Answer:
i think radian degree thank you
Explanation:
cuz right the degree angle i responsible more
Answer:
Its radian degree
Explanation:
Because the length of an arc of a unit circle is equal to measurement in radians of angle.
So it is the biggest unit of plane angle
7. Apply Concepts: suppose the dog walked at a constant speed the whole way. What
would the graph look like then? Explain.
If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.
What is the speed about?A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.
If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.
In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.
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In the diagram, q₁, q2, and q3 are in a straight line. Each of these particles has a charge of -2.35 x 10-⁶ C. Particles q₁ and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. What is the net force on particle q₁?
ANSWERED: -6.21 N
Masses m and 2m are joined by a light inextensible string which runs without slipping over a uniform circular pulley of mass 2m and radius a. Using the angular position of the pulley as generalized coordinate, write down the Lagrangian function and Lagrange's equation. Find the acceleration of the masses.
Answer: the acceleration of the masses is given by = 0, which means the angular acceleration of the pulley is zero. This implies that the masses m and 2m move with constant velocity, they are in equilibrium.
Aphids are a type of insects that sucks the sap out of certain types of plants, including potatoes. Not only do they physically damage and weaken the potato plants, but they can also infect them with diseases.
Which of the following examples shows a relationship that is most like that of the aphid and potato plants?
Answer Choices:
A. Crop plants must compete with weeds for available resources like nutrients, water, and space.
B. Anemones protect clownfish from predators while benefiting from nutrients in the waste of the fish.
C. The mistletoe plant attaches to trees and extracts nutrients for itself, which stunts tree growth.
D. Remora fish attach to sharks, eat scraps off the shark's prey, and remove parasites from the shark's skin.
A uniform electric field is directed upward and has a magnitude of 24 N/C. A charge of -6 C is placed in this
field.
The direction of the force on the charge placed in the electric field is upward.
True or False
The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.
The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.
The force on a charged particle in an electric field can be calculated using the formula:
F = q * E
Where F is the force, q is the charge of the particle, and E is the electric field.
Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:
F = (-6 C) * (24 N/C)
F = -144 N
The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.
The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.
Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.
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4. What happens to the total resistance of a
parallel circuit when another resistor is added?
Answer:add resistance in the parallel circuit with the total resistance
Explanation:
the total resistance in the parallel circuit is also add resistance.
PLZZ HELP
How many kg are there in 335 m
How much effort will be required on the small piston having cross section area zam to lift a lead of 4000N on a large piton having cross sectional area 1m². also calculate pressure exerted on the small piston.
Answer:
4000 Nm^-2
Explanation:
Dude that "zam" drove me away, anyway:
Given:
Force on the large piston (F1) = 4000 N
Cross-sectional area of the large piston (A1) = 1 m²
Cross-sectional area of the small piston (A2) = zam (let's assume zam represents the area in square meters)
According to Pascal's law, the pressure exerted on the large piston (P1) is equal to the pressure exerted on the small piston (P2):
P1 = P2
Pressure is defined as force divided by area:
P1 = F1 / A1
P2 = F2 / A2
Since P1 = P2, we can equate the two expressions:
F1 / A1 = F2 / A2
Rearranging the equation to solve for F2, the force on the small piston:
F2 = (F1 / A1) * A2
Substituting the given values:
F2 = (4000 N / 1 m²) * zam
Now, to calculate the pressure exerted on the small piston (P2), we can divide the force by the area:
P2 = F2 / A2
Substituting the values we obtained:
P2 = [(4000 N / 1 m²) * zam] / zam
The area "zam" cancels out in the equation, leaving us with:
P2 = 4000 N/m²
Therefore, the pressure exerted on the small piston is 4000 N/m².
To determine the effort required on the small piston, we need to know the area of the small piston. Once we have that information, we can substitute it into the equation for F2 to calculate the effort required
Which landscape feature can be caused by chemical
weathering?
OU-shaped valley
O Basalt columns
O Limestone caves
Answer: Limestone Caves
Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.
A car moving initially at 20 m/s accelerates up to 60 m/s during the
course of 5 seconds. The average acceleration of the car is m/s2
Physics help, thank you guys so much!
Answer:
Δt = 5.85 s
Explanation:
For this exercise let's use Faraday's Law
emf = \(- \frac{d \phi}{dt}\) - d fi / dt
\(\phi\) = B. A
\phi = B A cos θ
The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.
suppose a linear change of the magnetic field
emf = - A \(\frac{B_f - B_o}{ \Delta t}\)
Dt = - A \(\frac{B_f - B_o}{emf}\)
the final field before a fault is zero
let's calculate
Δt = - 0.046 (0- 1.4) / 0.011
Δt = 5.85 s
1. On each of your equipotential maps, draw some electric field lines with arrow heads indicating the direction of the field. (Hint: At what angle do field lines intersect equipotential lines?) Draw sufficient field lines that you can "see" the electric field.
Answer:
The angle between the electric field lines and the equipotential surface is 90 degree.
Explanation:
The equipotential surfaces are the surface on which the electric potential is same. The work done in moving a charge from one point to another on an equipotential surface is always zero.
The electric field lines are always perpendicular to the equipotential surface.
As
\(dV = \overrightarrow{E} . d\overrightarrow{r}\\\\\)
For equipotential surface, dV = 0 so
\(0 = \overrightarrow{E} . d\overrightarrow{r}\\\\\)
The dot product of two non zero vectors is zero, if they are perpendicular to each other.
CAN SOMEONE PLS HELP ME!
Hello, please could you explain the formula: work done = charge * voltage, and also give the units for work done (if there is one)?
The expression for the work done is given as
\(W=Q\times V\)*Here Q is the charge
*Here V is the potential difference
The work done in the electric circuit is the product of charge (Q) flows and the potential difference (V) in the circuit.
The basic standard unit for the work done is in Joules.
An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. What is its speed when it hits its target?
The speed of the artillery shell when it hits its target is 100 m/s.
Given:
Initial vertical displacement (y) = 200 m
Vertical displacement at 100 m in the air (y') = 100 m
Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)
Using the equation for vertical displacement in projectile motion:
y' = vy^2 / (2g),
where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).
100 m = vy^2 / (2 * 9.8 m/s^2),
vy^2 = 100 m * 2 * 9.8 m/s^2,
vy^2 = 1960 m^2/s^2,
vy = sqrt(1960) m/s,
vy ≈ 44.27 m/s.
Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.
Hence, the speed of the artillery shell when it hits its target is 100 m/s.
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A cave diver enters a long underwater tunnel, when her displacement with respect to the entry point is 20m,she accidentally drops her camera but she doesn't notice it missing until she is some 6m farther into the tunnel.She swims back 10m but cannot find the camera,so she decides to end the dive.How far from the entry point is she?Taking the positive direction out of the tunnel,what is her displacement vector relative to the entry point?
Answer:
3x864/y488bjehdksuwiieirjr
(a)the magnitude of the dependent current source in the circuit below depends on the current flowing through the resistor. determine_____.
Electronics Tutorial on the Current Source and how independent and dependent sources can be used to describe continuous current sources.
How do you locate the source of the dependent current?A dependent source is a current or voltage source that depends on another circuit's current or voltage rather than having a set value (i.e., independence). Y=kX, where X and Y are currents or voltages and k is the proportionality factor, is the usual expression for the value of a dependent source.On the other hand, a current source is referred to be a dependent or controlled current source if the current flowing through it is controlled by another voltage or current in a circuit. In Figure 2, these sources' symbols are depicted. Internal opposition to an ideal current source is infinite.To learn more about current source refer to:
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A 269 kg weather balloon is designed to lift a 2910 kg package. What volume should the balloon have after being inflated with helium in order that the total load can be lifted? (Assume standard temperature and pressure, at which the density of air is ρair = 1.29 kg/m3 and the density of helium is ρHe = 0.179 kg/m3.)
The volume of the helium balloon in order to lift the weight is 17,760m³.
To find the answer, we need to know about the buoyant force.
What's the buoyant force?When a lighter object is kept in a higher density medium, it experiences a force along upward by that medium. This is buoyant force.Mathematically, buoyant force= density × volume of the object×gWhat's the volume of helium required to lift the 269kg weather balloon and 2910kg package?To lift the weight, the buoyant force must equal to the weight.If V is the volume of helium, buoyant force= V×0.179×gSo, V×0.179×g = (269+2910)g=> V= 3179/0.179 = 17,760m³
Thus, we can conclude that the volume of the helium balloon in order to lift the weight is 17,760m³.
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12
The motion of an object can be described by it
A.
speed.
В.
position.
C.
direction.
D.
all of these
Answer:
D
Explanation:
The motion of an object can be described by its speed, position, and direction so its all of the above
Determine the magnitude of the current flowing through a 4.7 kilo ohms resistor if the voltage across it is (a) 1mV (b) 10 V (c) 4e^-t
Answer:
213 nA
2.13 mA
851e^-t μA
Explanation:
We have a pretty straightforward question here.
Ohms Law states that the current in an electric circuit is directly proportional to the voltage and inversely proportional to the resistance in the circuit. It is mathematically written as
V = IR, since we need I, we can write that
I = V/R
a) at V = 1 mV
I = (1 * 10^-3) / 4.7 * 10^3
I = 2.13 * 10^-7 A or 213 nA
b) at V = 10 V
I = 10 / 4.7 * 10^3
I = 0.00213 A or 2.13 mA
c) at V = 4e^-t
I = 4e^-t / 4.7 * 10^3
I = 0.000851e^-t A or 851e^-t μA
A 92-kg rugby player running at 7.5 m/s collides in midair with a 112-kg player moving in the opposite direction. After the collision each player has zero velocity.A. What is the initial momentum of the 92-kg player?B. What is the change in momentum of the 92-kg player due to the collision?Δp1 =C. How is the change in momentum of the 92-kg player related to the change in momentum of the 112-kg player?The two changes in momenta are equal in magnitude and opposite in direction.The two changes in momenta are opposite in magnitude and opposite in direction.The two changes in momenta are equal in magnitude and equal in direction.The two changes in momenta are opposite in magnitude and equal in direction.Part DWhat was the initial speed of the 112-kg player before the collision?Express your answer to three significant figures and include the appropriate units.v2i =
Answer:
A. pi1 = 690 kg m/s
B. Δp1 = - 690 kg m/s
C. The two changes in momenta are equal in magnitude and opposite in direction.
D. v2i = -6.16 m/s
Explanation:
Part A.
The momentum can be calculated as mass times velocity, so the initial momentum of the 92-kg player is equal to
pi = mv
pi = (92 kg)(7.5 m/s)
pi = 690 kg m/s
So, the initial momentum of the 92-kg player was 690 kg m/s
Part B.
After the collision, each player has zero velocity, so the final velocity will be 0 m/s. Then, the change in momentum is equal to
\(\begin{gathered} \Delta p_1=p_f-p_i=mv_f-p_i_{} \\ \Delta p_1=92\operatorname{kg}(0\text{ m/s) - }690\operatorname{kg}\text{ m/s} \\ \Delta p_1=0\operatorname{kg}\text{ m/s - 690 kg m/s} \\ \Delta p1=-690\text{ kg m/s} \end{gathered}\)Part C.
In a closed system the momentum is conserved, so to conserve the momentum the change in momentum of the 92-kg player should be equal in magnitude but opposite in direction. Then, when we add them, the sum should be equal to 0. So, the answer is:
The two changes in momenta are equal in magnitude and opposite in direction.
Part D.
Taking into account part C, we can write the following equation
\(\begin{gathered} \Delta p_2=-\Delta p_1 \\ m_2v_f-m_2v_{i2}=-\Delta p_1 \end{gathered}\)Since the final velocity of the 112-kg player is also 0 m/s, we can solve for v2i as
\(\begin{gathered} m_2(0)-m_2v_{2i}=-\Delta p_1 \\ -m_2v_{2i}=-\Delta p_1 \\ v_{2i}=\frac{-\Delta p_1}{-m_2}=\frac{\Delta p_1}{m_2} \end{gathered}\)Replacing the values, we get
\(v_{2i}=\frac{-690\text{ kg m/s}}{112\operatorname{kg}}=-6.16\text{ m/s}\)Therefore, the answers are:
A. pi1 = 690 kg m/s
B. Δp1 = - 690 kg m/s
C. The two changes in momenta are equal in magnitude and opposite in direction.
D. v2i = -6.16 m/s
write a vector equation
Answer:
In general, a vector equation is any function that takes any one or more variables and returns a vector. The vector equation of a line is an equation that identifies the position vector of every point along the line. This works for straight lines and for curves.
Explanation:
1.A vector has magnitude (size) and direction:
2.a − b.
3.A vector is often written in bold, like a or b.
4.The vector a is broken up into.
5.We can then add vectors by adding the x parts and adding the y parts:
6.When we break up a vector like that, each part is called a component:
7.|a|
8.||a||
(hope this helps can i plz have brainlist :D hehe)
A 10 kg rock falls from a height of 18 m and
lands on a guy about 3 s later. How much power
did it hit him with?
It struck him with 60 W of power. when a 10 kg rock hits a guy after falling from a height of 18 m and landing on him after around 3 s.
What does the word "power" mean?Power is the rate of production of work. P=Wt. The watt (W), which is equal to 1 joule per second (1J/s), is the SI unit for power. Power is a measure of how quickly energy is used up since power is the transfer of energy. An example would be a 60-W light bulb, which uses 60 J of energy every second.
Power= mass. velocity + power=10*18/3*10 = 60 W,
resulting in the power of a falling rock being 60W.
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How do a neutron and a proton compare?
O
A. The proton has much greater mass.
O
B. The proton is farther from the nucleus.
O
C. They have opposite charges.
O
D. They are both found inside the nucleus.
\(\qquad\qquad\huge\underline{{\sf Answer}}\)
The Correct choice is : D
Neutrons and Protons are collectively known as Neucleons because they are found in nucleus of the cell and they have almost equal mass, [ but neutron has slightly greater mass than proton ]. also, Neutrons are neutral particle with no charge on them, where as protons have positive charge on them. making nucleus positively charged altogether ~
Answer:
Option D
Explanation:
Remember that neutrons and protons both are found inside the nucleus.Electrons wander around themProtons have positive chargeElectrons have negative chargeNeutrons are neutralHow fast must a 2500-kg elephant move to have the same kinetic energy as a 67.0-kg sprinter running at 15.0 m/s
Answer:
2.45 m/s
Explanation:
kinetic energy = 1/2 * m * v^2
then, 0.5 * 2500 * x^2 = 0.5 * 67 * 15^2
by solving for x, X = 2.45 m/s
A long piece of wire with a mass of 0.100 kg and a total length of 4.00 m is used to make a square coil with a side of 0.100 m. The coil is hing along a horizontal side, carries a 3.80 A current, and is placed in a vertical magnetic field with a magnitude of 0.010 0 T.
a, Determine the angle that the plane of the coil makes with the vertical when the coil is in equilibrium. b Find the torque acting on the coil due to the magnetic force at equilibrium.
The torque is equal to zero since the coil is in equilibrium. As a result, will also equal zero, indicating that the coil's plane is parallel to the vertical direction at equilibrium.
Calculation-The current-carrying coil in a magnetic field is given by:
τ = μ * B * I * A * sin(θ)
where:
τ = torque (in Nm)
μ = magnetic moment of the coil (in Am^2)
B = magnetic field strength (in T)
I = current flowing through the coil (in A)
A = area of the coil (in m^2)
θ = angle between the plane of the coil and the magnetic field (in radians)
μ = N * A * I
N = number of turns of the coil
A = area of the coil (in m^2)
I = current flowing through the coil (in A)
the equations to calculate the angle θ:
m = 0.100 kg (mass of the wire)
L = 4.00 m (total length of the wire)
side length = 0.100 m
I = 3.80 A (current flowing through the coil)
B = 0.0100 T (magnetic field strength)
Calculations:
A = side length^2 * N = 0.100^2 * 1 = 0.0100 m^2
μ = N * A * I = 1 * 0.0100 * 3.80 = 0.0380 Am^2
Now we can rearrange the equation for torque to solve for θ:
θ = arcsin(τ / (μ * B * I * A))
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Two skydivers jump from a plane at the same timeSkydiver 1 las of 50 kg and Skydiver 2 has a mass of 80 kg. If they both pull their parachute cord when they are 1000 ground which one will have a faster terminal velocity?A) skydiver 1B) sky driver 2C) they fall at the same rate the whole timeD) neither
It's important to know that both skykdivers have the same veloxcity before they pull their parachute because the gravity is the same for both. However, when they open the parachute, the force exerted upside depends on the weight of the person, specifically, the drag force of the parachute is greater if the weight of the skydiver is greater (supposing that that there's no external forces involved).
However, the heavieast person will have greater velocity at the end.
Therefore, the answer is B because skydriver 2 has greater mass.
Q10. Explain the Retention time, in GC. What will happen to retention time, if you increase the detector temperature
Answer:
The detector temperature doesn't affect retention time
Explanation:
Retention time is one of the chromatographic parameters. Is defined as the time of a compound spends from injection to detection.
A solute in GC is added to the injector where is volatilized. When volatilized, it pass through a column until the detector.
The detector temperature doesn't affect retention time. To change retention time you must change injector temperature or column temperature. An increase in column or injector temperature results in a decrease in retention time.
A trebuchet launches a pumpkin at an angle of 63 degrees at an initial velocity of 51 m/ s from the ground. What is the range of the pumpkin?
Answer:
214.72m
Explanation:
The range (R) of a projectile can be calculated using the formula:
R = u²sin2θ/g
Where R = Horizontal range
u = initial velocity
θ = angle of initial velocity
g = acceleration due to gravity (9.8m/s²)
According to the provided information in this question, R= ?, u= 51m/s, θ = 63°, g = 9.8m/s².
Hence, R = u²sin2θ/g
R = 51² × sin 2×63/ 9.8
R = 2601 × sin 126/9.8
R = 2601 × 0.809/9.8
R = 2104.25/9.8
R = 214.72m
estimate the work you do to mow a lawn 10m by 20m with a 50 cm wide mower. Assume you push with a force of about 15 N.
Answer:
W = 6000 Joule
Explanation:
Work is defined as force times distance
W = F * d
We know that F = 15N, we just need the distance (d)
Imagine you have a square lawn with length of 10 m and width of 20m. So, we want to know the the distance you have to travel to cover every square meter of the lawn.
The width of the mower is only 50 cm = 0.5 m.
This means that you have to go back and forth 40 times to cover 20m (lawn width), with a distance of 10 m (lawn length). So,
d = 10 (meter) * 40 (times) = 400 meter
Therefore:
W = (15) * (400) = 6000 J