Which organelle provides a protective covering is the cell control what enters and leaves?

vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

Answer:

A.) Longer and Shorter

Explanation:

If the wavelength of a light wave is shorter that means the frequency will be higher.

That means that longer wavelengths have a lower frequency.

Answer:

(o) Al + NaOH + H2O -NaAlO2 + H2.

When aluminum oxide Al 2 O 3 reacts with sodium hydroxide solution, it forms sodium aluminate and water H 2 O . This reaction takes place at a temperature of 900 - 1100 ° C

Answer:

Because they have variable oxidation states

Explanation:

Transition metals are designated with roman numerals because they have variable oxidation states.

They do not form a single ionic ion as seen by the main group elements.

Answer:

Earth

Explanation:

The Earth and the sun are the part of the solar system and the earth and other planets revolve around the Sun. The solar system is placed in the universe.

Answer:

The negative charge (fewer protons than electrons) for an anion is shown by a number and minus sign after the formula. If there's just a minus sign, it means the charge is minus 1. Here are several examples of anions: If an ion consists of two or more atoms it is called a polyatomic ion.

Explanation:

Answer: I think it’s A, positive charge

Explanation:

Maxwell's relations can be used to show how the enthalpy of an ideal gas changes with volume held at constant temperature. This is how it's done:
Using the fundamental equation, dU = TdS - PdV, and taking the partial derivative with respect to volume,
we get:dU/dV = T(dS/dV) - P This equation represents the relationship between internal energy and volume for a constant temperature process.

Using the Maxwell relation, dS/dV = (dP/dT)/T,
we can substitute it in the previous equation: dU/dV = T(dP/dT)/T - PdU/dV = (dP/dT) - P
This equation represents the relationship between internal energy and volume for a constant temperature process.
The enthalpy, H = U + PV, can then be used to express the result as:dH/dV = dU/dV + P + V(dP/dT)dH/dV = (dP/dT)V

The above equation shows how the enthalpy of an ideal gas changes with volume held at constant temperature. Therefore, we can conclude that the enthalpy of an ideal gas is dependent on the temperature and the pressure of the gas.

To learn more about "Maxwell relation" here:

https://brainly.com/question/28956380#

#SPJ11

The enthalpy of vaporization for the liquid is 40.7 kJ/mol.

The slope of the graph, -4830 K, can be used to calculate the enthalpy of vaporization (ΔHvap) using the Clausius-Clapeyron equation:

ΔHvap = -RT^2 * dln(p) / d(1/T)

Where R is the gas constant (8.314 J/mol.K), T is the temperature in kelvin and dln(p) / d(1/T) is the slope of the graph.

By substituting the values, we get:

ΔHvap = -8.314 * (1/1000) * (-4830) = 40.7 kJ/mol

So, the enthalpy of vaporization for the liquid is 40.7 kJ/mol.

Learn more about vaporization:

https://brainly.com/question/11465845

#SPJ4

a)Elements that form hydrides by electrovalent binding are Sodium(Na), and Magnesium (Mg).

b)None of the elements is used to catalyze a chemical reaction and the elements that catalyze the reaction are platinum, cobalt, and iron.

c)Elements used in are radioactive dating  \(C^{14}\)

d)The element which forms acid anhydride is phosphorous (P).

e)The element that exhibits both metallic and non-metallic behavior is Metalloids.

The tabular display of chemical elements is the periodic table, Which contains 18 periods and 7 groups.

All the elements are configurable in the S, P, D, and F blocks.

S and D block elements mostly contain metals, and P- block contains non-metals and Metalloids.

To learn more about Periodic Table, use the following link

https://brainly.com/question/11155928

#SPJ9

The percent composition of lithium bromide is 91.9% bromine and 8.1% lithium.

This can be calculated by dividing the mass of each element in the compound by the total mass of the compound, and then multiplying by 100 to get the percent composition.

For bromine, the mass is 4.96 g and for lithium, the mass is 0.43 g.

Therefore, the percent composition of bromine is (4.96/5.39) x 100 = 91.9%, and the percent composition of lithium is (0.43/5.39) x 100 = 8.1%.

To know more about chemical compound, click

https://brainly.com/question/2648746

Answer:

Explanation:

A) The concentration = The mass of the solute/the total volume

                                   =m/v

                                   = 20g/1L

B) The concentration = n/v

                                  first we have to find the number of moles in 20g of NaCl

n=m/M

n=20mol/58.5

1000cm^3=1000ml

1000cm^3=1dm^3

C=n/v

  = 20/58.5

   = 0.341\(moldm^{-3}\)

c) 20g*10^6/1000g

=20000ppm

d)20*100/1000 = 2%

Answer:

c

Explanation:

C is the answer for increasing Atomic number

This peptide is positively charged at physiological pH. In conclusion, SDEKAINVKWQLA and SDEKAINVKWQHA are neutral at physiological pH, SEERAINVAWQHA is negatively charged, and SDEK is positively charged.A peptide is a short chain of amino acids that are joined together with peptide bonds.

The nature of a peptide's charge depends on the overall charges of the amino acids in the sequence. At physiological pH, amino acids will either be positively charged, negatively charged, or neutral, depending on their side chains. Let's examine the peptides provided to determine their charges at physiological pH:SDEKAINVKWQLA: This peptide contains a mix of amino acids with positively charged, negatively charged, and neutral side chains. However, the positively charged amino acid (lysine) and the negatively charged amino acid (aspartic acid) are present in equal amounts.

Therefore, this peptide is considered neutral at physiological pH.SDEKAINVKWQHA: This peptide is similar to the first one but has one less amino acid (alanine instead of leucine at the end). It contains the same number of positively charged and negatively charged amino acids, and so it is also neutral at physiological pH.SEERAINVAWQHA: This peptide contains three negatively charged amino acids (aspartic acid and glutamic acid) and only one positively charged amino acid (lysine). Therefore, the peptide overall is negatively charged at physiological pH.SDEK: This peptide contains both positively charged (lysine) and negatively charged (aspartic acid) amino acids. However, there are more positively charged amino acids in the peptide than negatively charged ones.

To know more about peptide  visit:-

https://brainly.com/question/32004016

#SPJ11

The diffusion coefficient is 4.39x10-12 m2/s.

Given information;

Initial nitrogen concentration, c₀ = 0.08 wt %

Nitrogen concentration to be achieved, cₙ = 0.52 wt %

Diffusion coefficient, D = 9.10E-05 m²/s

Temperature, T = 1100 K

Activation energy, Qd = 168 kJ/mol

Gas constant, R = 8.31 J/mol K

To find;

Diffusion coefficient at 1100 K using Arrhenius equation;

The Arrhenius equation for diffusion coefficient is given as;

D = D₀ exp(-Qd / R T)

where; D₀ is the diffusion coefficient at an infinite temperature.

Substituting the given values of D, Qd, R, and T into the equation above;

D = 9.10E-05 m²/s

Qd = 168 kJ/mol

R = 8.31 J/mol

KT = 1100 K

At 1100 K, the value of kT is;

kT = R T

     = 8.31 J/mol K x 1100 K

     = 9141 J/mol

Multiplying by Avogadro's number to get the value in J;

9141 J/mol x (6.022 x 10²³) / (1 mol) = 5.50 x 10²⁹ J-1

                                                          = 5.50 x 10²⁹ m²/kg

Multiplying by the Boltzmann constant to get the value in m²/s;

K = 1.38 x 10⁻²³ J/KD₀ can now be obtained by rearranging the Arrhenius equation as;

D₀ = D / exp(-Qd / R T)

Substituting the values into the equation;

D₀ = 9.10E-05 m²/s / exp(-168 x 10³ J/mol / 8.31 J/mol K x 1100 K)D₀

     = 9.10E-05 m²/s / exp(-21.36)D₀

     = 9.10E-05 m²/s / 1.29E-09D₀

     = 7.05E-04 m²/s

Therefore, the diffusion coefficient at 1,100 K if k = 8.31 is;

D = D₀ exp(-Qd / R T)D

   = 7.05E-04 m²/s exp(-Qd / R T)D

   = 7.05E-04 m²/s exp(-168 x 10³ J/mol / 8.31 J/mol K x 1100 K)

D = 7.05E-04 m²/s exp(-21.36)D

   = 4.39 x 10⁻¹² m²/s

Therefore, the correct option is 4.39x10-12 m2/s.

Learn more about Concentration from the given link :

https://brainly.com/question/17206790

#SPJ11

The work done during the combustion of 1.0 mol of octane is 10.2 kJ.

The work done during the combustion of a substance is equal to the change in internal energy minus the change in heat energy. Since we are dealing with 1.0 mol of octane at a pressure of 1.0 atm, we can calculate the change in internal energy as 5084.3 kJ.

The change in heat energy is given as 5074.1 kJ. We can calculate the work done during the combustion using the formula W = ΔU - ΔH. Substituting the values we get W = 5084.3 - 5074.1 = 10.2 kJ. This is the work done during the combustion of 1.0 mol of octane at a pressure of 1.0 atm.

For more questions like Internal energy click the link below:

https://brainly.com/question/14853446

#SPJ4

The complete question:

The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is 5084.3 kJ. If the change in heat energy is 5074.1 kJ, how much work is done during the combustion?

Answer:

metallic characteristics refers to the level of reactivity of a metal. Metals tend to lose electrons in chemical reactions, as indicated by their low ionization energies. Within a compound, metal atoms have relatively low attraction for electrons, as indicated by their low electronegativities.

Explanation:

Answer:

a).

Explanation:

precise electron locations cannot be calculated, only predicted based on previous calculations. they cannot know whether or not an electron will be or will not be somewhere specific

have a nice day!

The chemist's results with aluminum foil would be different from the experiment that used gold foil because the results would show less scattering and smaller deflection angles compared to the gold foil experiment.

In the gold foil experiment, conducted by Ernest Rutherford, alpha particles were fired at a thin gold foil. Most of the alpha particles passed straight through the foil, but a few were deflected at large angles, indicating the presence of a dense, positively charged nucleus.

Aluminum, with an atomic number of 13, has a significantly lower atomic number compared to gold (atomic number 79). This means that aluminum has fewer protons in its nucleus and is less dense. As a result, the aluminum foil would be less effective in scattering alpha particles compared to gold foil.

Therefore, in the experiment with aluminum foil, the majority of the alpha particles would pass through with minimal deflection, indicating a smaller scattering angle and less interaction with the nucleus. This would demonstrate that the aluminum foil has a less dense nucleus compared to gold.

You can learn more about aluminum foil at

https://brainly.com/question/28735093

#SPJ11

Answer:

Explanation:

Hope it helps!

#CarryOnLearning!

#KeepStudy!

these are the examples of homogeneous mixture

Answer:

219.1K

Explanation:

T1/V1= T2/V2

Temp for Gas Laws are always in Kelvin

Volume is always Liters

so T2= (T1xV2)/V1

(35Lx313K)/50L=219.1K

The substances initially involved in a chemical reaction are called reactants.

They are the substances that are present at the start of the reaction and are transformed into different substances, known as products, during the reaction. The reactants are written on the left side of a chemical equation and the products are written on the right side.

In a chemical reaction,

Example:

In the reaction between hydrogen gas (H2) and oxygen gas (O2) to form water (H2O), the reactants are H2 and O2, and the product is H2O. This reaction can be represented by the equation: H2 + O2 -> H2O

In this equation, the reactants H2 and O2 are listed on the left side of the arrow and the product H2O is listed on the right side.

It is important to note that the number of atoms of each element on the reactants side and products side must be equal. This principle is called the law of conservation of mass.

Learn more about chemical reactions here:

https://brainly.com/question/29470602

#SPJ4

If you hold the temperature and partial pressure of a gas over a liquid constant while doubling the volume of the liquid, the following statements are true: It is important to note that these statements are true assuming other factors, such as temperature and pressure, remain constant.

1. The concentration of the gas in the liquid will decrease. When you double the volume of the liquid, the same amount of gas is spread over a larger space, resulting in a lower concentration.
2. The equilibrium between the gas and the liquid will shift towards the gas phase. As the volume of the liquid increases, the equilibrium will shift to compensate for the decrease in concentration.

3. The rate of evaporation of the liquid will increase. With the increase in volume of the liquid, more surface area is exposed to the gas phase.  
4. The solubility of the gas in the liquid will decrease. Doubling the volume of the liquid will result in a decrease in the solubility of the gas.

To know more about pressure visit:-

https://brainly.com/question/32099691

#SPJ11

The electronic configuration for the \(S^{-2}\) ion is [Ne] 3s2 3p6.

\(S^{-2}\) ions are negatively charged ions that are composed of two sulfur atoms. They are produced when sulfur atoms gain two electrons, creating a net negative charge. These ions are highly reactive and can form strong bonds with other atoms, molecules, and ions. This is because when an atom loses two electrons, the outermost shell (3p) must gain two electrons to fill the quantum level. its electron configuration changes to the next noble gas (in this case, Neon) plus two additional electrons. Since 3p has six electrons, the electronic abbreviation for the \(S^{-2}\) ion is [Ne] 3s2 3p6.

learn more about electronic configuration Refer:brainly.com/question/29157546

#SPJ1

Answer:

a.) It matches the universal pH indicator and is indicating the proper pH.

Explanation:

it says its the answer.

Answer:

Explanation:

An object is thrown vertically from the ground upwards with a speed of 10 m/s. Considering g = 10 m/s2, the maximum height that the object reaches from the ground, in meters, will be:

a) 15.0.

b) 10.0.

c) 5.0.

d) 1.0.

e) 0.5.

Chlorine is most likely to bond with elements from Group 1 (alkali metals) or other elements that can donate an electron to chlorine, allowing it to achieve a stable octet configuration.

Chlorine (Cl) has 7 valence electrons in its outermost energy level. In order to achieve a stable electron configuration, chlorine tends to gain one electron to complete its octet (8 valence electrons).

Based on its tendency to gain an electron, chlorine belongs to Group 17, also known as Group VIIA or the halogens, in the periodic table. The elements in Group 17 include fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). All of these elements have 7 valence electrons and exhibit similar chemical behavior.

Chlorine can form bonds with elements from other groups by accepting an electron to achieve a stable electron configuration. For example, chlorine can readily react with elements from Group 1, such as sodium (Na), to form an ionic compound like sodium chloride (NaCl). In this case, chlorine gains an electron from sodium to achieve a full outer shell, and sodium loses an electron to also achieve a stable electron configuration.

In summary, chlorine is most likely to bond with elements from Group 1 (alkali metals) or other elements that can donate an electron to chlorine, allowing it to achieve a stable octet configuration.

learn more about alkali metals here

https://brainly.com/question/18534253

#SPJ11

In brief, the pKa of Et2NC(O)CH2NMe3+ (amide) is estimated to be within the range of 9-11. Keep in mind that this is an estimation, and the exact pKa value may vary.                                                                                                                      The pKa of Et2NC(O)CH2NMe3+ (amide) can be found using the following steps:

1. Identify the compound: The given compound is an amide, with the chemical structure Et2NC(O)CH2NMe3+. This is a protonated tertiary amine, where the positive charge is on the nitrogen atom.

2. Determine the acidic site: In this amide, the acidic site is the proton attached to the nitrogen atom.

3. Find pKa values: pKa values are typically found in tables or using online databases. However, since the specific pKa value for this amide is not widely available, you can estimate its pKa based on similar compounds.

4. Estimate pKa: Tertiary amines usually have pKa values around 9-11. For example, the pKa of trimethylamine (NMe3) is approximately 9.8. Since the given amide has a similar structure, you can estimate its pKa to be within this range as well.

Learn more about  acidic site from : brainly.com/question/31592227

#SPJ11