Answer:
1
Explanation:
it go up than down than up
party hearing. as the number of people at a party in creases you must rasie your voice for a listerner to her you agaisnt the backgorund noise of the other party ogesrs. however, once you reach
The listener must be 0.67 meters away from the speaker in in order to hear that speaker's voice.
What does the word "yelling" mean?to shout or make a loud sound, typically out of anger, discomfort, or excitement: This morning, our neighbors were shouting (using expletives) at one another. The youngster screamed in agony.
Briefing :difference in sound level is-
Δβ=βf −βt =(10dB)log( If/It)
Thus, if Δβ=5.0 db, then log(I f /I t )=1/2, which implies that It = √10 It.
The intensity, however, is lower at a separation r from of the source because
I= P/4πr²
where P represents the source's power.
A fixed P implies that Itrt²=Ifrf². Thus, with
rt =1.2 m, we obtain
rt =( If/It ) ∧1/2 rt
=(1/10) ∧1/4 (1.2 m)
=0.67 m.
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The complete question is -
Party hearing. As the number of people at a party increases, you must raise your voice for a listener to hear you against the backgrounds noise of the other partygoers. However, once you reach the level of yelling, the only way you can be heard is if you move closer to your listener, into the listener's "personal space". Model the situation by replacing you with an isotropic point source of fixed power P and replacing your listener with a point that absorbs part of your sound waves. These points are initially separated by r1 =1.20 m. If the background noise increases by Δβ=5 dB, the sound level at your listener must also increase. What separation rf is then required?
The normal force n with arrow, the gravitational force mg with arrow, and the upward component of the applied force do no work on the sled because they're perpendicular to the displacement. The mass of the sled didn't come into play here, but it is important when the effects of friction must be calculated and in the work-energy theorem. QUESTION How does the answer for the work done by the applied force change if the load is doubled
Answer and Explanation:
Should let force applied throughout horizontal direction become "F", as well as the displacement of that same sled, become "d." This same force's work seems to be "Fd."Presently, unless the mass would be doubled as well as the force is applied continues to remain the very same, the work used by the force to keep moving the sled by such the distance "d" would then remain the same.So that the above seems to be the right answer.
The horizontal surface on which the block slides is frictionless. The speed of the block before it touches the spring is 5.0 m/s. How fast is the block moving at the instant the spring has been compressed 15 cm? The spring constant k = 2000 N/m.
The block moving at instant the spring is compressed 15cm is √[(25m - 45)/m]
What is conservation of energy principle?When there is no external force acting on the system, the total mechanical energy remains conserved.
K.E i = K.E f + SPE
1/2 mu² =1/2 mv² + 1/2 kx²
Substitute u = 5m/s, k =2000N.m and x =0.15m, we get the final velocity
1/2 mu² =1/2 mv² + 1/2 kx²
v =√[(25m - 45)/m]
Thus, the block moving at the instant the spring has been compressed 15 cm is √[(25m - 45)/m]
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Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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A kettle is rated as 2.3kW. A mass of 750g of water at 20oC is poured into the kettle.When the kettle is switched on, it takes 2.0 minutes for the H2O to start boiling. In a further 7.0 minutes, half of the mass of H2O is boiled away. Estimate for this water: The specific heat capacity, the specific latent heat of vaporization.
The specific heat capacity of water, Cw is 4.6 J/g/K
The specific latent heat of vaporization of water, Cv is 2576 J/K
What is the amount of energy used by the kettle?Electrical energy is defined as the product of electrical power in watts and time in seconds.
Mathematically;
Electrical energy = power * time
The amount of energy used by the kettle to boil the water is calculated below:
Energy used = 2.3 kW * 1000 W/kW * 2 * 60 s/min
Energy used = 276000 J
The specific heat capacity of water, Cw is determined as follows:
Energy = mass * Cw * temperature change
Cw = Energy / mass * temperature change
Cw = 276000 / 750 * (100°C - 20°C)
Cw = 4.6 J/g/K
The amount of energy used by the kettle to evaporate half the mass of the water is calculated below:
Energy = 2.3 kW * 1000 W/kW * 7 * 60 s/min
Energy used = 966000 J
The specific latent heat of vaporization of water, Cv is determined as follows:
Energy = mass * Cv
Cv = Energy / mass
Cv = 966000 / (750 * 0.5)
Cv = 2576 J/K
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In which type of collision is no kinetic energy converted to heat or sound
energy?
Answer:
elastic collision
An elastic collision occurs when the two objects "bounce" apart when they collide. Two rubber balls are a good example. In an elastic collision, both momentum and kinetic energy are conserved. Almost no energy is lost to sound, heat, or deformation.
I hope it's helpful!
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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What do you know about the current at different points in a series circuit?
A)it increases the farther it gets from the battery
B)it decreases the farther it gets from the battery
C)it decreases based on the resistance of the devices
D)it is the same at all points in the circuit
Answer:
D
Explanation:
In a series circuit there is only one path for the current to complete the path....so D
A physics instructor wants to project a spectrum of visible light colors from 400 nm to 700 nm as part of a classroom demonstration. She shines a beam of white light through a diffraction grating with 500 lines per mm, projecting a pattern on a screen 2.4 m behind the grating. How wide is the spectrum corresponding to m=1?
Answer:
औडंठः की दुनिया कार्टून दर्शन होली है और यह बियर का अच्छा विकल्प है। विकल्प है। यो कुरा मेरो आफ्ना लागि विचार र त्यहाँको बडेमाको बिल्डिङ भित्र म जिन्दगी एक यात्रा हो कहाँबाट शुरु भइ कहाँ पुगेर अन्त हुन्छ
How does a wave length of the infrared portion of the electromagnetic spectrum differ from that of the visible portion of the spectrum
The wavelength of infrared portion differs from that of the visible portion being that Infrared waves have longer wavelengths than visible light.
What is wavelength?Wavelength is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.
The electromagnetic spectrum is the entire range of wavelengths of all known electromagnetic radiations, which include;
gamma raysX-raysvisible lightinfraredradio wavesHowever, the wavelength of the infrared portion (700 nm – 1 mm) of the EM is longer than that of the visible portion (380 nm – 750 nm).
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A 1 000 kg car is pulling a 300 kg trailer. Together, the car and trailer move forward with an acceleration of 2. 15 m/s². Ignore any force of air drag on the car and all friction forces on the trailer. Determine (a) the net force on the car
(a) A 1 000 kg car is pulling a 300 kg trailer, together the car and trailer move forward with an acceleration of 2. 15 m/s² the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).
To determine the net force on the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
The total mass of the car and trailer combined is the sum of their individual masses: 1,000 kg + 300 kg = 1,300 kg.
The acceleration of the car and trailer system is given as 2.15 m/s².
Using Newton's second law:
Net force = mass × acceleration
Net force = 1,300 kg × 2.15 m/s²
Net force ≈ 2,795 N
Therefore, the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).
This net force is responsible for accelerating the combined mass of the car and trailer in the forward direction. It represents the sum of all external forces acting on the system, such as the force exerted by the car's engine and the tension in the connection between the car and trailer.
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4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.
a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.
The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.
The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.
b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.
The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.
In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.
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someone help me is physics
Answer:
I don't know, but my class ends in like 30 mins so im superrrr happy. Please shut up thought because no one cares. Just kidding that was a joke it helps your math knowledge go up, ha ha. Do you understand what im saying?
Explanation:
Why must humans limit their exposure to X-rays and gamma rays?
A. The rays can change molecules and atoms in the body into ions.
B. Exposure can cause the human body to give off heat.
O C. Even a small amount of radiation can burn the skin.
D. These rays act similarly to microwaves on the human body.
Answer:
A. The rays can change molecules and atoms in the body into ions.
Increasing the telescope diameter beyond the value found in part (a) will increase the light-gathering power of the telescope, allowing more distant and dimmer astronomical objects to be studied, but it will not improve the resolution. In what ways are the Keck telescopes (each of 10-m diameter) atop Mauna Kea in Hawaii superior to the Hale Telescope (5-m diameter) on Palomar Mountain in California
Answer:
Ability of the Keck telescope to capture more distant object despite been atop Mauna kea that Hale Telescope may not capture even if it is atop Palomar mountain in California
Explanation:
If increasing the Diameter of a Telescope beyond a given value will increase the ability of the telescope to capture more light and also capture astronomical objects located in a very distant position without improving resolution.
Hence the superiority of Keck telescope atop Mauna Kea over Hale Telescope atop Palomar mountain in California is the ability of the Keck telescope to capture more distant object despite been atop Mauna kea that Hale Telescope may not capture even if it is atop Palomar mountain in California
The SI base unit of length is the __________. A. meter B. liter C. kilogram D. kilometer
Answer:
A. Metre
Explanation:
it's just goes by metres
A man goes around a field at an average rate of 5.0 m/s, and a second time at an average rate of 4.0m/s. What is his average speed in the two round trip?
Let A and B are the starting and end point of field respectively.
The velocity of man going from point A to point B is,
\(v_{ab}=5\text{ m/s}\)The velocity of man going from point B to point A is,
\(v_{ba}=4\text{ m/s}\)The time is given as,
\(t=\frac{\text{ distance}}{\text{ speed}}\)Therefore, time taken by man going from point A to point B is given as,
\(t_{ab}=\frac{d}{v_{ab}}\)The time taken by man going from point B to point A is given as,
\(t_{ba}=\frac{d}{v_{ba}}\)The average speed is given as,
\(\begin{gathered} v_{avg}=\frac{\text{ total distance covered}}{\text{ total time taken}} \\ =\frac{d+d}{t_{ab}+t_{ba}} \\ =\frac{2d}{\frac{d}{v_{ab}}+\frac{d}{v_{ba}}} \\ =\frac{2d}{d(\frac{1}{v_{ab}}+\frac{1}{v_{ba}})} \end{gathered}\)Simplifying the above equation;
\(\begin{gathered} v_{avg}=\frac{2}{\frac{1}{v_{ab}}+\frac{1}{v_{ba}}} \\ =\frac{2}{\frac{v_{ba}+v_{ab}}{v_{ab}v_{ba}}} \\ =\frac{2v_{ab}v_{ba}}{v_{ab}+v_{ba}} \end{gathered}\)Substituting all known values,
\(\begin{gathered} v_{avg}=\frac{2\times(5\text{ m/s})\times(4\text{ m/s})}{(5\text{ m/s})+(4\text{ m/s})} \\ =4.44\text{ m/s} \end{gathered}\)Therefore, the average speed of the man is 4.44 m/s.
What does it mean when work is positive?
Answer:
When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work.
Explanation:
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0.55 kg mouse moving E at 60m s or a 900 kg elephant moving E at 0.03m Which has the most momentum?
Answer:
the mouse
Explanation:
the mouse has a momentum of 33 m kg/s
while the elephant has a momentum of 27 m kg/s
i found this out using p=mv
Scientists seek to acquire knowledge and understanding of the real world through the formulation, testing, and evaluation of what?
A. technology
B. scientific method
C. scientific hypothesis
D. deductive reasoning
Scientists seek to acquire knowledge and understanding of the real world through the formulation, testing, and evaluation of scientific hypotheses (Option C).
What are scientific hypotheses?Scientific hypotheses are explanations about questions of the real world that can be used to test them by using the scientific method, i.e., by testing them to confirm or reject their assumptions through experimental and observation procedures.
Therefore, with this data, we can see that a scientific hypothesis is formulated and tested by using the scientific method in order to confirm or reject its assumptions and thus build scientific knowledge.
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Answer:
Scientific hypothesis
Explanation:
. Two charges, Q1 and Q2 , are separated by a certain distance R. If the magnitudes of the charges are halved, and their separation is also halved, then what happens to the electrical force between these charges
Answer: Magnitude of electrical force stays the same.
Explanation:
Equation:
\(F_{e} =k\frac{Q_{1}Qx_{2} }{r^{2} }\)
Since the magnitude of each charge is halved.
and
the separation is halved.
\(F_{e} =k\frac{(.5Q_{1}*.5Q_{2} }{(.5r)^{2} }\)
\(F_{e} =k\frac{.25*Q_{1}Qx_{2} }{.25*r^{2} }\)
Cancel out .25 on the numerator and denominator. Leaving the original equation.
Can someone please explain why the answer to this net torque question is +115 Nm
Answer:
Net torque in positive direction:
Fz = -450 * cos 30 deg * 1.5 = -585 N-M
Fz = 200 * 3.5 = 700 N-M
Net F = 115 N-M
Torque is generally defined as L = R X F
X cross Y = Z normal coordinate system
Note that Z will be out of the page giving the positive value for the torque.
The figure shows a motorcyclist traveling east along a straight
road. After passing point B, the cyclist continues to travel at an average
velocity of 18 m/s east and arrives at point C 2.8 s later. What is the
position of point C?
v=
t=
x1=
xf=
The position of point C from point A is determined as 96.4 m east.
What is the distance travelled by cyclist from B to C?
The distance travelled by cyclist from point B to point C is calculated by applying the following kinematic equation as shown below;
d = vt
where;
v is the speed of the cyclist after passing point Bt is the time of motion of the cyclist from point B to point CSubstitute the given parameters and solve for the distance travelled by the cyclist from point B to point C.
d = 18 m/s x 2.8 s
d = 50.4 m
The position of point C is calculated by adding the distance travelled by the cyclist from point B to point C;
position of point C = 50.4 m + 46 m = 96.4 m
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why cant we always see the stars that are all around us
A sample of helium behaves as an ideal gas as it is heated at constant pressure from 283 K to 358 K. If 70 J of work is done by the gas dur- ing this process, what is the mass of the he- lium sample? The universal gas constant is 8.31451 J/mol · K. Answer in units of g.
The mass of the helium sample is approximately 0.187 g.
To solve this problem, we can use following formula:
w = nR(T2 - T1)
We can rearrange this formula to solve for n:
n = w / (R * (T2 - T1))
To find the mass of the helium sample, we can use following formula:
m = n * M
where m is the mass of the sample, n is number of moles of gas, and M is the molar mass of helium.
Substituting the given values into the first equation, we get:
70 J = n * 8.31451 J/mol*K * (358 K - 283 K)
Simplifying this equation, we get:
n = 0.0467 mol
Substituting this value into the second equation, we get:
m = 0.0467 mol * 4 g/mol = 0.187 g
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Urgent
The following picture is an example of which type of energy?
Electromagnetic Energy
Nuclear Energy
Electric Energy
Answer:
I think its n u c l e a r e n e r g y.
What are the action and linking verb in: are you a spoiled child?
A car accelerates uniformly from rest to a speed of 10 meters per second in 2 seconds.
The acceleration of the car is?
The acceleration with which the car uniformly increases its speed from zero to the given speed is 5m/s².
Given the data in the question
Since the car was initially at rest
Initial velocity; \(u = 0m/s\)Final velocity; \(v = 10m/s\)Time taken; \(t = 2s\)Acceleration of the car; \(a = \ ?\)
Using the First Equation of Motion:
\(v = u + at\)
Where u is the initial velocity, v is the final velocity, a is the acceleration and t is the time taken.
We substitute our given values into the equation and solve for "a"
\(10m/s = 0m/s\ +\ ( a * 2s ) \\\\10m/s = a * 2s\\\\a = \frac{10m/s}{2s}\\\\a = 5m/s^2\)
Therefore, the acceleration with which the car uniformly increases its speed from zero to the given speed is 5m/s².
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A piston-cylinder device containing a fluid is fitted with a paddle wheel stirring device operated by the fall of an external weight of mass 51kg. As the mass drops by a height of 5.6m, the paddle wheel makes 10100 revolutions. Meanwhile the free moving piston (frictionless and weightless) of 0.51m diameter moves out by a distance of 0.71m. Determine the net work for the system if atmospheric pressure is 101 kPa.
Answer:
The value is \(W_N = 11849 \ J \)
Explanation:
From the question we are told that
The mass of the external weight is \(m = 51 \ kg\)
The height through which the mass drops is \(h = 5.6 \ m\)
The number of revolution made is \(N = 10100 \ kg\)
The diameter of the free moving piston is \(d = 0.51 \ m \ kg\)
The distance moved by the free moving piston is \(s = 0.71 \ m \ kg\)
The atmospheric pressure is \(P = 101 \ kPa = 101*10^{3}\ Pa \)
Generally the workdone by the external weight is mathematically represented as
\(W_w =m * g * h\)
= \( 51 * 9.8 * 5.6 \)
= \(2799 N \)
Generally the workdone by the free moving piston is mathematically represented as
\(W_p =P * A * s\)
Here A is the cross-sectional area with value
\( A = \pi * \frac{d^2}{4}\)
\( A = 3.142 * \frac{0.51^2}{4}\)
So
\(W_p =101*10^{3} * 3.142 * \frac{0.51^2}{4} * 0.71\)
=> \(W_p = 14651 \)
So
The net workdone is mathematically evaluated as
\(W_N = -W_w+W_p \)
The negative sign shows that it is acting in opposite direction to \(W_N\)
So
\(W_N = -2799+14651 \)
\(W_N = 11849 \ J \)
Which energy source has no greenhouse gas emissions or health impacts on humans, but is only
available in certain geographic locations?
Answer: geothermal
Explanation:
The geothermal energy source has no greenhouse gas emissions or health impacts on humans.
What is geothermal energy?Geothermal energy can be described as the thermal energy in the Earth's crust which arises from the formation of the planet and from the radioactive decay of materials.
The high temperature in Earth's interior cause rock to melt and solid mantle to behave plastically. The mantle convects upward since it is lighter than the surrounding rock. Temperatures at the core-mantle boundary reach over 4000 °C.
Geothermal heating can use water from hot springs and geothermal power means the generation of electricity from geothermal energy, which has gained importance.
Earth's geothermal resources are more than adequate to supply humanity's energy needs, although a small fraction is currently being profitably exploited, commonly in areas near tectonic plate boundaries.
The greenhouse gas emissions of geothermal stations are on average 45 g of CO₂ per kWh of electricity or less than 5% of that of conventional coal-fired plants.
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