The relationship between the number of homework assignments completed and the grade of the exam could potentially have a causal relationship. However, it is important to note that correlation does not always imply causation.
In this scenario, a positive correlation between the number of homework assignments completed and the grade of the exam suggests that as the number of completed assignments increases, the exam grade also tends to increase. This relationship could be casual if completing more homework assignments directly leads to better exam preparation and understanding of the material.
However, other factors such as studying habits, individual effort, and external factors could also influence exam grades. Therefore, while a positive correlation suggests a potential causal relationship, it is necessary to consider other variables and conduct further research or analysis to establish a definitive causal connection between completing homework assignments and exam grades.
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An object is sighted from a helicopter at an angle of
depression of 58°. After the helicopter has traveled 7.0
km, the angle of depression to the same side of the object.
is 64°. Determine the distance at that point from the
helicopter to the object.
(THIS IS TRIG)
The distance at that point from the helicopter to the object is 7km
How to determine the valueTo determine the value, we need to know the different trigonometric identities.
These identities are listed thus;
sinecosinetangentcotangentsecantcosecantFrom the information given, we have that the;
The angle at the point of the object is expressed as;
180 - (64 + 58)
add the values, we have;
180 - (122)
Now, subtract the values, we get;
58 degrees
Since, the angle measure is equal , then, we have that;
The distance = 7km
Hence, the distance is 7km
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50;41 The change is increase or decrease?by ? %
50 to 41
\(\begin{gathered} percent\text{ change = }\frac{new\text{ - old}}{|\text{old}|}\times100 \\ \text{percent change = }\frac{41-50}{|50|}\times100=-\frac{9}{50}\times100=-18 \\ \end{gathered}\)this is
decrease in 18 %
answer: decrease by 18%
Which sum is equal to 3 1/4+1 2/5?
Answer:
\(\huge\boxed{\bf\: \frac{93}{20}=4.65}\)
Step-by-step explanation:
\(3 \frac { 1 } { 4 } + 1 \frac { 2 } { 5 }\)
Now,
\(3 \frac { 1 } { 4 } \\= \frac{4 * 3+1}{4}\\= \frac{13}{4}\)
Then,
\(1 \frac { 2 } { 5 }\\= \frac{1* 5+2}{5} \\= \frac{7}{5}\)
So,
\(3 \frac { 1 } { 4 } + 1 \frac { 2 } { 5 }\\= \frac{13}{4}+\frac{7}{5}\\ \\\mathrm{LCM = 20}\\\\= \frac{65}{20}+\frac{28}{20} \\=\boxed{\bf\: \frac{93}{20}=4.65}\)
\(\rule{150pt}{2pt}\)
Determine whether or not the function f(x)=5⋅3x+3 is continuous everywhere. If it is continuous everywhere it is defined, enter the domain on which it is continuous in interval notation. To enter [infinity], type infinity. To enter ∪, type U.If it is discontinuous, state where it is discontinuous. Enter your answer as a list of numbers separated by semicolons (e.g. 2;4;6). The order of the list does not matter.
The function f(x) = \(5(3)^x+3\) is continuous everywhere on its domain, which is (-∞, ∞).
The function f(x) = \(5(3)^x+3\) is continuous everywhere because it is an exponential function with a base of 3, which is a positive number. Exponential functions with positive bases are continuous over their entire domain.
To see why, consider the definition of continuity: a function f(x) is continuous at a point x = c if the limit of f(x) as x approaches c exists and is equal to f(c). For an exponential function with a positive base, as x approaches c, the function values either increase to infinity or decrease to 0, depending on whether the exponent is positive or negative, respectively. In either case, the limit exists and is equal to the function value at c, so the function is continuous at c. Since this holds for all points in the domain, the function is continuous everywhere it is defined.
The domain of f(x) is all real numbers, so the function is continuous on the interval (-infinity, infinity), or in interval notation, the domain is (-∞, ∞).
In summary, the function f(x) = 5(3)ˣ +3 is continuous everywhere on its domain, which is (-∞, ∞).
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Mirando asked Jimmy, "Do you have a college degree?"
Is this a statistical question?
Choose 1 answer:
Answer: No, it’s not a statistical question
Step-by-step explanation:this question only pertains to one person and it not something that can be represented as a statistic.
Find the square root of the following decimal numbers.
(b) 0.0016
The square root of the decimal number is √0.0016 = 0.04
How to find the square root of the decimal number?Here we can find the square root of the decimal number:
N = 0.0016
Notice that we can write this number as:
0.0016 = 16*10⁻⁴
Now we can take the square root of that, so we will get:
√(16*10⁻⁴)
We can distribute the square root to get:
√16*√10⁻⁴
These two are easy, we will get:
√16*√10⁻⁴ = 4*10⁻² = 0.04
That is the square root.
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Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.
Answer:
Option B is the correct answer.What is -1/3 x 15 I really need help
negative five (-5) is the answer
Suppose the population of a city is currently 40,000 . If the city's population is increasing at a rate of 2.4% per year, what will the population be 5 years from now? Round your answer to the nearest person.
The population of the city will be approximately 44,968 people five years from now.
To calculate the population five years from now, we need to determine the population growth over that period. The city's population is increasing at a rate of 2.4% per year, which means the population is growing by 2.4% of its current value each year.
First, let's find the population growth for one year:
Population growth for one year = 2.4% of 40,000 = 0.024 * 40,000 = 960 people
Next, we can calculate the population after five years:
Population after five years = 40,000 + (Population growth for one year * 5)
= 40,000 + (960 * 5)
= 40,000 + 4,800
= 44,800
Rounding the population to the nearest person, the estimated population five years from now is approximately 44,968 people.
Note that the population growth calculation assumes a steady growth rate of 2.4% per year. In reality, population growth can be affected by various factors and may not follow a precise exponential pattern.
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The graph of a linear function passes through the points (-1, -1/4) and (1, -3/4). Which equation represents the function ?
The equation of the line will be given as y = -4x - (- 17/ 4).
What is an equation?It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
Given that:-
The equation of the line will be given as:-
y - y₁ = m ( x - x₁)
slope m will be calculated as:-
\(m =\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1+1}{\dfrac{-3}{4}+\dfrac{1}{4}}=-4\)
The equation will be:-
y - (1/4) = -4( x + 1 )
y = -4x - (17/4)
Therefore the equation of the line will be given as y = -4x - (- 17/ 4).
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Find a Cartesian equation for the curve.
r^2 cos(2θ)=16
Identify the curve. line circle limaçon hyperbola ellipse
The Cartesian equation for the curve r^2 cos(2θ) = 16 can be determined using the relation between cartesian and polar coordinates.
The relation between cartesian and polar coordinates is
x = r cos(θ)
y = r sin(θ)
First, note that r^2 = x^2 + y^2.
Now, we need to find cos(2θ). Using the double-angle formula, we have:
cos(2θ) = 2cos^2(θ) - 1 = 2(x^2/r^2) - 1
Now, substitute r^2 and cos(2θ) into the original equation:
(x^2 + y^2) (2(x^2/(x^2 + y^2)) - 1) = 16
Simplify the equation:
2x^2 - (x^2 + y^2) = 16
x^2 - y^2 = 16
Now we have the Cartesian equation for the curve:
x^2 - y^2 = 16.
This equation represents a hyperbola, as it has the general form of a hyperbola equation
(A^2 - B^2 = C^2, where A, B, and C are constants).
So, the Cartesian equation for the curve r^2 cos(2θ) = 16 is x^2 - y^2 = 16, and the curve is a hyperbola.
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hey please help this is really important (first to answer i will give brainlyiest) after some else answers
Answer:
can u type out the question i cant see the photo i will help thou
Step-by-step explanation:
Answer:
29
-26
Step-by-step explanation:
the equation of f(x) is given. to find f(8) just apply 8 in the place of x in the equation
same method for f(-3) just apply -3 in place of x
The endpoints of a diameter of the circle are (-1, -11) and (-17, -5). Determine the equation of the circle.
Answer:
(x+9)² +(y+8)² = 73
Step-by-step explanation:
The standard form of equation of a circle is expressed as;
(x-a)² +(y-b)² = r²
(a,b) is the centre of the circle
r is the radius
Get the midpoint;
Given the coordinate (-1, -11) and (-17, -5).
a= x1+x2/2
b = y1+y2/2
a = -1-17/2
a = -18/2
a = -9
b = -11 - 5/2
b = -16/2
b = -8
Get the diameter using the distance formula
d = √(y2-y1)² +(x2-x1)²
d = √(-5+11)² +(-17+1)²
d = √(6)² +(-16)²
d = √36+256
d = √292
r = d/2
r = √292/2
r² = 292/4
r² = 73
Get the equation
Recall rhat
(x-a)² +(y-b)² = r²
(x+9)² +(y+8)² = 73
An equation for the line whose slope is 5 and which passes through the point (-2,11) is
Answer:
y=5x+10
Step-by-step explanation:
y-11=5(x+2)
y-11=5x+10
+11 +11
y=5x+21
AutoSave AutoSave Off (iii) What percentage of the 151 body masses fall within the interval u + 20 (round to 2 decimal places)? (1 mark) File Home Inse PROTECTED File H2O File File Home In PROTECTED VIEW B 2. The body masses (in grams) of 151 Adelie penguins living in the Palmer Archipelago in Antarctica were recorded as part of the Palmer Station Long Term Ecological Research (LTER) Program. This data is stored in the Excel file called Adelie.xlsx, which can be downloaded from the LMS. The data consists of a single column with the heading "Body Mass". You are required to use Excel to answer the questions below. We will treat this data as population data for this question.
First, open Excel, then go for the Body Mass column. Second, In Excel, you can do this using the AVERAGE function: =AVERAGE(column_ range). Third, determine the upper limit of the interval by adding 20 to the mean. Forth, In Excel, use the COUNTIF function: =COUNTIF(column_ range, "<="&upper_ limit). Fifth, calculate the percentage of body mass.
Sixth, the percentage to 2 decimal places using Excel's ROUND function: =ROUND(percentage, 2)
To answer the question, we need to calculate the number of body masses that fall within the interval u + 20, where u is the mean body mass of the population.
First, we need to find the mean body mass. We can do this by using the AVERAGE function in Excel. Select the column with the body mass data and click on the Formulas tab. Click on the More Functions dropdown menu and select Statistical. Then, click on AVERAGE. Excel will automatically select the column with the body mass data and give you the mean value.
Next, we need to add 20 to the mean body mass to get the upper limit of the interval. We can do this by typing "=AVERAGE(B2:B152)+20" in a cell, where B2:B152 is the range of body mass data. This will give us the upper limit of the interval.
Now, we need to find the number of body masses that fall within this interval. We can do this by using the COUNTIF function in Excel. Type "=COUNTIF(B2:B152,"<="&upper limit)-COUNTIF(B2:B152,"<"&mean)" in a cell, where B2:B152 is the range of body mass data, the upper limit is the upper limit of the interval, and mean is the mean body mass. This will give us the number of body masses that fall within the interval u + 20.
To find the percentage of body masses that fall within this interval, we need to divide the number of body masses that fall within the interval by the total number of body masses and multiply by 100. We can do this by typing "= a number of body masses within interval/151*100" in a cell, where the number of body masses within the interval is the result of the COUNTIF function. This will give us the percentage of body masses that fall within the interval u + 20.
Therefore, the answer to the question is the percentage of body masses that fall within the interval u + 20, which we calculated using Excel.
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P and Q have coordinates (-2,3) and (5,4) respectively. Reflect P inthe X-axis to P' and Q in tha Y-axis to Q' .Find the distance between P'Q'.
Step-by-step explanation:
Hey, there!!
Let's simply work with it,
The given coordinates are, P(-2,3) and Q(5,4).
Now, finding the P' and Q'.
Reflection on x- axis .
P(x,y)---------> P' (x,-y)
P (-2,3)----------> P'(-2,-3)
Now, let's find Q'
Reflection on y-axis.
Q(x,y)----------> Q'(-x,y)
Q(5,4)---------> Q'(-5,4)
Now, The points are P'(-2,-3) and Q'(-5,4)
By distance formulae,
\(P'Q' = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } \)
Putting their values,
\(P'Q' = \sqrt{( { - 5 + 2)}^{2}( {4 + 3)}^{2} } \)
\(P'Q' = \sqrt{( { - 3)}^{2} + ( {7)}^{2} } \)
Simplifying them we get,
\(pq = \sqrt{58} \)
Therefore, the distance between P'and Q' is root under 58 units.
Hope it helps...
DOES ANYONE KNOW THIS!!? ILL GIVE BRAINLIST :)
Answer:
4x+2
Step-by-step explanation:
I'm not sure what they mean by defining a variable but this question could be modeled through the following equation
4x+2 where x (the variable) is a book
let r = x i y j z k and r = |r|. find each of the following. (a) ∇r 0 r/r2 r/r r/r −r/r3
a). The gradient of r/r^2 is (∇r)/r^2 = (∇r)/(x^2 + y^2 + z^2)
b). The gradient of r/r is (∇r)/r = (∇r)/|r|.
c). ∇r = ∂x/∂x i + ∂y/∂y j + ∂z/∂z k = i + j + k
d). The gradients of the given expressions are as follows: (∇r)/r^2 = (∇r)/(x^2 + y^2 + z^2), (∇r)/r = (∇r)/|r|, ∇r = i + j + k, and -∇r/r^3 = -∇r/(x^2 + y^2 + z^2)^3.
The gradient of a vector r is denoted by ∇r and is found by taking the partial derivatives of its components with respect to each coordinate. In this problem, the vector r is given as r = xi + yj + zk.
Let's calculate the gradients of the given expressions one by one:
(a) ∇r/r^2:
To find the gradient of r divided by r squared, we need to take the partial derivatives of each component of r and divide them by r squared. Thus, the gradient of r/r^2 is (∇r)/r^2 = (∇r)/(x^2 + y^2 + z^2).
(b) ∇r/r:
Similarly, to find the gradient of r divided by r, we need to take the partial derivatives of each component of r and divide them by r. Therefore, the gradient of r/r is (∇r)/r = (∇r)/|r|.
(c) ∇r:
The gradient of r itself is found by taking the partial derivatives of each component of r. Therefore, ∇r = ∂x/∂x i + ∂y/∂y j + ∂z/∂z k = i + j + k.
(d) -∇r/r^3:
To find the gradient of -r divided by r cubed, we multiply the gradient of r by -1 and divide it by r cubed. Thus, -∇r/r^3 = -∇r/(x^2 + y^2 + z^2)^3.
In summary, the gradients of the given expressions are as follows: (∇r)/r^2 = (∇r)/(x^2 + y^2 + z^2), (∇r)/r = (∇r)/|r|, ∇r = i + j + k, and -∇r/r^3 = -∇r/(x^2 + y^2 + z^2)^3.
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The carousel at an amusement park has 20 horses spaced evenly around its circumference. The horses are numbered consecutively from 1 to 20. The carousel completes one rotation about its axis every 40 seconds.
a. What is the central angle, in degrees, formed by horse #1 and horse #8?
b. What is the speed of the carousel in rotations per minute?
c. What is the speed of the carousel in radians per minute?
d. A child rides the carousel for 6 minutes. Through how many radians will the child pass in the course of the carousel ride?
The child passes through 18π radians in the course of the carousel ride.
To determine the number of radians the child passes during the 6-minute ride on the carousel, we need to know the distance traveled in terms of radians.
Since there are 20 horses spaced evenly around the carousel, each horse is separated by an angle of 360/20 = 18 degrees or π/10 radians.
Therefore, during one rotation of the carousel, the child passes through 20π/10 = 2π radians. And since the carousel completes one rotation every 40 seconds, the angular velocity is 2π/40 = π/20 radians per second.
To find the total distance traveled in radians during a 6-minute ride, we need to multiply the angular velocity by the time elapsed.
6 minutes is equal to 360 seconds,
so the child passes through π/20 x 360 = 18π radians during the ride.
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Did I do this right????
Answer:
The order should be:
0.7, 0.73, 0.81, 0.9
Step-by-step explanation:
Ms. Hurst is planning a dance recital for her students. The maximum duration for the recital is 87 minutes. Group dance numbers last 4 minutes and a solo performance lasts 3 minutes.
Which inequality (in standard form) describes this situation. Use the given numbers and the following variables.
x = the number of group dances on the program
y = the number of solo numbers on the program
4x+3y<87 3x+4y≤87 3x+4y<87 4x+3y≤87
Convert each inequality into Slope-Intercept Form.
Determine which one matches the situation.
Graph the inequality.
Choose 2 solutions for the inequality, written in context.
Explain, in detail and using academic language, how you found your solution.
Answer:
Inequality is \(4x+3y\leq 87\)
Slope intercept form is \(y\leq 29-\frac{4}{3}x\)
Solutions are \((2,3)\,,\,(3,4)\)
Graph: attached to the question
Step-by-step explanation:
Given: Group dance numbers last 4 minutes and a solo performance lasts 3 minutes. The maximum duration for the recital is 87 minutes.
To find: inequality (in standard form) that describes the given situation, inequality in slope-intercept form, solutions for the inequality
To graph: the inequality
Solution:
x denotes the number of group dances on the program
y denotes the number of solo numbers on the program
Total duration of group dance numbers = \(4x\) minutes
Total duration of solo performance = \(3y\) minutes
According to question,
\(4x+3y\leq 87\)
Slope intercept form of equation is \(y\leq mx+c\) where m denotes slope of line and c denotes y-intercept of the line.
Slope intercept form of \(4x+3y\leq 87\) :
\(4x+3y\leq 87\\3y\leq 87-4x\\y\leq 29-\frac{4}{3}x\)
For \((x,y)=(2,3)\),
\(4(2)+3(3)\leq 87\\8+9\leq 87\\17\leq 87\,\,which\,\,is\,\,true\)
So, \((2,3)\) is a solution of the inequality.
For \((x,y)=(3,4)\),
\(4(3)+3(4)\leq 87\\12+12\leq 87\\24\leq 87\,\,which\,\,is\,\,true\)
So, \((3,4)\) is a solution of the inequality.
Graph: attached as image
Find the area of the rectangle to the right. 9 inches for width and 5y inches for the length
Answer:
The area is 45 inches
Step-by-step explanation:
L×W=A
from a (western) standard 52-card deck, how many ways are there to draw two cards such that the first card is a diamond and the second card is a king?
There are a total of 1,326 different ways to draw two cards from a standard 52-card deck, with the first card being a diamond and the second card being a king.
The formula for this type of problem is given by the combination formula, which is expressed as C(n,r). In this case, we want to determine the number of combinations of two cards from a standard 52-card deck, with the first card being a diamond and the second card being a king. Therefore, n = 52 and r = 2.
Using the combination formula, we can calculate the number of ways to draw two cards such that the first card is a diamond and the second card is a king as follows: C(52,2) = 1326. This means that there are a total of 1,326 different ways to draw two cards from a standard 52-card deck, with the first card being a diamond and the second card being a king.
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a cylindral drill with radius 5 cm is used to bore a hole through the center of a sphere with radius 10 cm. find the volume of the ring-shaped solid that remains.
The volume of the ring-shaped solid that remains after drilling is 3961.73cm³.
The radius of the cylindrical drill is 5cm and the radius of the sphere is found to be 10cm.
After drilling,
The radius of the of the sphere will act as a hypotenuse to the triangle where the base is the radius of the cylinder and the perpendicular is the height of the cylinder.
So, we can say,
Height H of cylinder = √(10² - 5²)
Height H of cylinder = 8.66 cm.
The volume V of the ring shape remaining,
V = Volume of sphere - volume of cylinder
V = 4/3πR³ - 1/3πr²H
R is the radius of sphere and r is the radius of cylinder,
Putting values,
V = 4/3π(10)³ - 1/3π(5)²8.66
V = 3961.73 cm³.
So, the volume that remains is 3961.73cm³.
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In ΔABC, AB = 16 in, BC = 9 in, AC = 10 in. AD is perpendicular to the extension of BC . Find CD.
Answer:
25/6
I don't really know how I got it, sorry I can't help with that
Which statement is most likely to be true? the scores of mrs. scott’s class are the closest to the class mean. the scores of mr. phan’s class are the closest to the class mean. the scores of mrs. jones’s class are the closest to the class mean. the scores of mrs. rijo’s class are the closest to the class mean.
Answer:
The scores from Mrs. Rijo’s class are the closest to the class mean.
Step-by-step explanation:
Just took the test
2(M+7)+5m-6
Umm I need help
Answer:
7m+8
Step-by-step explanation:
distributive prop then pemdas
Help with problem in photo
Answer:
(x-6)²+(y+3)²=17²
Step-by-step explanation:
The equation of a circle with center (a,b) and radius r is given by the formula:
(x - a)² + (y - b)² = r²
In this case, the center of the circle is (6,-3), and it passes through the point (-9,5). To find the radius of the circle, we need to calculate the distance between the center and the point on the circle. Using the distance formula, we get:
r = √[(x₂ - x₁)² + (y₂ - y₁)²]
= √[(-9 - 6)² + (5 - (-3))²]
= √[225 + 64]
= √289
= 17
So, the radius of the circle is 17. Now we can plug in the values for the center and radius into the equation of a circle:
(x - 6)² + (y + 3)² = 17²
Mr. Odulate’s rectangular classroom has an area of 1,152 square feet. If the width of the room is 36 feet, what is the length of the room?
Answer:
32 feet
Step-by-step explanation:
The area of a rectangle is \(a = lw\), where the area equals the length times the width. Since we are given the area and the width, we can divide them to find the width, since it's the inverse operation.
⇒ 1152 ÷ 36 ≈ 32 feet
PLEASE HELP ASAP
BRAINLIEST
HAVE 10 MINUTES