Which statement describes a similarity between an apple and gasoline

The rate at which the nitrogen dioxide, NO₂ will effuse is 64 mL/s

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

Where

Applying the Graham's law of diffusion equation, we have:

R₁/R₂ = √(M₂/M₁)

82 / R₂ = √(46 / 28)

Cross multiply

82 = R₂√(46 / 28)

Divide both sides by √(46 / 28)

R₂ = 82 /√(46 / 28)

R₂ = 64 mL/s

Thus, nitrogen dioxide, NO₂ will effuse at 64 mL/s

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Answer:

Swedish physicist Johannes Rydberg

Explanation:

The microscopic interface asymmetry of grown semiconductor heterostructures.

The dispersion of restricted electrons. beginning from a multiband envelope formulation we practice matrix perturbation theory to derive specific expressions. Interface asymmetry, which in the conduction band Hamiltonian appear as a warping and a spin-splitting term. The warping term consequences in an inequivalence of the dispersion.

The microscopic interface asymmetry of grown semiconductor heterostructures that gives upward thrust to heavy-light hole coupling even at 0 in-plane wave vector, modifies also the dispersion of restricted electrons. beginning from a multiband envelope method we practice matrix perturbation principle to derive explicit expressions as a result of this interface asymmetry, which inside the conduction band.

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The molarity of the HCl solution is 1.22 M.

To solve this problem, we need to use the balanced equation provided:

NaOH + HCl → NaCl + H2O

The reaction shows that one mole of NaOH reacts with one mole of HCl to form one mole of NaCl and one mole of water. This means that the number of moles of NaOH used in the titration is equal to the number of moles of HCl present in the solution.

First, let's calculate the number of moles of NaOH used in the titration:

moles NaOH = M x V
moles NaOH = 0.900 M x 0.0540 L
moles NaOH = 0.0486 mol

Since the reaction is 1:1, the number of moles of HCl is also 0.0486 mol. To find the molarity of the HCl solution, we need to divide the number of moles by the volume of the HCl solution used in the titration (40.0 mL or 0.0400 L):

Molarity HCl = moles HCl / volume HCl
Molarity HCl = 0.0486 mol / 0.0400 L
Molarity HCl = 1.22 M

Therefore, the molarity of the HCl solution is 1.22 M.

In conclusion, we used the balanced equation provided to determine the molarity of the HCl solution. We found that the molarity of the HCl solution is 1.22 M by dividing the number of moles of HCl by the volume of the HCl solution used in the titration.

This calculation shows the importance of using balanced equations and stoichiometry in solving chemical problems, which allows us to determine the amount and concentration of substances involved in a reaction.

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Answer:

9.3 g of Ca3(PO4)2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3CaO + 2H3PO4 —> Ca3(PO4)2 + 3H2O

Next, we shall determine the number of mole of H3PO4 present in 200 cm³ of 0.3 mol/dm³ phosphoric acid (H3PO4) solution. This can be obtained as follow:

Molarity of H3PO4 = 0.3 mol/dm³

Volume = 200 cm³ = 200 cm³/1000 = 0.2 dm³

Mole of H3PO4 =?

Molarity = mole /Volume

0.3 = mole of H3PO4 /0.2

Cross multiply

Mole of H3PO4 = 0.3 × 0.2

Mole of H3PO4 = 0.06 mole

Next, we shall determine the number of mole of the salt, Ca3(PO4)2, obtained from the reaction. This can be obtained as shown below:

3CaO + 2H3PO4 —> Ca3(PO4)2 + 3H2O

From the balanced equation above,

2 moles of H3PO4 reacted to produced 1 mole of Ca3(PO4)2.

Therefore, 0.06 moles of H3PO4 will react to produce = (0.06 × 1)/2 = 0.03 mole of Ca3(PO4)2.

Thus, 0.03 mole of Ca3(PO4)2 is produced from the reaction.

Finally, we shall determine the mass of Ca3(PO4)2 produced as follow:

Mole of Ca3(PO4)2 = 0.03 mole

Molar mass of Ca3(PO4)2 = (40×3) + 2[31 + (16×4)]

= 120 + 2[31 + 64]

= 120 + 2[95]

= 120 + 190

= 310 g/mol

Mass of Ca3(PO4)2 =?

Mole = mass /Molar mass

0.03 = mass of Ca3(PO4)2 / 310

Cross multiply

Mass of Ca3(PO4)2 = 0.03 × 310

Mass of Ca3(PO4)2 = 9.3 g

Thus, 9.3 g of Ca3(PO4)2 was obtained from the reaction.

The best reagents to convert 1-hexyne into (e)-1,2-dibromo-1-hexene are 1 equiv. Br2 in CCl4, followed by NaOH to convert the mixture of (Z)- and (E)-isomers to the desired (E)-isomer.

This reaction is called the Vicinal Dibromination reaction. Option A: xs Br2 in CCl4 is a good choice of reagents, but it will give a mixture of (Z)- and (E)-isomers. Option B: 1 equiv. HBr will result in the formation of (Z)-1-bromo-1-hexene. Option C: ROOR is a radical initiator and will not result in the desired product.

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A synthesis reaction is a chemical process in which two dissimilar atoms interact to create a new substance or molecule.

The atomic number of the alkali metal sodium is 11. The valence electron in its outermost shell is positive (+1).

With the atomic number 17, chlorine belongs to the halogen family of elements. Its octet structure can only be completed with an electron.

Because of this, their bonding process is known as electrovalent or ionic bonding.

When 2 moles of sodium (Na) and 1 mole of chlorine (Cl) are combined, the following results:

2Na(s)Sodium+Cl2(g)Chlorine→2NaCl(s)Sodium Chloride

As a result of the foregoing process, we can infer that two sodium molecules are created when two sodium (Na) atoms interact with one molecule of chlorine gas (Cl2).

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Answer:

it is actually 45 points

Explanation:

Freezing rain melts in warm air and then freezes on cold surfaces while sleet refreezes before it hits the surface of Earth. Sleet is wet and rain is frozen. Freezing rain melts in warm air then refreezes before it reaches the surface, while sleet falls wet and freezes on the surface. you basically wrote out your answer yourself and you´re proof, i gooogled it, lol

Answer:

Freezing rain melts in warm air and then freeze then refreeze before it reaches the surface

When the heavy isotopes of hydrogen undergo fusion at extremely high temperatures, they release a tremendous amount of energy.This process is known as nuclear fusion.

Nuclear fusion occurs when two light atomic nuclei combine to form a heavier nucleus. In the case of heavy hydrogen isotopes, deuterium (D) and tritium (T), the fusion reaction can be represented as follows:

D + T -> He + n + Energy

In this reaction, deuterium and tritium nuclei fuse together to form a helium nucleus (He) along with the release of a neutron (n) and a tremendous amount of energy.

The high temperatures required for nuclear fusion are necessary to overcome the strong electrostatic repulsion between positively charged atomic nuclei. By providing enough thermal energy, the kinetic motion of the nuclei allows them to approach closely enough for the strong nuclear force to take effect and bind them together.

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In voltaic cells, electrons flow from the negative electrode (anode) to the positive electrode (cathode).

Electrons are moved from one species to another in redox reactions. When a reaction occurs spontaneously, energy is released that can be put to good use. The process must be divided into the oxidation reaction and the reduction reaction in order to capture this energy. A wire is used to move the electrons from one side of the reactions to the other after they have been placed into two separate containers. A voltaic/galvanic cell is produced as a result.

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Answer:

200/60 aka 3.33333333333

Explanation:The reason why is because 200km/h means that the skydiver will travel 200 km every hour.  Because there are 60 minutes in an hour, all you have to do is divide 200 by 60 and you'll get 3.33333 repeating kilometers.  

The molecules of oil are nonpolar because their charges are balanced and therefore these molecules are not attracted by other in solution, while water molecules are polar because their atoms are arranged to form positive and negative poles in solution.  

Oil is nonpolar and water polar due to the active forces between molecules, in the case of non polar substances the charges are balanced while polar molecules contain negative and positive poles.

Therefore, with this data, we can see that oil is nonpolar and water is polar due to the charges of their atoms.

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Answer:

12 miles per hour. your welcome

The indicator would be red in a solution with a pH of 4.00.

The pH of a solution gives us the concentration of hydrogen ions (H+) in the solution. We can use this information to determine the ionization state of the indicator and therefore its color.

The ionization of the indicator Hin can be represented by the following equilibrium equation:

Hin  ⇌  H⁺  +  in-

The ionization constant, Ka, of the indicator can be expressed as:

Ka = [H⁺][in-]/[Hin]

At pH 4.00, the concentration of H+ can be calculated as:

[H+] = \(10^{-pH\) = 10⁻⁴ = 0.0001 M

Let's assume that the initial concentration of the indicator Hin is 1.00 M. At equilibrium, the concentration of Hin will be equal to (1.00 - [H⁺]) M and the concentration of in- will be equal to [H⁺].

Using the equilibrium equation and the expression for Ka, we can write:

Ka = [H⁺][in-]/[Hin]

Ka = [H⁺]²/[Hin] = [H⁺]²/(1.00 - [H⁺])

Substituting the value of [H⁺] in the above equation, we get:

Ka = (0.0001)²/(1.00 - 0.0001) ≈ 9.99 x 10⁻⁸

Since Ka is much smaller than the initial concentration of the indicator, we can assume that the ionization of the indicator is negligible. This means that the indicator will be mostly in its non-ionized form at pH 4.00. According to the problem, the non-ionized form is red and the ionized form is yellow.

Therefore, the color of the indicator in a solution whose pH is 4.00 would be red.

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Answer: A

Explanation: According to the Bohr model, often referred to as a planetary model, the electrons encircle the nucleus of the atom in specific allowable paths called orbits. When the electron is in one of these orbits, its energy is fixed.

Coefficient of C3H8O2 = 3

Coefficient of KMnO4 = 8

We are given that a reaction in which C3H8O2 reacts with KMnO4

We have to find the coefficient of each reactants in balanced reaction

3C3H8O2(aq) + 8KMnO4(aq) → 3C3H2O4K2(aq) + 8MnO2(aq) + 2KOH+8H2O

Coefficient is defined the constant value multiplied with a reactant in a reaction.

Coefficient of C3H8O2 = 3

Coefficient of KMnO4 = 8

Coefficient of C3H2O4K2 = 3

Coefficient of MnO2 = 8

Coefficient of H2O = 8

Coefficient of KOH = 2

Hence, Coefficient of C3H8O2 = 3 and coefficient of KMnO4 = 8

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Answer:

Compound 3 is a clear liquid with a strong pleasantly fruity smell. If cooled it freezes at about −10°C. In the solid state it does not conduct electricity. ... It dissolves slightly in water, and a solution of 2g in 100mL of water doesn't change the electrical conductivity of the water.

Answer:

molecular

Explanation:

In the case of Compound 1, the fact that melted below room temperature, and is a volatile liquid at room temperature, strongly suggests it's a molecular compound.

The portion of energy from the Sun that reaches the Earth​ is known as

electromagnetic spectrum.

Energy transfer from objects in space such as the Sun usually reach the

earth through the process known as radiation. The energy is referred to as

electromagnetic energy.

Components of the electromagnetic spectrum are:

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Technetium-99m is a radioisotope that is widely used in nuclear medicine for various imaging studies. It is usually produced through a process called generator system from the decay of its parent isotope, Molybdenum-99 (Mo-99).

How technetium-99m is generated:Technetium-99m is generated by a process called a generator system from the decay of its parent isotope, Molybdenum-99 (Mo-99). This generator system is essentially a column packed with a gel-like substance, which is usually made of alumina, silica, or another material. The column contains Mo-99, which is produced in a nuclear reactor, and its daughter isotope Technetium-99m (Tc-99m).The Mo-99 decays into Tc-99m by beta decay, emitting a beta particle and a neutrino.

As a result, Tc-99m is separated from Mo-99 by using a saline solution or another eluant to flush the column. The Tc-99m-containing eluant is then used for imaging studies.There are several advantages to using Tc-99m for imaging studies. It has a short half-life of only six hours, which means that it does not stay in the body for a long time and is eliminated quickly. This makes it safer for patients than isotopes with longer half-lives. Additionally, Tc-99m emits gamma rays, which can be detected by imaging equipment such as gamma cameras. This allows for high-quality imaging studies that can help diagnose a wide range of medical conditions.

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Answer: In simplest case mass of reactants is same as mass of products.

Without thinking this question deeper, mass of ZnCl2 would be 49, but..

Explanation: Reaction should be  Zn + 2 HCl ⇒ ZnCl2 + H2

Amount of zinc is  5 g / 65,38 g/mol = 0,076476 mol and amount

of Hydrogen Chloride is 50 g / 36.458 g/mol = 1,371 mol.

Althought HCl is needed 0.152 moles, zinc is an limiting reactant.

So it is possible to produce only 0.076476 mol Hydrogen and its mass

is 0.154 g.  Mass of ZnCl2 would be 0.076476 mol · (65.38 + 2·35.45) =

 10.42 g

The hydroxide ion concentration [OH-] in a 1.1×10−3 M solution of Sr(OH)2 can be calculated using the solubility product constant (Ksp) for the compound. The final concentration of [OH-] in the solution is 2.4×10−4 M.

1. The Ksp for Sr(OH)2 is 5.4×10−12, which represents the equilibrium constant for the dissolution of Sr(OH)2 in water. By assuming that the dissociation of Sr(OH)2 in water is complete, we can calculate the molar concentration of [OH-] from the stoichiometry of the reaction.

2. The solubility product constant (Ksp) is the equilibrium constant for the dissolution of a sparingly soluble salt in water. It represents the concentration of the ions produced when the solid salt dissolves. For Sr(OH)2, the Ksp is given as: Sr(OH)2 ⇌ Sr2+ + 2OH−

Ksp = [Sr2+][OH−]2 = 5.4×10−12

3. The stoichiometry of the reaction shows that for every one mole of Sr(OH)2 that dissolves, it produces one mole of Sr2+ ions and two moles of OH− ions. Therefore, if we assume that all of the Sr(OH)2 has dissociated completely, then the molar concentration of [OH−] is twice that of [Sr(OH)2]. [OH−] = 2[ Sr(OH)2]

[OH−] = 2 × 1.1×10−3 M

[OH−] = 2.2×10−3 M

4. However, we need to take into account the fact that [Sr2+] and [OH−] will recombine to form Sr(OH)2, which will affect the concentration of [OH−]. To calculate the concentration of [OH−] at equilibrium, we can use the quadratic equation to solve for x in the expression for the Ksp:

Ksp = [Sr2+][OH−]2 = (x)(2x)2 = 5.4×10−12

x = [OH−] = 2.4×10−4 M

5. Thus, the final concentration of [OH−] in the solution is 2.4×10−4 M, which is much smaller than the initial concentration of 2.2×10−3 M. This indicates that the reaction has reached equilibrium, with most of the Sr2+ and OH− ions combining to form solid Sr(OH)2.

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Explanation:

At the start of the citric acid cycle, a molecule of oxaloacetate accepts a two-carbon acetyl group from acetyl CoA to form citrate. This reaction kicks off the citric acid cycle; thus, oxaloacetate is required for the cycle to take place.

To begin the citric acid cycle, an oxaloacetate molecule accepts a two-carbon acetyl group from acetyl CoA to form citrate. Because this reaction initiates the citric acid cycle, oxaloacetate is required for the cycle to occur.

The Krebs cycle, also known as the citric acid cycle or TCA cycle, is a chain of reactions that occurs in the mitochondria and is used by almost all living cells to produce energy through aerobic respiration. It consumes oxygen and emits water and carbon dioxide as byproducts.

All aerobic organisms use a series of chemical reactions to generate energy by converting acetate derived from carbohydrates, fats, and proteins into carbon dioxide.

The citric acid cycle involves the attachment of an acetyl group from acetyl CoA to a four-carbon oxaloacetate molecule to form a six-carbon citrate molecule.

Thus, Citrate is oxidized in a series of steps, releasing two carbon dioxide molecules for each acetyl group fed into the cycle.

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Determining the hydroxide ion concentration of an aqueous solution with legal ramifications would require using a reliable and accurate method that is accepted in the scientific community. One such method is titration.

Titration is a laboratory technique used to determine the concentration of a solution by reacting it with a known concentration of another solution. In the case of determining hydroxide ion concentration, the solution would be titrated with a strong acid of known concentration, using a pH indicator to determine the endpoint of the reaction.

To ensure accuracy without any reasonable doubt, it is essential to follow the proper procedures and protocols for the titration method. This includes accurately measuring the solutions used, maintaining appropriate conditions (such as temperature and pressure), and using appropriate equipment and techniques.

It is also important to use a reliable and accredited laboratory, and to have the analysis performed by a qualified analyst with appropriate credentials.

In summary, using the titration method with proper protocols and in a reputable laboratory with qualified analysts would be the best method to determine the hydroxide ion concentration of an aqueous solution with legal ramifications, ensuring accuracy without any reasonable doubt.

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Without enough iron, Andrew may not have sufficient hemoglobin. When hemoglobin is not present in sufficient amounts, the equilibrium shifts in the direction of decreased oxygen binding to red blood cells.

This means that each time Andrew breathes in, the oxygen in the air is not being transported efficiently by his red blood cells to his tissues. As a result, his tissues are not obtaining sufficient oxygen, which can lead to symptoms such as fatigue, shortness of breath, and headaches.

To address this issue, Andrew may need to increase his iron intake through diet or supplements, or undergo medical treatment if the problem is more severe. Overall, it is important to identify and address any underlying factors that may be contributing to inadequate oxygen transport in the body to ensure optimal health and functioning.

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Answer: 3.6

Explanation: You use the formula pH = -log([H+]) and plug in the 2.4E-4 with a negative log. After you convert H+ to the pH, you will change the final answer of 3.62 to the correct amount of significant figures which is 3.6.

Answer:

Here is the correct answer. 3.6

There must have been 0.10mol of \(C_{2} H_{2} O\) in the container at the beginning.

 \(C_{2} H_{2} O\) + \(2O_{2}\) = \(2CO_{2}\) + \(H_{2} O\)

The above reaction makes it quite evident that 1 mol of \(C_{2} H_{2} O\) combines to create 2 mol of \(CO_{2}\) and \(O_{2}\) is given in excess that \(C_{2} H_{2} O\) alone controls a product's formation. Therefore, here, O is an excess reactant and \(C_{2} H_{2} O\) is a limiting reactant.

It takes 6 times as much \(C_{2} H_{2} O\) to produce 1 mol of \(CO_{2}\) from 0.05 mol of \(C_{2} H_{2} O\).

Now, 0.6 divided by 6 mol of reactant is required for 0.60 moles of \(CO_{2}\)to produce, which translates to

moles of \(C_{2} H_{2} O\) = 0.6/6 = 0.1 mol .

Therefore, \(C_{2} H_{2} O\) must have been present in the container in an initial concentration of 0.10mol.

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Based on the given information, it can be inferred that delta S for the reaction at 600K is positive. The delta S for the reaction CH3OH (g) = CO (g) + 2H2 (g) at 600K can be inferred to be positive.

The fact that the reaction goes essentially to completion suggests that it is highly spontaneous, which indicates a large negative delta G. We can use the equation delta G = delta H - T delta S, where delta H is the enthalpy change and T is the temperature, to determine the sign of delta S.

The enthalpy change (Delta H) is given as +91 kJ/mol, which is a positive value, and the temperature is 600K. To make the Gibbs free energy change (Delta G) negative and ensure that the reaction is spontaneous, the entropy change (Delta S) must be positive. This is because a positive entropy change will result in a larger negative value when multiplied by the temperature, and will overcome the positive enthalpy change to make Delta G negative.

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