Answer:
D)a burning natural gas releases 21,000 kj
Which measure of a gas does the expression
nRT/p
represent? (1 point)
O molar mass
O volume
O number of moles
O gas constant
Answer:
A. volume
Explanation:
Generally the equation for the ideal gas is mathematically given as
PV=nRT
Where
P=pressure
V=volume
R=gas constant
n=Number of Moles
T=Temperature
Therefore
V=nRT/P
Option A
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A scientist was studying a population of elephants. The first year, he counted a population of 80. Over the next eight
years, the population's numbers were 94, 100, 103, 110, 125, 120, 125, 120. What appears to be the carrying capacity
for this population?
0 120
0124
O 125
O 126
Answer:
The carrying capacity of this population would be 125 we know this because we see that this number occur multiple times and seems to be the tipping point after which the number of the population always go down
Answer:
The carrying capacity of this population would be 125 we know this because we see that this number occur multiple times and seems to be the tipping point after which the number of the population always go down
Explanation:
Which atmospheric gas molecules were not affected by the visible or
infrared radiation?
Answer:
it will be nitrogen and oxygen
Explanation:
doing the assignment
The air around the equator has a high temperature, so it has a _______ air pressure. *
Explanation:
The air around the equator has a high temperature, so it has a _lower_____ air pressure
What’s the answer? I need an answer as soon as possible please!
Answer:
1, 1, 2
Explanation:
1, 1, 2
what is the noble gas shorthand electron configuration for y+?
The noble gas shorthand electron configuration for Y+ is \([Kr]5s24d1.\). The noble gas shorthand provides a concise representation of the electron configuration by using the symbol of the noble gas and indicating the additional electrons specific to the element being considered.
To determine the noble gas shorthand electron configuration, we start by locating the noble gas that comes before the element Yttrium (Y) in the periodic table. In this case, the noble gas is Krypton (Kr), which has the electron configuration \([Kr]4d^{10}5s^2\) Next, we remove the outermost electrons from Krypton and continue with the electron configuration of Yttrium. Yttrium has an atomic number of 39, which means it has 39 electrons. Yttrium’s electron configuration is \(1s^22s^22p^63s^23p^64s^23d^104p^65s^24d^1.\)
To simplify the electron configuration using the noble gas shorthand, we can replace the electron configuration of Yttrium from the beginning with the noble gas Kr. This allows us to represent the inner electrons of Kr without writing them out explicitly. Thus, the noble gas shorthand electron configuration for Y+ is \([Kr]5s24d^1.\)
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A certain polyatomic ion contains 49 protons and 50 electrons. What's the net charge of this ion?Question options:A) +1B) +2C) –1D) –2
Explanation:
We have to find the net charge of a polyatomic ion that contains 49 protons and 50 electrons.
n° of protons = 49 n° of electrons = 50
The charge of each electron is -1 and the charge of each proton is +1.
charge of electron = -1 charge of proton = +1
Finally the net charge will be:
Net charge = n° of electrons * charge of electron + n° of protons * charge of proton
Net charge = 50 * (-1) + 49 * (+1)
Net charge = -1
Answer: C) -1
3. Some of the reagents used in this lab are easily confused: such as persulfate (S208?)
and thiosulfate (S20:2). A student inadvertently switched these reagents, adding the
persulfate to beaker A and thiosulfate to beaker B. How would this affect the results?
What would the student observe with respect to the mixture in beaker A?
Answer:
Different compounds are formed.
Explanation:
Due to this switching of chemicals, the result of both beakers will be different because the chemicals react with the different solution in the beaker. The composition of both chemicals are different from one another which produces different compounds or products when they are mixed with the solution so we can say that this switching of chemicals will definitely affect the results of the experiment. The student will observe the formation of different compounds and different colour of the solution.
In the lab, a student adds 4.5 g of sodium chloride (NaCl) to 100.0 g of water. Calculate the molality of the solution.
Answer:
0.77mol/Kg.
Explanation:
The following data were obtained from the question:
Mass of NaCl = 4.5g
Mass of water = 100g.
Molality =...?
Next, we shall determine the number of mole in 4.5g of NaCl. This can be obtained as follow:
Mass of NaCl = 4g.
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Number of mole NaCl =..?
Mole = Mass /Molar Mass
Number of mole of NaCl = 4.5/58.5
Number of mole of NaCl = 0.077 mole.
Next, we shall convert 100g of water to kilograms. This is illustrated below:
1000g = 1kg
Therefore, 100g = 100/1000 = 0.1Kg.
Finally, we can determine the molality of the solution as follow:
Molality is simply defined as the mole of solute per unit kilogram of solvent (water). Mathematically, it is represented as:
Molarity = mole of solute / kg of solvent
Mole of solute, NaCl = 0.077 mole
Kg of solvent = 0.1kg
Molality = 0.077mol/0.1kg
Molality = 0.77mol/Kg
The molarity of the solution is 0.77mol/Kg.
Calculation of the molarity of the solution:
Since
Mass of NaCl = 4.5g
Mass of water = 100g.
Here,
Mass of NaCl = 4g.
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Now
Mole = Mass /Molar Mass
= 4.5/58.5
= 0.077 mole.
Now
1000g = 1kg
So,
100g = 100/1000 = 0.1Kg.
Now
Molarity = mole of solute / kg of solvent
Mole of solute, NaCl = 0.077 mole
Kg of solvent = 0.1kg
So,
Molality = 0.077mol/0.1kg
= 0.77mol/Kg
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What is the molarity of a solution that was prepared by dissolving 70.0 g of MgCl (molar
mass = 94.0 g/mol) in enough water to make 342 mL of solution?
I need the steps…
We must first determine how many moles of solute are in a solution in order to compute the molarity of the solution. To do this, divide the solute's mass, 70.0 g, by its molar mass, 94.0 g/mol.
MgCl, 0.743 moles, are the result. Next, we must determine the solution's overall volume, which comes to 342 mL. Since there are 1000 mL in a litre, we may multiply 342 mL by 0.001 to convert this to litres. This produces 0.34 L.
By dividing the entire volume of the solution, 0.342 L, by the number of moles of MgCl, 0.743, we may finally get the solution's molarity. A molarity of 2.17 M is the result.
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Assuming that oleic acid molecules are cubic in shape where a side of the cube is the height of the monolayer, discuss how you would calculate the area of a molecule.
The area of the oleic acid molecule is 6h².
What is the area of a shape?The area of a given shape is the total space taken up by a place surface.
Area usually apply to shape or two dimensions of a solid object.
A cube is a three dimensional object that has six faces that which have equal areas.
The total area of a cube is calculate by adding the results of all the area of the six faces.
Total surface area of a cube = 6 * a²
Where a is the area of any of the six faces.
Given that oleic acid molecules are cubic in shape where a side of the cube is the height of the monolayer.
Let the height of the oleic acid be h
The area of a molecule of oleic will be obtained by multiplying the square of the height of the molecule by six.
Area of the oleic acid molecule 6 * h².
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Why does a straw look broken when it is placed in a water glass?
\(hopefully \: \: that \: \: helps\)
Concentrated hydrochloric acid is 36% (Weight/Volume) hydrochloric acid and has a density of 1.18 g.cm -3.
( i ) If 10 cm 3 of the concentrated acid is dissolved in water to produce 1 dm 3 of solution, calculate the concentration in mol. dm-3 of the dilute solution.
( ii ) If 5cm3 of the dilute solution in ( i ) above is made up to 20 cm3, what will be the new concentration in mol.dm-3.
i. The new concentration is 0.116 M
ii. The new concentration is 0.029 M
What is the concentration of the original hydrochloric acid acid?The concentration of the original or stock hydrochloric acid is calculated as follows:
Molarity = Percentage concentration * Density * 1000/Molar mass * 100Molarity of stock HCl = 36 * 1.18* 1000 /36.5 * 100
Molarity of stock HCl = 11.6 mol/dm
i. Using the dilution formula: M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 11.6 * 10/1000
M₂ = 0.116 M
The new concentration = 0.116 M
ii. Using M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 0.116 * 5/20
M₂ = 0.029 M
The new concentration = 0.029 M
In conclusion, the new concentrations are found using the dilution formula.
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Question 6 of 25
Which phrase best describes a car that has negative acceleration?
A. The car is slowing down.
B. The car is moving fast.
C. The car is moving slowly.
Answer:
C. the car is moving slowly
A sphere of radius 0.457 m, temperature 32.2 ∘
C, and emissivity 0.924 is located in an environment of temperature 82.9 ∘
C. At what rate does the sphere (a) emit and (b) absorb thermal radiation? (c) What is the sphere's net rate of energy exchange? (a) Number (b) Number Units Units
a) The sphere emits thermal radiation at a rate of 139.75 Watts.
b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.
c) The sphere's net rate of energy exchange is 102.09 Watts.
What are the rates of thermal radiation emission, absorption, and net energy exchange for the sphere?To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.
a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:
Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))
Plugging in the given values:
Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)
Emitting Rate ≈ 139.75 Watts
b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:
Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))
Plugging in the given values:
Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)
Absorbing Rate ≈ 37.66 Watts
c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:
Net Rate = Emitting Rate - Absorbing Rate
Net Rate = 139.75 Watts - 37.66 Watts
Net Rate ≈ 102.09 Watts
Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.
Note: The units for all the rates are Watts.
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which is stronger H2SO4 (sulfuric acid) or NaOH (sodium hydroxide)? It takes 8 drops of sulfuric acid added to sodium hydroxide for it to turn yellow and 14 drops of sodium hydroxide for sulfuric acid to turn purple so which one is stronger?
Answer: H2SO4 (sulfuric acid)
Explanation: Oops mb i just double cheked
When water reacts with potassium metal the hydrogen produced ignites explosively on the surface of water.What causes ignition?
Explanation: Pottasium reacts with water vigorously and the reation is exothermic. The heat released causes the hydrogen released to ignite.
Answer: Pottasium reacts with water vigorously and the reation is exothermic. The heat released causes the hydrogen released to ignite.
Calculate the standard potential for the following galvanic cell:
Ni(s) | Ni2+(aq) | Ag+(aq) | Ag(s)
which has the overall balanced equation:
Ni(s)+2Ag+(aq)→Ni2+(aq)+2Ag(s)
Express your answer to three significant figures and include the appropriate units.
Reduction half-reaction E∘ (V)
Ag+(aq)+e−→Ag(s) 0. 80
Cu2+(aq)+2e−→Cu(s) 0. 34
Ni2+(aq)+2e−→Ni(s) −0. 26
Fe2+(aq)+2e−→Fe(s) −0. 45
Zn2+(aq)+2e−→Zn(s) −0. 76
The standard potential for the given galvanic cell is +1.06 V.
To calculate the standard potential for the given galvanic cell, we need to determine the individual reduction potentials of the half-reactions and then subtract the potential of the anode (where oxidation occurs) from the potential of the cathode (where reduction occurs).
Given reduction half-reaction potentials:
Ag+(aq) + e^− → Ag(s): E∘ = +0.80 V
Ni2+(aq) + 2e^− → Ni(s): E∘ = -0.26 V
Since we have the reduction potentials for both half-reactions, we can directly calculate the standard potential for the cell:
E∘(cell) = E∘(cathode) - E∘(anode)
= E∘(Ag+(aq) + e^− → Ag(s)) - E∘(Ni2+(aq) + 2e^− → Ni(s))
E∘(cell) = +0.80 V - (-0.26 V)
= +1.06 V
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Any individual offspring produced through a sexual reproduction is always,
Answer:
Any individual offspring produced through asexual reproduction is always: genetically identical to its parent. made up of cells with a cell wall. different from all of its siblings
be31 has a single electron. calculate the frequencies and wavelengths of light in the emission spectrum of the ion for the first three lines of each of the series that are analo- gous to the lyman and the balmer series of neutral hydro- gen. in what region of the spectrum does this radiation lie?
The frequencies and wavelengths of light in the emission spectrum of the Be3+ ion for the first three lines of each of the series that are analogous to the Lyman and the Balmer series are 48.8 eV, 97.6 eV, and 146.4 eV respectively, and wavelengths of 254 nm, 126 nm, and 84 nm respectively. This radiation lies in the ultraviolet region of the spectrum.
The frequencies and wavelengths of light in the emission spectrum of the Be3+ ion can be determined by calculating the energy of the electron in the ground state and in each of the excited states. The ground state energy of the ion is -13.6 eV.
The energy of the first three excited states of the ion is calculated by subtracting the ground state energy from the ionization energy, which is 13.6 eV. The frequencies and wavelengths of light of the three excited states are then calculated using the equation E=hv, where h is Planck's constant and v is the frequency of the light.
The wavelengths of light in the emission spectrum of the Be3+ ion for the first three lines of each of the series that are analogous to the Lyman and the Balmer series are 254 nm, 126 nm, and 84 nm respectively. These frequencies and wavelengths of light lie in the ultraviolet region of the spectrum.
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Complete question:
Be^3+ has a single electron. Calculate the frequencies and wavelengths of light in the emission spectrum of the ion for the first three lines of each of the series that are analogous to the Lyman and the Balmer series of neutral hydrogen. In what region of the spectrum does this radiation lie?
what is the numerical value of the apparent rate, k'', constant of the reaction?
Determining the numerical value of k'' requires careful experimentation and analysis to accurately characterize the kinetics of the reaction being studied.
The numerical value of the apparent rate constant, k'', is dependent on the specific reaction being studied. The apparent rate constant is a measure of how quickly a reaction proceeds and is influenced by factors such as temperature, reactant concentrations, and catalysts.
The rate constant is typically determined experimentally by measuring the change in concentration of a reactant or product over time and using this data to calculate the rate of the reaction. The numerical value of k'' is expressed in units of concentration over time, such as mol/L/s. It is important to note that the apparent rate constant is different from the actual rate constant, k, which takes into account the effects of any intermediates or catalysts on the reaction.
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Creepers! A creepy corpse stole
all of Ma Ribbins money from her
grocery store. The crime scene
team found a compound that was
27.37%Na, 1.20%H, 14.30% C, and
57.14%0. What was the empirical
formula of this compound, and
who committed the theft?
Thus, the empirical formula of this compound is S2O5 S 2 O 5 .
An empirical formula is what GCSE?The simplest whole number ratio of atoms from each element in a compound is called the empirical formula. The precise amount of atoms of each element in a compound is given by its molecular formula. the connection between the molecular formula and empirical formula.
The simplest whole number ratio of atoms from each component of a compound is its empirical formula. It is determined empirically utilizing data from trials. For instance, whereas the empirical formula for glucose is CH 2O, its molecular formula is C 6H 12O 6.
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the volume of hydrogen produced at stp was 94.1 ml determine the mass of magnesium required
The mass of the Mg is 0.1 g
What is the stoichiometry of the reaction?Stoichiometry is the quantitative relationship between the reactants and products in a chemical reaction. It involves determining the mole ratios of the reactants and products based on the balanced chemical equation for the reaction.
To find the stoichiometry of a reaction, you need to start with a balanced chemical equation that shows the reactants and products and their respective coefficients. The coefficients in the balanced chemical equation represent the mole ratios of the reactants and products in the reaction.
The equation of the reaction is;
Mg + 2HCl ----> MgCl2 + H2
We know that;
1 mol of the H2 occupies 22400 mL
x moles of H2 occupies 94.1 mL
x = 1 mol * 94.1 mL/ 22400 mL
x = 0.0042 moles
Now;
If 1 mole of Mg produces 1 mole of H2 then 0.0042 moles of Mg is required.
Hence the mass of Mg = 0.0042 moles * 24 g/mol
= 0.1 g
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A solution of NaCl was prepared in the following manner: 0.0842 g of NaCl is massed out on an analytical balance. The solid is transferred to a 25.00 mL volumetric flask. Deionized water is added to the flask such that the bottom of the meniscus is at the line. A 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask using a volumetric pipet and diluted to volume. 6. Calculate the concentration of NaCl in the resulting solution in mg/L NaCl. (answer = 67.4 mg/L) 7. Calculate the concentration of NaCl in the resulting solution using propagation of error through the calculation. Use the manufacturer's tolerance values as the absolute error. The tolerances can be found in Chapter 2 of the Harris text. Assume a Class 1 balance and Class A glassware. Treat the tolerances as random error. (answer = 67.4+0.4 mg/L) 8. Identify 2 possible sources of random (indeterminate) error. Identify 2 possible sourses of systematic (determinate) error.
Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl
To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7. Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.
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A compound is found to contain 15.94 % boron and 84.06 % fluorine by mass. What is the empirical formula for this compound
The empirical formula of the compound is BF3.
The empirical formula of a compound is the simplest whole-number ratio of atoms that represents the compound's composition. To determine the empirical formula of a compound, we need to determine the number of moles of each element present and then simplify the ratio of moles to the smallest whole-number ratio.
First, we can use the percentages of boron and fluorine to find the number of grams of each element present in 100 grams of the compound:
15.94 g boron / 100 g compound
84.06 g fluorine / 100 g compound
Next, we can convert the number of grams of each element to moles using the molar masses of boron and fluorine:
15.94 g B / (10.81 g/mol) = 1.48 mol B
84.06 g F / (18.99 g/mol) = 4.44 mol F
To find the empirical formula, we divide the number of moles of each element by the lowest number of moles:
1.48 mol B / 1.48 mol B = 1.00
4.44 mol F / 1.48 mol B = 3.00
So the empirical formula of the compound is BF3.
It's important to note that this is the empirical formula, and the actual formula of the compound could be a multiple of this depending on the chemical structure of the compound.
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It will take _____ years to double your money at a 11% rate of interest compounded annu
It will take __6.4 years.___ years to double your money at a 11% rate of interest compounded annually.
Compounded interest is aa type of interest that allows investors to earn interest on both their initial principal and any interest earned. The compounding frequency refers to the number of times per year that interest is paid out or credited to an account. Annual compounding, which is once per year, is a common compounding frequency. To double your money in annual compounded interest, use the rule of 72, which says that 72 divided by the interest rate equals the number of years it takes to double your money. Using this formula, we have 72/11, which equals about 6.4 years. Thus, it will take approximately 6.4 years to double your money at an 11% rate of interest compounded annually.
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1- Hydrogenated compounds are considered as the most suitable fuels for spark ignition engines . 2- Due to increasing temperature, the chemical reaction rate also increase as the element moves from bu
Hydrogenated compounds, particularly hydrogen gas (H2), are often considered as potential fuels for spark ignition engines.
Hydrogenated compounds are considered the most suitable fuels for spark ignition engines because hydrogen is a highly flammable gas with a low ignition energy and a wide flammability range. When compared to gasoline or diesel, hydrogen has a higher energy content by weight, which makes it an attractive fuel choice.
Due to increasing temperature, the chemical reaction rate also increases as the element moves from a solid to a liquid to a gas.Physical state transitions are dependent on temperature, and the rate of chemical reactions that occur as a result of these state transitions is also influenced by temperature.
At higher temperatures, the chemical reaction rate typically rises as molecules have more kinetic energy and collide with one another more frequently.
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What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
area in contact between the two substances
specific heat of the material that makes up the substances
Odensity of the two substances in contact
amount of time the two substances are in contact. area in contact between the two substances. specific heat of the material that makes up the substances. the density of the two substances in contact.
The characteristics determine how easily two substances change temperature is amount of time the two substances are in contact, area of contact between the two substances, specific heat of the material that makes up the substances and the density of the two substances in contact. Therefore, option B, C, D and E are correct.
When two substances have different temperatures come into contact?When two substances that have different surface temperatures come in contact, conduction happens. The substance with the higher temperature always transfers energy to the one with the lower temperature.
When two objects with different temperatures come in contact with one another, energy moves from the hotter (higher temperature) object to the cooler (lower temperature) object until both objects reach the same temperature.
The latitude of the location has an impact on the air temperature there. The location's elevation. separation from the ocean.
Thus, option B, C, D and E are correct.
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The image shows energy flowing from coal, to a coal-fired power plant, to a power
tower, and finally to a radio. Match the types of energy as they are converted from
one type to the other in each stage of the process. HELPP PLS
The types of energy are correctly matched below:
Thermal energy: Coal-fire power plant
Electrical energy: power plant
Sound energy: Radio
Chemical/potential energy:Coal
What is energy conversion?Energy conversion is also known as energy transformation whereby a type of energy changes to another form of energy.
There are various types of energy which includes:
Thermal energy: A typical example of thermal energy is the coal-fire power plant which generates heat energy upon its performance and usage.Electrical energy: A typical example of the electrical energy is the power plant which has the ability to generate electricity.Sound energy: A typical example of the sound energy is the radio device which has the ability to generate sounds.Chemical/potential energy: A typical example of chemical energy is the coal.Learn more about energy here:
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where dose everything go plz help!!???!?