The sample that is most likely to undergo the smallest change in temperature upon the absorption of 100 kJ of heat is 15 g lead. The correct answer is B.
The specific heat capacity of a substance is a measure of how much energy is required to raise the temperature of a unit mass of that substance by one degree Celsius. Since water has a much higher specific heat capacity than lead, it requires more energy to raise the temperature of the same amount of water than the same amount of lead.
Therefore, the 50 g sample of lead is most likely to undergo the smallest change in temperature upon the absorption of 100 kJ of heat, as compared to the other options.
This is because the heat energy absorbed will be spread over a larger mass of lead, and since lead has a lower specific heat capacity than water, the temperature change will be smaller. On the other hand, the 15 g sample of water is most likely to undergo the largest change in temperature since water has a high specific heat capacity.
Therefore, option (b) is the correct answer.
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You push on 35 N object for 3 seconds. Find work.
a running person has a what you need. Mass of 60kg and a speed of 3.16m/s what is her kinetic energy?
Answer:
\(\boxed {\boxed {\sf 299.568 \ Joules }}\)
Explanation:
Kinetic energy can be found using the following formula:
\(E_k=\frac{1}{2}mv^2\)
where m is the mass and v is the velocity.
The mass of the person is 60 kilograms and the velocity is 3.16 meters per second
\(m= 60 \ kg \\v= 3.16 \ m/s\)
Substitute the values into the formula.
\(E_k=\frac{1}{2} (60 \ kg) *(3.16 \ m/s)^2\)
First, evaluate the exponent.
(3.16 m/s)²= (3.16 m/s) * (3.16 m/s) = 9.9856 m²/s²\(E_k=\frac{1}{2}(60 \ kg ) (9.9856 \ m^2/s^2)\)
Multiply 60 kg by 9.9856 m²/s²
\(E_k=\frac{1}{2} (599.136 \ kg*m^2/s^2)\)
Multiply 599.136 kg*m²/s² by 1/2, or divide by 2.
\(E_k=299.568 \ kg*m^2/s^2\)
1 kg*m²/s² is equal to 1 Joule Therefore, our answer of 299.568 kg*m²/s² is equal to 299.568 Joules.\(E_k= 299.568 \ J\)
The running person has a kinetic energy of 299.568 Joules.
Solution:
We know that, Kinetic energy(kE)= 1/2×m×v^2
By applying formula,we get
Or,KE=1/2×60×3.16^2
Or,kE=299.57j
So,her kinetic energy is 2999.5j
Write a sentence on how these words are used in real life situations
1. Frame of Reference
2. Displacement
3. Average Velocity
4. Instantaneous Velocity
Answer:
they can all be used on motor vehicles or transpostation
Explanation:
Design two separate oscillators of 97 kHz with NE555, crystal
oscillator and 79 MHz.
To design separate oscillators of 97 kHz and 79 MHz using the NE555 timer and a crystal oscillator.
Follow the steps below:
Designing an oscillator with the NE555 timer for a frequency of 97 kHz:
1. Connect pins 1 (Ground) and 8 (Vcc) of the NE555 to the appropriate power supply.
2. Connect pin 4 (Reset) to Vcc to disable the reset function.
3. Connect pin 5 (Control Voltage) to Ground.
4. Connect a resistor (R1) and a capacitor (C1) in series between pins 6 (Threshold) and 7 (Discharge). Choose values for R1 and C1 to set the desired time constant.
5. Connect pin 2 (Trigger) to the junction of R1 and C1.
6. Connect pin 3 (Output) to an appropriate load or circuit.
7. Provide necessary decoupling capacitors and stabilize the power supply.
8. Adjust the values of R1 and C1 to achieve the desired frequency of 97 kHz.
Designing an oscillator with a crystal oscillator for a frequency of 79 MHz:
1. Choose a crystal oscillator with a resonant frequency of 79 MHz.
2. Connect the crystal oscillator component to the appropriate pins of a suitable oscillator circuit or microcontroller.
3. Provide necessary decoupling capacitors and stabilize the power supply.
4. Configure the oscillator circuit or microcontroller to use the crystal oscillator component as the clock source.
5. Program or adjust the oscillator circuit or microcontroller to generate an output signal with a frequency of 79 MHz.
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can be ignored, what will be the maximum height that the pendulum can
reach - that is, what is the height at point B? (Recall that g = 9.8 m/s²)
B
A
4
SUBMIT
15 m
O A. 30 m
OB. 20 m
OC. 45 m
OD. 25 m
The height at point B will be 30 m. Option D is corect.
What is simple harmonic motion?Simple harmonic motion is a form of periodic motion in which the restoring force on a moving item is proportionate to the amount of the object's displacement.
At the highest point the kinetic energy is equal to the potential energy on the maximum height h;
\(\rm mgh = \frac{1}{2} mv^2 \\\\ 2gh=v^2 \\\\\ h= \frac{v^2}{2g} \\\\\ h=\frac{14^2}{2 \times 9.81}\\\\\ h= 9.9 \ m\)
The height at point B is calculated by adding the initial height to the obtained height as;
\(\rm h_B = 15+9.9 \\\\ h_B = 29.9 \ m \\\\ h_B=30 \ m\)
The height at point B will be 30 m.
Hence, option D is corect.
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te. the electrons are emitted from the cathode with zero velocity, one velocity, or a range of velocities? explain.
When electrons are emitted from the cathode, they can have zero velocity, one velocity, or a range of velocities depending on the conditions under which they are emitted.
For example, in a vacuum tube, electrons are emitted from the cathode due to thermionic emission and they typically have a range of velocities.
However, in a photoelectric effect experiment, electrons are emitted from the cathode due to the absorption of photons and they typically have a well-defined velocity determined by the energy of the incident photons.
Similarly, in a field emission experiment, electrons are emitted from the cathode due to a high electric field and they typically have a high velocity.
Therefore, the velocity of the electrons emitted from the cathode depends on the mechanism of emission and the conditions under which they are emitted.
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I wanna learn more English
Answer:
then read some more about it and learn it make that your career and study it
Explanation:
Answer:
Use Awabe language learning app or you can buy some books to learn english learn tenses verbs etc or you can talk to me sometimes to learn cuz I'm very excellent in English
A 1250 kg truck is moving down the highway with a velocity of 2. 0 m/s crashes head-on with another car with a mass of 875 kg and a velocity of 6. 0 m/s. After the collision, the two vehicles bounce off each other and the truck has a new velocity of 1. 0m/s. What is the new velocity of the car?
Together, the two cars are traveling at a speed of 29.11 m/s.
As a result,
The car's mass is 1 m = 1250 kg.
Initially, the car's speed was 1, u = 32 m/s.
Car 2 mass, m' = 875 kg
The starting speed of vehicle 2 is 25 m/s.
both vehicles stick together. An inelastic collision is a situation here. The pace is maintained. Let V be the combined speed of the two vehicles.
Using conV = 29.11 m/s, it is determined.
Thus, the combined speed of the two cars is 29.11 m/s. Therefore, this is the necessary solution. momentum preservation as:
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A hiker travels 12 km in a direction of 50 degrees west of north. What are the north and west components of this displacement?
The north and west components of this displacement are 9.19 km and -7.71 km respectively.
North component of the displacement
The north component of the displacement is calculated as follows;
Dy = D sinθ
Dy = 12 km x sin50
Dy = 9.19 km
West component of the displacementDx = D x cosθ
Dx = - 12 km x cos(50)
Dx = -7.71 km
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1. Write the goal of the lab or the question you tried to answer.
Answer:
Type your answer here.
Lab report density and buoyancy
The goal of the lab is to investigate the relationship between density and buoyancy. The lab aims to determine how different objects or substances behave in fluids and understand the principles of density and buoyancy through experimental observations and calculations.
The goal of the lab or the question being addressed in the lab report is to investigate and understand the concepts of density and buoyancy. Density refers to the measure of how much mass is contained within a given volume, while buoyancy refers to the upward force exerted on an object submerged in a fluid, such as water or air.
The lab report aims to explore the relationship between density, mass, and volume by conducting experiments and analyzing data. It may involve measurements of different objects or substances, determining their masses and volumes, and calculating their densities. The report may also involve experiments related to buoyancy, such as determining the buoyant force on an object and investigating factors affecting buoyancy.
By conducting the lab and analyzing the obtained results, the lab report aims to provide a deeper understanding of these fundamental concepts in physics and to demonstrate the principles of density and buoyancy through practical experimentation. The report may also include discussions of the significance and applications of density and buoyancy in various fields, such as engineering, architecture, and fluid dynamics.
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how light is channelled down an optical fibre
Explanation:
Suppose you want to shine a flashlight beam down a long, straight hallway. Just point the beam straight down the hallway -- light travels in straight lines, so it is no problem. What if the hallway has a bend in it? You could place a mirror at the bend to reflect the light beam around the corner. What if the hallway is very winding with multiple bends? You might line the walls with mirrors and angle the beam so that it bounces from side-to-side all along the hallway. This is exactly what happens in an optical fiber.
The light in a fiber-optic cable travels through the core (hallway) by constantly bouncing from the cladding (mirror-lined walls), a principle called total internal reflection. Because the cladding does not absorb any light from the core, the light wave can travel great distances.
However, some of the light signal degrades within the fiber, mostly due to impurities in the glass. The extent that the signal degrades depends on the purity of the glass and the wavelength of the transmitted light (for example, 850 nm = 60 to 75 percent/km; 1,300 nm = 50 to 60 percent/km; 1,550 nm is greater than 50 percent/km). Some premium optical fibers show much less signal degradation -- less than 10 percent/km at 1,550 nm.
1
in which state is it possible for the sun to be directly overhead at local noon?
the sun can be directly overhead at local noon in states located between the Tropic of Cancer and the Tropic of Capricorn. as the angle of the sun's rays will always be at an angle.
The equator is an imaginary line that circles the Earth at 0 degrees latitude. States that are near the equator, such as Ecuador, Colombia, Brazil, Kenya, and Indonesia, experience the sun being directly overhead at local noon twice a year, during the equinoxes.
This is because the Earth's axis is tilted at an angle of about 23.5 degrees, which causes the sun's angle to change throughout the year as the Earth orbits around it. States that are farther away from the equator will not experience the sun being directly overhead at local noon, as the angle of the sun's rays will always be at an angle.
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If force F, volume V and density D are taken as fundamental quantities, then the representation of pressure P will be
Using the principle of dimensional analysis, the representation of Pressure would be \( P = F^{1}V^{-\frac{2}{3}}D^{0}\)
Pressure is related to Force, Volume and Density thus :
\( Pressure, P = F^{a}V^{b}D^{c}\)
Using dimensional analysis :
Pressure, P = ML¯¹T¯²Substituting the dimension into the relation :
\( ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} \)
\( ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} \)
Equating the power ;
a + c = 1 - - - (1)
a + 3b - 3c = - 1 - - - (2)
-2a = - 2
a = - 2/-2
a = 1
From (1)
1 + c = 1
c = 1 - 1 = 0
c = 0
From (2) :
1 + 3b - 3(0) = - 1
1 + 3b = - 1
3b = - 2
b = - 2/3
Hence, \( P = F^{1}V^{-\frac{2}{3}}D^{0}\)
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The representation of pressure is:
\(P=FV^{-\frac{2}{3} }\)
Given that:
Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:
\(P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}\)
Hence:-
2 = -2a
a = 1
a + c = 1
1 + c = 1
c = 0
a + 3b - 3c = -1
1 + 3b - 3(0) = -1
3b = -2b = -2/3
Hence the representation of pressure is:
\(P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }\)
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A bullet of mass 50 g travelling with a speed of 15ms penetrates into a
bag of sand and is uniformly brought to rest in 0.05s.
Find
(a) How for the bullet will penetrate into the bag of sand?
(b) The Average force exerted by the sand ?
Answer:
a) The bullet will penetrate 0.375 meters into the bag of sand.
b) The average force exerted by the sand is 15 newtons.
Explanation:
The statement is incorrectly written. The correct form is presented below:
A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.
a) How far the bullet will penetrate into the bag of sand?
b) The average force exerted by the sand?
b) The average force exerted by the sand on the bullet (\(F\)), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:
\(F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}\) (1)
Where:
\(m\) - Mass of the bullet, measured in kilograms.
\(v_{o}\), \(v_{f}\) - Initial and final speeds of the bullet, measured in meter per second.
\(\Delta t\) - Impact time, measured in seconds.
If we know that \(m = 0.05\,kg\), \(v_{o} = 15\,\frac{m}{s}\), \(v_{f} = 0\,\frac{m}{s}\) and \(\Delta t = 0.05\,s\), then the average force exerted by the sand is:
\(F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}\)
\(F = -15\,N\)
The average force exerted by the sand is 15 newtons.
a) The distance travelled by the bullet (\(\Delta s\)), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:
\(\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }\) (2)
If we know that \(m = 0.05\,kg\), \(v_{o} = 15\,\frac{m}{s}\), \(v_{f} = 0\,\frac{m}{s}\) and \(F = -15\,N\), then the distance travelled by the bullet is:
\(\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}\)
\(\Delta s = 0.375\,m\)
The bullet will penetrate 0.375 meters into the bag of sand.
Particles q1, 92, and q3 are in a straight line.
Particles q1 = -28.1 uc, q2 = +25.5 uc, and
q3 = -47.9 uc. Particles q1 and q2 are separated
by 0.300 m. Particles q2 and q3 are separated by
0.300 m. What is the net force on q3?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-28.1 μC:
+25.5 °C
-47.9 uc
The particle when placed nearby at a distance, the force acting between the charges will be towards each other. The net force on q₃ is 88.496 N.
What is the electrostatic force?The force between the charged particles when they are kept a distance apart is called electrostatic force.
Referring to the figure, Particles q₁ = -28.1 μC = -28.1 x 10⁻⁶, q₂ = +25.5 μC =+25.5 x 10⁻⁶, and q₃ = -47.9 μc =-47.9 x 10⁻⁶ C kept at distance r = 0.3 m
Net force on q₃ , F₃ = F₁₃ - F₃₂
F₃ = k q₁q₃ / (0.3 +0.3)² + k q₂q₃ / (0.3 )²
where k = 9 x 10⁹ N.m²/C²
Substitute the values into the equation, we get the net force.
F₃ = 88.496 N
Therefore, the net force on q₃ is 88.496 N.
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Answer:
-88.496
Explanation:
acellus
Which property determines and Adams ability to attract electrons shared in a chemical bond?
Answer:
Electronegativity
Explanation:
Answer:
The property that determines an atom;s ability to attract electrons shared in a chemical bond is electronegativity.
Explanation:
Hope you have a great day :)
Jibari walks 40. 0 meters east in 120. 0 seconds. He then walks 30. 0 meters west in 60. 0 seconds. What is his average velocity for the trip??
Answer:
0.389 meters per second
Explanation:
1. Get your knowns
a. 40 meters per 120 seconds
b. 30 meters per 60 seconds
2. Add
Total distance = 40 meters + 30 meters = 70 meters
Total time = 120 seconds + 60 seconds = 180 seconds
3. Divide
Average velocity = 70 meters / 180 seconds
= 7 meters / 18 seconds
= 0.388... meters per second
Becky has a shower and uses 20,000g of water with a specific heat capacity of 4200J/KG. When the water is supplied with 336,000J of energy, it heats up to 50^c. What is the startig temperature of the water?
Answer:
46°C
Explanation:
q = mCΔT
336,000 J = (20 kg) (4200 J/kg/°C) (50°C − T)
T = 46°C
Becky takes a shower, and he uses 20,000 g of water with specific heat of 4200 J/kg then the starting temperature of the water will be equal to 46 °C.
What is Specific heat?Specific heat is the amount of energy needed to raise a product's temperature by one degree Celsius per gram. Traditionally, the units of heat capacity are calorie or joules per gram per degree Celsius. The specific heat of water, for instance, is 1 calorie (or 4.186 joules) per gram per degree Celsius.
In the 18th century, the Scottish scientist Joseph Black noted that equivalent masses of various substances required varying quantities of heat to increase them across the same ambient temperature. Based on this discovery, he developed the theory of specific heat.
From the given data in the question,
q = mCΔT
Here ΔT is the change in the temperature.
336,000 J = (20 kg) × (4200) × (50 °C − T)
T = 46 °C
Therefore, the starting temperature of the water is 46 °C.
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what is the scientific name of humans
A sound wave is traveling in air at 343 m/a and the wavelength is 320 nm what is the frequency?
The frequency of the sound wave is 1.07 × 10⁹ Hertz
What is the frequency of the sound wave?Wavelength is simply the distance over which the shapes of waves are repeated.
From the wavelength, frequency and speed relation,
λ = v ÷ f
Where λ is wavelength, v is velocity/speed and f is frequency.
Given that:
Speed of the wave v = 343 m/sWavelength of the wave λ = 320 nm = 3.2 × 10⁻⁷ mFrequency of sound wave = ?Plug values into the above formula.
λ = v ÷ f
f = v / λ
f = ( 343 m/s ) / ( 3.2 × 10⁻⁷ m )
f = 1.07 × 10⁹ Hz
Therefore, the frequency is 1.07 × 10⁹ Hz.
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cuál es la diferencia entre ciencia y tecnología
¿Cuál es la diferencia entre ciencia y tecnología?
La ciencia se refiere al proceso de explorar nuevos conocimientos metódicamente a través de la observación y los experimentos.
La tecnología se refiere al proceso de aplicar el conocimiento científico en aplicaciones prácticas para varios propósitos.
What is the difference between science and technology?
Science refers to the process of exploring new knowledge methodically through observation and experiments.
Technology refers to the process of applying scientific knowledge in practical applications for various purposes.
Imagine you inherit a farm and now have to purchase fertilizer for the farm. The farm is 340 acres and had corn planted the previous year. You must add fertilizer to the soil before you plant this year's crop. You go to the local fertilizer store and find SuperPhosphate-brand fertilizer. You read the fertilizer bag and can recognize from your high school chemistry class a molecular formula C*a_{3}*P_{2}*H_{14}*S_{2}*O_{21} (you don't understand anything else written on the bag because it is imported fertilizer from Japan). You must decide how much fertilizer to buy for application to your cornfields. If each bag contains 25 kg of fertilizer and costs $54.73, how many bags of fertilizer must you purchase, and how much will it cost you to add the necessary fertilizer to your fields ?
Total Cost is = $107,380 if The farm is 340 acres and had corn planted add fertilizer to the soil before you plant this years' crop.
What is called fertilizer?A fertiliser is a natural or artificial substance containing chemical elements (such as Nitrogen (N), Phosphorus (P) and Potassium (K)) that improve growth and productiveness of plants. Some synonyms include the terms "enrichment" or "plant nutrient".
Why is fertilizer important?Without fertilizers, nature struggles to replenish the nutrients in the soil. When crops are harvested, important nutrients are removed from the soil, because they follow the crop and end up at the dinner table. If the soil is not replenished with nutrients through fertilizing, crop yields will deteriorate over time.
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A secant-secant angle intercepts arcs that are 3/5 and 3/8 of the circle. if a chord-chord angle and its vertical angle intercept the same arc, what is the measure of the chord-chord angle?
The measure of the chord-chord angle is 175.5.
What is a chord in a circle?A circle's chord is the line segment that connects any two locations on the circle's circumference. It should be remembered that a circle's diameter is defined as the lengthiest chord that runs across the center of the circle.
What is an angle in math?An angle is a figure created by two rays or lines that have the same termination in plane geometry. The Latin word "angulus," which meaning "corner," is where the term "angle" originates. The common terminal of the two rays—known as the vertex—is referred to as an angle's sides.
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For every force there is one that is ___________ in size but ______________ in direction.
Answer:
» equal , oppositeExplanation:
For every force there is one that is equal
in size but opposite in direction.
because , Newton's Third law states thatFor every force, there is another force of equal magnitude, acting in the opposite direction.
If we increase the distance traveled over the same period of time, this will (2 points)
decrease the speed
increase the speed
decrease the velocity
not affect speed or velocity
A telescope mirror is part of a sphere with a radius of 3 m. what is the focal length of the mirror?
The focal length of the mirror will be 0.33 m
Focus is defined as the point through which the reflected light rays pass (or appear to pass) when incident light rays are parallel to the principal axis. It is located at the midpoint of pole and center of curvature. The distance between the pole and the focus of the mirror is called the focal length of the mirror.
F =2R or focal length of a mirror is half of its radius of curvature.
The radius of curvature of convex or concave mirror is equal to two times of the focal length of convex or concave mirror. The radius of curvature is the radius of sphere formed by the convex or concave mirror. It is also equal to the distance between the pole and center of curvature.
F = 1/R
R = 3 m (given )
F = 1 / 3 = 0.33 m
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an electron travels at a speed of 8.60 x 10^7 m/s. what is its total energy
The total energy of an electron traveling at a speed of 8.60 x 10^7 m/s is (3.68 x 10^-15) J.
The total energy of an electron can be calculated by the formula E=0.5mv², where E is the total energy, m is the mass of the electron and v is the velocity of the electron. We know that the speed of the electron is 8.60 x 10^7 m/s. The mass of an electron is 9.109 x 10^-31 kg.Using the formula, we can calculate the total energy as follows:E = 0.5 x (9.109 x 10^-31 kg) x (8.60 x 10^7 m/s)²E = 3.68 x 10^-15 JTherefore, the total energy of an electron traveling at a speed of 8.60 x 10^7 m/s is (3.68 x 10^-15) J. The total energy is dependent on the velocity of the electron and the mass of the electron.
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What are 3 main ways to improve the Cardiovascular system???
Worth 100 points
A hydraulic lift is used to raise an automobile of mass 1520 kg. The radius of the shaft of the lift is 8.00 cm and that of the piston is 1.00 cm. How much force must be applied to the piston to raise the automobile?
To raise the automobile with a hydraulic lift, a force of approximately 19,000 N must be applied to the piston.
In a hydraulic lift, the principle of Pascal's law is applied, which states that pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and the walls of its container. By utilizing this principle, a smaller force applied to a smaller piston can generate a larger force on a larger piston.
In this scenario, the force needed to lift the automobile can be calculated using the formula:
\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)
where \(F_{1}\) is the force applied to the piston, \(A_{1}\) is the area of the piston, \(F_{2}\) is the force generated on the larger piston (required to lift the automobile), and \(A_{2}\) is the area of the larger piston.
Given the radius of the shaft (small piston) as 0.08 m and the radius of the piston as 0.01 m, we can calculate the forces applied and generated as follows:
\(A_{1} = \pi (0.08)^2\\A_{2}= \pi (0.01)^2\)
\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)
Simplifying the equation and substituting the values, we can solve for \(F_{2}\):
\(F_{2}=\frac{F_{1}A_{2}}{A_{1}}\)
Plugging in the values, we find:
\(F_{2}=\frac{F_{1} \pi (0.01)^2 }{ \pi (0.08)^2} \\F_{2}= \frac{F_{1}\times 0.0001}{0.0064} \\F_{2}= 0.015625 \times F_{1}\)
Given that the mass of the automobile is 1520 kg and the acceleration due to gravity is \(9.8 \hspace m/s^{2}\), we can equate \(F_{2}\) to the weight of the automobile:
\(F_{2}= mg\\0.015625\times F_{1}= 1520\times 9.8\)
Solving for \(F_{1}\), we find:
\(F_{1}\approx \frac{1520\times 9.8}{0.015624} \\F_{1} \approx 19072 \hspace N\)
Therefore, a force of approximately 19,000 N must be applied to the piston in order to raise the automobile using the hydraulic lift.
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Help me please, it's for physics and I really need help.
Answer:
4. y = 2.38333t - 26.55 is the answer.