which statement describes the action of a buffer composed of propionic acid (c3h6o2) and sodium propionate (c3h5nao2) which statement describes the action of a buffer composed of propionic acid (c3h6o2) and sodium propionate (c3h5nao2) both components, propionic acid and sodium propionate, neutralize added base. both components, propionic acid and sodium propionate, neutralize added acid. propionic acid neutralizes added base, and sodium propionate neutralizes added acid. sodium propionate neutralizes added base, and propionic acid neutralizes added acid.

Answer:

\(thank \: yo\)

In a beta emission, the mass number of the daughter nucleus remains unchanged while the atomic number of the daughter nucleus increases by one unit. The following are isotopes produced when the following undergo beta emission;

1) potassium-42  ------> Ca - 42

2) iodine-131 ------------> Xe - 131

3)  iron-52 ---------------> Co - 52

4)  sodium-24 -----------> Mg -24

The daughter nucleus formed after beta emission is found one place after its parent in the periodic table.

Regarding the stability of the daughter nuclei, a nucleus is unstable if the neutron-proton ratio is less than 1 or greater than 1.5.

Hence, the following daughter nuclei are stable; Ca - 42, Xe - 131, Mg -24.

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The correct answer is a) Henry's Law. This law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas in the overlying space.

This means that as the partial pressure of the gas increases, more gas molecules will dissolve in the liquid. Henry's Law is important in many areas of science, including chemistry, environmental science, and biology.

For example, it is used to understand the behavior of gases in the atmosphere and their impact on climate change, as well as the ability of aquatic organisms to obtain oxygen from water.

Henry's Law can also be applied to industrial processes such as gas purification and carbonation of beverages.

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Answer:

mid orbitals

Explanation:

Usually mid orbitals has highest energy. Note after the electrons reach 32 they can't be accumulated in a shell.

Answer:

Atoms are at their most stable when their outermost energy level is either empty of electrons or filled with electrons. Sodium atoms have 11 electrons. Two of these are in the lowest energy level, eight are in the second energy level and then one electron is in the third energy level

Explanation:

Answer:

Single replacement

Explanation: Al is replacing Cu

A. Isomerases.

The enzyme responsible for the interconversion of dihydroxyacetone-3-phosphate and glyceraldehyde-3-phosphate is called triosephosphate isomerase (TPI).

This enzyme catalyzes the reversible isomerization of the two compounds, converting dihydroxyacetone-3-phosphate into glyceraldehyde-3-phosphate, and vice versa.

Isomerases are a category of enzymes that catalyze the interconversion of isomers - molecules that have the same molecular formula but different structural arrangements.

In the case of TPI, it catalyzes the interconversion of two isomers of triosephosphate - dihydroxyacetone-3-phosphate and glyceraldehyde-3-phosphate.

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Answer:

pure science is the study of nature and its environment while applied science is the acquisition of scientific knowledge from pure science to solve practical problems

Balanced molecular equation-

Sometimes a balanced equation will suffice to refer to a molecular equation.

NiCl₂ (aq) + Na₂S (aq) -----> NiS (s) + 2NaCl (aq)

Complete ionic equation-

A chemical equation known as an ionic equation expresses the electrolytes in aqueous solution as dissociated ions.

Ni²⁺ + 2Cl⁻ + 2Na⁺ + S²⁻------> NiS + 2Na⁺ + 2Cl⁻

Net ionic equation

Ni²⁺ + 2Cl⁻ + 2Na⁺ + S²⁻------> NiS + 2Na⁺ + 2Cl⁻

or

Ni²⁺ (aq) + S²⁻ (aq)-----> NiS (s)

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If two moles of HBr and three moles of KOH are mixed with enough water to make one liter of solution, two moles of KBr are produced. Hence option 'a' is correct.

A mole is the quantity of a substance made up from 6.022 X 1023 of it's own constituent constituents, including such particle, atoms, ion, molecules, etc. The unit of measurement for atoms, molecules, and ions is called a mole.

According to the chemical reaction between HBr and KOH, which is balanced: HBr + KOH KBr + H2O

As can be seen, 1 mole of HBr reacts with 1 mole of KOH to form 1 mole of KBr. Because of this, when 2 moles of HBr & 3 mole of KOH are mixed, all of the HBr will react whereas only 2 mole of KOH are required. You can expect to produce two mole of KBr as a result.

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Answer:

There are 11 protons in a sodium atom but only 3 in a lithium atom, so the nuclear charge is much greater. ... The only factor left is the extra distance between the outer electron and the nucleus in sodium's case. That lowers the ionization energy.

Dipole-induced dipole forces must be overcome between br2 when liquid br2 dissolves into ethanol.

In contrast to C2H5OH, which is a very polar molecule, bromine is non-polar and has zero dipole moment. Charges are separated within polar molecules.

When a nonpolar Br2 molecule interacts with a polar C2H5OH molecule, one half of the bromine molecule acquires a charge and the other half acquires an opposing charge. A dipole is created when two adjacent bromine molecules have different charges. Bromine molecules must thus overcome the intermolecular forces—also known as dipole-induced dipole forces—that form in order to dissolve in ethanol.

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The values of irreducible water saturation, residual oil saturation, and end-point relative permeabilities to oil and water for the chalk core plug are:

In the given equations, the relative permeabilities for oil (kro) and water (krw) are expressed as functions of water saturation (Sw). To determine the values of irreducible water saturation (Swi), residual oil saturation (Sor), and end-point relative permeabilities, we need to analyze the equations.

From the equation for krw, we can observe that when Sw = Swi, krw = 0. Therefore, the irreducible water saturation (Swi) is 0.25.

From the equation for kro, we can see that when Sw = 1 (100% water saturation), kro = 0. This indicates that at maximum water saturation, there is no flow of oil, and the end-point relative permeability to oil (kro) is 0.

The end-point relative permeability to water (krw) can be determined by substituting Sw = 1 in the equation for krw. This gives us krw = 0.52\((1 - 0.25)^3\) = 0.199. Therefore, the end-point relative permeability to water is 0.199.

The residual oil saturation (Sor) can be calculated by substituting Sw = 0 in the equation for kro. This gives us kro = 3.62 \((0.75 - 0)^3\) = 3.245. Therefore, the residual oil saturation is 0.75.

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The methods of simulating general aerofoil shape include experimental techniques such as wind tunnel testing, and numerical techniques such as Computational Fluid Dynamics (CFD) simulations.

Simulating general aerofoil shapes involves both experimental and numerical techniques. Experimental methods include wind tunnel testing, where scaled-down models of the aerofoil are tested in controlled airflow to measure aerodynamic forces. Numerical techniques, such as Computational Fluid Dynamics (CFD) simulations, involve solving fluid flow equations on a computer to analyze flow characteristics and aerodynamic forces. CFD simulations are cost-effective, flexible, and can handle complex aerofoil shapes, but require accurate modeling and validation. A combination of experimental and numerical methods enhances our understanding of aerofoil aerodynamics and helps optimize their design.

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FAD (flavin adenine dinucleotide) is a more appropriate electron acceptor than NAD (nicotinamide adenine dinucleotide) in the dehydrogenation of succinate due to the difference in their standard reduction potentials (e′°) and the redox potentials of the fumarate/succinate couple.

The standard reduction potential reflects the tendency of a redox couple to accept electrons. In this case, the e′° value for FAD/FADH2 in succinate dehydrogenase is 0.050 V, while the e′° value for NAD/NADH is -0.32 V. The positive e′° value of FAD indicates a higher tendency to accept electrons compared to NAD.

The e′° values of the fumarate/succinate couple are crucial in understanding why FAD is more suitable for succinate dehydrogenation. Fumarate/succinate has a relatively low e′° value, meaning that the succinate molecule has a higher affinity for electrons. Since succinate dehydrogenase catalyzes the conversion of succinate to fumarate by removing two hydrogen atoms, FAD, with its more positive e′° value, efficiently captures the electrons released during the reaction.

The use of FAD as an electron acceptor in succinate dehydrogenase ensures effective electron transfer and maintains the flow of electrons in the citric acid cycle. The specific redox properties of FAD and the favorable redox potentials of the fumarate/succinate couple make it a suitable choice for succinate dehydrogenation.

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Answer:  3.36 L of ammonia gas

Explanation:

The balanced chemical reaction is:

\(N_2(g)+3H_2(g)\rightarrow 2NH_3(g)\)  

According to stoichiometry :

3 moles of \(H_2\) produce = 2 moles of \(NH_3\)

Thus 0.75 moles of \(H_2\) will producee=\(\frac{2}{3}\times 0.75=0.50moles\)  of \(NH_3\)

But as percent yield is 30 %, amount of ammonia produced = \(\frac{30}{100}\times 0.50moles=0.15moles\)

According to ideal gas equation:

\(PV=nRT\)

P = pressure  = 1 atm

V = Volume  = ?

n = number of moles = 0.15

R = gas constant =\(0.0821Latm/Kmol\)

T =temperature =\(273K\)

\(V=\frac{nRT}{P}\)

\(V=\frac{0.15\times 0.0820 L atm/K mol\times 273K}{1atm}=3.36L\)

Thus 3.36 L of ammonia gas is obtained by reacting 0.75 moles of hydrogen with excess nitrogen.

3.36 L of ammonia gas.

The balanced chemical reaction is:

\(N_2(g) + 3H_2(g)\rightarrow 2NH_3(g)\)

  According to the above reaction:- :

3 moles of \(H_2\) produce = 2 moles of \(NH_3\)

Thus 0.75 moles of  \(H_2\) will produce\(\frac{2}{3} \times0.75=0.50\ mol\ NH_3\)  

But as percent yield is 30 %, amount of ammonia produced = \(\frac{30}{100} \times0.50\ moles\\\\=0.15\ moles\)

According to ideal gas equation:

\(PV=nRT\)

P = pressure  = 1 atm

V = Volume  = ?

n = number of moles = 0.15

R = gas constant =0.0821 Latm\Kmol

T =temperature =273 K

\(V=\frac{nRT}{P} \\\\=\frac{0.15\ times0.0820\ Latm\Kmol\times273\ K}{1\ atm} \\\\=3.36\L\)

Hence,  3.36 L of ammonia gas is obtained by reacting 0.75 moles of hydrogen with excess nitrogen.

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Answer:

Alexandra should pack 7 nutrition bars for climbing the Mt. Krumpett that will require 3150 kcal of energy for the trip.

According to the question, one pack of nutrition bar contains

To calculate the energy of food (in Kcal), the formula used will be:

Energy = 4 × [carbohydrates (gm) + proteins (gm)] + 9 × [fats]

Energy (E) = 4 × [50 + 40] + 9 × [10]

E = 360 + 90

E = 450 Kcal.

One pack of nutrition bar contains 450 Kcal of energy, therefore to calculate the number of packs required, the total energy required to climb should be divided by the energy of one bar.

Number of nutrition bars = 3150 Kcal / 450 Kcal

Number of nutrition bars = 7.

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Answer:

call an vet ASAP 10 pounds of chocolate is very bad for a dog.

Explanation:

Chocolate is one of the worst things a dog can eat, and 10 pounds of it is worst! Take your dog to the vet IMMEDIATELY! I hope that that the dog will survive.

-------------------------------------------------------------------------------------------------------------Brainiest would make my day, but you don’t have to give it! You’re welcome.

Answer:

c

Explanation:

Exposure route can be defined as a way by means of which a person can come in contact with the hazardous chemicals, this can be prevented by wearing personal protective equipments.

Personal protective equipment is a protective clothing which is worn to protect the wearer's body from hazard or injury.The hazards which can be addressed by the use of personal protective equipment are physical,chemical and bio hazards.

It imposes a barrier between the user and the working environment.The main purpose of personal protective equipment is to reduce exposure of employees to the hazards.

It has a limitation that it does not eliminate the hazard and may lead to harm to the employee if the equipment is damaged.

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B.The potential energy the reactants have stored in molecular bonds

The C—H bond in the methyl cation, CH3+, results from the overlap of sp3–sp3 orbitals.

In the methyl cation, the carbon atom is bonded to three hydrogen atoms and has a positive charge (+1). The carbon atom in the methyl cation is sp3 hybridized, meaning that it has undergone hybridization of one 2s orbital and three 2p orbitals.

This hybridization results in four sp3 hybrid orbitals, which are directed towards the corners of a tetrahedron around the carbon atom.

Each of the three hydrogen atoms contributes a 1s orbital. The overlap of the sp3 hybrid orbitals from the carbon atom with the 1s orbitals from the hydrogen atoms results in the formation of sigma (σ) bonds between carbon and hydrogen.

The C—H bond in the methyl cation, CH3+, results from the overlap of sp3–sp3 orbitals. This overlapping allows the formation of sigma bonds between the carbon and hydrogen atoms in the molecule.

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The pair of amino acids that can form a salt bridge at physiological pH is aspartic acid and histidine. Hence the correct option is (A).

A salt bridge is formed when the carboxylic acid group (-COOH) of one amino acid donates a proton (H+) to the amino group (-NH2) of another amino acid, which becomes positively charged. This creates an electrostatic attraction between the positively charged amino acid and the negatively charged carboxylate ion of the other amino acid. At physiological pH (around 7.4), the carboxylic acid group of aspartic acid (Asp) is deprotonated and has a negative charge, while the amino group of histidine (His) is protonated and has a positive charge. Therefore, Asp and His can form a salt bridge through electrostatic attraction between the negatively charged carboxylate group of Asp and the positively charged amino group of His. The other pairs of amino acids listed do not form salt bridges at physiological pH for the following reasons:

(B) Glutamic acid (Glu) and aspartic acid (Asp) both have negatively charged carboxylate groups at physiological pH, so they repel each other and do not form salt bridges.

(C) Two cysteines (Cys) can form a disulfide bond through the oxidation of their sulfur-containing side chains, but they do not form salt bridges.

(D) Arginine (Arg) has a positively charged guanidino group at physiological pH, while tyrosine (Tyr) has a neutral hydroxyl group. They do not have complementary charges to form a salt bridge.

(E) Lysine (Lys) has a positively charged amino group, while glutamic acid (Glu) has a negatively charged carboxylate group. They have complementary charges to form a salt bridge, but the pH is too low for Glu to be deprotonated and have a negative charge. Therefore, they do not form a salt bridge at physiological pH.

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Question - Which of the pairs of amino acids can form a salt bridge at physiological pH? Select from the following options:-

(A) aspartic acid and histidine

(B) glutamic acid and aspartic acid

(C) two cysteines

(D) arginine and tyrosine

(E) lysine and glutamic acid

Answer:

515.04

Explanation:

The vanilla extract can be used in the house to;

Vanilla beans are steeped in ethyl alcohol and water to produce vanilla extract, an aromatic, amber-colored liquid. pure vanilla extract is gotten through macerating and percolating vanilla pods in an ethanol and water mixture, vanilla extract is created.

In many Western sweets, particularly baked goods like cakes, cookies, brownies, and cupcakes, as well as custards, ice creams, and puddings, it is seen as a necessary component.

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The pair that will produce a buffer solution is 0.10 M HCl and 0.15 M NH3.

A buffer solution is a solution that resists changes in pH when small amounts of acid or base are added to it. It is made up of a weak acid and its conjugate base, or a weak base and its conjugate acid. The key to a buffer solution is the presence of both the weak acid/base and its conjugate pair in roughly equal concentrations.

Looking at the given pairs of solutions:

Out of these options, the pair that will produce a buffer solution is option C: 0.10 M HCl and 0.15 M NH3. This is because HCl is a strong acid and NH3 is a weak base. When mixed in equal volumes, the HCl will react with some of the NH3 to form NH4+ (conjugate acid) and Cl- ions. The remaining NH3 and NH4+ will act as a buffer, resisting changes in pH when small amounts of acid or base are added.

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A buffer solution is a solution that resists changes in pH when small amounts of acid or base are added to it. In buffer, we should have weak acid/weak base and salt or a weak base and strong acid or weak acid and strong base Hence the correct option is C) 0.10 M HCl and 0.15 M NH₃ because here the acid is strong, base molarity > acid molarity.

A) 0.10 mol L⁻¹ HCl and 0.05 mol L⁻¹ NH₃

HCl is neutralized by NH₃ forming NH₄Cl. - not a buffer

B) 0.10 mol L⁻¹ HCl and 0.05 mol L⁻¹ NaOH

HCl and NaOH form salt and water - not a buffer

C) 0.10 mol L⁻¹ HCl and 0.15 mol L⁻¹ NH₃

HCl is neutralized by NH₃ forming NH₄Cl.

The remaining NH₃ will form an NH₃-NH₄Cl buffer

0.10 mol L⁻¹ HCl and 0.20 mol L⁻¹ CH₃COOH

Acetic acid is a weak acid and a good buffer.

D) 0.10 molL⁻¹ HCl and 0.20 mol L⁻¹ NaCl

Just a salty, acid solution.

So, C produces a Buffer.

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Answer:

15000 g

Explanation:

We simply multiply 100 grams with 150 grams to get 1.5(10⁴) grams.

Answer:

0.015 kg2

Explanation: