Which statement is true about the transformation shown

Answer:

A (-2,-3) B (3,-3)

Step-by-step explanation:

I took math in high school

Answer:

The coordinate numbers are A (-2,-3) B(3,-3)

Answer:

768

Step-by-step explanation:

I hope you mean this, if you don't say so

P(at least 1 infected person) = 0.7

Note that:

Probability = (Number of possible outcomes) / (Number of total outcomes)

The crew members = 5

Number of infected crew members = 2

Number of uninfected crew members = 3

We want to select two crew members for a task out of 5

Number of total outcomes = 5C2 (Selecting 2 out of 5)

Note that:

Number of total outcomes = 10

That is, there are 10 ways of selecting 2 crew members from 5

Number of ways of selecting 1 infected person means how we can select two people out of 5 such that 1 one of them will be infected. This means that we will select 1 from the two infected persons, and select the second one from the 3 uninfected persons

Number of ways of selecting 1 infected persons = 2C1 x 3C1

Number of ways of selecting 1 infected persons = 2 x 3

Number of ways of selecting 1 infected persons = 6

Number of ways of selecting 2 infected persons = 2C2

Number of ways of selecting 2 infected persons = 1 way

Probability of selecting 1 infected person = 6/10 = 0.6

Probability of selecting 2 infected person = 1/10 = 0.1

P(at least 1 infected person) = P(1 infected person) + P(2 infected persons)

P(at least 1 infected person) = 0.6 + 0.1

P(at least 1 infected person) = 0.7

Answer:

(D)3 units

Step-by-step explanation:

To find the value of a, we use the Theorem of Intersecting Secants.

Applying this to the diagram, we have:

UV X TV = RV X SV

12 X a=(5+4)*4

12a=9*4

12a=36

Divide both sides by 12

a=3 units.

The correct option is D.

By applying the Theorem of Intersecting Secants, the length of TV (a) is equal to: D. 3 units.

The Theorem of Intersecting Secants states that the product of a secant and its external secant is equal to the product of the other secant and its external secant, when two (2) secants are drawn to a circle from an exterior (outside) point:

In order to determine the length of TV (a), we would apply the Theorem of Intersecting Secants as follows:

UV × TV = RV × SV

12 × TV = (5 + 4) × 4

12TV = 9 × 4

12TV = 36

TV = 36/12

TV = 3 units.

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Answer:

5

Step-by-step explanation:

The positive solution for x in the equation log_x(1)/256 = -4/3 is x = 4.57

To solve the logarithm problem for the positive solution for x, we can use the following steps:

1. First, we can rewrite the equation in exponential form:
x^(-(4)/(3)) = 1/256

2. Next, we can raise both sides of the equation to the power of -(3)/(4) to isolate x:
(x^(-(4)/(3)))^(-(3)/(4)) = (1/256)^(-(3)/(4))

3. Simplify the left side of the equation:
x = (1/256)^(-(3)/(4))

4. Simplify the right side of the equation:
x = 256^((3)/(4))

5. Take the fourth root of both sides of the equation:
x = (256^((3)/(4)))^(1/4)

6. Simplify the right side of the equation:
x = 256^((3)/(16))

7. Simplify the exponent:
x = 256^(3/16)

8. Calculate the value of x:
x ≈ 4.57

Therefore, the positive solution for x is approximately 4.57.

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The addition rule is used to calculate the union of two events.

Explanation:

In probability theory, the addition rule is a fundamental principle that allows us to calculate the probability of the union of two events. The union of two events refers to the event that either one event occurs or the other event occurs, or both events occur simultaneously.

The addition rule states that the probability of the union of two events A and B is equal to the sum of their individual probabilities minus the probability of their intersection:

The addition rule is used to calculate the union of two events. It is given by the formula:

\(\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]\)

where \(\( P(A) \)\) represents the probability of event A, \(\( P(B) \)\) represents the probability of event B, and \(\( P(A \cap B) \)\) represents the probability of the intersection of events A and B.

You can use this rule to calculate the probability of the union of two events in various probability problems.

In other words, to calculate the probability of either event A or event B occurring (or both), we add the probabilities of the individual events and then subtract the probability of their intersection to avoid double-counting.

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Answer: 4π cm or 12.56 cm

Step-by-step explanation: To find the circumference of this circle, start with the formula for the circumference of a circle which is C = 2πr.

Since the radius is 2 centimeters, we can

plug in 2 centimeters for r in the formula.

So we have (2)(π)(2 cm) which is equal to 4π cm.

So the circumference of this circle is 4π cm.

Remember that π is approximately equal to 22/7 or 3.14 so we can estimate the value of the circumference by plugging in 3.14 for π.

So we have (4)(3.14) which is equal to 12.56.

So the circumference of the circle is

approximately equal to 12.56 cm.

The height of the red section is 6.3 feet.

The design has a total height of 10.5 feet.The middle section is 4.2 feet tall and is painted white. The heights of the blue and red sections are separated by a factor of 2:1.To calculate the height of the red section, subtract 4.2 feet from 10.5 feet to get 6.3 feet. This is the height of the red section of the design. The height of the blue section can then be calculated by multiplying 6.3 feet by 2, which gives a height of 12.6 feet. Therefore, the height of the red section of the design is 6.3 feet and the height of the blue section is 12.6 feet.

The height of the red section = 10.5 feet - 4.2 feet = 6.3 feet

The height of the blue section = 6.3 feet x 2 = 12.6 feet

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The third side is 6.

Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

We have,

3² + 3√3²

This can be assumed as,

The two sides are 3 and 3√3.

Now,

Applying the Pythagorean theorem.

The third side = x

x² = 3² + (3√3)²

x² = 9 + 27

x² = 36

x = √36

x = 6

Thus,

6 is the third side.

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The complete question:

Find the length of the third side. If necessary, write in the simplest radical form.

3² + 3√3²

d. Expected life in years of the depreciable asset. The acceptable way to express the useful life of a depreciable asset is in terms of the expected life in years.

The useful life refers to the period of time over which the asset is expected to contribute to the revenue-generating activities of a business.

While options a, b, and c may be relevant factors for certain specific assets (such as units produced, hours of productivity, or miles driven), they do not encompass the overall concept of useful life. Useful life is a broader measure that takes into account the anticipated duration of productive use, regardless of specific output or activity metrics.

Expressing the useful life in years provides a common standard for comparison and allows for consistency in depreciation calculations and financial reporting. It is a practical and widely accepted approach to estimating the lifespan of a depreciable asset.

It is worth noting that the estimated useful life in years may vary depending on the nature of the asset and industry practices. It is typically determined based on factors such as technological advancements, physical wear and tear, economic obsolescence, and the intended purpose of the asset.

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Given statement solution is :- a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

Set A: {apple, banana}, Set B: {cat, dog}

Power set of A: {{}, {apple}, {banana}, {apple, banana}}

Power set of B: {{}, {cat}, {dog}, {cat, dog}}

Set A: {red, blue}, Set B: {circle, square}

Power set of A: {{}, {red}, {blue}, {red, blue}}

Power set of B: {{}, {circle}, {square}, {circle, square}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

Set A: {apple, banana, orange}, Set B: {cat, dog, elephant}

Power set of A: {{}, {apple}, {banana}, {orange}, {apple, banana}, {apple, orange}, {banana, orange}, {apple, banana, orange}}

Power set of B: {{}, {cat}, {dog}, {elephant}, {cat, dog}, {cat, elephant}, {dog, elephant}, {cat, dog, elephant}}

Set A: {red, blue, green}, Set B: {circle, square, triangle}

Power set of A: {{}, {red}, {blue}, {green}, {red, blue}, {red, green}, {blue, green}, {red, blue, green}}

Power set of B: {{}, {circle}, {square}, {triangle}, {circle, square}, {circle, triangle}, {square, triangle}, {circle, square, triangle}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

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Answer:

A quadrilateral is a parallelogram if and only if opposite angles are equal.

So, to make the quadrilateral a parallelogram, we can set the following equalities:

(4x + 13) deg = (5x - 12) deg

(4y + 7) deg = (3x - 8) deg

Solving the first equation,

4x + 13 = 5x - 12

x = -5

Solving the second equation,

4y + 7 = 3(-5) - 8

4y + 7 = -17

4y = -24

y = -6

So, the values of x and y that make the quadrilateral a parallelogram are x = -5 and y = -6

The curvature κ(t) is given by |6 / (2 + 3t²)³|.

To find the curvature κ(t) for the given parametric equations x = 9 + t² and y = 3 + t³, we need to use the formula:

κ(t) = |(x'y'' - y'x'') / (x'² + y'²)^(3/2)|

where x' and y' represent the first derivatives with respect to t, and x'' and y'' represent the second derivatives with respect to t.

Let's find the derivatives first:

Given:

x = 9 + t²

y = 3 + t³

First derivatives:

x' = 2t

y' = 3t²

Second derivatives:

x'' = 2

y'' = 6t

Now, we can substitute these values into the curvature formula:

κ(t) = |(x'y'' - y'x'') / (x'²+ y'²)^(3/2)|

= |((2t)(6t) - (3t²)(2)) / ((2t)² + (3t²)²)^(3/2)|

= |(12t² - 6t²) / (4t² + 9t\(x^{4}\))^(3/2)|

= |(6t²) / (t²(4 + 9t²))^(3/2)|

= |(6t²) / (t²(√(4 + 9t²)))³|

= |(6t²) / (t² * (2 + 3t²))³|

= |6 / (2 + 3t²)³|

Therefore, the curvature κ(t) is given by |6 / (2 + 3t²)³|.

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The resulting derivative is -5.3 times the derivative of g(x). To find the derivative of the function 9 (30) ^3 - 5.3g'(x), we need to apply the power rule of differentiation, which states that the derivative of x^n is n*x^(n-1).

First, let's simplify the given function by using the power rule of exponentiation. 9(30)^3 is equal to 243,000, which gives us:

243,000 - 5.3g'(x)

Now, we can apply the power rule of differentiation to the second term, which is -5.3g'(x). The derivative of a constant times a function is equal to the constant times the derivative of the function. Therefore, we have:

d/dx (-5.3g(x)) = -5.3*d/dx(g(x))

This gives us:

243,000 - 5.3*d/dx(g(x))

So, the derivative of the given function is -5.3 times the derivative of g(x).

In conclusion, to find the derivative of the function 9(30)^3 - 5.3g'(x), we simplified the first term, then applied the power rule of differentiation to the second term. The resulting derivative is -5.3 times the derivative of g(x).

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The statement "Ray had the faster time" is true because comparing the times, Joel completed the race in 8.04 seconds, while Ray completed the race in 8.40 seconds.

Since the race is a competition where the objective is to complete it in the shortest amount of time, the athlete with the smaller time is considered the faster runner.

In this case, Ray's time of 8.40 seconds is greater than Joel's time of 8.04 seconds. Therefore, Joel had the faster time.

It's important to note that even though the time difference between them is relatively small, Ray's time is greater, indicating that it took him longer to complete the race compared to Joel.

Thus, the statement "Ray had the faster time" accurately describes the situation, highlighting that Joel achieved a quicker completion time than Ray in the race.

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To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:

ρ(r) = ρ₀(1 - r/R) for r ≤ R,

ρ(r) = 0 for r > R,

where ρ₀ = 3Q/πR³.

To find the total charge, we integrate ρ(r) over the volume:

Q = ∫ρ(r) dV,

where dV represents the volume element.

Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.

The integral becomes:

Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.

Evaluating this integral gives:

Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.

Simplifying further, we get:

Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].

Simplifying the expression inside the parentheses:

Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].

Simplifying once more:

Q = ρ₀ * π * (R³ - R³/3),

Q = ρ₀ * π * (2R³/3),

Q = (3Q/πR³) * π * (2R³/3),

Q = 2Q.

Therefore, the total charge contained in the charge distribution is Q.

To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.

By Gauss's law, the electric field through a closed surface is given by:

∮E · dA = (1/ε₀) * Qenc,

where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.

Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.

For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q,

Simplifying:

E = Q / (4πε₀r²).

This is the same expression as the electric field created by a point charge Q at the origin (r = 0).

To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.

The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.

By Gauss's law, we have:

∮E · dA = (1/ε₀) * Qenc.

Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q.

Simplifying:

E = Q / (4πε₀r²).

This expression represents the electric field inside the charge distribution for r ≤ R.

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Answer: 3π

I don't see 3π in your answer choices, but I'm assuming the "3x" is supposed to be 3π.

Step-by-step explanation:

To convert from degrees to radians, you multiply by π/180.

\(540*\frac{\pi }{180} =3\pi\)

The sum of the measures of the exterior angles of any polygon, including a triangle, is always 360 degrees.

We have,

An exterior angle of a polygon is formed by extending one of its sides outward.

In the case of a triangle, when we extend each side, we create three exterior angles.

These exterior angles are located outside the triangle.

The key concept to understand is that the sum of the exterior angles of any polygon is always 360 degrees.

This property holds true for all polygons, regardless of their shape or size.

To visualize this, imagine starting at any vertex of a triangle and moving along its sides while measuring the exterior angles.

As you move around the triangle, the sum of the exterior angles will always add up to 360 degrees.

This is because, at each vertex, the exterior angle supplements the interior angle to form a straight angle of 180 degrees.

In a triangle, each interior angle measures less than 180 degrees.

So, when we extend each side to create the exterior angles, they collectively compensate for the deficiency of the interior angles, resulting in a sum of 360 degrees.

Therefore,

The sum of the measures of the exterior angles of a triangle is always 360 degrees.

This principle holds true for all polygons, making it a fundamental property of geometry.

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The equation to find the cost of each pair of shorts is 175 = 75 + 5x where each short cost $20

Cost of jackets= $75

Number of shorts= 5

Cost of each short = x

Total amount Jim spent= $175

Total amount Jim spent = Cost of jackets + (Number of shorts × Cost of each short)

175 = 75 + 5x

subtract 75 from both sides

175 - 75 = 5x

100 = 5x

divide both sides by 5

x = 100/5

x = $20

Ultimately, each pair of shorts cost $20

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To verify if F_Y(t) is a distribution function, we need to check three conditions:

1. F_Y(t) is non-decreasing: In this case, F_Y(t) is non-decreasing because for any t_1 and t_2 where t_1 < t_2, F_Y(t_1) ≤ F_Y(t_2). Hence, the first condition is satisfied.

2. F_Y(t) is right-continuous: F_Y(t) is right-continuous as it has no jumps. Thus, the second condition is fulfilled.

3. lim(t->-∞) F_Y(t) = 0 and lim(t->∞) F_Y(t) = 1: Since F_Y(t) = 0 when t < 0 and F_Y(t) = 1 when t > 1, the third condition is met.

Therefore, F_Y(t) = 0 for t < 0, F_Y(t) = t^2 for 0 ≤ t ≤ 1, and F_Y(t) = 1 for t > 1 is a valid distribution function.

To find the probability density function (pdf) for Y, we differentiate F_Y(t) with respect to t.

For 0 ≤ t ≤ 1, the pdf f_Y(t) is given by f_Y(t) = d/dt (t^2) = 2t.

For t < 0 or t > 1, the pdf f_Y(t) is 0.

To compute Pr(4 < Y < 11), we integrate the pdf over the interval [4, 11]:

Pr(4 < Y < 11) = ∫[4, 11] 2t dt = ∫[4, 11] 2t dt = [t^2] from 4 to 11 = (11^2) - (4^2) = 121 - 16 = 105.

Therefore, Pr(4 < Y < 11) is 105.

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Answer:

300 students

Step-by-step explanation:

Hope this answer helps you :)

Have a great day

Mark brainliest

30 students brought papers.

Any number of equal parts is represented by a fraction, which also represents a portion of a whole. A fraction, such as one-half, eight-fifths, or three-quarters, indicates how many components of a particular size there are when stated in ordinary English.

Given

3/4 th of 40 brought papers

students brought paper = 3/4 *40 = 3*10 = 30

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Answer:

The slope is 0.98 and the y-intercept is 1.44.

Step-by-step explanation:

The equation is a linear equation in the Slope-Intercept form y=mx+b. It’s called this because it identifies the slope m and the point on the y-axis at which the line intersects.

The inequality shaded in the graph is given as follows:

y ≥ 5x/2 + 3.

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

In which:

The graph crosses the y-axis at y = -3, hence the intercept b is given as follows:

b = 3.

When x increases by 2, y increases by 5, hence the slope m is given as follows:

m = 5/2.

Then the equation of the line is given as follows:

y = 5x/2 + 3.

The line is a solid line, and values above it are plotted, hence the inequality is given as follows:

y ≥ 5x/2 + 3.

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We use the format (x, y) to write the coordinates in format XY. Coordinates XY is a coordinate that use in Cartesian coordinate.

What is Cartesian coordinate?

Cartesian coordinate is system to draw a specific location of an unique point in the numerical condition that oriented in the two constant line where the vertical line called ordinate or Y and the horizontal line called abscess or X. The Cartesian coordinate commonly use in architecture or  a design of a certain object that has a certain dilate with its original plan. This design later is use to control the construction process of the original object.

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Answer:

We have the proportion: 8/10 = 100/y

We can solve for y by cross-multiplying.

That is, 8y = 100 * 10 Simplifying the right-hand side, 8y = 1000

Dividing both sides by 8 to solve for y, y = 125

Hence, the value of y is 125.

Finally, we have the expression: y = √80We can simplify this expression by factoring 80 into its prime factors:80 = 2 * 2 * 2 * 2 * 5

Taking the square root of 2 * 2 * 2 * 2, we have:√(2 * 2 * 2 * 2) = 2 * 2 = 4

Therefore, y = 4√5The value of y is 4√5.

Step-by-step explanation:

Hope this helps!! Have a good day/night!!

The cost of constructing the box will be = $81.77

Since the question gives us information about the rectangle,

so the area of the rectangle is shown by,

Area = 2 x (length + width)

So we have the area as,

Area = 2(lh + wh) +lw

(since the area per square meter is also given so we added l x w)

Since the cost of the base is = $5 per square meter and the cost of the sides is = $3 per square meter, so area in terms of the cost function,

⇒ C = 3 x 2(lh + wh) + 5 x l x w

⇒ C = 6(lh + wh) +5lw ---------equation 1

According to the question, the length of the rectangular container is twice that of the width of the container,

⇒ l = 2w

Substituting the new value of l in equation 1,

⇒ C = 6(2wh + wh) + 10 \(w^{2}\)

⇒ C = 18wh + 10 \(w^{2}\) ---------- equation 2

To calculate the volume of the rectangle,

V = length x width x height ( lwh )

substituting v = 10 and 2w = l,

2\(w^{2}\)h = 10

h = \(\frac{5}{w^{2} }\)

Substitute the value of h in equation 2,

⇒ C = 18w x \(\frac{5}{w^{2} }\) + 10\(w^{2}\)

⇒ C = \(\frac{90}{w}\) + 10\(w^{2}\) --------- equation 3

Differentiating the above equation we get,

⇒ C* = - \(\frac{90}{w^{2} }\) + 20w

⇒ 20w = \(\frac{90}{w^{2} }\)

Multiply both sides by \(w^{3}\)

⇒ \(20w^{3}\) = 90

⇒ \(w^{3}\) = 4.5

w = 1.65

Put the value of w in equation 3,

⇒ C = \(\frac{90}{1.65}\) + 10 x \(1.65^{2}\)

⇒ C = 81.77

Therefore, The cost of constructing the box will be = $81.77

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Answer:

I believe that it is (1,-3)

Step-by-step explanation:

Since it isn't reflecting about the x-axis, the x coordinate shouldn't change. The only thing that should be reflected is the y-coordinate, which is why the y changes to a negative. I don't know if I worded that good enough for you, but I believe my answer is correct.