching 60 mi/hr
Explanation:
Given:
Initial velocity = 0 m/s
Final velocity = 26.8 m/s
Time = 1.9 seconds
Acceleration = change in velocity/time
\(a = \frac{26.8}{1.9}\)
The equation to find displacement (Δx) with given starting and final velocity, time, and acceleration is:
\(x = x_{0} + v_{0}t + \frac{1}{2} at^{2}\)
Starting position and initial velocity both equal 0, so
\(x = \frac{1}{2} at^{2}\)
\(x=\frac{1}{2} (\frac{26.8}{1.9})(1.9)^{2}\)
x = 25.46m
Rounded to the nearest whole number, x = 25m