while an object near the earth's surface is in free fall, its acceleration increases. mass increases. mass decreases. velocity increases.

Answer:

The potential energy is zero since the rock isn't moving.

Answer:

149 N

Explanation:

We can start by resolving the forces acting on the chair in the vertical direction:

N - mg = 0

where N is the normal force exerted by the floor on the chair, m is the mass of the chair, and g is the acceleration due to gravity.

Since the chair is not accelerating vertically, we know that the sum of the forces in the vertical direction is zero.

Now, let's resolve the forces acting on the chair in the horizontal direction. We'll use the force you applied and the force of friction between the chair and the floor:

F - f = ma

where a is the acceleration of the chair, and f is the force of friction.

The force of friction can be calculated as:

f = μN

where μ is the coefficient of friction between the chair and the floor.

We don't know the coefficient of friction or the acceleration of the chair, so we can't solve this equation directly. However, we can use the fact that the chair is sliding along the floor, which tells us that the force of friction is equal and opposite to the force you applied:

f = F sinθ = 39.0 N * sin(36.0°) ≈ 23.5 N

Therefore, we can substitute this value for f in the horizontal force equation:

F - f = ma

39.0 N * cos(36.0°) - 23.5 N = ma

Solving for a, we get:

a ≈ 0.34 m/s^2

Now we can go back to the vertical force equation and solve for the normal force:

N - mg = 0

N = mg = (110 N) + (m chair)(a)

We don't know the mass of the chair, but we can use the acceleration we just calculated to find it:

a = F/(m chair)

m chair = F/a ≈ 115 kg

Substituting this value for the mass of the chair, we get:

N = mg = (110 N) + (115 kg)(0.34 m/s^2)

N ≈ 149 N

Therefore, the normal force that the floor exerts on the chair is approximately 149 N.

Answer:

-0.375 m/s2

Explanation:

To find the acceleration due to gravity in this planet, we can use the Torricelli formula of UALM (uniformly accelerated linear motion):

V^2 = Vo^2 + 2*a*S

Where V is the final velocity, Vo is the inicial velocity, a is the acceleration and S is the total displacement.

With V = 3, Vo = 0 and S = -12, we have:

3^2 = 0^2 - 2*a*12

24a = -9

a = -9/24 = -0.375 m/s2

Answer:

Step 1:

The main answer is as follows:

The S-P interval (lag time) for the seismogram at the Maesters station at The Eyrie (EYR) is X seconds.

Step 2:

What is the duration of the S-P interval (lag time)?

Step 3:

The S-P interval, also known as the lag time, is the time difference between the arrival of the S-wave and the P-wave on a seismogram. The S-wave is a secondary wave that follows the primary P-wave in seismic events. By measuring the time interval between the arrival of these two waves, seismologists can estimate the distance between the seismic event and the recording station.

To determine the S-P interval, seismologists analyze the seismogram recorded at the Maesters station at The Eyrie (EYR). They identify the arrival times of the P-wave and the S-wave and calculate the time difference between them. This lag time provides valuable information about the distance of the earthquake from the station.

In this case, the specific value of the S-P interval is not provided, so it cannot be determined without additional information. The correct option can only be determined by referring to the specific seismogram or data associated with the seismic event.

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Answer:

It allows people in different places and different countries to use the same units

Explanation:

A 4 kg particle moves in an xy-plane and force on the particle is F = (-3.0N)i so,

The product of an object's mass and its velocity is its momentum. Momentum exists in all mass-moving objects. Only the fact that it deals with rotating or spinning objects makes angular momentum different.

A characteristic known as angular momentum describes the rotating inertia of an item or set of objects when they are moving along an axis that may or may not pass through them. The Earth possesses spin angular momentum from its daily rotation around its axis and orbital angular momentum from its yearly revolution around the Sun. Since angular momentum is a vector quantity, its full representation calls for the identification of both a magnitude and a direction.

a)  Particle  angular momentum  =  rp

                                                    =  4[(2 i  +  4 j) x ( - 4 j) ]

                                                     =   (-32 kg*m2/s)  k

b)     particle momentum about point  =   4[(2 i  +  0 j)  x ( - 4 j) ]

                                                           =   (-32 kg*m2/s)  k

c)   torque acting on particle about origin  =   rF

                                                              =   [(2 i  +  4 j) x (-3 i)]

                                                             =      (12  N.m)  k

d)    torque acting on particle about point  =  [(2 i  +  0 j) x (-3 i)]

                                                                   =    0  N.m

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Answer:

84 kj/min = 1.4 kj/sec

Power Out / Power In = Heat Out / Heat In - Coefficient of Performance

1.4 kj/sec / 1.2 kj/sec = 1.17 = COP

In a microcontroller, r/w memory is assigned the address range from 2000h to 21ffh, the size of r/w memory is 544 bytes.

In a microcontroller, r/w memory is assigned the address range from 2000h to 21ffh. To calculate the size of r/w memory, we need to find the total number of memory locations between 2000h and 21ffh. The memory range can be calculated using the formula.

Memory range = Last address – First address + 1. Memory range of r/w memory = (21ffh – 2000h) + 1= 220h.To find the size of r/w memory, we need to multiply the total number of memory locations by the size of each memory location. Since the size of each memory location in a microcontroller is one byte, the size of r/w memory is 220h × 1 byte = 544 bytes. Therefore, the size of r/w memory is 544 bytes.

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The value of a^2 is 3600 if Starting from rest, a particle moves along an axis from point A to point B with constant acceleration a = 2.20 m/2 through displacement d = 500 m.

To determine the value of a^2, we need to use the relationship between acceleration, displacement, and time, which is given by the equation:

\(d = 1/2 a t^2\)

First, we can find the time t1 required for the particle to travel from point A to point B by using the equation:

\(d = 1/2 a t1^2\)

Substituting the given values, we get:

\(500 = 1/2 (a) (t1)^2\)

Rearranging and solving for t1:

\(t1 = \sqrt{} (500 / (1/2 a)) = \sqrt{} (1000 / a)\)

Next, we can find the time t2 required for the particle to travel from point B to point C by using the equation:

\(dz = 1/2 a t2^2\)

Substituting the given values, we get:

\(300 = 1/2 (a) (t2)^2\)

Rearranging and solving for t2:

\(t2 =\sqrt{} (300 / (1/2 a)) = \sqrt{} (600 / a)\)

Finally, we can use the total time t to find the value of a by using the equation:

t = t1 + t2

Substituting the values of t1 and t2, we get:

60 = sqrt(1000 / a) + sqrt(600 / a)

Squaring both sides, we get:

\(3600 = 1000 / a + 600 / a + 2 sqrt(1000 * 600) / a\)

Rearranging and solving for a:

\(a = sqrt(3600 * a / (1000 + 600)) = sqrt(3600 * a / 1600)\)

Squaring both sides again, we get:

\(a^2 = 3600 / (1600 / a) = 3600 * a / 1600\)

Rearranging and solving for a^2:

\(a^2 = 3600^2 / 1600 = (60^2)^2 / (40^2) = 3600.\)

So, the value of a^2 is 3600.

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STP is defined as the standard temperature and pressure. These are some standard values given in 1982. the approximate value of n according to the ideal gas law will be 0.986.

The ideal gas equation is derived from the Boyle and Charles law states that the product of pressure and volume is directly propotional to the temperature at STP.

It is mathematically given as

\(\rm pv=nRT\)

P is the pressure =100kPa at STP.

R is universal gas constant=8.314 j/kgk

v is the volume=22.4 L=22.4×10³ m³

T is the temperature =273.15 K at STP

\(\rm pv=nRT\\\\\rm n=\frac{RT}{pv} \\\\\ \rm n=\frac{8.314\times273.15}{100\times10^3\times10^{-3}} \\\\\rm n=0.986\)

Hence the approximate value of n according to the ideal gas law will be 0.986.

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Answer:

1

Explanation:

1 mol = 22.4 L

Answer:

िििििििििििििििििििििििििोोोोोोोोोोोोोोोोोोो

To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.

First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:

1/Req = 1/22 + 1/22 + 1/22

1/Req = 3/22

Taking the reciprocal of both sides, we find:

Req = 22/3 Ω

Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:

I = V/R

Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:

I = 1.1/32

Calculating this value, we find:

I ≈ 0.034375 A

Therefore, the current in the resistor is approximately 0.034375 A.

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Answer:

Gravity

Gravity as well as electrostatic and magnetic attraction and repulsion provide real life examples of forces being exerted by one object on another without them being in contact with each other. Many children are aware of magnetism and have played with fridge magnets.

Explanation:

A force that one object can apply to another object without touching it is Gravity.

Gravity is the force of attraction between the two objects separated by a particular distance. Gravity force is exerted on every object present in the universe.

Gravity as well as electrostatic and magnetic attraction and repulsion provide real-life examples of forces being exerted by one object on another without them being in contact with each other. Many children are aware of magnetism and have played with fridge magnets.

Therefore force that one object can apply to another object without touching it is Gravity.

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Answer:

Explanation:

The mass of the rocket given it's acceleration and force can be found by using the formula

\(mass = \frac{f}{a} \\ \)

where

f is the force in N

a is the acceleration in m/s²

From the question

f = 54,080 N

a = 65 m/s²

We have

\(mass = \frac{54080}{65} = 832 \\ \)

We have the final answer as

hope this helps you

Answer:

The answer is Revising

Answer:

D

Explanation:

Revising

The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

Answer:

The initial current is just V / R    because the capacitor will generate not back EMF

Q = V C   for a capacitor - since there is no charge initially on the capacitor the voltage across the capacitor will be zero

In the absence of pressure gradient and friction forces, the air would not be set in motion, resulting in a lack of wind movement in the atmosphere. These forces play a crucial role in driving and impeding the flow of air.

Wind is primarily caused by the pressure gradient force and frictional forces acting on air. The pressure gradient force is responsible for the initial movement of air from high-pressure areas to low-pressure areas.

This force arises due to the imbalance in atmospheric pressure. Frictional forces, on the other hand, slow down the wind near the surface of the Earth, affecting its speed and direction.

Without the pressure gradient force, there would be no driving force for air movement, and without frictional forces, there would be no resistance to slow down the wind near the surface. Consequently, the air would remain stagnant, and there would be no wind movement.

Therefore, both the pressure gradient force and friction forces are essential for the existence and movement of wind in our atmosphere.

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Answer:

The force will be "5,488". A further solution is provided below.

Explanation:

The given values are:

speed,

v = 100m/s

mass,

m = 80 kg

acceleration,

a = 7

Now,

Radius will be:

⇒ \(r=\frac{v^2}{ac}\)

⇒    \(=\frac{(100)^2}{7\times 9.8}\)

⇒    \(=\frac{10000}{68.6}\)

⇒    \(=145.77\)

Force will be:

⇒ \(F=m\times ac\)

⇒     \(=80\times 68.6\)

⇒     \(=5488\)

Answer:

D.

Explanation:

I think its D. because Tea during a cold workout isnt safe at all. Drinking tea while working out adds weight and you just simply dont need tea when working out.. Hope this helps man :)

C. You shouldn't exercise while drinking hot tea because you can spill it and burn yourself especially while on a treadmill.

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\(\left[\begin{array}{ccc}Thanks,\\JustSomeIdiot\end{array}\right]\)

To determine which of the four general expansion models best describes the present-day universe, we must rely on observational evidence. Accurate measurements of distances between galaxies and the masses of galactic central supermassive black holes are essential for making these determinations.

One effective method for measuring distances involves using standard candles, such as white dwarf supernovae, which allow us to gauge distances accurately. Another approach involves observing active galactic nuclei X-ray and gamma-ray bursts, which also serve as reliable distance indicators.

Additionally, measuring the masses of galactic central supermassive black holes can provide insight into the expansion model. Mapping the relative speeds of stellar clusters and examining the relative amounts of gas and stars in galaxies are suitable techniques for obtaining such measurements.

In summary, a combination of accurate distance measurements using standard candles like white dwarf supernovae and active galactic nuclei bursts, along with mass measurements of galactic central supermassive black holes, can help us identify the most appropriate expansion model for the present-day universe.

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The lamp will develop a power of 60 watts when connected to a 120-volt electrical outlet.

To calculate the power developed by an electric lamp, we can use the formula:

Power (P) = Current (I) × Voltage (V)

Given that the current passing through the lamp is 0.50 amperes (A) and the voltage of the electrical outlet is 120 volts (V), we can substitute these values into the formula:

Power (P) = 0.50 A × 120 V

P = 60 watts (W)

The power of an electrical device is determined by the product of the current flowing through it and the voltage applied across it. In this case, the current passing through the lamp is given as 0.50 amperes, and the voltage of the electrical outlet is 120 volts.

By multiplying these values together, we find that the power developed by the lamp is 60 watts. Power is the rate at which energy is consumed or transferred, and in the case of the lamp, it represents the rate at which electrical energy is converted into light and heat.

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Answer:

c

Explanation:

on edg

Answer:

Explanatioit cn:

Answer: Yes the further the sun is away the longer the shadow is. At noon,the shadow is the shortest because its straight up above you. If this helps pls mark brainliest!

Answer:

Further the sun, the longer the shadow; true.

Answer:

with what? ..................