Which one of the following statements about Bernoulli' s theorem is correct?A) The dynamic pressure decreases as static pressure decreases.B) The dynamic pressure increases as static pressure decreases.C) The total pressure is zero when the velocity of the stream is zero.D) The dynamic pressure is maximum in the stagnation point.

The correct answer is Now that the three crucial components of an electric circuit have been described,... The watt (W) de- is the electrical unit of measurement for power.

A computer system's four primary equipment operations are input, processing, storage, and output. Transferring data into a computer system is referred to as input. When hardware fails, drivers become obsolete, or there is insufficient airflow because of clogged fans, a computer will crash. Malware, viruses, corrupted registry, bad sectors on the hard drive, and other factors can also cause your System to shut down suddenly. The display, power supply, or CPU is overheating are a few of the frequent causes of computer crashes. The computer's internal hardware is faulty. Hardware and software can't coexist.

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A utility-scale wind turbine's hub and blades make up the rotor, which transforms green energy into centrifugal energy that powers an electrical generator.

The blades of a turbine, which resemble propellers and function similarly to an airplane wing, capture the wind's energy. A compartment of low-pressure air develops on one edge of the blade when the wind blows. The blade is subsequently drawn toward the low-pressure air pocket, which turns the rotor.

Francis and Propeller reaction turbines are the two most popular varieties. Reaction turbines include kinetic turbines as well. The runner of a propeller turbine typically has three to five blades.

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Answer:

the correct answer is option B. W

Answer:

it is b and w

Explanation:

pls mark as brainlist

Answer:

So The emergency vehicle can pass so they can get to where they need to go

Explanation:

Answer:

15psig

Explanation:

Answer:

The generator delivers current of 500.11 A

Explanation:

Given the data in the question;

mechanical energy delivered to the generator = 1500 hp

efficiency η = 80.0 %

terminal potential difference of the generator = 1790 V

we know that;

1 hp = 746 W

so

the mechanical energy delivered to the generator will be

Generator Input = ( 1500 × 746 )W = 1119000 W

So the generator output will be;

Generator Output = Generator Input × η

we substitute

Generator Output = 1119000 W × 80.0 %

Generator Output = 1119000 W × 0.8

Generator Output = 895200 W

So the Current will be;

\(I\) = Generator Output / terminal potential difference of the generator

we substitute

\(I\) =  895200 W / 1790 V

\(I\) =  500.11 A

Therefore, The generator delivers current of 500.11 A

Answer:

the world will not be the same it will change dramticily and

things will not be the same

Explanation:

Urbanization increases the amount of impervious surface in a given area, which often slows down hydrologic response time and so raises the danger of flooding.

While impermeable rocks prevent water from passing through pores and fissures, permeable rocks do. Because there is more surface run-off when a valley is built of impermeable rocks, flooding is more likely. excessive rain. arriving ocean waves, such as a storm surge. ice jams, melting snow, and melting ice. Levees or dams breaching India is unique in that the monsoon season brings with it a lot of rain. Numerous rainy weather systems can also be found elsewhere. Coastal communities and villages may also be impacted by storm surges. Dams can have serious consequences when water is released suddenly or when it is not released at all.

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Answer:a

a) Vo/Vi = - 3.4

b) Vo/Vi = - 14.8

c) Vo/Vi = - 1000

Explanation:

a)

R1 = 17kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

(Va - Vi)/5kΩ + (Va -Vo)/17kΩ = 0

sin we know Va≈Vb=0

so

-Vi/5kΩ + -Vo/17kΩ = 0

Vo/Vi = - 17k/5k

Vo/Vi = -3.4

║Vo/Vi ║ = 3.4    ( negative sign phase inversion)

b)

R2 = 74kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

so

(Va-Vi)/5kΩ + (Va-Vo)74kΩ = 0

-Vi/5kΩ + -Vo/74kΩ = 0

Vo/Vi = - 74kΩ/5kΩ

Vo/Vi = - 14.8

║Vo/Vi ║ = 14.8  ( negative sign phase inversion)

c)

Also for ideal op-amp

Va≈Vb=0 so Va=0

Now for position 3 we apply nodal analysis we got at position 1

(Va - Vi)/5kΩ + (Va - Vo)/5000kΩ = 0           ( 5MΩ = 5000kΩ )

so

-Vi/5kΩ + -Vo/5000kΩ = 0

Vo/Vi = - 5000kΩ/5kΩ

Vo/Vi = - 1000

║Vo/Vi ║ = 1000  ( negative sign phase inversion)

Answer:

a. Composition of Vector.

Explanation:

When a bird flies in the air, it stretches its wings into air and this movement helps it move in a certain direction. This is an example of composition of vector. Air strikes the wings in opposite direction and bird wing movement helps it move against the wind.

Answer:

a) The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

b) The change in diameter of the specimen is  - 0.015 mm

Explanation:

Given the data  in the question;

(a) The amount by which this specimen will elongate in the direction of the applied stress.

First we find the area of the cross section of the specimen

A = \(\frac{\pi }{4}\) d²

our given diameter is 20.5 mm so we substitute

A = \(\frac{\pi }{4}\) ( 20.5 mm )²

A = 330.06 mm²

Next, we find the change in length of the specimen using young's modulus formula

E = σ/∈

E = P/A × L/ΔL

ΔL = PL/AE

P is force ( 46300 N), L is length ( 201 mm ), A is area ( 330.06 mm² ) and E is  elastic modulus (60.5 GPa) = 60.5 × 10⁹ N/m² = 60500 N/mm²

so we substitute

ΔL = (46300 N × 201 mm) / ( 330.06 mm² × 60500 N/mm² )

ΔL =  0.466 mm

Therefore, The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

(b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.

Using the following relation for Poisson ratio

μ = -  Δd/d / ΔL/L

given that Poisson's ratio of the metal is 0.33

so we substitute

0.33 = -  Δd/20.5 / 0.466/201

0.33 = -  Δd201 / 20.5 × 0.466

0.33 = - Δd201  / 9.143

0.33 × 9.143 =  - Δd201

3.01719 = -Δd201

Δd = 3.01719 / - 201

Δd  = - 0.015 mm

Therefore, The change in diameter of the specimen is  - 0.015 mm

Answer:

false

Explanation:

Answer:

[a]. It is the same substance as the colorless liquid with a strong smell.

[b]. the substance with colorless liquid with a strong smell and a white solid with no smell are being used up to produce the ending substance had the repeating group of atoms shown above on the right and the other ending substance.

Explanation:

Atoms are referred to be the smallest units of a substance although it can be sub-divided into smaller units such as proton, neutron and electron. When atoms combines in group they form a molecule.

From the question above it is seen that two substances were mixed together to give two ending substances that is:

substance A [ colorless liquid with a strong smell] + substance B[white solid with no smell] ---------> substance C[ repeating group of atoms shown above on the right] + substance D.

The ending substance that is, substance C is the same substance as substance A which is the colorless liquid with a strong smell.

When the substance A reacted with substance B, it gives substance C and D that is the ending substances are the products of the reaction between A and B.

Hence, the substance with colorless liquid with a strong smell and a white solid with no smell are being used up to produce the ending substance had the repeating group of atoms shown above on the right and the other ending substance.

Answer:

a) 4.74 * 10^-23 cm^3

b)  8.9 g/cm^3

Explanation:

Given data :

Lattice parameter of copper = 0.362 nM

Atomic weight of copper = 63.54 g/mole

Given that copper forms a fcc structure

a) Calculate the volume of the unit cell

V = a^3

  = ( 0.362 * 10^-7  cm )^3 = 4.74 * 10^-23 cm^3

b) Calculate density of copper in g/cm^3

Density = ( n*A ) / ( Vc * NA) ----------- ( 1 )

where: NA = Avogadro's number = 6.022 * 10^23  atoms/mol

n = number of atoms per unit cell = 4

A = atomic weight = 63.54 g/mol

Vc = volume of unit cell =  4.74 * 10^-23 cm^3

Input values into equation 1

Density = 8.9 g/cm^3

Press fit power steering pump pulleys require a special puller to remove the pulley, according to Technician A. In contrast, Technician B claims that the power steering pump pulley should be mounted in a vice to press the pulley off the pump.

As a result, both technicians have different opinions on the best way to remove the power steering pump pulley. However, it should be noted that Technician A is correct.A press-fit pulley is one that is installed by pressing it onto a power steering pump shaft. Because the pulley is affixed to the pump shaft, it can be challenging to remove without causing damage. To accomplish this task, a press-fit pulley remover tool is required. The tool attaches to the pump shaft and then connects to the pulley's hub.

The tool will extract the pulley from the shaft as the nut is tightened.Typically, if you try to remove a press-fit pulley by using a vice, you can harm it. When using a vice, the pulley will be ruined, which is why Technician B is incorrect. In addition, attempting to pry off the press-fit pulley with a pry bar or a screwdriver will cause damage to the power steering pump shaft.In summary, Technician A is correct that a press-fit power steering pump pulley requires a special puller to remove the pulley. Technician B's method of mounting the power steering pump pulley in a vice to press the pulley off the pump is incorrect.

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One environmental disadvantage of nuclear energy is the risk of radiation leaks, which can cause long-term damage to the environment and human health.

Nuclear energy has many advantages, such as being a clean and efficient source of energy that does not produce carbon emissions. However, there are also some environmental disadvantages associated with it. One of the most significant is the risk of radiation leaks, which can cause serious damage to the environment and human health. Radiation leaks can occur due to equipment failure, natural disasters, or human error during the production or storage of nuclear materials.

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Answer:

0.00695 A

Explanation:

µ represents \(10^{-6}\). Multiply this by 6,950.

In automobiles, an alternator produces an internal AC (alternating current) that is changed back into DC (direct current) before leaving the alternator.

The alternator in automobiles generates AC, or alternating current, as its internal output. However, since most automotive electrical systems operate on DC, or direct current, the AC output needs to be converted back to DC before leaving the alternator.Alternators are responsible for generating electrical power in vehicles. They convert mechanical energy, supplied by the engine's crankshaft, into electrical energy. The alternator's rotor consists of a coil of wire that rotates within a magnetic field. This rotation induces an alternating current (AC) in the coil.

To utilize this electrical energy, it needs to be converted into direct current (DC), which is the type of electricity used by the various electrical components in an automobile. The AC output from the alternator is rectified, meaning it is changed back into DC. This is achieved through the use of diodes, which allow current flow in only one direction.Once the AC output is rectified, it can be used to charge the vehicle's battery and power the electrical systems. The battery acts as a buffer, storing the electrical energy and providing a steady supply of DC power when the engine is not running.

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The equation holds for any value of t, and the smallest positive delay parameter is since t₁ is equal to t.

To find the smallest positive value for the delay parameter, let's acknowledge the equation is as takes after:

cos(20n(t - t₁)) + cos(20π(t - 2t)) + cos(20ñ(t - 3t)) = 2cos(20nα)

where t₁, t, and α are unknown parameters.

To create this equation honest to goodness for all t, we require the disputes of the cosine capacities to be equal, meaning:

20n(t - t₁) = 20π(t - 2t) = 20ñ(t - 3t) = 20nα

From the essential two equalities, we are able to conclude that:

t - t₁ = t - 2t ⇒ t₁ = t

From the second and third values, we have:

t - 2t = t - 3t ⇒ t = t

This shows up that t can take any value and t₁ is equal to t. Thus, the smallest positive value for the delay parameter is 0.

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The answer is hazardous locations.

Locations in which flammable gases or vapors may be present in the air in quantities sufficient to produce explosive or ignitable mixtures are identified as hazardous locations. These locations include areas where flammable liquids, gases, or vapors may be present, such as chemical plants, refineries, paint booths, and storage facilities. It is important to identify and properly label these hazardous locations to ensure that proper precautions are taken to prevent explosions or fires.

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These locations are identified as hazardous or potentially explosive environments. It is important to follow proper safety protocols and guidelines when working in these areas to prevent any accidents or incidents.

Workplace safety protocols are an underappreciated but essential part of your safety program. That’s because they help guide your workers through complex tasks that could easily go awry, ensuring that they always know what to do.

Of course, writing safety protocols to ensure safe behavior is an art in and of itself. Here’s a quick look at how to write protocols effectively.

Workplace safety protocols, often called safety procedures, are step-by-step safety plans guiding employees through the safe performance of a given workplace procedure. As such, the protocol refers to both the process itself and the internal document put together by an organization.

All safety protocols will include a list of hazards associated with a given work task. The EHS team will then use a risk assessment matrix to assign a risk factor to each hazard. From there, the EHS team will break the process into steps to ensure each step is handled in a way that avoids or mitigates hazards associated with a given step.

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When incoming traffic is halted and a special left-turn signal, green arrow, or delayed green light allows you to turn left. shows that one side of an intersection has a green light while the oncoming traffic light is still in the red.

A protected left turn is one that is permitted at an intersection with a left-turn signal, a green arrow, or a delayed green light. The right answer is A. when a special left-turn signal, green tick, or delayed green light allows you to make a left turn while oncoming traffic is stopped. shows that a crossroads has a green arrow on one side and a red light on the other.

When a green indicator is pointing downhill steadily, it means that the lane is open for driving. Drivers should get ready to evacuate if they see a continuous YELLOW X signal, which signifies that the lane it is over is about to close to traffic. If there is a steady green arrow, it means you can turn in that direction.

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When hand-propping a small aircraft engine, safety procedures must be observed.

The following are safety procedures that should be followed when hand-propping a small aircraft engine:-

1. Keep the ignition switch off when preparing to hand-prop the engine.

2. Both pilot and propeller hand-proper are required to wear hearing protection.

3. Check the surrounding area before starting the engine to ensure that nobody is near the aircraft.

4. Use a chock block to stop the airplane from moving.

5. Confirm that the brakes are on, the throttle is in the idle position, and the mixture control is set to full rich.

6. Engage the pilot's assistant to remove the propeller brakes while keeping clear of the aircraft.

7. The pilot should not touch the propeller during the engine's start-up phase.

8. After the engine starts, remove the chock blocks and check the engine's systems before taking off.

These are the safety procedures that must be followed when hand-propping a small aircraft engine.

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Answer: Why is even here then.

Explanation:

Answer:

A

Explanation:

Answer:

the answer is a

Explanation:

it is a because thats what the answer is

Just took the test and it ISN'T 92.6 V, my guess is 80 V but I dont know because it only says if I got it wrong.

Answer:

True

Explanation:

Mechanical Advantage Of A Wedge

It is the ratio of the output force to the input force. A wedge applies more force to the object (output force) than the user applies to the wedge (input force), so the mechanical advantage of a wedge is greater than 1

Answer:

Option A is the correct answer. The bus traveled at 50 mph for 20 minutes

Explanation:

The complete question is

Which of the following choices best describes velocity of a bus traveling along its route? A. The bus traveled at 50 mph for 20 minutes. B. The airplane traveled southwest at 280 mph. C. The car went from 35 mph to 45 mph. D. The train made several stops, with an average rate of 57 mph.

Solution

In option A the bus is travelling at a speed of 50 miles per hour. This describes the velocity of bus along its route.

The other options are about the velocity of airplane, car and train

The eigenvalues of the Coefficient matrix A(t) are 7 + 3i√2 and 7 - 3i√2.

The matrix A: A = |  6   13  |
     | -2    8   |
Next, we compute the determinant of (A - λI), where λ is an eigenvalue and I is the identity matrix:
det(A - λI) = |  6-λ  13  |
                   | -2     8-λ |
det(A - λI) = (6 - λ)(8 - λ) - (-2 * 13)
Now, solve the characteristic equation for λ:
(6 - λ)(8 - λ) + 26 = 0
λ^2 - 14λ + 48 + 26 = 0
λ^2 - 14λ + 74 = 0
To find the eigenvalues, solve this quadratic equation. In this case, the equation does not have real roots, so the eigenvalues are complex:
λ = (14 ± √(-112)) / 2
λ1 = 7 + 3i√2
λ2 = 7 - 3i√2
Therefore, the eigenvalues of the coefficient matrix A(t) are 7 + 3i√2 and 7 - 3i√2.

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To find the eigenvalues of the coefficient matrix A(t) for the given system, first write down the matrix:

A(t) = |  6  13 |
       | -2   8 |

Next, we need to find the determinant of (A(t) - λI), where λ represents the eigenvalues and I is the identity matrix:

A(t) - λI = | 6 - λ  13   |
            | -2    8 - λ |

Now, calculate the determinant:

(6 - λ)(8 - λ) - (-2)(13) = 0

Expand and simplify:

48 - 14λ + λ^2 - 26 = λ^2 - 14λ + 22 = 0

This is a quadratic equation, which can be solved using the quadratic formula:

λ = (14 ± √(14^2 - 4(22)))/2 = (14 ± √(144))/2 = (14 ± 12)/2

The eigenvalues are:
λ1 = (14 + 12)/2 = 13
λ2 = (14 - 12)/2 = 1

So, the eigenvalues of the coefficient matrix A(t) are 13 and 1.

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