Answer:
Allah asked Abraham(Ibrahim)
In which stage is the individual willing to modify their behavior and their
environment to overcome the problem, as they are ready to change and take
the proper steps to make change happen?
OA. Maintenance
OB. Precontemplation
C. Action
D. Contemplation
SUBMIT
In C. Action stage is the individual willing to modify their behavior and environment to overcome problem, as they are ready to change and take proper steps to make change happen
Five phases of behaviour modification are identified as per phases of modification model. Precontemplation, Contemplation, Preparation, Action, and Maintenance are the phases. The person has made a commitment to change and is actively making changes to their surroundings and behaviour to address the issue in the Action stage.
In this mode, people have a strategy in place, and are generally moving in the right direction. Since it involves making significant changes to behaviour, attitudes, and lifestyle, the action stage is the most labor-intensive. In addition to having the tools and assistance they require for success, the person must be motivated and dedicated to making the change.
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A 2.0 kg block slides on a frictionless 15° inclined plane. A force parallel to the inclined plane is applied to the block. The acceleration of the block is 1.5 m/s? downhill. What is the applied force?
The applied force on the block sliding on the frictionless inclined plane is 1.9 N.
What is friction?Friction is the force that opposes the sliding or rolling motion of one body relative to another. For example, when you want to stop or slow down, you use your car's brakes because the friction created between the brakes and the wheels slows down or stops the car.
The unevenness of the two contact surfaces creates friction. When an object rides on another object, the surface irregularities become entangled and friction occurs. The rougher the surface, the more irregularities there are, and the greater the friction.
Equation of motion along an inclined plane:
Fₙ = (m×g×sinθ) - (m×a)
Where, Fₙ = applied force
m = mass of the block (2.0 kg)
g = gravitational acceleration (9.8 m/s²)
a = acceleration (1.5 m/s²)
θ = inclination of plane (15°)
Fₙ = (2 × 9.8 × sin15) - (2 × 1.5)
Fₙ = (19.6 × 0.25) - 3
Fₙ = 4.9 - 3
Fₙ = 1.9 N
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In Figure (a), both batteries have em - 1.20 V and the external resistance R is a variable resistor. Figure (6) gives the electric potentials V between the terminals of each battery as functions of
Curve 1 corresponds to battery 1, and curve 2 corresponds to battery 2. The horizontal scale is set by R, -0.500 . What is the internal resistance of (a) battery 1 and (b) battery 2?
0.60
V(V)
0
-0.350
(
R(0)
(6)
Answer:
i know da way ese'
Explanation:
During a tornado in 2008 the peachtree plaza Westin hotel in downtown Atlanta suffered damage. Suppose a piece of glass dropped near the top of the hotel falling 215 meters.
Time = t = 6.62 s
Explanation:
Given data:
Height = h = 215 m
Initial velocity = = 0 m/s
gravitational acceleration = g = 9.8 m/s²
Time = t = ?
According to the second equation of motion
As the initial velocity is zero, the first term of right-hand side of the above equation is equal to zero.
t² = 2h/g
t = square root 2h/g
t = square root 2x215/9.8
t = 6.62 s
A 10,000-Ω resistor has a tolerance of 5%. What is the maximum values of this resistor?
The maximum value of the resistance is 105,000 Ω
What is the maximum value of the resistance?
We are given the following properties of the resistor as;
Resistance = 10,000-Ω
Tolerance = 5%
Now, when we say a tolerance of 5%, it means the value of the resistance can only reduce or increase by a maximum of 5%.
Thus;
For a decrease of 5%, we would get the minimum value of the resistance which is;
Minimum value = (100% - 5%) * 10000
Minimum value = 95000 Ω
Then the maximum value of the resistance is;
Maximum Value = (100% + 5%) * 10000
Maximum Value = 105,000 Ω
Thus, the maximum value of the resistance is 105,000 Ω
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Using the same cost and time estimates, consider any trade-offs that Drehex Corporation may have to make to complete the project. Camilla John Nora Oracio Cost per Hour $40 $30 $20 $15 Time to Complete Job 20 hours 30 hours 40 hours 50 hours Ideally, the process of technological design should be cost-effective and time-effective. However, sometimes this is simply not possible and trade-offs are necessary. Explain the trade-offs Drehex Corporation may have to make to complete the project.
Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.
Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:
Cost vs. Time: The corporation may need to decide whether to prioritize completing the project quickly or keeping the costs low. If they want to minimize costs, they might opt for a longer completion time by choosing a team member with a lower cost per hour. Conversely, if time is crucial, they might choose a team member with a higher cost per hour to expedite the process.Expertise vs. Cost: The team members have different levels of expertise, as indicated by their respective costs per hour. Drehex Corporation may need to evaluate the trade-off between the level of expertise required for the project and the associated cost. They might decide to invest more in a highly skilled team member to ensure the quality and efficiency of the project, even if it means incurring higher costs.Resource Allocation: The corporation will need to allocate resources effectively among the team members to ensure a balanced workload. They may need to assign tasks and responsibilities based on individual strengths and expertise, considering the trade-off between utilizing the most capable team members and maintaining a fair distribution of work.Quality vs. Time/Cost: The trade-off between project quality and time/cost is a common consideration. If Drehex Corporation wants to deliver a high-quality output, they might need to allocate more time and resources to ensure thoroughness and attention to detail. Conversely, if time or cost constraints are significant factors, they may need to compromise on certain aspects of quality to meet project deadlines or budget limitations.Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.
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Answer:
Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.
Explanation:
A space station in the form of a large wheel,
356 m in diameter, rotates to provide an “artificial gravity” of 5.1 m/s2 for people
located at the outer rim.
What is the frequency of the rotational mo-
tion for the wheel to produce this effect? Answer in units of rev/min.
The frequency of the rotational motion for the wheel to produce this effect 1.62 rev/min.
What is the angular speed of the wheel?
The angular speed of the wheel is calculated by applying the formula for centripetal acceleration of the wheel.
a = v²/r = ω²r
where;
ω is the angular speed of the wheel in radian per secondsr is the radius of the wheelThe radius of the wheel = 356 m / 2 = 178 m
ω = √a/r
ω = √(5.1/178)
ω = 0.17 rad/s
The angular speed in revolution per minute is calculated as follows;
ω = 0.17 rad/s x 1 rev/2π rad x 60 s/1min
ω = 1.62 rev/min
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Car P travels due East along a straight highway at a constant speed of 30 m/s. At 9:00
a.m., P passes Exit 17. At precisely the same moment, car Q passes Exit 16, traveling due
West at a constant 26 m/s. Slightly later, car P and car Q pass the same point. Knowing
the exits are exactly 7 km apart, determine how many minutes past 9:00 a.m. the cars pass
each other.
Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.
How to calculate time?The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.
The distance between the cars is 7 km = 7000 m.
The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.
1750 seconds is 29 minutes and 15 seconds.
To calculate the time in minutes;
Let:
v_p = the speed of car P (m/s)
v_q = the speed of car Q (m/s)
d = the distance between the cars (m)
t = the time it takes for the cars to pass each other (s)
Given that:
v_p = 30 m/s
v_q = 26 m/s
d = 7000 m
Use the equation for relative velocity to find the velocity of the cars relative to each other:
v_r = v_p - v_q
v_r = 30 m/s - 26 m/s = 4 m/s
Use the equation for distance to find the time it takes for the cars to pass each other:
d = v_r × t
7000 m = 4 m/s × t
t = 7000 m / 4 m/s = 1750 s
Convert 1750 seconds to minutes and seconds:
1750 s = 29 minutes and 15 seconds
Therefore, the cars pass each other at 9:29 and 15 seconds a.m.
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Vector A points along the + y axis and a magnitude of 100.0 units. Vector B points at an angle of 60.0 degrees above the +x axis and has a magnitude of 200.0 units. Vector C points along the +x axis and has a magnitude of 150.0 units. Which vector has (a ) the largest x component and (b) the largest y component ?
Answer:
vector quantities are resolved into their component form (along the x and y-axis) before adding them. Let us assume that two vectors are
→
a
=
x
1
^
i
+
y
1
^
j
and
→
b
=
x
2
^
i
+
y
2
^
j
, we can find the sum of two vectors as follows.
→
a
+
→
b
=
x
1
^
i
+
y
1
^
j
+
x
2
^
i
+
y
2
^
j
=
(
x
1
+
x
2
)
^
i
+
(
y
1
+
y
2
)
^
j
The direction of the sum of the vectors (with positive x-axis) is,
θ
=
tan
−
1
(
y
1
+
y
2
x
1
+
x
2
)
Out of all the largest x component is of Vector C of value 150i and Vector B will have highest y component of value 173j
What is vector ?Vectors are objects which have both, magnitude and direction. Magnitude defines the size of the vector. It is represented by a line with an arrow, where the length of the line is the magnitude of the vector and the arrow shows the direction.
Vector A = direction is in y direction = 100j
Since , this vector is only in y direction and have no component in x direction , so its x component will be = 0i
Vector B = direction is at angle of 60.0 degrees above the +x axis
Resolving into x and y components
x component = Vector B*cos(60) = Vector B * (1/2) = Vector B /2 = 200 /2
= 100i
y component = Vector B * sin(60) = Vector B * \(\sqrt{3}\)/2 = 173j
Vector C = direction is along the +x axis
hence , it will not have any y component
x component = 150i
y component = 0j
Out of all the largest x component is of Vector C of value 150i and Vector B will have highest y component of value 173j
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outline the reason for gay luccas law of volume
Gay-Lussac's law of volume states that for a fixed mass of an ideal gas kept at a fixed pressure, the volume and temperature are directly proportional.
What is Gay-Lussac's law about?This means that if the temperature of a gas is increased, its volume will also increase, and vice versa.
The reason for Gay-Lussac's law of volume is that the average kinetic energy of the gas molecules is directly proportional to the temperature. As the temperature increases, the molecules move faster and collide with the walls of the container more often. This causes the pressure to increase. However, if the pressure is kept constant, the increase in pressure will cause the volume to increase.
Gay-Lussac's law of volume can be expressed mathematically as follows:
V₁ / T₁ = V₂ / T₂
where:
V₁ = initial volume of the gas
T₁ = initial temperature of the gas
V₂ = final volume of the gas
T₂ = final temperature of the gas
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Gay-Lussac's Law of Volume provides a useful relationship between the volumes of reactant and product gases, allowing for predictions and calculations in chemical reactions involving gaseous substances.
Understanding Gay-Lussac's Law of VolumeGay-Lussac's Law of Volume, also known as the Law of Combining Volumes of Gases, states that "the volumes of gases involved in a chemical reaction at constant temperature and pressure are in the ratio of small whole numbers."
Reason for Gay-Lussac's Law of Volume
1. Avogadro's Law: According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain an equal number of particles (atoms, molecules, or ions). This law established the concept of the mole, which is a unit of measurement representing a fixed number of particles. Since the number of particles is the same, the volume occupied by these particles should also be the same.
2. Stoichiometry: Chemical reactions involve the rearrangement of atoms and molecules to form new substances. The coefficients in a balanced chemical equation represent the relative amounts of reactants and products. In the gaseous state, these coefficients can be directly related to the volumes of the gases involved. For example, if the balanced equation shows that two volumes of gas A react with three volumes of gas B to form four volumes of gas C, it implies that the gases react in simple volume ratios.
3. Gas Behavior: Gases follow certain ideal gas laws, such as Boyle's Law (pressure-volume relationship), Charles's Law (temperature-volume relationship), and Gay-Lussac's Law (pressure-temperature relationship). These laws describe how the physical properties of gases change under different conditions. Gay-Lussac's Law of Volume specifically relates the volumes of gases involved in a chemical reaction and shows that the volumes are proportional to each other.
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1. Rectifiers:
A crystal diode having internal resistance rf = 200 is used for half-wave
rectification. If the applied voltage v = 50 sin o t and load resistance
RL=800 22, find:
(A) Im, Idc, Irms
(B) A.C. power input and D.C. power output
(C) d.c. output voltage.
(D) Efficiency of rectification.
A crystal diode having internal resistance rf = 200 is used for half-wave
rectification. If the applied voltage v = 50 sin o t and load resistance
RL=800 22- Efficiency of rectification. So, option (d) is correct.
What is voltage?
An electrical circuit's power source exerts pressure known as voltage on charged electrons (current), causing them to flow through a conducting loop and perform tasks like lighting a lamp. Voltage is measured in volts and is simply equal to pressure (V).
What is rectification?
Using one or more P-N junction diodes, a rectifier is a piece of electronic equipment that changes alternating electricity into direct current. As a one-way valve that only permits current to flow in one direction, a diode functions as a device. Corrective action is the name for this process.
Therefore, crystal diode having internal resistance rf = 200 is used for half-wave rectification. If the applied voltage v = 50 sin o t and load resistance
RL=800 22- Efficiency of rectification. So, option (d) is correct.
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Common static electricity involves charges ranging from nanocoulombs to microcoulombs. (a) How many electrons are needed to form a charge of −7.50 nC? electrons (b) How many electrons must be removed from a neutral object to leave a net charge of 0.580 µC? electrons
Answer:
a) 4.681*10^10 electrons
b) 3.67*10^12 electrons
Explanation:
The amount of electrons in a charge of 1C is:
\(1C=6.2415*10^{18}\ electrons\)
You use the previous equality as a conversion factor.
a) The sing of the charge is not important in the calculation of the number electrons, so, you use the absolute value of the charge
\(7.50nC=7.50*10^{-9}C*\frac{6.2415*10^{18}}{1C}=4.681*10^{10}\ electrons\)
In 7.50nC there are 4.61*10^18 electrons
b)
\(0.580\mu C=0.580*10^{-6}C*\frac{6.2415*10^{18}}{1C}=3.67*10^{12}\ electrons\)
To obtain a charge of 0.580 µC in a neutral object you need to take out 3.67*10^12 electrons
Select the correct answer.
A car moves with an average speed of 45 miles/hour. How long does the car take to travel 90 miles?
OA.
2 minutes
OB.
2 hours
O c.
45 minutes
OD.
45 hours
O E.
90 minutes
Reset
Next
Answer:
B. 2 hours
Explanation:
45 miles an hour times 2 is 90 miles in 2 hours
Answer:
B. 2 Hours
Explanation:
If your going at a constant speed of 45 miles per hour then, it will take two hours because 45x2 is 90. and if you divided 90 and 45, you will get 2.
A golf ball is whacked in a direction 25 degrees south of the east axis. The ball travels 125m. What are the east and north components of its displacement?
We are given:
Direction of motion: 25 degrees south of the east axis
Distance covered = 125 m
East component of the Ball:
this component is denoted by green color in the image
Once we drop a perpendicular from the end of the direction vector on the x-axis, we get a right angled triangle
The magnitude of the side of the triangle on the x-axis denotes the east component of the ball
Using trigonometry, we find that the east component of the ball is:
125 * Cos(25 degrees)
125 * 0.9 = 112.5 i (here, i denotes rightward direction on the x-axis)
North Component of the Ball:
this component is denoted by blue color in the image
Using trigonometry, we find that the North component of the ball is:
125* Sin(25 degrees) (-j) [j denotes upward movement on the y-axis, since the vector is acting downwards, we have used '-j']
125 * 0.42 (-j)
52.5 (-j) = -52.5 j
Therefore the direction vector of the ball is 112.5 i - 52.5 j
where 112.5 i is the East Component and -52.5 is the North Component
6. A metal block increases in temperature from 15 °C to 60 °C when supplied with 13 500 J of heat energy.
a) Calculate the heat capacity of the metal.
b) Calculate the specific heat capacity of the metal, if this sample has a mass of 0.75 kg.
Answer:
Since 1 cal = 4.19 J the heat Q received by the metal is
Q = 13,500 J * 1 C / 4.19 J = 3,222 calories
S = ΔQ / (ΔT * ΔM) = 3222 cal / (45 deg C / 750 gm)
S = .095 cal / gm deg C
Note that specific heat capacity for Cu is .093 cal / gm deg C
Sun, Earth, Moon Models Lab Quiz
What was the purpose of the experiment?
HELP PLS
The aim of this study is to develop a Sun-Earth-Moon model that will serve to describe "the real and apparent movements of the Sun-Earth-Moon system and the results of these movements".
A fundamental topic in astronomy, that is difficult To properly understand the why requires three-dimensional thinking and imagination. In this context;
• Students have difficulty understanding basic concepts of astronomy; H.
such as creating seasons, phases of the moon, lunar and solar eclipses that require three-dimensional thinking must be properly understood. So to teach difficult abstract concepts,
• To solve the problem of the lack of materials and tools related to matter.
• To enhance learning retention by engaging students' multiple senses,
• Capturing concepts visually and verbally increases skills. Remember the image of this concept when you meet its verbal equivalent, or reversed. Therefore, to help students remember what they are learning,
• Have students see tools, objects, and events that they cannot see perceive with their five senses,
• Show students tools, objects, and events that they cannot reach
or bring to class,
• Attract attention and arouse interest in a topic, needed a model to grow.
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The orbital radius of Venus
is 10.8 x 1010 m. Its rotation
period is 224.7 days. What is its
orbital speed?
A 20 km s-1 C 35 km s-1
B 25 km s-1 D 62 km 5-1
Answer:
v = 35 km/s
Explanation:
Given that,
Orbital radius of Venus, \(r=10.8\times 10^{10}\ m=10.8\times 10^{10}\times 10^{-3}=10.8\times 10^{7}\ km\)
The rotation period is, \(T = 224.7\ \text{days}=19414080\ s\)
We need to find the orbital speed of the Venus. The formula for the orbital speed is given by :
\(v=\dfrac{2\pi r}{T}\\\\v=\dfrac{2\pi \times 10.8\times 10^{7}}{19414080}\\\\=34.95\ km/s\)
or
v = 35 km/s
So, the orbital speed of Venus is 35 km/s.
(a) Express the following in their respective units
12nm to pm
Answer:
To convert nanometers (nm) to picometers (pm), you need to multiply the value by 1,000. Therefore, to convert 12 nanometers to picometers, you would perform the following calculation:
12 nm * 1,000 pm/nm = 12,000 pm
So, 12 nanometers is equal to 12,000 picometers.
4) A force of 100 N is applied to the wrapped present, giving it an
acceleration of 2 m/s2. What is the mass of the object?
Please help me nowwww!!!!!!!!
Answer:
50kg
Explanation:
Force = 100N
Acceleration = 2 m/s2
Mass = ?
From formula,
Force = Mass * Acceleration
100 = Mass * 2
Mass = 50 kg
Hence ,mass of object is 50 kg.
In short,Force(F) = 100N
Acceleration(a) = 2 m/s2
Mass(m) = ?
We know,
F = ma
100 = m x 2
m = 100/2
m = 50kg
Hence ,mass of object is 50 kg.
Answer:
50 kg
Explanation:
Force(F) = 100N
Acceleration(a) = 2 m/s2
Mass(m) = ?
We know,
F = ma
100 = m x 2
m = 50kg
hence ,mass is 50 kg.
Although science strives for objectivity by basing conclusions and explanations on data gathered during scientific investigations,
some subjectivity still exists in science, since it is a human endeavor. What beneficial qualities exist in scientific processes,
methods, and knowledge as a result of science being a human endeavor?
A. bias and favoritism
B.
creativity and discovery
C. inaccuracies and errors
D.
all of these
Answer: creativity and discovery
Explanation: i got it right on study island .
Answer:
CREATIVITY AND DISCOVERY
Explanation:
STUDY ISLAND
Please help with this
2.38 m/s to the left is the tugboat's speed immediately upon the rope's attaining full tension (opposite to the initial direction of motion of the barge).
What does velocity look like in practise?The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car travelling north on a highway or a rocket taking flight.
The overall momentum before the rope tightens is:
p1 = m1 * v1 + m2 * v2
The total momentum after the rope becomes taut is: p2 = (m1 + m2) * v
Since the total momentum is conserved, we can equate p1 and p2:
m1 * v1 + m2 * v2 = (m1 + m2) * v
Substituting the given values, we get:
350 Mg * (-5 m/s) + 65 Mg * (0.5 m/s) = (350 Mg + 65 Mg) * v
Simplifying and solving for v, we get:
v = [-350 Mg * (-5 m/s) + 65 Mg * (0.5 m/s)] / (350 Mg + 65 Mg)
v = -2.38 m/s
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An automobile accelerates from zero to 30 m/s in 6 s. The wheels have a diameter of 0.4 m. What is the angular acceleration of each wheel
Answer:
12.5 rad/s²
Explanation:
Angular Acceleration: This can be defined as the ratio of linear acceleration and radius. The S.I unit is rad/s²
From the question,
a = αr................... Equation 1
Where a = linear acceleration, α = angular acceleration, r = radius.
But,
a = (v-u)/t.............. Equation 2
Where v = final velocity, u = initial velocity, t = time.
Substitute equation 2 into equation 1
(v-u)/t = αr
make α the subject of the equation
α = (v-u)/tr................. Equation 3
Given: v = 30 m/s, u = 0 m/s, t = 6 s, r = 0.4 m
Substitute into equation 3
α = (30-0)/(0.4×6)
α = 30/2.4
α = 12.5 rad/s²
So how should i get (i)
Still didn’t get it ?
Answer & Explanation:
using a ruler measure the distance between the pivot and the center point of the load
note : prevent zero error
2. The components of vector A are given as follows:
Ax = 5.6 Ay = -4.7
What is the angle between vector A and positive direction of x-axis?
Answer:
50 degree.
Explanation:
Given that the components of vector A are given as follows: Ax = 5.6 Ay = -4.7
The angle between vector A and B in the positive direction of x-axis will be achieved by using the formula:
Tan Ø = Ay/Ax
Substitute Ay and Ax into the formula above.
Tan Ø = -4.7 / 5.6
Tan Ø = -0.839
Ø = tan^-1(-0. 839)
Ø = - 40 degree
Therefore, the angle between vector A and B positive direction of x-axis will be
90 - 40 = 50 degree.
In the electric of capacitance 4 ,3 and 2 microfaradas, respectively, are connected in senes to a battery of 260 V , calculate the charge?
The total charge in the circuit is 240 microcoulombs.
To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.
In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.
To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.
Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.
Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.
Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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Find the mass of an object on planet F if its weight is 650 N (g = 13m/s^2)
Answer:
the object's mass is 50 kg
Explanation:
We use Newton's second law to solve for the mass:
F = m * a , then m = F / a
In our case, the acceleration is the gravitational acceleration on the planet, and the force is the weight of the object on the planet. So we get:
m = w / a = 650 N / 13 m/s^2 = 50 kg
Then, the object's mass is 50 kg.
A ball that is attached to a string travels in a horizontal, circular path, as shown in Figure 1. At time t0 , the ball has a speed v0 . The forces exerted on the ball at t0 are represented by the free-body diagram, as shown in Figure 2. At a later time t1 , the tangential speed of the ball is increased to 2v0 . What is the magnitude of the force that the ball exerts on the string at time t1 ?
Answer:
F₁ = 4 F₀
Explanation:
The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:
F₀ = mv₀²/r --------------- equation (1)
where,
F₀ = Force on string at t₀
m = mass of ball
v₀ = speed of ball at t₀
r = radius of circular path
Now, at time t₁:
v₁ = 2v₀
F₁ = mv₁²/r
F₁ = m(2v₀)²/r
F₁ = 4 mv₀²/r
using equation (1):
F₁ = 4 F₀
Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3
Answer:
Ro = 8.65 [g/cm³]
Explanation:
We must remember that density is defined as the ratio of mass to volume.
\(Ro=m/V\)
where:
m = mass = 0.450 [kg] = 450 [g]
V = volumen = 52 [cm³]
Ro = density [g/cm³]
Now replacing:
\(Ro = 450/52\\Ro = 8.65 [g/cm^{3} ]\)
An african bush elephant has a mass of 5,900 kg and is on a skateboard traveling to the
left at 10 m/s. What is her momentum?
. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification
The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.
Given:
Object height (h) = 5 cm
Focal length of the convex lens (f) = 10 cm
Object distance (u) = 15 cm (positive since it's on the same side as the incident light)
To determine the nature, position, and size of the image, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values:
1/10 = 1/v - 1/15
To simplify the equation, we find the common denominator:
3v - 2v = 2v/3
Simplifying further:
v = 30 cm
The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.
To find the magnification (M), we use the formula:
M = -v/u
Substituting the values:
M = -30 / 15 = -2
The magnification is -2, indicating that the image is inverted and twice the size of the object.
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