Which statement about Niels Bohr's atomic model is true?
O Higher orbits have lower energies.
O Each orbit has a specific energy level.
O Electrons can exist in any energy level.
O Orbits close to the nucleus have no energy.

Answer: 75° C for mercury, 40.59° C for iron

Explanation:

the equation used to solve this problem is q=mcΔT ( where q is heat in joules, m is mass in grams, c is the specific heat capacity, and ΔT is the change in temperature in degrees celsius)

For mercury:

q = mcΔT

1050J = (150g)(0.140J/g°C)(final T - 25°C)

\(\frac{1050}{(150)(0.140)}\) = final T - 25

Final T = \(\frac{1050}{(150)(0.140)}\) - 25

Final T = 75°C

For iron:

q = mcΔT

1050J = (150g)(0.449J/g°C)(final T - 25°C)

\(\frac{1050}{(150)(0.449)}\) = final T - 25°C

final T = \(\frac{1050}{(150)(0.449)}\) + 25

Final T = 40.59°C

1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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Answer:: We're asked to find the molar concentration of the NaCl solution given some titration data.

Explanation:

In my own opinion, scientists should continue to try create super heavy elements and expand the periodic simply because these elements will help understand better, nuclei structure, properties and its reactions

An element is a substance which cannot be split into simpler forms by an ordinary chemical process. This simply goes to say that elements are substances which cannot be decomposed into simpler substances by ordinary chemical reactions.

An atom is the smallest unit or part of an element which can take part in a chemical reaction.

On a general note, elements are classified as thus:

So therefore, in my own opinion, scientists should continue to try create super heavy elements and expand the periodic simply because these elements will help understand better, nuclei structure, properties and its reactions

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Answer:

Pretérito (Pretérito perfecto):

estiró, sudó, peleó, compartí

Copretérito (Pretérito imperfecto):

saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian

Explanation:

Los verbos en pretérito, también llamado pretérito perfecto, son los siguientes:

estiró, sudó, peleó, compartí

Como se aprecia, los verbos conjugados en pretérito perfecto terminan la última sílaba en vocal con acento, es decir, -á, -é, -í u -ó.

Los verbos en copretérito, también llamado pretérito imperfecto, son los siguientes:

saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian

Como se aprecia, los verbos conjugados en pretérito imperfecto terminan la última sílaba en -ía, ías, -ían, -aba, -abas o -aban.  

(a) Because acid is caustic, dolphins can perish from exposure to it. Acids are compounds that give other things protons (H+). Acid can react with the proteins and lipids in dolphins' skin when they come into touch with it, leading to chemical burns and damage to the underlying tissue. Systemic consequences from this include death.

(b) Because chlorine is a potent oxidizer, it interacts with red-hot iron powder to produce Iron(III) chloride (FeCl3) rather than Iron(II) chloride (FeCl2). FeCl3 is created when chlorine at high temperatures rapidly accepts electrons from iron atoms. Contrarily, iron interacts with HCl, a less potent oxidizer than chlorine, to produce FeCl2.

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Answer:

percentage of salt is 57.6% in this seasoning.

Explanation:

Total amount of seasoning given is = 125 gram

Amount of salt = 72 gram

Now to calculate percentage of salt in seasoning we can use percentage formula:

percentage of salt = \(\frac{weight of salt}{weight of seasoning}\) × 100

= \(\frac{72}{125}\) × 100

= 57.6 %

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Explanation:

Nuclear power plants deliver electricity 24 hours a day, 7 days a week, irrespective of weather and seasons. As well as reducing greenhouse gas emissions, nuclear generation helps reduce air pollution

Answer:

D

Explanation:

Just did the test

From the forgoing, we can conclude that the the correct statements are;

The redox reaction is one in which one specie is oxidized and the other is reduced. We can obtain the equilibrium constant from the relation;

E°cell = 0.0592/n log K

E°cell = cell potential

n = number of electrons

K = equilibrium constant

E°cell = -0.403 - 0.535 = -0.938 V

n = 2 electrons

Thus;

-0.938 =  0.0592/2 logK

-0.938 * 2/ 0.0592 = log K

K = 2 * 10^-31

Also;

ΔG = - nFE°cell

ΔG = - (2 * 96500 *  -0.938)

ΔG = 181kJ/mol

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The VSEPR (Valence Shell Electron Pair Repulsion) theory describes the arrangement of electron pairs around a central atom in a molecule, and the VSEPR number represents the total number of electron pairs around the central atom, including both bonding pairs and lone pairs.The VSEPR number can be determined from the Lewis structure of the molecule, which shows the arrangement of atoms and lone pairs around the central atom. The first two digits of the VSEPR number correspond to the number of bonding pairs and lone pairs, respectively, around the central atom.To determine the third digit of the VSEPR number, you need to consider the shape of the molecule. The shape is determined by the repulsion between electron pairs, which is strongest between lone pairs and decreases in the order lone pair-lone pair > lone pair-bonding pair > bonding pair-bonding pair.The third digit of the VSEPR number indicates the shape of the molecule according to the following scheme:1: linear shape2: trigonal planar shape3: tetrahedral shape4: trigonal bipyramidal shape5: octahedral shapeThus, to determine the third digit of the VSEPR number, you need to determine the shape of the molecule based on the number of electron pairs and their relative positions. This can be done by applying the VSEPR theory and considering the repulsion between electron pairs. Alternatively, you can consult a table or chart that lists the shapes associated with different VSEPR numbers.

Answer:

............................................................................................................................

Explanation:

because ........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

Answer:

68.4°C is the final temperature of the water

Explanation:

In this problem, the heat lost by the water is equal to the heat lost by the sample of glass, that is:

W(Gl)*S(Gl)*ΔT(Gl) = W(H₂O)*S(H₂O)*ΔT(H₂O)

Where W is mass (Gl = 33.0g; H₂O = 200.0g)

S is specific heat (Gl = 0.670J/g°C; H₂O = 4.184J/g°C)

And ΔT is change in temperature ( Gl = T-7.6°C; H₂O = 70.0°C-T)

Replacing:

33.0g*0.670J/g°C*(T-7.6°C) = 200.0g*4.184J/g°C*(70.0°C-T)

22.11*(T-7.6) = 836.8*(70.0-T)

22.11T - 168.04 = 58576 - 836.8T

858.91T = 58744.04

T = 68.4°C is the final temperature of the water

Answer:

True

Explanation:

When ice is heated, the ice gains heat.

This heat gained by the ice is both used to break the intermolecular forces in ice to form water, as well as to raise the temperature of the water to it's final temperature.

Answer:

on the last underline, put a 2

Explanation:

leave the first two blank

Answer:

H₂SO₄

have a great day

Answer:

Explanation:

The chemical formula for Sulfuric acid​ is H₂SO₄

Answer:

Acid, Horizontally, Drain off the acid by opening the stopcock

Explanation:

A buret is a calibrated glass appratus used to measure and deliver accurate volume of liquid, usually acids, in acid-base titrations.

Before usually the buret to carry out your titration reaction, it is advised to condition or prepare your buret for use.

To condition the buret, add a small volume of the acid to the buret and rotate the barrel horizontally to ensure that the liquid ( acid) makes contact with the inner surface of the barrel o the buret.

This procedure is done to wash off any previous acid or liquid that the buret had been used for in previous titrations.

Complete this action by opening the stopcock of the buret to drain off the acid and discarding each volume in a designated waste container.

Note that acids could be corrosive and dangerous to the skin and so should be handled with great care

A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol, the molecular formula is NO₂.

We must compute the empirical formula in order to ascertain the compound's chemical composition.

If we have 100 grams of the compound.

This suggests we have:

30.4 g of nitrogen

69.6 g of oxygen

Now, we have to convert the mass of each element to moles.

The molar mass of nitrogen (N) = 14.01 g/mol

the molar mass of oxygen (O)  =  16.00 g/mol.

Number of moles of nitrogen (N):

2.17 mol

Number of moles of oxygen (O):

4.35 mol

The simplest whole-number ratio between the moles of nitrogen and oxygen must now be determined. To calculate the ratio, we divide both numbers by the smaller value.

Moles N / moles O = 2.17 mol / 2.17 mol = 1.00

Moles O / moles O = 4.35 mol / 2.17 mol = 2.00

The ratio is approximately N₁O₂.

We divide the subscripts by their greatest common divisor to obtain the simplest ratio, since we are looking for the empirical formula. The empirical formula is NO₂ since the greatest common divisor in this situation is 1.

The molecular formula of the compound is NO₂.

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The molarity is an important method which is used to determine the concentration of a solution. So the term molarity is also known as the concentration. Here the grams of Kr which occupies a volume of 42.6 mL is

The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. Its unit is mol L⁻¹ and it is essential to calculate the concentration of a binary solution.

Here M₁V₁ = M₂V₂

M₂ = M₁V₁ /  V₂

25.7 mL = 0.0257 L

42.6 mL = 0.0426 L

M₂ =  5.10 × 0.0257 / 0.0426  = 3.076 g

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Answer:

the answer is B:

Explanation:

I hope it help.

To measure reaction heat under isochoric conditions, a bomb calorimeter is needed.

This device is designed to maintain a constant volume (isochoric) during the reaction, allowing for accurate measurement of reaction heat. To improve the accuracy of the coffee cup calorimeter for measuring reaction heat under isobaric conditions, a modification that could be made is to use a stirring device to ensure uniform mixing of the reactants and to minimize heat loss to the surroundings.

Additionally, a lid with a small hole could be placed over the top of the calorimeter to prevent heat loss while still allowing for pressure equalization. These modifications would help to minimize errors in heat measurement and improve the accuracy of the results obtained.

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Answer:

A. It occurs when a gas passes through a tiny hole.

Explanation:

Edge2020

Have a great day y'all :)

Answer:

Liquid to gas.

Explanation:

Answer:

b

Explanation:

Water in to a gas or evaporation

Answer:

b) Li2S(aq)+Pb(NO3)2(aq)

e) K2S(aq)+Sn(NO3)4(aq)

Explanation:

they are the only two of the options that contain a sulfide ion (S) therefore they are the only ones that could be considered in the question.

b) Li2S(aq)+Pb(NO3)2(aq)

e) K2S(aq)+Sn(NO3)4(aq)

0.25 Molarity of lead nitrate aqueous solution is there when a solution of nacl is added slowly to  a solution of lead nitrate.

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Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Consumers are organisms which depend on the producers or autotrophs for their food and nutrition.

Consumers are also known as heterotrophs, and they feed on the producers (autotrophs or self-feeders or plants) and herbivores (animals that eat plants) for food and energy. They don't produce their own food.

There are four types of consumers:

1) Primary – Herbivores are known as primary consumers and their source of food is plants or the first trophic level of the food chain. Example, Rabbits, Butterflies, Zooplanktons, etc.

2) Secondary – these consumers eat both plants and herbivores and are therefore also known as omnivores. Example, Ants, Crabs, Rats, Humans, etc.

3) Tertiary – these consumers eat primary and secondary consumers. Thus, they can be omnivores as well as carnivores. Example, Hawks, Snakes, Lions, etc.

4) Quaternary – these consumers prey on the tertiary consumers. Example, Polar bear, Alligator, etc.

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From the given data, the name of the hydrated salt would be  \(CoCl_2.83H_2O\).

The formula of the hydrated salt can be determined using the empirical formula approach. That is, we will find the mole equivalent of the anhydrous salt and the water of hydration and then combine them into a single formula after dividing by the smallest mole.

First, we need to determine the mass of the anhydrous salt and the water of hydration.

Mass of crucible (x) = 12.090 g

Mass of hydrated salt + crucible (y) = 16.250 g

Thus, the mass of the hydrated salt can be determined by subtracting x from y.

Mass of hydrated salt = 16.250 - 12.090 = 4.16 g

Mass of hydrate + crucible after evaporating off the water (z) = 12.424 g

Mass of anhydrous salt = z - x

                                      = 12.424 - 12.090

                                      = 0.334 g

Mass of water = 4.16 - 0.334

                        = 3.826 g

Now, let's find the moles:

Molar mass of \(CoCl_2\) = 129.839 g/mol

Molar mass of water = 18.01 g/mol

Mole of \(CoCl_2\) = 0.334/129.839 = 0.00257 mol

Mole of water = 3.826/18.01 = 0.2124 mol

Dividing through by the smallest mole

\(CoCl_2\) =  0.00257 / 0.00257  = 1

water = 0.2124/ 0.00257 = 83

Thus, the formula of the hydrate would be \(CoCl_2.83H_2O\)

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The concentration of Oxalic Acid is 0.2625 M.

A kinetic experiment is conducted to determine the rate law of a reaction. The concentration of Oxalic Acid can be calculated using the given amount of the reactants and the volume of the test tube. A balanced chemical equation can be used to find the stoichiometric ratio of the reactants in the given reaction.The balanced chemical equation for the reaction is:5 H2C2O4 + 2 KMnO4 + 3 H2SO4 → 10 CO2 + 2 MnSO4 + 8 H2OThe stoichiometric ratio between Oxalic Acid and Potassium Permanganate is 5:2. The Oxalic Acid is the limiting reactant, and Potassium Permanganate is in excess.The amount of Oxalic Acid in the solution can be calculated using the formula:molarity = moles of solute / volume of solution in L.The moles of Oxalic Acid can be calculated using the formula:moles of H2C2O4 = Molarity of H2C2O4 x Volume of H2C2O4 in L= 0.525 M x 0.006 L= 0.00315 moles.

The volume of the solution after the addition of the reactants is:6.00 mL of 0.525 M Oxalic Acid + 4.00 mL of distilled water + 2.00 mL of 0.200 M KMnO4= 12.00 mLThe concentration of Oxalic Acid in the solution can be calculated using the formula:Molarity of H2C2O4 = moles of H2C2O4 / volume of solution in L= 0.00315 moles / 0.012 L= 0.2625 M.

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