Answer:
Electrical power is the product of voltage times current.
Is corrosion garvanic or electrolytic?Why?
Answer:
yes
Explanation:
While galvanic corrosion is driven by the difference in corrosion potential between two metals, the electrolytic corrosion is driven by the external sources of EMF.
Calculate the number of gold atom
present in 0.6g of 18 carat gold (24 carat
gold is taken as 100%
where and amu of
gold in 197
Teacher's Signature.
The number of gold atom : 1.204 x 10²¹
Further explanationGiven
0.6 g of 18 carat gold
mass number of gold = 197
24 carat as 100% gold
Required
The number of gold atom
Solution
Percentage of gold in 18 carat :
\(\tt \dfrac{18}{24}\times 100\%=75\%\)
Mass of gold in 0.6 g of 18 carat :
\(\tt 75\%\times 0.6~g=0.45~g\)
mol :
\(\tt mol=\dfrac{mass}{MW}=\dfrac{0.45}{197}=0.0023\)
A mole is a number of particles(atoms, molecules, ions) in a substance
1 mole = 6.02.10²³ particles
So the number of gold atom :
\(\tt 0.0023\times 6.02\times 10^{23}=1.204\times 10^{21}\)
1. Explain the test for unsaturation.
2. Write down the balanced chemical equations for the complete and incomplete
combustion of octene
3. Explain how propanol, an alcohol, is formed from propene..
4. How is margarine formed?
Answer:
1)In organic chemistry, the bromine test is a qualitative test for the presence of unsaturation (carbon-to-carbon double or triple bonds), phenols and anilines. ... The more unsaturated an unknown is, the more bromine it reacts with, and the less coloured the solution will appear.
2)The equation for incomplete combustion of propane is: 2 C3H8 + 9 O2 → 4 CO2 + 2 CO + 8 H2O + Heat. If not enough oxygen is present for complete combustion, incomplete combustion occurs. The result of incomplete combustion is, once again, water vapour, carbon dioxide and heat. But it also produces carbon monoxide.
Explanation:
3)Propene, also known as propylene, is an unsaturated organic compound with the chemical formula {\displaystyle {\ce {CH3CH=CH2}}}. It has one double bond, and is the second simplest member of the alkene class of hydrocarbons. It is a colorless gas with a faint petroleum-like odor.
Formula: C3H6
IUPAC ID: Propene
4)Margarines are chemically created during hydrogenation which, until January 1, 2006, relied upon trans fats to solidify their vegetable oils. Food companies have been exploring options for replacing trans fat in partially hydrogenated margarine.
How many elements are in the compound C2H8O
Answer:
I think 2
Explanation:
How many mL are in 0.365 L?
Answer:
365 mL
Explanation:
There are 1,000 mL per every 1 L. As such, to convert between the two measurements, you need to multiply the given volume (0.365 L) by the conversion. To allow for the cancellation of units (liters), liters should be in the denominator of the conversion.
1,000 mL = 1 L
0.365 L 1,000 mL
---------------- x ----------------- = 365 mL
1 L
An unknown compound contains only carbon, hydrogen, nitrogen, and oxygen. Complete combustion of a 2.77 g sample of the compound gives 6.64 g CO2 and 1.67 g H2O. Another sample of mass 1.69 g was found to contain 0.143 g N. The molar mass of the compound was found to be 165 g mol−1. Find the molecular formula of the unknown compound
The molecular formula of the unknown compound is determined as C₉H₁₁NO₂.
Molecular formula of the compoundThe molecular formula is calculated as follows;
CHNO + O₂ ------------> CO₂ + H₂O
Mass of carbon, C: = (6.64 x 12)/44 = 1.81 g in 2.77 g sample
Mass of hydrogen, H: = (1.67 x 2)/18 = 0.186 g in 2.77 g sample
Mass of Nitrogen, N: = (2.77 x 0.143)/1.69 = 0.234 g
Mass of oxygen, O: = 2.77 g - 1.81 g - 0.186 g - 0.234 g = 0.54 g
molar ratio of the elements:C = 1.81 g = 0.15 mol
H = 0.186 g = 0.186 mol
N = 0.234 g = 0.017 mol
O = 0.54 g = 0.0337 mol
divide through with the smallest number of moles (0.017 mol);
C = 9
H = 11
N = 1
O = 2
Molecular formula = C₉H₁₁NO₂
Check the molar mass of the compound = (9 x 12) + (11 x 1) + (14) + (2 x 16) = 165 g/mol
Thus, the molecular formula of the unknown compound is determined as C₉H₁₁NO₂.
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List the 2 pKa's for H2SO4
I am an unknown element located between Krypton and Argon. I am +1/2, +1/2, +1/2 in the p area when looking at my orbital configuration. I am a household item used to kill organisms. What am I?
The element between Krypton and Argon as decribed is; Niobium (Nb).
An element which is +1/2, +1/2, +1/2 in the p area when looking at it's orbital configuration can be described as follows;
Has 3 electrons in its outermost p-orbital.In essence, it has, 5 electrons in its outermost shell including its 2 electrons in its outermost s-orbital.The element is therefore am element with valency 5 between Krypton and Argon.
The element in discuss is Niobium (Nb).
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The normal boiling point of a liquid is 282 °C. At what temperature (in °C) would the vapor pressure be 0.500 atm? (∆Hvap = 28.5 kJ/mol)
For a normal boiling point of a liquid is 282 °C, the temperature is mathematically given as
T2=181.55°C\
What temperature (in °C) would the vapor pressure be 0.500 atm?Generally, the equation for the gas is mathematically given as
ln(p1/p2)=dHvap/R(1/T2-1/T1)
Therefore
ln(1/0.26)=23500/8.214(1/T2-1/555)
T2=181.55^C
In conclusion
T2=181.55°C
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According to the law of conservation of mass, how much zinc was produced if Calcium = 25 g, Zinc Carbonate = 125 g, and Calcium Carbonate = 95 g.
HELPP
All the balanced chemical equations obey the law of conservation of mass. The numbers which are used to balance the chemical equation are called the coefficients. So here the mass of zinc is 55 g.
According to the law of conservation of mass, the mass can neither be created nor be destroyed but it can be converted from one form to another. The reactants appear on the left hand side and the products appear on the right hand side.
The amount of products is equal to the amount of reactants according to the law of conservation of mass.
25 + 125 = 95 + Zn
Zn = 55 g
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If you were an element, what element are you and in what another element would you like to bind with and why?
Answer:
If I were an element, I would want to be Carbon. I would want to combine with oxygen. It would create carbon dioxide. It has daily life uses. For heat, and for refridgment and more.
Explanation:
what is the final temperature of both the water and the iron?
Hello!
Answer:
32.8 °C
Hope this helps :)
What does it mean for heat to be transferred by thermal conduction?
Answer:
thermal energy
Explanation:
Thermal conduction is the diffusion of thermal energy (heat) within one material or between materials in contact. The higher temperature object has molecules with more kinetic energy; collisions between molecules distributions this kinetic energy until an object has the same thermal energy throughout.
Answer:
energy is transferred when one molecule collides with another.
Explanation:
aP33x
You need to prepare 50.00 mL of a pH 4.75 buffer solution using 0.600 M formic acid (pKa=3.74) and a 0.3000 M sodium formate. How many milliliters of formic acid are needed to prepare this buffer?
0.766 mL volume of formic acid is needed to prepare the buffer.
What is volume of formic acid?
To calculate the amount of formic acid needed to prepare the buffer, we can use the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
where pH is the desired pH of the buffer, pKa is the acid dissociation constant of the weak acid, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.
First, we can rearrange the Henderson-Hasselbalch equation to solve for the ratio of [A-]/[HA]:
[A-]/[HA] = \(10^{(pH - pKa)}\)
[A-]/[HA] = \(10^{(4.75 - 3.74)}\)
[A-]/[HA] = 3.52
Next, we can use the fact that the sum of the concentrations of [A-] and [HA] must be equal to the total volume of the buffer solution times the total concentration of the buffer components:
[A-] + [HA] = (0.0500 L)(0.600 M + 0.3000 M)
[A-] + [HA] = 0.0450 mol
We can also express [A-] in terms of [HA] using the ratio we calculated above:
[A-] = 3.52[HA]
Substituting this into the previous equation, we get:
3.52[HA] + [HA] = 0.0450 mol
4.52[HA] = 0.0450 mol
[HA] = 0.00994 mol
Finally, we can use the molar mass of formic acid (46.03 g/mol) to calculate the volume of formic acid needed to prepare the buffer:
volume of formic acid = (0.00994 mol)(46.03 g/mol) / (0.600 mol/L)
volume of formic acid = 0.766 mL
Therefore, 0.766 mL of formic acid is needed to prepare the buffer.
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A chemist wants to make a 17.85 %(m/m) solution of NaCl using a only 50.0 g of the salt. How much water is needed to make the solution? Numerical answer only. No units.
The mass percentage is an important method which is used to calculate the concentration of a solution. The amount of water needed to add in order to make 17.85 % NaCl solution is 230.1 g.
What is mass percentage?The mass percentage of a component in a solution is defined as the mass in grams of that component present per 100 g of the solution. The term mass percentage is denoted as w/w. It is used to calculate the concentration of a binary solution.
Mass percentage = Mass of the component in the solution / Total mass of solution × 100
17.85 = 50.0 / 50.0 + x × 100
0.1785 (50.0 + x) = 50.0
8.925 + 0.1785 x = 50.0
0.1785 x = 41.075
x = 230.1 g
Thus the amount of water added to make the solution is 230.1 g.
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in the reaction of calcium with 1 m hydrochloric acid, which of the following will increase the reaction rate
increasing the concentration of a reactant in solution
increasing the surface area of a solid reactant
increasing the temperature of the reaction system
The reaction rate increases by increasing the temperature of the reaction system , increasing the concentration of a reactant in solution and increasing the surface area of a solid reactant.
In the reaction of calcium with 1 M hydrochloric acid, The factor which will increase the reaction rate is by increasing the temperature of the reaction system. When the temperature of the reaction increases , the molecules kinetic energy of the molecules increases more than the activation energy and it will increases the rate of reaction.
The activation energy of the reaction decreases and therefore the rate of the reaction increases. The reaction rate increases by increasing the concentration of the reactant in the solution and increasing the surface area of the solid reactant.
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How many moles are contained within 18.6 g Zn
Ok, so
First of all, let's remember what a mole is:
A mole can be described as the molecular mass of a compound or the mass of an element.
For example:
The molar mass of Zn is 65.38g. So, 1 mole of Zn equals to 65.38g of Zn. We can find the value of molar mass in the periodic table.
Now, we want to find the number of moles that are contained within 18.6g Zn.
For this, we could use the fact that:
\(\text{moles}=\frac{\text{Given mass}}{\text{ molar mass}}\)In this case, our given mass is 18.6g of Zn, and, the molar mass of Zn is 65.38g/mole. Then, if we replace:
\(\text{moles Zn = }\frac{18.6gZn}{\frac{65.38gZn}{moleZn}}=0.284molesZn\)Therefore, there are 0.284 moles of Zn in 18.6g of Zn.
A 7.212 g sample of hydrated salt is heated until a constant mass is obtained. The mass of the anhydrous salt is 3.524. What is the percent by mass of water in the original hydrated salt sample in % H20?
Answer:
51.14%
Explanation:
The following data were obtained from the question:
Mass of hydrated salt = 7.212 g
Mass of anhydrous salt = 3.524 g
Percentage mass of water =..?
Next, we shall determine the mass of the water in the hydrated salt. This can be obtained as follow:
Mass of hydrated salt = 7.212 g
Mass of anhydrous salt = 3.524 g
Mass of water =.?
Mass of water = (Mass of hydrated salt) – (Mass of anhydrous salt)
Mass of water = 7.212 – 3.524
Mass of water = 3.688 g
Finally, we shall determine the percentage mass of water in the hydrated salt as follow:
Percentage of water
= mass of water /mass of hydrated salt × 100
Percentage of water = 3.688/7.212 × 100
Percentage of water = 368.8/7.212
Percentage of water = 51.14%
Therefore, the percentage of water in the hydrated salt is 51.14%
A neutral atom of on element has two electrons
with n=1, eight electrons with n=2, eight electrons
with n=3 and one electron with n =4 and has mass
number of 39. Deduce the following from the above
information
i the atomic number of the element.
is number of neutrons in the nucleus
i total number of s electrons.
iv total number of p electrons .
v the group the element belongs to
A neutral atom of on element has two electrons with n=1, eight electrons with n=2, eight electrons with n=3 and one electron with n =4 and has mass number of 39 then the atomic number of element is 39 and number of neutron in the nucleus is 50 and total number of s electron is 2 and total number of p electron is 8 and the group is 3rd group
Yttrium is a metallic element with atomic number 39 usually included in the rare earth group that occur usually with other rare earth element in minerals and is used especially in phosphorous and YAG laser and alloy etc and element with mass number of 39 is yttrium and the atomic number of element is 39 and number of neutron in the nucleus is 50 and total number of s electron is 2 and total number of p electron is 8 and the group is 3rd group
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True or False, a skeleton equation shows the formulas of the compounds participating in a chemical reaction and their states of matter but not the ratio in which they react.
The given statement is true. A skeleton equation shows the formulas of the compounds participating in a chemical reaction and their states of matter but not the ratio in which they react.
What does a skeleton equation show?A skeleton equation defines the chemical formulas and physical states of the reactants and products, yet it does not account for the relative amounts of the reactants and products. Chemical reactions result simply from the rearrangement of atoms, thus the law of conservation of mass have to be observed.
Skeleton Equations are the equations where there is only chemical formula of reactants and products but no state mentioned and no balancing of atoms on either side of the equation done. For example: Mg + O2 → MgO, it is a skeleton equation. In the equation, the only thing mentioned is the chemical formula of reactant.
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What is the result of a neutralization reaction between nitric acid (HNO3) and potassium hydroxide (KOH)?
O A. potassium nitrate (KNO3)
O B.
water and potassium nitride (H20 and K3N)
OC. potassium nitride (K3N)
O
D.
water and potassium nitrate (H20 and KNO3)
Answer:
D
acid+base-----> salt + water
. 2.514g Ca, 1.004g O empirical formula
The empirical formula of the given compound is \(CaO\).
A chemical compound's empirical formula in chemistry is the simplest whole number ratio of atoms within a molecule.
Given:
Mass of Ca = 2.514g
Mass of O = 1.004g
Molar mass of Ca = 40.078g/mol
Molar mass of O = 15.999g/mol
To find:
Empirical formula = ?
Formula:
Empirical formula = Moles of Ca : Moles of O
Calculations:
No. of moles of Ca = 2.514 / 40.078
n of Ca = 0.06273 moles
No. of moles of O = 1.004 / 15.999
n of O = 0.06275 moles
Divide both by the lowest no. of moles
n of Ca : n of O = 1 : 1
Empirical formula = \(CaO\)
Result:
\(CaO\) is the empirical formula of the compound.
The complete question is:
In an experiment, a 2.514 g sample of calcium was heated in a pure stream of oxygen, and was found to increase in mass by 1.004 g. Calculate the empirical formula for the given compound.
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All atoms of the same element contain the same number of protons. The atom that has 9 protons can be represented by the symbol? The answer is B) F
Answer:Ok den...
Explanation:
Nope
if the solubility constant product of baf2 is 2.4×10^-3 m what the solubility of Baf2
The solubility of BaF₂ is 0.18 g/L
What is solubility?
Solubility is defined as the maximum quantity of a substance that can be dissolved in another. It is the maximum amount of solute that can be dissolved in a solvent at equilibrium, which produces a saturated solution
The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution.
It represents the level at which a solute dissolves in solution.
The more soluble a substance is, the higher the Ksp value it has.
Given,
Ksp for barium fluoride = 2.4 × 10⁻³
We know that, Barium Flouride dissociates as -
BaF₂ ⇒ Ba²⁺ + 2F⁻
Let the solubility be s = [ Ba²⁺] = [F⁻]
Thus, Ksp = [Ba²⁺] [2F⁻]²
= s × 4s² = 4s³
Substituting the values, we get
2.4 × 10⁻³ = 4s³
s³ = 2.4 × 10⁻³ ÷ 4
s³ = 6 × 10⁻³
s = ∛ 6 × 10⁻³
s = 0.18 g/L
Therefore, the solubility of BaF₂ is 0.18 g/L
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Calculate the molarity of an aqueous solution that is 22. 3% by mass calcium chloride. You might need to know that the density is 1. 20 g/ml.
Answer:
Explanation:
To calculate the molarity of the solution, we first need to determine the mass of calcium chloride (CaCl2) in 100 g of the solution.
If the solution is 22.3% calcium chloride by mass, this means that there are 22.3 g of CaCl2 in 100 g of the solution.
We can use the density of the solution to convert 100 g of the solution to its volume:
volume of 100 g of the solution = mass of the solution / density of the solution
volume of 100 g of the solution = 100 g / 1.20 g/mL = 83.3 mL
Now, we can calculate the molarity of the solution using the following formula:
molarity = moles of solute / volume of solution (in L)
The molar mass of CaCl2 is 40.08 + 2(35.45) = 110.98 g/mol. Therefore, the number of moles of CaCl2 in 22.3 g of the solution is:
moles of CaCl2 = 22.3 g / 110.98 g/mol = 0.2008 mol
The volume of the solution containing 22.3 g of CaCl2 is:
volume of solution = 83.3 mL / 1000 mL/L = 0.0833 L
Substituting these values into the formula for molarity, we get:
molarity = 0.2008 mol / 0.0833 L = 2.41 M
Therefore, the molarity of the aqueous solution that is 22.3% by mass calcium chloride is 2.41 M.
What is the pH of a solution the hydroide concentration of 1 X 10.5?
Answer:
Explanation:
Therefore, the pH of the HCl solution is 5.
An element is lustrous, brittle, and silver colored. What type of element is it
Metal
Metalloid
Non Metal
Other
Will give brainlist
A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol.
A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol, the molecular formula is NO₂.
We must compute the empirical formula in order to ascertain the compound's chemical composition.
If we have 100 grams of the compound.
This suggests we have:
30.4 g of nitrogen
69.6 g of oxygen
Now, we have to convert the mass of each element to moles.
The molar mass of nitrogen (N) = 14.01 g/mol
the molar mass of oxygen (O) = 16.00 g/mol.
Number of moles of nitrogen (N):
2.17 mol
Number of moles of oxygen (O):
4.35 mol
The simplest whole-number ratio between the moles of nitrogen and oxygen must now be determined. To calculate the ratio, we divide both numbers by the smaller value.
Moles N / moles O = 2.17 mol / 2.17 mol = 1.00
Moles O / moles O = 4.35 mol / 2.17 mol = 2.00
The ratio is approximately N₁O₂.
We divide the subscripts by their greatest common divisor to obtain the simplest ratio, since we are looking for the empirical formula. The empirical formula is NO₂ since the greatest common divisor in this situation is 1.
The molecular formula of the compound is NO₂.
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Are the gas laws affected depending on whether you use heavy gas particles or light gas particles? If anything, what is affected by the size of the molecule?
Answer:
yes
Explanation:
Yes, size of molecule has greatly affected the gas law.
The gas laws affected depending on whether we use heavy gas particles or light gas particles because the heavy gas particles can't move faster as light gas particles with the increase of temperature.
If the temperature is increased, the gas particles move faster due to absorb of heat energy so they hit the walls of the container. This causes the pressure to rise. The pressure of a gas also increases when the volume of container in which it is placed is decreased. Bigger the molecule size, the stronger the intermolecular forces, so the molecule has higher melting and boiling points so we can conclude that big size molecule greatly affected the gas law.
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which gas is fossil fuel
Answer:
methane
Explanation: methane is obtained from the decaying of flora and fauna mostlyunder damp