Which process do self-feeders use to get energy?

Answer:

Products

Explanation:

The substances Al and Cl₂ can both be referred to as the product of the chemical action.

Products of a chemical reaction are usually found on the right hand side. They are the new substances that are produced from the reaction between two or more substances on the right hand of the chemical reaction.

When two species combines, they give a product. A single substance can also decompose to give products.

In the given reaction, we have been given a decomposition reaction and the products are  Al and Cl₂.

The molarity of the NiSO₄ solution made by dissolving 38.81 grams of nickel (ii) sulfate, NiSO₄, in enough water to make 0.467 liters of solution is 0.535 M

First, we shall obtain the mole of 38.81 grams of nickel (ii) sulfate, NiSO₄. Details below:

Mole of NiSO₄ = mass / molar mass

= 38.81 / 154.75

= 0.25 mole

Now, we shall determine the molarity of the solution. Details below:

Molarity of solution = mole / volume

= 0.25 / 0.467

= 0.535 M

Thus, the molarity of the solution is 0.535 M

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Answer: The osmotic pressure of 5.0g of sucrose solution in 1 L is 271.32 torr.

Explanation:

Given: Mass = 5.0 g

Volume = 1 L

Molar mass of sucrose = 342.3 g/mol

Moles are the mass of a substance divided by its molar mass. So, moles of sucrose are calculated as follows.

\(Moles = \frac{mass}{molarmass}\\= \frac{5.0 g}{342.3 g/mol}\\= 0.0146 mol\)

Hence, concentration of sucrose is calculated as follows.

\(Concentration = \frac{moles}{Volume (in L)}\\= \frac{0.0146 mol}{1 L}\\= 0.0146 M\)

Formula used to calculate osmotic pressure is as follows.

\(\pi = CRT\)

where,

\(\pi\) = osmotic pressure

C = concentration

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

\(\pi = CRT\\= 0.0146 \times 0.0821 L atm/mol K \times 298 K\\= 0.357 atm (1 atm = 760 torr)\\= 271.32 torr\)

Thus, we can conclude that the osmotic pressure of 5.0g of sucrose solution in 1 L is 271.32 torr.

The number of grams in 6.02 × 10²³ formula units of aluminium chloride is 101.96g.

The mass of a substance can be calculated from the formula units by dividing the number of formula units by Avogadro's number.

According to this question, there are 6.02 × 10²³ formula units of aluminum oxide. This means that;

no of moles = 6.02 × 10²³ ÷ 6.02 × 10²³

no of moles = 1 mole

molar mass of aluminium oxide = 101.96g/mol

mass of aluminum oxide = 101.96g/mol × 1 mole = 101.96g

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As combustion always result into the formation of water, the other type of reactions that may result into formation of water are Acid-Base Neutralization Reactions and Hydrogen and Oxygen Reaction.

Acid-Base Neutralization Reactions:

A neutralisation reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products.

H⁺ ions and OH⁻ ions combine to generate water during a neutralisation reaction. Acid-base neutralisation is the most common type of neutralisation reaction.

Example: Formation of Sodium Chloride (Common Salt):

HCl + NaOH → NaCl + H₂O

Hydrogen and Oxygen Reaction:

Water vapour is created when hydrogen gas (H₂) and oxygen gas (O₂) are combined directly. This reaction produces a lot of heat and releases a lot of energy.

Example: 2 H₂ + O₂ → 2 H₂O

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The products of the alpha decay of radium-226 and the beta decay of carbon-14 are radon-222 and nitrogen-14, respectively.

The alpha decay of radium-226 results in the emission of an alpha particle, which is a helium nucleus consisting of two protons and two neutrons.

Therefore, the product of the alpha decay of radium-226 is radon-222:

Ra-226 → Rn-222 + alpha particle

On the other hand, In the case of carbon-14, beta minus decay occurs, in which a neutron is converted into a proton, and an electron and an antineutrino are emitted.

So carbon-14 becomes nitrogen-14:

C-14 → N-14 + beta particle

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--The complete Question is, What is the product of the alpha decay of radium-226 and the beta decay of carbon-14?--

The number of moles of carbondioxide that will be produced in the combustion of methane is 3 moles (option D).

Stoichiometry refers to the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, methane undergoes combustion in air to produce carbondioxide and water. Methane is the limiting reactant because the other reactant is oxygen of the air which is always present in excess.

Based on the chemical equation given above, 1 mole of methane produces 1 mole of carbondioxide.

This means that 3 moles of methane will produce 3 moles of carbondioxide.

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Answer:

To determine the correct subscripts in a chemical formula, you have to solve how many atoms you need to balance the charge.

For example if I had the compound Calcium Fluoride I would look at the periodic table and see that Calcium's ionic formula is

Ca2+

. How do I know this? Well all elements want to have 8 valance electrons so they can be stable(happy). Seeing that Calcium has 2 valance electrons it is going to give away 2 electrons because that is easier than gaining 6 to be happy. Since Calcium has given away 2 electrons it has two more protons than electrons. We know that Protons have a Positive charge, Electrons have Negative charge, and the number of electrons is equal to the atomic number of an element in its pure non-ionic state. (Meaning it doesn't have a positive or negative charge; it is balanced.)

So if calcium gave away two electrons, it will have two more protons than an electron giving it a (2+) charge. The same process can be applied to Fluoride. Since fluoride is one to the left of the noble gases(group 18 or 8A) on the periodic table we know that it has 7 valance electrons because it is in group 7A or 17.

Knowing that we have 7 electrons the fluoride atom will gain an extra electron. Since the fluoride atom gained an extra electron it will have one more negative charge than a positive making it a ^(−)ion.

So you know that Calcium has a 2+ charge and that fluoride has a 1- charge, you then need these ions to balance out. So you need two fluorine atoms with a 1- ions to balance out the 2+ ion of calcium. Your final answer would be

CaF2

because you need two fluorine atoms to balance out the 2+ charge of the calcium.

Final Tip: Determine the charges then inverse the charges, remove the positive and negative superscipts, and write the charge numbers as a sub script. Ie. Calcium Fluoride

Ca2+ and F−

inversing and removing the charge signs would give you

Answer:

Solid

Explanation:

Cus its solid, take a brick for example. It's hard and has no space unlike liquid or gas.

Answer:

Nitrogen is the chemical element with the symbol N and atomic number 7.

Explanation:

Answer:

B

Explanation:

The chemical formula will be Mg\(_3\)P\(_2\). Therefore, the correct option is option B among all the given options.

Using atomic symbols with numerical subscripts, a chemical equation is indeed a notation used by chemists to indicate the total amount and kind of atoms contained in some kind of a molecule. A written chemical equation is a straightforward illustration of an actual, three-dimensional molecule.

The precise atoms that make up a material are described in its chemical formula. The chemical equation, the molecular formula, as well as the structural formula are the three fundamental types of chemical formulas. The chemical formula will be  Mg\(_3\)P\(_2\).

Therefore, the correct option is option B.

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Answer:

The solubility of alkaline earth metal hydroxides in water increases down the group because the size of the metal cation increases as you move down the group. This increase in size results in a decrease in the cation's charge density, which makes it less able to attract and hold onto hydroxide ions. As a result, the hydroxides become more soluble in water as you move down the group. Additionally, the lattice energies of the hydroxides decrease down the group, making it easier to break apart the crystal lattice structure and dissolve the hydroxides in water.

6.4875 moles of nitrogen gas would be produced if 8.65 moles of copper(II) oxide were reacted with excess ammonia.

Given the following balanced equation, 2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g). We are required to determine the number of moles of nitrogen gas that would be produced if 8.65 moles of copper(II) oxide were reacted with excess ammonia. We can use stoichiometry to solve this problem. Stoichiometry is the quantitative relationship between the reactants and products in a chemical reaction. It allows us to make predictions about the amount of product produced or reactant required in a chemical reaction. Stoichiometry relies on the balanced chemical equation for the reaction. In this case, the balanced chemical equation is 2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g).

The balanced chemical equation shows that 2 moles of ammonia react with 3 moles of copper(II) oxide to produce 1 mole of nitrogen gas and 3 moles of water. This means that the mole ratio of ammonia to nitrogen gas is 2:1. We can use this mole ratio to determine the number of moles of nitrogen gas produced in the reaction. We know that 8.65 moles of copper(II) oxide is reacted with excess ammonia. Since copper(II) oxide is the limiting reagent, we can use it to calculate the number of moles of ammonia used in the reaction. The molar ratio of copper(II) oxide to ammonia is 3:2. Therefore, we can calculate the number of moles of ammonia used in the reaction as follows:Number of moles of ammonia = (3/2) × number of moles of copper(II) oxideNumber of moles of ammonia = (3/2) × 8.65Number of moles of ammonia = 12.975 molesWe know that the mole ratio of ammonia to nitrogen gas is 2:1. Therefore, the number of moles of nitrogen gas produced in the reaction is half the number of moles of ammonia used.Number of moles of nitrogen gas produced = (1/2) × number of moles of ammoniaNumber of moles of nitrogen gas produced = (1/2) × 12.975Number of moles of nitrogen gas produced = 6.4875 moles.

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An isotope corresponds to the variation of an element that has a different number of neutrons, that is, its mass number changes. To find the atomic mass, we take the average of the atomic mass of the isotopes multiplied by their abundance.

So the atomic weight of potassium, in this case, will be:

Answer: The molar mass of pottasium will be 39.101amu

Answer:

1.12 moles

Explanation:

To find the amount of moles, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation and solve for "n".

P = 1.00 atm                     R = 0.08206 atm*L/mol*K

V = 25.0 L                        T = 0. °C + 273 = 273 K

n = ? moles

PV = nRT

(1.00 atm)(25.0 L) = n(0.08206 atm*L/mol*K)(273 K)

25.0 = n(22.4)

1.12 = n

Answer:

Water acts as a base in the presence of a strong acid

Explanation:

Water,being an amphoteric compound, can act both as an acid and as a base.

In the presence of an acid , water acts as a base but in the presence of a base, water acts as an acid.

Answer: 24.305052 (8 sig figs)  [Mg]

Explanation:  The AMU of each isotope is multiplied by it's percent abundance to yield a weighted average for each isotope.  The sum of these weighted averages will be the wighted average of the element's isotopes:

Isotope    Mass (AMU)     %            Weighted AMU

24Mg 23.985042 78.99% 18.94578468

25Mg 24.985837 10.00%   2.4985837

26Mg 25.982593 11.01%   2.860683489

                                   24.305052 (8 sig figs)

If a government wants to efficiently reduce a widespread negative externality like air pollution, it must know the costs of pollution abatement of the individual polluters.

a. lower, higher

b. lower, lower

The term "abatement costs" refers to the expenses incurred by a company or organization when it becomes necessary to get rid of any unwelcome annoyances or unfavorable byproducts of the production process. It is the cost associated with removing a harmful externality, such as pollution that has an adverse environmental impact.

As tradable emissions permits are available, organizations with lower abatement costs can sell them to companies with higher abatement costs in order to address the issue of pollution abatement costs.

The firm that sold the permit would have lower abatement costs and the negative externality is also lowered at the lowest cost achievable if the firm still had to cut its pollution output after selling.

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If a government wants to efficiently reduce a widespread negative externality like air pollution, it must know the costs of pollution abatement of the individual polluters. However, this information is difficult to obtain directly. Tradeable emissions permits are one way to solve the asymmetric information problem affecting pollution abatement efforts.

a. Because the permits are tradeable, firms with ___ abatement costs will sell some of their permits to firms with ___ abatement costs.

Now consider that even after a firm has sold its permits, it must still reduce its pollution output.

b. Since those who sell their permits would have ___ abatement costs, the negative externality is reduced at ___ possible cost to society.

A)  the addition of \(H_3O\)+ or OH- ions would have opposing effects on the buffer solution.

b) \(H_3O\)+ would favor the formation of acetic acid, while adding OH- would favor the formation of acetate ions.

c) The exact magnitude of the changes in concentrations depends on the initial concentrations of \(CH_3COOH\) and \(CH_3COONa\), as well as the specific amount of \(H_3O\)+ or OH- added.

To determine the effect of adding \(H_3O\)+ and OH- on the given buffer solution, we need to consider the ionization of acetic acid (\(CH_3COOH\)) and the dissociation of its sodium salt (CH3COONa). Let's analyze each scenario separately:

A) Buffer solution consisting of 0.5 M\(CH_3COOH\) and 0.5 M \(CH_3COONa\):

When acetic acid (CH3COOH) and its sodium salt (\(CH_3COONa\)) are present together in a solution, they form a buffer system. Acetic acid partially ionizes in water, releasing \(H_3O\)+ ions, while sodium acetate dissociates into Na+ and \(CH_3COO\)- ions.

Adding \(H_3O\)+:

The \(H_3O\)+ ions would react with the acetate ions (CH3COO-) to form undissociated acetic acid (\(CH_3COOH\)) through the following reaction:

\(H_3O\)+ + \(CH_3COO\)- ⇌ \(CH_3COOH\) + H2O

The addition of H3O+ would shift the equilibrium to the left, promoting the formation of more acetic acid and decreasing the concentration of acetate ions.

Adding OH-:

The OH- ions would react with the acetic acid (\(CH_3COOH\) to form water and acetate ions (CH3COO-) through the following reaction:

OH- + \(CH_3COOH\) ⇌ \(CH_3COO\)- + H2O

The addition of OH- would shift the equilibrium to the right, consuming acetic acid and increasing the concentration of acetate ions.

B) After adding 0.02 mol of NaOH to 1.0 L of the buffer solution:

When solid NaOH is added to the buffer solution, it dissociates completely in water to form Na+ and OH- ions.

NaOH dissociation:

NaOH → Na+ + OH-

The OH- ions formed would react with acetic acid according to the reaction mentioned in Scenario A (2), increasing the concentration of acetate ions and consuming acetic acid.

C) After adding 0.02 mol of HCl to 1.0 L of the buffer solution:

When HCl is added to the buffer solution, it dissociates completely in water to form \(H_3O\)+ and Cl- ions.

HCl dissociation:

HCl → \(H_3O\)+ + Cl-

The \(H_3O\)+ ions formed would react with acetate ions (\(CH_3COO\)-) according to the reaction mentioned in Scenario A (1), forming more undissociated acetic acid and decreasing the concentration of acetate ions.

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Answer:

655

Explanation:

using bodmas, (bracket first), 8.81-7.50=1.31

1.31÷0.0020=655

There are numerous ways to determine whether lead is present in an ore. Atomic absorption spectroscopy is a popular approach. With this method, an ore sample is dissolved in acid and then atomized in a flame or plasma.

The sample's atoms will absorb light at particular wavelengths that are peculiar to the element under investigation. The amount of light absorbed can be used to calculate how much lead is present in the sample. Inductively coupled plasma mass spectrometry and X-ray fluorescence spectroscopy are further techniques. It is crucial to remember that these procedures call for specialized tools and training, thus they ought to only be carried out in a lab by qualified experts.

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Answer:

\(m=397.6gC_8H_{18}}\)

Explanation:

Hello there!

In this case, according to the given chemical reaction, we can set up the heat of reaction per mole of gasoline as shown below:

\(\Delta H=\frac{-10,990kJ}{2molC_8H_{18}}=-5495\frac{kJ}{molC_8H_{18}}\)

Now, since the total heat is obtained by multiplying the moles and heat of reaction, we can calculate the moles as shown below:

\(n=\frac{Q}{-\Delta H } \\\\n=\frac{19,126kJ}{-(-5495\frac{kJ}{molC_8H_{18}} )} \\\\n=3.48molC_8H_{18}}\)

Finally, since the molar mass of gasoline is 114.22 g/mol, we can easily calculate the mass as follows:

\(m=3.48molC_8H_{18}} *\frac{114.22gC_8H_{18} }{1molmolC_8H_{18}} } \\\\m=397.6gC_8H_{18}}\)

Best regards!

Because:

Their roots are no longer in the soil. Thus, can't absorb water and mineral ions needed for plant growth via photosynthesis.

Hope this helps!

Answer:

Yes

Explanation:

Well this is because when a plant is planted water goes from the soil, into the roots then finally distributed to other parts of the plant.

So when plants have been plucked or uprooted water no longer has access to the plant which may result to the plant being dried up and will possibly die

 1 grams Methane is equal to 0.062334579609362 mole. Note that rounding errors may occur, so always check the results. 

The two functional groups that the aminoacid has according to the picture are amine and carboxyl.

In chemistry and related areas, a functional group can be defined as a group of atoms bonded in a specific molecule that can affect the was the molecule reacts or the specific behavior of it.

In the case of the molecule presented, which is an amino acid, two functional groups can be identified:

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Answer:

the volume in mL is 15

Explanation:

The computation of the volume in mL is shown below:

As we know that

N = nM

where

N denotes the normality

n denotes the number of equivalents

M denotes the molarity

Also

For NaOH , N = M

Now

M× V_1 = N × V_2

V_1 = N × V_2 ÷ M

= 0.09000 N × 1.0 L ÷ 6.0 M

= 15 mL

hence, the volume in mL is 15

Answer:

1. C

2.B

Explanation:

Answer:

-0.1767°C (Option A)

Explanation:

Let's apply the colligative property of freezing point depression.

ΔT = Kf . m. i

i = Van't Hoff factot (number of ions dissolved). Glucose is non electrolytic so i = 1

m = molality (mol of solute / 1kg of solvent)

We have this data → 0.095 m

Kf is the freezing-point-depression constantm 1.86 °C/m, for water

ΔT = T° frezzing pure solvent - T° freezing solution

(0° - T° freezing solution) = 1.86 °C/m . 0.095 m . 1

T° freezing solution = - 1.86 °C/m . 0.095 m . 1 → -0.1767°C

The freezing point of the 0.05500 m aqueous solution of glucose is  -0.1023 °C.

The freezing point is the temperature at which a substance transitions from its liquid phase to its solid phase at a given pressure. It is the point at which the substance freezes and forms a solid.

At the freezing point, the substance reaches a state of thermodynamic equilibrium between the liquid and solid phases, with the rate of freezing (solidification) equal to the rate of melting (liquefaction). The freezing point is a characteristic property of a substance and is typically determined under standard atmospheric pressure.

Using the freezing-point depression equation:

ΔT = Kf * m

where ΔT is the freezing point depression, Kf is the molal freezing-point depression constant, and m is the molality of the solution.

Given:

Kf = 1.86 °C/m

m = 0.05500 m

ΔT = 1.86 °C/m * 0.05500 m

ΔT = 0.1023 °C

The freezing point depression is 0.1023 °C.

Freezing point = 0 °C - 0.1023 °C

Freezing point = -0.1023 °C

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