Which statement about velocity is true?

Answer:

I = Q / t          definition of current I

Q = i t = 10 Coul/sec * 60 sec = 600 Coul

A 10-A current is maintained in a simple circuit with a total resistance of 209 ohms, then the net charge passes through any point in a circuit during a 1-minute interval would be 6000 Coulombs.

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge.

Electric current is defined as the charge per unit of time.

The mathematical relation between current and the electric charge

I =Q/T

Let us first convert the time period of minutes into seconds

1 min = 60 seconds

10  min = 10*60 seconds

            =600 seconds

Q = I*t

   =10*600

   =6000 Amperes

Thus, the net charge that passes through any point in a circuit during a 1-minute interval would be 6000 Amperes.

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The type of change that occurs when coal is burned completely in a power plant, resulting in the formation of carbon dioxide, is a chemical change.

When coal is burned completely in a power plant, a chemical reaction takes place between the solid carbon in the coal and the oxygen gas from the atmosphere. This reaction is known as combustion. During combustion, the carbon in the coal combines with oxygen to form carbon dioxide (CO2). This process involves the breaking and rearranging of chemical bonds between the carbon atoms and the oxygen atoms.

A chemical change, also known as a chemical reaction, involves the transformation of one or more substances into different substances with different chemical properties. In this case, the solid carbon in the coal is being transformed into carbon dioxide gas. The formation of carbon dioxide is a chemical change because new chemical bonds are formed and the chemical composition of the coal is altered.

Therefore, the correct answer is c. Chemical.

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Answer:

The correct answer is option D: 20 m.

Explanation:

Answer:a. To find the potential difference between points A and B, we need to use the formula:

ΔV = W / q

where ΔV is the potential difference, W is the work done, and q is the charge.

Plugging in the given values, we get:

ΔV = 5 J / 0.25 C = 20 V

Therefore, the potential difference between points A and B is 20 volts.

b. The kinetic energy gained by a charged particle as it moves through a potential difference is given by:

KE = qΔV

where KE is the kinetic energy, q is the charge, and ΔV is the potential difference.

Assuming that the xenon ion is a singly ionized ion with a charge of +1.6 × 10^-19 C, we can calculate the kinetic energy gained in each case as:

Case 1: ΔV = 500 V, d = 0 (immediate)

KE = qΔV = (1.6 × 10^-19 C) × (500 V) = 8 × 10^-17 J

Case 2: ΔV = 500 V, d = 1 cm

The electric field between the two points is given by:

E = ΔV / d = 500 V / (0.01 m) = 5 × 10^4 V/m

The force on the ion is given by:

F = qE = (1.6 × 10^-19 C) × (5 × 10^4 V/m) = 8 × 10^-15 N

Using the work-energy theorem, we can calculate the distance traveled by the ion as:

W = Fd = KE

d = KE / F = (8 × 10^-17 J) / (8 × 10^-15 N) = 0.01 m

Therefore, the ion travels a distance of 1 cm before it comes to rest.

c. The electric field at the surface of the spherical shell is given by:

E = V / r

where V is the potential and r is the radius of the shell.

The dielectric strength of air is the maximum electric field that air can withstand before it breaks down and becomes conductive. In this case, the dielectric strength of air is 3 × 10^6 V/m.

Therefore, we can write:

E = 3 × 10^6 V/m

V / r = 3 × 10^6 V/m

Solving for r, we get:

r = V / E = (1 × 10^6 V) / (3 × 10^6 V/m) = 0.333 m

Therefore, the minimum radius of the spherical shell is 0.333 meters or 33.3 cm.

The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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Answer: friction has no role to play in this case. because friction usually occurs between to parts which come in contacts. examples (a)our joints in the human body (b)two mechanical parts (shafts).

Explanation:

However what this topic relates to is gravity. The pebble and paper both weigh one gram, but have different density this is the sole reason why if both are drop from same height the pebble would reach the ground faster than the paper because it is more denser. unlike the paper with a lesser density which would take a longer time to reach the ground.

Answer:

An element is a pure substance and is made of only one type of atom; it cannot be broken down into a simpler substance.

Answer:

Regular Reflection:

1. Reflection from a polished surface is called regular reflection.

2. parallel rays remain parallel after reflection.

DIFFUSED REFLECTION:-

1. Reflection from a rough surface is called diffuse reflection.

2. Parallel rays do not remain parallel after reflection.

Answer:

done

Explanation:

eeeeeeeeeeeeeeeeeeeeee

The power in circuit A is two times the power in circuit B. Therefore, Circuit A has the greatest power, and it is by a factor of 2.  

Given that the current in circuit A is two times the current in circuit B and the light bulb in circuit A has one-half the resistance of the light bulb in circuit B, we need to find out which circuit has the greatest power.

The power of an electric circuit is given as `P = VI`, where V is the voltage across the circuit and I is the current flowing through the circuit. The voltage across a circuit is directly proportional to the resistance of the circuit.

That is, as the resistance of a circuit increases, the voltage across the circuit also increases.

Hence, we can rewrite the equation for power as `P = I²R`.

For circuit A, let the current be I₁ and resistance be R₁. For circuit B, let the current be I₂ and resistance be R₂.

Given that, I₁= 2I₂ and R₁ = (1/2)R₂.

Substituting the values in the equation for power,

P1 = I₁²R₁ and P₂

= I₂²R₂P₁/P₂

= (I1²R₁) / (I₂²R₂)

= (4I₂²(1/2)R₂) / (I₂²R₂)

= 2/1

= 2

Hence, the power in circuit A is two times the power in circuit B.

Therefore, Circuit A has the greatest power, and it is by a factor of 2.

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Answer:

27.5Ω

Explanation:

Given parameters:

Potential difference in the circuit = 11V

Current in the circuit  = 0.4A

Unknown:

Resistance in the circuit = ?

Solution:

According to ohm's law;

   V = IR

V is the voltage

I is the current

R is the resistance

  Since the unknown is R, we find it;

        11  = 0.4 x R

         R  = \(\frac{11}{0.4}\)   = 27.5Ω

The resistance of the variable resistor will be 27.5 ohms

According to Ohm's law which states that the current flowing through a metallic conductor is directly proportional to the potential difference across its ends.

Mathematically, V = IR

V is the potential difference

I is the current

R is the resistance

Given the following parameters

V = 11V

I = 0.4A

Get the resistance of the variable resistor  

R = V/I

R = 11/0.4

R = 27.5 ohms

Hence the resistance of the variable resistor will be 27.5 ohms

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By using uniform motion, the time taken to accelerate is 3.72 seconds.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

a = 0.6 m/s²

vo = 55 mi/h

vt = 60 mi/h

Convert the velocity to m/s

vo = 55 mi/h

vo = 55 x 1609.34/3600 m/s

vo = 24.59 m/s

vt = 60 mi/h

vt = 60 x 1609.34/3600 m/s

vt = 26.82 m/s

Find the time taken

vt = vo + a . t

26.82 = 24.59 + 0.6t

0.6t = 2.23

t = 3.72 seconds

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Answer:

Yes, when the velocity of the object is negative.

Explanation:

In position and time graphs, the slope of line indicates the velocity. Therefore negative slope of a position-time graph actually indicates negative velocity. Negative velocity is defined as the velocity of the object moving in an opposite direction.

The time graph reveals pertinent information about an object's velocity. For example, a small slope means a small velocity; a negative slope means a negative velocity; a constant slope (straight line) means a constant velocity; a changing slope (curved line) means a changing velocity.

Answer:

true

Explanation:

Answer:

yes

Explanation:

you don't learn it until high school

Answer:

I think the answer might be the first one

Assuming that the pistons are of equal size and the water in the tank is incompressible, the water level in the tank will be c), falling.

Piston movement usually refers to the movement of a piston within a cylinder, which is commonly found in many types of engines and machinery. When a piston moves within a cylinder, it creates a pressure differential that can be used to generate motion or power.

This is because piston A is moving twice as fast as piston B, which means that it is displacing water from the tank at a faster rate. As a result, more water is leaving the tank than entering it, causing the water level to fall.

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Answer:

Not 500 points I got 18 but thx

Explanation:

Answer: The equations in column A is matched with gas laws in column B as follows:

21. PV = nRT : (g) Ideal gas law

22. \(V_{1}n_{2} = V_{2}n_{1}\) : (f) Avogadro's law

23. \(P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}\) : (e) Combined Gas Law

24. \(P_{1}T_{2} = P_{2}T_{1}\) : (d) Gay-Lusaac's law

25. \(V_{1}T_{2} = V_{2}T_{1}\) : (c) Charles' law

26. \(P_{1}V_{1} = P_{2}V_{2}\) : (b) Boyle's law

27. \(\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}\) : (a) Graham's Law of effusion

Explanation:

(A) Ideal gas law: It states that the product of pressure and volume is directly proportional to the product of number of moles and temperature.

So, PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant

T = temperature

So, \(P_{1}V_{1} = P_{2}V_{2}\)

\(V \propto T\\\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\V_{1}T_{2} = V_{2}T_{1}\)

So,  \(P_{1}T_{2} = P_{2}T_{1}\)

So, \(V_{1}n_{2} = V_{2}n_{1}\)

\(\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\or, P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}\)

\(\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}\)

Thus, we can conclude that equation in column A is matched with gas laws in column B as follows:

21. PV = nRT : (g) Ideal gas law

22. \(V_{1}n_{2} = V_{2}n_{1}\) : (f) Avogadro's law

23. \(P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}\) : (e) Combined Gas Law

24. \(P_{1}T_{2} = P_{2}T_{1}\) : (d) Gay-Lusaac's law

25. \(V_{1}T_{2} = V_{2}T_{1}\) : (c) Charles' law

26. \(P_{1}V_{1} = P_{2}V_{2}\) : (b) Boyle's law

27. \(\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}\) : (a) Graham's Law of effusion

The answer is no. Hope this helps

The quality of early caregiver-child relationships has been the most consistent predictor of a secure attachment.
Sensitivity has been the most consistent predictor of a secure attachment.

The most reliable indicator of a stable attachment has historically been the standard of parenting.

According to attachment theory research, the most crucial aspect in determining whether a child will establish a secure attachment style is the quality of parenting, particularly the responsiveness and sensitivity of the carer. A kid who has a secure attachment has faith in their caregiver's availability and responsiveness, which fosters a sense of safety and security that allows them to explore their surroundings and form long-lasting, healthy relationships with others.

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Answer:

This is called restricted speed

Hello!

My best guess would be hydrogen and oxygen.

hopefully this helps!

Answer:

electrons

Explanation:

i think this is right

Answer:

180.7km/hr²

Explanation:

Given parameters:

Initial velocity  = 10miles/hr

Final velocity  = 25miles/hr

Time taken = 5minutes

     To hr

               60min  = 1hr

               5min gives 0.083hr

Unknown:

Acceleration  = ?

Solution:

To solve this problem,

   Acceleration  = \(\frac{v - u}{t}\)  

v is the final velocity

u is the initial velocity

  Acceleration  = \(\frac{25 - 10}{0.083}\)   = 180.7km/hr²

The rms current of an L-R-C series circuit with L = 0.115 H, R = 240 Ω, and C = 7.31 μF is 0.452 A at a frequency of 410 Hz.

In an L-R-C series circuit with an inductance (L) of 0.115 H, a resistance (R) of 240 Ω, and a capacitance (C) of 7.31 μF, the rms current is measured to be 0.452 A at a frequency of 410 Hz. This means that in this circuit, the effective current flowing through it is 0.452 A, representing the average power delivered to the circuit.

An L-R-C series circuit consists of three components - an inductor (L), a resistor (R), and a capacitor (C) - connected in series. Inductors store energy in the form of a magnetic field, resistors dissipate energy in the form of heat, and capacitors store energy in the form of an electric field.

At a frequency of 410 Hz, the inductor offers opposition to the flow of current, causing a phase shift between the current and voltage. The resistor dissipates power, reducing the overall amplitude of the current. The capacitor also plays a role in modifying the phase relationship between the current and voltage.

By analyzing the values of L, R, and C in the circuit, we can determine how these components affect the current. In this case, with an inductance of 0.115 H, resistance of 240 Ω, and capacitance of 7.31 μF, we find that the rms current is 0.452 A at a frequency of 410 Hz.

To further explore L-R-C series circuits and their behavior, one can study the concepts of reactance, impedance, and resonance. Reactance describes the opposition to the flow of current by inductors and capacitors, while impedance is the overall opposition to current flow in the circuit. Resonance occurs when the reactance of the inductor and the reactance of the capacitor cancel each other out, resulting in a minimum impedance and a maximum current.

Understanding the behavior of L-R-C series circuits is essential in analyzing and designing electrical circuits, as they are commonly found in various applications such as filters, oscillators, and power supplies. By manipulating the values of L, R, and C, engineers can tailor the circuit's response to meet specific requirements.

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Considering the definition of speed and propagation of sound, sound is a sequence of waves of pressure which propagates through compressible media and depends on the characteristics of the medium in which the propagation occurs.

Sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid.

That is, sound is a longitudinal wave, mechanical (does not travel in a vacuum) and propagates in all directions, so that the wave front is spherical.

Propagation of sound involves energy transport without matter transport, in the form of mechanical waves.

The speed of propagation of a sound wave depends on the characteristics of the medium in which the propagation occurs and not on the characteristics of the wave or the force that generates it. The speed of propagation of sound waves is also known as the speed of sound.

In summary, sound is a sequence of waves of pressure which propagates through compressible media and depends on the characteristics of the medium in which the propagation occurs.

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In parallel circuits, when all resistors are of equal value, the total resistance is equal to the value of one individual resistor  C. divided by the number of resistors.

The electrical circuits come in two primary forms - series and parallel. A parallel circuit is defined as a circuit in which the resistors are arranged in a way that they have the same potential difference or voltage across them. This implies that every component of the circuit gets the same amount of voltage. The basic principle of a parallel circuit is that every resistor gets the same amount of voltage.

When the voltage of the circuit is calculated, each component of the circuit has the same voltage. The voltage rating of each component is identical in a parallel circuit. According to Ohm's law, the resistance in a parallel circuit is inversely proportional to the current. The more the number of resistors in the circuit, the smaller the resistance of the circuit.

This means that the total resistance of a parallel circuit is always less than the resistance of the smallest resistor in the circuit. Therefore, when all the resistors are of equal value, the total resistance is equal to the value of one individual resistor divided by the number of resistors. In other words, R(total) = R(1) / n, where n is the number of resistors. Therefore the correct option is C

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Answer:

1.33

Explanation:

Apparent Depth = 1.0m

Real Depth = x

Refractive Index = 1.33

n = r.d/a.d

1.33 = x/1

x = 1.33 x 1

1.33

The paint vibrates in response to pressure waves created by the speaker, demonstrating energy transfer as a wave.

The lab set-up with paint poured onto a speaker and afterward turned on with clearly music playing shows energy being moved as a wave thanks to air. At the point when the speaker is turned on, it makes the stomach of the speaker vibrate, which thusly makes the air particles around it vibrate too.

These vibrations make pressure waves all around, which travel outwards from the speaker this way and that.As the tension waves travel through the air, they make the paint on the speaker vibrate and move too, making a noticeable example.

This example is made in light of the fact that the paint isn't quite as adaptable as air, so it doesn't vibrate similarly. All things considered, it moves because of the strain waves, making a noticeable portrayal of the wave energy.

In this manner, the lab set-up shows how energy is moved as a wave through a medium. The energy is conveyed by the tension waves, which cause development and vibrations in the medium.

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