Answer:
The number of valence electrons increases from left to right.
Explanation: The number of valence electrons increases going across a period, or row in the periodic table, for example, group 1 elements have 1 valence electrons and group 2 elements have have 2.
find the concentration in mol/dm^3 of the solution
0.8 g of solid sodium hydroxide is dissolved in
distilled water to a final volume of 1 dm³.
Answer:
0.02 mol/dm³
Explanation:
To find the concentration of the solution in mol/dm^3, you need to know the molar mass of sodium hydroxide and the number of moles of sodium hydroxide that are present in the solution.
The molar mass of sodium hydroxide is 40 g/mol. To find the number of moles of sodium hydroxide in the solution, divide the mass of sodium hydroxide (0.8 g) by the molar mass (40 g/mol):
0.8 g / 40 g/mol = 0.02 mol
The concentration of the solution is then calculated by dividing the number of moles of sodium hydroxide by the volume of the solution:
0.02 mol / 1 dm³ = 0.02 mol/dm³
So the concentration of the solution is 0.02 mol/dm³.
Why does a lump of cotton wool shrink in water?
Answer: Sufficient volume of air is present in lump of cotton wool. then dipped in water, this air goes out due to which the cotton lump shrunk.
yes
which of the following co2 samples contains the greatest number of moles of co2?
Answer:
3.21 x 10²³ CO² molecules
The atomic masses of 35^Cl (75.53 percent) and 37^Cl (24.47 percent) are 34.968 and 36.956 amu, respectively. Calculate the average atomic mass of chlorine. The percentages in parentheses denote the relative abundances
An element can have multiple isotopes. Isotopes correspond to variations of the same element with respect to the number of neutrons in its nucleus. the number they give us, 35 and 37 correspond to the mass number of chlorine. The percentage will be how abundant the element is.
To find the average atomic mass we must multiply the mass of the isotope by its respective percentage of abundance and add these two results.
So, the average atomic mass of Cl will be:
\(AtomicMassCl=34.968amu\times75.53\%+36.956amu\times24.47\%\)\(\begin{gathered} AtomicMassCl=26.411amu+9.043amu \\ AtomicMassCl=35.454amu \end{gathered}\)Answer: the average atomic mass of chlorine is 35.454 amu
the molar solubility of pbi 2 is 1.5 × 10 −3 m. calculate the value of ksp for pbi 2 .4.5 x 10 -6
The value of Ksp for PbI2 is 4.05 × 10^-8 if the molar solubility of PBI 2 is 1.5 × 10 −3 m.
The molar solubility of PBI 2 = 1.5 × 10 −3 m
The solubility product constant = 2 .4.5 x 10 -6
The solubility product constant (Ksp) for PbI2 can be estimated using the molar solubility of PbI2, the stoichiometry of the equilibrium equation is:
\(PbI2(s) = Pb2+(aq) + 2I-(aq)\)
The equation for Ksp is:
Ksp = \([Pb2+][I-]^2\)
[Pb2+] = S = 1.5 × 10−3 M,
[I-] = 2S = 3 × 10−3 M
The stoichiometric coefficient of I- is 2. Substituting these values into the Ksp equation we get:
Ksp =\((1.5 × 10^-3) × (3 × 10^-3)^2\)
Ksp = 4.05 × 10^-8
Therefore, we can conclude that the value of Ksp for PbI2 is 4.05 × 10^-8.
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The value of Ksp for PbI2 is 3.375 × 10^-9 or 4.5 x 10 -6. The expression for the solubility product constant (Ksp) of a sparingly soluble salt such as PbI2 is: Ksp = [Pb2+][I-]^2
where [Pb2+] and [I-] are the molar concentrations of the lead ion and iodide ion, respectively, in a saturated solution of PbI2.
Given that the molar solubility of PbI2 is 1.5 × 10^-3 M, we can assume that [Pb2+] and [I-] in the saturated solution are also equal to 1.5 × 10^-3 M. Therefore, we can substitute these values into the Ksp expression and solve for Ksp:
Ksp = (1.5 × 10^-3 M)(1.5 × 10^-3 M)^2
Ksp = 3.375 × 10^-9
So the value of Ksp for PbI2 is 3.375 × 10^-9 or 4.5 x 10 -6 (if that was a typo in the question).
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What is not required on a hazardous material label?
Provider Information is not required (for secondary containers used in the workplace) on a hazardous material label.
The following components need to be on a label to be GHS compliant:
Identification of the product
warning or danger as a signal word
Risk pictograms
Advisory statements
Statements of caution
Provider Information (not required for secondary containers used in the workplace)
If the primary container fails, secondary containment acts as a backup barrier to prevent leaking into an exposed area. It is necessary to store all containers of hazardous waste and liquid hazardous materials in an appropriate secondary containment system. Systems for secondary containment may include
What information must be on labels for chemicals used at work?
The warning or signal phrase "Danger," "Warning" pictograms, "Hazmat" or "Precautionary" remarks, and "Product" and "Supplier" identification signs (supplier identification is not required for secondary containers used in the workplace)
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I WILL GIVE YOU BRANILY PLS
Answer:
what dose this even mean?
Explanation:
Why does the carbon anode burn away in the electrolysis of aluminium chloride?
State your claim. Make sure your claim fully explains how infrared photography can be used to visualize temperature differences
My claim is that infrared photography can be used to visualize temperature differences by capturing the infrared radiation emitted by objects and converting it into visible light, with warmer objects appearing brighter and cooler objects appearing darker in the final image. This is because all objects emit some level of infrared radiation, and the amount of radiation emitted increases as the temperature of the object increases. By using a specialized camera that is sensitive to infrared radiation, it is possible to capture these differences in radiation and convert them into visible light, allowing the viewer to see temperature variations in the final image.
10 facts about “molecules”
Answer:
Explanation:
A perfect diamond is a single molecule made of carbon atoms.
DNA is a super long molecule that has information uniquely describing every human being.
When two or more atoms chemically bond together, they form a molecule.
They are very small in size.
They have space between them.
They are in constant random motion.
molecules move when Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.
In 1926, French physicist Jean Perrin received the Nobel Prize in physics for proving, conclusively, the existence of molecules.
Molecules can exist in free state because they are very stable.
The smallest particle of a compound capable of existing on its own is a Molecule-not a atom.
Ice at 0.0°C is mixed with 7.30 × 10^2 mL of water at 25.0°C. How much ice must melt to lower the water temperature to 0.0°C? The specific heat capacity of water is 4.186 J/(g·K). Latent heat of fusion for water is 333.7 J/g.
Approximately 35.90 grams of ice must melt to lower the water temperature to 0.0°C.
To solve this problem, we need to calculate the amount of heat that needs to be transferred from the water to the ice in order to lower the water temperature to 0.0°C.
First, let's calculate the initial heat content of the water. The specific heat capacity of water is 4.186 J/(g·K), and the mass of the water can be calculated using its density (1 g/mL) and volume (7.30 × 10^2 mL):
Mass of water = density × volume = 1 g/mL × 7.30 × 10^2 mL = 7.30 × 10^2 g
The initial heat content of the water can be calculated using the formula:
Heat content = mass × specific heat capacity × temperature change
Heat content = 7.30 × 10^2 g × 4.186 J/(g·K) × (25.0°C - 0.0°C) = 7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C
Next, we need to calculate the amount of heat that needs to be transferred from the water to the ice to lower the water temperature to 0.0°C. This heat transfer occurs during the melting of the ice.
The amount of heat required to melt the ice can be calculated using the formula:
Heat = mass of ice melted × latent heat of fusion
Let's assume that x grams of ice melts. The mass of the ice can be calculated using its density (0.92 g/mL) and volume (same as the volume of water):
Mass of ice = density × volume = 0.92 g/mL × 7.30 × 10^2 mL = 6.716 × 10^2 g
Heat = x g × 333.7 J/g
Now, we need to ensure that the heat transferred from the water to the ice is enough to lower the water temperature to 0.0°C. The heat transferred from the water to the ice is equal to the heat transferred from the water when its temperature drops to 0.0°C:
Heat content of water = Heat transferred to ice
7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C = x g × 333.7 J/g
Now, we can solve for x:
x = (7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C) / (333.7 J/g)
x ≈ 35.90 g
Therefore, approximately 35.90 grams of ice must melt to lower the water temperature to 0.0°C.
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1) How would the temperature change and the calculated heat of neutralization vary if the
volumes remained the same but the concentrations of the acid and the base were
doubled? Explain.
2) How would the temperature change and the calculated heat of neutralization vary if the
concentrations remained the same but the volume of the acid and base was cut in half?
Explain.
Answer:
1) The standard enthalpy change of neutralization is the enthalpy change when solutions of an acid and an alkali react together under standard conditions to produce 1 mole of water. Notice that enthalpy change of neutralization is always measured per mole of water formed. Enthalpy changes of neutralization are always negative - heat is released when an acid and and alkali react. For reactions involving strong acids and alkalis, the values are always very closely similar, with values between -57 and -58 kJ mol-1. That varies slightly depending on the acid-alkali combination (and also on what source you look it up in!).
2)same of n1
3.
a) Using the five-step method, predict the predominant Bronsted-Lowry acid base
reaction when solutions of perchloric acid and sodium dihydrogen phosphate are
combined.
b) Identify one conjugate acid-base pair from the reaction equation.
c) Predict whether the equilibrium will favour the formation of the reactants or
products. Support and explain your answer.
Answer:
a) The predominant Brownstead-Lowry acid- base is perchloric acid
b) A conjugate acid base pair is HClO4 and ClO4^-
c) forward reaction is favored and equilibrium position lies towards the far right
Explanation:
The molecular equation is;
HClO4(aq) + NaH2PO4(aq) -----> H3PO4(aq) + NaClO4(aq)
The net ionic equation of the reaction is;
H^+(aq) + H2PO4^-(aq) ----> H3PO4(aq)
The predominant Brownstead-Lowry acid- base is perchloric acid .
A conjugate acid base pair is HClO4 and ClO4^-
Since the both species; perchloric acid and sodium dihydrogen phosphate are both highly soluble in water yielding ions and also dissociate to a large extent in solution, the forward reaction is favoured leading to the formation of phosphoric acid. Remember that phosphoric acid does not easily dissociate in solution hence the forward reaction is faster than the reverse reaction and the equilibrium position lies towards the far right.
Calculate the pHpH of 1.0 LL of the solution upon addition of 30.0 mLmL of 1.0 MHClMHCl to the original buffer solution. Express your answer to two decimal places. pHpH
The pH of the solution after the addition of 30.0 mL of 1.0 M HCl to the original buffer solution is 4.45.
1. First, find the moles of HCl added. Moles = Volume (L) × Molarity = (30.0 mL × 1 L/1000 mL) × 1.0 M = 0.03 mol HCl
2. Determine the moles of the acid and base components in the buffer solution. The initial moles will be given in the problem, and you need to know the amount of each component in the buffer.
3. Now, account for the reaction between HCl and the base component of the buffer. The moles of HCl will react with the same amount of the base component, so subtract the moles of HCl from the base component and add it to the acid component. If there's not enough base component to neutralize all the HCl, you will have to deal with excess HCl, and that will change the pH more dramatically.
4. Calculate the new concentrations of the acid and base components in the buffer solution. Divide the new moles of each component by the total volume of the solution (1.0 L + 0.03 L = 1.03 L).
5. Finally, use the Henderson-Hasselbalch equation to find the pH of the solution: pH = pKa + log10([Base]/[Acid]). The pKa value will be given or can be found using the Ka value of the weak acid in the buffer solution.
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The pictures represent three different states of matter.
Which order of pictures places molecules with the
most amount of motion to the least amount of motion?
OX-Y-Z
OZ Y-X
OY-Z-X
OY X-Z
Answer:
OX-Y-Z
Explanation:
its the correct answer
The correct order from the most amount of motion( Kinetic energy) to the least amount of motion is Y (gas), Z (liquid), and X (ice). The correct answer is C, Y-Z-X.
In the given sequence, the states of matter with the most amount of motion (kinetic energy) to the least amount of motion are as follows:
Y - Gas (highest kinetic energy, molecules move freely and quickly in all directions)
Z - Liquid (intermediate kinetic energy, molecules have some freedom of movement but are more closely packed than in a gas)
X - Ice (lowest kinetic energy, molecules are tightly packed and have minimal movement, as it is in a solid state)
This sequence reflects the increasing freedom of movement and mobility of molecules as they transition from a solid to a liquid to a gas state.
Thus, the correct option is C.
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The density of air under ordinary conditions at 25°C is 1.19 g/L. How many kilograms of air is in a room that measures 11.0 ft x 12.0 ft and has a(n) 10.0 ft ceiling? 1 in =2.54 cm (exactly); 1 L = 10^3 cm^3?A. 45 x 10^4B. 0.1145C. 3.99D. 44.5E. 0.166
First, we define density as:
Density = mass/volume;
We focus first on the volume of air in the room.
Volume:
We have the measurements of where the air is.
We calculate the volume with these measurements, but first, we change the units to L:
1 inch = 2.54 cm
1 L = 10^3 cm^3
1 ft = 12 inch
Now,
11.0 ft x (12 in/1 ft) x (2.54 cm/1 in) = 335.28 cm
12.0 ft = 365.76 cm
10.0 ft = 304.8 cm
Therefore, the volume of the room = 335.28 cm x 365.76 cm x 304.8 cm
Volume = 37378237.5 cm^3 x (1 L/10^3cm^3) = 374 x 10^2 L
From the Density equation, we clear the mass:
Density x volume = mass (g)
1.19 g/L x 374x10^2 L = 445x10^2 g x (1 kg/1000 g) = 44.5 kg
Answer: 44.5 kg
Which unit is used for measuring atomic mass? O A. atomic mole O B. grams/mole Ос. grams O D. atomic mass unit ОЕ. atomic mass weight
match each of the ions with the noble gas that has the same number of electrons. Ne=
Ar=
Kr=
answer bank Mg2+
K+
F-
Ca2+
Br-
The electronic configuration of an atom determines its chemical properties. Noble gases have unique electronic configurations that make them stable and unreactive.
The outermost energy level of noble gases is fully occupied with electrons, which means they have eight electrons, except for helium, which has only two electrons. This outermost level is also known as the valence shell.
Matching the ions with the noble gas that has the same number of electrons helps us understand the similarities in their chemical properties. For instance, the magnesium ion, Mg2+, has the same number of electrons as the neon atom, Ne. This means that both have a fully occupied valence shell with eight electrons, which makes magnesium ion highly stable and unreactive.
Similarly, potassium ion, K+, has the same number of electrons as argon, Ar, and calcium ion, Ca2+, has the same number of electrons as krypton, Kr. Both potassium and calcium ions have a single electron in their valence shell, while argon and krypton have eight electrons in their valence shell.
Finally, the bromide ion, Br-, has the same number of electrons as the krypton atom, Kr, which means they both have eight electrons in their valence shell. This similarity in electronic configuration explains why bromide ion can form ionic bonds with cations that have one electron fewer than a noble gas.
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how many atoms are in the compound 3AI(C2H3O2)2
Answer:56
Explanation:YW
First, state your claim about how the Mesosaurus fossils got separated. Then, use evidence to support your claim. For each piece of evidence you use, explain how the evidence supports your claim. Be sure to include the words from the Word Bank!
Claim: The separation of Mesosaurus fossils can be explained by the continental drift hypothesis. Evidence: Fossil Distribution, Geological Similarities, Matching Climate and Habitat. The distribution of Mesosaurus fossils across South America and Africa, the geological similarities between these regions, and the matching climate and habitat conditions all support the claim that the separation of Mesosaurus populations can be explained by the process of continental drift.
Claim: The separation of Mesosaurus fossils can be explained by the continental drift hypothesis.
Evidence:
Fossil Distribution: Mesosaurus fossils are found in both South America and Africa. This distribution aligns with the hypothesis of continental drift, which suggests that these continents were once connected and later separated. The similarity in fossil remains on different continents supports the claim that Mesosaurus populations were separated when the continents drifted apart.
Geological Similarities: The geological formations and sedimentary layers in which Mesosaurus fossils are found in South America and Africa display remarkable similarities. This similarity implies that these regions were once part of the same landmass and were subsequently separated. The matching geological features provide further evidence for the separation of Mesosaurus populations due to continental drift.
Matching Climate and Habitat: Mesosaurus fossils indicate that the species was adapted to a freshwater environment. The presence of similar freshwater environments in both South America and Africa further supports the claim that Mesosaurus populations were separated when the continents drifted apart. The matching climate and habitat conditions provide evidence that supports the idea of geographic isolation and subsequent speciation.
In conclusion, the distribution of Mesosaurus fossils across South America and Africa, the geological similarities between these regions, and the matching climate and habitat conditions all support the claim that the separation of Mesosaurus populations can be explained by the process of continental drift.
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three students are asked to discuss the percent error obtained from this lab and explain some sources of error that would account for the discrepancy seen, if any. which student employs correct scientific reasoning?student 1: if the reaction was not allowed to go to completion, the sodium bicarbonate would not have fully decomposed, making the final mass higher than the theoritical. student 2: if th baking soda was not heated long enough, the mass of solid product would be lowstudent 3: the student didnt weight the masses correctly therefore human error is the main source of discrepancya. student 3b. student 1c. student 2
Students who use correct scientific reasoning are Student 1 namely: If the reaction is not allowed to finish, the sodium bicarbonate will not decompose completely, making the final mass higher than the theory.Te corrct amswer is B.
If the sodium bicarbonate is not properly broken down, water and carbon monoxide will not be produced, which can be eliminated to lessen the product's mass. The product will therefore weigh heavier or have a bigger ultimate mass than predicted because of an incomplete reaction.
Given the aforementioned justifications, it is obvious that Student 2 is mistaken in this instance. This is not a scientific explanation in the instance of Student 3 and is merely a wild guess that isn't true in all circumstances.
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LAB: SOIL PARTICLES
You have learned that soil is made of weathered rock, water, air, and organic material. The size of particles is an important soil characteristic. According to the United States Department of Agriculture (USDA), there are three main particle sizes—sand, silt, and clay. Clay is particles smaller than 0.002 mm. Sand is particles larger than 0.05 mm. Particles in between are silt. The size of particles in soil determines how much water the soil will hold. Small particles hold more water than large particles.
Soil usually settles into different layers called horizons. The arrangement of horizons is the soil profile. In this experiment, you will observe how particle size affects the soil profile.
Describe how particle size affects the settling of soil.
Which type of soil do you think will settle to the bottom of the container faster?
1 1/2 cups potting soil
1 1/2 cup sand
3 wide-mouthed juice bottles with lids
Masking tape
Pen
Water
Make masking tape labels for each juice bottle. Label one "soil" and the other "soil and sand."
Fill both bottles 3/4 full of water.
Slowly pour 1 cup of soil into the water in the "soil" bottle. Observe the behavior of the soil particles.
Fill the "soil" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Slowly pour 1 cup of sand into the water in the "sand" bottle. Observe the behavior of the soil particles.
Fill the "sand" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Add the 1/2 cup of sand to the remaining 1/2 cup of soil. Mix thoroughly with the spoon.
Slowly pour the sand and soil mixture into the water in the "soil and sand" bottle. Observe the behavior of the particles.
Fill the "soil and sand" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Leave both bottles undisturbed for 8 hours.
Look at the bottles again after 8 hours and record your observations.
Data
What did you notice about the way the soil particles sank in the water? How was it different from the way the soil and sand particles sank?
What does the soil look like in the "soil" bottle? How is it different from the soil in the "soil and sand" bottle?
In the "soil and sand" bottle, which type of soil is on the bottom? Why?
The amount of each size particle in soil is the particle size distribution. Do you think this is a good way to determine particle size distribution? Why or why not?
State whether your hypothesis was supported or disproved, and then explain why it was supported or disproved using your data. Summarize your observations and answer one or more of the following questions: How does this lab relate to what I have been learning? How does this experiment relate to things I have seen in my own life? What could be done to improve this experiment?
Heading and title
Hypothesis, procedure, data, post lab, and conclusion section headings
Each section is thorough and complete
Lab report typed into a word processor (such as Microsoft Word) and saved
Typed lab document uploaded to Ignitia and submitted
1. I noticed that the soil particles settled out of the water with the larger, heavier particles settling out first and on the bottom, and each layer has smaller and lighter particles in it.
2. Sand settled on the bottom because they are heavier and have more mass than the smaller particles such as silt and clay.
3. Yes, this is a good way to determine particle size distribution. The method used in the experiment allows for the separation of soil particles based on their size and weight, which is a good indicator of their distribution in the soil sample.
4. The results in this experiment may look different when done in different locations because the particle size distribution of soil can vary depending on the location, climate, and geology of the area. Soils in different locations may have different compositions, including different amounts of sand, silt, and clay, which can affect the results of the experiment. Additionally, the sedimentation rate of the particles can also be influenced by factors such as the temperature, the presence of organic matter, and the presence of clay minerals, which can further affect the results.
If Liquid diethyl ether (AHvap = 26.5 kJ/mol) is poured into a beaker on a humid day, the ether will evaporate, and frost will form on the beaker. Construct an explanation for the process.
In comparison to the greater hydrogen bonding in ethanol, diethyl ether molecules are bound together by weak dispersion forces. As a result, one mole of diethyl ether takes less heat to vapourize than one mole of ethanol.
Is diethyl ether a more volatile substance than water?The vapour pressure of diethyl ether at these temperatures is more than 20 times that of water, indicating its volatility.
Diethyl Ether, CH3CH2OCH2CH3, is a highly flammable organic solvent that was also revealed to be one of the earliest anaesthetics. Because it boils at 34.6°C, just below the typical human body temperature, ether evaporates quickly. Since its vapour is denser than air, ether fumes tend to sink into the atmosphere.
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During photosynthesis what takes place under the leaf
Answer:
In plants, the process of photosynthesis takes place in the mesophyll of the leaves, inside the chloroplasts. Chloroplasts contain disc-shaped structures called thylakoids, which contain the pigment chlorophyll.
Explanation: Hope this helps
When a compound is added to water only a few of its molecules dissociate to produce hydrogen ions. It is a...
a. strong acid.
b. weak acid.
c. strong base.
d. weak base.
In which orbitals would the valence electrons for carbon (C) be placed?
Answer: orbitals supernumerary
Explanation:
Answer:
both S orbital and p orbitals
Explanation:
took the exam got the question right.
Genetic material is carried the ______________ of a cell
1.vacuoles
2.cytoplasm
3.nucleus
4.cell membrane
Answer:
3. nucleus
Explanation:
The nucleus contains all the genetic information.
The maximum number of electrons which can adopt 2p waveforms (occupy 2p orbitals) is2p orbital, two lopsided ovals next to each other with a space between them.
The maximum number of electrons that can occupy 2p orbitals is six.
In atomic theory, each orbital has a maximum capacity for two electrons, one with a spin-up (+1/2) and the other with a spin-down (-1/2). The 2p orbitals consist of three separate orbitals labeled as 2px, 2py, and 2pz. These orbitals are oriented along the x, y, and z axes, respectively.
Since there are three 2p orbitals, the total number of electrons that can occupy them is 2 electrons per orbital x 3 orbitals = 6 electrons. This means that each of the 2p orbitals can accommodate a maximum of two electrons.
The 2p orbitals are higher in energy than the 2s orbital, and they are typically filled after the 2s orbital in the electron configuration of atoms. Understanding the maximum electron capacity of orbitals is important for determining the electronic structure and chemical behavior of elements.
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what happens when burning matchstick is held near the nitrogen gas jar
Explanation:
No observable change because nitrogen is an inert gas...
which buffered solution, buffer a or buffer b, would be more resistant to ph change when a strong acid or a strong base is added? justify your answer.
The buffered solution that would be more resistant to pH change when the strong acid or the strong base is added is the buffer b - acidic buffer.
The acidic buffer will be the most resistant to the pH change when the both of the concentrations of the acid and the base are equal. The Acid buffer contains the acidic pH and which is prepared by the mixing of the weak acid and its salt with the strong base.
The basic buffer has the basic pH and which is prepared by the mixing of the weak base and its salt with the strong acid. Therefore, the buffer will be more resistant to the change in the pH.
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This question is incomplete, the complete question is :
which buffered solution, buffer a or buffer b, would be more resistant to ph change when a strong acid or a strong base is added? justify your answer.
buffer a - basic buffer
buffer b - acidic buffer