Which sentence describes Newton's third law?

The maximum distance the train can travel is 26.47 miles. If the train starts from rest and must come to a complete stop in 15 minutes, it can travel a maximum distance of 138600 ft.

The maximum distance a train can travel is affected by several factors such as the initial velocity of the train, the time spent accelerating, the cruising speed, the time spent cruising, the time spent decelerating and the deceleration rate. Additionally, the train's engine power, fuel capacity, and the weight of the train also affect the maximum distance it can travel. In this case, the train starts from rest and has a constant acceleration of 10ft/s^2, a cruising speed of 105mi/h and a time of 15min before decelerating.

The maximum distance the train can travel if it accelerates from rest until it reaches its cruising speed and then runs at that speed for 15 minutes can be found using the kinematic equation:

d = 1/2 x a x t^2 + v x t

Given,

a = 10 ft/s^2 (acceleration)

v = 105 mi/h = 150 ft/s (cruising speed)

t = 15 minutes = 900 seconds

d = 1/2 * 10 ft/s^2 * 900 seconds^2 + 150 ft/s * 900 seconds

d = 40,500 ft

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Given:

Diameter, D = 10.0 m

Distance, x = 7.38 x 10¹⁰ m

Wavelength, λ = 633 nm

Let's find how far apart the closest objects it could possibly resolve.

First, apply the formula for the angle for angle separation (limit of resolution):

Thus, we have:

Now, to find the distance of the closest objects, we have:

Thus, we have:

Therefore, the distance of the closest objects is 5699.28 meters.

• ANSWER:

5699.28 m

Pulsars are thought to be a group of rapidly rotating neutron stars.

A neutron star is the dense remnant left behind after the collapse of a massive star during a supernova explosion. Neutron stars are incredibly compact and contain a high concentration of neutrons. They have masses typically around 1.4 times that of the Sun but are compressed into a sphere with a radius of only about 10 kilometers.

When a massive star undergoes a supernova explosion, the core collapses under gravity, causing the protons and electrons to merge and form neutrons. This collapse results in a highly dense neutron star with a strong gravitational field.

Pulsars, a type of neutron star, are characterized by their rapid rotation and the emission of beams of electromagnetic radiation that are observed as regular pulses of radiation. These pulses occur at precise intervals and are detectable across a range of wavelengths, from radio waves to X-rays.

The emission of radiation from pulsars is believed to be caused by two main factors:

1. Rotation: Pulsars rotate rapidly, often spinning hundreds of times per second. As the neutron star rotates, it emits beams of radiation from its magnetic poles. These beams are not aligned with the rotational axis, resulting in a lighthouse-like effect where the beams sweep across space. When the beams pass through Earth's line of sight, we detect them as regular pulses of radiation.

2. Magnetic Field: Pulsars possess extremely strong magnetic fields, typically billions of times stronger than Earth's magnetic field. This powerful magnetic field interacts with the charged particles surrounding the pulsar, causing them to emit radiation in the form of radio waves, X-rays, and gamma rays.

Accreting white dwarfs, black holes, and unstable high-mass stars are not typically associated with pulsars. Accreting white dwarfs are white dwarf stars that accrete material from a companion star, black holes are formed from the collapse of massive stars, and unstable high-mass stars are stars that undergo various stages of stellar evolution before potentially exploding as supernovae.

In summary, pulsars are believed to be rapidly rotating neutron stars with strong magnetic fields that emit beams of radiation as they rotate. Their distinct pulsing behavior makes them observable as regular pulses of electromagnetic radiation across different wavelengths.

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Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

\(a_c = \dfrac{v^2}{R}\)

Solving for v:

\(v = \sqrt{a_c R} = \sqrt{(250\;m/s^2)(0.50\;m)} = 5\sqrt{5}\;m/s \approx 11.18\;m/s\)

The yo-yo’s tangential speed 11.18 m/sec.

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

\(a_{c} = v^2/r\)

Solving for v

\(v = \sqrt{a_{c}r }\) = 11.18 m/sec

The yo-yo’s tangential speed 11.18 m/sec.

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The symbol "m" is used for both apparent magnitude and absolute magnitude, but they represent different quantities in different contexts.

The usual symbols used for the following properties of a star are:

- Brightness: Usually represented by the symbol "B" or "m". It refers to the amount of light received from a star as observed from a particular location.

- Luminosity: Represented by the symbol "L". It refers to the total amount of energy radiated by a star per unit of time.

- Apparent Magnitude: Represented by the symbol "m". It is a measure of the brightness of a star as observed from Earth. Lower values indicate brighter stars.

- Absolute Magnitude: Also represented by the symbol "m". It is the intrinsic brightness of a star, defined as the apparent magnitude a star would have if it were placed at a standard distance of 10 parsecs (32.6 light-years) from the observer.

- Temperature: Represented by the symbol "T". It refers to the surface temperature of a star, typically measured in Kelvin.

- Mass: Represented by the symbol "M". It is the amount of matter contained in a star, typically measured in solar masses (M☉).

Note: The symbol "m" is used for both apparent magnitude and absolute magnitude, but they represent different quantities in different contexts.

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Answer:

True, overtone occurs when two or more sounds are produced at the same time.

Answer:

This statement is true.

Explanation:

Answer:

artist

Explanation:

The value of Vgs required to obtain Rds = 200Ω in an NMOS transistor operated in the triode region with small Vds is approximately 0.9V.

To calculate the required Vgs, we can use the equation that relates Rds to the transistor parameters. In this case, we assume the electron mobility (μn), oxide capacitance per unit area (Cox), and the width-to-length ratio (W/L) of the transistor to be constant.

By rearranging the equation and substituting the given values, we find that Vgs - Vt is inversely proportional to Rds. Since we know the initial value of Vgs (1.5V) and Rds (1kΩ), we can calculate the new value of Vgs using the proportionality.

By solving the equation, we find that Vgs ≈ 0.9V is required to achieve Rds = 200Ω in the given NMOS transistor.

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Answer:

0.2m

Explanation:

F = 6 x 10^3N

k = 3 x 10^4 Nm-1

x = ?

from Hooke's law, F = kx

x = F/k = 6 x 10^3 ÷ 3 x 10^4 = 0.2m

Germanium is a metalloid. this means it has the same properties as a metal and a nonmetal.

In chemistry, a chemical element that forms a simple substance with properties in-between those of a conventional metal and a typical nonmetal is referred to as a metalloid.

The name is typically used to describe a collection of six to nine elements (boron, silicon, germanium, arsenic, antimony, tellurium, and maybe bismuth, polonium, and astatine) that can be found close to the main block of the periodic table, also known as the P-block.

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Answer:

the fusion of hydrogen nuclei or in other words "nuclear fusion"

Explanation:

Answer: 6,277,647m

Explanation:

Radius of Earth = 6400km

To calculate the gravitational acceleration of a planet, we use the following formula:

g = mG/r^2

Gravitational acceleration is equal to the mass of the planet multiplied by the gravitational constant all divided by the radius of the planet squared.

We already know what the gravitational acceleration will be, 2.45m/s^2.

So, 2.45m/s^2 = mG/r^2

the mass of the earth is equal to 5.9*10^24.

And the gravitational constant is equal to 6.67408 * 10^-11.

We don't know the radius though.

2.45m/s^2 = 5.9*10^24 * 6.67408 * 10^-11 divided by r^2

2.45m/s^2 = 3.93 * 10^14 divide by r^2

Now, we can cross-multiply.

2.45m/s^2 * r^2 = 3.93 * 10^14

divide r^2 from both sides.

r^2 = 3.93 * 10^14 divided by 2.45m/s^2

r^2 = 1.6*10^14.

Now, take the square root of both sides.

r = 12,677,647 meters from the center of the Earth.

To calculate the height from the surface of the Earth, we need to subtract r by the Earth's radius.

That will be 12,677,647-6.400.000m = 6,277,647m from the surface of Earth.

X-rays: They have Longer wavelengths than gamma rays, but shorter wavelengths and thus higher energy than UV radiation.

Electromagnetic radiation is made up of electromagnetic field waves that travel through space carrying momentum and electromagnetic radiant energy.

When an atom absorbs energy, it emits electromagnetic radiation. The absorbed energy causes one or more electrons within the atom to move. An electromagnetic wave is formed when the electron returns to its original position.

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Big has no cause of action against Temper. In this scenario, while Temper may have made a verbal threat and raised his fists in a confrontational manner, there is no indication that he physically touched or harmed Big.

Assault refers to the act of intentionally causing apprehension or fear of imminent harmful or offensive contact. Battery, on the other hand, involves the intentional and harmful or offensive physical contact with another person without their consent.

In this case, Temper's actions may constitute assault due to the verbal threat and raising his fists, creating an atmosphere of fear or apprehension. However, since no physical contact or harm occurred, battery is not applicable. Therefore, the appropriate response is option d: Big has no cause of action against Temper.

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The Q need to be to make the magnitude of the electric field 0.00264 meters away from the surface equal to 1.43 nC is 1.07 × 10⁻⁹ C.

The  magnitude of the electric field at the point near the charged surface is as :

E = Q / (4 × π × ε × A)

Q = E ( 4 × π × ε × A)

Where

E = 1.43 nC

ε = 8.85 x 10⁻¹² C²/N m²

A = 6.77 m²

Q = E ( 4 × π × ε × A)

Q  = 1.43 × 4 × 3.14 × 8.85 x 10⁻¹² × 6.77

Q = 1.07 × 10⁻⁹ C

Thus, the charge is  1.07 × 10⁻⁹ C.

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Prioritizing hydropower in Nepal can lead to increased energy security and a more sustainable future for the country.

Nepal, hydropower should be given more priority than fossil fuels for two main reasons:
1. Abundant Water Resources: Nepal is endowed with numerous rivers and streams, which makes it an ideal location for hydropower generation. Tapping into these water resources to produce electricity can greatly contribute to the country's energy needs, while reducing its dependence on imported fossil fuels.
2. Environmental Sustainability: Hydropower is a renewable and clean energy source, unlike fossil fuels, which emit harmful greenhouse gases when burned. By prioritizing hydropower, Nepal can reduce its carbon footprint and mitigate the impacts of climate change, while also preserving its natural resources for future generations.
In summary, prioritizing hydropower in Nepal can lead to increased energy security and a more sustainable future for the country.

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Answer:

La frecuencia cardíaca objetivo durante las actividades de intensidad moderada es aproximadamente del 50 al 70% de la frecuencia cardíaca máxima, mientras que durante la actividad física intensa es de, aproximadamente, entre el 70 y el 85% del valor máximo.

The resistance R at both ends of this resistor in a hollow cylinder of length L, is  \(R=\frac{p_1L}{\pi (b^{2} - a^{2}}\) . The correct answer is A.

Explanation of the calculation to find the resistance R of a hollow cylinder of length L:

To find the resistance R across both ends of this resistor, we can use the formula for the resistance of a cylinder:

\(R=\frac{pL}{A}\)

Where p is the resistivity of the material, L is the length of the cylinder, and A is the cross-sectional area of the cylinder.

In this case, the cross-sectional area of the cylinder is the area of the outer circle minus the area of the inner circle:

\(A=\pi b^{2}-\pi a^{2}=\pi (b^{2}-a^{2})\)

So the resistance R across both ends of this resistor is:

\(R=\frac{p_1L}{\pi (b^{2}-a^{2})}\)

In conclusion, the resistance R of the hollow cylinder is equal to the resistivity of the material multiplied by the length of the resistance and divided by the difference between the area of the outer and inner circles. The material resistivity of the hollow cylinder is equal to the material resistivity of the region a<r<b, which is p1, divided by the material resistivity of the region r<a, which is p2. Therefore, the resistance of the hollow cylinder is: \(R = (p1/p2)*L/[π(b^2 - a^2)]\)

Complete question:

A resistor is made from a hollow cylinder of length L, inner radius a, and outer radius b. The interior of the cylinder is filled with a different material. Let r be the distance from the axis of the cylinder. The region a<r<b is filled with material of transitivity p1. The region r<a is filled with material of resistivity p2.​ where p2=p 1/2. Find the resistance R across both ends of this resistor:

A)\(R=\frac{p_1L}{\pi (b^{2} - a^{2}}\)

B)\(R=\frac{p_1L}{\pi (b^{2} + a^{2}}\)

C)\(R=\frac{p_1L (b^{2}- a^{2}) }{2\pi (b^{2} - a^{2}}\)

D)\(R=\frac{p_1L (a^{2}- b^{2}) }{2\pi (b^{2} - a^{2}}\)

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The average force acting on the car as it comes to a stop is \(7.00 \times 10^5 N.\)

We can use the equation for average force, which is:

average force = change in momentum / time

To use this equation, we first need to find the change in momentum of the car. We can use the equation:

change in momentum = final momentum - initial momentum

The initial momentum of the car is:

p1 = m1 × v1

where m1 is the mass of the car (2000 kg) and v1 is the initial velocity (14 m/s).

p1 = (2000 kg)(14 m/s) = 28,000 kg × m/s

The final momentum of the car is zero, since it comes to a stop.

p2 = 0

So the change in momentum is:

Δp = p2 - p1 = -28,000 kg × m/s

Now we can substitute these values into the equation for average force:

average force = Δp / t

where t is the time it takes for the car to come to a stop\((4.00 \times 10^{-2} s).\)

average force =\((-28,000 kg\times m/s) / (4.00 \times 10^{-2} s)\)

average force =\(- 7.00 \times 10^5 N\)

The negative sign indicates that the force is acting in the opposite direction to the motion of the car. We could also take the magnitude of the force, which would be:

|average force| = \(7.00 \times 10^5 N\)

Therefore, the average force acting on the car as it comes to a stop is \(7.00 \times 10^5 N.\)

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Answer:

¢

Explanation:

Given that:

Mass of metal = 12g = 0.012

Density of metal = 4 g/cm³ = 4000kg/m³

Density of oil = 1.5g/cm³ = 1500 kg/m³

Recall : density = mass / volume

Volume of metal, V = mass / density = 0.012/ 4000 = 0.000003

0.000003

T + Density of oil * g * V - (0.012 * 9.8) = 0

T + 1500 * 9.8 * 0.000003 - 0.1176 = 0

T = 0.0441 - 0.1176 = 0

T = 0.1176 - 0.0441

T = 0.0735N

Tension, T

The automatic identification of materials is facilitated by spectroscopy.

Spectroscopy is the scientific technique used for analyzing the interaction between matter and electromagnetic radiation. It involves the measurement and interpretation of the spectrum of light or other forms of electromagnetic radiation emitted, absorbed, or scattered by a sample. By examining the unique patterns of wavelengths or frequencies in the spectrum, spectroscopy enables the identification and characterization of different materials.

Various spectroscopic techniques, such as infrared spectroscopy, ultraviolet-visible spectroscopy, and nuclear magnetic resonance spectroscopy, among others, are employed for material identification in fields like chemistry, physics, biology, and materials science.

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Option 2 is the correct answer. The Roche limit is reached when ring particles closest to a planet fall into its atmosphere.

The Roche limit is the minimum distance at which a celestial body, such as a moon or a ring system, can approach a planet before being disrupted by tidal forces. When a celestial body gets too close to a planet, the planet's tidal forces can overcome its gravitational pull, and the body may be torn apart by these forces.

Option 2 is the correct answer. The Roche limit is reached when ring particles closest to a planet fall into its atmosphere. This happens because the tidal forces from the planet become stronger than the gravitational forces holding the particles together, causing them to break apart and fall towards the planet. Once the particles are within the Roche limit, they will continue to break apart and eventually form a disk or ring around the planet.

The Roche limit is an important concept in planetary science, as it helps us understand the structure and behavior of planets, moons, and other celestial bodies. It can also help us explain the formation of planetary rings, such as those around Saturn and other gas giants in our solar system.

So, the right response is Choice 2. When ring particles closest to a planet enter its atmosphere, the Roche limit is achieved.

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The Planck equation and rules of direct proportions can be found that the amount of energy emitted by sodium the answer is;

              E = 2.2 10⁻¹³ J

Planck's equation establishes a relationship for the energy of photons

          E = h f

          c = λ f

          E = \(\frac{h \ c}{\lambda}\)

Where E is the energy, h the Planck constant (h = 6.63 10⁻³⁴ J s), f the frequency of radiation, c the speed of light and λ the wavelength

The energy emitted by each sodium atom is the energy of the emitted radiation that has a wavelength of 590 nm, two lines close together, indicate that each atom emits a photon, its energy is

             E₀ =  \(\frac{6.63 \ 10^{-34} \ 3 \ 10^8}{ 590 \ 10^{-9}}\)

             E₀ = 3.37 10⁻¹⁹ j

We look for the mass of a mole of sodium in the periodic table

             PM = 29.9897uma ( \(\frac{1.66 \ 10^{-17} kg}{1 una}\)) = 49.78 10⁻²⁷ kg

With a direct rule of proportions we can find the atoms of sodium in the lamp. If in mol of sodium it has a mass 49.78 10⁻²⁷ kg and has avogadro number 6.022 10²³ atoms. How many atoms are there in 45.8 10⁻⁹ kg

               # sodium atoms = \(\frac{49.78\ 10^{-27} \ 6.022 \ 10^{23}}{ 45.8 \ 10^{-9}}\)

               #_atom Sodium = 6.54 10⁵ Sodium atoms.

Let's use a direct ratio rule, If a sodium atom emits an energy Eo, how much energy do you emit? 6.54 105 atoms

              E = Eo  # _atmos / 1 atom

              E = 3.37 10⁻¹⁹ 6.54 10⁵

              E = 2.2 10⁻¹³ J

In conclusion, using the Planck equation and direct proportions rules we can find the amount of energy emitted by sodium, the answer is;

              E = 2.2 10⁻¹³ J

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Answer:

4 * 10^-8 mg = .4 * 10^-7 mg        divide and multiply by 10

5.0 x 10^-7mg + .4 x 10^-7 mg = 5.4 x 10^-7 mg

Also 5.4 x 10^-7 mg = 5.4E-7 mg

In the case of dry ice pucks sliding on an aluminum ramp, the pivot interaction occurs between the ramp and the puck. The forces involved include gravity, normal force, and a small frictional force due to the gas layer under the puck.

Pivot Interactions refer to the type of forces that act on objects that are pivoting around a fixed point. These forces cause the object to rotate around the pivot point. In the case of the dry ice pucks sliding on an aluminum ramp, the pivot interaction is between the ramp and the dry ice puck.As the puck slides down the ramp, it pivots around the point where it first touches the ramp. This point acts as the pivot point for the pivot interaction. The forces acting on the puck include the force of gravity, the normal force, and the force of friction.In this case, the force of friction is very small due to the thin layer of gas that is trapped under the puck. This gas layer is created by the sublimation of the dry ice caused by the warm aluminum. This gas layer reduces the sliding friction, allowing the puck to slide with almost no friction.The normal force is the force exerted by the ramp on the puck, perpendicular to the surface of the ramp. This force is equal and opposite to the force of gravity, which is the force that pulls the puck downwards. The normal force acts as the pivot force, causing the puck to rotate around the point where it first touches the ramp.

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Answer:

Sorry I need points \( \boxed{}\)

Answer:

The centripetal acceleration, \(a_c = 1280 m/s^2\)

Explanation:

Centripetal acceleration is given by the formula:

\(a_c = \frac{v^2}{r}\)

Where the speed of the ball, v = 16 m/s

Length of the string, r = 0.2 m

Substituting these parameters into the centripetal equation above:

\(a_c = \frac{16^2}{0.2}\\a_c = \frac{256}{0.2}\\a_c = 1280 m/s^2\)

Answer:

B

Explanation:

Got it right

Answer:

B. X: Releases energy to the photosphere

Y: Takes longer for photons to move through

Explanation:

Right on ED2021, goodluck!

The mass of the object is obtained as 130 g.

The triple beam balance is the kind of balance that could be used to measure the mass of a substance. There are so many kinds of balance that could be used in science and these include;

1) beam balance

2) Spring balance
3) unequal arm balance

We read the mass of the object by looking at all the points that we have set on the triple beam balance to achieve the balance point. In the case of the substances that we have seen in the image of the question, the mass of the object is obtained as 130 g.

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