Which sets of ordered pairs represent a function? Select all that apply.
A {(3,5), (4, -1), (2, -1), (2, 7), (-3, 6)}
B {(-3, 9), (-2, 4), (-1, 1), (0, 0), (1, 1)}
C {(1, 1), (4, 2), (9, 3), (16, 4), (25, 5)}
D {(9, -3), (4, -2), (1, -1), (0, 0), (1, 1)}

To calculate chi-square test, the exact steps and options may vary slightly depending on the specific model of the TI-83 calculator and its operating system

What is Chi-Square Test?

When the sample sizes are large, a chi-squared test is a statistical hypothesis test used in the study of contingency tables.

To put it another way, the main purpose of this test is to determine whether two category factors have independent effects on the test statistic.

It is frequently used to assess how well sampling data represents the entire population.

To calculate the chi-square test statistic on a TI-83 calculator, you can do the following:

Please note that the exact steps and options may vary slightly depending on the specific model of the TI-83 calculator and its operating system. It's always a good idea to refer to the calculator's manual or user manual for detailed instructions.

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For the given matrix A, the minors M13, M23, M33 are 8, -4, and 10 respectively. The cofactors C13, C23, C33 are 8, 4, and 10 respectively. The determinant det(A) is 68.

To find the minors of a matrix, we need to find the determinants of the submatrices obtained by removing the row and column corresponding to the element of interest. In this case, the minors M13, M23, and M33 correspond to the determinants of the 2x2 submatrices obtained by removing the first row and the third column, second row and third column, and third row and third column, respectively.

To find the cofactors, we multiply each minor by a positive or negative sign based on its position in the matrix. The signs alternate starting with a positive sign for the top left element. In this case, the cofactors C13, C23, and C33 correspond to the minors M13, M23, and M33 respectively.

Finally, the determinant of a 3x3 matrix can be found by using the formula det(A) = a11C11 + a12C12 + a13C13, where a11, a12, and a13 are the elements of the first row of the matrix and C11, C12, and C13 are their corresponding cofactors. In this case, the determinant det(A) is 68.

Therefore, the minors M13, M23, M33 are 8, -4, and 10 respectively. The cofactors C13, C23, C33 are 8, 4, and 10 respectively. And the determinant det(A) is 68.

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Answer:

240 seconds (4 minutes)

Step-by-step explanation:

find the lcm (least common multiple) which in this case is 240.

Answer:

a = -32

Step-by-step explanation:

-1/4a - 4 =4

Add 4 to each side

-1/4a - 4+4 =4+4

-1/4a = 8

Multiply each side by -4 to isolate a

-1/4 a * -4 = 8 *-4

a = -32

Answer:

A) 3w(w-7)

Step-by-step explanation:

\(\frac{w-5}{w-7} and \frac{w+8}{3w}\)

w-7 is a binomial, and 3w is a monomial. Because you cannot put one denominator into the other or multiply both denominators by a number when you have this type of difference where multiplying by a number won't get you the same result, you must multiply them each other.

Therefore:

3w(w-7) would be your LCD.

Answer:

Step-by-step explanation:

Fractions

We observe that the fractions can't be simplified any more and they are in the simplest form

Next, the denominators w - 7 and 3w don't have common factors

Therefore the common denominator is the product of denominators:

Correct option is A

Using the combination formula, it is found that 4845 combinations of four students are possible.

\(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by:

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

In this problem, four students are taken from a set of 20, hence the number of combinations is given by:

\(C_{20,4} = \frac{20!}{4!16!} = 4845\)

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Answer: $466.1

Step-by-step explanation:

100*(1.08)^20=

100*4.661=$466.1

Step-by-step explanation:

We know that divisor = (dividend)(quotient)+remainder.

So we can do (x^2 - x +8)(x+4)-5, which you can just expand out.

Answer:

$7.58/lb

Step-by-step explanation:

raw roast: $5.99 per lb

deli roast: $2.99 for 100g

We know the price per lb of the raw roast.

Let's find the price per lb of the deli roast.

1 lb = 454 grams

454 grams / 100 grams = 4.54

1 lb is 4.54 times 100 g

If we multiply the price of 100g of deli roast by 4.54, we get teh price per lb.

$2.99/lb * 4.54 = $13.57/lb

raw roast: $5.99/lb

deli roast: $13.57/lb

difference in price of 1 lb: $13.57 - $5.99 = $7.58

Answer: $7.58/lb

Answer:

.01669 $/g or $7.57 $/lb

Step-by-step explanation:

$2.99/100g = .0299 $/g

1 lb = 453.59237 g.

$5.99/453.59237 g= .0132$/g

The angle x in the diagram is 98 degrees.

When parallel lines are cut by a transversal line, angle relationships are formed such as corresponding angles, alternate interior angle, alternate exterior angles, vertically opposite angles, same side interior angles etc.

Therefore, let's find the angle of x using the angle relationships as follows:

The size of the angle x can be found as follows:

82 + x = 180(same side interior angles)

Same side interior angles are supplementary.

Hence,

82 + x = 180

x = 180 - 82

x = 98 degrees

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Answer:

62.8 in

Step-by-step explanation:

The circumference (C) of a circle is calculated as

C = πd ( d is diameter ) , then

C = π × 20 = 20π ≈ 62.8 inches ( to the nearest tenth )

With the help of the figure we can say that triangles are congruent by SAS Rule

What is Congruence of Triangle?

Triangle congruence: Two triangles are said to be congruent if all three of their corresponding sides are equal and all three of their corresponding angles are equal in size. These triangles can be moved, rotated, flipped, and turned to look exactly the same.

Solution:

By SAS rule, two triangles are said to be congruent if any two sides and the angle included between the sides of one triangle are comparable to the corresponding two sides and the angle included between the sides of the second triangle.

In given figure, sides AB= PQ, BC=QR and angle between AB and BC equal to angle between PQ and QR i.e. ∠B = ∠Q. Hence, Δ ABC ≅ Δ PQR.

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Answer:

D, X^2 -18 + 81 = -45 + 81

Step-by-step explanation:

it is complating squer method that used for solving x in a quadratic equetion . in this step you will add

(y/2)^2 if y is the cofitient of x .

Answer:

45 + 20 + 30 + 40 + 15 + 60 = 210 mm

Answer:

I am not certain if its right

Step-by-step explanation:

To find the rate of change of the demand (with respect to time) 5 years from now, we need to take the derivative of the demand function with respect to time, and then plug in the values for x and y given in the equations for their future values.

What Is Partial Derivative: Partial derivative is derivative over only 1 variable.First, let's take the partial derivatives of the demand function with respect to x and y:

∂D/∂x = -1/6(√x)
∂D/∂y = -7(0.2y - 10)^(1/2)

Now, let's plug in the values for x and y:

x = 67,200 + 300t
y = 137 + 11√t

So, we have:

∂D/∂t = (∂D/∂x)(∂x/∂t) + (∂D/∂y)(∂y/∂t)
∂D/∂t = (-1/6)(√(67,200 + 300t))(300) + (-7(0.2(137 + 11√t) - 10)^(1/2))(11/2t^(-1/2))
∂D/∂t = (-1/6)(√(67,200 + 300t))(300) + (-77(137 + 11√t - 500)^(1/2))(1/t^(1/2))

Now, we can plug in t = 5 and simplify:

∂D/∂t = (-1/6)(√(67,200 + 1500))(300) + (-77(137 + 11√5 - 500)^(1/2))(1/5^(1/2))
∂D/∂t = -280.94

Therefore, the rate of change of the demand (with respect to time) 5 years from now is approximately -280.94 cars per year.

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Answer:

The sale price of the sweater is $29.4

Step-by-step explanation:

OG Price: $42

Marked Down: 30%

42x0.30=12.6

42-12.6=29.4

The height of a cylinder with a 36-square-foot base and a 189-square-foot volume is 6.

The formula for the volume of a cylinder is given by V = \(\pi\)\(r^{2}\)h, where V is the volume, r is the radius of the base, and h is the height of the cylinder.

The area of the base of the cylinder is given by A = \(\pi\)\(r^{2}\), where A is the area of the base, r is the radius of the base.

We are given that the area of the base is 36, so we can write:

\(\pi\)\(r^{2}\)= 36

Solving for r, we get:

\(r^{2}\) = 36/\(\pi\)

r = \(\sqrt{36}/\pi\)

r ≈ 3.02

We are also given that the volume of the cylinder is 189, so we can write:

V = \(\pi\)\(r^{2}\)h = 189

\(\pi 3.02^{2} h\) = 189

h = 189 / \(\pi 3.02^{2}\)

h ≈ 6

Therefore, the height of the cylinder is approximately 6 units.

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Answer:

15

Step-by-step explanation:

you will add each set of number together:

13+0+14+36+18+9=90

Then you will take 90 and divide it by how many numbers are in the number set:

90÷6=15

Answer:

It's A I'm pretty sureeeeeee I have to type alot cause then I can't submit but ya A:)

Answer:

239 miles in 0.75 of an hour

Step-by-step explanation:

Answer:

B) 9

Step-by-step explanation:

f(2) means what is the value of y when x = 2.

Therefore, from inspection of the graph, when x = 2, y = 9

The ΔH (enthalpy change) for aluminum when it is heated from 0.0°C to 100.0°C is 2074.19 J.

The expression given for the temperature-dependent heat capacity of a substance is:

c_p = a + bT + cT^2

where c_p is the heat capacity in J/K, T is the temperature in °C, and a, b, and c are coefficients.

To calculate the ΔH (enthalpy change) for aluminum when it is heated from 0.0°C to 100.0°C, we need to integrate the heat capacity expression with respect to temperature over the given temperature range.

ΔH = ∫(c_p dT)

First, let's substitute the given coefficients into the expression:

c_p = 20.68 + (12.38×10^-3)T + 0

Next, we integrate the expression over the temperature range of 0.0°C to 100.0°C:

ΔH = ∫[20.68 + (12.38×10^-3)T] dT

Integrating with respect to T gives:

ΔH = 20.68T + (12.38×10^-3)(T^2/2)

To evaluate the integral, we substitute the upper and lower temperature limits:

ΔH = 20.68(100.0) + (12.38×10^-3)((100.0)^2/2) - [20.68(0.0) + (12.38×10^-3)((0.0)^2/2)]

Simplifying the equation gives:

ΔH = 2068 + 6.19

ΔH = 2074.19 J

Therefore, the enthalpy change (ΔH) for aluminum when it is heated from 0.0°C to 100.0°C is 2074.19 J.

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To know how many metric tons of water fell on the city, we'll solve the given questions step by step. In Part A, 2 cm^3 of water corresponds to 1 * 10^-4 metric tons. In Part B, 1 cm^3 of water corresponds to 1 metric ton.

In Part A, we are given that 2 cm^3 of water has a mass of 1 gram (10^-1 kg), and we need to determine the amount of water in metric tons. Since 1 metric ton is equal to 10^3 kg, we can convert the mass of water from grams to metric tons by dividing it by 10^3. Therefore, the amount of water that fell on the city is 1 * 10^-1 kg / 10^3 kg = 1 * 10^-4 metric tons.

Moving on to Part B, we are given that 1 cm^3 of water has a mass of 1 gram (10^3 kg). Similar to the previous calculation, we divide the mass of water by 10^3 to convert it to metric tons. Thus, the amount of water that fell on the city is 1 * 10^3 kg / 10^3 kg = 1 metric ton.

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Answer: 24

Step-by-step explanation:

The perimeter of the length of the rectangle is 24. The perimeter or circumference of the circle can be found using the equation C=2π(r), where r= the radius of the circle. Since we have two semi-circles we can find the circumference of one whole circle with a radius of 4, which would be 8π.

Answer:

Absolutely correct. you got the answer

Answer:

89 is the answer.

Step-by-step explanation:

Answer:

yr ans is 89.

hope it helps.

Answer:

the price has practically multiplied by 12 because if the ounce was 2 and now is 24 divide and get 12 hope this helps

Step-by-step explanation:

Whiskers climbed approximately 480 centimeters high up the tree.

We must divide the number of ladder steps climbed by the distance between each step in order to determine Whiskers' height up the tree.

It is stated that Josefina's father climbed 15 ladder steps, and the distance between each step is 32 centimeters.

We multiply the number of steps (15) by the 32 centimeters between each step to get the total height:

Absolute level = 15 stages * 32 centimeters/step

Computing the increase:

Whiskers' total height was 480 centimeters, so he climbed the tree about 480 centimeters.

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